Answer:
The velocity increases, the acceleration decreases, and the net force decreases.
Explanation:
Velocity is at maximum when acceleration is zero thus as the pendulum moves closer to equilibrium position, velocity increases and acceleration decreases. As the pendulum moves closer to equilibrium, the magnitude of force decreases until it reaches the equilibrium position when the magnitude of force is zero. This means the net force decreases in the same manner the acceleration decreases because from the formula of force which is the product of mass and acceleration.
Answer:
B
Explanation:
on edge
Identify the state of matter.
A)The molecules are a great distance apart, moving
very rapidly, with negligible interaction. The
substance occupies all the space available.
B)The molecules are only able to vibrate rapidly about
fixed positions. The substance does not need a
container to maintain its shape.
C)The molecules move about amongst each other,
with attractive forces between them. The substance
does not necessarily fill its container
Answer:
Gases
Solids
Liquids
Explanation:
A)The molecules are a great distance apart, moving very rapidly, with negligible interaction. The substance occupies all the space available.
Gases
The state of matter described above is for gases. The distances between gases are far apart and they have very weak intermolecular attraction. They have no fixed volume as they occupy any volume of space they are introduced into.
B)The molecules are only able to vibrate rapidly about fixed positions. The substance does not need a container to maintain its shape.
Solids
Solids have fixed shape and volume. They are held together in their fixed lattice and are only able to rapidly vibrate about their fixed positions.
C)The molecules move about amongst each other, with attractive forces between them. The substance does not necessarily fill its container.
Liquids
The state of matter described here are the liquids. Liquids flow amongst each other. The attractive force between them is greater than that of gases but lesser than those of solids.
Hi!! Does anyone know this answer? :D
Answer:
Im not fully corrrect but I would say C
Explanation:
what volume of alcohol will have the same mass as 4.2m^3 of petrol? (density of alcohol 0.4kg/m^3 and petrol is 0.3kg/m^3)
Answer:
3.15m³
Explanation:
To solve this problem, let us first find the mass of the petrol from the given dimension.
Mass = density x volume
Volume of petrol = 4.2m³
Density of petrol = 0.3kgm⁻³
Mass of petrol = 4.2 x 0.3 = 1.26kg
So;
We can now find the volume of the alcohol
Volume of alcohol = [tex]\frac{mass}{density}[/tex]
Mass of alcohol = 1.26kg
Density of alcohol = 0.4kgm⁻³
Volume of alcohol = [tex]\frac{1.26}{0.4}[/tex] = 3.15m³
2. Arrange the following types of electromagnetic waves in order by wavelength, from longest to
shortest: Gamma rays, visible light, infrared radiation, ultraviolet radiation, microwaves, radio
waves, X-rays
Answer:
Radiowaves > microwaves> Infrared radiation > visible light > Ultraviolet radiation > x -rays > gamma rays
Explanation:
To solve this problem, we use the electromagnetic spectrum as a reference. On the electromagnetic spectrum, the lesser the wavelength, the higher the frequency and more energetic a wave is.
Therefore;
Radiowaves > microwaves> Infrared radiation > visible light > Ultraviolet radiation > x -rays > gamma rays
So, radiowaves have the longest wavelength and gamma rays have the shortest.
Answer:
Radio, microwave, infrared radiation, visible light, ultraviolet radiation, x-rays and gamma rays.
Explanation:
These electromagnetic waves are arranged from longest to shortest wavelengths.
Have an amazing day!
Please help me this is worth allot
Please help I’ll give you brain
Answer:
Explanation:
distance (km)
a) As near as I can tell from the graph, the distance travelled was 4km
b) I would answer 40 minutes, but don't be surprised if your instructor says 30 minutes.
c) The average speed is 4 km/40 minutes = 0.1 km/minute
ANSWER QUICK 30 POINTS
What force controls the movement of the planets around the sun, holds together stars grouped in galaxies, and galaxies grouped in clusters? Thoroughly explain your answer, making sure to include an example and describe how this force keeps planets in orbit. Make sure to write at least 3-5 sentences and proper conventions (spelling, grammar, punctuation, etc.) to respond. Put all answers in your own words
Answer:
Gravity controls the movement of the planets around the sun, holds together stars grouped in galaxies, and galaxies grouped in clusters. The Universal Law of Gravitation depends on two things. First it depends on mass of each object and the second factor is the distance between two objects. If the mass of one object is Larger, the gravitational pull towards it will be larger and the smaller distance, the larger the gravitational pull will be between the objects. Therefore the Larger planets have more moon and the inner planets have less.
Explanation:
a train has an initial velocity of 44m/s and an accelaration of _4m/s calculate its velocity
Answer:
It's 4m/s
Explanation:
V = u _ at, at u = 44m/s
44 + [-4]10
4m/s
An object is subject to a 84 Nm torque about a point when a
21 N of force is applied to a second point along the object's
length. How far apart are the two points
Answer:
d = 4[m]
Explanation:
Torque in physics is defined as the product of force by distance. This way you can use the following equation to calculate the torque.
[tex]T=F*d[/tex]
where:
T = torque [N*m]
F = force [N]
d = distance [m]
Now replacing in the equation above.
[tex]84=21*d\\\\d= 4[m][/tex]
On Earth, a spring stretches by 5.0 cm when a mass of 3.0 kg is suspended from one end.
The gravitational field strength on the Moon is
1/6 of that on Earth.
Which mass, on the Moon, would stretch the spring by the same extension?
Reasons too :(
igcse physics
Answer:
Mass = 18.0 kg
Explanation:
From Hooke's law,
F = ke
where: F is the force, k is the spring constant and e is the extension.
But, F = mg
So that,
mg = ke
On the Earth, let the gravitational force be 10 m/[tex]s^{2}[/tex].
3.0 x 10 = k x 5.0
30 = 5k
⇒ k = [tex]\frac{30}{5}[/tex] ................ 1
On the Moon, the gravitational force is [tex]\frac{1}{6}[/tex] of that on the Earth.
m x [tex]\frac{10}{6}[/tex] = k x 5.0
[tex]\frac{10m}{6}[/tex] = 5k
⇒ k = [tex]\frac{10m}{30}[/tex] ............. 2
Equating 1 and 2, we have;
[tex]\frac{30}{5}[/tex] = [tex]\frac{10m}{30}[/tex]
m = [tex]\frac{900}{50}[/tex]
= 18.0
m = 18.0 kg
The mass required to produce the same extension on the Moon is 18 kg.
Answer:
18 kg
Explanation:
weight (N) = mass (kg) × gravitational acceleration (m/s²)force (N) = k (spring constant) × extension (m)On Earth, acceleration of gravity is 10 m/s²
weight = 3.0 (kg) × 10 (m/s²)weight = 30 (N)Since weight is a force, the force is 30 N. The value of spring constant is unknown
30 (N) = k × 5 (m)k = 6 (m/N)Spring constant is 6. Now let's find the mass on the Moon
mass (kg) × gravitational acceleration (m/s²) = k (spring constant) × extension (m)Gravitational acceleration of the moon is 1/6 of that on Earth. Earth's g = 10, so Moon's g = 10/6
m × 10/6 = 6 × 5m = 30/(10/6)m = 18The mass is 18 kg
what is projectile. what is projectile motion
The projectile is any object thrown into space upon which the only acting force is gravity. In other words, the primary force acting on a projectile is gravity. This doesn’t necessarily mean that the other forces do not act on it, just that their effect is minimal compared to gravity. The path followed by a projectile is known as a trajectory. A baseball batted or thrown and the instant the bullet exits the barrel of a gun are all examples of the projectile.
Projectile Motion:When a particle is thrown obliquely near the earth’s surface, it moves along a curved path under constant acceleration that is directed towards the center of the earth (we assume that the particle remains close to the surface of the earth). The path of such a particle is called a projectile and the motion is called projectile motion. Air resistance to the motion of the body is to be assumed absent in projectile motion.
In a Projectile Motion, there are two simultaneous independent rectilinear motions:
Along the x-axis: uniform velocity, responsible for the horizontal (forward) motion of the particle.
Along y-axis: uniform acceleration, responsible for the vertical (downwards) motion of the particle.
Accelerations in the horizontal projectile motion and vertical projectile motion of a particle: When a particle is projected in the air with some speed, the only force acting on it during its time in the air is the acceleration due to gravity (g). This acceleration acts vertically downward. There is no acceleration in the horizontal direction, which means that the velocity of the particle in the horizontal direction remains constant.
[tex]\sf~~~~~~~~~~~~~~~{\red{\underbrace{\underline{\green{projectile~motion}}}}}[/tex]
Projectile motion is a form of motion in which object or particle is thrown near earth's surface and it moves along a curved path under the action of gravity only.
A sample of gas in a syringe releases heat to its surroundings while the
plunger is pulled out. What are the correct signs of heat and work for this
change?
A. +Q+W
B. --W
O C. +Q, -W
D. -Q. +W
Answer: b
Explanation:
When heat is released by the system i.e. system loses heat. So, we take it as negative -Q
When the work is done on the system then it is considered as negative work on the system i.e. -W
In this case, the plunger is pulled out, and work is done on the system. So, we take work as negative work -W
Correct option is b
The answer is D.
-Q +W
explain how balanced and unbalanced forces effect an objects motion differently
Answer:
Balanced Forces will not change the object's motion.
Unbalanced Forces will change the object's motion.
Explanation:
Will mark brainliest Why are acoustic panels are used in concert halls
Answer:
what person above said is correct
Explanation:
The walls of the concert halls are used to control the acoustic. ... Rough surfaces can also be used to disperse sound in all directions – this might be used in concert halls to get rid of echoes that would distract from performances.
An acoustic panel is a sound-absorbing panel used to mitigate noise and reduce the reverberation and echo in a space. For both types, we can talk about different principles of good acoustics: absorption, diffusion, and attenuation. These are all linked to the acoustic performance of the panels.
brainliest?which unit would be most
suitable for its scale?
Answer:
down below
Explanation:
for a scale, kg is used, as well as grams
for force, newtons is used
Brian Berg of lowa built a house of cards 4.88 m tall. Suppose Berg throws a ball from ground level
with a velocity of 9.98 m/s straight up. What is the velocity of the ball as it first passes the top of
the card house?
Answer:
Vf = final velocity = 1.96 [m/s]
Explanation:
To solve this problem we must use the following equation of kinematics.
[tex]v_{f}^{2}=v_{o}^{2}-2*g*x[/tex]
where:
Vf = final velocity [m/s]
Vo = initial velocity = 9.98 [m/s]
g = gravity acceleration = 9.81 [m/s²]
x = vertical distance [m]
[tex]v_{f}^{2}=(9.98)^{2}-2*9.81*4.88\\v_{f}^{2} = 99.6-95.74\\v_{f}=\sqrt{3.8544}\\v_{f}=1.96[m/s][/tex]
Note: The negative sign of the gravity acceleration means that the gravity acceleration is pointing in the opposite direction of the movement.
Two spheres have a gravitational force between
them of 45 N. If the distance between the masses
is increased to 4.0 times its original distance, what
is the new force?
Answer:
The new force is 2.8125 N
Explanation:
Newton’s Law of Universal Gravitation
Objects attract each other with a force that is proportional to their masses and inversely proportional to the square of the distance.
[tex]\displaystyle F=G{\frac {m_{1}m_{2}}{r^{2}}}[/tex]
Where:
m1 = mass of object 1
m2 = mass of object 2
r = distance between the objects' center of masses
G = gravitational constant: 6.67\cdot 10^{-11}~Nw*m^2/Kg^2
Suppose two spheres have a gravitational force between them of F = 45 N. Now increase the distance to r'=4r. The new force F' is:
[tex]\displaystyle F'=G{\frac {m_{1}m_{2}}{(4r)^{2}}}[/tex]
[tex]\displaystyle F'=G{\frac {m_{1}m_{2}}{16r^{2}}}[/tex]
[tex]\displaystyle F'=\frac{1}{16}\ G{\frac {m_{1}m_{2}}{r^{2}}}[/tex]
Substituting the original value of the force:
[tex]\displaystyle F'=\frac{1}{16}\ 45 N[/tex]
F' = 2.8125 N
The new force is 2.8125 N
A pickle sits 8.0 cm from the center of a circular, rotating platter. The platter rotates such
that the pickle's tangential speed is 4.8 cm/s. What is the pickle's centripetal
acceleration?
(A) 0.36 cm/s
(B) 0.60 cm/s2
(C) 1.2 cm/s2
(D) 2.9 cm/s2
(E) 5.8 cm/s2
can be answered using momentum.
momentum = p
p1= mass1 * velocity1
p1 = p2
therefore
p1 = 6kg * 4m/s
p1 = 24kgm/s
p2=m2 * v2
24 kgm/s = 7kg * v2
v2 = 24 kgm/s / 7kg
v2= 3.42 m/s
If the boy travelled 2 meters to the right and 4 meters to the left what is the total distance that he travelled?
4 m
-4 m
6 m
2 m
Answer:
6m
Explanation:
2+4=6
Question 17 of 25
A sound wave from a brass bell passes through the air with a
wavelength of 3.5 m. When the sound wave originated in the
brass bell, its wavelength was 47 m. If the sound wave has a
constant frequency of 100 Hz, what was its speed as it
traveled through the brass bell? (The equation for wave speed
is v= f*1.)
A. 3,500 m/s
B. 4,700 m/s
C. 350 m/s
D. 470 m/s
Answer:
The speed of the wave as it travelled through the brass bell is;
B. 4,700 m/s
Explanation:
The given parameters are;
The wavelength of the sound wave produced from the brass bell, [tex]\lambda _{(air)}[/tex] = 3.5 m
The wavelength of the wave in the brass bell, [tex]\lambda _{(brass \ bell)}[/tex] = 47 m
The frequency of the wave in the brass bell, f = 100 Hz
The given equation for wave speed, v = f × λ
Therefore, the speed of the wave as it travelled through the brass bell, [tex]v _{(brass \ bell)}[/tex], is given as follows;
[tex]v _{(brass \ bell)}[/tex] = f × [tex]\lambda _{(brass \ bell)}[/tex] = 100 Hz × 47 m = 4,700 m/s
The speed of the wave as it travelled through the brass bell = [tex]v _{(brass \ bell)}[/tex] = 4,700 m/s
Answer:
B.) 4700 m/s
Explanation:
1. A kangaroo hops 84 m to the east in 7 seconds.
o What is the kangaroo's speed? 12 m/s
o What is the kangaroo's velocity?
Explanation:
Given parameters:
Distance hopped = 84m
Displacement = 84m due east
Time = 7s
Unknown:
Speed of kangaroo = ?
Velocity of kangaroo = ?
Solution:
To solve this problem,
Speed = [tex]\frac{distance}{time }[/tex] = [tex]\frac{84}{7}[/tex] = 12m/s
Velocity = [tex]\frac{displacement}{time}[/tex] = [tex]\frac{84}{7}[/tex] = 12m/s due east
What is the volume of a liquid in a 50 mL cup?
A. 50mL
B. 10mL
C. There is not enough information to answer this question.
Answer:
there is not enough information
I need help please I will give points
Answer:
-5 N of force
Explanation:
Hope it helps!
Nina's measurements, shown in the table here, BEST represent a wave with
A)
decreasing frequency.
B)
increasing frequency.
C)
increasing amplitude.
D)
decreasing amplitude.
Nina's data in this table most accurately depict a wave with decreasing frequency. Option A is right.
What is frequency?A recurring event's frequency is measured by how many times it occurs in a unit of time.
To emphasize distinctions with spatial and angular frequencies, respectively, it is also sometimes referred to as ordinary frequency or temporal frequency.
If the duration, or time interval, required to complete one cycle or vibration is half a second, the frequency is 2 per second; if it is one hundredth of an hour, the frequency is 100 per hour.
The frequency and period, or time interval, are often reciprocally equal, therefore frequency = 1/period = 1 in most circumstances.
The Moon rotates about Earth about a little bit more than 12 times a year. In a violin A string vibrates at a frequency of 440 cycles per second.
Thus, the correct option is A.
For more details regarding frequency, visit:
https://brainly.com/question/5102661
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How much force is needed to accelerate 250 kg at a rate of 6 m/s/s?
Answer:
[tex]1500 \: \mathrm{N}[/tex]
Explanation:
The equation [tex]F=ma[/tex] represents the force needed.
Plugging in [tex]m=250[/tex] and [tex]a=6\: \mathrm{m/s^2}[/tex], we find that the force needed to accelerate a 250 kg object at a rate of [tex]6 \: \mathrm{m/s^2}[/tex] to be [tex]\fbox{$1500 \: \mathrm{N}$}[/tex].
.A water tank has dimensions
of 6m x 4m x 4m. Find the pressure exerted by
water at the base of dam when it is half
filled. ( Density of water - 1000 kg/ m2,
acceleration
due to to gravity is 9.8m/s2
Answer:
9800Nm⁻²
Explanation:
Given parameters:
Dimensions of the water tank = 6m x 4m x 4m
Density of water = 1000kgm⁻³
Gravity = 9.8m/s²
Unknown:
Pressure exerted by the water at the base of the dam = ?
Solution:
The pressure exerted by the water is given as:
Pressure = density of water x acceleration due to gravity x height of water
The height of the water here is half = 1m
Pressure = 1000 x 9.8 x 1 = 9800Nm⁻²
At the height of 800 meters, a skydiver falls from an airplane flying horizontally at 40 m/sec. What is the horizontal distance of the skydivers travel before they "hit" the ground?
Answer:
The horizontal distance traveled by the skydiver is 510.8 m.
Explanation:
Given;
height of fall, h = 800 m
initial velocity of the airplane, u = 40 m/s
The time to fall to the ground is calculated as;
[tex]t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2 \times 800}{9.81} }\\\\t = 12.77 \ s[/tex]
The horizontal distance or range of the motion is calculated as;
R = ut
R = 40 m/s x 12.77 s
R = 510.8 m
Therefore, the horizontal distance traveled by the skydiver is 510.8 m.
please answerrr asapp tyty Laura goes for cycle from her house to the post office 4km away how long did it take for Laura to reach the post office
Answer:
See the answer below
Explanation:
The time Laura took to reach the post office would depend on the speed of cycling.
We know that;
speed = [tex]\frac{distance}{time}[/tex]
hence,
time = [tex]\frac{distance}{speed}[/tex]
Since the distance from Laura's house to the post office is 4 km, the equation becomes;
time = [tex]\frac{4}{speed}[/tex]
Just ensure that the speed is in km per hour, minute, or seconds in order to obtain the time in hours, minutes, or seconds respectively.
How much work is done if a force of 20 N is used to move an object 6 meters
Explanation:
W=f×d
=20×6
w=120 joule
Which two life functions of animals help maintain the water cycle by recycling water back into the environment?
Answer:
Respiration and excretion
Explanation:
Respiration. When animals breathe, their lungs release water vapour to the atmosphere.
Animals excrete water by respiration and by passing urine.