The system of equations to represent this scenario is x + y = 20 and 2x + 4y = 70 .
In the question ,
it is given that
the total number of tables in the restaurant = 20 tables
let the number of round tables be "x"
let the number of rectangular tables be "y" .
number of person that can seat on a round table = 2
So , the number of person that can seat on "x" round tables = 2x person
number of person that can can seat on rectangular table = 4
So , the number of person that can seat on "y" rectangular tables = 4y person
since total number of table is 20
So , the equation is x + y = 20
and total number of person that can seat are 70 seats .
So , the equation is 2x + 4y = 70
Therefore , The system of equations to represent this scenario is x + y = 20 and 2x + 4y = 70 .
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A bag contains 4 blue and 6 white tokens. Two tokens are drawn from the bag one after another, without replacement. Find the probability that: the first is blue and the second is white.
Concept; Probability
Step1: The total number of tokens is
[tex]6\text{white +4 Blue}=\text{ 10 tokens}[/tex]let the probability of blue be P(B) and the probability of red be P(R)
The probability that the first is Blue is
[tex]\begin{gathered} P(B)=\frac{number\text{ of blue }}{total\text{ number of tokens}}=\frac{4}{10}=\frac{2}{5} \\ \end{gathered}[/tex]The probability the second is white without replacement is
[tex]P(R)=\frac{number\text{ of white}}{total\text{ token}}=\frac{6}{9}=\frac{2}{3}[/tex]Hence the combined probability of Blue and Red is
[tex]P(BR)=\frac{2}{5}\times\frac{2}{3}=\frac{4}{15}[/tex]Therefore the probability that the first is blue and the second is white is 4/15
The graphs below have the same shape. What is the equation of the blue graph? G(x) = _ A. G(x) = x2 + 5 B. G(x) = (x + 5)2 C. G(x) = x2 - 5 D. G(x) = (x - 5)2
The blue graph is represented by the equation g(x) = (x - 5)²
How to determine the equation represented by the blue graph?The possible graph that completes the question is added as an attachment
From the attached graph, we have the following parameters
Red graph = f(x)Blue graph = g(x)Also from the graph, we have the equation of the function f(x) to be
f(x) = x²
Solving further, we can see that:
The function g(x) is on the same level as the function f(x) Also, the function has the same size as .f(x)The only difference is that, f(x) is shifted to the right by 5 units
This means that
g(x) = f(x - 5)
So, we have
g(x) = (x - 5)²
Hence, the blue graph equation is g(x) = (x - 5)²
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Question 3 of 5
A Galapagos penguin can walk mile in an hour. How many hours would it
take the penguin to walk mile?
O A. x = hour
OB. +=
hours
O c.
hour
OD. + hours
-
Answer:
1 hour
Step-by-step explanation:
Since the penguin supposedly walks a 1 mile per hour, it would take one hour to achieve 1 mile
an industrial manufacturing company uses an inverted conical (cone-shaped) tank to dispense liquid into containers. the tank measure 24 inches with a base radius of 48 inches. if the liquid flows out of the tank at a rate of 40 cubic inches per minute, at what rate is the height of the liquid falling when the height of the liquid is 10 inches deep?
If the liquid flows out of the tank at a rate of 40 cubic inches per minute, the height of the liquid will decrease at rate 0.0318 in./minute
Referring to the attached picture, the two triangles in a cone are similar. Hence,
r/h = 48/24
or
r = 2h.
The volume of the liquid is given by:
V = 1/3 . πr²h
Substitute r = 2h,
V = 1/3 . π(2h)²h = 4/3 . πh³
Take the derivative with respect to t
dV/dt = 4/3 . 3πh² . dh/dt
dV/dt = 4 . πh² . dh/dt
Substitute dV/dt = -40 and h = 10
-40 = 4 . π(10)² . dh/dt
dh/dt = - 0.0318 in./minute
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WATER DEPTH An echo sounder is a device used to determine the depth of water by measuring the time it takes a sound produced just below the water surface to return, or echo, from the bottom of the body of water. The accuracy of an echo sounder is the positive difference between the depth of water reading on the echo sounder and the actual depth of water w. Write two absolute value expressions equivalent to the accuracy of an echo sounder.
The absolute value expressions of the echo sounder are |r - w| and |w - r|
How to determine the absolute value expressions of the echo sounder?The statement in the question is represented as
The accuracy of an echo sounder is the positive difference between ...
To solve further, we use the following representations
Depth of water reading = r
Actual depth = w
So, the statement becomes
The accuracy of an echo sounder is the positive difference between r and w
The difference can be represented as
Difference = r - w or Difference = w - r
Represented as absolute value expressions
Difference = |r - w| or Difference = |w - r|
Hence, the expressions are |r - w| and |w - r|
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pulse rates of adult females are normally distributed with a mean of 74.0 beats per minute (bpm) and a standard deviation of 12.5 bpm. what is the percentage of adult females with pulse rates between 49.0 bpm and 86.5 bpm? what percentage of adult females have pulse rates below 90 bpm?
The percentage of adult females with pulse rates between 49.0 bpm and 86.5 bpm - 81.86%
The percentage of adult females have pulse rates below 90 bpm - 89.97%
a)
X ~ N ( µ = 74 , σ = 12.5 )
P ( 49 < X < 86.5 )
Standardizing the value
Z = ( X - µ ) / σ
Z = ( 49 - 74 ) / 12.5
Z = -2
Z = ( 86.5 - 74 ) / 12.5
Z = 1
P ( -2 < Z < 1 )
P ( 49 < X < 86.5 ) = P ( Z < 1 ) - P ( Z < -2 )
P ( 49 < X < 86.5 ) = 0.8413 - 0.0228
P ( 49 < X < 86.5 ) = 0.8186 ≈ 81.86%
b)
X ~ N ( µ = 74 , σ = 12.5 )
P ( X < 90 )
Standardizing the value
Z = ( X - µ ) / σ
Z = ( 90 - 74 ) / 12.5
Z = 1.28
P ( ( X - µ ) / σ ) < ( 90 - 74 ) / 12.5 )
P ( X < 90 ) = P ( Z < 1.28 )
P ( X < 90 ) = 0.8997 ≈ 89.97%
What is pulse rate ?
The pulse rate, or the number of times the heart beats each minute, is gauged by the pulse rate. The arteries enlarge and constrict with the flow of blood as the heart pumps blood through them. An elevated heart rate, or tachycardia, can occur for any reason. Exercise-induced or stress-related heart rate increases are two possible causes (sinus tachycardia). Sinus tachycardia is not seen as an illness but rather a symptom. Another factor contributing to tachycardia is an unsteady heartbeat (arrhythmia).
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The length of a rectangle is 3 inches greater than the width. (Hint: draw a pictureand label itA. Write a polynomial that represents the area of the rectangle.B. Find the area of the rectangle when the width is 4 inches..
We are given that the length of a rectangle is 3 inches greater than the width.
Let us draw a rectangle and label the width and length.
Part A:
Let the width of the rectangle is x inches.
Then the length of the rectangle is (x + 3) inches.
Now recall that the area of a rectangle is given by
[tex]A=L\cdot W[/tex]Where L is the length and W is the width of the rectangle.
[tex]\begin{gathered} A=(x+3)\cdot x \\ A=x^2+3x \end{gathered}[/tex]Therefore, the above polynomial represents the area of the rectangle.
Part B:
We are given that the width is 4 inches.
Substitute the width (x = 4) into the equation of the area that we found in part A.
[tex]\begin{gathered} A=x^2+3x \\ A=(4)^2+3(4) \\ A=16+12 \\ A=28in^2 \end{gathered}[/tex]Therefore, the area of the rectangle is 28 square inches.
Part of the proceeds from a garage sale was 535$ worth of 5$ and 20$ bills. If there were 2 more 5$ bills than 20$ bills, find the number of each denomination
Using concept of Linear equation in two variables, we got 23 is denomination count of 5$ bills and 21 is denomination count of 20$ bills.
Linear equations are used to solve equation in which two variables are connected with each other via some specific methods.
The linear equations in two variables are the equations in which each one of the two variables are of the highest exponent order of the 1 and have one, none, or may be infinitely many solutions. The standard form of a two-variable linear equation is given by ax + by + c = 0 where x and y are the two variables. The solutions can also be written in form of ordered pairs like (x, y).
It is given that 5$ bills are 2 more than 20$ bills,
so let suppose 20$ bills denomination count is x,
then 5$ bills denomination count=x+2;
It is also given that 535$ worth is summation of 5$ bills and 20$ bills
Therefore,[5×(x+2)+(20×x)]=535
On solving for x, we get x=21
Therfore,20$ bills denomination count is 21,and 5$ bills denomination count is 23.
Hence,5$ bills denomination count is 23 and 20$ bills denomination count is 21
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8b^2 + 56b + 48 = 0
Solve for X
Answer:
b= -1, -6
Step-by-step explanation:
divide by common factor
then use x=- b+- sqrt b^2-4ac/2a
separate the equations and solve them
Rain fell at a rate of .25 inches per hour. Before the rain began, 6 inches had already fallen that month. At this rate, how much total rain will have fallen after 4 hours?
Answer:
y=.25x+6
Step-by-step explanation:
20, 33, 44, 53, 69, 75, 89, 90 Find the mean and the standard deviation. Round to the nearest thousandth.
The mean and the standard deviation of the following numbers 20, 33, 44, 53, 69, 75, 89, 90 are 59.125 and 22.461 respectively
What are mean and standard deviation?The mean is the average value in a collection and a standard deviation is the average amount of variability in a data.
mean= sum of data in the collection/ number of data
= (20+33+44+53+69+75+89+90)/8 = 473/8 = 59.125( nearest thousandth)
standard deviation= sum of √(x- mean)^2/ number of data while x is each number in the data
finding (x- mean)^2 for each value of x
(20-59.125)^2=848.266
(33-59.125)^2=682.516
(44-59.125)^2=228.766
(53-59.125)^2=37.516
(69-59.125)^2=102.516
(75-59.125)^2= 260.016
(89-59.125)^2= 907.516
(90-59.125)^2= 968.766
S.D= √(848.266+682.516+228.766+37.516+102.516+260.016+907.516+968.766)/8 =
√504.484
Therefore S.D =22.461 ( to the nearest thousandth)
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FAST PLS
Which brand of granola typically weighs more?
Brand A bags typically weigh more because the median of brand A is higher than that of brand B.
Brand B bags typically weigh more than brand A bags because there is a high outlier at 52.5.
Brand A bags typically weigh more than brand B bags because there are no outliers in the distribution.
Brand B bags typically weigh more because the range of weights is higher than that of brand A.
Answer:
brand A. The bag weights for brand A have less variability than the bag weights for brand B
Find the radius of a cylinder whose height is 10 cm and the total surface area is 352 cm².
Answer: the radius of a cylinder is 4 cm
Step-by-step explanation:
[tex]S_{ts}=352\ cm\ \ \ \ H=10\ cm\ \ \ \ \ r=?[/tex]
The total surface area:
[tex]\displaystyle\\ S_{ts}= 2\pi r^2+2\pi rH\\\\S_{ts}=2\pi (r^2+rH)\\\\352=2\pi (r^2+10r)\\\\[/tex]
Divide both parts of the equation by 2π:
[tex]\displaystyle\\56=r^2+10r\\\\56-56=r^2+10r-56\\\\0=r^2+10r-56\\\\Thus,\\\\ r^2+10r-56=0\\\\D=(-10)^2-4(1)(-56)\\\\D=100+224\\\\D=324\\\\\sqrt{D}=\sqrt{324} \\\\\sqrt{D}=18\\\\ r=\frac{-10б18}{2(1)} \\\\r=-14\notin\ (r > 0)\\\\r=4\ cm[/tex]
Answer:
r ≈ 4 cm
Step-by-step explanation:
Total Surface Area of a cylinder
A = Base Area x 2 + Lateral Surface Area
A = 2(πr²) + 2πrh
where r = radius of base and h = height of cylinder
Solving for r we get
[tex]\displaystyle r = \dfrac{1}{2} \sqrt{h^2 + 2 \dfrac{A}{\pi} }-\dfrac{h}{2}\\\\[/tex]
Given h = 10 cm and A = 325 we get
[tex]\displaystyle r = \dfrac{1}{2} \sqrt{10^2 + 2 \dfrac{352}{\pi} }-\dfrac{10}{2}\\\\\\[/tex]
[tex]\sqrt{10^2 + 2 \dfrac{352}{\pi} } =\sqrt{100+\dfrac{704}{\pi }}\\\\= \sqrt{100 + 224.09}\\\\\\[/tex]
= [tex]\sqrt{324.09}[/tex]
= 18.0025
1/2 x 18.0025 ≈ 9
So r ≈ 9 - 10/2 = 9 -5 = 4
r ≈ 4 cm
Find the measure of each angle in the diagram
A bacterial colony starts with 120 cells and quadruples in size each day. Write an equation that relates the population of cells in this colony (P) at the start of each day and the number of days (d). Find the population on day 8.
Answer:
P = 120*([tex]2^{2d-2}[/tex])P(8) = 1, 966, 080Step-by-step explanation:
Since the population quadruples each day, the population for the subsequent day would be 4*(population of the previous day).
Thus, the evolution of the population value takes the form of a geometric progression, with a common ratio, r = 4
The n-th term of a geometric progression is given by:
[tex]a_{n}[/tex] = [tex]ar^{n-1}[/tex] (1)
Where a is the 1st term of the progression.
From (1), our population would generally take the form:
[tex]P_{d}[/tex] = [tex]P_0r^{d-1}[/tex] (2)
In this case, the initial value (1st term) [tex]P_{0}[/tex] = 120.
So putting r and [tex]P_{0}[/tex] into (2):
P(d) = 120*([tex]4^{d-1}[/tex])
Noting that 4 = 2²:
P(d) = 120*([tex]2^{2(d-1)}[/tex])
P(d) = 120*([tex]2^{2d-2}[/tex])FOR d = 8:
P(d) = 120*([tex]2^{2d-2}[/tex])
becomes:
P(8) = 120*([tex]2^{2(8)-2}[/tex])
P(8) = 120*([tex]2^{16-2}[/tex])
P(8) = 120*([tex]2^{14}[/tex])
P(8) = 120*(16,384)
P(8) = 1, 966, 080What is (9 x 10^4) (6 x 10^-7)?
Answer:0.0008994
Step-by-step explanation:
it is decided that this barrel must be painted pink and the barrel's surface area is requested in order to determine the amount of paint needed. what is the surface area of the barrel g
The surface area of the barrel needs to be calculated in order to determine the amount of paint. The surface area of the barrel, including the lid, is 13 m²
Missing data from the problem:
radius of the barrel = 0.4 meters
height of the barrel = 1.2 meters
The shape of a barrel is cylinder. The surface area of the barrel, including the lid) is:
A = 2. πr² + 2. πr.h
Where:
r = radius
h = height
Plug the parameters into the formula:
A = 2. π(0.4)² + 2. π(0.4).(1.2)
A = 13 m²
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Find the values of Y and X
Given: ZADB = ZCBD ZABDZCDB m ZA= 3x + 15 mZC=8x-20 Find: x and m ZA A4 D B
Answer:
x = 7 , ∠ A = 36°
Step-by-step explanation:
since ∠ ADB ≅ ∠ CBD ( alternate angles )
and ∠ ABD ≅ ∠ CDB ( alternate angles )
then ABCD is a parallelogram
the opposite angles of a parallelogram are congruent , so
∠ C = ∠ A , that is
8x - 20 = 3x + 15 ( subtract 3x from both sides )
5x - 20 = 15 ( add 20 to both sides )
5x = 35 ( divide both sides by 5 )
x = 7
Then
∠ A = 3x + 15 = 3(7) + 15 = 21 + 15 = 36°
Answer: x = 7 and m∠A = 36
Step-by-step explanation:
Here ∠ADB ≅ ∠CBD and ∠ABD ≅ ∠CDB
This configuration is found when a quadrilateral has two parallel sides which have a diagonal as their transversal. Thus the figure is of parallelogram. In a parallelogram, opposite angles are equal. Thus m∠A = m∠C
⇒3x +15 = 8x - 20
⇒3x + 15 - 3x = 8x - 3x -20
⇒5x = 20 + 15
⇒x = 7
Now m∠A = (3X7) +15 = 36
PLEASE HELP NOW DUE AT 11 PM. Are the linear expressions equivalent? Drag the choices to the boxes to correctly complete the table. .
In these linear expressions one is equivalent which is 3- 2( - 2.6x + 2.1) = 5.2x - 1.2 and one is not .
What are linear expressions?An algebraic expression known as a linear expression has terms that are either constants or variables raised to the first power.
Alternatively pluging; we will see that none of the exponents can be greater than 1.
2x - 3(1.3x - 2.5) = 5.9x + 7.5
2x -3.9x + 7.5 = 5.9 + 7.5
-1.9x + 7.5 ≠ 5.9 + 7.5
thus linear expression is not equivalent.
3- 2( - 2.6x + 2.1) = 5.2x - 1.2
3 + 5.2x - 4.2 = 5.2x - 1.2
5.2x - 1.2 = 5.2x - 1.2
thus, linear expression is equivalent.
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3/4+(1/2+1/4) 2⋅2
NEED HELP.
Answer:
15/8 for exact form
1.875 for decimal form
And
1 and 7/8 for mixed number form
hope this helps you!
(also already in the simplest form :)
f(x)= x-6/2
g(x)=√x-4
Express the function gf in the form gf(x) = ...
Give your answer as simply as possible.
The function is given below
What is a function?
The value of a function f at an element x of its domain is indicated by f(x); the numerical value resulting from the function evaluation at a given input value is expressed by substituting x with this value; for example, the value of f at x = 4 is denoted by f(x) (4). When the function is not named and is represented by an expression E, the function's value at, say, x = 4 can be expressed by E|x=4. In science, engineering, and the bulk of the mathematical disciplines, functions are commonly used. Functions are claimed to be "the central objects of research" in most branches of mathematics.
The given function is
f(x) = x - 6/2
The function in gf is
g{f(x)} = √(x - 6/2) - 4
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The value of the required composite function is [tex]g(f(x))=\sqrt{x-\frac{6}{2} } -4[/tex].
What is a composite function?
When the result of one function is utilized as the input for another, a composite function is created.
Given that:
[tex]f(x)=x-\frac{6}{2}[/tex] and [tex]g(x)=\sqrt{x}-4[/tex]
To find the composite function [tex]g(f(x))[/tex], it is required to use the output of the first function as the input of the second function. It means that replace [tex]x[/tex] by [tex]f(x)[/tex] in the second function as:
[tex]g(x)=\sqrt{x}-4\\g(f(x))=\sqrt{f(x)}-4[/tex]
Now, substitute the value of [tex]f(x)[/tex] on the right side of the above equation as:
[tex]g(f(x))=\sqrt{x-\frac{6}{2}}-4[/tex]
Hence, the required answer is:
[tex]g(f(x))=\sqrt{x-\frac{6}{2}}-4[/tex]
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Choose the number and type of roots of each quadratic function.
Function
f(x)=x²-9x + 21
f(x) = x² + 16x - 64
f(x) = -4x²-4x²10x +84
f(x) = 3x² + 24
The number and type of roots of each quadratic function are:
f(x) = x² - 9·x + 21, Has complex rootsf(x) = x² + 16·x - 64 has two real and distinct rootsf(x) = -4·x² + 10·x + 84 has two real and distinct rootsf(x) = 3·x² + 24 has complex rootsWhat determines the type of root that a quadratic function has?The type of roots of a quadratic function is given by the value of the discriminant, which is the value under the square root of the quadratic formula.
The types of roots of a quadratic equation are;
Two real and distinct rootsTwo real and equal rootsComplex rootsThe roots or solution to the quadratic equation, a·x² + b·x + c = 0, are given by the quadratic formula, [tex]x = \dfrac{-b\pm \sqrt{b^2 - 4\cdot a \cdot c} }{2\cdot a}[/tex]
Where:
b² - 4·a·c is known as the discriminant of the quadratic equation.
The type of root of a quadratic equation is given by the discriminant, b² - 4·a·c, as follows:
If the discriminant, b² - 4·a·c is less than 0, then the quadratic equation has no roots or no real rootsIf b² - 4·a·c = 0, then the quadratic equation has two real and equal roots (or one real root)If the discriminant, b² - 4·a·c > 0, then the quadratic equation has two real and distinct roots.The given functions are:
f(x) = x² - 9·x + 21Comparing the above equation to the, general form of a quadratic equation, f(x) = a·x² + b·x + c, we have;
a = 1, b = -9, and c = 21
The discriminant is therefore, (-9)² - 4 × 1 × 21 = -3 < 0
The quadratic equation therefore, has complex roots.
f(x) = x² + 16·x - 64The quadratic equation, f(x) = x² + 16·x - 64 has a discriminant given as follows;
The discriminant is: 16² - 4 × 1 × (-64) = 512 > 0, therefore, the quadratic equation two real roots, given by the equation;
[tex]x = \dfrac{-16\pm \sqrt{16^2 - 4\times 1 \times 64} }{2\times 1}= \dfrac{-16\pm \sqrt{512} }{2}= \dfrac{-16\pm 16\cdot \sqrt{2} }{2}[/tex]
x = -8 + 8·√2 or x = -8 - 8·√2
f(x) = -4x² + 10·x + 84The value of the discriminant is 10² - 4 × (-4) × 84 = 1444 > 0, therefore, the equation has two real and distinct roots, given by the equation;[tex]x = \dfrac{-10\pm \sqrt{1444} }{2\times (-4)}= \dfrac{-10\pm 38 }{-8}[/tex]
[tex]x = \dfrac{28 }{-8}= -3.5[/tex] and [tex]x = \dfrac{-48 }{-8}= 6[/tex]
f(x) = 3·x² + 24The discriminant of the above quadratic equation is; 0² - 4 × 3 ×24 = -288 < 0
Therefore, the quadratic equation, f(x) = 3·x² + 24, has no real roots or complex roots
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When and where does the story The circuit take place?
Answer:
Mexico to the United States in 1947
Step-by-step explanation:
150 14 Solve for x. Round to the nearest tenth. 63.5 54.1 3.6 74.9
The given triangle is a right angled triangle having the follwoing sides;
Hypotenuse = x (longest side)
Opposite = 14 (side facing the given acute angle)
Theta = 15 degrees
Using the SOH trigonometry identity;
sin 15 = opposite/hypotenuse
sin15 = 14/x
x = 14/sin15
x = 14/0.2588
x = 54.09
x is approximately equal to 54.1. Option B is coorect
A ball is thrown directly upward from a height of 7 ft with an initial velocity of 28 ft/sec. The function s(t)= -16t+28t+7 gives the height of the ball, in feet, t seconds after it has been thrown. Determine the time at which the ball reaches the maximum height and find the maximum height.
Answer:
Brainliest Answer?
( 7 / 8 ) seconds
( 77 / 4 ) feet
Step-by-step explanation:
The question is a bit confusing but I will do it both ways. I will assume that you made a mistake copying over the function because the graph s( t ) is linear. Linear functions have a maximum value of infinity because it is an odd-degree polynomial.
AlgebraAssume that s( t ) = - 16t² + 28t + 7;
The equation forms an upside-down parabola which means it has a maximum value.
Complete the square to get the axis of symmetry and the maximum value of the parabola or use my very cool formula. The variables h and k represent the axis and max respectively.
Formulaax² + bx + c = a( x - h )² + k;
ax² + bx + c = a( x - ( - b / 2a ) )² + c - ( b² / 4a );
Completing the Squareax² + bx + c;
Take a as a factor.
a( x² + ( b / a )x + ( c / a ) );
Add and subtract the square of ( 1 / 2 ) of ( b / a ). This is called completing the square because it forms a perfect square trinomial.
a( x² + ( b / a )x + ( b / 2a )² - ( b / 2a )² + ( c / a ) );
Factorise the trinomial.
a( ( x + ( b / 2a ) )² - ( b / 2a )² + ( c / a ) );
Use the distributive property of multiplication.
a( x + ( b / 2a )² + a( ( c / a ) - ( b / 2a )² );
a( x + ( b / 2a )² + a( ( c / a ) - ( b² / 4a² ) );
Simplify the fractions.
a( x + ( b / 2a )² + c - ( b² / 4a );
SolutionSubstitute the values.
- 16( t - ( - 28 / 2( - 16 ) )² + 7 - ( ( 28 )² / 4( - 16 ) );
Time is the x-axis so we need to solve for the axis of symmetry.
h = ( - 28 / 2( - 16 ) );
h = ( - 28 / - 32 );
Simplify the fraction.
h = ( 7 / 8 );
Maximum height is the parabola's y of the vertex.
k = 7 - ( ( 28 )² / 4( - 16 ) );
k = 7 - ( ( 28 )( 28 ) / - 64 );
k = 7 - ( 784 / - 64 );
k = 7 - ( - 49 / 4 );
k = ( 28 / 4 ) + ( 49 / 4 );
k = 77 / 4;
triangle RST had coordinates: R(-2, 1) S(-8, 2) T(-4, 5) Draw the translation of RST 8 units right and 4 units down on your recording sheet. what are 3 coordinates of R'A. R'(-3, 6)B. R'(0, -2) C. R'(6, -3) D. R'(4, 1)
Since the translation is 8 units right and 4 units down, we have to add 8 to the x coordinate and subtract 4 to the y coordinate.
R=(-2,1)
R' = (-2+8,1-4)= (6,-3)
R' = (6,-3)
In a race, Kara ran eight- eighteenths of a kilometer and cycled sixteen-eighteenths of a kilometer. Estimate how many kilometers the race was in all.
a) 1/2 kilometer
b) 1 kilometer
c) 1 1/2 kilometers
d) 2 kilometers
Number of kilometers the race was in all is [tex]1\frac{1}{3}[/tex] kilometers.
Given that, Kara ran 8/18 of a kilometer and cycled 16/18 of a kilometer.
What is addition of two fractions?To add two fractions, with different denominators, we need to rationalise the denominators by taking out the LCM and make the denominator same. Then add the numerators of the fractions, keeping the denominator common.
Now, total distance in race
8/18 + 16/18
= (8+16)/18
= 24/18
= 4/3
= [tex]1\frac{1}{3}[/tex] kilometers
Therefore, number of kilometers the race was in all is [tex]1\frac{1}{3}[/tex] kilometers.
To learn more about the addition of a fractions visit:
https://brainly.com/question/17544795.
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What is the number sentence for "4 and N together make9"?
Given:
The number sentence for 4 and n
Required:
We have to find the given sentence
Explanation:
4 and N, simply means you mixed them up, you sum them up
your result is 9, 4+N=9
Required solution :
4+N=9
PLEASE HELP!!!!!!!!! It’s algebra
Answer:
See below
Step-by-step explanation:
From 5 to 10 mugs is 5 mugs
These cost 110 - 67.50 = 42.50
So each mug costs 42.50 / 5 = 8.50 each
With a 'base cost' of 25 dollars
(Base cost might be artwork, design, order processing, shipping or whatever.....but this amount is added to each order)
(As a check 20 mugs would be 25 + 20 (8.50) = 195 <====yep
150 mugs will then be 25 + 150 ( 8.50) = 1300 dollars