arrange the following elements in order of increasing electronegativity: aluminum, sulfur, phosphorus, silicon

In 1 minute, a galvanic cell with a current of 0.30 A would pass a charge of 18,300 C (coulombs) through the cell.

To calculate the charge passed through the cell, we use the formula:

Charge (C) = Current (A) * Time (s)

Since the current is given as 0.30 A and the time is 1 minute, we need to convert the time to seconds. There are 60 seconds in a minute, so 1 minute is equal to 60 seconds.

Now we can substitute the values into the formula:

Charge (C) = 0.30 A * 60 s = 18 C

However, the given formula constant (f) is in units of C/mol. To convert from C to mol, we need to divide the charge by the Faraday constant (f), which is 96,500 C/mol.

Charge (mol) = \frac{Charge (C) }{f }= \frac{18 C }{ 96,500 C/mol }≈ 0.00019 mol

Therefore, the charge passed through the cell in 1 minute is approximately 18,300 C.

learn more about galvanic cell Refer: https://brainly.com/question/32132953

#SPJ11

The correct answer is d. 1,3-cyclohexadiene undergoes dehydrogenation readily because it would gain considerable stability by becoming benzene. Benzene is a highly stable and aromatic compound that possesses resonance energy due to its delocalized pi-electrons.

Dehydrogenation is a chemical reaction that involves the removal of hydrogen from a molecule. In the case of 1,3-cyclohexadiene, the removal of two hydrogen atoms would result in the formation of benzene. This transformation would result in the formation of a highly stable compound, which has much lower energy than its precursor.
Moreover, 1,3-cyclohexadiene is an unsaturated compound that possesses a double bond between two carbon atoms. This double bond makes the molecule reactive towards dehydrogenation. During dehydrogenation, the double bond is broken, and the two hydrogen atoms that were attached to the carbon atoms are removed. As a result, the molecule undergoes a structural change, and a highly stable compound, benzene, is formed.
In conclusion, 1,3-cyclohexadiene undergoes dehydrogenation readily because it would gain considerable stability by becoming benzene. This transformation is a result of the removal of two hydrogen atoms from the molecule, and it occurs due to the reactivity of the double bond that the molecule possesses.

To know more about dehydrogenation visit:

https://brainly.com/question/23186275

#SPJ11

An element is a pure substance that cannot be broken down into simpler substances by chemical means. It is made up of atoms that have the same number of protons in their nuclei.

Examples of elements include oxygen, carbon, and hydrogen. A compound, on the other hand, is a pure substance made up of two or more elements that are chemically combined in a fixed ratio. Examples of compounds include water (H2O) and carbon dioxide (CO2).
Ionic bonds are formed when two atoms have a large difference in electronegativity, resulting in the transfer of electrons from one atom to another. This results in the formation of positively and negatively charged ions, which are held together by electrostatic attraction. Covalent bonds, on the other hand, are formed when two atoms share one or more pairs of electrons. This sharing of electrons results in the formation of a molecule.

In summary, the key difference between an element and a compound is that an element is a pure substance made up of only one type of atom, while a compound is a pure substance made up of two or more elements that are chemically combined. The difference between ionic and covalent bonds is the way in which electrons are shared or transferred between atoms. Ionic bonds involve the transfer of electrons, while covalent bonds involve the sharing of electrons.

To know more about nuclei visit:

https://brainly.com/question/32368659

#SPJ11

The molarity of the resulting solution, prepared by mixing 300 mL of a 0.250 M H2SO4 solution with 700 mL of a 6.00 M H2SO4 solution, is approximately 2.14 M (option b).

To find the molarity of the resulting solution, we can use the equation: M1V1 = M2V2, where M1 and V1 represent the molarity and volume of the initial solution, and M2 and V2 represent the molarity and volume of the final solution. Given:

M1 = 0.250 M (for the 300 mL solution)

V1 = 300 mL

M2 = 6.00 M (for the 700 mL solution)

V2 = 700 mL

To calculate the molarity of the resulting solution, we substitute the given values into the equation:

M1V1 = M2V2

(0.250 M)(300 mL) = (M2)(700 mL)

Solving for M2:

M2 =\frac{ (0.250 M)(300 mL)}{ (700 mL)}

≈ 0.1071 M

Therefore, the molarity of the resulting solution is approximately 2.14 M (option b).

learn more about  molarity Refer: https://brainly.com/question/31545539

#SPJ11

complete question: What is the molarity of a solution prepared by mixing 300. mL of a 0.250 M solution of H2SO4 with 700 mL of a 6.00 M H2SO4 solution?

a. 4.20 M

b. 2.14 M

c. 4.28 M

d. 6.24 M

In an 8.2 dm³ cylinder at 320 K, a pressure of 10 atm would be exerted by approximately 3.16 moles of oxygen.

To determine the number of moles of oxygen that would exert a pressure of 10 atm at 320 K in an 8.2 dm³ cylinder, we can use the ideal gas law equation:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant (0.0821 L·atm/mol·K), and T is the temperature in Kelvin.

First, let's convert the volume from dm³ to liters:

8.2 dm³ = 8.2 L

Now we can rearrange the ideal gas law equation to solve for the number of moles (n):

n = PV / RT

n = (10 atm) * (8.2 L) / (0.0821 L·atm/mol·K * 320 K)

Simplifying the expression, we find:

n ≈ 3.16 moles

Therefore, approximately 3.16 moles of oxygen would exert a pressure of 10 atm at 320 K in an 8.2 dm³ cylinder.

You can learn more about moles at

https://brainly.com/question/15356425

#SPJ11

The arrangement of the boiling points of the aqueous solutions, relative to pure water, from highest to lowest is as follows:

0.20 m CaI2 > 0.13 m NaCl > 0.36 m CH3OH > h2o > 0.31 m NH3.

The boiling point elevation of a solution is directly proportional to its molality (moles of solute per kilogram of solvent). Higher molality corresponds to a higher boiling point. In this case, we compare the molality of different solutes to determine the order of boiling points.

0.20 m CaI2:

Since CaI2 is an ionic compound, it dissociates completely into three ions in water (Ca2+ and two I-). This results in a greater number of solute particles per kilogram of solvent, leading to a higher boiling point compared to the other compounds.

0.13 m NaCl:

Similar to CaI2, NaCl also dissociates completely into two ions (Na+ and Cl-) in water. Although the molality is lower than CaI2, it still contributes to a higher boiling point compared to the remaining compounds.

0.36 m CH3OH:

CH3OH (methanol) is a molecular compound that does not dissociate into ions in water. The molality is higher than the remaining compounds, but since it does not produce additional solute particles, its boiling point elevation is lower compared to ionic compounds.

h2o (Pure Water):

Pure water acts as a reference point with no solute present. Therefore, it has the lowest boiling point among the given solutions.

0.31 m NH3:

NH3 (ammonia) is a weak base and does not completely dissociate into ions in water. Although its molality is higher than pure water, it is lower compared to the other compounds, resulting in the lowest boiling point among them.

The arrangement of the boiling points, from highest to lowest, is 0.20 m CaI2 > 0.13 m NaCl > 0.36 m CH3OH > h2o > 0.31 m NH3. This ranking is based on the concept that complete dissociation of ionic compounds results in a greater number of solute particles, leading to a higher boiling point, while molecular compounds and weak bases have lower boiling point elevations.

To know more about aqueous solutions ,visit:

https://brainly.com/question/19587902

#SPJ11

The difference in pH among strong acids, weak acids, and weak bases can be attributed to their varying degree of ionization or dissociation in water, which influences the concentration of hydrogen ions (H+) or hydroxide ions (OH-) present in the solution.

The difference in pH between strong acids, weak acids, and weak bases can be explained by their varying degree of ionization or dissociation in water. Strong acids fully dissociate in water to produce hydrogen ions (H+) and their corresponding conjugate base ions. This high concentration of hydrogen ions results in a low pH, indicating acidity.

For example, hydrochloric acid (HCl) is a strong acid that dissociates completely in water according to the equation:

HCl(aq) → H+(aq) + Cl-(aq)

On the other hand, weak acids partially dissociate in water, resulting in a lower concentration of hydrogen ions. This leads to a higher pH compared to strong acids. Acetic acid (CH3COOH) is an example of a weak acid that undergoes partial dissociation:

CH3COOH(aq) ⇌ H+(aq) + CH3COO-(aq)

Weak bases, on the other hand, accept hydrogen ions (H+) from water, resulting in the production of hydroxide ions (OH-) and their corresponding conjugate acid species. This leads to an increase in hydroxide ion concentration and a higher pH, indicating basicity.

For example, ammonia (NH3) is a weak base that reacts with water to form ammonium ions (NH4+) and hydroxide ions (OH-):

NH3(aq) + H2O(l) ⇌ NH4+(aq) + OH-(aq)

Know more about difference in pH here:

https://brainly.com/question/14843959

#SPJ11

The osmotic pressure inside the bacterial cell is approximately 11.73 atm.

a. To calculate the osmotic pressure inside the bacterial cell, we can use the equation:

Π = i * M * R * T

where Π is the osmotic pressure, i is the van't Hoff factor, M is the molar concentration of the solute, R is the ideal gas constant, and T is the temperature in Kelvin.

In this case, the concentration of sodium chloride is given as 15% (m/v), which means 15 grams of NaCl dissolved in 100 mL of solution. We need to convert this to molar concentration.

First, calculate the molar mass of NaCl:

Na: 22.99 g/mol

Cl: 35.45 g/mol

Molar mass of NaCl = 22.99 g/mol + 35.45 g/mol = 58.44 g/mol

Next, calculate the molar concentration:

15 g / 58.44 g/mol = 0.257 mol/L

Convert temperature to Kelvin:

30°C + 273.15 = 303.15 K

Now we can calculate the osmotic pressure:

Π = 1.9 * 0.257 mol/L * 0.0821 Latm/(molK) * 303.15 K = 11.73 atm

b. If an Escherichia coli cell, a non-halotolerant species of bacterium, is placed in a 15% NaCl solution, it will experience a hypertonic environment. This means that the concentration of solutes outside the cell is higher than inside the cell. Water will tend to move out of the cell, following the concentration gradient, in an attempt to equalize the solute concentrations.

As a result, the E. coli cell will undergo plasmolysis, which is the shrinking of the cell membrane away from the cell wall due to water loss. The high concentration of salt in the external environment causes water to leave the cell, leading to cellular dehydration and impairment of vital cellular functions. Ultimately, this can lead to cell death or significant damage to the cell's structure and function.

Know more about osmotic pressure here:

https://brainly.com/question/29819107

#SPJ11

After adding 2.00 g of N₂ gas and cooling the flask to -55°C, the final pressure in the flask is approximately 1.91 atm.

To determine the final pressure in the flask after adding 2.00 g of N₂ gas and cooling the flask to -55°C, we can use the ideal gas law:

PV = nRT,

where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.

Given:

Initial pressure (P₁) = 1.00 atm

Initial temperature (T₁) = 25°C = 25 + 273.15 = 298.15 K

Final temperature (T₂) = -55°C = -55 + 273.15 = 218.15 K

Additional N₂ gas added (m) = 2.00 g

Molar mass of N₂ (M) = 28.0134 g/mol

Volume (V) = 1.00 L

First, we calculate the number of moles of the initial gas using the ideal gas law:

n₁ = (P₁V) / (RT₁).

Next, we calculate the number of moles of the additional N₂ gas:

n₂ = m / M.

Then, we calculate the total number of moles in the flask after adding the N₂ gas = n₁ + n₂ = n

Using the ideal gas law, we can calculate the final pressure:

P₂ = (nRT₂) / V.

So,

n₁= [(1.00 atm * 1.00 L) / (0.0821 L·atm/(mol·K)(298.15 K)] ≈ 0.0404 mol

n₂ = 2.00 g / 28.0134 g/mol ≈ 0.0714 mol

n = 0.0404 mol + 0.0714 mol = 0.1118 mol

Hence,

P₂ = (0.1118 mol * 0.0821 L·atm/(mol·K) * 218.15 K) / 1.00 L ≈ 1.91 atm.

Learn more about the ideal gas equation here:

https://brainly.com/question/11544185

#SPJ4

Fοr a chemical reactiοn tο be spοntaneοus οnly at high temperatures, the cοnditiοn that must be met is:

C. ΔS° < 0, ΔH° < 0

Chemical reactiοns οccur when οne οr mοre cοmpοunds, knοwn as reactants, are transfοrmed intο οne οr mοre new substances, knοwn as prοducts. Bοth chemical cοmpοnents and elements are substances. A chemical reactiοn rearranges the atοms that make up the reactants tο create diverse mοlecules as prοducts.

In οrder fοr a reactiοn tο be spοntaneοus, the Gibbs free energy change (ΔG°) must be negative. The Gibbs free energy change is related tο the enthalpy change (ΔH°) and the entrοpy change (ΔS°) thrοugh the equatiοn:

ΔG° = ΔH° - TΔS°

Where T is the temperature. At high temperatures, the term -TΔS° dοminates the equatiοn, and fοr ΔG° tο be negative, ΔS° must be negative (ΔS° < 0) and ΔH° must be negative (ΔH° < 0).

Therefοre, the cοrrect answer is C. ΔS° < 0, ΔH° < 0.

Learn more about chemical reaction

https://brainly.com/question/22817140

#SPJ4

Electrolytes dissociate in solution, meaning that they break down into charged particles called ions. This allows them to conduct electricity in solution because the charged ions can move freely and carry electrical current.

Examples of electrolytes include NaOH and KBr. On the other hand, non-electrolytes do not dissociate in solution, meaning they do not break down into ions and cannot conduct electricity. Examples of non-electrolytes include C6H12O6 (glucose) and CCl4 (carbon tetrachloride).

In summary, electrolytes answer "conduct electricity in solution" and "dissociate in solution" while non-electrolytes answer "do not conduct electricity in solution" and "do not dissociate in solution".

To know more about ions visit:

https://brainly.com/question/30663970

#SPJ11

The answer is B) Decrease. The equilibrium constant (Keq) for the reaction will decrease when the temperature is increased by 20 K while the volume is kept constant.

When the temperature of a chemical reaction at equilibrium is increased, the equilibrium constant (Keq) can change. In this case, the reaction is exothermic (∆H°rxn < 0), which means it releases heat.

According to Le Chatelier's principle, when the temperature is increased, the equilibrium will shift in the direction that absorbs heat. Since the reaction is exothermic, it will favor the reactant side in order to consume the excess heat.

In this reaction, the forward reaction (2NO2 ⇔ N2O4) is the exothermic direction. Therefore, when the temperature is increased, the equilibrium will shift to the left, favoring the formation of more reactants (NO2).

As a result, the concentration of NO2 will increase, while the concentration of N2O4 will decrease. This change in concentrations will lead to a decrease in the value of Keq.

Know more about equilibrium constant here:

https://brainly.com/question/28559466

#SPJ11

When a base is mixed with an acid, a neutralization reaction occurs.

This type of reaction involves the combination of H+ ions from the acid with OH- ions from the base to form water (H2O) and a salt. The salt produced depends on the specific acid and base used. For example, when hydrochloric acid (HCl) is mixed with sodium hydroxide (NaOH), the resulting salt is sodium chloride (NaCl). The reaction is not spontaneous and requires an input of energy to occur. Typically, the heat produced during the reaction is used to drive the reaction forward. When a base is mixed with an acid, the type of reaction that occurs is called a neutralization reaction. In this process, the acidic and basic properties of the reactants are neutralized, producing water and a salt as the products. This reaction is important in various chemical processes and everyday situations, such as in the regulation of pH levels and the formation of salts. Neutralization reactions are essential for maintaining a balance in different environments and have various practical applications.

To know more about neutralization visit:

https://brainly.com/question/14156911

#SPJ11

To identify an aromatic aldehyde, you can follow the following identification scheme Test for Carbonyl Group and Chromic Acid Test

Test for Carbonyl Group: Perform a test to confirm the presence of a carbonyl group, which is a characteristic functional group of aldehydes. This can be done using Tollens' test or Fehling's test, which give positive results for aldehydes.

Test for Carbonyl Group: Aromatic aldehydes often have distinct odors. Conduct a smell test to check for the presence of a strong, sweet, or floral odor, which is typical of many aromatic aldehydes.

Chromic Acid Test: Perform the chromic acid test by adding a small amount of chromic acid reagent to the sample. A positive result indicated by a color change indicates the presence of an aldehyde, including aromatic aldehydes.

NMR Spectroscopy: Utilize Nuclear Magnetic Resonance (NMR) spectroscopy to analyze the compound's structure and identify the presence of an aldehyde group. The aldehyde proton signal typically appears in the region of 9-10 ppm.

Other Tests: Additional tests can be performed to confirm the presence of an aromatic aldehyde. These include Schiff's test, which gives a positive result for aldehydes, and silver mirror test, which forms a silver mirror on the inner surface of the test tube for aldehydes.

Challenges in making a unique, positive identification of an aromatic aldehyde and differentiating it from other molecules include:

Similar Functional Groups: Some other functional groups, such as ketones, may also give positive results in certain tests, making it necessary to perform additional tests to confirm the presence of an aldehyde.

Isomeric Structures: Aromatic aldehydes can have isomeric structures, making it important to analyze the compound's structure accurately using techniques like NMR spectroscopy to distinguish between different isomers.

Impurities or Mixtures: Presence of impurities or mixtures can complicate the identification process, as they may interfere with the test results or provide additional signals in spectroscopic analysis.

To overcome these challenges, it is important to perform a combination of tests and use multiple analytical techniques to make a reliable and conclusive identification of an aromatic aldehyde.

Know more about aromatic aldehyde here:

https://brainly.com/question/32104005

#SPJ11

if pH of a drink is 4, then the OH- concentration of the drink with a pH of 4 is 1.0 x [tex]10^-^1^0[/tex] mol/L, as the concentration of  H₃O+ and OH- are inversely related.

if the pH of a drink is 4, one can determine the H₃O+ concentration using the equation pH = -log[ H₃O+]. Plugging in the pH value:

4 = -log[H₃O+]

Taking the antilog ([tex]10^x[/tex]) of both sides:

[tex]10^4[/tex] = [H₃O+]

[H₃O+] = [tex]10^-^4[/tex] mol/L

Since the concentration of  H₃O+ and OH- are inversely related, one can use the Kw expression to find the OH- concentration:

[ H₃O+][OH-] = Kw

([tex]10^-^4[/tex] mol/L)(OH-) = 1.0 x [tex]10^-^1^4[/tex] mol/[tex]L^2[/tex]

Solving for [OH-]:

OH- = (1.0 x [tex]10^-^1^4[/tex] mol/[tex]L^2[/tex]) / ([tex]10^-^4[/tex] mol/L)

OH- = 1.0 x [tex]10^-^1^0[/tex] mol/L

Learn more about the pH calculation here.

https://brainly.com/question/29182422

#SPJ1

The IUPAC nomenclature is based on an organized process that involves determining and prioritizing functional groups, substituents, and other structural features of the compound. The names of the given compounds are:

2-methyl, 2-hexene

4-ethyl, 3,5-dimethyl, nonane

4-methyl, 2-heptyne

5-propyl decane

Specific priority rules are used to decide the parent chain (main carbon backbone) in organic compounds, the choice of functional groups, and the numbering of carbon atoms. Prefixes and suffixes are used to suggest substituents, functional groups, and other structural elements present in the compound.

Learn more about IUPAC nomenclature, here:

brainly.com/question/14379357

#SPJ1

The compound with the most polar bonds is AsCl3. To determine this, we need to compare the electronegativity difference between the atoms in each compound. Polar bonds occur when there is a significant electronegativity difference between the two atoms involved in the bond. In AsCl3, As has an electronegativity of 2.1 and Cl has an electronegativity of 3.0. The difference is 0.9, which is the highest among the given options, indicating that AsCl3 contains the most polar bonds.

To determine which compound contains the MOST polar bonds, we need to compare the electronegativity of the atoms involved in each bond. Polar bonds occur when there is a significant difference in electronegativity between the atoms. The larger the difference, the more polar the bond.
In this case, we need to calculate the difference in electronegativity between the two atoms in each compound. The larger the difference, the more polar the bond. Here are the electronegativity values for each atom:
H (2.1); S (2.5); P (2.1); As (2.1); Cl (3.0); Si (1.8); Sb (1.9)
a. H2S: (2.5-2.1) = 0.4
b. PH3: (2.1-2.1) = 0
c. AsCl3: (3.0-2.1) = 0.9
d. SiH4: (2.1-1.8) = 0.3
e. SiCl4: (3.0-1.8) = 1.2
The compound with the largest electronegativity difference (and therefore the most polar bonds) is SiCl4 with a difference of 1.2. Therefore, the answer is e. SiCl4. This compound contains the most polar bonds out of all the given compounds.
To know more about electronegativity visit:

https://brainly.com/question/3393418

#SPJ11

He (helium) exhibits the weakest intermolecular forces. This is because He is a noble gas with a full electron shell, making it stable and non-reactive. H2O, NH3, and HCl all have polar bonds and stronger intermolecular forces such as hydrogen bonding (H2O and NH3) or dipole-dipole interactions (HCl).

Of the given options, the gas He exhibits the weakest intermolecular forces. This is because He is a noble gas and exists as a single atom, making it non-polar and lacking any dipole-dipole or hydrogen bonding intermolecular forces. On the other hand, H2​O and NH3​ are polar molecules and exhibit hydrogen bonding intermolecular forces, making them stronger than He. HCl also exhibits intermolecular forces due to its polarity, but it is stronger than H2​O and NH3​ because it has stronger dipole-dipole forces. In 100 words, the intermolecular forces are attractive forces between molecules. The strength of these forces determines the physical properties of substances, such as boiling and melting points. The weakest intermolecular forces are found in non-polar molecules, such as He, which have no dipole-dipole or hydrogen bonding. Polar molecules, such as H2​O and NH3​, exhibit stronger intermolecular forces due to their polarity and ability to form hydrogen bonds. HCl, another polar molecule, has stronger intermolecular forces than H2​O and NH3​ because it has stronger dipole-dipole forces.

To know more about intermolecular forces visit:

https://brainly.com/question/31797315

#SPJ11

Answer:

Explanation: the answer is in the picture

The ratio of the half-lives at 0.05M and 0.01M concentrations, measured at 55 °C.

The half-life of a reaction represents the time it takes for the concentration of a reactant to decrease by half. In this case, we are comparing the half-lives at two different concentrations, 0.05M and 0.01M, both measured at a temperature of 55 °C. Let's denote the half-life at 0.05M concentration as [tex]\(t_{1/2}(0.05M)\)[/tex] and the half-life at 0.01M concentration as [tex]\(t_{1/2}(0.01M)\)[/tex].

To calculate the ratio of these two half-lives, we divide [tex]\(t_{1/2}(0.05M)\)[/tex] by [tex]\(t_{1/2}(0.01M)\)[/tex]. Assuming you have experimental values for both half-lives, you can substitute those values into the formula. For example, if [tex]\(t_{1/2}(0.05M)\)[/tex] is measured to be 10 seconds and [tex]\(t_{1/2}(0.01M)\)[/tex] is measured to be 5 seconds, the ratio would be [tex]\(\frac{10}{5} = 2\)[/tex].

Please provide the experimental values for the half-lives at 0.05M and 0.01M concentrations measured at 55 °C, and I can calculate the specific value for the ratio [tex]\(t_{1/2}(0.05M) / t_{1/2}(0.01M)\)[/tex].

To learn more about half-lives refer:

https://brainly.com/question/25750315

#SPJ11

To find the excess grams of the reactant that remain after the reaction, we need to determine the limiting reactant first. The limiting reactant is the one that is completely consumed and determines the maximum amount of product that can be formed.

The moles of each reactant:

Molar mass of AgNO3 (silver nitrate) = 107.87 g/mol

Molar mass of FeCl3 (iron(III) chloride) = 162.2 g/mol

Moles of AgNO3 = mass / molar mass = 24.2 g / 107.87 g/mol = 0.2245 mol

Moles of FeCl3 = mass / molar mass = 39.2 g / 162.2 g/mol = 0.2413 mol

According to the balanced equation:

AgNO3 + FeCl3 → AgCl + Fe(NO3)3

The stoichiometric ratio between AgNO3 and FeCl3 is 1:1. This means that for every 1 mole of AgNO3, we need 1 mole of FeCl3.

Since the moles of AgNO3 (0.2245 mol) and FeCl3 (0.2413 mol) are very close, we can conclude that AgNO3 is the limiting reactant. This means that FeCl3 is in excess.

To find the excess grams of FeCl3 remaining, we need to determine the moles of FeCl3 that reacted with AgNO3. Since the stoichiometric ratio is 1:1, the moles of FeCl3 reacted will be equal to the moles of AgNO3 used.

Moles of FeCl3 reacted = Moles of AgNO3 = 0.2245 mol

Now, let's calculate the mass of FeCl3 that reacted:

Mass of FeCl3 reacted = Moles of FeCl3 reacted × Molar mass of FeCl3

Mass of FeCl3 reacted = 0.2245 mol × 162.2 g/mol = 36.393 g

To find the excess grams of FeCl3 remaining, we subtract the mass of FeCl3 that reacted from the initial mass of FeCl3:

Excess grams of FeCl3 remaining = Initial mass of FeCl3 - Mass of FeCl3 reacted

Excess grams of FeCl3 remaining = 39.2 g - 36.393 g = 2.807 g

Therefore, there are 2.807 grams of excess FeCl3 remaining after the reaction is over.

Learn more about limiting reactant here ;

https://brainly.com/question/10090573

#SPJ11

Answer:

There is litteraly no question

The balanced equation for the half-reaction that takes place at the cathode is: N2H4(aq) + 4OH^-(aq) + 4e^- → N2(g) + 4H2O(l)

The balanced equation for the half-reaction that takes place at the anode is: 2Br2(l) → 4Br^-(aq) + 4e^-

The cell voltage under standard conditions is -1.91 V.

The balanced equation for the half-reaction that takes place at the cathode is:

N2H4(aq) + 4OH^-(aq) + 4e^- → N2(g) + 4H2O(l)

The balanced equation for the half-reaction that takes place at the anode is:

2Br2(l) → 4Br^-(aq) + 4e^

To calculate the cell voltage under standard conditions, we need to find the reduction potentials (E°) for the half-reactions involved. The reduction potential for the cathode half-reaction is -0.84 V, and for the anode half-reaction, it is +1.07 V.

The cell voltage (E°cell) is calculated by subtracting the reduction potential of the anode half-reaction from the reduction potential of the cathode half-reaction:

E°cell = E°cathode - E°anode = -0.84 V - (+1.07 V) = -1.91 V

Therefore, the cell voltage under standard conditions is -1.91 V.

learn more about half-reaction Refer: https://brainly.com/question/18403544

#SPJ11

The pH scale ranges from 0 to 14, with values below 7 considered acidic, 7 being neutral, and values above 7 being alkaline. Hair and scalp have a slightly acidic pH, and using a pH-balanced shampoo helps maintain the natural balance.

The characteristic that identifies a pH-balanced shampoo is having a pH level close to the natural pH level of the hair and scalp, which is around 4.5 to 5.5. Therefore, a pH-balanced shampoo will have a pH level in the acidic to neutral range, typically between 4.5 and 5.5, to avoid causing damage or disrupting the natural pH balance of the hair and scalp.

Learn more about natural pH here ;

https://brainly.com/question/5171852

#SPJ11

A pH-balanced shampoo should have a pH between 4.5 and 5.5, contain mild acids or bases, and help to keep the hair and scalp's natural pH level balanced.

A pH-balanced shampoo is important because it prevents the scalp from becoming too dry or too oily. It ensures that the hair cuticle is closed, reducing frizz and improving shine. Using a pH-balanced shampoo can also help maintain the effectiveness of other hair products.

https://brainly.com/question/32512053

#SPJ6

The correct answer to your question is: c. lithium-ion battery. Lithium-ion batteries are rechargeable, making them suitable for various applications like electronics and electric vehicles. In contrast, dry cell and alkaline batteries are typically single-use and not rechargeable.

The correct answer to your question is option c. Lithium ion battery is a rechargeable battery that is commonly used in electronic devices. It is known for its high energy density, which means it can store more energy in a smaller size compared to other types of batteries. In contrast, dry cell and alkaline batteries are typically single-use and not rechargeable. This makes it popular in portable devices such as smartphones, laptops, and tablets. Lithium ion batteries typically last longer than other rechargeable batteries, making them a popular choice for consumers.
To know more about Lithium-ion batteries visit:

https://brainly.com/question/31115504

#SPJ11

To calculate the heat change in kJ when 3.245 x 10^23 pg of phosphorus pentachloride (PCl5) are produced in the given reaction. So, the heat change in the reaction when producing 3.245 x 10^23 pg of phosphorus pentachloride is approximately -1.31 x 10^-7 kJ.

To calculate the heat change in kJ for the given reaction, we first need to determine the moles of phosphorus pentachloride produced.
Using the molar mass of phosphorus pentachloride (208.24 g/mol), we can convert the given amount of 3.245 x 10^23 pg into moles:
3.245 x 10^23 pg = 3.245 x 10^-2 g
3.245 x 10^-2 g / 208.24 g/mol = 1.559 x 10^-4 mol
Now we can use the molar enthalpy of the reaction (-84.2 kJ/mol) to calculate the heat change:
-84.2 kJ/mol x 1.559 x 10^-4 mol = -0.0131 kJ or -13.1 J
Therefore, the heat change for the production of 3.245 x 10^23 pg of phosphorus pentachloride in this reaction is -13.1 J or -0.0131 kJ.

To know more about phosphorus pentachloride visit:

https://brainly.com/question/29141612

#SPJ11

False. The kinetic energy of gas molecules depends on their temperature, not their molar mass. Since both gases are at the same temperature and have the same volume, they have the same average kinetic energy.

The only difference is that gas B has larger and heavier molecules than gas A, which means it will have a lower number of molecules per mole compared to gas A. However, this does not affect the kinetic energy of each individual molecule. Therefore, the statement that the molecules of gas B have greater kinetic energy than those of gas A is false.
The kinetic energy of gas molecules is determined by their temperature, not their molar mass. Since both gases A and B are combined in a 1-L container at room temperature, their molecules have the same average kinetic energy. The fact that gas B has a molar mass twice that of gas A does not affect the kinetic energy of its molecules in this case.

To know more about Molecules visit:

https://brainly.com/question/16897383

#SPJ11

The equilibrium constant (K) for the reaction Ca(IO3)2(s) ↔ Ca2+(aq) + 2IO3-(aq) is approximately 0.000121

The equilibrium constant (K) for the reaction Ca(IO3)2(s) ↔ Ca2+(aq) + 2IO3-(aq) can be determined using the given concentration of IO3-(aq) in the solution.

The equilibrium constant expression for the reaction is given by:

K = [Ca2+][IO3-]^2

Given that the concentration of IO3-(aq) at equilibrium is 0.011 M, we can substitute this value into the equilibrium constant expression:

K = [Ca2+](0.011 M)^2

Since excess Ca(IO3)2(s) is present, the concentration of Ca2+(aq) can be assumed to be negligibly small compared to the concentration of IO3-(aq). Therefore, we can simplify the expression further:

K ≈ 0.011 M^2

Calculating this expression gives us the equilibrium constant for the reaction: K ≈ 0.000121

Therefore, the equilibrium constant (K) for the reaction Ca(IO3)2(s) ↔ Ca2+(aq) + 2IO3-(aq) is approximately 0.000121

learn more about equilibrium constant Refer: https://brainly.com/question/29809185

#SPJ11

To answer this question, we need to use the equilibrium constant expression for acetic acid, which is: Ka = [H+][CH3COO-] / [CH3COOH]. Therefore, the pH of the 0.28 M solution of acetic acid is 2.39.

Where [H+] represents the concentration of hydrogen ions, [CH3COO-] represents the concentration of acetate ions, and [CH3COOH] represents the concentration of acetic acid.
Since we are given the Ka and the concentration of acetic acid, we can solve for the concentration of acetate ions and hydrogen ions:
Ka = [H+][CH3COO-] / [CH3COOH]
1.76 x 10^-5 = [x][x] / (0.28 - x)
Where x is the concentration of hydrogen ions and acetate ions.
Solving for x, we get:
x = 0.00405 M
This is the concentration of both hydrogen ions and acetate ions. To find the pH of the solution, we can use the equation:
pH = -log[H+]
Where [H+] is the concentration of hydrogen ions.
pH = -log(0.00405)
pH = 2.39
Therefore, the pH of the 0.28 M solution of acetic acid is 2.39.

To know more about Acetic acid visit:

https://brainly.com/question/15202177

#SPJ11