Ozone has a molecular formula of O3. If 7.92*1024 atoms of oxygen react to form ozone, how many
moles of ozone would be produced?

Answers

Answer 1

337.92 moles of Ozone will be produced

1 Oxygen atom is 8 g

1 mole of ozone, O3 = 8 * 3 = 24 g

7.92 * 1024 = 8110.08 g

1 mole = 24 g

? moles = 8110.08 g

? = 337.92 moles


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Answer 2

Ozone has a molecular formula of O3. If 7.92*1024 atoms of oxygen react to form ozone, then 337.92 moles of ozone will produce.

What is molecular formula?

Molecular formula is defined as an expression that defines a number of atoms of each element in one molecule of a compound.

It can also be defined as a chemical formula that gives the total number of atoms of each elements in each molecules of a substance.

Ozone is defined as a highly reactive gas composed of three oxygen atoms and form a layer above the earth surface called as ozone layer.

1 oxygen atom = 8 g

1 mole of ozone = 8 x 3 = 24 g

7.92 x 10²⁴ = 8110.08 g

24 g = 1 mole

So, 8110.08 g = 337.92 moles

Thus, Ozone has a molecular formula of O3. If 7.92*1024 atoms of oxygen react to form ozone, then 337.92 moles of ozone will produce.

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Related Questions

how would changing the proportions in an alloy change its properties

Answers

Answer:

An alloy is a mixture of two or more metals which is produced with a specific proportion between metals. So, if the proportion is changed the physical characteristic would be changed as well. For example, brass musical instruments are made of brass which is a mixture (an alloy) of zinc and copper in a specific proportion. If you change a proportion, you will change the physical characteristic of brass musical instruments, and a sound they produce will be different.

Explanation:

9. Using the balanced equation from Question #8, how many grams of lead will be produced if 2.54 grams of PbS is burned with 1.88 g of O2? Express your answer to the correct number of significant figures and you must show all work in the form of dimensional analysis as shown in Lesson 4. (Hint: be sure to work the problem with both PbS and O2).

Answers

Answer: 2.24 grams of Pb

Explanation:

Step 1

Balanced chemical reaction;

2PbS + 3O2 → 2Pb + 2SO3

Step 2

Moles of both PbS and O2

Moles = mass / molar mass

Moles of PbS = 2.54 g / 239.3 g/mol = 0.0108 moles

Moles of O2 = 1.88 / 32 g/mol = 0.0588 moles

Step 3

Finding the limiting reactant.

Limiting reactant, is that reactant which is completely used in the reaction;

If we assume that PbS is the limiting reactant;

We have 0.0588 moles of O2. This needs ( 0.0588 * 2) / 3 = 0.0392 moles of PbS to fully react. But we have only 0.0108 moles of PbS available. That means that the PbS will be completely consumed hence the limiting reactant

If we assume O2 is the limiting reactant;

We have 0.0108 moles of PbS. That needs ( 0.0108 * 3) / 2 = 0.0162 moles of O2. But we have 0.0588 moles of O2 which is in excess further confirming that PbS is the limiting reactant since it will be depleted in the reaction.

Step 4

Moles of lead

For this step we apply the mole ratios with the limiting reactant;

Mole ratio of PbS : Pb = 2 : 2 = 1 : 1

Therefore;

Moles of Pb = (0.0108 moles  * 1 ) 1

Moles of Pb =0.0108 moles

Step 5

Mass of Pb

Mass = moles * molar mass

Mass of Pb =0.0108 moles * 207.2 g/mol

Mass of Pb = 2.24 grams


Why do we have to decide what to do in a day?

Answers

Answer:

otherwise you will be bord and have nothing to do

Explanation:

Because people like to keep busy/have things to do.

Otherwise, we would just be blobs and do nothing.

What does the sum of oxidation numbers need to equal for a charged compound?

Answers

Answer:

The charge on the compound

Explanation:

The charge on the compound signifies that the compound is not in its neutral state.

Therefore, the oxidation state would be equal to the charge on the compound.

Answer:

The charge on the compound

Explanation:

The charge on the compound signifies that the compound is not in its neutral state.

Therefore, the oxidation state would be equal to the charge on the compound.

What is molarity of 47.0 g KCl dissolved in enough water to give 375 mL of solution?

Answers

This question provides us –

Weight of [tex] \bf KCl [/tex] is = 47 gVolume, V = 375 mL

__________________________________________

Molar Mass of [tex]\bf KCl [/tex] –

[tex]\qquad[/tex] [tex]\twoheadrightarrow\bf 39.0983 \times 35.453 [/tex]

[tex]\qquad[/tex] [tex]\twoheadrightarrow\bf 74.5513[/tex]

Using formula

[tex]\qquad[/tex] [tex]\purple{\twoheadrightarrow\bf Molarity _{(Solution)} = \dfrac{ W\times 1000}{MV}}[/tex]

[tex]\qquad[/tex] [tex]\twoheadrightarrow\bf Molarity _{(Solution)} = \dfrac{ 47 \times 1000}{74.5513\times 375}[/tex]

[tex]\qquad[/tex] [tex]\twoheadrightarrow\bf Molarity _{(Solution)} = \dfrac{47000}{27956.7375}[/tex]

[tex]\qquad[/tex] [tex]\twoheadrightarrow\bf Molarity _{(Solution)} = \cancel{\dfrac{47000}{27956.7375}}[/tex]

[tex]\qquad[/tex] [tex] \twoheadrightarrow\bf Molarity _{(Solution)} = 1.68117M [/tex]

[tex]\qquad[/tex] [tex]\pink{\twoheadrightarrow\bf Molarity _{(Solution)} = 1.7M} [/tex]

Henceforth, Molarity of the solution is = 1.7M

___________________________________________

73.5 mol of P4O10 contains how many moles of P ? moles of P:

Answers

Answer:

294 moles of P

Explanation:

For every 1 mol of P4O10 contains 4 mol of P

so;

73.5 mol P4O10 × 4 mol P

1 mol P4O10

= 73.5 × 4

= 294 moles of P

73.5 mol of [tex]P_4O_{10}[/tex] contains 294 moles of P. In 1 mole of [tex]P_4O_{10}[/tex], there are 4 moles of P.

The International System of Units (SI) uses the mole (abbreviated as mol) as its basic unit to measure the amount of a substance. It is mostly used in chemistry and is defined as the volume of a substance that contains exactly 12 grammes of pure carbon-12 in terms of atoms (or equivalent amounts of molecules, ions, or particles). The fundamental notion that atoms combine in whole-number ratios to form compounds serves as the foundation for the concept of the mole. It makes it simple for scientists to convert between a substance's mass and the quantity of atoms or molecules it contains.

In 1 mole of [tex]P_4O_{10}[/tex], there are 4 moles of P.

=4 × 73.5 moles of P.

= 294 moles of P

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0.75 mol hydrogen sulfide (H2S)

Answers

Answer:

• Information and media literacy

Directions

Read the instructions for this self-checked activity. Type in your response to each question, and check your answers. At the end of the activity, write

brief evaluation of your work.

Activity

Part A

Now that you have analyzed the resources provided in the lesson, write your own response to the question, What is the main reason the US Civil

War started? Base your

Explanation:

• Information and media literacy

Directions

Read the instructions for this self-checked activity. Type in your response to each question, and check your answers. At the end of the activity, write

brief evaluation of your work.

Activity

Part A

Now that you have analyzed the resources provided in the lesson, write your own response to the question, What is the main reason the US Civil

War started? Base your

Answer: =378.94000053g

Explanation:

I think that explains it

A 0.205 g sample of CaCO3 (Mr = 100.1 g/mol) is added to a flask along with 7.50 mL of 2.00 M HCl. CaCO3(aq) + 2HCl(aq) → CaCl2(aq) + H2O(l) + CO2(g)Enough water is then added to make a 125.0 mL solution.

Answers

The volume of the NaOH used is calculated as 14 mL.

What is stoichiometry?

The term stoichiometry has to do with the calculation of the amount of substance in a reaction using mass - mole or mass - volume relationship.

Here;

Number of  moles of CaCO3 = 0.205 g/100.1 = 0.00205 moles

Number of  moles of HCl = 2.00 M * 7/1000 L = 0.014 moles

2 moles of HCl reacts with 1 mole of CaCO3

x moles of HCl reacts with 0.00205 moles of CaCO3

x = 0.00205 moles * 2/1 = 0.0041 moles

Hence HCl is the excess reactant

Amount of excess HCl =  0.014 moles -  0.0041 moles = 0.0099 moles

Concentration of excess HCl reacted = 0.0099 moles/125 * 10^-3 = 0.0792 M

Using;

CAVA/CBVB = NA/NB

CAVANB = CBVBNA

VB = CAVANB/CBNA

VB = 0.0792 M * 10 mL * 1/ 0.058 M

VB = 14 mL

Missing parts;

A 0.205 g sample of caco3 (mr = 100.1 g/mol) is added to a flask along with 7.50 ml of 2.00 m hcl. caco3(aq) + 2hcl(aq) → cacl2(aq) + h2o(l) + co2(g) enough water is then added to make a 125.0 ml solution. a 10.00 ml aliquot of this solution is taken and titrated with 0.058 m naoh. naoh(aq) + hcl(aq) → h2o(l) + nacl(aq) how many ml of naoh are used?

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I2 is produced by the reaction of 0.4235 mol of CuCl2 according to the following equation: 2CuCl2+4KI⟶2CuI+4KCl+I2. What volume of I2 gas is produced at STP?

Answers

Answer: 4.7432 L

Explanation:

Use stoichiometry: .4235 mol CuCl2 (1 mol I2 / 2 mol CuCl2)(22.4 L / 1 mol I2) = 4.7432 L :)

Oxidation Number of Carbon in C6H12O6​

Answers

Correct option is C)

C

6

H

12

O

6

6x+12−12=0

C has oxidation number = 0

Sorry if my answers wrong.

one revolution of the moon around earth takes_______ days.

Answers

Answer:It’s important to know WHY. Great explanations are what makes Brainly awesomeExplain everything. Imagine that the person who was asking, knows nothing at all so you need to start from the very beginningAlways include the steps and/or background required to get to the final answer. Let’s help other people understand and solve future problems on their ownShow all the calculation if it is a numerical question.

Explanation:

Select the correct answer.
Iron oxide reacts with aluminum to give aluminum oxide and iron. What kind of chemical reaction is this?

Answers

Answer:

Single-replacement reaction

Explanation:

Single-replacement reactions, aka. single-displacement reactions, involve one element/ion in a compound being replaced by another element/ion. In this case, aluminum is replacing the iron in the compound.

If you need help visualizing, the equation looks like this:

FeO + Al³⁺ --> AlO + Fe³⁺

A compound is 69.9% Fe and 30.1% O. What is the empirical formula?

Answers

Answer:

Fe2O3

Explanation:

get the ratio for both Fe and O using relative atomic mass and the percent as the mass

why are hydrocarbons insoluble in water

Answers

Answer:

Hydrocarbons are insoluble in water because they are non-polar compounds while water is a polar solvent. By principle, like dissolves like. Nonpolar solvents dissolve nonpolar solutes and polar solvents dissolve polar solutes.

Explanation:

please brainliest me

hope it helps

Hydrocarbons are insoluble in water because :-

1)Hydrocarbons are nonpolar whereas water is polar. (like dissolves like).

2) Hydrocarbons and water do not exhibit appropriate solvent-solute interactions. Hydrocarbons only form very weak dispersion forces whereas water produces strong polar hydrogen bonding interactions.

Explanation:

Hope it helps you!!

Question 13 options:
A) What is the volume (L) of 2.5 moles of oxygen at STP?


B) What is the volume (L) of 2.5 moles of nitrogen at STP?

Answers

At STP

one mol of oxygen weighs=22.4L

No of moles=2.5mol

Total volume:-

2.5(22.4)56L

What does it mean that our solar system is about 25,000 light-years from the center of the Milky Way?(1 point) It took our solar system 25,000 light-years to form. It took our solar system 25,000 light-years to form. It would take about 25,000 years for light to travel from our solar system to the center of the Milky Way. It would take about 25,000 years for light to travel from our solar system to the center of the Milky Way. There are 25,000 stars between our solar system and the center of the Milky Way. There are 25,000 stars between our solar system and the center of the Milky Way. It would take 25,000 years for humans to fly, using a rocket ship, from our solar system to the center of the Milky Way.

Answers

Answer: A light year is a measure of distance, for example, there is a big comet 5 light years away, it takes 5 years for light to get to the comet, and just like the galaxy, it would take 25,000 years for light to reach the center of the galaxy.

(Squirrels gather and store acorns for the winter, which is an example of a ___________ adaptation.)

A. Mimicry

B. Behavioral

C. Structural

D. Environmental

Answers

Answer:

C

Explanation:

Identify the independent /manipulated variable

Answers

Answer:

independent- test variable

manipulated - outcome variable; if needed, there could be changes.

Explanation:

knowledge

What type of molecule is cis-2-pentene?
O A. Alkane
B. Alkyne
C. Branched alkane
D. Alkene

Answers

The given molecule, cis-2-pentene, is an Alkene. The correct option is D. Alkene

Saturated & Unsaturated Hydrocarbons

Alkanes, Alkenes, and Alkynes are examples of simple hydrocarbons.

Alkanes are the simplest organic compounds. They have only single bonds between carbon atoms and are called saturated hydrocarbons. Their nomenclature usually ends in -ane.

Alkenes on the other hand have at least one carbon-carbon double bond. Their nomenclature usually ends in -ene.

Alkynes have one or more carbon-carbon triple bonds.Their nomenclature usually ends in -yne. Alkenes and alkynes are called as unsaturated hydrocarbons.

The given molecule is cis-2-pentene

Since the name of the molecule ends in "ene", the molecule is an Alkene.

Hence, the given molecule, cis-2-pentene, is an Alkene. The correct option is D. Alkene

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Answer: Alkene

Explanation: just took tha test

how many grams of lead II chloride are produced from the reaction of 15.3 g of NaCl and 60.8 gr of Pb(NO3)2?

Answers

The mass, in grams, of lead that will be produced from the illustrated reaction would be 71.47 grams

Stoichiometric reactions

From the balanced equation of the reaction:

Pb(NO3)2 + 2NaCl ---> PbCl2 + 2NaNo3

Mole ratio of Pb(NO3)2 and NaCl = 1:2

Mole of 15.3 g NaCl = 15.3/58.4

 = 0.257 moles

Mole of 60.8 g PbCl(NO3)2 = 60.8/331.2

  = 0.184 moles

Thus, NaCl is limiting.

Mole ratio of NaCl to PbCl2 = 1:1

Mas of 0.257 moles PbCl2 = 0.257 x 278.1

 = 71.47 grams

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Determine which reaction has the highest activation energy.
A. Burning charcoal
B. Melting ice
C. Combusting gasoline
D. Reacting metal and acid

Answers

Answer:

A.

Explanation:

Which would lower the reaction rate?

A. Increasing the concentration of reactants.

B. Increasing the temperature of the system.

C. Raising the value of k.

D. Decreasing the temperature of the system.

Answers

Answer:

D. Decreasing the temperature of the system

Explanation:

The volume of a gas is 3.0 L, the pressure is 1.0 atm, and the temperature is 300 K. A chemist changes one factor while keeping another constant so that the new volume is 2.0 L. Which of the following could be the new conditions?

Group of answer choices

The final pressure is 0.5 atm, while temperature is kept constant.

The final temperature is 200 K, while pressure remains constant.

The final pressure is 0.2 atm, while temperature is kept constant.

The final temperature is 350 K, while pressure remains constant.

Answers

Given the data from the question, the final temperature is 200 K, while pressure remains constant.

Basic concepts

To obtain the correct answer to the question, we shall consider two conditions:

Case 1 (temperature is constant) Case 2 (pressure is constant)

Case 1 (Temperature is constant)

We shall determine the new pressure by using the combined gas equation (P₁V₁ / T₁ = P₂V₂ / T₂) as illustrated below:

Initial volume (V₁) = 3 LInitial pressure (P₁) = 1 atmTemperature = constant New Volume (V₂) = 2 L New pressure (P₂) =?

P₁V₁ / T₁ = P₂V₂ / T₂

Since temperature is constant, we have:

P₁V₁ = P₂V₂

3 × 1 = P₂ × 2

3 = P₂ × 2

Divide both side by 2

P₂ = 3 / 2

P₂ = 1.5 atm

Case 2 ( pressure is constant)

We shall determine the new temperature by using the combined gas equation (P₁V₁ / T₁ = P₂V₂ / T₂) as illustrated below:

Initial volume (V₁) = 3 LInitial pressure (T₁) = 300 KPressure = constant New Volume (V₂) = 2 L New pressure (T₂) =?

P₁V₁ / T₁ = P₂V₂ / T₂

Since pressure is constant, we have:

V₁ / T₁ = V₂ / T₂

3 / 300 = 2 / T₂

1 / 100 = 2 / T₂

Cross multiply

T₂ = 100 × 2

T₂ = 200 K

SUMMARY

when the temperature is constant, the new pressure is 1.5 atmWhen the pressure is constant, the new temperature is 200 K

From the calculations made above, we can conclude that the correct answer is:

The final temperature is 200 K, while pressure remains constant.

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Answer:

b

Explanation:

how do the parts of the liverworts above the soil get the minerals from the soil that are needed for plant processes

Answers

Answer:

I don't know but I'm curious now

what is the percent (mass/volume) if 22 g of kcl is added to 75 ml of water to make 83 ml of solution

Answers

Considering the definition of volume percentage, the mass/volume percent in this solution is 26.5%.

Definition of mass/volume percent

Mass/volume percent is a measure of concentration that indicates the number of grams of solute in each 100 mL of solution.

In other words, the volume percent of a component in the solution is defined as the ratio of the mass of solute that is present in a solution, relative to the volume of the solution, as a whole.

The volume percentage of a solution is determined by the following expression:

[tex]mass/volume percent=\frac{mass of solute}{volume of solution}100[/tex]

Mass/volume percent in the solution

In this case, you know:

mass of solute= 22 gvolume of solution= 83 mL

Replacing in the definition of mass/volume percent:

[tex]mass/volume percent=\frac{22 g}{83 mL}100[/tex]

Solving:

mass/volume percent= 26.5 %

Finally, the mass/volume percent in this solution is 26.5%.

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the ability of atoms to attract electrons from surrounding atoms is called

Answers

Answer:

Electronegativity

Explanation:

The ability of an atom to attract itself an electron pair shared with another atom in a chemical bond.

. Calculate how many times greater the change in phosphorous levels between 1965 and 1975 is than between 2008 and 2014. Show your work.

Answers

The number of times phosphorous is greater in not visible in the data

How to calculate the change in Phosphorus levels

The steps involved for calculating the times the change in phosphorus level are :

First step: Determine the difference between Phosphorus levels in 1965 and 1975

Second step: Determine the difference between Phosphorus levels in 2008 and 2014

Last step: Determine the quotient by dividing first step by second step

Hence can conclude that The number of times phosphorous is greater in not visible in the data.

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Attached below is the missing Image related to your question

Starting with the following equation,
BaCl2(aq) + Na3PO4(aq) → Ba3(PO4)2(S) + NaCl(aq)

Calculate the mass in grams of BaCl2 that will be required to produce 50.5 grams of Ba3(PO4)2.

Answers

In the double displacement reaction between BaCl₂ and Na₃PO₄, 52.4 g of BaCl₂ are required to produce 50.5 g of Ba₃(PO₄)₂.

What is stoichiometry?

Stoichiometry refers to the relationship between the quantities of reactants and products before, during, and following chemical reactions.

Step 1: Write the unbalanced equation.

BaCl₂(aq) + Na₃PO₄(aq) → Ba₃(PO₄)₂(s) + NaCl(aq)

Step 2: Balance the equation.

We will use the trial and error method. We will:

Multiply BaCl₂ by 3 to balance Ba atoms.Multiply Na₃PO₄ by 2 to balance P atoms.Multiply NaCl by 6 to get the balanced equation.

3 BaCl₂(aq) + 2 Na₃PO₄(aq) → Ba₃(PO₄)₂(s) + 6 NaCl(aq)

Step 3: Calculate the mass of BaCl₂ required to produce 50.5 g of Ba₃(PO₄)₂.

The mass ratio of BaCl₂ to Ba₃(PO₄)₂ is 624.69:601.93.

50.5 g Ba₃(PO₄)₂ × 624.69 g BaCl₂/601.93 g Ba₃(PO₄)₂ = 52.4 g BaCl₂

In the double displacement reaction between BaCl₂ and Na₃PO₄, 52.4 g of BaCl₂ are required to produce 50.5 g of Ba₃(PO₄)₂.

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write an equation to show the effect of heat on the nitrate of silver​

Answers

Answer:

2AgNO³(l) → 2Ag(s) + O²(g) + 2NO²(g)

Explanation:

I used powers ³,²,²

So change them to be down


If 1.76 g of an ideal gas occupy 1.0 L at standard temperature and pressure (STP), what is the molar mass of the gas?

Answers

Answer:

Explanation:

Whenever you see molar masses in gas law questions, more often than not density will be involved. This question is no different. To solve this, however, we will first need to play with the combined ideal gas equation PV=nRT to make it work for density and molar mass. The derivation is simple but for the sake of time and space, I will skip it. Hence, just take my word for it that you will end up with the equation:M=dRTPM = molar mass (g/mol)d = density (g/L)R = Ideal Gas Constant (≈0.0821atm⋅Lmol⋅K) T = Temperature (In Kelvin) P = Pressure (atm)As an aside, note that because calculations with this equation involve molar mass, this is the only variation of the ideal gas law in which the identity of the gas plays a role in your calculations. Just something to take note of. Back to the problem: Now, looking back at what we're given, we will need to make some unit conversions to ensure everything matches the dimensions required by the equation:T=35oC+273.15= 308.15 KV=300mL⋅1000mL1L= 0.300 LP=789mmHg⋅1atm760mmHg= 1.038 atmSo, we have almost everything we need to simply plug into the equation. The last thing we need is density. How do we find density? Notice we're given the mass of the sample (0.622 g). All we need to do is divide this by volume, and we have density:d=0.622g0.300L= 2.073 g/LNow, we can plug in everything. When you punch the numbers into your calculator, however, make sure you use the stored values you got from the actual conversions, and not the rounded ones. This will help you ensure accuracy.M=dRTP=(2.073)(0.0821)(308.15)1.038= 51 g/molRounded to 2 significant figuresNow if you were asked to identify which element this is based on your calculation, your best bet would probably be Vandium (molar mass 50.94 g/mol). Hope that helped :) 

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