Application of Geometric Series

Application Of Geometric Series

Answers

Answer 1

Answer:

  7.2224

Step-by-step explanation:

The value of the summation is given by the formula ...

  Sn = (a1)(1 -r^n)/(1 -r) . . . . . where a1 is the first of n terms, and r is the common ratio.

Your sum has first term and ratio ...

  a1 = 2(0.6) . . . . . summation term for n=1

  r = 0.6

So the sum is ...

  [tex]\displaystyle \sum_{n=1}^4{2(0.6^n)}=2(0.6)\dfrac{1-0.6^4}{1-0.6}=\dfrac{1.2}{0.4}(0.8704) = 2.6112[/tex]

Then the value of the entire given expression is ...

  [tex]\displaystyle 2+2\sum_{n=1}^4{}2(0.6^n)=2+2(2.6112)=\boxed{7.2224}[/tex]

_____

A calculator can help you find the value.

Application Of Geometric Series

Related Questions

A plant nursery receives shipments of soil in containers as shown below
( a picture of a cube that has 3 numbers - The heigh = 1 1/4 the base =2 . The width= 1 1/2
Part a- what is the volume of the soil in each container in cubic yards
(I put my answer as 3 3/4 which is right I think )
Part b - if a cubic yard of soil weighs 2000 pounds of soil does each container hold?
***I need help with part b pls

Answers

The volume of the three-dimensional figure is 3.75 yd³, and it can hold 7500 pounds of soil

What is volume?

Volume is the amount of space occupied by a three dimensional shape or object.

The volume of the three dimensional shape is:

Volume = length * width * height = 1 1/4 * 1 1/2 * 2 = 3.75 yd³

1 yd³ = 2000 pounds

3.75 yd³ = 2000 pounds * 3.75 yd³ = 7500 pounds

The volume of the three-dimensional figure is 3.75 yd³, and it can hold 7500 pounds of soil

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9. To stitch a shirt, 2 m 15 cm cloth is needed. Out of 40 m cloth, how many shirts can be stitched and how much cloth will remain? (Hint : convert data in cm.)​

Answers

Answer:

1 Shirt and 185cm remaining cloth

Step-by-step explanation:

2m and 15cm = 215cm

40m = 400cm

400/215=1.860465116

A shirt cant be in decimal so we remove the decimals, and take the as the answer. For the decimals, they are the remaining cloth.. to calculate the amount of remaining cloth we do:

1.860465116-1

=860465116

215*860465116=185cm

What is the solution to the equation?

Answers

Answer: Your answer is X=-63

Hope this helps!


What is a major difference between parallel lines and perpendicular lines?

Answers

Answer:

Parallel lines never intersect. Perpendicular lines are lines that intersect.

Step-by-step explanation:

Hope this helps.

Answer:

Perpendicular lines meet at a 90 degree angle while parallel lines will never touch

Step-by-step explanation:

Solve the simultaneous equations
4x + 5y = 4
2x - y = 9
Show clear algebraic working.

Answers

Answer:

[tex]x= \dfrac 72, ~~y= -2[/tex]

Step by step explanation:

[tex]4x+5y=4~~~...(i)\\\\2x-y=9~~~...(ii)\\\\\text{Multiply eq (ii) by 2 to isolate x:}\\\\4x-2y=18~~~.....(iii)\\\\(iii)-(i):\\\\4x-2y-4x-5y=18-4\\\\\implies -7y=14\\\\\implies y = -\dfrac{14}7 = -2\\\\\text{Substitute}~ y=-2~ \text{in equation (iii):}\\\\4x-2(-2) = 18\\\\\implies 4x +4 = 18\\\\\implies 4x = 18-4\\\\\implies 4x = 14\\\\\implies x = \dfrac{14}4 = \dfrac 72\\\\\text{Hence}~ (x,y) =\left(\dfrac 72 , -2 \right)[/tex]

Step-by-step explanation:

4x+5y=4 (equation 1)

2x-y=9 (equation2)

solving equation 1 and 2 and multiplying equation 2 by 2

4x+5y=4

4x-2y=18

- + -

________

7y= -14

y= -2

putting the value of y in equation 2

2x-y=9

2x+2=9

2x=7

x=3.5

Help me out please simple

Answers

A straight line is 180 degrees in measure

The straight line is made up of three angles

           --> angle 1

           --> angle 2

           --> angle with a little square on it

                     (angle with a little square means it is 90 degrees in measure)

Let's set up an equation

    [tex]angle1 + angle2 + 90 = 180\\angle1 + 87 + 90 = 180\\angle1 = 3[/tex]

Thus angle 1 is 3 degrees or the second choice

Hope that helps!

help me find Find AB

Answers

25.9
The reason is b/c there is a pattern. 1st is since 11.5+7.2=18.7 than you would add 7.2 to 18.7 than you would get 25.9. Also another way is subtracting 18.7-11.5=7.2.

Ps: Jisoo is my bias wby???
Blackpink in your area

The distance of AB is 42.04 units, BC is 35.77 units and CA is 34.5 units.

We have,

The length along a line or line segment between two points on the line or line segment.

The coordinates of A are (-18, -18)

coordinates of B are (20, 0)

coordinates of C are (-12, 16)

The formula for distance is Distance=√(x₂-x₁)²+(y₂-y₁)²

Distance AB=√(20-(-18))²+(0-18)²

=√(20+18))²+(0-18)²=√38²+18²

AB=√1444+324

    =√1768

    =42.04 units

Distance BC=√(-12-20)²+(16)²

=√(-32)²+(16)²=√1024+256

=√1280

=35.77

Distance CA=√(-12-(-18))²+(16+18)²

=√(6)²+(34)²

=√36+1156=34.5

Hence, the distance of AB is 42.04 units, BC is 35.77 units and CA is 34.5 units.

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complete question:

PLease help me find the distance between AB BC and CA please help

Mr. Turner has two Algebra 1 classes. With one class, he lectured and the students took notes. In the other class, the students worked in small groups to solve math problems. After the first test, Mr. Turner recorded the student grades to determine if his different styles of teaching might have impacted student learning.

Class 1: 80, 81, 81, 75, 70, 72, 74, 76, 77, 77, 77, 79, 84, 88, 90, 86, 80, 80, 78, 82

Class 2: 70, 90, 88, 89, 86, 86, 86, 86, 84, 82, 77, 79, 84, 84, 84, 86, 87, 88, 88, 88

1. Analyze his student grades by filling in the table below. Which class do you think was the lecture and which was the
small group? Why?

Answers

                          Q1            Q2       IQR   Mean      Median         MAD

Class 1            76.25         81.75    5.5      79.35         79.50       3.12

Class 2             84             88        4           84.60         86           3.85

What is Q1, Q3, IQR, Mean, Median and the MAD?

The first step is to arrange the grades in the classes in ascending order.

Class 1: 70, 72, 74, 75, 76, 77, 77,77, 78, 79, 80, 80, 80, 81, 81, 82, 84, 86, 88, 90

Class 2: 70, 77, 79, 82, 84, 84, 84, 84, 86, 86, 86, 86, 86, 87, 88, 88, 88, 88, 89, 90

Q1 for class 1= 1/4(n + 1) = 21/4 = 5.25 = 76.25

Q2 for class 2 = 1/4(n + 1) = 5.25 = 84

Q3 for class 1= 3/4(n + 1) = 15.75 = 81.75

Q3 for class 2 = 3/4(n + 1) = 15.75 = 88

IQR for class 1 = Q3 - Q1 = 81.75 - 76.25 = 5.50

IQR for class 2 = Q3 - Q1 = 88 - 84 = 4

Mean for class 1 = sum of grades / total number of grades = 1587 / 20 = 79.35

Mean for class 2 = sum of grades / total number of grades= 1692 / 20 = 84.6

Median for class 1 = (n + 1) / 2 = 21/2 = 10.5 = 79.50

Median for class 1 = (n + 1) / 2 = 21/2 = 10.5 = 86

MAD = [tex]\frac{1}{n}[/tex]∑ l x - m(x) l

Where: n = number of observations

x = number in the data set

m = mean

Mean absolute deviation for class 1 = 62. 3/ 20 = 3.12

Mean absolute deviation for class 2. = 77/ 20 = 3.85

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help to search for JOIN in this alphabet soup please ​

Answers

Answer:

hopefully this helps :] 16th line down I think

how many mL of normal saline should be added to 50mL of hydrogen peroxide to create a solution that is 5/8 strength?

Answers

1.5
I think… hope I’m right lol

Which expression is approximately equal to 5 5/8 x 4 5/6?

Answers

[tex]\huge\text{Hey there!}[/tex]

[tex]\mathsf{5 \dfrac{5}{8}\times 4\dfrac{5}{6}}\\\\\mathsf{= \dfrac{5\times6+5}{8}\times\dfrac{4\times6+5}{6}}\\\\\mathsf{= \dfrac{45}{8}\times \dfrac{29}{6}}\\\\\mathsf{= \dfrac{45\times29}{8\times6}}\\\\\mathsf{= \dfrac{1,305}{48}}\\\\\mathsf{= \dfrac{1,305\div3}{48\div3}}\\\\\mathsf{= \dfrac{435}{16}\approx 27 \dfrac{3}{16}}\\\\\huge\textbf{Therefore, your answer is: \boxed{\mathsf{27\dfrac{3}{16}}}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

solve for x ~
[tex]46x - 23x = 2[/tex]


thankyou ~​

Answers

Answer: x = 2/23

Step-by-step explanation:

[tex]46x-23x=2[/tex]

[tex]\mathrm{Add\:like\:terms:}\:46x-23x=23x[/tex]

[tex]23x=2[/tex]

[tex]\mathrm{Divide\:both\:sides\:by\:}23[/tex]

[tex]\frac{23x}{23}=\frac{2}{23}[/tex]

[tex]$$Simplify[/tex]

[tex]\bold{x=\frac{2}{23}}[/tex]

Answer:

x = 2/23

Step-by-step explanation:

Inthis question we are given with one equation that is 46x - 23x = 2 and we have asked to find the value of x or solve for x .

So , from here we are solving :

[tex] \longmapsto \: 46x - 23x = 2[/tex]

Step 1 : Taking 23x common at left hand side :

[tex] \longmapsto \: 23x(2 - 1) = 2[/tex]

Step 2 : Subtracting 1 with 2 :

[tex] \longmapsto \:23x = 2[/tex]

Step 3 : Transposing 23 to right hand side :

[tex] \longmapsto \: \red{ \boxed{x = \frac{2}{23} }}[/tex]

Therefore, value of x is 2/23

Verifying the answer :

We are verifying our answer by substituting the value of x in the given equation .

[tex] \longmapsto \: 46(\frac{2}{23}) - 23( \frac{2}{23} ) = 2[/tex]

Now , calculating :

[tex] \longmapsto \: \cancel{46}(\frac{2}{ \cancel{23}}) - \cancel{23}( \frac{2}{ \cancel{23}} ) = 2[/tex]

[tex] \longmapsto \: 4 - 2 = 2[/tex]

[tex] \longmapsto \: 2 = 2[/tex]

[tex] \longmapsto \: L.H.S = R.H.S[/tex]

[tex] \longmapsto \: Hence, \: Verified . \: [/tex]

Therefore , our value for x is correct .

#Keep Learning

List three numbers that are less than -7

Answers

Answer:

Step-by-step explanation: first one way that you can answer this question is to use a numberline, so you start at zero and go to the left of the numberline and the numbers behind -7 would be -8,-9, and or ,-10 they are all less than negative seven




C. Test your team's method by determining the midpoint of the segment with endpoints (-5,7) and (9, 4) and checking your answer with your teacher. On a map, Cary drew a set of coordinate axes. He noticed that the town of Coyner is located at the point (3,1) and Woottonville is located at (15,7), where 1 grid unit represents 1 mile. If the towns want to place a school at the midpoint between the towns, where should it be located? How far would it be from each town?​

Answers

The town should be located 13.4 units from each other

How to calculate the distance between two  points

The formula for calculating the distance between two points is expressed as:
√(x2-x1)²+(y2-y1)²

The midpoint of two coordinates is expressed as:
[tex]m(x, y)=(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2} )[/tex]

Substitute the given coordinate

[tex]m(x, y)=(\frac{3+15}{2}, \frac{1+7}{2} )\\m(x,y)=(9,4)[/tex]

Hence the town should be located at coordinate (9, 4)

Calculate the distance

D =  √(15-3)²+(7-1)²

D =  √(12)²+(6)²

D = 13.4units

Hene the town should be located 13.4 units from each other

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find the equation of the tangent to the circle whose equation is given below at the point (1,2)

(x-3)^2 + (y+2)^2 = 20

give answer in form ax+by+c=0 where abc are integers

Answers

Answer:

[tex]x-2y+3=0[/tex]

Step-by-step explanation:

Equation of a circle:  [tex](x-h)^2+(y-k)^2=r^2[/tex]

(where (h, k) is the centre, and r is the radius)

Given equation: [tex](x-3)^2+(y+2)^2=20[/tex]

Therefore, the centre is (3, -2) and the radius is √20

To find the equation of the tangent

The tangent of a circle is perpendicular to the radius at the point.

Therefore, first find the gradient (slope) of the line that passes through the centre of the circle and the given point.

[tex]\textsf{let}\:(x_1,y_1)=(1,2)[/tex]

[tex]\textsf{let}\:(x_2,y_2)=(3,-2)[/tex]

[tex]\textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{-2-2}{3-1}=-2[/tex]

If two lines are perpendicular to each other, the product of their gradients will be -1.

Therefore, the gradient of the tangent is:  

[tex]m_t \cdot-2=-1\implies m_t=\dfrac12[/tex]

Now use the point-slope formula of a linear equation to find the equation of the tangent:

[tex]\implies y-y_1=m_t(x-x_1)[/tex]

[tex]\implies y-2=\dfrac12(x-1)[/tex]

[tex]\implies 2y-4=x-1[/tex]

[tex]\implies x-2y+3=0[/tex]

Danita is working on a new sculpture. It will be 2 meters tall when she is finished. Will the sculpture fit in a room with a 300-centimeter high ceiling? Explain.​

Answers

Answer:

  yes; 2 m = 200 cm

Step-by-step explanation:

The SI prefix "centi-" signifies 1/100. That is 300 cm = 300/100 m = 3 m.

If the ceiling is 3 meters high, a sculpture that is 2 meters tall will have no difficulty fitting into the room.

PLEASW HELP
The number of bats in a colony is growing exponentially. After 4 years, there were 2025 bats. After 6
years, there were 18225 bats.
If the colony continues to grow at the same rate, how many bats are expected to be in the colony after
12 years? Do not include units in your answer.

Answers

Answer:

there would be around 40,000 colony of bats

There to be about 13,286,025 bats in the colony after 12 years if the growth rate remains constant.

What is Exponential Growth?

An exponential function's curve is created by a pattern of data called exponential growth, which exhibits higher increases over time.

y = a(1+r)ˣ,

where a is the initial population and r is the rate in decimals and x is the time period.

To solve this problem, we need to use the formula for exponential growth:

N = N₀ (1 + r)ˣ

where:

N is the final number of bats after x years

N₀ is the initial number of bats

r is the annual growth rate (expressed as a decimal)

x is the number of years.

We can use the information given in the problem to find the values of N0, r, and t for the first two time periods:

For the first 4 years:

2025 = N₀(1 + r)⁴

For the next 2 years (6 years in total):

18225 = N₀ (1 + r)⁶

To solve for N₀ and r, we can divide the second equation by the first equation:

18225/2025 = (N₀ (1 + r)⁶) / (N₀(1 + r)⁴)

9 = (1 + r)²

Taking the square root of both sides, we get:

1 + r = 3

r = 2 (since r is expressed as a decimal)

Now that we know r, we can use either of the two original equations to find N₀. Let's use the first equation:

2025 = N₀(1 + 2)⁴

2025 = N₀(81)

N₀ = 25

So the initial number of bats was 25, and the annual growth rate is 200% (or 2 as a decimal).

Now we can use the formula to find the number of bats after 12 years:

N = 25 (1 + 2)¹²

N = 25 (531441)

N = 13,286,025

Therefore, we can expect there to be about 13,286,025 bats in the colony after 12 years if the growth rate remains constant.

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1. Determine the lateral and total surface area
of the square pyramid.
12 cm
12.8 cm
qom
Lateral Surface Area
Total Surface Area

Answers

The areas of the square pyramid are the amount of space on it

The lateral surface area is 307.2 square cmThe total surface area is 451.2 square cm

How to determine the lateral surface area?

The given parameters are:

Base (b) = 12 cm

Slant height (l) = 12.8 cm

The lateral surface area is calculated using:

L = 2bl

So, we have:

L = 2 * 12 * 12.8

Evaluate the product

L = 307.2

How to determine the total surface area?

This is calculated using:

T = L + b^2

So, we have:

T = 307.2 + 12^2

Evaluate

T = 451.2

Hence, the total surface area is 451.2 square cm

Read more about areas at:

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Please hurry
What is the surface area of this figure? Enter your answer in the box.​

Answers

Answer:

692ft3

Step-by-step explanation:

Surface area of the rectangular prism;

SA = lw(2) + wh(2) + hl(2)

SA = 15(5)(2) + 5(8)(2) + 8(15)(2)

SA = 150 + 80 + 240 =

SA = 470ft3

Surface area of the triangular prism

SA = (S1 + S2 + S3) l + bh

SA = (9 + 9 + 11) 5 + 11(7)

SA = (29) 5 + 11(7)

SA = 145 + 77

SA = 222ft3

Add both the SA's

470ft + 222ft = 692ft3

please help me in this mathematics questionplease help me in this mathematics questionplease help me in this mathematics question

Answers

The twenty units of potatoes illustrates the measure of central tendency  and probability

The modal weight, mean, and median

Start by sorting the dataset:

0.19; 0.28; 0.55;

0.62; 0.68; 0.77;

0.88; 0.89; 0.98;

0.99; 1.11; 1.22;

1.22; 1.22; 1.33;

1.44; 1.48; 1.68;

1.77; 1.99

The highest occuring element is 1.22 with a frequency of 3

The two middle elements are 0.99 and 1.11.

The mean of these two middle elements is: 0.5 * (0.99 + 1.11) = 1.05

The mean of the whole dataset is:

Mean = (0.19+ 0.28+ 0.55+ 0.62+ 0.68+ 0.77+ 0.88+ 0.89+ 0.98+ 0.99+ 1.11+ 1.22+1.22+ 1.22+ 1.33+ 1.44+ 1.48+ 1.68+1.77+1.99)/20

Mean = 1.06

Hence, the modal weight is 1.22, the mean is 1.06, and the median is 1.05

The probabilities

(a) at least 1.1 kg

There are 10 potatoes that weigh at least 1.1 kg.

So, the probability is:

P = 10/20

P = 0.5

(b) more than 3.5kg

There are 0 potatoes that weigh more than 3.5 kg.

So, the probability is:

P = 0/20

P = 0

(c) below 0.50kg

There are 2 potatoes that weigh below 0.50 kg.

So, the probability is:

P = 2/20

P = 0.1

The Variance of the weight.

This is calculated as:

Var = [tex]\sum[/tex](x - mean)^2/n

This gives

Var = [(0.19 - 1.06)^2 + (0.28 - 1.06)^2 + (0.55 - 1.06)^2 + (0.62 - 1.06)^2 + (0.68 - 1.06)^2 + (0.77 - 1.06)^2 + (0.88 - 1.06)^2 + (0.89 - 1.06)^2 + (0.98 - 1.06)^2 + (0.99 - 1.06)^2 + (1.11 - 1.06)^2 + (1.22 - 1.06)^2 + (1.22 - 1.06)^2 + (1.22 - 1.06)^2 + (1.33 - 1.06)^2 + (1.44 - 1.06)^2 + (1.48 - 1.06)^2 + (1.68 - 1.06)^2 + (1.77 - 1.06)^2 + (1.99 - 1.06)^2]/20

Evaluate

Var = 0.22

This means that:

The expectation of the squared deviation of the random variable from the mean is 0.22 kg

Read more about measure of central tendency at:

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Answer:

0.22 kg

Step-by-step explanation:

Solve the system of equations.​
−4x+3y=−2y=x−1​

Answers

Step-by-step explanation:

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Critical Thinking: I am a 7-digit number. All my digits are non-zero and distinct, My ones digit is four times the tens digit. • The sum of the ones and tens digits is equal to the sum of the lakhs and ten lakhs digits. • The sum of the ten thousands and thousands digits is equal to the double of the hundreds digit. • The ten lakhs digit is greater than the lakhs digit , and the ten thousands digit is greater than the thousands digit. Find which number I am. ​

Answers

Answer:

3286714

Step-by-step explanation:

Let the digits of the number be :

ABCDEFG

Our given conditions :

G = 4F [ones digit is four times the tens digit]G + F = B + A [sum of the ones and tens digits is equal to the sum of the lakhs and ten lakhs digits]C + D = 2E [sum of the ten thousands and thousands digits is equal to the double of the hundreds digit]A > B and C > D [ten lakhs digit is greater than the lakhs digit , and the ten thousands digit is greater than the thousands digit]

Solving :

Condition 1 : G is either 1 or 2 and F is either 4 or 8For now, let G be 1 and F be 4 Now G + F = A + BThen A + B = 5 [but not 1 + 4] ⇒ A can be 3 and B can be 2Now C + D = 2E and our remaining numbers are 5,6,7,8,9C and D can be 8 and 6, then their mean would be 7, which is E

Solution :

So, the number is :

ABCDEFG3286714

{2x+3y=−7, 7x+9y=−14
Answer as an ordered pair (x,y).

Answers

Answer:

Step-by-step explanation:

2x + 3y = -7

7x + 9y = -14

-3(2x+3y= -7) = -6x - 9y = 21

-6x - 9y = 21

7x + 9y = -14

add columns (y values cancel)

1x + 0y = 7

x = 7

plug 7 into the x value in either equation to find y

2(7) + 3y = -7

14 + 3y = -7

3y = -21

y = -7

(x,y) = (7,-7)

Lillian spent 18 minutes practicing her spelling words. How many seconds did she practice?

Answers

Answer:

1080 seconds.

Step-by-step explanation:

There are 60 seconds in a minute. As provided in the question, Lillian spent eighteen minutes, so 18x60=1080.

Answer:

1,080 seconds

Step-by-step explanation:

What is the mode of the data set?
78, 82, 91, 78, 92, 77, 80, 74, 81

Answers

Answer:

The mode is 78

Step-by-step explanation:

Mode: The digit that has been repeated the most in a specific data.

To determine the mode of the data, let's arrange the data in ascending order.

Arranging the data in ascending form, we get:

⇒ 74, 77, 78, 78, 80, 81, 82, 91, 92

In the ascending data, we can see that: (Refer to underlined and bolded text)

74 has been repeated once77 has been repeated once78 has been repeated twice80 has been repeated once81, has been repeated once82 has been repeated once91 has been repeated once92 has been repeated once

Since 78 has been repeated the most, 78 is the mode of the data.

HELP MEEEEEE PLESEEE

Answers

Answer:

648 cubic centimeters

Step-by-step explanation:

6×9×12=648

Answer:

648 cubic centimeters

Step-by-step explanation:

All you need to do is multiply all of the measures that they show you.

6 x 9 x 12 which equals 648

find the second derivative of the parametric equation x(t)=sin t and y(t)=cos t​

Answers

Presumably you mean the second derivative of y with respect to x, d²y/dx².

Compute the first derivative. By the chain rule,

[tex]\dfrac{dy}{dx} = \dfrac{dy}{dt} \times \dfrac{dt}{dx} = \dfrac{\frac{dy}{dt}}{\frac{dx}{dt}}[/tex]

Differentiate the two parametric equations with respect to t :

[tex]x = \sin(t) \implies \dfrac{dx}{dt} = \cos(t)[/tex]

[tex]y = \cos(t) \implies \dfrac{dy}{dt} = -\sin(t)[/tex]

Then the first derivative is

[tex]\dfrac{dy}{dx} = \dfrac{-\sin(t)}{\cos(t)} = -\tan(t)[/tex]

Now, dy/dx is a function of t, so we can denote it by, say, dy/dx = f(t). Then by the chain rule, the second derivative will be

[tex]\dfrac{d^2y}{dx^2} = \dfrac{df}{dx} = \dfrac{df}{dt} \times \dfrac{dt}{dx} = \dfrac{\frac{df}{dt}}{\frac{dx}{dt}}[/tex]

Differentiating f(t) :

[tex]f(t) = -\tan(t) \implies \dfrac{df}{dt} = -\sec^2(t)[/tex]

Then the second derivative is

[tex]\dfrac{d^2y}{dx^2} = \dfrac{-\sec^2(t)}{\cos(t)} = \boxed{-\sec^3(t)}[/tex]

and since y = cos(t), we can go on to say

[tex]\dfrac{d^2y}{dx^2} = -\dfrac1{y^3}[/tex]

1. Select the three rational numbers.

A. 5/1
B. 7/0
C. -0.02
D. 4.17(the 7 repeats)
E. 3.14 (pi)
F. 3.14 (pi squared)

Answers

Answer:

A. 5/1

C. -0.02

D. 4.177777....

Step-by-step explanation:

Rational numbers can be written as a ratio of numbers, such as 5/1. As decimals, the numbers either

*** "terminate" the decimal has a certain number of digits and then stops, such -0.02, this can be written as a ratio -2/100 which is -1/50

OR

*** "repeats" , such as 4.17777... which can also be written as a ratio, 4.1777... = 188/45

7/0 is undefined and the pi numbers are irrational, the digits of the decimal do not repeat and do not ever end, therefore NOT rational.

-1/2 (-3 / 2x + 6x + 1) -3 x

Answers

Answer: here

Step-by-step explanation:

−21−24

Answer: negative 21 Negative 224


-21-24

Rodney says that he can draw two rectangles that have the same areas but different perimeters.

Which of the following pairs of rectangles could Rodney draw?
Select all that apply.

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A rectangle with side lengths 4 cm and 6 cm and a rectangle with side lengths 2 cm and 12 cm

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A rectangle with side lengths 4 cm and 6 cm and a rectangle with side lengths 2 cm and 8 cm

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A rectangle with side lengths 3 cm and 6 cm and a rectangle with side lengths 2 cm and 9 cm

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A rectangle with side lengths 5 cm and 6 cm and a rectangle with side lengths 2 cm and 9 cm

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A rectangle with side lengths 5 cm and 4 cm and a rectangle with side lengths 2 cm and 7 cm

Answers

Answer:

A rectangle with sides lengths 4cm and 6cm and a rectangle with side lengths 2cm and 12 cm...

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