ASAP!!!
Arthur cuts a 24° slice from a pizza 22 inches in diameter. Find the length of AB.
(See attached photo)​

The magnitude of the speed of the particle is determined as √ (17), m/s.

option A.

The speed of a particle is defined as the rate of change of the particle's displacement with time.

Mathematically, the formula for the speed of the a particle is given as;

v = dx/dt

where;

The speed of the particle is calculated as;

v = u + at

where;

at time, t = 0, the equation for the speed of the particle becomes;

v = u

v = i + 4j

The magnitude of the speed is calculated as follows;

v = √ (1² + 4²)

v = √ (17), m/s

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Answer:

Step-by-step explanation:No, Lonnie is not correct. Step-by-step explanation: Because if we put 35 and 42 in rational form we can write it to its simple form by dividing it and after dividing we get the answer as 5 : 6. so that means Lonnie in incorrect.D

a) Based on the exponential function, p(t)=1200 (1.026)^t, the item's current price with a rate of inflation of 2.6% per year is $1,200.

b) In 8 years, the future price of the item would be $1,473.53.

An exponential function is a mathematical equation depicting the relationship between one variable and another with a periodic constant rate of growth or decline.

Exponential functions are classified into two:

Let the number of years from today = t

Annual inflation rate = 2.6%

Current price = $1,200

Time in years = 8 years

p(t)=1200 (1.026)^t

p(8) = 1,200(1.026)^8

= $1,473.53

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a)

The investment cost for replacing the 800 fixtures is $240,000.

b)

Annual utility cost savings is $57,600/year.

c)

Since the NPV is positive, the proposal should be accepted as it generates a positive return and is expected to be profitable.

We have,

a.

The investment cost for replacing the 800 fixtures is given as $300 per fixture, so the total investment cost would be:

Total Investment Cost = Number of fixtures x Investment cost per fixture

Total Investment Cost = 800 x $300

Total Investment Cost = $240,000

b.

To calculate the annual utility cost savings, we need to find the difference in the watt-hour consumption per fixture between HID and LED lighting, and multiply it by the number of fixtures, operating hours per day, operating days per year, and the metered utility rate per kilowatt-hour:

Energy consumption savings per fixture per hour = HID watt hour consumption - LED watt hour consumption

Energy consumption savings per fixture per hour = 500 watts/hr - 300 watts/hr

Energy consumption savings per fixture per hour = 200 watts/hr

Total energy consumption savings per hour for 800 fixtures:

= Energy consumption savings per fixture per hour x Number of fixtures

Total energy consumption savings per hour for 800 fixtures.

= 200 watts/hr x 800

Total energy consumption savings per hour for 800 fixtures.

= 160,000 watts/hr

Total energy consumption savings per year = Total energy consumption savings per hour x Operating hours per day x Operating days per year

Total energy consumption savings per year = 160,000 watts/hr x 10 hrs/day x 300 days/year

Total energy consumption savings per year = 480,000,000 watt-hours/year

Total energy consumption savings per year in kilowatt-hours (kWh):

= Total energy consumption savings per year / 1,000

Total energy consumption savings per year in kWh = 480,000,000 / 1,000

Total energy consumption savings per year in kWh = 480,000 kWh/year

Annual utility cost savings:

= Total energy consumption savings per year in kWh x Metered utility rate per kWh

Annual utility cost savings = 480,000 kWh/year x $0.12/kWh

Annual utility cost savings = $57,600/year

c.

To evaluate the proposal using net present value (NPV), we need to calculate the present value of the investment cost and the present value of the annual utility cost savings over a 15-year period.

Using the Present Value of the Ordinary Annuity formula with a 15-year life and 8% minimum rate of return, we get:

PV of Investment Cost = -$240,000 (negative because it's a cash outflow)

PV of Annual Utility Cost Savings = $514,883.81

NPV = PV of Annual Utility Cost Savings - PV of Investment Cost

NPV = $514,883.81 - (-$240,000)

NPV = $754,883.81

Therefore,

The investment cost for replacing the 800 fixtures is $240,000.

Annual utility cost savings is $57,600/year.

Since the NPV is positive, the proposal should be accepted as it generates a positive return and is expected to be profitable.

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The points are not at a distance of 6 units from each other.

Given that the distance between point (2, 2) and point (8, 2) is 6 units a coordinate plane.

We need to find which other pairs of points are also 6 units apart.

The distance between two points (x₁, y₁), (x₂, y₂) are 6 if and only if either

( x₂ - x₁ = 6 and y₂ = y₁ )or ( x₂ = x₁ and y₂ - y₁ = 6 ).

If either of the conditions is satisfied, then only we can say that the two points has distance of 6 units between them.

Now, As given

Let (x₁, y₁) = ( 2, 2) , (x₂, y₂) = (8, 2)

Check whether the conditions are satisfied or not .

Here x₁ = 2 , x₂ = 8, y₁ = 2, y₂ = 2

Now,

x₂ - x₁ = 8 - 2 = 6 , y₂ - y₁ = 2 - 2 = 0

∴ we get

1st condition is satisfied, So the points have a distance of 6 units between them.

Now,

Let us suppose another point (x₁, y₁) = ( 4, 3) , (x₂, y₂) = (3, 3)

Here x₁ = 4 , x₂ = 3, y₁ = 3, y₂ = 3

Now,

x₂ - x₁ = 4 - 3 = 1 , y₂ - y₁ = 3 - 3 = 0

Here neither of the conditions are satisfied.

So, the points are not at a distance of 6 units from each other.

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Answer: C. V ≈ 635.2 cm^3.

Explanation: The formula for the volume of a cone is V = (1/3)πr^2h, where r is the radius and h is the height (or slant height in this case).

Using the given values, we have:

V = (1/3)π(4.25 cm)^2(12 cm)

V ≈ 635.2 cm^3 (rounded to the nearest tenth)

Therefore, the answer is C. V ≈ 635.2 cm^3.

The area of the border is 105.53 feet².

We have,

The swimming pool is a combination of two shapes.

Rectangle:

Length = 60 feet

Width = 30 feet

Area = 60 x 30 = 1800 feet²

Semicircle:

Diameter = 30 feet

Radius = 15 feet

Area = π/2 r² = 1/2 x 3.14 x 15 x 15 = 353.25 feet².

Now,

The area of the swimming pool.

= 1800 + 353.25

= 2153.25 feet²

Now,

Without the border.

Area of the swimming pool.

= rectangle area + semicircle area

= 60 x (30 - 1) + 1/2 x π x (15 - 1)²
= 60 x 29 + 1/2 x 3.14 x 14 x 14

= 1740 + 307.72

= 2047.72 feet²

Now,

The area of the border.

= 2153.25 - 2047.72

= 105.53 feet²

Thus,

The area of the border is 105.53 feet².

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The log expression in single equation is   log 12 - log 3 + log 2.

The solution of the log equation is calculated by applying the following method.

log 12 - ¹/₂log 9  +  ¹/₃log 8

we can simplify the equation as follows;

log 12 - log 3 ⁽² ˣ ¹/₂⁾ +  log 2 ⁽³ ˣ ¹/₃⁾

= log 12 - log 3¹ + log 2¹

=  log 12 - log 3 + log 2

Thus, the log equation or expression has been simplified in the form of single equation.

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The surface area of the rectangular prism is 82 square cm.

Given that:

Length, L = 3 cm

Width, W = 7 cm

Height, H = 2 cm

Let the prism with a length of L, a width of W, and a height of H. Then the surface area of the prism is given as,

SA = 2(LW + WH + HL)

The surface area of the rectangular prism is calculated as,

SA = 2 x (3 x 7 + 7 x 2 + 2 x 3)

SA = 2 x (21 + 14 + 6)

SA = 2 x 41

SA = 82 square cm

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Answer:

If we are looking at 100th it is 176 if it's tens look at 7 and 9

The function type of f(x) = √3x + 2 is A. square root

From the question, we have the following parameters that can be used in our computation:

f(x) = √3x + 2

In the above function, we have the notation √

The notation √ is a square root notation

This means that the function type of f(x) is A. square root

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Answer:

[tex]f(x)=\dfrac{1}{20}x^5+\sinh(x)-\dfrac{1}{2}\sinh(2)x+6[/tex]

Step-by-step explanation:

Given:

    [tex]\phantom{ww} \bullet\;\;\;f''(x)=x^3+\sinh(x)[/tex]

    [tex]\phantom{ww} \bullet\;\;\;f(0)=6[/tex]

    [tex]\phantom{ww} \bullet\;\;\;f(2)=7.6[/tex]

To find f'(x), integrate f''(x):

[tex]\begin{aligned}\displaystyle f'(x)=\int f''(x)\; \text{d}x&=\int \left(x^3+\sinh(x)\right)\; \text{d}x\\\\&=\int x^3\;\text{d}x+\int \sinh(x)\; \text{d}x\\\\&=\dfrac{1}{4}x^4+\cosh(x)+\text{K}\end{aligned}[/tex]

To find f(x), integrate f'(x):

[tex]\begin{aligned}\displaystyle f(x)=\int f'(x)\; \text{d}x&=\int \left(\dfrac{1}{4}x^4+\cosh(x)+\text{K}\right)\;\text{d}x\\\\&=\int \dfrac{1}{4}x^4\; \text{d}x+\int \cosh(x) \; \text{d}x + \int \text{K}\; \text{d}x\\\\&=\dfrac{1}{20}x^5+\sinh(x)+Kx+\text{C}\end{aligned}[/tex]

Substitute f(0) = 6 to determine the value of the constant C:

[tex]\begin{aligned}f(0)=\dfrac{1}{20}(0)^5+\sinh(0)+K(0)+\text{C}&=6\\\\0+0+0+\text{C}&=6\\\\\text{C}&=6\end{aligned}[/tex]

Substitute f(2) = 7.6 and C = 6 to determine the value of the constant K:

[tex]\begin{aligned}f(2)=\dfrac{1}{20}(2)^5+\sinh(2)+K(2)+6&=7.6\\\\1.6+\sinh(2)+2K+6&=7.6\\\\\sinh(2)+2K&=0\\\\2K&=-\sinh(2)\\\\K&=-\dfrac{1}{2}\sinh(2)\end{aligned}[/tex]

Therefore, function f(x) is:

[tex]\boxed{f(x)=\dfrac{1}{20}x^5+\sinh(x)-\dfrac{1}{2}\sinh(2)x+6}[/tex]

[tex]\textsf{As}\;\;\sinh(2)=\dfrac{e^4-1}{2e^2},\;\textsf{we can also write the equation as:}[/tex]

[tex]f(x)=\dfrac{1}{20}x^5+\sinh(x)-\dfrac{1}{2}\left(\dfrac{e^4-1}{2e^2}\right)x+6[/tex]

[tex]f(x)=\dfrac{1}{20}x^5+\sinh(x)-\left(\dfrac{e^4-1}{4e^2}\right)x+6[/tex]

The solution and graph of each of the inequalities is shown below:

In Mathematics and Geometry, an inequality simply refers to a mathematical relation that is typically used for comparing two (2) or more numerical data and variables in an algebraic equation based on any of the inequality symbols;

Next, we would determine the solution for each of the inequalities as follows;

k + 7 ≥ 11

k ≥ 11 - 7

k ≥ 4

5 > v - 12

5 + 12 > v

17 > v

v < 17 (flip).

-5x ≤ -30

x ≤ 6

y/4 > 2

y > 2(4)

y > 8

10g + 19 > 49

10g > 49 - 19

10g > 39

g > 3.9

-w - 7 > 0

-w > 7

w > -7

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Answer:

To answer the question, you first need to understand what a net is. A net is a two-dimensional diagram that can be folded to form a three-dimensional object. In the context of this question, a net represents the unfolded and flattened-out shape of a flower box before it is assembled.

To draw a net that represents a flower box, you need to imagine what the box would look like if it were flattened out and unfolded. You can start by drawing a rectangle for the bottom of the box. Then draw four rectangles that represent the sides of the box. Each of the side rectangles should be the same length as the length of the bottom rectangle, and the width of each side rectangle should be the same as the height of the box.

Next, you need to label the net to indicate which sides will be connected to form the box. Label the edges of the rectangles with the corresponding letter to show how the box will be assembled. For example, label the top edge of the bottom rectangle as "A" and the bottom edge of one of the side rectangles as "B". Then, label the side edges of the side rectangle as "C" and "D".

To find the amount of material George needs for each box, you need to calculate the total surface area of the net. The surface area represents the amount of material needed to cover the entire box. You can find the surface area by calculating the area of each rectangle and adding them together.

In this case, the bottom rectangle has an area of 16 square inches, and each of the four side rectangles has an area of 8 square inches. Therefore, the total surface area of the net is:

16 + 4(8) = 48 square inches

This means that George needs 48 square inches of material to make one flower box.

You drew the net the way you did because it represents the flattened-out and unfolded shape of the flower box before it is assembled. Labeling the edges and rectangles helps to visualize how the box will be assembled and allows you to calculate the surface area needed to cover the entire box.  

have a good day and stay safe

Each of the graphs should be matched with the appropriate function as follows;

Graph 1: D. f(x) = (x - 2)² + 3

Graph 2: C. f(x) = -(x - 2)² - 3

Graph 3: B. f(x) = -(x - 3)² - 2

Graph 4: C. f(x) = (x - 3)² + 2

In Mathematics and Geometry, the standard or general form of a quadratic function can be modeled and represented by using the following quadratic equation;

y = ax² + bx + c

Where:

Mathematically, the vertex form of a quadratic function is modeled by this equation:

f(x) = a(x - h)² + k

Where:

In conclusion, we can logically deduce that each of the given quadratic function were either vertically translated or horizontally translated.

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The measure of the missing angle is 20 degrees.

The figure in the image is a right triangle.

To solve for the missing angle. we use trigonometric ratio.

Note: Tangent = Opposite / Adjacent

Plug in the values and solve for the angles:

tanθ = 8/20

Take the tan inverse

θ = tan⁻¹( 8/20 )

θ = 21.8°

θ ≈ 20°

Therefore, the angle is 20 degrees.

Option B)20° is the correct answer.

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There is 1 smaller can that will be put on the shelve.

Given that, a clerk is placing cans of soup on an 8-ft long shelf, we need to find how many more of the smaller cans will fit on the shelf than the larger cans,

Volume of small cans = 127.2 in³

Therefore,

127.2 = 3.14 × 4.5 × r²

r² = 127.2 / 14.13

r² = 9

r = 3

Similarly, the volume of the large can = 301.6 in³

301.6 = 3.14 × 6 × r²

r² = 16

r = 4

The number of small cans that can be out on the shelve = 8/3 ≈ 9

The number of larger cans that can be out on the shelve = 8/4 = 2

Hence, there is 1 smaller can that will be put on the shelve.

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Answer: - None of the above.

Step-by-step explanation:

The median is the middle value of the data set when arranged in order. In this case, we have an even number of values, so we need to take the average of the middle two values to find the median. The middle two values are 80 and 85. Therefore, the median student score is:  (80 + 85) / 2 = 82.5

The closest answer choice to this value is C. 85, but it is not the correct answer. Therefore, the correct answer is none of the above.

The experimental probability of the rolling a 6 is 13%.

Probability is the likelihood of a desired event happening. Experimental probability is a probability that relies mainly on a series of experiments.

From the table:

The total number of times all the numbers appear is:

total number of times = 7 + 4 + 4 +  5 + 6 + 4 = 30

The number six (6) occurred 4 times.

Experimental probability = (occurrence of 6 / total number of times)

Experimental probability = 4/30 * 100

Experimental probability = 13%

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The probability that the sum of the numbers is even is,

⇒ P = 0.47

Since, We know that;

To have this kind of event you can have the following events, where

(d₁ ,d₂),  d1 is the number that appears uppermost on die 1 and d2 is the number that appears uppermost on dice 2:

(1, 1), (1, 3) , (1, 5), (2, 2), (2, 4) (2, 6) (3, 1) (3, 3) (4, 2) (4, 4) (4, 6), (5, 1) (5, 3), (5, 5) (6, 2) (6, 4) (6, 6)

And,  the total number of events is 36 since every dice have 6 numbers.

The probability is:

P(Event)=P(sum is even)/Total number of events

P = 17/36

P = 0.47

Thus, The probability that the sum of the numbers is even is,

⇒ P = 0.47

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The requried value of x that satisfies the problem is 4.5,

Let's start by finding the side length of the square tabletop, which is equal to the square root of its area. We have:

Area = 9x² - 30x + 25

Side length = √(Area) = √(9x² - 30x + 25)

To find x, we need to use the fact that the perimeter of the table top is 34 feet. The perimeter of a square is given by 4 times the length of one of its sides, so we can write:

Perimeter = 4 * Side length

34 = 4 * √(9x² - 30x + 25)

8.5 = √(9x² - 30x + 25)

9x² - 30x - 47.25 = 0

We can solve this quadratic equation by using the quadratic formula gives,

x = 4.5 and -1.16

Therefore, the value of x that satisfies the problem is approximately 4.5, since the other solution is negative and not meaningful in this context.

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The measure of side DF is 15cm

Similar triangles are triangles that have the same shape, but their sizes may vary. For two traingles to be similar, the corresponding angles of the triangles must be equal.

And also, the ratio of corresponding sides of Similar triangles are equal

This means;

15 /25 = 9/DF

representing DF by x

15/25 = 9/x

15x = 25×9

15x = 225

divide both sides by 15

x = 225/15

x = 15cm

Therefore the measure of DF is 15cm

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The painted area of the sign is approximately 324 square inches. This was calculated by finding the area of the pole, square signboard, and triangle portion of the signboard and adding them together.

To find the painted area, we need to find the area of the pole, the area of the square signboard, and the area of the triangular portion of the signboard.

Area of pole

The pole is a rectangular prism with height 60in and width 4in. Therefore, the area of the pole is:

60in x 4in = 240 sq. in.

Area of square signboard

The square signboard has a side length of 8in. Therefore, the area of the square signboard is:

8in x 8in = 64 sq. in.

Area of triangular portion of the signboard

The triangular portion of the signboard has a base of 8in and a height of 5in. Therefore, the area of the triangular portion of the signboard is:

(1/2) x 8in x 5in = 20 sq. in.

Total painted area

The total painted area is the sum of the area of the pole, the area of the square signboard, and the area of the triangular portion of the signboard. Therefore, the painted area is:

240 sq. in. + 64 sq. in. + 20 sq. in. = 324 sq. in.

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--The given question is incomplete, the complete question is given

" clara is running a bakery she has made a street sign to direct people to her bakery . She painted one of the post and sign. What is the painted area?8in,8in,5in, 60in, 4in "--

Answer:

2700

Step-by-step explanation:

20 inches x 15 inches x 9 inches! <3

also get some sleep lol

The parent function is [tex]y = ab^x[/tex]

A function for the translation indicated is [tex]y = ab^{x+6} - 7[/tex].

In Mathematics and Geometry, the vertical translation a geometric figure or graph downward simply means adding a digit to the value on the y-coordinate of the pre-image or function.

In Mathematics and Geometry, a horizontal translation to the right is modeled by this mathematical equation g(x) = f(x - N) while a vertical translation to the negative y-direction (downward) is modeled by this mathematical equation g(x) = f(x) - N.

Where:

In this scenario, we can logically deduce that the graph of the parent function  was translated or shifted to the left (horizontally) by 6 units and downward (vertically) by 7 units;

[tex]y = ab^x[/tex]

[tex]y = ab^{x+6} - 7[/tex]

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To check if a solution is correct for a system of equations, we substitute the values of the solution into both equations and see if they are true.

Let's assume that the solution for the system of equations is (x,y) = (1,-1).

To check if this solution is correct for the first equation y = 2x - 3, we substitute x = 1 and y = -1:

-1 = 2(1) - 3

-1 = -1

Since -1 = -1, the solution (1,-1) satisfies the first equation.

To check if this solution is correct for the second equation y = -1/2x + 2, we substitute x = 1 and y = -1:

-1 = -1/2(1) + 2

-1 = 1

Since -1 is not equal to 1, the solution (1,-1) does not satisfy the second equation.

Therefore, the solution (1,-1) is not a solution for the system of equations y = 2x - 3 and y = -1/2x + 2.

The correct graph of the system of equations 3x + y = 12 and x - 4y = 4 is:

The graph shows a line with an x-intercept at (4, 0) and a y-intercept at

(0, -1). There is a second line with an x-intercept at (4, 0) and a y-intercept at (0, 12).

We have,

To graph the system of equations 3x + y = 12 and x − 4y = 4, we first need to rearrange them in slope-intercept form (y = mx + b) where m is the slope and b is the y-intercept:

3x + y = 12 => y = -3x + 12

x - 4y = 4 => y = (1/4)x - 1

Now we can see that the first equation has a slope of -3 and a y-intercept of 12, while the second equation has a slope of 1/4 and a y-intercept of -1.

Now,

The x-intercept is when y = 0.

So,

3x + y = 12

3x = 12

x = 4

And,

x - 4y = 4

x = 4

Thus,

The correct graph of the system of equations 3x + y = 12 and x - 4y = 4 is:

The graph shows a line with an x-intercept at (4, 0) and a y-intercept at

(0, -1). There is a second line with an x-intercept at (4, 0) and a y-intercept at (0, 12).

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Mary has the qualities of being a team leader.

Here, we have,

Team leaders upload any other stage of control. They’re employed to persuade and construct relationships, to make matters happen. Team chief’s to-do lists may be vast, however through categorizing them, it’ll come up with readability approximately the reason of your job.

A group chief has an outline of a set of humans, motivates, offers guidance and video display units performance. It is probably an professional identify alternate or a delegation exercising out of your management, however both way, being a group chief separates you out of your friends as a depended on individual to manipulate a assignment or institution of humans.

Team leaders and executives have exceptional responsibilities. Unlike managers, group leaders won’t have the authority to direct, alternate plans, put in force or construct their groups via hiring and firing. Their position is mostly a motivational and inspirational one inside an organization. They’re professional dating developers and mediators, liaising among the humans and management.

Thus this are the qualities of team leader.

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complete question;

Mary is a perfectionist . She loves participating on teams and often takes on too many tasks because she wants to ensure that they are done on time and on budget.

Answer:5.08

4.34 are correct

Step-by-step explanation:We can solve this quadratic equation in sin(θ) by using the substitution u = sin(θ):

6u^2 - 3u - 8 = 0

We can use the quadratic formula to solve for u:

u = (-b ± sqrt(b^2 - 4ac)) / 2a

where a = 6, b = -3, and c = -8. Substituting these values, we get:

u = (3 ± sqrt(9 + 192)) / 12

u = (3 ± sqrt(201)) / 12

Therefore, either: