4NaOH + 4HCI - NaCl + H20

Answer:

1.44 g/mL

Explanation:

total mass is mass of the flask plus mass of the solution

TM = Flask + H2O2

88.5 = 16.5 + x

x = 72.0 gram

density = mass/volume

H2O2 density = 72/50

= 1.44 g/mL

because they need a medium to travel they can travel everywhere if they got the medium

Answer: D

Explanation: I took the quiz! Module 04.06! Have a good day!

Answer: Water level remains same as there is no difference in concentration gradient.

Explanation: When concentration inside and outside of the cell membrane is the same, no transport takes place and the levels will remain the same.

Answer:

do you have a picture of the choices?

Answer:

RbF2 + Ca

Explanation:

Since Rb is located in IIA as well as Ca, Rb has ion form Rb2+

Hence CaF2 + Rb → RbF2 +Ca

Please be reminded, this answer may not be 100% correct

Answer:

The attractive force between the sodium and chloride ions has a magnitude of -2.94 x 10⁻⁹ N

Explanation:

An electron is a negatively-charged particle. The charge on an electron is -1.6 x 10⁻¹⁹ C. This is also known as the fundamental unit of charge, e. A proton has the same charge as as electron but its charge is positive.

The charge on the chloride ion is negative and is due to an electron whereas the charge on the sodium ion is positive and is due to a proton.

The magnitude of the force of attraction between two charges is given by the Coulomb's law: F = Kq₁q₂/r²

where K is a constant = 9 x 10⁹ N.m₂.C⁻², q₁ = -1.6 x 10⁻¹⁹ C, q₂ = +1.6 x 10⁻¹⁹ C, r = 0.28 nm = 0.28 x 10⁻⁹ m

F = {(9 x 10⁹ N.m₂.C⁻²) (-1.6 x 10⁻¹⁹ C) (+1.6 x 10⁻¹⁹ C)} / (0.28 x 10⁻⁹ m)²

F = -2.94 x 10⁻⁹ N

Therefore, the attractive force between the sodium and chloride ions has a magnitude of -2.94 x 10⁻⁹ N

Answer:

migratory distribution

Explanation: The pattern of migratory distribution of species may require collaboration between different countries for effective preservation. This is because species migration can make them enter different territories, which will need to provide an effective level of preservation for species survival

Answer:

A yan hehehehe

salamat puso ma ah

Answer:

52.8 Liters

Explanation:

Gay-Lussacs law states that P1/T1 = P2/T2

if:

then:

45/298.1 = P2/328.1

P2 = 52.8

The new volume of the balloon is 52.8 Liters this can be calculated by using gas laws.

Charles law states the volume occupied by a fixed amount of gas is directly proportional to its absolute temperature. It is given by

V₁/T₁ = V₂/T₂

What information do we have?

V₁ = 45 L

T₁ = 25 + 273.1 =298.1 K

T₂ = 55 + 273.1 = 328.1 K

To find:

V₂= ?

On substituting the values:

45/298.1 = V₂/328.1

V₂ = 52.8 L

Thus, the volume of the balloon is 52.8 liters.

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Answer:

an atom is the smallest part of an element that has the properties of that element

it can't be broken further into smaller substances

an element is the simplest chemical

it consists of one type of atoms

so you can consider atoms as the building block of an element

The mass of the boat is equal to the mass of the liquid which is displaced by placing the boat in the liquid.

Archimedes' Principle states that the buoyant force of the object is equal to the weight of the water which is displaced by the boat. If the weight of the water that is displaced by the boat is less than that of the weight of the boat, then in this case the boat sinks. Archimedes' principle or the buoyant force is very useful for the calculation of the volume of an object that does not have a regular shape.

The mass of the displaced liquid is always equal to the volume of the liquid multiplied by the density of the fluid. When a boat is placed in the water, the volume of displaced water is equal to the mass of the boat which is placed in it.

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Answer:

dating and correlating the strata in which it is found

Explanation:

Answer:

The correct answer is A:The age of an unfamiliar layer of rock

Explanation:

I promise that I got it correct on A P E X <3

Answer:

True

Explanation:

Answer: True

Explanation:

Answer: Body plans change as new challenges arise.

Explanation:

The mollusks are the invertebrate animals. They live marine environment. They live in shallow waters. They have been found in variety of marine habitats so this indicates their adaptiveness to different conditions. They have body plan that comprises of shell, mantle, radula and muscular foot that helps in survival and adaptation in different conditions. The shell and mantle are hard structures which protect these animals from predators and also help them to camouflage. Also the muscular foot helps in locomotion. Radula helps in feeding. Oysters, snails are some examples of mollusks.

Answer:

Dehydration synthesis reactions build molecules up and generally require energy, while hydrolysis reactions break molecules down and generally release energy. Carbohydrates, proteins, and nucleic acids are built up and broken down via these types of reactions, although the monomers involved are different in each case.

Explanation:

Answer:

oKaY?!

Explanation:

Answer:

1. True

2. resting position

3. 5 cm

4. Compressions

5. false

6. 7 m

7. true

8. second one has more amplitude

9. True

10. true

Explanation:

Answer:

true mark me brainlist

Explanation:

Answer - B Atoms in the original substances are arranged in a different way to make new substances

Answer:

Estoy deprimido y odio la vida. Así que sí

Answer:

A. catalyst.

Explanation:

Catalyst is something that causes things to decay. I think catalyst is the right answer from what i know from Miraculous Ladybug... Did you know the show was originally going to be an anime?

Answer:

i. 3 moles.

ii. 132.03 grams.

iii. 105.6 grams.

Explanation:

Hello!

In this case, given the balanced chemical reaction, we can proceed as follows:

i. By starting with 5 moles of oxygen, via the 5:3 mole ratio we compute the produced moles of CO2:

[tex]n_{CO_2}=5molO_2*\frac{3molCO_2}{5molO_2} =3molCO_2[/tex]

ii. Now, since we have previously computed the moles of CO2 from the same moles of oxygen, by using its molar mass (44.02 g/mol), we obtain:

[tex]m_{CO_2}=3molCO_2*\frac{44.01gCO_2}{1molCO_2} =132.03gCO_2[/tex]

iii. Now, we need to combine the previously used two proportional factors for the calculation of the mass of CO2 from 128.00 grams of oxygen (molar mass 32.00 g/mol):

[tex]m_{CO_2}=128.00gO_2*\frac{1molO_2}{32.00gCO_2}*\frac{3molCO_2}{5molO_2}*\frac{44.01gCO_2}{1molCO_2}\\\\m_{CO_2}=105.6gCO_2[/tex]

Best regards!

Answer: in this ecosystem tuna fish are considered predators and small fishes are their prey.

Explanation: This is just an easy smart guess why? because the Tuna fish(predator) eat the small fishes(prey) as if what it looks like in the chart.

Im not sure about this question but i hope this helps

Answer:

in this ecosystem tuna fish are considered predators and small fishes are their prey.

Explanation:

Answer:

d. Urea nitrate

Explanation:

Urea nitrate is a fertilizer-based explosive that is produced in one step by reaction of urea with nitric acid. The is an exothermic reaction, therefore, necessary steps and precautions must be taken to ensure safety during the process. The equation of the reaction is given below:

(NH₂)₂CO (aq) + HNO₃ (aq) → (NH₂)₂COHNO₃ (s)

It is as easily-made explosive and can also be used as a catalyst in Diels-Alder reactions of aromatic amines.

In the presence of water, urea nitrate readily decomposes to its original components, urea and nitric acid.

On its own, urea  is commonly used as a deicer for sidewalks as it is a noncorrosive de-icing material. However, it is a more costly method of deicing,  compared to other methods and it is best used where water runs off into vegetation than into a water-body or a storm drain because of its high-oxygen demand which could result in its reducing the oxygen level of the water body. It It is readily found in nature (in our urine) and is also  synthesized artificially.  It has a very high nitrogen content, and is most often used as a nitrogen‐based fertilizer.

B) loses electrons and is oxidised

Its oxidation number is 0 in Co(s) and +2 in Co(C2H302)2(aq), hence it gets oxidised

In the reaction as mentioned below:-

[tex]Co(s) + Ni(C2H302)2aq -- > Co(C2H3O2)2aq + Ni(s)[/tex]

As shown in reaction cobalt losses elections so the reaction is oxidised.  Thus, option b is correct.

Oxidation is a type of reaction in which loss of electrons and gain of protons is takes place during a reaction by molecules, atom or ion. Oxidation takes place when the oxidation state of a molecule, atoms or ion is increased.

The opposite reaction is called as reduction in which gains of electron and loss of protons is takes place . In reduction reaction the oxidation state of molecules, atoms or ion is decreased.

Oxygen has been added to a compound as an older method of oxidation.  Although oxygen is typically added to a compound in compliance with the loss of electrons requirements and the oxidation state increase.

Therefore, we can say that in the reaction

[tex]Co(s) + Ni(C2H302)2aq -- > Co(C2H3O2)2aq + Ni(s)[/tex]

As shown in reaction cobalt losses elections so the reaction is oxidised.  Thus, option b is correct.

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Answer:

¹/3 C3H8(g) + ⁵/3 O2(g)

Explanation:

The coefficient before every molecule is representative of the number of moles. We can represent it in ration form so as to calculate the question;

C₃H₈(g) + 5 O₂(g) → 3 CO₂(g) + 4 H₂O(l) means;

For every 1 mole of C₃H₈(g) and 5 moles of  O₂(g) produces  3 moles of  CO₂(g) and 4 moles of H₂O(l).

Therefore to produce 1.00 mole of CO₂(g);

We represent it in ratio;

C₃H₈(g) : CO₂(g)

1  :     3

For more on evaluating moles in chemical reactions check out;

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We can write:

5/4 = 3,8/x

Solving for x:

x = 3,04 mols of H2O

Calculating the H2O mass:

M H2O = 18 g/mol

n = m/M

Solving for m:

m = 54,72 g of water

****************************

Using the same, but with molar mass:

M CO2 = 44 g/mol => 3 x 44 = 132 g

M O2 = 32 g/mol => 5 x 32 = 160 g

160/132 = x/90,6

solving for x:

x = 109,82 g if CO2

Answer:

[tex]0.1090\ \text{M}[/tex]

Explanation:

Volume of [tex]KOH[/tex] = 41.22 mL

Molarity of [tex]KOH[/tex] = 0.1322 M

Number of moles of [tex]KOH[/tex]

[tex]n=\text{Molarity}\times \text{Volume of }KOH\\\Rightarrow n=0.1322\times 41.22\times 10^{-3}\\\Rightarrow n=0.005449284\ \text{mol}[/tex]

2 moles of [tex]KOH[/tex] reacts with 1 mole of [tex]H_2SO_4[/tex]

So,

[tex]0.005449284\ \text{mol}[/tex] of [tex]KOH[/tex] reacts with M mole of [tex]H_2SO_4[/tex]

[tex]M=\dfrac{0.005449284}{2}=0.002724642\ \text{mol}[/tex]

Volume of [tex]H_2SO_4=25\times 10^{-3}\ \text{L}[/tex]

Concentration of [tex]H_2SO_4[/tex] is

[tex]M=\dfrac{0.002724642}{25\times 10^{-3}}\\\Rightarrow M=0.10898568\approx 0.1090\ \text{M}[/tex]

The concentration of the unknown [tex]H_2SO_4[/tex] solution is [tex]0.1090\ \text{M}[/tex].