At the position of the stop-light 4 s after the light had turned green. what is the slowest constant speed which the green car can maintain and still catch up to the blue car? answer in units o

University physics with modern physics and mastering physics access code (15th edition), by h. young and r. freedman.

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The pig is moving slower in the negative direction during the next 2 seconds.

The term acceleration refers to the change in the velocity of the object with time. Now we know that velocity is a vector quantity. This implies that we have to take the magnitude and the direction into focus when we are discussing about the velocity.

Similarly, the acceleration is a vector quantity and the magnitude and the direction must also be taken into account when dealing with the acceleration.

In this case, it is clear that a  pig on roller skates is moving with an initial velocity of -10 m/s and is accelerating at a rate of 2m/s/s.

Seeing that the velocity is negative, we can see that the pig roller coaster is moving the negative direction. Recall that the axes must be defined such that one is negative and one is positive.

Having said that, we can conclude that; the pig is moving slower in the negative direction during the next 2 seconds.

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If the motion (or polarity of the magnet) is reversed, the direction of deflection in a galvanometer is also reversed.

An electromechanical device used to measure electric current is a galvanometer. Early galvanometers were not calibrated, but later models, known as ammeters, were, and could measure current flow more precisely.

If the motion (or polarity of the magnet) is reversed, the direction of deflection in a galvanometer is also reversed. This suggests that an emf is produced anytime the magnetic flux connected to a coil changes.

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Answer:

what graph?

Explanation:

please give the proper information

The FitnessGram PACER Test is a multistage aerobic capacity test that progressively gets more difficult as it continues.

The test is used to measure a student's aerobic capacity as part of the FitnessGram assessment. Students run back and forth as many times as they can, each lap signaled by a beep sound. The test get progressively faster as it continues until the student reaches their max lap score.

The PACER Test score is combined in the FitnessGram software with scores for muscular strength, endurance, flexibility and body composition to determine whether a student is in the Healthy Fitness Zone™ or the Needs Improvement Zone™.

The correct answer is 29883.3m/s

The pace at w.hich an object's position changes in relation to a frame of reference is known as its velocity, which is a time-dependent quantity. The speed and direction of an object's motion are its velocity. The rate at which an object's velocity changes in relation to time is defined as its acceleration.

The following kinematic equation can be used to connect velocity and acceleration:

v_1=v_0+at

Where v_1 denotes the ultimate velocity, v_0 denotes the starting velocity, a denotes the acceleration, and t is the passing of time.

Calculate the length of the Earth's orbit around the Sun to get started. For this issue, a circle rather than an ellipse can be used to represent the Earth's orbit.

Circumference = C=πD=2πR

=2π(1.5×10km)

=9.424π×10^8

Do a dimensional analysis to convert the speed of the Earth around the Sun from miles per hour to metres per second:

s_earth= 9.424π×10^8/1year × (1year×100m×1day×1hour×1min)/(1km×365days×24hours×3600seconds)

=29883.3m/s

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Answer:

Help with what??

Explanation:

Explanation:

there is no question to answer..

The magnitudes of these two vectors could be the same which could be 100 for each.

A vector quantity has both magnitude and direction. Some of the examples of vectors quantities are;

Given that two vectors of fixed magnitude, but variable direction, are added. the result has a minimum magnitude of 0 and a maximum magnitude of 200.

When the two vectors are parallel and move opposite direction to each other, the resultant will be zero. That is,

Resultant vector = 100 - 100 = 0

But when the two vectors are parallel and move in the same direction to each other, the resultant will be 200. That is,

Resultant vector = 100 + 100 = 200

Therefore, the magnitudes of these two vectors could be the same which could be 100 for each.

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Answer:

The acceleration of the ball (excluding air resistance) is

9.80 m/s^2 in the downward direction.

That's all that can be inferred from the problem as it is stated.

The change in the internal energy of the system is 96 j.

The change in the internal energy of the system is given by

              Δ U = Q + W

Q = 71.0 j

W = 25.0j

Δ U = Q + W

Δ U = 71 +25

Δ U = 96 j

The system's kinetic energy and potential energy together make up the system's internal energy. When a reaction is conducted at a constant pressure, the internal energy change (U) of the reaction is equal to the heat acquired or lost (enthalpy change).

A thermodynamic system's internal energy is its total internal energy. It is the energy required to build or prepare the system in the internal state that it is in at the time.

In thermodynamics, internal energy is a quantity or state function that characterizes a substance's energy when capillary effects and other external fields, such as electric and magnetic forces, are absent.

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1.72*10^-9

On an empty capacitor, there is no dielectric so E= 8.85E-12

C=EA/(d)

c is capacitance, A is area , d is distance between the parallel plate and E is dielectric constant.

C=(8.85E-12 c2/Nm2)(0.535m2)/ (2.75*10^-3m)

C= 1.72*10^-9

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The correct option is option (D) Was an excellent north pole star in 3,000 BC.

Thuban (/jubaen/), also known as Alpha Draconis or Draconis, is a binary star system. It is a faint star in the Northern Hemisphere’s night sky, but because it served as the north pole star from the fourth to the second millennium BC, it is noteworthy historically. Thuban is the only member of Johann Bayer’s secondary magnitude class in the constellation Draco, despite the fact that at its current apparent magnitude of 3.65, it is 3.7 times fainter than Gamma Draconis (formerly called Eltanin), the brightest star in the constellation, which Bayer placed in his tertiae magnitude class despite its current apparent magnitude of 2.24.Thuban’s positioning regard to the Big Dipper (also known as the Plough) asterism of Ursa Major makes it very simple to see in the night sky under ideal viewing conditions. The two inner stars, Phecda and Megrez, point to Thuban, which is located only 15 degrees of arc from Megrez.Thuban is not bright enough to be seen in locations with significant light pollution.  

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Light is emitted, energy is  9.16 × [tex]10^{-20}[/tex] J , frequency is 1.38 × [tex]10^{-14}[/tex] [tex]s^-[/tex]    

and wavelength is  2.17 × [tex]10^{-6}[/tex] m      

n = 7 → n = 4

higher → lower

Light is emitted

[tex]\Delta[/tex]E = [tex]\frac{-13.6}{7^2} - (\frac{-13.6}{4^2})[/tex]

[tex]\Delta[/tex]E = 0.85 - 0.277

     = 0.572 eV

[tex]\Delta[/tex]E = 9.16 × [tex]10^{-20}[/tex] J              -> [energy calculated]

[tex]\Delta[/tex]E = hv           (h is Planck's constant and v is frequency)

v = [tex]\frac{\Delta E}{h}[/tex]  = [tex]\frac{9.16 * 10^{-20}}{6.626 * 10^{-39}}[/tex]

v = 1.38 × [tex]10^{-14}[/tex] [tex]s^-[/tex]                 ->[frequency calculated]

[tex]\Delta[/tex]E = [tex]\frac{hc}{\Lambda}[/tex]            (c is speed of light)

[tex]\Lambda[/tex] = [tex]\frac{hc}{\Delta E}[/tex]

[tex]\Lambda[/tex] = [tex]\frac{6.626 * 10^{-34} . 3*10^8 m/s}{9.16 *10^{-20 J} }[/tex]

[tex]\Lambda[/tex] = 2.17 × [tex]10^{-6}[/tex] m                    ->[wavelength calculated]

Energy, according to scientists, is the capacity for work. The ability to transform energy from one form to another and use it to perform tasks is what makes modern civilization possible. People utilize energy to travel by foot and bicycle, drive vehicles on land and in water, prepare meals on stoves, create ice in freezers, illuminate our homes and workplaces, create goods, and launch people into space.

Energy comes in a wide variety of forms, including:

These energies can be divided into two categories for working energy:

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A hallmark of courage is being ready and willing to face challenging or uncomfortable circumstances. The word "bravery" is similar. It can also include doing so, even though confronting these situations fearlessly is generally thought of as showing courage.

In reality, courage is the capacity to move forward in the face of fear. The ability to behave bravely in the face of any anxiety or tension is what is meant by having courage. One of the finest ways to be courageous is to recognize your fears and then decide not to let them stop you. having the guts to handle risk in a responsible manner as opposed to acting cowardly or irrationally confident.

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The rating of the branch-circuit protective device is affected when the conductors used are of a larger size than called for by the code of up the amps and up the AWG.

Branch circuit protection devices are also known as UL 489 circuit breakers.

These devices are tasked to provide protection to all sorts of circuit wiring by keeping in control the amps and AWG.

In addition to this, they also help prevent fire and electric shocks and are also suitable for electrical isolation.

During the maintenance period, they limit the flow of current and also serve as means to cut off the electricity supply.

If large-sized conductors are used then the performance of the branch-circuit protective device may get affected.

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The amount of heat this resistor gives in 24 hours and heat fiux q is mathematically given as

Qd=4340.589 W/m^2

Q_t amp;=Q*time

amp;=1.2 *J*(24*3600)

Q_damp=03680J

Q_damp;=103.680

[tex]A_s &=\frac{\pi}{4} d^2 \times 2+\pi d L \\\\A &=\frac{\pi}{4} \times 0.4^2 \times 2+\pi \times 0.4 \times 2[/tex]

A amp;=2.764601 cm^2

[tex]\\\q &=\frac{1.2 \times 104^{+}}{2.764601}=4340.589(\mathrm{~W} / \mathrm{m})[/tex]

qamp;=4340.589mm^2

In conclusion,

Qd=103.680Jq

Qd=4340.589 W/m^2

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In a two-d coordinate system, every vector can be broken down and considered as the x-component and y-component.

A vector quantity has two characteristics, a magnitude and a direction. And these two characteristics are accompanied by two components.

If the vector is V, then these components can be represented as vx and vy.

These vx and vy are the parts of the vector that are generated along the axes of the coordinate plane.

Any vector with a two-dimensional direction can be conceived of as having two distinct parts. A single vector's component specifies how that vector acts in a certain direction.

If the magnitude of the vector is given as a and the direction is given as [tex]\theta[/tex] of a two-dimensional vector, then the components of the vector can be found out using the following formulas:

vx=vcosθ for the x component

and

vy=vsinθ for the y component

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The time of flight of the launched particle will be 2v₀ sinθ / g.

The study of motion without considering the mass and the cause of the motion.

A projectile is launched from level ground with an initial speed v₀ at an angle θ with the horizontal. If air resistance is negligible.

Then the time of flight of the launched particle will be given as,

Determine how long it requires the projectile to reach its highest point in order to calculate the flight duration. Just twice as long as the maximum altitude is the travel time.

[tex]\rm v_y = v_{o_y} + a_y t[/tex]

At maximum height, [tex]\rm v_y = 0[/tex].

The time to reach maximum height is given as

[tex]\rm t_{1/2} = - \dfrac{v_{o_y} }{ a_y}[/tex]

The time of flight is given as,

[tex]\rm t = 2 \times t_{1/2} = - \dfrac{2v_{o_y}}{ a_y}[/tex]

Substituting in [tex]\rm v_{o_y} = v_o \ \sin(\theta ) \ and \ a_y = -g[/tex], then we have

The time of flight of the launched particle will be 2v₀ sinθ / g.

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The electric fields is always directed from higher potential to the lower potential.

The electric fields always aiming from the region of higher potential to the region of lower potential. So the force of electrostatic and the direction of the travel of electrons will be always from lower potential to the region of higher potential.

An electric field is defined as the physical field which covers the electrically charged particles and also they can apply force on all other charged particles.

So we can conclude that the electric fields is always directed from higher potential to the lower potential.

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The position of a particle undergoing simple harmonic motion is given by:

x = 2 cos (50t).

The maximum velocity is 100 m/s.

What is meant by Simple Harmonic Motion, refer to:

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Low-energy state of condensed matter is characterized by structural rigidity and resistance to changes of shape or volume is solid.

When particles are arranged and packed closely -- compared to those in a gas or liquid -- and are relatively stable, they are considered to be in solid state. Solids tend to have a rigid shape, as the atoms or molecules of matter in the solid state are generally compressed and tightly connected through the chemical bonds. These bonds can produce an amorphous shape or regular lattice.

In electronics, the solid state refers to components and systems based entirely on semiconductor materials, such as silicon, germanium or gallium arsenide. Transistors and diodes -- the most common solid-state devices -- are often combined with resistors, capacitors and other components to create the integrated circuits (ICs). All the electronic systems incorporate ICs and, therefore, transistors.

The particles that make up solid have the lowest energy, and vibrate in place. This results in the characteristics of a solid, such as definite shape and volume. A solid is actually the frozen state of matter for substance. A substance does not have to freeze at cold temperature. For example, the faucet you have at your lab station in chemistry, and the faucets in your home are frozen the stainless steel; and so is your desk, pencils, pens, cell phones, and computers are all frozen. In fact anything solid is frozen.

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The pivot point should be placed 15m right from the 4kg board and 60m left from 1kg block to be balanced.

Let d block be x and d board be y      

so, x + y = 75   ...1

This problem needs to add torques about the pivot point. In order to be balanced, the torque must be equal on each side of the pivot point.

T block =T board

Use the equation for torque in this equation.

(F block)(d block )=(F board )(d board )

The force of each object will be equal to the force of gravity.

(m block )g(d block )=(m board )g(d board )

Gravity is cancelled from each side of the equation. for simplicity.

(m block )(d block )=(m board )(d board )

⇒ 1 kg × x = 4kg × y

⇒ 1/4  = x/y    

⇒ x = 4y     ...2

Now applying eq 2 in eq 1 we get

⇒ 4y + y = 75

⇒ 5y = 75

⇒ y = 75/5

      = 15

Thus, the pivot point should be placed 15 m right from the 4kg board and 60 m left from 1kg block to be balanced.

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The speed of a moving rod that has a length 55 % that of an identical rod in terms of c will be v/c= 0.824

or v = 0.824c.

The formula for length contraction rod is,

L = L1{√(1-v^2/c^2)}

Here L is the length of the moving rod

L1 is the length of the stationary rod

v is the velocity with which the rod is moving

c is the speed of light

We are given that

L = 55% of L1 = 0.55L1

Putting the values in the above equation,

0.55L1 = L1{√(1-v^2/c^2)}

0.55 = {√(1-v^2/c^2)}

Squaring both sides

(0.55)^2 = 1- v^2/c^2

V^2/c^2 = 1 - 0.3025

V^2/c^2 = 0.6975

v/c = 0.824

Thus, the speed of  a moving rod that has  a length 55 % that of an identical rod in terms of c will be v/c= 0.824 or v = 0.824c.

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(a) Its instantaneous velocity at t = 10.0s is 0.4m/s.

(b) Its instantaneous velocity at t = 30.0s is 0.5 m/s.

(c) Its average velocity between t = 0 and t=5.0s is 0.6 m/s.

(d) Its average velocity between t = 25.0s and t=30.0s is 1.4 m/s.

(e) Its average velocity between t=40.0s and t=50.0s is -1 m/s.

Instantaneous velocity is defined as the velocity of an object under motion at a specific point of time.

at time, t = 10 seconds, x = 4 m

v = 4 m / 10 s = 0.4 m/s

at time, t = 30 seconds, x = 15 m

v = 15 m / 30 s = 0.5 m/s

v(avg) = Δx / Δt

v(avg) = (3 - 0)/(5 - 0) = 0.6 m/s

v(avg) = Δx / Δt

v(avg) = (15 - 8)/(30 - 25) = 1.4 m/s

v(avg) = Δx / Δt

v(avg) = (10 - 20)/(50 - 40) = -1 m/s

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Data can be displayed as graphs, which are graphic representations, to help identify trends more quickly.

A graph is a visual representation of the relationship between two variables, typically two variables that are measured along an axis that is perpendicular to the other two axes. A graph, in a nutshell, is a visual representation of data for easy comprehension. Graphs are commonly used to show scientific data so that readers may immediately see trends. Graphs are often used in the social sciences to visually convey important information. A network's connection between lines and points is represented mathematically by a graph. The points and arcs that connect them make form a graph.

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When Tron accelerates vertically upward, traveling 4.50 m in the first 3.00 ms after it is released. Then magnitude of the electric field is E= 3.4893 N/C.

The electric force per unit charge is referred to as the "electric field." It is thought that the field's direction corresponds to the force it would apply to a positive test charge.

The SI unit for the electrical field is volts per meter (V/m). This unit is equivalent to the Newtons per coulomb. Both Newton, which represents for force, and Coulomb, which stands for charge, are the ancestors of these units.

Around a charged object, an electric field is produced that affects the surrounding environment.

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Answer:

a = (v2 - v1) / t

If the velocity is changing but not the magnitude of speed then

the change in velocity is directed perpendicular to the current velocity of the object

(An example is an object undergoing uniform circular motion where the speed of the object around the circle is constant but the change in velocity is always directed toward the center of rotation)

Answer:

Average speed: approximately [tex]76.9\; {\rm m\cdot s^{-1}}[/tex].

Average velocity: approximately [tex]38.5\; {\rm m \cdot s^{-1}}[/tex] (to the north.)

Explanation:

Consider an object that travelled along a certain path. Distance travelled would be equal to the length of the entire path.

In contrast, the magnitude of displacement is equal to distance between where the object started and where it stopped.

In this question, the path George took required him to travel [tex]750\; {\rm m} + 250\; {\rm m} = 1000\; {\rm m}[/tex] in total. Hence, the distance George travelled would be [tex]1000\; {\rm m}[/tex]. However, since George stopped at a point [tex](750\; {\rm m} - 250\; {\rm m}) = 500\; {\rm m}[/tex] to the north of where he started, his displacement would be only [tex]500\; {\rm m}[/tex] to the north.

Divide total distance by total time to find the average speed.

Divide total displacement by total time to find average velocity.

The total time of travel in this question is [tex]13\; {\rm s}[/tex].. Therefore:

[tex]\begin{aligned}\text{average speed} &= \frac{\text{total distance}}{\text{total time}} \\ &= \frac{1000\; {\rm m}}{13\; {\rm s}} \\ &\approx 76.9\; {\rm m\cdot s^{-1}}\end{aligned}[/tex].

[tex]\begin{aligned}\text{average velocity} &= \frac{\text{total displacement}}{\text{total time}} \\ &= \frac{500\; {\rm m}}{13\; {\rm s}} && \genfrac{}{}{0px}{}{(\text{to the north})}{}\\ &\approx 38.5\; {\rm m\cdot s^{-1}} && (\text{to the north})\end{aligned}[/tex].

The runner who starts from rest and attains a speed of 8.00 ft/s, after 2.00 s his acceleration would be 4ft/s^2.

An object’s velocity can change depending on whether that object moves faster or slower or in a different direction.

A few instances of acceleration include an apple falling to the ground, the moon orbiting the earth, and a car coming to a stop at a stop sign.

Sir Isaac Newton (1642–1727) defined acceleration in his second law of motion as the relationship between the force acting on an object and its mass: a = f/m.

The meter per second per second square (m/s2) is the unit of acceleration. The newton is the force that causes an acceleration of one newton per kilograms of mass when it acts on that mass.

u=0 (initial speed)

v= 8 ft/sec (speed of the runner)

t = 2s

According to equation of motion,

a = (v-u)/ t = 8/2

a= 4ft/s^2

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After the equivalence point, pH of the base solution is 1.52.

The number of moles of base = 88.4 x 0.2700 = 23.868

The number of moles of acid = 0.4300 x 66.3 = 28.509

After the equivalence point,

Net moles of acid = 28.509 - 23.868

= 4.641mol

Total vol. of solution = 88.4 + 66.3 = 154.7mL

Conc. of Acid = moles/volume = 4.641/154.7 = 0.03M

pH = [tex]-log[H^{+} ][/tex] = -Log[0.03]

pH = 1.52

Hence, the pH of the base solution is 1.52.

The titration's equivalence point occurs when the amount of titrant applied is just sufficient to totally neutralize the analyte solution. In an acid-base titration, the solution only comprises salt and water at the equivalence point, where moles of base equal moles of acid.

The equivalency point for acid-base titrations is extremely simple to identify. To create a titration curve, different quantities of titrant are added, and then the pH of the solution is measured using a pH meter. Then, the curve's equivalence point can be determined.

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