IF P(A)=0.2 P(B)=0.1 and P(AnB)=0.07 what is P(AuB) ?A.0.13 B. 0.23 C. 0.3 D.0.4
ANSWER
P(AuB) = 0.23
STEP-BY-STEP EXPLANATION:
Given information
P(A) = 0.2
P(B) = 0.1
P(AnB) = 0.07
What is P(AUB)
[tex]P(\text{AuB) = P(A) + P(B) }-\text{ P(AnB)}[/tex]The next step is to substitute the above data into the formula
[tex]\begin{gathered} P(\text{AuB) = 0.2 + 0.1 - 0.07} \\ P(\text{AuB) = 0.3 - 0.07} \\ P(\text{AuB) = 0.23} \end{gathered}[/tex]How do I solve this problem?Mary reduced the size of a painting to a width of 3.3 inches. What is the new height of it was originally 32.5 inches tall and 42.9 inches wide? Round your answer to the nearest tenth.
Given the follow equivalence
[tex]\frac{Oldwidth}{Oldheight}=\frac{Newwidth}{Newheight}[/tex]where
old width=42.9
Old height= 32.5
New width=3.3
then
[tex]\frac{42.9}{32.5}=\frac{3.3}{Newheight}[/tex][tex]Newheight=3.3*\frac{32.5}{42.9}[/tex][tex]Newheight=2.5[/tex]New height is 2.5 inches
solve the inequality for h. h-8> 4h+5. write the answer in simplest form
Subtract '4h' from both RHS (Right-Hand side) and LHS of the inequality (Left-Hand side).
[tex]\begin{gathered} h-8-4h>4h+5-4h \\ (h-4h)-8>5+(4h-4h) \\ -3h>5 \end{gathered}[/tex]Add '8' on both LHS and RHS of the above expression.
[tex]undefined[/tex]Divide both RHS and LHS of the above expression with '-3'. Whenever an inequality is divide or multiple with a negative value, the sign of the inequality shifts. Here, the above expression is dividing with '-3'. Thus, the > symbol shifts to < symbol.
[tex]\begin{gathered} \frac{-3h}{-3}<\frac{5}{-3} \\ h<\frac{-5}{3} \end{gathered}[/tex]Thus, the iniequality for h is h<-(5/3).
Which of the following graphs shows a negative linear relationship with a correlation coefficient, r, close to -0.5?A. Graph AB. Graph BC. Graph CD. Graph D
A negative linear relationship occurs when for increasing x values, the values of y are decreasing.
Observing the graphs, we can see a positive linear relationship for graphs A and C (x - increases, y - increases).
For Graph D, we can observe no correlation.
For graph B, we can observe a negative linear relationship (x - increases, y - decreases).
Answer: Graph B
Silvergrove Hardware kept an inventory of 517,110 lawnmowers in the past. With a change inmanagement, the hardware store now keeps an inventory of 70% more lawnmowers. Howmany lawnmowers is that?
879,087.
EXPLANATION
To find the number of lawnmowers, we need to first find 70% of the number of lawnmowers that was kept in the past. Then add the to the number of lawnmowers kept in the past.
From the given question;
Number of lawnmowers kept in the past = 517, 110.
70% of lawnmowers kept in the past = 70% of 517 110
[tex]\begin{gathered} =\frac{70}{100}\times517\text{ 110} \\ \\ =361\text{ 977} \end{gathered}[/tex]Number of lawnmowers now kept in store = number of lawnmowers kept in the past + 70% of lawnmowers kept in the past
= 517 110 + 361 977
= 879,087.
you are packing for a road trip and want to figure out how much you can fit in your rectangular suitcase the suitcase has the following dimensions list length2 1/3ft width 1/3ft 1 1/2ft what is the volume of your suitcase in cubic feet
The Volume of the suitcase is given by the formula:
Length x width x height = L X W X H
L= 2 1/3ft
W= 1/3ft
H= 1 1/2ft
[tex]\begin{gathered} \text{Volume = 2}\frac{1}{3\text{ }}\text{ x }\frac{1}{3}\text{ x 1}\frac{1}{2}ft^3 \\ V\text{ = }\frac{7}{3}\text{ x }\frac{1}{3}\text{ x}\frac{3}{2}ft^3 \\ V\text{ = }\frac{21}{18}ft^3 \\ V=\text{ }\frac{7}{6}ft^3 \\ V=\text{ 1}\frac{1}{6}ft^3 \end{gathered}[/tex]Volume of the suitcase is 1 1/6 cubic feet
A)As the x-value Increases by one, the y-value decreases by 2.26.B)As the x-value increases by one, the y-value decreases by 53.769.C)As the x-value Increases by one, the y-value increases by 2.26.D)As the x-value Increases by one, the y-value Increases by 53.769. Which equation describes the line of best fit for the table below?
Option A
Explanations:The graph shows an inverse proportion.
As x increases, y decreases in value.
Finding the slope of the graph:
dy / dx = (y₂ - y₁) / (x₂ - x₁)
x₁ = 5, x₂ = 9, y₁ = 40, y₂ = 30
dy / dx = (30 - 40) / (9 - 5)
dy / dx = -10 / 4
dy / dx = -2.5
This means that as x increases by 1, decreases by 2.5
A is the only correct option.
nction.
f(x) = -x² + 3x + 11
Find f(-1)
Answer:
f(-1) = 7
Step-by-step explanation:
Hello!
You can evaluate for f(-1) by substituting -1 for x in the equation.
Evaluate f(-1)f(x) = -x² + 3x + 11f(-1) = -(-1)² + 3(-1) + 11f(-1) = -1 -3 + 11f(-1) = -4 + 11f(-1) = 7f(-1) is 7.
Answer:
f(-1) = 7
Step-by-step explanation:
Hello!
You can evaluate for f(-1) by substituting -1 for x in the equation.
Evaluate f(-1)f(x) = -x² + 3x + 11f(-1) = -(-1)² + 3(-1) + 11f(-1) = -1 -3 + 11f(-1) = -4 + 11f(-1) = 7f(-1) is 7.
If we use 3.14 for pi, describe the ratio between the circumference and the diameter of a circle.
Solution
The ratio of the circumference of any circle to the diameter of that circle.
[tex]\begin{gathered} \text{circumference of a circle=}\pi d \\ \text{where d is the diameter} \\ \\ \text{circumference of a circle=3.14}d \end{gathered}[/tex]The ratio of the circumference of any circle to the diameter of that circle. Regardless of the circle's size, this ratio will always equal pi.
jen has to put 180 cards into boxes of 6 cards each. she put 150 cards into boxes. write an equation that could use to figure out how many boxes jen need. let b stand for the unknown number of boxes.
Let b be the number of boxes.
Since each box has 6 cards, we will have the term 6b to get the remaining boxes.
Since Jen already put 150 cards into boxes, we have the following:
[tex]150+6b=180[/tex]for 150 cards, Jen used 25 boxes. We can check that the remaining 5 boxes can be found using the previous equation:
[tex]\begin{gathered} 150+6b=180 \\ \Rightarrow6b=180-150=30 \\ \Rightarrow b=\frac{30}{6}=5 \\ b=5 \end{gathered}[/tex]therefore, the equation is 150+6b=180
Patient Smith was on a diet. He weighed 122.6 kilograms. After one month he weighed 112.8 kilograms. Whatwas his total weight loss in one month?
If Smith uses both medications, then its dosage is the sum of each.
[tex]\text{total dosage = 48.5 + 0.5 = 4}9\text{ ml}[/tex]The total dosage of the medication would be 49 ml if he got both medications.
Find the union of E and L.Find the intersection of E and L.Write your answers using set notation (in roster form).
For the intersection operation we have to look what elements both sets have in common, in this case both E and L has the number 8. Then the second answer is:
[tex]E\cap L=\lbrace8\rbrace[/tex]Now, the union operation adds the all elements into a single set without repetition, in this case the first answer is:
[tex]E\cup L=\lbrace-2,1,2,3,6,7,8\rbrace[/tex]Given points C(-3,-8) and D(-6.5,-4.5), find the coordinate of the point that is 2/3 of the way from C to D.
Answer:
(-16/3,-17/3)
Explanation:
Let the point which is 2/3 of the way from C to D = X
It means that point X divides the line segment CD internally in the ratio 2:1.
To determine the coordinate of point X, we use the section formula for internal division of a line segment:
[tex](x,y)=\left\{ \frac{mx_2+nx_1}{m+n},\frac{my_2+ny_1}{m+n}\right\} [/tex][tex]\begin{gathered} (x_{1,}y_1)=(-3,-8) \\ (x_2,y_2)=(-6.5,-4.5) \\ m\colon n=2\colon1 \end{gathered}[/tex]Substituting these values into the formula above, we have:
[tex]X(x,y)=\left\{ \frac{2(-6.5)+1(-3)}{2+1},\frac{2(-4.5)+1(-8)}{2+1}\right\} [/tex]We then simplify:
[tex]\begin{gathered} X(x,y)=\left\{ \frac{-13-3}{3},\frac{-9-8}{3}\right\} \\ =\left\{ \frac{-16}{3},\frac{-17}{3}\right\} \end{gathered}[/tex]Therefore, the exact coordinate of the point that is 2/3 of the way from C to D is (-16/3,-17/3).
Help me to answer this question with vectors, thank you
To find:
The coordinates of a point P such that PA = PB.
Solution:
Given that A(4, 0) and B(0, 9) are the coordinates.
Let the point P is (x,0) because the point is on x-axis, and it is given that |PA| = |PB|.
So,
[tex]\sqrt{(4-x)^2+(0-0)^2}=\sqrt{(x-0)^2+(0-9)^2}[/tex]Now, squaring both the sides:
[tex]\begin{gathered} (4-x)^2=x^2+9^2 \\ 16+x^2-8x=x^2+81 \\ 8x=-65 \\ x=\frac{-65}{8} \end{gathered}[/tex]Thus, the coordinates of point P are (-65/8, 0).
which of the following circles have their centers in the second quadrant
The circles in option B and D has their centers in the second quadrant
Here, we want to know which of the circles have their centers in the second quadrant
Generally, the equation of a circle can be represented as;
[tex](x-h)^2\text{ + (y-}k)^2=r^2[/tex]where (h,k) represents the center of the circle
Now, let us get the center of each of the circles;
A. (4,-3)
b. (-1,7)
C.(5,6)
D. (-2,5)
The second quadrant has its coordinates in the form (-x,y)
Out of all the options, the option that fits these quadrant is the second and fourth
So the circles in option B and D has its center in the second
Which of the following is true of points on the line y=5/3 x + 1/2? (1) For every 3 units that increases, y will increase by 5 units. (2) For every 5 units that x increases, y will increase by 2 units. (3) For every 2 units that x increases, y will increase by 1 unit. (4) For every 1 unit that x increases, y will increase by 2 units.
4) For every 1 unit that x increases, y will increase by 2 units.
1) For the function y=5/3x +1/2
If we remember that "rise over run" mnemonics, that'll make it easier to memorize it.
2) Plotting the graph of this function. Look at point A (1,2)
Counting from bottom to up (2 units "rise" on the y-axis, point A is 1 unit to right "run". So, For every 1 unit that x increases, y will increase by 2 units.
4. 1st drop down answer A. 90B. 114C. 28.5D. 332nd drop down answer choices A. Parallel B. Perpendicular 3rd drop down answer choices A. 180 B. 360 C. 270D. 90 4th drop down answer choices A. 33B. 57C. 90D. 28
Answer:
Tangent to radius of a circle theorem
A tangent to a circle forms a right angle with the circle's radius, at the point of contact of the tangent.
Part A:
With the theorem above, we will have that the tangent is perpendicular to the line radius drawn from the point of tangency
Therefore,
The value of angle CBA will be
[tex]\Rightarrow\angle CBA=90^0[/tex]Part B:
Since the angle formed between the tangent and the radius from the point of tangency is 90°
Hence,
The final amswer is
Tangent lines are PERPENDICULAR to a radius drawn from the point of tangency
Part C:
Concept:
Three interior angles of a triangle will always have the sum of 180°
Hence,
The measure of angles in a triangle will add up to give
[tex]=180^0[/tex]Part D:
Since we have the sum of angles in a triangle as
[tex]=180^9[/tex]Then the formula below will be used to calculate the value of angle BCA
[tex]\begin{gathered} \angle ABC+\angle BCA+\angle BAC=180^0 \\ \angle ABC=90^0 \\ \angle BAC=57^0 \end{gathered}[/tex]By substituting the values,we will have
[tex]\begin{gathered} \operatorname{\angle}ABC+\operatorname{\angle}BCA+\operatorname{\angle}BAC=180^{0} \\ 90^0+57^0+\operatorname{\angle}BCA=180^0 \\ 147^0+\operatorname{\angle}BCA=180^0 \\ substract\text{ 147 from both sides} \\ 147^0-147^0+\operatorname{\angle}BCA=180^0-147^0 \\ \operatorname{\angle}BCA=33^0 \end{gathered}[/tex]Hence,
The measure of ∠BCA = 33°
What are the solutions to the equation ? e^1/4x = (4x) [tex]e^1/4x =abs( 4x)[/tex](Round to the nearest hundredth). The solutions are about x = and
The solution of the equation e^(x/4) = |4x| for the x by graphical approach is 0.27 and -0.24.
What is the equation?The definition of an equation in algebra is a mathematical statement that demonstrates the equality of 2 mathematical expressions.
A formula known as an equation uses the same sign to denote the equality of two expressions.
As per the given expression,
e^(x/4) = |4x|
The function e^(x/4) is an exponential function and the plot of this function has been plotted below.
The mode function |4x| has also been plotted below.
The point of intersection is the point where both will be the same or the solution meets.
The first point of intersection is (0.267,1.0691) so x = 0.267 ≈ 0.27
The second point of intersection (-0.2357,0.9428) so x = -0.2357 ≈ -0.24
Hence " The solution of the equation e^(x/4) = |4x| for the x by graphical approach is 0.27 and -0.24.".
For more about the equation,
brainly.com/question/10413253
#SPJ1
Describe the features of the function that can be easily seen when a quadratic function is givenin the form: y = ax2 + bx + c and how they can be identified from the equation. How can thisform be used to find the other features of the graph?
Hello there. To solve this question, we need to remember some properties about quadratic functions and its key features.
Let f(x) = ax² + bx + c, for a not equal to zero.
The main key feature we can see at first glance is the leading coefficient a.
If a < 0, the parabola (the graph of the function) will have its concavity facing down.
If a > 0, the parabola will have its concavity facing up.
It also means the function will have either a maximum or a minimum point on its vertex, respectively.
Another key feature of the function is the y-intercept, i. e. the point in which the x-coordinate is equal to zero, is (0, c).
The x-intercepts of the graph (in plural), are the roots of the function.
If b² - 4ac > 0, we'll have two distinct real roots.
If b² - 4ac = 0, we'll have two equal real roots.
If b² - 4ac < 0, we'll have two conjugate complex roots (not real roots)
This b² - 4ac is the discriminant of the function.
The roots can be found by the formula:
x = (-b +- sqrt(b² - 4ac))/2a
The vertex of the graph can be found on the coordinates (xv, yv), in which xv is calculated by the arithmetic mean of the roots
xv = ((-b + sqrt(b²-4ac))/2a + (-b-sqrt(b²-4ac))/2a)/2 = -b/2a
The yv coordinate can be found by plugging in xv in the function
yv = a(-b/2a)² + b(-b/2a) + c, which will be equal to -(b²-4ac)/4a.
find the value of X and y if l || m.
The Solution.
Step 1:
We shall find two equations from the given angles.
First, by vertically opposite angle property of angles between two lines, we have that:
[tex]\begin{gathered} 7y-23=23x-16 \\ \text{Collecting the like terms , we get} \\ 7y-23x=23-16 \\ 7y-23x=7\ldots.eqn(1) \end{gathered}[/tex]Similarly, by alternate property of angles between lines, we have that:
[tex]\begin{gathered} 23x-16+8x-21=180 \\ \text{Collecting like terms, we get} \\ 31x-37=180 \\ 31x=180+37 \\ 31x=217 \\ \text{Dividing both sides by 31, we get} \\ x=\frac{217}{31}=7 \end{gathered}[/tex]Step 2:
We shall find the values of y by substituting 7 for x in eqn(1), we get
[tex]\begin{gathered} 7y-23(7)=7 \\ 7y-161=7 \\ 7y=7+161 \\ 7y=168 \\ \text{Collecting the like terms, we get} \\ y=\frac{168}{7}=24 \end{gathered}[/tex]Step 3:
Presentation of the Answer.
The correct answers are; x = 7 , and y = 24
Find the value of x in the triangle shown below.42
Since we are dealing with a right triangle, we can use the Pythagorean theorem, shown below
[tex]H^2=L^2_1+L^2_2[/tex]In our case, H=4, L_1=2, L_2=x; then,
[tex]4^2=2^2+x^2[/tex]Solving for x,
[tex]\begin{gathered} \Rightarrow x^2=16-4 \\ \Rightarrow x^2=12 \\ \Rightarrow x=\sqrt[]{12}=\sqrt[]{4\cdot3} \\ \Rightarrow x=2\sqrt[]{3} \end{gathered}[/tex]The answer is x=2sqrt(3)
Find the percent of change from 120 bananas to 40 bananas.
Answer:
67% decrease
Explanation:
From the given problem:
Initial number of bananas = 120
Final number of bananas = 40
[tex]\begin{gathered} \text{Percent Change=}\frac{Final\text{ Value-Initial Value}}{\text{Initial Value}}\times100 \\ =\frac{40-120}{120}\times100 \\ =-\frac{80}{120}\times100 \\ =-0.667\times100 \\ =-66.7\% \\ \approx-67\% \end{gathered}[/tex]Since we have a negative value, we have a 67% decrease.
Use function composition to verify f(x)=-3x+5 and g(x)=5x-3 are inverses. Type your simplified answers in descending powers of x an do not include any spaces between your characters.Type your answer for this composition without simplifying. Use parentheses to indicate when a distribution is needed to simplify. g(f(x))=AnswerNow simplify the composition, are f(x) and g(x) inverses? Answer
Answer:
• (a)g[f(x)]=5(-3x+5)+5
,• (b)No
Explanation:
Given f(x) and g(x):
[tex]\begin{gathered} f(x)=-3x+5 \\ g(x)=5x-3 \end{gathered}[/tex](a)First, we find the composition, g[f(x)].
[tex]\begin{gathered} g(x)=5x-3 \\ \implies g\lbrack f(x)\rbrack=5f(x)-3 \\ g\lbrack f(x)\rbrack=5(-3x+5)+5 \end{gathered}[/tex](b)Next, we simplify g[f(x)] obtained from part (a) above.
[tex]\begin{gathered} g\mleft[f\mleft(x\mright)\mright]=5\mleft(-3x+5\mright)+5 \\ =-15x+25+5 \\ =-15x+30 \end{gathered}[/tex]Given two functions, f(x) and g(x), in order for the functions to be inverses of one another, the following must hold: f[g(x)]=g[f(x)]=x.
Since g[f(x)] is not equal to x, the functions are not inverses of one another.
URGENT!! ILL GIVE
BRAINLIEST!!!!! AND 100 POINTS!!!!!
Answer:
-45 is an integer
√100 = 10 is a whole number
√89 is an irrational number-root
4.919191... is a rational decimal
-2/5 is a rational number-ratio
.12112111211112... is an irrational decimal
Finnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnn
( x+y+z = -1), ( y-3z = 11), ( 2x+y+5z = -12)1. determine whether the system is inconsistent or dependent2. if your answer is dependent, find the complete solution. Write x and y as functions of zx=y=
Inconsistent
Explanation:a) Given:
x + y + z = -1 . . .(1)
y - 3z = 11 . . . (2)
2x + y + 5z = -12 . . .(3)
To find:
If the solution of the system of equations is either consistent dependent solution or an inconsistent one
We need to solve the system of equations. From equation (2), we will make y the subject of formula:
y = 11 + 3z (2*)
Substitute for y with 11 + 3z in both equation (1) and (2):
For equation 1: x + 11 + 3z + z = -1
x + 11 + 4z = -1
x + 4z = -1-11
x + 4z = -12 . . . (4)
For equation 3: 2x + 11 + 3z + 5z = -12
2x + 11 + 8z = -12
2x + 8z = -12-11
2x + 8z = -23 . . .(5)
We need to solve for x and z in equations (4) and (5)
Using elimination method:
To eliminate a variable, its coefficient needs to be the same in both equations
Let's eliminate x. We will multiply equation (4) by 2:
2x + 8z = -24 . . . (4*)
Now both equations have the same coefficient of x. Subtract equation (4) from (5):
2x - 2x + 8z - 8z = -23 - (-24)
0 + 0 = -23 + 24
0 = 1
Let hand side is not the same as right hand side.
When the left hand side is not equal to right hand side, the solution is said to be inconsistent or no sloution.
Your answer is inconsistent
Under certain conditions, the velocity of a liquid in a pipe at distance r from the center of the pipe is given by V = 400(3.025 x 10-5--2) where Osrs5,5x10 -3. Writeras a function of V.r=where the domain is a compound inequality(Use scientific notation. Use integers or decimals for any numbers in the expression.)Le
Solving the equation for r:
[tex]\begin{gathered} V=400(9.025\cdot10^{-5}-r^2) \\ r^2=9.025\cdot10^{-5}-\frac{V}{400} \\ r=\sqrt[]{9.025\cdot10^{-5}-\frac{V}{400}} \end{gathered}[/tex]With the first equations, we can establish some limits for V:
With the lowest value for r (r=0):
[tex]\begin{gathered} V=400(9.025\cdot10^{-5}-0^2) \\ V=400(9.025\cdot10^{-5}) \\ V=3.61\cdot10^{-2} \end{gathered}[/tex]With the highest value for r (r=9.5x10^-3)
[tex]\begin{gathered} V=400(9.025\cdot10^{-5}-(9.5\cdot10^{-3})^2) \\ V=400(9.025\cdot10^{-5}-9.025\cdot10^{-5}) \\ V=400(0) \\ V=0 \end{gathered}[/tex]According to the radius range, velocity can be between 0 and 3.61x10^-2
It is also necessary to check the domain of the function considering it is a square root. The argument of an square root cannot be less than 0. Then:
[tex]\begin{gathered} 9.025\cdot10^{-5}-\frac{V}{400}\ge0 \\ 9.025\cdot10^{-5}\ge\frac{V}{400} \\ V\leq400(9.025\cdot10^{-5}) \\ V\leq3.61\cdot10^{-2} \end{gathered}[/tex]This is the same limit for velocity obtained before. Then, we can say for velocity that:
[tex]0\leq V\leq3.61\cdot10^{-2}[/tex]Write an equation for the inverse variation represented by the table.x -3, -1, 1/2, 2/3y 4, 12, -24, -18
By definition, Inverse variation equations have the following form:
[tex]y=\frac{k}{x}[/tex]Where "k" is the Constant of variation.
Given the values shown in the table, you can find the value of "k":
- Choose a point from the table. This could be:
[tex](-3,4)[/tex]Notice that:
[tex]\begin{gathered} x=-3 \\ y=4 \end{gathered}[/tex]- Substitute these values into the equation and solve for "k":
[tex]\begin{gathered} 4=\frac{k}{-3} \\ \\ (4)(-3)=k \\ k=-12 \end{gathered}[/tex]Knowing the Constant of variation, you can write the following equation:
[tex]y=\frac{-12}{x}[/tex]The answer is:
[tex]y=\frac{-12}{x}[/tex]=GEOMETRYPythagorean TheoremFor the following right triangle, find the side length x. Round your answer to the nearest hundredth.
From the triangle, we have:
c = 13
b = 7
Let's solve for a.
The triangle is a right triangle.
To find the length of the missing sides, apply Pythagorean Theorem:
[tex]c^2=a^2+b^2[/tex]We are to solve for a.
Rewrite the equation for a:
[tex]a^2=c^2-b^2[/tex]Thus, we have:
[tex]\begin{gathered} a^2=13^2-7^2 \\ \\ a^2=169-49 \\ \\ a^2=120 \end{gathered}[/tex]Take the square root of both sides:
[tex]\begin{gathered} \sqrt[]{a^2}=\sqrt[]{120} \\ \\ a=10.95 \end{gathered}[/tex]ANSWER:
[tex]10.95[/tex]What is the length of the side adjacent to angle 0?
To answer this question, we always need to take into account the reference angle in a right triangle. The reference angle here is theta, Θ, and we have that:
Then, the length of the side adjacent to theta is equal to 15.
In summary, we have that the length of the side adjacent to the angle Θ is equal to 15.
If 16 is increased to 23, the increase is what percent of the original number? (This is known as the percent of change.)
Step 1
Given data
Old value = 16
New value = 23
Step 2
Write the percentage increase formula
[tex]\text{Percentage increase = }\frac{I\text{ncrease}}{\text{Old}}\text{ }\times\text{ 100\%}[/tex]Step 3
Increase = 23 - 16 = 7
[tex]\begin{gathered} \text{Percentage increase = }\frac{7}{16}\text{ }\times\text{ 100\%} \\ =\text{ 43.75\%} \end{gathered}[/tex]