As officer konstantin explains, when driving at 60 mph, in four seconds, you've traveled?

Answer:

Rolling Friction

Explanation:

Friction always acts in the opposite direction to that of the motion of the other object. Meaning, friction slows down the motion of an object by exerting opposing forces on it

The speed of the electron as it emerges from the field is; 388.587 m/s

Initial speed; v₀x = 1.1 * 10⁶ m/s

Acceleration in horizontal direction = 0 m/s²

distance; s_x = 2 cm = 0.02 m

Thus, formula to find time here is;

t = s_x/v₀x

t = 0.02/(1.1 * 10⁶)

t = 1.82 * 10⁻⁶ s

Now for the vertical distance; v,y_o = 0 m/s

Thus, the equation of motion becomes;

s_y = ¹/₂at²

0.005 = ¹/₂a(1.82 * 10⁻⁶)²

Solving for a gives;

a = 3.02 * 10¹³ m/s²

Thus the speed of the electron as it emerges from the field is;

v² = u² + 2as

v = √(0² + 2(3.02 * 10¹³ * 0.005))

v = 388.587 m/s

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Complete Question is;

An electron is projected with an initial speed v0 = 1.1 * 10⁶ m/s into the uniform field between the parallel plates. The distance between the plates is 1 cm and the length of the plates is 2 cm. Assume that the field between the plates is uniform and directed vertically downward, and that the field outside the plates is zero. The electron enters the field at a point midway between the plates. E = N/C

find the speed of the electron as it emerges from the field?.

Answer:

lol the SUN

Explanation:

Answer:

bro SUN just sun giving us heat

The heat of the surroundings is  - 4482 J.

A calorimeter is a device in which that is no exchange of heat between the device and the environment. In other words, there could only be exchange of heat when the a substance has been put inside the calorimeter.

We know that in a calorimeter;

Heat of the surrounding =  Heat of the system

That implies that they are of the same magnitude but of opposite direction hence the heat of the system is - 4482 J.

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The probability of rolling a one is twice that of rolling any other number.

Then the probability of rolling a 1 is 1/6.

The probability of something is how likely it is to happen. When we don't know how an event will turn out, we can talk about the probabilities of several outcomes—how likely they are. Examining events with a probability component is known as statistics.

Probability is a mathematical concept used to determine the likelihood of an event. It is challenging to make an accurate prediction for many events. We can only predict an event's likelihood, or how probable it is to occur, by using it.

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The velocity vector is (v = 3ti + 4tj + k) and the position vector is (x = (3t²/2 + 1) i + 2t²j + tk)

We need to know about vector to solve this problem. The velocity is depend on position vector and acceleration. It can be written as

v = dx / dt

where v is velocity, dx is displacement and dt is time interval.

By differentiating the velocity function, we can also get the acceleration

a = dv / dt

where a is acceleration.

From the question above, we know that

a(t) = 3i + 4j

Hence, the velocity is

a = dv / dt

dv = a . dt

v = ∫a . dt

v = ∫(3i + 4j) . dt

v = (3i + 4j)t + v(0)

because v(0) is k, thus

v = 3ti + 4tj + k

Find the position vector

v = dx / dt

dx = v . dt

x = ∫v . dt

x =  ∫(3ti + 4tj + k) . dt

x = (3t²/2 i + 2t²j + tk) + x(0)

because x(0) is i, thus

x = 3t²/2 i + 2t²j + tk + i

x = (3t²/2 + 1) i + 2t²j + tk

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Answer:

Shaking hands with the opponent at the end of the game.

Explanation:

Hope this helps.

The correct answer is 1.5 seconds.

We are aware that the differentiation is used to calculate the rate at which a quantity changes over time. We are aware that the velocity is the name given to the derivative of the displacement. Acceleration is what we get when we differentiate velocity.

x = t^4 - 6t^2 + 9t

To calculate the velocity, take the derivative.

v = 4t^2 - 12t + 9

To acquire acceleration, repeat the derivative.

a = 8t - 12

force:

F = ma

If a = 0, F = 0. As a result, when a = 0, the net force on the locomotive is equal to zero.

a = 0 = 8t -12

8t -12 = 0

8t = 12

t = 12/8 = 1.5 seconds

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In SI, prefixes are used with the names of the base unit to indicate the multiple of 10 that is being used with the base unit

Base units are units used for various measurements such as length, time, mass, temperature etc. For example the SI base unit of length is meter, SI base unit of time is second, SI base unit of mass is gram and SI base unit of temperature is kelvin.

Prefixes such as kilo, mega, giga, deci, centi, milli, micro, nano etc are used with base units mentioned above to indicate multiples and submultiples of 10. The multiples of 10 are used to mention larger measurements and the submultiples of 10 are used to mention smaller measurements. For example, the total unit will be called as millimeter, kilo seconds etc.

Therefore, in SI, prefixes are used with the names of the base unit to indicate the multiple of 10 that is being used with the base unit.

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The two possible angles to where this water from the the hose travels at are 24.9° (below the horizontal) and 85.2° (above the horizontal)

Equations of motion in physics are the kind of equations that explain how any physical system behaves in terms of how its motion changes over time.

This kind of behavior of a physical system is described in more detail by the equations of motion as a collection of mathematical functions expressed in terms of dynamic variables.

The three equations of motion can be stated as follows:

v = u + at.

v² = u² + 2as.

s = ut + ½at²

So, from this we already have the idea about,

V = U + at

35 = 0 + 80 cosθ t

also,

S = Ut + 1/2a t^2

-20 = -80 sinθt + 1/2 (-32.2)t^2

Thus, we have

20 (cosθ)^2 = 17.5 sin2θ + 3.0816

solving for theta, we have

θ1 = 24.9° (below the horizontal)

θ2 = 85.2° (above the horizontal)

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Answer:

why?

Explanation:

Do you need any help on anything else?

Answer:

The car moving at velocity 15 m/s will take 2.67 s to travel 40 m.

What do you mean by velocity?

An object's velocity can be defined as the rate of change in the object's position with respect to a frame of reference and time.

A rocket launching into space and a car going north on a busy freeway may both be quantified using velocity.

Explanation:

Velocity of the car = 15 m/s

Distance = 40 m

Therefore, time taken to travel 40 m at a velocity of 15 m/s

= 40/15 = 2.666 ≈ 2.67 s

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d = -1 m

The negative sign indicates that the charge from that force of the space of the two spheres.

When charged matter is exposed to an electromagnetic field, its electric charge—a property of matter—causes it to feel a force. An electric charge can be either positive or negative (commonly carried by protons and electrons respectively). Like and unlike charges are attracted to one another while being repelled by the other. Neutral describes a thing without any net charge. Classical electrodynamics, a term coined to describe early understanding of the interactions of charged particles, is still applicable to issues that do not demand for taking quantum effects into account.

The net charge, or the total of the positive and negative charges, is constant in an isolated system because electric charge is a conserved attribute. Electrical charge is transported by subatomic particles.

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A 900 kg car that exerts 5000 n of applied force on a level road while being opposed by 1000 n of friction -the acceleration of the car is 44.4  m/s².

Given that

To find

So, according the question

we have,

     mass of the car m = 900 kg

     applied force by car f = 5000 n

     friction force r = 1000 n

now,

    total net force (F) = applied force (f)- friction force (r)

                              F = 5000 - 1000

                              F = 4000 n

we know that,

                             F = ma

where,

      m = mass of car

       a = acceleration

So, putting the values of m and F,

                          4000 = 900 × a        

                                a  [tex]= \frac{4000}{900}[/tex]

                                a  =  44.4  m/s²

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By orthogonality, vectors tj < Vj, Vi> = 0.

Given,

v₁, v₂, and v₃ are mutually orthogonal vectors in r³.

Let v₁, v₂,...vₓ ∈ V form an orthogonal set if and only if

<Vi, Vj> = { 1 if i = j ; and 0 if i ≠ j}

Now, let v₁, v₂, and v₃ are non-zero vectors that form an orthogonal set.

Suppose t₁v₁ + t₂v₂ + t₃v₃ = 0; for some t₁, t₂, t₃∈ R

Then for any index t ≤ i ≤ 3, we have

< t₁v₁ + t₂v₂ + t₃v₃, Vi> = < 0, Vi> which equals to 0.

t₁<v₁,Vi>  + t₂<v₂,Vi> + t₃<v₃, Vi> = 0

By orthogonality, tj < Vj, Vi> = 0

Or, tj = 0

Where, i = j = < 1, 2, 3>

Hence proved.

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The corresponding wavelengths for these jumps are as follows:

[tex]\lambda_{7-2}[/tex] = 397.7 nm

[tex]\lambda_{6-2}[/tex] = 411 nm

[tex]\lambda_{5-2}[/tex] = 434.9 nm

[tex]\lambda_{4-2}[/tex] = 487.1 nm

[tex]\lambda_{3-2}[/tex] = 657.5 nm

The distance that is present between ant two successive crests of a wave, mostly points present between a sound wave or electromagnetic wave. Wavelength is also called as the distance between identical points (adjacent crests) in the adjacent cycles of any waveform signal that is propagated in space or along a wire.

Frequency, which is defined as the quantity of wave cycles per second, and wavelength have an inverse relationship. The wavelength of a signal decreases with increasing frequency.

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The work done on the cylinder against the external pressure is 408.34 J.

The work done on the cylinder against the external pressure is calculated as follows;

W = PΔV

where;

Substitute the given parameters and solve for work done on the cylinder.

W = 13 atm (0.46 L - 0.15 L)

W = 4.03 atm.L

1 atm.L = 101.325 J

4.03 atm.L = ?

= 408.34 J

Thus, the work done on the cylinder against the external pressure is 408.34 J.

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The mass flow rate of water is 0.08757 kg/s

mCp (T2 - T1) = Q =w

m x 1.015 (360-315) = 4000

m = 4000/ 1.015 x 10^3 x (360-315)

m = 0.08757 kg/s

The density of water at 68°F / 20°C has a flow rate in our example of about 998 kg/m3. However, as the density of water varies with temperature, salinity, and pressure, use our water density calculator if you want to be extremely accurate. 30.58 lbs/s of mass flow were shown by the gadget.

By dividing the volume flow rate by the fluid’s mass density, one can determine the mass flow rate. The cross-sectional vector area, A, is multiplied by the flow velocity of the mass elements, v, to determine the volume flow rate.

The mass of a substance that moves per unit of time is known as the mass flow rate in physics and engineering.

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Answer:

The swimmer must swim at 1.12 m/s at 26.565 ° upstream from the opposing bank, according to the parallelogram rule of vectors.

What is parallelogram law of vector addition?

If two vectors act along two consecutive sides of a parallelogram (with magnitude equal to the length of the sides) both heading away from the common vertex, then the resultant is represented by the parallelogram's diagonal passing through the same common vertex.

Explanation:

Let, the current's speed be x = 0.5 m/s, the swimmer's speed be y m/s and the angle between them be a°. The resulting speed at b° angle with x will be r = 1.0 m/s. Assuming b is 90°.

Then, the parallelogram law of vectors states that

Sin b = y Sin a/r

=> y Sin a = r

=> y Sin a = 1

And Cos b = (x + y Cos a)/r

=> y Cos a = -x = -0.5

Therefore, tan a = 1/ (-0.2)

=> tan a = -2

As a result, a = 116.565°

Consequently, y = 1/Sin a

=> y = 1/ Sin116.565°

=> y = 1.118 ≈ 1.12 m/s

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The effect of friction on air: B. is relevant only within the planetary boundary layer.

In Science, there are different types of force that acts on a physical object and these include the following:

Frictional force can be defined as a type of force that resists and slows the relative motion of two physical objects when there surfaces come in contact. This ultimately implies that, a frictional force prevents two surfaces from easily sliding over or slipping across one another.

Based on scientific research and experiments, we can reasonably infer that the effect of friction on air is relevant and important only within the planetary boundary layer.

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Complete Question:

The effect of friction on air:

A. increases wind speed.

B. is relevant only within the planetary boundary layer.

C. causes airflow to cross isobars rather than run parallel to them.

D. increases the Coriolis force. E. increases with height.

It is advisable to purchase a new circuit breaker with a higher capacity, perhaps a 240V, 80-100A circuit breaker, as breaker trips happen regularly.

We know that power is distributed as

P = IV

P stands for power in watts.

I is the same as current in amps.

And V stands for the voltage difference in potential.

The circuit breaker's function is to handle 240V, 60A.

A current of more over 60A will therefore trip the circuit breaker. The circuit breaker trips OFF when there is a significant amount of electricity flowing through it.

Three 5000W heating elements are now present in the furnace, and each of them trips the circuit breaker. Additionally, this element develops gradually; it does not happen all at once. When turned ON, the first component will draw the following amount of electricity from the mains:

We are aware that the initial heating element has a 3000W power rating.

P = IV

[tex]I' = \frac{P}{V} = \frac{3000}{240}[/tex]

I' =  20.833amps

The circuit breaker is still operational in this scenario because of its 60A capacity.

The second heating element eventually turns on.

Furthermore, this will result in a current of

[tex]I'' = \frac{P}{V} = \frac{3000}{240}[/tex]

I" = 20.833amps

the total current drawn at this time is I = I' + I" = 20.833 + 20.833

I = 41.667 amps

Once more, the 60A capacity of the circuit breaker makes it still appropriate.

Eventually, the third component will trip ON once more, drawing current from:

I"' = [tex]\frac{P}{V} = \frac{3000}{240}[/tex]

I"' = 20.833 amps

The current drawn overall is now I = I' + I" + I"'

I = 20.833+20.833+20.833

I = 62.5 Amps

The breaker will trip because the current exceeds the circuit rating.

Advice: Since replacing the furnace might be too expensive, I will suggest that they purchase a new circuit breaker with a higher capacity, possibly a 240V, 80-100A circuit breaker.

The complete question is : You have been sent to a new home. The homeowner reports that sometimes the electric furnace trips the 240-V, 60-A circuit breaker connected to it. Upon examination, you find that the furnace contains three 5000-W heating elements designed to turn on in stages. For example, when the thermostat calls for heat, the first 5000-W element turns on. After some period of time, the second element will turn on, and then, after another time delay, the third element will turn on. What do you think the problem is, and what would be your recommendation for correcting it? Explain your answer.

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A. Acceleration during launch = 4000 m/s²

B. Distance that the froghopper moves while its legs are pushing = 0.002 m

Kinematics is sometimes regarded as a subfield of mathematics and is sometimes referred to as the geometry of motion. But in physics, it serves as the basis for classical mechanics. Without considering the forces that propel an item, kinematics studies how an object moves. It gives a description of the spatial positions of bodies or systems of material particles as well as the velocities and rates of change of those velocities.

t = 0.001 s

u = 4 m/s

PART A :

a = Δv / t

a = [tex]\frac{4m/s}{0.001s}[/tex]

a = 4000 m/s²

Therefore, Acceleration during launch = 4000 m/s²

PART B :

S = ut +  [tex]\frac{1}{2}[/tex]at²

S = 0(0.001s) + [tex]\frac{1}{2}[/tex]  x 4000 m/s² (0.001)²

S = 0.002 m

Therefore, the Distance that the froghopper moves while its legs are pushing = 0.002 m

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a. Nyquist rate = 30 kHz is the Nyquist rate.

compact disc (CD) records audio signals digitally by means of a binary code. Assume an audio signal bandwidth of 15 kHz.

⇒ According to the Nyquist criteria, the sampling frequency must be at least 2 times the bandwidth.

⇒Nyquist rate = 2 x 15 kHz

⇒Nyquist rate = 30 kHz

So that means we need to take at least 30,000 sample/s to meet Nyquist criteria.  

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The calculated greatest speed is v=0.725 vs.

The ratio of a moving object's speed to the fundamental speed of sound is known as the Mach number. Therefore, an object travelling at twice the speed of sound has a Mach number of 2. speed of sound, the rate at which sound waves move through various substances. Modern estimates of the speed of sound, in particular, for dry air at a temperature of 0 °C (32 °F), are 331.29 meters (1,086.9 feet) per second.

The sound speed is vs=331 m/s.

The duration is t=4.9s.

A=5g is the acceleration.

u=0 is the beginning speed.

Let v be the fastest possible speed without a blackout.

The initial equation of motion is given by v=u+at

v=0+5gt

v=5(9.81m/s2)(4.9s)

v=240m/s

v=240m/svs/331m/s

v=0.725 vs.

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The time interval taken by the ball to strike the ground is 1.75 s.

First calculate the vertical velocity by using the kinematics equation of motion for constant acceleration.

Finally use the equation of motion which relates the vertical velocity with time and calculate the time.

The equation of motion for constant acceleration is,  

vf^2 = vi^2 + 2aΔy

vf is final velocity, vi is initial velocity, y  is vertical distance

vi = 7.60  vf = ? a = 9.8m/s^2  y = 29.3m

y = [tex]\sqrt{8.70^2-19.6-30.2[/tex]   , since height is vertical so we took -9.8 accelaration

y= -25.83

so now

The equation of motion which relates velocity with time is

vf = vi + at

t = [tex]\frac{ vf - vi }{ a}[/tex]

t = [tex]\frac{-25.83- (-8.70}{ -9.80}[/tex]

t = 1.748 s

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b = {- 8, 0, 7, 15}

15 elements of set b are greater than 7.

Mathematics Set Theory Symbols

Symbol Symbol Name Meaning

A ∪ B union                Elements that belong to set A or set B

A ∩ B intersection        Elements that belong to both the sets, A

                                              and B

A ⊆ B subset                subset has few or all elements equal to        

                                              the set

A ⊄ B not subset         left set is not a subset of right set

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Initially, an automobile is moving north at a speed of 23 m/s. If the automobile accelerates at [tex]1.1 m/s^{2}[/tex] in the direction of travel, its speed after 5.3 seconds will be 28.83 m/s.

The initial speed of the car u = 23 m/s

Time is taken t = 5.3 s

Acceleration, a = [tex]1.1 m/s^{2}[/tex]

the first movement equation (Vf =Vi + at) offers with time, acceleration, very last pace, and starting pace. the first equation of motion can be used to calculate time, acceleration, beginning pace, and final pace.

Applying 1st equation of motion,

v = u + at

v = 23 + 1.1 × 5.3       (Since both beginning speed and acceleration are in the same direction)

⟹  v = 28.83 m/s      (due North)

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On a cosmic calendar which compresses the history of the universe into one year, our milky way galaxy probably formed on March 1st.

A cosmic calendar can be defined as a scale on which the history of the universe is compressed into one (1) year. This ultimately implies that, a  cosmic calendar is used by astronomers and scientists alike to compress the history of the universe is compressed into one (1) year.

Based on the information on a cosmic calendar which compresses the history of the universe into one (1) year, we can reasonably infer and logically deduce that our milky way galaxy was probably formed on March 1st.

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Answer:

-2

Explanation:

Answer:

Explanation

hey b