ASAP
A train is travelling at 100 m/s when it receives an alert: “Brake! 600 meters ahead, the rails are broken”. The highest acceleration that the train can produce is 10 m/s^2. If the train slows down with a constant acceleration of 10 m/s^2
How long will it take for the train to stop?
How many meters will it travel before it stops?
Botcookiemaster please don't use a file just give me the answer

Answers

Answer 1

[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]

Let's consider the given terms ~

Initial velocity (u) = 100 m/s

Acceleration (a) = - 10 m/s²

(Acceleration is negative bbecause train slows down)

Final velocity (v) = 0 m/s

(final velocity is 0, because train stops)

Now, let's find the time taken (t) by using the first equation of motion ~

[tex]v = u + at[/tex]

[tex]0 = 100 + ( - 10 \times t)[/tex]

[tex]0 = 100 - 10t[/tex]

[tex]10t = 100[/tex]

[tex]t = 100 \div 10[/tex]

[tex]t = 10[/tex]

The train will take 10 secs to stop,

Now, let's find how much distance (s) it will cover before it stops using second equation of motion ~

[tex]s = ut + \dfrac{1}{2} at {}^{2} [/tex]

[tex]s = (100 \times 10) + ( \dfrac{1}{ 2} \times - 10 \times 10 \times 10)[/tex]

[tex]s = 1000 + ( - 500)[/tex]

[tex]s = 1000 - 500[/tex]

[tex]500 \: \: m[/tex]

It will cover 500 meters before coming to rest ~


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I'LL MARK YOU BRAINLIST!!
ali starts moving his car from rest and accelerates it at 5 m/s^2 over 8 seconds. what is the velocity of ali's car reached by the end of these 8 seconds ?

Answers

Explanation:

u=0, v=?, a=5m/s², t=8sec

So, by the formula,

v=u+at

v=0+5×8

v=40m/s.

hope this helps you .

What average force magnitude is required to stop a 15,000 kg train in 12.1 s if the train is traveling at 86 km/hr

Answers

Answer:

Explanation:

Givens

m = 15000 kg

t = 12.1 seconds

vi = 86 km / hr

vf =0

Formula

F = m*a

a = (vf - vi)/ t

vi has to be converted to m/s

86 km/hr [1000 m / 1 km] * [1 hour / 3600 seconds]

86 * 1000 / 3600 = 23.89 m/s

Solution

a = (vf - vi) / t

a = (0 - 23.89)/12.1

a = - 1.97 m/s^2 The minus means that the trains is slowing down.

F = 15000 kg * - 1.97 m/s^2

F = -29615.7 Newtons.

Find the work done while lifting a 115 kg sofa 1.5 m off the ground.
Find the weight first

Answers

P= 10m = 10 x 115 = 1150 N

work done while lifting a 115 kg sofa 1.5 m off the ground :

A= Ph = 1150 x 1.5 = 1725 J

P/s: I think the weight first is 115kg

ok done. Thank to me :>

Please help me calculate this question along with the equation

Answers

Hi there!

We can use the following:

U (Gravitational Potential Energy) = mgh

m = mass of object (kg)

g = acceleration due to gravity OR gravitational field strength

h = height, or displacement (m)

ΔU = Uf - Ui, so:

Uf = 3 × 1.5 × 10 = 45 J

Ui = 3 × 0 × 10 = 0

ΔU = Uf - Ui = 45 - 0 = 45 J

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BRAINLIST PLS

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It should be mentioned that an efficient way to work this vector addition problem is with the cosine law for general triangles (and since  

a

,

b

 and  

r

 from an isosecles triangle, the angles are easy to figure). However, in the interest of reinforcing the usual systematic approach to vector addition, we note that the angle  

b

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0

+105

0

=135

0

(a) The x component of  

r

x

=(10.0m)cos30

0

+(10.0m)cos135

0

=1.59m

(b)  the y component of  

r

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y

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0

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r

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r

∣=

(1.59m)

2

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2

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(d) The angle between  

r

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−1

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Answers

Answer:

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Answer:

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Answers

Explanation:

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Answers

Answer:

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From the question we have

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NEED ANSWER ASAP!
Which statement about a converging lens is not correct?

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Answer:

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Answer:

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Answers

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