The products of the double displacement reactions are given in the equations of the reaction below:
a. 3 Sn(OH)₂ (aq) + 2 FeBr₃ (aq) ---> 3 SnBr₂ (aq) + 2 Fe(OH)₃ (s)
Iron (iii) hydroxide is obtained as a precipitate
b. CsNO₃ (aq) + KCI (aq) ---> CsCl (aq) + KNO₃ (aq)
No double displacement reaction occurs as both products are soluble.
What are double displacement reactions?Double displacement reactions are reactions in which there is an exchange of radicals by two compounds when solutions of the compounds are added together.
In a double displacement reaction, an insoluble precipitate is obtained since one of the products of the double displacement reaction is insoluble in aqueous solutions.
The products of the double displacement reactions are given in the equations of the reaction below:
a. Reaction between Sn(OH)₂ and FeBr₃
3 Sn(OH)₂ (aq) + 2 FeBr₃ (aq) ---> 3 SnBr₂ (aq) + 2 Fe(OH)₃ (s)
Iron (iii) hydroxide is obtained as a precipitate
b. Reaction between CsNO₃ and KCI
CsNO₃ (aq) + KCI (aq) ---> CsCl (aq) + KNO₃ (aq)
No double displacement reaction occurs as both products are soluble.
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Classify each of the following chemical reactions as a synthesis decomposition and single displacement or double displacement reaction
1. Synthesis reaction : there is only 1 product formed from 2 or more reactant
E.g:
[tex]H_2(g)+N_2(g)\text{ }\Rightarrow2NH_3(g)\text{ }[/tex]2. Decomposition : reaction that occurs in presence of UV light and only 1 reactant that decomposes into 2 or more products.
E.g:
[tex]CH_3Br(g)+UV_{light}\Rightarrow CH_3(g)\text{ + Br (g)}[/tex]3. Single displacement : reaction that occurs when 1 reactant displaces other reactant from its compound:
E.g:
[tex]Zn(s)+CoCl_2(aq)\text{ }\Rightarrow ZnCl_2(aq)\text{ + Co(s)}[/tex]4. Double displacement : reaction that occurs when both reactant displaces each other.
E.g :
[tex]K_2S(aq)+Co(NO_3)_2\Rightarrow2KNO_3(aq)\text{ + }CoS(s)\text{ }[/tex]Create a table of different types of radioactive decay and the changes that result in each.
answer and explanation
Radioactivity is the emission of ionizing radiation from nuclear decay. there are three types of radioactive decay.
alpha decay
in alpha decay an alpha particle is released. In the parent atom, the atomic number decreases by 2 and the atomic mass decreases by 4
beta decay
in beta decay a beta particle is released, the atomic number is unchanged and the atomic mass increases by 1
gamma decay
in gamma decay, energy is released as gamma rays from an excited nuclear state. the atomic mass and atomic number remain unchanged.
6.5 grams of zinc reacted with hydrochloric acid. Calculate how many grams of hydrogen were released. a) 0.1 g. b) 0.2 g. c) 1.0 g. d) 2.0 g.
0.2 grams
ExplanationsThe balanced reaction between zinc and hydrochloric acid is given as:
[tex]Zn+2HCl\rightarrow ZnCl_2+H_2[/tex]Given the following parameters
Mass of Zinc = 6.5grams
Determine the mole of Zinc
Mole of Zn = mass/molar mass
Mole of Zn = 6.5/65.38
Mole of Zn = 0.0994moles
According to stoichiometry, 1 mole of Zinc produced 1 mole of hydrogen gas, hence the mole of hydrogen gas required will be 0.0994moles
Determine the mass of hydrogen gas produced
[tex]\begin{gathered} Mass\text{ of H}_2=mole\times molar\text{ mass} \\ Mass\text{ of H}_2=0.0944moles\times2.016 \\ Mass\text{ of H}_2=0.19g\approx0.2grams \end{gathered}[/tex]Hence the mass of hydrogen that were released is 0.2 grams
How many liters of NH3, at STP, will react with 5.3 g. O2 to form NO3 and water? 4NH3 (g) + 9O2 (g) —> 4NO3 + 6H2O (g)
Step 1
The reaction must be completed and balanced:
4NH3 (g) + 9O2 (g) => 4NO3 + 6H2O (g)
Reactants: NH3 and O2
Products: NO3 and H2O
--------------------
Step 2
Information provided:
STP conditions, therefore:
1 mole of gas (NH3 in this case) = 22.4 L (volume)
5.3 g of O2
Liters => L
Grams => g
---------
Information needed:
The molar mass of O2 = 32.0 g/mol
-------------------
Step 3
By stoichiometry,
1 mole NH3 = 22.4 L NH3
1 mole O2 = 32.0 g O2
Procedure: We will work with volume and mass
4NH3 (g) + 9O2 (g) => 4NO3 + 6H2O (g)
4 x 22.4 L NH3 ---------- 9 x 32.0 g O2
X ----------- 5.3 g O2
X = 5.3 g O2 x 4 x 22.4 L NH3/9 x 32.0 g O2 = 1.65 L approx.
Answer: 1.65 L of NH3
identify an element that has similar chemical properties as those of the element krypton (K).
Aluminum reacts with chlorine gas to form aluminum chloride. (a) If 35g of aluminum reacts with excess chlorine, how many grams of aluminum chloride will form. (b) How many grams of chlorine will react completely with 42.8 g of aluminum 2Al + 3Cl2 ==> 2AlCl3
Answer
(a) 172.848 grams
(b) 168.584 grams
Explanation
The balanced equation for the reaction of aluminum with chlorine gas is:
[tex]2Al+3Cl_2\rightarrow2AlCl_3[/tex](a) Mass of Al = 35 g
From the Periodic Table;
Molar mass of Al = 27 g/mol
Molar mass of AlCl₃ = 133.34 g/mol
From the balanced equation above; 2 moles Al produced 2 moles AlCl₃
So in grams, 2 mol x 27 g/mol = 54 g Al produced 2 mol x 133.34 g/mol = 266.68 g AlCl₃
Therefore, 35 g Al will form:
[tex]\frac{266.68\text{ g AlCl}_{3}\text{ }\times35\text{ g Al}}{54\text{ g Al}}=172.848\text{ g AlCl}_{3}[/tex]172.848 grams of aluminum chloride will be formed.
(b) Mass of Al = 42.8 g
Also from the Periodic Table; the molar mass of Cl₂ = 70.90 g/mol
From the equation above; 2 mol of Al requires 3 mol Cl₂.
In grams, 2 mol x 27 g/mol = 54 g Al requires 3 mol x 70.90 g/mol = 212.7 g Cl₂
Hence, 42.8 g Al will react with:
[tex]\frac{42.8\text{ g Al }\times212.7\text{ g Cl}_{2}}{54\text{ g Al}}=168.584\text{ g Cl}_{2}[/tex]168.584 grams of chlorine will react completely with 42.8 g of aluminum
the partial negative charge at one end of a water molecule is attracted to the partial positive charge of another water molecule. what is this attraction called?
Hydrogen bonding is formed when the partial negative charge at one end of a water molecule is attracted to the partial positive charge of another water molecule
Hydrogen bonding is a potent intermolecular force. In a water molecule, a partial negative charge is formed due to the oxygen, which is electro-negative.This oxygen gets attracted towards the positively charged Hydrogen, thus partial charges are shared between these two atoms of two different molecules.An electrostatic force is created between these molecules which helps in attraction of the partial charges.A hydrogen bond is formed between the water molecules which is formed due to hydrogen bonding. This kind of bond is formed between hydrogen atom and an electronegative atom, typically fluorine (F), nitrogen (N), or oxygen (O).Thus, when the partial negative charge at one end of a water molecule is attracted to the partial positive charge of another water molecule, hydrogen bonding is formed.
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A 695.7 ng sample of an unknown radioactive substance was placed in storage and its mass measured periodically. After 47 daysthe amount of radioactive substance had decreased to 86.96 ng. How many half-lives of the unknown radioactive substancehave occurred?
The decay of this radioactive unknown compound is a first-order process.
We can express the time dependence of its mass m using a first-order integrated rate law, where k is the rate constant:
[tex]m_t=m_0xe^{-kxt}[/tex]mt = mass at time t
m0 = initial mass
t = time
-----------------------------------------------------------------------------------------------------
Procedure:
1) We need to find "k":
From the first-order rate law we clear k,
[tex]\begin{gathered} \frac{m_t}{m_0}=\text{ }e^{-kxt} \\ \ln (\frac{m_t}{m_0})=\text{ -kxt} \\ \frac{\ln (\frac{m_t}{m_0})}{-t}=\text{ k} \end{gathered}[/tex][tex]k\text{ = }\frac{\ln (\frac{86.96ng}{695.7ng})}{-47}=0.044days^{-1}\text{ }[/tex]----------------------------------------------------------------------------------------------
2) We find the half-life from the value of k we have just calculated:
[tex]t_{\frac{1}{2}}=\text{ }\frac{\ln 2}{k}=\text{ }15.7\text{ days}[/tex]-----------------------------------------------------------------------------------------------
3) The number of half-lives of the unknown sample is:
Number of Half-lives = 47 days / 15.7 days = 3 (approx.)
Answer: Number of half-lives = 3
What is the percent yield if 15.5 g SO2 is obtained from the reaction of 42.5 g of O2 with excess ZNS according to the following equation 2ZnS (s) + 3O2 -> 2ZnO (s) + 2 SO2(g)
Answer:
Percent yield = 27.3%.
Explanation:
First, let's write the chemical equation:
[tex]2ZnS+3O_2\rightarrow2ZnO+2SO_2.[/tex]The limiting reactant, in this case, would be O2 because we have an excess of ZnS. So, we have to convert 42.5 g of O2 to moles. Remember that the molar mass of O2 is 32 g/mol (you can calculate the molar mass of a compound using the periodic table). The conversion will be:
[tex]42.5\text{ g O}_2\cdot\frac{1\text{ mol O}_2}{32\text{ g O}_2}=1.33\text{ moles O}_2.[/tex]With this value, we're going to find the number of moles of SO2 produced by 1.33 moles of O2. You can see in the chemical equation that 3 moles of O2 reacted produces 2 moles of SO2, so the calculation would look like this:
[tex]1.33\text{ moles O}_2\cdot\frac{2\text{ moles SO}_2}{3\text{ moles O}_2}=0.887\text{ moles SO}_2.[/tex]The next step is to find the mass of SO2 based on its number of moles and the molar mass of SO2 which is 64 g/mol, like this:
[tex]0.887\text{ moles SO}_2\cdot\frac{64\text{ g SO}_2}{1\text{ mol SO}_2}=56.8\text{ g SO}_2.[/tex]And finally, we replace the values that we have in the formula of percent yield:
[tex]\%\text{ yield }=\frac{experimental\text{ yield}}{theoretic\text{al yield}}\cdot100\%.[/tex]Our experimental yield is the mass that we obtained of SO2 which is 15.5 g and the theoretical yield is the mass that we found through stoichiometry which is 56.8g:
[tex]\%\text{ yield}=\frac{15.5\text{ g}}{56.8\text{ g}}\cdot100\%\approx27.3\%.[/tex]The percent yield of this reaction would be 27.3%
3.(a) Draw the following five-carbon hydrocarbons:•Pentane•Pentene•Pentyne(e)Classify each molecule and explain the differences between them. (Classes of organic molecules include alkanes, alkenes, alkynes, alcohols, carboxylic acids, aldehydes, ketones, esters, ethers, amines, and amides.)
Structural formulas are ways atoms and elements are arranged in a molecule. The structural formula of pentane, pentene, and pentyne are as shown below;
Pentane - C5H12
Pentene - C5H10
Pentyne - C5H8
e) Pentane is an alkane compound with a general formula CnH2n+2. The chemical formula of pentane is C5H12. There are only single bonds between the C-H atoms in the molecule.
Pentene is an alkene compound with a general formula of CnH2n. The chemical formula of pentene is C5H10. There is a double bond present between the C=H atoms. This double bond shows that the compound is an alkene.
Pentyne is an alkyne compound with a general formula of CnH2n-2. The chemical formula of pentene is C5H8. There is a triple bond present between the Carbon Hydrogen atoms. This presence of a triple bond shows that the molecule is an alkyne compound.
Calculate the mass (in g) of 5.86x10^20 SO3 molecules.
Answer
0.0779 g SO₃
Procedure
To solve this question, you will need to use the Avogadro's number equivalent to 6.02214 x 10^23 molecules/ mol, and then the molecular weight in grams per mole for the SO₃.
[tex]5.86\times10^{20}\text{ molecules SO}_3\frac{1\text{ mol SO}_3}{6.02214\text{ x 10}^{23}\text{molecules SO}_3}\frac{80.06\text{ g SO}_3}{1\text{ mol SO}_3}=0.0779\text{ g SO}_3[/tex]If I have 10.0g of Mg, what is my theoretical yield of MgCl2
Explanation:
First, let's write the balanced equation of formation of MgCl2 from Mg and Cl2:
Mg + Cl2 → MgCl2
Now let's transform 10.0g of Mg into moles, using the following formula: moles = mass/molar mass
molar mass of Mg = 24.3 g/mol
moles = 10/24.3
moles = 0.412 moles
Now we use the equation ratio between Mg and MgCl2 to find the quantity of MgCl2 in moles.
1 mole of Mg produces 1 mole of MgCl2.
So 0.412 moles of Mg produces 0.412 moles of MgCl2.
Now we transform 0.412 moles of MgCl2 into mass using the following formula: mass = moles x molar mass
Molar mass of MgCl2: 24.3 + (2*35.45) = 95.21 g/mol
Mass = 0.412 * 95.21
Mass = 39.2 g
Answer: The theoretical yield of MgCl2 is 39.2 g.
Synthesize Information If you calculate the percent composition of elements in a compound, is there enough information to determine the empirical formula for the compound? If yes, how? If no, improve the model by identifying and explaining additional information needed to identify the compound.
If you only have the percent composition of each element in a give compound, you can't determine yet the empirical formular for the compound. The problem is, the percent composition only gives relative numbers for each element. What can be determined is the empirical stochiometry of one element relative to the others.
For example, supose you have a compound with element X and Y, with the percent composition you can determine how much X you have relative to how much Y you have. Say you determine that for each 2 X you have 3 Y, the formula can be X₂Y₃ but it can also be X₄Y₆ or even othre possibilities.
To determine the empirical formula you need to know how many of one of the elements you have in each compound. A common way of getting the empirical formula is to use the percent composition and, in addition, the molar mass of the compound, which will make it possible to get the empirical formula from the relative ratios of each element you have.
Write down a specific step by step procedure of the titration process which the goal is to determine the unknown concentration of a basic solution.
Explanation:
Titration is a technique used to determine the amount of matter in a sample using a solution of known concentration. In other words, titration is a quantitative chemical analysis. In this process, the sample has its concentration determined through a chemical reaction when it is mixed with another substance. The use of pH indicators in this process is useful to determine the endpoint of the titration, indicating that the entire sample has reacted. Titration is used to accurately determine the amount of a substance, confirm that the concentration described on the label is true or that the amount of a chemical compound is indicated on the package.
Sample weighing: With the solid sample on a watch glass, weigh it on the balance.
Sample dissolution: The sample is transferred to an Erlenmeyer flask with water, where dissolution takes place.
Problem solution: The solution is transferred to a volumetric flask and the volume is made up with water, creating the problem solution.
Aliquot transfer: Remove an aliquot of the problem solution with the aid of a pipette and transfer it to an Erlenmeyer flask.
Titration: To the Erlenmeyer flask, the problem solution (titrated) is added and the solution of known concentration (titrant) is inserted into the burette.
An acid-base indicator is also added to the titrator to indicate when the titration should be stopped due to the color change. The color change indicates the end point or turning point of the titration.
After that, when the color change persists, the volume of titrant used is verified and stoichiometric calculations will help us to discover the concentration of the titrated solution.
Answer:
Step 1 - Sample weighing: With the solid sample on a watch glass, weigh it on the balance.
Step 2 - Sample dissolution: The sample is transferred to an Erlenmeyer flask with water, where dissolution takes place.
Step 3 - Problem solution: The solution is transferred to a volumetric flask and the volume is made up with water, creating the problem solution.
Step 4 - Aliquot transfer: Remove an aliquot of the problem solution with the aid of a pipette and transfer it to an Erlenmeyer flask.
Step 5 - Titration: To the Erlenmeyer flask, the problem solution (titrated - basic solution) is added and the solution of known concentration (titrant - acidic solution) is inserted into the burette.
Step 6 - An acid-base indicator is also added to the titrator to indicate when the titration should be stopped due to the color change. The color change indicates the endpoint or turning point of the titration.
Step 7 - After that, when the color change persists, the volume of titrant used is verified and stoichiometric calculations will help us to discover the concentration of the titrated solution.
Scientists discovered a rock formation in the mountains that
contains some amount of Uranium-235. Upon further testing you
learn that the rock is composed of 25% Uranium-235. Knowing that
the rock is 1.426 billion years old, how long is the half-life of
Uranium-235?
The half-life of the Uranium-235, given that the rock is composed of 25% Uranium-235 is 713 million years
How do i determine the half-life?First, we shall calculate the number of half lives that has elapsed. This can be obtained as follow:
Original amount of Uranium-235 (N₀) = 100%Amount remaining of Uranium-235 (N) = 25%Number of half-lives (n) =?2ⁿ = N₀ / N
2ⁿ = 100 / 25
2ⁿ = 4
2ⁿ = 2²
n = 2
Finally, we shall determine the half-life of the Uranium-235. This can be obtained as follow:
Number of half-lives (n) = 2 Age of rock (t) = 1.426 billion years Half-life (t½) = ?n = t / t½
Cross multiply
n × t½ = t
Divide both sides by n
t½ = t / n
t½ = 1.426 / 2
t½ = 713 million years
From the calculations made above, we can conclude that the half-life is 713 million years
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does lead melt in atoms or molecules
Answer:
Atoms
Explanation:
Answer:
atoms
Explanation:
its right, trust
Consider the balanced thermochemical equation given below: W(s) + 3 H2O(g) → WO3(s) + 3 H2(g) ∆Η° = –125.9 kJ How many grams of H2 were produced when 377 kJ of heat was produced?
Answer:
Explanation:Consider the balanced thermochemical equation given below: AH = -125.9 kJ W(s) + 3 H2O(g) WO3(s) + 3 H2(g) If a mass of 94.6 g H2 is produced, what is the enthalpy change? Express your answer in kJ. Express your answer to the correct number of significant figure, in scientific notation and include the unit with
Calculate the number of moles of magnesium, chlorine, and oxygen atoms in 8.30 moles of magnesium perchlorate,Mg(Cl04)2Express the number of moles of Mg, Cl, and O atoms numerically, separated by commas.moles of Mg, CI, O =
The question requires us to calculate the number of moles of each element (magnesium, chlorine and oxygen) in 8.30 moles of the compound magnesium perchlorate (Mg(ClO4)2).
From the molecular formula of magnesium perchlorate we can take the following information:
- in 1 mol of Mg(ClO4)2, there is only 1 mol of Mg;
- in 1 mol of Mg(ClO4)2, there are 2 moles of Cl;
- in 1 mol of Mg(ClO4)2, there are 8 moles of O.
With the information above, and knowing that the amount of Mg(ClO4)2 given by the question was 8.30 moles, we can calculate the amount, in moles, of each element:
1 mol Mg(ClO4)2 --------------- 1 mol Mg
8.30 mol Mg(ClO4)2 ---------- x = 8.30 mol Mg
1 mol Mg(ClO4)2 --------------- 2 mol Cl
8.30 mol Mg(ClO4)2 ---------- y = 2 x 8.30 mol Cl = 16.6 mol Cl
1 mol Mg(ClO4)2 --------------- 8 mol O
8.30 mol Mg(ClO4)2 ---------- z = 8 x 8.30 mol O = 66.4 mol O
Therefore, there are 8.30, 16.6 and 66.4 moles of Mg, Cl and O in 8.30 moles of magnesium perssufate.
Abed found fingerprints at a crime scene that match fingerprints that were taken from the suspect. What does this MOST likely mean?
A.
The suspect’s fingerprints match someone else’s.
B.
All 150 ridge characteristics are identical.
C.
The suspect touched something at the crime scene.
D.
At least three different points were a perfect match.
Answer:
C
Explanation:
Because the suspect touched something at the crime scene and thus he's fingerprint are matching
How much heat is released when 245 g of steam cools from 106.0°C to -4.5°C
ANSWER
The amount of heat released is -54, 957.175J
EXPLANATION
Given that;
[tex]\begin{gathered} \text{ The mass of the steam is 245g} \\ \text{ The final temperature of the steam is -4.5}\degree C \\ \text{ The initial temperature of the steam is 106.0}\degree C \end{gathered}[/tex]To find the amount of energy released, then apply the below formula
[tex]\text{ q = mc \lparen}\theta2\text{ - }\theta1)[/tex]Recall, that the specific heat capacity of steam (c) is 2.03 J/g degrees Celcius
[tex]\begin{gathered} \text{ q = 245 }\times\text{ 2.03 \lparen-4.5 - 106\rparen} \\ \text{ q = 245 }\times\text{ 2.03 \lparen -110.5\rparen} \\ \text{ q = -54,957.175J} \end{gathered}[/tex]Therefore, the amount of heat released is -54, 957.175J
Which of the following elements would have chemical properties similar to those of Na?O Ne KBr
Ne is a noble gas, O is a non metal and Br is an halogen.
K is a metal that belongs to the same group as Na, it means that they have similar chemical properties.
It means that the answer is K.
Question 7 of 10What makes up an ionic compound?O A. A positive cation and a negative anionB. A negative anion and a negative anionOC. A positive anion and a negative cationOD. A positive cation and a positive anionаSUBMIT
A ionic compound is made of two ions, one with positive charge and the other one with a negative charge.
The ion with positive charge is known as cation and the one with negative charge is known a anion.
It means that the correct answer is A. A positive cation and a negative anion.
I believe the incorrect statement is dissolution of oxygen in water is due to dipole- induced dipole interaction.
For this question we have 4 options and relates a few chemical concepts, let's analyze each option and reach a final conclusion:
A. Since in a geometric 3-D point of view, neopentane is more closely together in its bondings, the boiling point will be lower in it, and n-pentane has more surface to be heated, therefore the boiling and melting point will be higher, as it is proven experimentally, n-pentane = 36.1°C, neopentane = 9.5°C. Correct
B. If we have O2 being thrown in water, the covalent bonding between these two atoms is very nonpolar and weak, the weak Van der Waals force, also known as temporary dipole-induced dipole interactions. Correct
C. Dipole moment has a lot to do with the strength of a bond, greater the dipole moment, the stronger the bond will be, and if we have a strong bond, more energy will be required to break, therefore higher the boiling and melting point will be for these compounds, therefore this one is Incorrect
D. Yes, in DNA the main type of intermolecular force is Hydrogen bonding
How many moles of carbon dioxide are formed when reacting with 36 moles of oxygen?
1) Chemical equation
[tex]CH_4+2O_2\rightarrow CO_2+2H_2O[/tex]2) Moles of CO2 produced oxygen reacts
The molar ratio
2 mol O2: 1 mol CO2
[tex]molCO_2_{}=36molO_2\cdot\frac{1molCO_2}{2molO_2}=18molCO_2[/tex]If 36 mol O2 reacts, it will produce 18 mol CO2.
.
Which of these are true situations that could be explained by the kinetic molecular theory?Select all that apply.
Kinect-molecular theory hypothesis:
- The formation of a gas occurs by a large number of molecules;
- Gas molecules have a negligible dimension, which means that the volume occupied by them is very small, almost insignificant;
- These gases move in a discontinuous and random way, thus occupying the entire volume of the container where they are found, having a rectilinear and uniformly varied movement;
- They are independent, they only interact with each other when a collision occurs;
- Collisions between molecules and molecules and between molecules and container walls are elastic collisions, which cause the kinetic energy of the molecules to remain constant.
Having seen these statements, the answers can only be:
The warmer a glass of water, the faster a drop of ink will spread through the water.
The colder a room is, the longer it would take to smell a spray of perfume from the other side of the room.
A gas has a volume of 1.82 L at-30°C and 131 kPa. At what temperature would the gasoccupy 1.3 L at 233 kPa?Answer in units of°C.
To solve this problem we can use the Ideal gas law:
[tex]\frac{P_1\cdot V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]The problem give us de following information:
P1= 131kPa
V1=1.82L
T1=-30°C= 243.15 K
P2= 233 kPa
V2= 1.3L
Then we just have to solve for T2 and use the information provided:
[tex]T_2=\frac{P_2\cdot V_2}{P_1\cdot V_1}\cdot T_1=\frac{233\text{ kPa}\cdot1.3L}{131kPa\cdot1.82L}\cdot243.15K=308.91K=35.76°C[/tex]Then the answer is T2=35.76°C
How many copper atoms are in a pure copper statue with a mass of 187 kg?
Avogadro's number states that:
1 mol of Cu = 63.54 g of Cu = 6.02x10^23 atoms of Cu
Now, we proceed like this:
1 kg = 1000 g ===> 187 kg = 187,000 g
63.54 g Cu -------- 6.02x10^23 atoms of Cu
187,000 g Cu -------- X
X = 1.77x10^27 atoms Cu
Answer: 1.77x10^27 atoms Cu
A certain copper ore contains 3.24% of Cu2S by mass. In 1991, a single open-air smelt furnace heated 30000 tons of this ore. Compute the mass of copper metal obtained by this process. Enter in tons.
The mass of the copper that is obtained is 97.2 tons.
What is combustion?We can define the term combustion as the procedure by which a substance can be burnt in oxygen. We can also be able to refer to the process as roasting the object in the air. It is an oxidation reaction.
Having said all all of these, the reaction equation can be written as;
[tex]Cu_{2} S + O_{2} ------ > 2Cu + SO_{2}[/tex]
We know that the percent of the copper that it contains can now be used when we are trying to compute the mass of the copper that can be obtained from the process as we are going to have in the question that is at hand here to solve.
We are now going to proceed to see the mass of the copper that can be produced from the 300 tons of the copper I sulfide ore given.
Thus;
The mass of copper that can be obtained is;
3.24/100 * 3000 tons
= 97.2 tons
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True or false; The amount of energy required to heat 10 grams of water by 15 degreesCelsius is greater than that required to heat 10 grams of aluminum from15 degrees Celsius.
To answer this question we have to compare the specific heats of each substance.
The specific heat of a substance is the amount of energy required to make 1 gram of a substance increase its temperature by 1 °C. The greater the specific heat of a substance the more energy it will be required to heat it up.
The specific heat of water is 4.18J/g°C and the specific heat of aluminum is 0.897J/g°C.
It means that the amount of energy required to heat water is greater than the one to heat aluminum.
It means that the answer is TRUE.
Potential Molecular TheoryThere are 500 grams of Kl in a volumetric flask. It is dissolved in 1 liter of water. What is the molarity?3.141 M3.012 M0.500 M500.000 M20A precipitate is formed when two solutions are mixed. This would only occur if
Molarity or molar concentration is a measure of the concentration of a chemical species, of a solute in a solution, using as units, number of moles, and volume in liters. The formula for Molarity is:
M = n/V
Where:
n = number of moles
V = volume in Liters, 1 Liter
But we need to find the number of moles, we will do so by using its molar mass, KI = 166g/mol and the given mass in the question, 500g grams
166g = 1 mol
500g = x moles
x = 3.012 moles
Now we can use the Molarity formula
M = 3.012/1
M = 3.012 M, this is the molar concentration of the solution, 2