Answer:
3x^2+1
Step-by-step explanation:
you cannot add in the 3x^2 and the -4 and 5 but you can add the -4 and the 5
I hope this helps!
Step-by-step explanation:
3x to the power 2 is 9x;
New equation: 9x-4+5 = 0
9x- (4+5) = 0
9x-9=0
x=1
HELP PLEASEEEEEEEEEEE
Answer:
I not see the number 2
I think that is number 2
Answer:
first and last one should be the answer (not sure about the first, cant see it too good)
simplify 12x⁵y² ÷ 3x²y
Answer:
f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)
Step-by-step explanation:
Please Solve Brainliest and 10 points!
Answer:
x=20°
Step-by-step explanation:
statements:1.) m<DOB = m<DOE + m<BOE (or m<EOB)
2.) m<DOB = 90°+x
3.) m<AOC = m<DOB
4.) 110° = 90° + x
5.) x = 20°
reasons:1.) given
2.) substitution
3.) vertical/reflexive
4.) substitution
5.) algebra
324 soldiers queued up such that the number of queues is equal to the number of soldiers in each queue. find the number of queues
VODY VON
Dom
18. Mr. Cook's class has a female student to male student ratio of 3:2. If Mr. 5 points
Cook's class has 18 girls, how many boys does he have?
17 boys
5 boys
12 boys
16 boys
Math To Do, i-Ready X G isabella belongs to a fitness club X + student/dashboard/home sabella belongs to a fitness club. She paid an initial fee of $50 when she joined and also pays $10 per month. Since becoming a member of the fitness club, Isabella has paid a total of $240. Use the drop-down menus to complete the statements about the length of time that Isabella has been a member of the fitness club. Click the arrows to choose an answer from each menu.
The equation Choose can be used to determine the value of the number of months Isabella has been a member of the fitness club. She has been a member of the fitness club for Choose months.
Answer: 19 months
Step-by-step explanation:
given data:
amount paid initially when joining the club = $50.
monthly payments made = $10.
total amount paid since joining the club = $240.
Solution:
= 10X + 50 = 240
collect like terms
= 10X = 240 – 50
10X = 190
divide both sides by 10
10X/10 = 190/10
X = 19
isabella has been a member of the club for 19 months.
Christina's ice cream parlor sold 60 vanilla cones on the first day of summer. If the goal is to increase the number of vanilla cones sold each day by 4, how many will be sold 20 days later?
1280 cones because you would add 60 +4 and multiply by 20, and would get 1280 cones.
how do you solve 1/2x=6
Answer:
x=12
Step-by-step explanation:
multiply 2 from both sides to isolate x
then u should end up with 1x=12
he is reading a novel into passive voiceWhat is the simplified form of the expression? 5 + 3(2)
Answer:
The answer is 11
hence 5 + 6 = 11
Answer:
hi
Step-by-step explanation:
[tex]5 + 3(2) = 11[/tex]
probably…
Could you answer this please a lot of points to you
Answer:
Step-by-step explanation:
13/16 dived by 5/6 = 9/40
7 dived by 1/6 = 42
2 1/5 dived by 1 1/3 = 1 13/20
2 1/7 dived by 3/28 = 20
Factorise fully
-12a - 16
please do quick, first to answer marked brainiest!!
Answer:
-4( 3a+4)
Step-by-step explanation:
-12a - 16
-4*3a -4*4
Factor out a -4
-4( 3a+4)
While attending a baseball game, Eva buys hamburgers and hotdogs for her family. The number of hot dogs bought is five more than the number of hamburgers bought. Hamburgers cost $6.25 each and hot dogs cost $3.75 each. Eva spent a total of $58.75 on the hamburgers and hot dogs.
Answer:
2.35 hamburgers
Step-by-step explanation:
H6.25 + H18.75 = 58.75
Jana and Jenn are training to run a race. Jana runs 3 miles in 1/3 hour. Jenn runs 5 miles in 3/4 hour. Who runs faster, and what is the unit rate of her speed in minutes per mile?
Answer:
Jenn runs faster at 9 minutes/mile.
Step-by-step explanation:
Jana runs 3 miles in 1/3 hour.
1/3 hour is equivalent to 1/3*60 = 20 minutes
The ratio time/distance is the reciprocal of the speed and is greater as the speed is lower and vice-versa.
This ratio for Jana is 20/3=16.7 minutes/mile
As for Jenn, she runs 5 miles in 3/4 hour.
3/4 hour is equivalent to 3/4*60=45 minutes
The ratio time/distance is 45/5=9 minutes/mile
Since Jenn has a lower ration, her speed is greater than Jana's, thus Jenn runs faster.
Nicole buys candy that costs $4 per pound. She will spend more than $28 on candy. What are the possible numbers of pounds she will buy?
Determine the number that can be used in place of the question mark to make the
equation true.
3^? = 27
Answer:
3
Step-by-step explanation:
You just divide 27 by 3, then divide that answer by 3, and keep doing that until you get to 1:
27/3
9
9/3
3
3/3
1
3^x = 27
3^3 = 27
3 x 3 x 3 = 27
9 x 3 = 27
27 =27
1079 divided by 4 Yeah Also whoever helps thank you :D
Answer:
269.75
Hope this helps:)
Step-by-step explanation:
NEED HELP WITH MATH! Will Give Brainliest! Image is below.
Enter the correct answer in the box. Write the sum of √28x^6 + 4√7x^6 in simplest form, if x ≠ 0.
Answer:
21.97025026/250
3252614683754629158741032465x93756356872264881+432757232878247-3243566=
Answer:
bout 7
Step-by-step explanation:
Answer:3.049533e+44 to be exact
Step-by-step explanation:
Drag the operator to the correct location on the image. Which operation results in a trinomial?
Answer:
-
Step-by-step explanation:
I took the test
The correct operator that enters a circle is a subtraction sign.
Given the expressions
[tex](4x^5-8x) ()(3x^2-8x+9)[/tex]
We need to know which sign goes into the bracket that will give a trinomial when simplified.
A trinomial is a function containing 3-terms.
Using the subtraction sign.
[tex](4x^5-8x) - (3x^2-8x+9)[/tex]
Expand
[tex]= 4x^5-8x - 3x^2+8x-9\\= 4x^5-3x^2-8x+8x-9\\=4x^5-3x^2+0-9\\=4x^5-3x^2-9[/tex]
Since the resulting term is a trinomial (3 terms), hence the correct operator that enters a circle is a subtraction sign.
Learn more here: https://brainly.com/question/1320408
* Pending
This map shows the organization that was
association of nearly 30 countrior
find the value of x
I have to show the work
Answer:
x = 39
Step-by-step explanation:
A circle is made up of 360 degrees
235+ 54+ x+32 = 360
Combine like terms
x+321=360
Subtract 321 from each side
x+321-321 = 360-321
x = 39
PLEASE HELP!!! ILL GIVE BRANLIEST *EXTRA POINTS* dont skip :((
Answer:
-3.21
Step-by-step explanation:
If you pay close attention the numbers are 5 points away from each other, so after -3.2 is -3.21! Hope that helped love :)
Select three ratios that are equivalent to 11:1.
Choose 3 answers:
1:11
22:2
55:5
9:99
Answer:
22:2, 55:5, 1:11
Step-by-step explanation:
Answer:
22:2 55:5 and no others
Step-by-step explanation:
what value is equivalent to 13 - 2(1 - 15) divided by 14
Answer:
15
Step-by-step explanation:
Following PEMDAS you would do the equation in the parentheses first.
1 - 15 = -14
13 - 2 ⋅ (-14) divided by 14
-2 ⋅ (-14) = 28
13 + 28 divided by 14
28 divided by 14 = 2
13 + 2 = 15
Your answer is 15
Hope I helped :)
Please consider Brainliest :)
Find the general solution of y''' + 9y'' + y' − 111y = 0 if it is known that y1 = e−6x cos(x) is one solution.
Answer:
[tex]\mathbf{y(x) = \dfrac{(c_1 + c_2) \ cos (x)}{e^{6x} }+ \dfrac{i(c_1 -c_2) \ sin (x)}{e^{6x}}+ c_3e^{3\ x}}[/tex]
Step-by-step explanation:
The objective of this question is to solve:
[tex]\dfrac{dy(x)}{dx}+ 9\dfrac{d^2y(dx)}{dx^2}+\dfrac{d^3y(x)}{dx^3}-111y(x) = 0 :[/tex]
Suppose the general solution is proportional to [tex]e^{\lambda x}[/tex] for [tex]\lambda[/tex] is constant; Then:
Let's replace [tex]y(x) = e^{\lambda\ x}[/tex] into the above equation:
i.e.
[tex]\dfrac{d^3}{dx^3}(e ^{\lambda x} )+ 9 \dfrac{d^2}{dx^2}(e ^{\lambda x} ) + \dfrac{d}{dx}(e ^{\lambda x} )- 111 \ e ^{\lambda x} = 0[/tex]
To Replace:
[tex]\dfrac{d^3}{dx^3}(e ^{\lambda x} )[/tex] with [tex]\lambda^3 e ^{\lambda x }[/tex]
[tex]\dfrac{d^2}{dx^2}(e ^{\lambda x} ) \ with \ \lambda^2 e^{\lambda\ x}[/tex]
[tex]\dfrac{d}{dx}(e ^{\lambda x} ) \ with \ \lambda e ^{\lambda \ x}[/tex]
Thus;
[tex]\lambda^3 e ^{\lambda x }[/tex] + [tex]9 \lambda^2 e^{\lambda\ x}[/tex] + [tex]\lambda e ^{\lambda \ x}[/tex] - 111 [tex]e ^{\lambda \ x}[/tex] = 0
[tex]e ^{\lambda \ x} (\lambda ^3 + 9 \lambda ^2 + \lambda - 111 )= 0[/tex]
∴
In as much as [tex]e^{ \lambda x}\neq 0[/tex] for any finite [tex]\lambda[/tex]; Then:
[tex]\lambda ^3 + 9 \lambda ^2 + 111 = 0[/tex]
By Factorization:
[tex](\lambda - 3) ( \lambda ^2 + 12 \lambda + 37) = 0[/tex]
[tex]\lambda = -6 + i \ or\ \lambda = -6 - i \ or \ \lambda = 3[/tex]
However;
The root [tex]\lambda = -6 \pm i[/tex] yield;
[tex]y_1 = (x) = c_1 e ^ {(-6+i)x}[/tex]
[tex]y_2 (x) = c_2e^{(-6-i)x}[/tex]
The root [tex]\lambda = 3[/tex] yield;
[tex]y_3(x) = c_3 e^{3x}[/tex]
∴
The general solution is:
[tex]y(x) = y_1(x) + y_2(x) + y_3(x) = \dfrac{c_1}{c^{(6-i)}x}+\dfrac{c_2}{c^{(6+i)}x}+ c_3e^{3x}[/tex]
Using Euler's Identity ;
[tex]e^{\alpha+i \beta} = e^\alpha \ cos (\beta ) + i \ e^\alpha \ sin ( \beta)[/tex]
[tex]y(x) = c_1 ( \dfrac{cos (x) }{e^{6x}}+ \dfrac{i \ sin x }{e^{6x} }) + c_2 ( \dfrac{cos (x)}{e^{6x}}- \dfrac{-i \ sin (x)}{e^{6x}})+c_3 e^{3x}[/tex]
[tex]\mathbf{y(x) = \dfrac{(c_1 + c_2) \ cos (x)}{e^{6x} }+ \dfrac{i(c_1 -c_2) \ sin (x)}{e^{6x}}+ c_3e^{3\ x}}[/tex]
Al changes saved
4. Ten students in your class put their names on slips of paper inside a box. Out of the ten students, four
are girls, and six are boys. Five names are chosen.
What is the probability that three girls and two boys are chosen?
O 7.14%
350%
O 1.90%
O 23.81%
Answer:
1.90 percent
Step-by-step explanation:
Type the integer that makes the following addition sentence true
Blank + (-8) = -2
HELP ME PLEASE!!!!!!!!!
Which statement describes the system of equations?
5x-3y=34
x-2y=4
It has infinitely many solutions.
It has no solution.
It has one solution (24/13, -14/13)
It has one solution (8, 2).
Answer: It has one solution (8, 2).
Step-by-step explanation:
I put both equations in Desmos and the solution was (8,2)
NEED HELP WITH MATH! Will Give Brainliest! Image is below.
Answer:
#2
Even though the graph dips down, x is still increasing, and y will increase as will .
As x is decreasing, y is also decreasing.