Both questions 7 and 8

Both Questions 7 And 8

Answers

Answer 1

9514 1404 393

Answer:

  7.  $10,459.28

  8.  $30,060.93

Step-by-step explanation:

Your table 12-2 will tell you the present-value multiplier of the annual payment for a 10-year annuity due will be ...

  7%: 7.515232

  11%: 6.537048

__

7. The 11% table value will be used with a payment of $1600 to find the present value:

  6.537048 × $1600 = $10,459.28 . . . present value of the annuity due

__

8. The 7% table value will be used with a payment of $4000 to find the present value:

  7.515232 × $4000 = $30,060.93 . . . present value of the annuity due


Related Questions

(2³ x 2⁵) ÷ 2⁸
Solution​

Answers

Answer:

it is 1

Step-by-step explanation:

Let's use PEMDAS (do the parenthesis first).

2 to the 3 = 2x2x2 = 8

2 to the 5 = 2x2x2x2x2 = 32

8 x 32 = 256 (all the solutions are factors of 2048).

2 to the 8 = 2x2x2x2x2x2x2x2 = 256 again

256 / 256 = 1

What is the scale factor for the dilation of triangle ABC
to produce triangle A'B'C'?
A. 0.25
B. 0.5
C. 2
D. 3

What is the scale factor for the dilation of triangle ABC
to produce triangle A"B"C?
A. 0.25
B. 0.5
C. 2
D. 3

Answers

Answer:

1) B 0.5

2) C 2

Step-by-step explanation:

point A (-2, 2) (0.5) = (-1, 1) A'

point B (-2, -1) (0.5) = (-1, -0.5) B'

point C (3, -1) (0.5) = (1.5, -0.5) B'

point A (-2, 2) (2) = (-4, 4) A'

point B (-2, -1) (2) = (-4, -2) B'

point C (3, -1) (2) = (6, -2) B'

Help !!!!!!!!!!!!!!!!!!!!

Answers

Answer:

Step-by-step explanation:

One must rearrange the function to decreasing value of exponents

f(x) = -7x⁴ + 8x³ - 3x² - 9x + 11

to see that it is a 4th degree polynomial with leading coefficient of -7

1.)Which of the following is a linear inequality in two variables?
a. 3x≤16
b. 3m-4m>5
c. 9q+4<12
d. 11+2t ≥ 3?​

Answers

[tex] \large╚»★«╝ { \mathcal{Answer }}╚»★«╝[/tex]

The Correct option among them is B

[tex] \sf3m - 4n > 5[/tex]

_____________________________________

The other options have one variable each, but according to the given question there should be two variables in the inequality.

The only choice satisfying the conditions is Option B

having two variables in it ( that is "m" and "n" )

[tex] ꧁ \: \large \frak{Eternal \: Being } \: ꧂[/tex]

(10 points!!!) AND I’LL GIVE YOU BRAINLIEST IF CORRECT


I ALREADY KNOW THE ANSWER I JUST WANT THE EXPLANATION!!

The answer is ( Jose, $901.31 more)

Janell deposits $2,000 and for 5 years leaves it in an account earning 3% annual interest, compounded quarterly. For 5 years, José saves and deposits $150 per quarter in an account earning 3% interest compounded quarterly. Who will have more money in the account after 5 years? How much more?

Use the table to answer:

Answers

Answer:

2%

Step-by-step explanation:

If the length of the rectangle is thrice its breadth and breadth is 7 cm. find the perimeter...​

Answers

Step-by-step explanation:

breath=7

lenghth=3(7)

=21

perimeter of rect=2(l+b)

=2(21+7)

=56

Form an equation to help you solve this problem Four identical lumps of gold on one side of some scales balance with one identical lump and a 22kg mass. Find the mass of one lump of gold. kg​

Answers

Answer:

equation= 4x=x+22kg

Step-by-step explanation:

i hope it helped :))

What is the equation of a line that passes through the points (3, 6) and (8, 4)?

Answers

To solve this problem you find the slope of the equation and then use that to plug in a given point to find b:

y=-2/5x+7.2

Answer:

[tex]y=-\frac{2}{5} x+\frac{36}{5}[/tex]

Step-by-step explanation:

→ Find the gradient

[tex]\frac{4-6}{8-3}= \frac{-2}{5} =-\frac{2}{5}[/tex]

→ Write into y = mx + c format

[tex]y=-\frac{2}{5} x+c[/tex]

→ Substitute in ( 3 , 6 )

[tex]6 = -\frac{6}{5} +c[/tex]  ∴ [tex]c = 6+\frac{6}{5} =\frac{36}{5}[/tex]

→ Rewrite into y = mx + c format

[tex]y=-\frac{2}{5} x+\frac{36}{5}[/tex]

Pregnant women have the option of being scanned for Cystic Fibrosis risks in their unborn babies. If a mother or a father have a certain recessive gene, the baby is at risk for Cystic Fibrosis. Given the three events, which of the following statements is true? Select all that apply.
Event A: The mother or father carries the recessive gene.
Event B: The father carries the recessive gene.
Event C: The baby is at risk for Cystic Fibrosis.

Answers

Answer:

Pregnant women have the option of being scanned for Cystic Fibrosis risks in their unborn babies. If a mother or a father have a certain recessive gene, the baby is at risk for Cystic Fibrosis.

Given the three events, which of the following statements is true?  

Select all that apply.

Event A: The mother or father carries the recessive gene.

Event B: The father carries the recessive gene.

Event C: The baby is at risk for Cystic Fibrosis.

Select all that apply:

Event A and Event B are mutually exclusive.

Event B and Event C are mutually exclusive.

Event A and Event C are not mutually exclusive.

Event A and Event C are mutually exclusive.

Event A and Event C are not mutually exclusive.

Remember that in general, A and B are mutually exclusive events if they cannot occur at the same time. This means that A and B do not share any outcomes and P(A AND B)=0.

In this question, note that if the mother or father carries the recessive gene for cystic fibrosis, the baby is at risk. So here, A and C are not mutually exclusive, and B and C are not mutually exclusive.

A and B are not mutually exclusive because they share an outcome: the father carrying the recessive gene.

Step-by-step explanation:

50 points + brainliest answer questions 7 and 8 with work and all

Answers

Answer:

7) m∠BHE = 146°

8) m∠BAC = 25°

Step-by-step explanation:

Question 7:

Given that, [tex]\displaystyle\mathsf{\overline{CD}\:||\:\overline{EF}}[/tex], and that [tex]\displaystyle\mathsf{\overline{AB}}[/tex] is a transveral.

We are also provided with the following measures of the angles: m∠DGH = 2x, and m∠FHB = 5x - 51.

∠DGH and ∠FHB are also corresponding angles, as they have corresponding positions on the same side of the transversal, [tex]\displaystyle\mathsf{\overline{AB}}[/tex]. These two angles also have the same measure.  

Solve for x:

In order to find the measure of ∠BHE, we could set up an equality statement on ∠DGH and ∠FHB to solve for the value of x.

m∠DGH = m∠FHB

2x = 5x - 51

Add 51 and subtract 2x from both sides of the equation:

2x -2x + 51  = 5x - 2x - 51 + 51

51 = 3x

Divide both sides by 3:

[tex]\displaystyle\mathsf{\frac{51}{3}\:=\:\frac{3x}{3}}[/tex]

x = 17

 m∠DGH = 2x = 2(17) = 34°,

 m∠FHB = 5x - 51 = 5(17) - 51 = 34°.

Since ∠FHB and ∠BHE are supplements (whose sum add up to 180°), we could determine the measure of ∠BHE as follows:

m∠BHE + m∠FHB  = 180°

m∠BHE + 34° = 180°

m∠BHE + 34°- 34° = 180°- 34°

m∠BHE = 146°.

Therefore, the measure of ∠BHE is 146°.

Question 8:

Given that ΔABC with [tex]\displaystyle\mathsf{\overline{AC}}[/tex] extended to D, and that m∠ABC = 63° and m∠BCD = 92°:

The Exterior Angle Theorem states that the measure of an exterior angle of a triangle is equal to the sum of the two nonadjacent interior angles. In other words: ∠BCD = ∠BAC + ∠ABC.  

Before we could apply the Exterior Angle Theorem, we must first find m∠BAC. Since ∠BCD and ∠BCA are supplements:

m∠BCD + m∠BCA = 180°

92° + m∠BCA = 180°

92° - 92°+ m∠BCA = 180° - 92°

m∠BCA = 88°

Solve for m∠BAC:

Now that we have the measure for ∠BCA, we can find m∠BAC by applying the Triangle Sum Theorem where it states that the sum of the interior angles of a triangle is equal to 180°.

m∠BCD + m∠ABC + m∠BAC = 180°

92° + 63° + m∠BAC  = 180°

125° + m∠BAC  = 180°

155° - 155° + m∠BAC  = 180° - 155°

m∠BAC  = 25°

Therefore, the measure of ∠BAC is 25°.

Determine whether each situation represents a discrete or continuous function.
a. The function y = 30.48x converts length from x feet to y centimeters. [ A. discrete , B. continuous ]
b. The function y = 3x + 2 represents the amount of water y in gallons in a tank after x minutes.
[ A. discrete ,B. continuous ]

Answers

Answer:

Both of those are continuous

Step-by-step explanation:

A discrete function is only defined for a specified countable set of x, neither of the two provided fit that description. On the other hand, both are defined for arbitrary positive real numbers.

The value of both functions is defined for a continuous interval of x thus both will be continuous.

What is a function?

A certain kind of relationship called a function binds inputs to essentially one output.

The nature of the relationship defines the function for example y = sinx and y = x +6 like that.

Given the first function →

y = 30.48x where x is feet and y is a centimeter of conversion.

Now, it is known that for every foot interval there will be a centimeter that exists therefore they will be defined for all continuous intervals of x so it will be continuous.

The second function →

y = 3x + 2 where x is minutes and y is the number of gallons in a tank.

Now since for every minute of the interval, there will be a certain amount of gallons in the tank so it will be also continuous.

Hence "The value of both functions is defined for a continuous interval of x thus both will be continuous".

For more about the function,

brainly.com/question/23712366

#SPJ2

Cuantos triángulos se pueden construir con un número entero de palillos

Answers

Answer:

Step-by-step explanation:

After creating an equilateral triangle using 3 toothpicks, I require 3 more toothpicks to create more 3 equilateral triangles ie.4 triangles it toto.

First place 3 toothpicks end to end on a Horizontal plane to create an equilateral triangle.

THEN erect 3 toothpicks on each corner of the triangles making other ends joined up together in space above the Horizontal plane so as to create another same THREE equilateral triangles. (I am unable to provide a pictorial presentation due to inadequacy of signs & symbols on the keyboard. )

I suppose, you must have visualised the superstructure.

Thanks.

least common denominator of both 4/x^2*t and x/t^2

Answers

Step-by-step explanation:

LCD of 4/x²t and x/t²

= LCM(x²t , t²)

=

URGENT: HELP ME WITH THE MATH PROBLEMS!!

(Note This Needs To Be Done Tonight!)

Answers

Answer:

1. 3 and 1/5 improper: 11/15

2. 3 and 3/4 improper: 15/16

3. 1 and 2/3 improper: 5/6

4. 2 and 1/2 improper: 5/6

5. 3 and 2/10 improper: 32/40

6. 3 and 3/9 improper: 30/36

7. 1 and 2/6 improper: 8/12

15 points plz answer soon

Answers

Answer:

P(ΔTRP) = 36 m

Hope this helps!


???????????????????????????????????????

Answers

Answer:

Its C (Third Multiple Choice Answer)

Step-by-step explanation:

The reason being that x + 1 / 2 (6x - 4) = 6 is the way it is instead of the first step being x + 6x / 2 - 4 / 2 = 6 is because it is using legal manipulation by multiplying the 1 / 2 out.

Math:

First

2 * (x + 1 / 2 (6x - 4) = 6 * 2 [In this case the x gets multiplied by 2 and multiplies 2 to the other side as well. The reason why it isn't a Distributive Property in the first place is because we are using multiplication only and the equation is not 1 / 2 (6x - 4).

Then

2x + 6x - 4 = 12 will then equal to 8x - 4 = 12 which is adding like terms

Thirdly

(+ 4) + 8x - 4 = 12 (+ 4) [The parenthesis is to identify that the 4 is positive]

will then turn into 8x = 16

Finally

By dividing 8 on both sides of the previous equation

8x / 8 = 16 / 8 equaling x = 2.

Draw a square and its diaginals

Answers

Answer:

you cant draw......................

Step-by-step explanation:

Can u tell answers of all the given questions? Plz

Answers

Help me toooo this work is hard

Flying against the wind, a jet travels 3780 miles in 6 hours. Flying with the wind, the same jet travels 5950miles in 7 hours. What is the rate of the jet in still air and what is the rate of the wind? 1111 Rate of the jet in still air: ​

Answers

The rate of the jet in still air is 740 mph and the rate of the wind is 110 mph.

The given parameters;

distance traveled against the wind, d₁ = 3780 milestime of motion, t₁ = 6 hoursdistance traveled with wind, d₂ = 5950 milestime of motion, t₂ = 7 hours

Let the rate of the jet in still air = R₁

Let the rate of the wind = R₂

The rate of the jet against the wind:

[tex]R_1 - R_2 = \frac{3780}{6} \\\\R_1 - R_2 = 630[/tex]

The rate of the jet with the wind:

[tex]R_1 + R_2 = \frac{5950}{7} \\\\R_1 + R_2 = 850\\\\[/tex]

The rate of the jet in still air is calculated as follows;

[tex]R_1 = \frac{630 + 850}{2} \\\\R_1 = 740 \ mph[/tex]

The rate of the wind is calculated as follows;

[tex]R_1 - R_2 = 630\\\\R_2 = R_1 - 630\\\\R_2 = 740 - 630 \\\\R_2 = 110 \ mph[/tex]

Thus, the rate of the jet in still air is 740 mph and the rate of the wind is 110 mph.

Learn more about rate here:https://brainly.com/question/11664428

Evaluate the algebraic expression if w= -0.5, x = 2, y= -3, and z = 2.5.

2w^2 - 3x + y - 8z

Answers

Answer:

-28.50

Step-by-step explanation:

Given the algebraic expression, 2w² - 3x + y - 8z, where w = -0.5, x = 2, y= -3, and z = 2.5:

Substitute the given values for the variables to evaluate the algebraic expression.

2w² - 3x + y - 8z

= 2(-0.5)² - 3(2) + (-3) - 8(2.5)

= 2(0.25) - 6 - 3 - 20

= 0.50 - 6 - 3 - 20

= -28.50

Therefore, 2w² - 3x + y - 8z = -28.50.

Answer:

-28.5

Step-by-step explanation:

Substitute the values for their given variables and evaluate.

[tex]2w^2-3x+y-8z\\\\2(-0.5)^2-3(2)+(-3)-8(2.5)\\\\2(0.25)-6-3-20\\\\0.5-6-3-20\\\\-28.5[/tex]

On two investments totaling $14,000, Peter lost 4% on one and earned 6% on the other. If his net annual receipts were $312, how much was each investment?

Answers

Answer:

5280 , 8720

Step-by-step explanation:

suppose the one is x, another is y

x+y=14000

y(6%)-x(4%)=312

x=5280

y=8720

net annual receipt means the income so you have to substract the lost from the gains

PLEASE HELP ILL GIVE BRAINLIEST


Matt ate 2005 calories. The next day he ate 1920 calories. What is the percent change in the number of calories from day 1 to day 2?​

Answers

Answer:

85%

Step-by-step explanation:

which of the following are perfect cubes 1)3375 2)8000 3)6859​

Answers

Answer:

all are perfect cubes

Step-by-step explanation:

you can just cube root the numbers and bom if it aint decimal its a perfect cube

The mass of Earth is approximately 6 x 10^27 that of the Sun is 330,000 times as much. The gravitational constant is 6.7 x 10^-8 cm/s2.g. The distance of Earth from the Sun is about 1.5 x 10^12 cm. Compute, approximately, the work necessary to increase the distance of Earth from the Sun by 1 cm.​

Answers

Answer:

12.89

Step-by-step explanation:

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What is the solution set for this inequality?
- 6x + 30 < -18
0x<-2
0x<&
Ox>-2
Ox>8

Answers

Answer:

x>8

Step-by-step explanation:

[tex]- 6x+ 30 < - 18 \\ - 6x < - 18 - 30 \\ - 6x < - 48 \\ \frac{ - 6x}{ - 6} < \frac{ - 48}{ - 6} \\ x > 8[/tex]

Select all of the following that are quadratic equations. 7x2 + 14x = 0 x3 - 3x2 + 1 = 0 5x - 7 = 0 x2 + 3x -5 = 0 x - 5 = 9x + 7 x2 - x = 3x + 7

Answers

Answer:

7x2 + 14x = 0

x2 + 3x -5 = 0

x2 - x = 3x + 7  

Step-by-step explanation:

A quadratic equation has the highest power of x to the second power.  It must have x to the second power

7x2 + 14x = 0  quadratic

x3 - 3x2 + 1 = 0   not quadratic  but cubic

5x - 7 = 0  not quadratic  but linear

x2 + 3x -5 = 0   quadratic

x - 5 = 9x + 7  not quadratic but linear

x2 - x = 3x + 7  quadratic

you have to estimate​

Answers

The answer is 75388.
802x94
=75388

Answer:

75,388

Step-by-step explanation:

Long Multiplication form

[tex]\mathrm{Mutliply\:the\:bold\:numbers}[/tex]

[tex]\frac{\begin{matrix}\space\space&8&0&\textbf{2}\\ \times \:&\space\space&9&\textbf{4}\end{matrix}}{\begin{matrix}\space\space&\space\space&\space\space&8\end{matrix}}[/tex]

[tex]\frac{\begin{matrix}\space\space&8&\textbf{0}&2\\ \times \:&\space\space&9&\textbf{4}\end{matrix}}{\begin{matrix}\space\space&\space\space&0&8\end{matrix}}[/tex]

[tex]\mathrm{Multiply}\\\\8\cdot \:4=32[/tex]

[tex]\mathrm{Carry\:}3\mathrm{\:to\:the\:column\:on\:the\:left\:and\:write\:}2\mathrm{\:in\:the\:result\:line}[/tex]

[tex]\frac{\begin{matrix}\space\space&3&\space\space&\space\space&\space\space\\ \space\space&\space\space&\textbf{8}&0&2\\ \times \:&\space\space&\space\space&9&\textbf{4}\end{matrix}}{\begin{matrix}\space\space&\space\space&2&0&8\end{matrix}}[/tex]

[tex]\mathrm{Add\:the\:carried\:digit,\:}3\mathrm{,\:to\:the\:result}[/tex]

[tex]\frac{\begin{matrix}\space\space&3&\space\space&\space\space&\space\space\\ \space\space&\space\space&8&0&2\\ \times \:&\space\space&\space\space&9&4\end{matrix}}{\begin{matrix}\space\space&3&2&0&8\end{matrix}}[/tex]

[tex]\mathrm{Multiply\:the\:top\:number\:by\:the\:bolded\:digit\:of\:the\:bottom\:number}[/tex]

[tex]\frac{\begin{matrix}\space\space&\space\space&\textbf{8}&\textbf{0}&\textbf{2}\\ \space\space&\times \:&\space\space&\textbf{9}&4\end{matrix}}{\begin{matrix}\space\space&3&2&0&8\end{matrix}}[/tex]

[tex]\mathrm{Mutliply\:the\:bold\:numbers}:\quad \:2\cdot \:9=18[/tex]

[tex]\mathrm{Carry\:}1\mathrm{\:to\:the\:column\:on\:the\:left\:and\:write\:}8\mathrm{\:in\:the\:result\:line}[/tex]

[tex]\frac{\begin{matrix}\space\space&\space\space&\space\space&1&\space\space\\ \space\space&\space\space&8&0&\textbf{2}\\ \space\space&\times \:&\space\space&\textbf{9}&4\end{matrix}}{\begin{matrix}\space\space&3&2&0&8\\ \space\space&\space\space&\space\space&8&\space\space\end{matrix}}[/tex]

[tex]\mathrm{Add\:the\:carried\:number\:to\:the\:multiplication}:\quad \:1+0\cdot \:9=1[/tex]

[tex]\frac{\begin{matrix}\space\space&\space\space&\space\space&\textbf{1}&\space\space\\ \space\space&\space\space&8&\textbf{0}&2\\ \space\space&\times \:&\space\space&\textbf{9}&4\end{matrix}}{\begin{matrix}\space\space&3&2&0&8\\ \space\space&\space\space&1&8&\space\space\end{matrix}}[/tex]

[tex]\mathrm{Mutliply\:the\:bold\:numbers}:\quad \:8\cdot \:9=72[/tex]

[tex]\mathrm{Carry\:}7\mathrm{\:to\:the\:column\:on\:the\:left\:and\:write\:}2\mathrm{\:in\:the\:result\:line}[/tex]

[tex]\frac{\begin{matrix}\space\space&7&\space\space&1&\space\space\\ \space\space&\space\space&\textbf{8}&0&2\\ \times \:&\space\space&\space\space&\textbf{9}&4\end{matrix}}{\begin{matrix}\space\space&3&2&0&8\\ \space\space&2&1&8&\space\space\end{matrix}}[/tex]

[tex]\mathrm{Add\:the\:carried\:digit,\:}7\mathrm{,\:to\:the\:result}[/tex]

[tex]\frac{\begin{matrix}\space\space&7&\space\space&1&\space\space\\ \space\space&\space\space&8&0&2\\ \times \:&\space\space&\space\space&9&4\end{matrix}}{\begin{matrix}\space\space&3&2&0&8\\ 7&2&1&8&\space\space\end{matrix}}[/tex]

[tex]\mathrm{Add\:the\:rows\:to\:get\:the\:answer.\:\:\:Fill\:in\:trailing\:zeros\:\:(not\:required)}[/tex]

[tex]\frac{\begin{matrix}\space\space&\space\space&8&0&2\\ \space\space&\times \:&\space\space&9&4\end{matrix}}{\begin{matrix}0&3&2&0&8\\ 7&2&1&8&0\end{matrix}}[/tex]     [tex]=75,388[/tex]

See Image for the addition:

PLS HELP REWARDING A LOT!!

Answers

Answer:

157°

Step-by-step explanation:

Sum of interior angles of polygon

(n-2)*180 ---- n = total number of sides

7 angles, 7 sides

5*180 = 900

final angle will be

900-162-115-125-138-105-98

=157

Answer:

157

Step-by-step explanation:

it is obvious that it's a heptagon

so (n-2) x180

n=7

(7-2) x 180 =900

900-162-115-125-138-105-98

900-743=157

final unknown=157°

The height of a parallelogram is 6[tex]a^{2}[/tex][tex]b^{5}[/tex] and the base of a parallelogram is 4[tex]a^{3}[/tex][tex]b^{4}[/tex] Find the area of the parallelogram using the formula A = bh

Answers

[tex]\text{Area of parallelogram} = \text{Base}~ \times~\text{Height} = (4a^3b^4)(6a^2 b^5)=24a^5 b^9[/tex]

pls help, what is the slope of the graph?

Answers

well, let's take 2 points from it and get it :) , say let's use (4 , 5) and (-1 , 5)

[tex](\stackrel{x_1}{4}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{-1}~,~\stackrel{y_2}{5}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{5}-\stackrel{y1}{5}}}{\underset{run} {\underset{x_2}{-1}-\underset{x_1}{(4)}}}\implies \cfrac{0}{-5}\implies 0[/tex]

bearing in mind that for any horizonal line it's always 0.

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