At a construction site, a crane lifts an object to a certain height in 12 seconds, and a second crane does the same work in 6 seconds. Compared to the power developed by the first crane, the power developed by the second crane is which of the following?

A. The same

B. One-half as much

C. Twice as much

D. Four times as much

Answers

Answer 1

option C

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Related Questions

The free-body diagram below represents all the forces acting on an object. What is the net force acting on this object?




300 N right


100 N down


0 N up


200 N right

Answers

Answer:

200 N to the right

Explanation:

The 50 N forces cancel each other since they are opposing each other.

The Earth's biosphere is consists of
A(only the water on Earth that is in its solid form.
B(all of the Earth's water, including surface water, groundwater, snowcover, ice, and water in the atmosphere.
C(the part of the earth and its atmosphere in which living organisms exist or that is capable of supporting life.
D(the solid part of the earth consisting of the crust and outer mantle.

Answers

Answer:

The part of the earth and its atmosphere in which living organisms exist or that is capable of supporting life.

Explanation:

It’s in the definition of biosphere. “Bio” means “life,” so “biosphere” is that portion of the Earth capable of supporting life.

how far does a 1.2g bullet with kinetic energy of 1.2 j go in 2 seconds ?


Answers

Answer:

To calculate the energy in joules, simply enter the mass of ammunition (in grams) that you use, and the fps that you've read from your Chrono unit.

Use F = 1/T as your basis:
9. Find the frequency of a tuning fork that takes 2.50×10−3s to complete one oscillation.

The answer is 400 Hz but please show your work.

Answers

Time Period=T=2.5×10^{-3}s

Now

Frequency:-

[tex]\\ \rm\rightarrowtail \nu=\dfrac{1}{T}[/tex]

[tex]\\ \rm\rightarrowtail \nu=\dfrac{1}{2.5\times 10^{-3}}[/tex]

[tex]\\ \rm\rightarrowtail \nu=0.4\times 10^{3}[/tex]

[tex]\\ \rm\rightarrowtail \nu=400Hz[/tex]

The frequency for this time will be 400 Hz.

What is the frequency?

Frequency is defined as the ratio of the number of waves to time. It is denoted by f.

f=[tex]\frac{1}{T}[/tex] where,

f is the frequency and,

T is the time period.

SI unit of frequency is Hz.

There are different types of frequency in sound :

Infrasonic-The frequency is less than 20 Hz.Audible-The frequency is between 20Hz to 20,000 Hz.Ultrasonic-The frequency is greater than 20,000 Hz.

According to the question :

Given :

T= 2.50×[tex]10^{-3}[/tex]

f=[tex]\frac{1}{T}[/tex]

⇒f=1/(2.50×[tex]10^{-3}[/tex])

⇒400 Hz

Hence, the frequency for this time will be 400 Hz.

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A soft foam block of mass m slides without friction in the
positive x-direction with speed v. At time t = 0, a student briefly
pushes the block with a force probe in the positive x-direction. The
graph to the right shows the force probe's measurements as a
function of time during the push. Which of the following statements
is true about the block's momentum between t = 0 and t = t;?

Answers

The true statement about the blocks momentum is : The momentum of the block has increased by approximately 1/2 F₀t₁  ( B )

Change in Momentum

Given that the change in momentum is equivalent to the Area which is under the force time graph

where :

Area under the force time graph = 1/2 F₀t₁ . Therefore we can conclude that the momentum of the block has increased by an equivalent value of the are under the time graph.

Hence we can conclude that the true statement about the blocks momentum is The momentum of the block has increased by approximately 1/2 F₀t₁ .

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Attached below is the missing part of your question

missing options

The momentum of the block has decreased to zero at time t1. - AThe momentum of the block has increased by approximately 1/2 F0t1 - BThe momentum of the block has decreased by approximately 1/2 F0t1 - CThe change in momentum cannot be determined without knowing the distance by which the force probe compressed the block. - D

In most cultures, the difference between the majority viewpoint and the minority viewpoint is that the majority group is made to feel __________ and the minority group is made to feel __________. A. Divergent. . . Normal B. Equal. . . Superior C. Superior. . . Equal D. Normal. . . Divergent Please select the best answer from the choices provided A B C D.

Answers

The difference between the majority viewpoint and the minority view is that the majority group is made to feel normal and the minority group is made to feel divergent.

What is the viewpoint?

A vantage point or point of view from which something is viewed or assessed is known as the viewpoint The story is narrated from a variety of perspectives, including two major ones and several smaller ones.

Most studies comparing majority versus minority influence argue the author, places a premium on influence in the sense of prevailing. In this context.

There is evidence that majorities have greater public influence than minorities, and that minority impact when it happens, is mostly latent. In the current version,

Hence the difference between the majority viewpoint and the minority view is that the majority group is made to feel normal and the minority group is made to feel divergent.

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    Answer:  D        

Explanation:

Simplified for you.

How does energy affecf a wave?

Answers

The energy transported by a wave is directly proportional to the square of the amplitude. So whatever change occurs in the amplitude, the square of that effect impacts the energy. This means that a doubling of the amplitude results in a quadrupling of the energy.

Which is NOT a characteristic of
the temperate region?
A. a lot of organic matter
B. moderate temperatures
C. moderate rainfall
D. under-developed soil horizons

Answers

Answer:

under developed soil horizons

The particles that make up matter are ______, ions or molecules.

Answers

Answer:

Atoms.

Explanation:

Atoms are purely one bit of an element. Ions are positive or negative atoms. Molecules are not pure, they have other stuff with it.

When charging objects by induction which of the following must be true
A. A path to ground is not needed when using a positive source

B. The objects being charged must be conductors

C. The objects takes on the same charge as it's source

D. The source loses some of its charge ​

Answers

Answer:

C

Explanation:

because that's how science works

Tuning a piano to tune middle c on a piano, a tuner hits the key and at the same time sounds a 261 hz tuning fork. if the turner hears 3 beats per second, what are the possible frequencies of the piano key?

Answers

This question deals with the physics of resonance and sound. The possible frequency of the pano key is 258hz.

How to compute the variation in frequency

The beat of a frequency is the difference (an absolute value) in the frequencies produced by the two waves.

Beat per second equals |f1 - f2| Where

ft = Frequency of the Tunning fork and

fp= Frequency of the Piano Key

Hence

3 =  261 - fp

Solving for fp,

fp = 261-3

= 258hz

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0. 85 kg of lead, specific heat 128 J/kgC, is heated from 50 C to 95 C. How much heat energy did the sample absorb?

Answers

4896

0.85 x 45 x 128 = 4896

Change in energy = specific heat capacity x mass x change in temperature

A 20 Ohm resistance is connected
across the secondary winding of a
single-phase power transformer
whose secondary voltage is 150 V.
Calculate the primary voltage if the
supply current is 5 A, neglecting
losses.

Answers

Answer: 225 V

Explanation:

Given:

Secondary voltage,V2 = 150v

Resistance is connected across secondary winding,∴R2 = 20Ω

Supply current, ie, I1 = 5A

[tex]\text{Now, secondary current,} \ $I_{2}=\frac{V_{2}}{R_{2}}=\frac{150}{20}=7.5$$$\therefore I_{2}=7.5 \mathrm{~A}$$For Transformers, we have $\frac{N_{2}}{N_{1}}=\frac{V_{2}}{V_{1}}=\frac{I_{1}}{I_{2}}$ so, Taking $\frac{N_{2}}{N_{1}}=\frac{l_{1}}{l_{2}}$ inserting all given \& obtained values, we get $\frac{N_{2}}{N_{1}}=\frac{5}{7.5}$$$\therefore \text { Turns ratio }=\frac{N_{1}}{N_{2}}=\frac{7.5}{5}=\frac{3}{2}=3: 2$$[/tex]

[tex]\text{Again taking,}\frac{N_{1}}{N_{2}}=\frac{V_{2}}{V_{1}}$ \\So, \\$V_{1}=\frac{N_{1}}{N_{2}} V_{2}\\$ inserting all values, we get, $V_{1}=\frac{7.5}{5} * 150=225$\\Therefore, \fbox{Primary voltage, {$V_{1}=225 \mathrm{~V}$}}[/tex]

A thundercloud has an electric charge of 48.8 C near the top of the cloud and –41.7 C near the bottom of the cloud. The magnitude of the electric force between these two charges is 7980000 N. What is the average separation between these charges

a/ 1.51 km
b/ 2.53 Km
c/ 1.51 m
d/ 1001 m

Answers

Answer: 1.51 km

Explanation:

Coulomb's Law: The electrostatic force between two charge particles Q: and Q2 is directly proportional to product of magnitude of charges and inversely proportional to square of separation distance between them.

Or,   [tex]\vec{F}=k \frac{Q_{1} Q_{2}}{r^{2}}[/tex]

Where Q1 and Q2 are magnitude of two charges and r is distance between them:

Given:

Q1 = Charge near top of cloud = 48.8 C

Q2 = Charge near the bottom of cloud = -41.7 C

Force between charge at top and bottom of cloud (i.e. between Q: and Q2) (F) = 7.98 x 10^6N

k = 8.99 x 109Nm^2/C^2

So,

[tex]\begin{aligned}&7.98 \times 10^{6}=\left(8.99 \times 10^{9} \mathrm{Nm}^{2} / \mathrm{C}^{2}\right) \frac{48.8 \mathrm{C} \times 41.7 \mathrm{C}}{\mathrm{r}^{2}} \\&r=\sqrt{\frac{1.8294 \times 10^{13}}{7.98 \times 10^{6}}}=1.514 \times 10^{3} \mathrm{~m}=1.51 \mathrm{~km}\end{aligned}[/tex]

Therefore, the separation between the two charges (r) = 1.51 km

4. An archer pulls a bowstring back 0.440 m, and the spring constant of the bow is 545 N/m.
a.) Find the amount of work the archer did to draw the bow.
b.) Find the speed an arrow of mass 0.060 kg will have when it is shot from the bow.
Assume no losses from friction

Answers

Answer: (a)part:545nm multiply by 0.440m=239.8JEWELS(J)

(B):1/2MULTIPLY BY MVSQUARE(APPLY THE FORMULA OF KINETIC ENERGY)REARANGE THE FORMULA,V=2.13MS

Explanation:

SO FOR PART A, IN ORDER TO CALCULATE THE WORK DONE YOUR SUPPOSE TO APPLY THE FORMULA FORCE MULTIPLY BY DISTANCE WHICH IS THE FORMULA FOR WORK DONE,IN THIS SCENARIO YOU HAD A FORCE OF 545NM AND A DISANCE OF 0.440,SO I ORDER TO FIND THE WORK DONE WE MULTIPLIED THEM BOTHE ACCORDING TO THE FORMULA AND GOT THE ANSWER.

FOR PARTB,I JUST SIMPLY APPLIED THE FORMULA FOR KINETIC ENERGY AND SIMPLY REARRANGED IT IN ORDER TO FIND THE VELOCITY.I MADE V THE SUBJECT OF THE FORMULA.

what is the medium for an ocean wave? Provide evidence that the medium is not transferred when a water wave moves on a lake

Answers

The medium for an ocean wave is the ocean water which involves movement on the water body.

What is a Medium?

This is defined as a substance or material that carries the wave. In the case of ocean waves, the medium is referred to the ocean water.

The medium is not transferred when a water wave moves on a lake as energy is transported but the water molecules aren't which is why lakes have water present in them.

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Why was the light peppered moth able to flourish prior to the Industrial Revolution?
O by blending in with the trees
o the ability to fly
O an abundance of food
O fewer predators

Answers

Answer:

B. by blending in with the trees

Answer:

B. by blending in with the trees

Explanation:

An aircraft is in a steady climb, at an airspeed of 100 knots, and the flight path makes a positive 10 degree angle with the horizontal. Find the Rate of Climb.

Answers

The rate of climb of the aircraft in a steady climb making a 10 degree angle with the horizontal is : 17.36 knots

Given data

Airspeed = 100 knots

Angle with the horizontal ( ∅ ) = 10°

Determine the rate of climb of the aircraft

we will apply the formula below

Vy ( rate of climb ) = Airspeed * sin ∅

                              = 100 * sin ( 10 )

                              = 17.36 Knots

Hence we can conclude that rate of climb of the aircraft in a steady climb is : 17.36 knots.

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Two planets are orbiting a star in a distant galaxy the first has a semimajor axis of 150 x 10^6 km an eccentricity of 0. 20 and a period of 1. 0 earth years

Answers

For two planets orbiting a star in a distant galaxy, having the first semimajor axis of 150 x 10^6 km,  the period of the second plane  is mathematically given as

T=2.2earth year

What is the period of the second planet?

Generally, the equation for the time period  is mathematically given as

[tex]T^{2} \appox a^{3}[/tex]

Therefore, for planet one

[tex]1^2\approx (150 x 10^6)^3[/tex]

In conclusion, For planet 2

T^2=(250/150)^3

T=√4.632

T=2.2earth year

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The period of the second planet for two planets circling a star in a faraway galaxy with a first semimajor axis of 150× 10⁶ km. The time period of the planet will be 2.2 earth years.

What is the time period of the revolution?

The time period of the revolution is the time required to complete one revolution. It is guven by T. It is measured in seconds.

The equation of the time period is found as;

[tex]\rm T = \frac{250}{150} ^3 \\\\ T= \sqrt{4.632} \\\\ T=2.2 \ earth \ year[/tex]

Hence the time period of the planet will be 2.2 earth years.

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The change in momentum that occurs when a 1. 0 kg ball traveling at 4. 0 m/s strikes a wall and bounces back at 2. 0 m/s is.

Answers

Answer:

The change is momentum is given by ∆p=p(inital) - p(final) =4-2=2 kg.m/s

Explanation:

momentum is the product of mass and velocity (speed)

So it's initial momentum would be:

p=mv=(1)(4)=4 kg.m/s

It's final momentum is given by:

p=mv=(1)(2)=2 kg.m/s

1. The Particle Theory of Matter says that. A. Particles are in constant motion
b. Everything is made up of particles
c. Plasmas have charged particles
d. Solids have no particles

Answers

Answer:

a. Particles are in constant motion.

HELP MEEEE, question number 5

Answers

Explanation:

The gravitational potential energy of an object is given by GPE=mgh

where m is the mass of the object, g is the gravitational field strength (9.81 m/s² on earth) and h the height it is lifted at above the GPE reference ground.

Mass 1 has a GPE=m¹gh=(2)(9.81)(10)=196.2 Joule

Mass 2 has a GPE=m²gh=(4)(9.81)(10)=392.4 Joule

Object 2 has more potential energy and it makes sense since it's heavier

Hope this helps :))

For ____________, the error is calculated by finding the sum of squared distance between actual and predicted values

Answers

Answer: It is minimising

For minimizing, the error is calculated by finding the sum of the squared distance between actual and predicted values.

What is the error?

The difference between the measured and analysis of the financial statements might well be defined as an error. For instance, if the two operators use the same complete and precise tool.

We have:

For ____________, the error is calculated by finding the sum of the squared distance between actual and predicted values

The correct answer is minimizing because according to the information provided in the problem. The sum of squared distance between actual and anticipated values is calculated to "minimize" the mistake.

This is one of the most significant aspects of statistics, and it involves mathematical computations involving error calculations for various values.

Thus, for minimizing, the error is calculated by finding the sum of the squared distance between actual and predicted values.

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The amount of potential energy possessed by an elevated object is:.

Answers

...equal to the work done in lifting it.

If you have 10 ounces of meat, what percentage of the calories comes from fat if the meat is 90% lean?

Answers

Answer:

There are 602 calories in 10 ounces of Ground Beef (85% Lean / 15% Fat).  serving sizes of Ground Beef

Explanation:

hope this helps if not please let me now

What type of charge is acquired when a rubber is rubbed with a fur

Answers

Answer:

The triboelectic charging process (a.k.a., charging by friction) results in a transfer of electrons between the two objects that are rubbed together. Rubber has a much greater attraction for electrons than animal fur.

Explanation:

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THANKS^_^

Derive an expression for the block's centripetal acceleration ac in terms of m , θ , and physical constants, as appropriate

Answers

The expression for the block's centripetal acceleration is derived as ω²r or v²/r.

What is centripetal acceleration?

The centripetal acceleration of an object is the inward or radial acceleration of an object moving in a circular path.

The expression for the block's centripetal acceleration is derived as follows;

ω = dθ/dt

where;

ω is the angular speed θ is the angular displacementt is the time of motion

ac = ω²r

where;

r is the radius of the circular path

Also, ω = v/r

ac = (v/r)²r

ac = v²/r

Thus, the expression for the block's centripetal acceleration is derived as ω²r or v²/r.

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If an electron is released at the equator and falls toward earth under the influence of gravity, the magnetic force on the electron will be toward the

Answers

Using Fleming’s left hand rule,

The magnetic force on the electron will be west. Example: If it is dropped above the equator in Africa, the electron will head towards North America.

A solid cylindrical disk has a radius of 0.15 m. It is mounted to an axle that is perpendicular to the circular end of the disk at its center. When a 50-N force is applied tangentially to the disk, perpendicular to the radius, the disk acquires an angular acceleration of 110 rad/s2. What is the mass of the disk?

Answers

For A solid cylindrical disk has a radius of 0.15 m, The mass of the disk  is mathematically given as

M=6.06kg

What is the mass of the disk?

Generally, the equation for the Torque   is mathematically given as

t=Ia

Therefore

FR=Ia

50*0.15=M((15^2)/2*10)

M=100/110*15

M=6.06kg

In conclusion,  the mass of the disk

M=6.06kg

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A metal spoon was placed in a dish of ice cream and became cool. Which correctly describes the heat transfer process that resulted in the cooling of the spoon?.

Answers

Answer:

The heat went from the i cream to the spoon making it cool.

Explanation:

i just know.

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