Mathematics High School

Anyone know the answer?

Answers

Answer 1

Answer:

Positive

Step-by-step explanation:

Negative over a negative cancel out and become positive.

Related Questions

PLS HELP ME I WILL MARK THE BRAINLIEST

Answers

First the rectangle

L=18mB=7m

Area

18(7)126m^2.

For semicircle

d=7m=>r=3.5m

Area

=πr^2/2=12.25π/2

Total area

126+2(12.25π/2)126+12.25πm^2

r=15fttheta=332°=332×π/180=0.92π

Area:-

r^2\theta15^2(0.92)207ft^2

Nick and his family travel by train to New York City.
The clocks show when the train leaves the station and when it arrives in New York City.

How long is the train ride?

Answers

Answer:4:15

Step-by-step explanation:

(ii) Two of the lights at the local stadium start flickering at 9:15 p.m. One of the lights flickers every 8
minutes and the other light flickers every 12 minutes. What time both lights flicker at the same time
again?

PLSS HELPPP

Answers

Answer:

At 9:39 they both will Flick

Step-by-step explanation:

so when the first light flicks it resets and starts counting to anthor 8 mins while the other takes 4 mins extra just keep adding till they both have same time

Gabrielle is saving money for a vacation. Each week she save $40. Let a represent the total amount of money Gabrielle saves, and let w represent the number of weeks. How much money would she save from 1 to 7 weeks?

Answers

Step-by-step explanation:

A = 40w

To Calculate how much she would get in 7 weeks

Substitute w = 7 into A = 40w

⇒ A = 40(7)

⇒ A = 280

Gabrielle would save $280 in 7 weeks

What is the constant term in the expression 8xy − 9x2 y − 5x 6

Answers

Answer:

Step-by-step explanation:

A constant is a term without a variable.

Every other number has a variable (x,y) to it except for 6.

Feel free to save this for whenever you get stuck on things like this! I know this section is hard.

In the expression 8xy − 9x^2+ y − 5x +6 the constant term is 6 which is a fixed quantity or cannot be changed.

What is polynomial?

Polynomial is the combination of variables and constants in a systematic manner with "n" number of power in ascending or descending order.

We have an expression:

[tex]\rm 8xy-9x^2+y-5x+6[/tex]

Let's denote it with f(x,y)

[tex]\rm f(x,y) =8xy-9x^2+y-5x+6[/tex]

As we know the constant term means which cannot be changed that values are fixed or fixed quantity.

From the above expression, the constant value in the expression is 6

Thus, in the expression 8xy − 9x^2+ y − 5x +6 the constant term is 6 which is a fixed quantity or cannot be changed.

Learn more about Polynomial here:

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Suppose that 16 inches of wire costs 48 cents.
At the same rate, how much (in cents) will 47 inches of wire cost?

Answers

let’s divide 48 by 16 to see how many cents per inch of wire. 48/16=3 so it costs 3 cents per inch of wire. now all we have to do is multiply 47 by 3, and you will get 141 cents, or $1.41.

What ratio forms a proportion with 2/3?
A. 2/4 B. 3/4 C. 4/6 D. 3/2

Answers

Answer:

Step-by-step explanation:

because you can simplify 4/6 by 2.

2 goes into 4 twice and then 2 goes into 6 3 times

2/3

I’ll give you brainiest who ever answer this right

Answers

Answer:

y=x+1

Step-by-step explanation:

at each x you move up by 1

Knowing that ΔBIG ≅ ΔFNS, an angle pair that is NOT necessarily congruent is:

Knowing that ΔDAL ≅ ΔEKS, a side pair that is NOT necessarily congruent is:

Answers

solutions:

1) G ≅ F

2) DA ≅ ES

Explanation:

Q)1

ΔBIG ≅ ΔFNS

pairs that are congruent:

B ≅ FI ≅ NG ≅ S

From the list given,

→ G ≅ F is not necessarily congruent.

Q)2

ΔDAL ≅ ΔEKS

pairs that are congruent:

DA ≅ EKAL ≅ KSDL ≅ ES

From the list given,

DA ≅ ES is not necessarily congruent.

Usually the congruence is done according to naming

∆BIG≅∆FNS

<B=F

<I=<N

<G=<S

Option A

Check the naming

∆DAL≅∆EKS

DA=EK

And DA may not be equal to ES

So option D

Find the area. Round to the nearest hundredth when necessary. Be sure you are showing all work to find each figure.

Answers

Additional requirements in figure :-

Mark point :-

ABCDE

Draw a straight line from E to AB .

And the point line joins mark it as "F" .

It will generate quadrilateral FBCD.

we get to know In quadrilateral left angle is 90°

How ?

{

proof :

As three angles are given 90° So third angle will also be 90°

Reason:

→ Sum of interior angles = 2 (no. of angles - 2 × 180°

→Sum of interior angles = (4-2 × 180°)

→Sum of interior angles = (2 × 180°)

→Sum of interior angles = 360°

}

✿Now let the left angle be x

90° +90° + 90° + x = 360° 180° + 90° + x = 360°270° + x = 360x = 360° - 270°x = 90°

we know :

Area of rectangle = Length × Breadth

STEPS :

Area of rectangle = Length × Breadth

Area of rectangle = 7 × 8

Area of rectangle = 56 in²

Now let's find EF :

EF = BD - EC

EF = 7 - 4

EF = 3 in

To find A

F :

A•F = AB - CD

A•F = 12 - 8

A•F = 4 in

In triangle AFE:

EF is base of triangle A•F is height of triangle

We know :

Area of triangle =( Height × Base)/2

Steps :

Area of triangle = (Height × Base)/2Area of triangle = (4 × 3)/2Area of triangle = 12/2Area of triangle = 6 in²

To find area of figure :

Area of figure = Area of rectangle + Area of triangleArea of figure = 56 + 6Area of figure = 62 in²

______________________

~WindyMint

Answer:

[tex]\displaystyle 62\:in.^2[/tex]

Step-by-step explanation:

▽ [tex]\displaystyle \frac{hb}{2} = A, \frac{1}{2}bh = A, or\:\frac{1}{2}hb = A[/tex]

▯ [tex]\displaystyle hb = A[/tex]

All edges meet at right angles, therefore resulting in this:

[tex]\displaystyle 62 = 56 + 6 \Rightarrow 62 = 7 \times 8 + 4 \times 1\frac{1}{2}[/tex]

I am joyous to assist you at any time.

solve- cbb to work it out

Answers

Answers:

➝ Hypotenuse of triangle ( a ) = 21.63 mm

➝ Hypotenuse of triangle ( b ) = 150 mm

➝ Hypotenuse of triangle ( c ) = 111.80 mm

[tex] \quad\rule{300pt}{1.5pt}\quad[/tex]

Solution:

We have to find the length of hypotenuse in the given 3 triangles, which can be done by using Pythagoras theorem.

Pythagoras theorem states that :

" In a right angled triangle, the square of hypotenuse side is equal to the sum of square of other two sides "

[tex] \qquad \bull \:{\pmb{\mathfrak{ h^2 = b^2 + p^2}}}[/tex]

And we have to convert the answer to the units indicated in red i.e, in mm.

Since 1cm = 10 mm, we will convert the given values of length of side in mm before putting the values in the formula

For triangle ( a )

[tex] :\implies\qquad \sf{ h^2 = b^2 + p^2}[/tex]

[tex] :\implies\qquad \sf{ h =\sqrt{b^2 + p^2}}[/tex]

[tex] :\implies\qquad \sf{h=\sqrt{ (12)^2 + (18)^2 }}[/tex]

[tex] :\implies\qquad \sf{ h= \sqrt{144 + 324}}[/tex]

[tex] :\implies\qquad \sf{ h = \sqrt{468}}[/tex]

[tex] :\implies\qquad\underline{\underline{\pmb{ \sf{ h = 21.63 mm}}}}[/tex]

For triangle ( b )

[tex] :\implies\qquad \sf{ h^2 = b^2 + p^2}[/tex]

[tex] :\implies\qquad \sf{h =\sqrt{b^2 + p^2} }[/tex]

[tex] :\implies\qquad \sf{ h = \sqrt{(90)^2+(120)^2}}[/tex]

[tex] :\implies\qquad \sf{ h=\sqrt{8100+14400}}[/tex]

[tex] :\implies\qquad \sf{ h =\sqrt{22500}}[/tex]

[tex] :\implies\qquad\underline{\underline{\pmb{ \sf{h = 150mm}}} }[/tex]

For triangle ( c )

[tex] :\implies\qquad \sf{h^2 = b^2 + p^2 }[/tex]

[tex] :\implies\qquad \sf{ h=\sqrt{b^2 + p^2}}[/tex]

[tex] :\implies\qquad \sf{ h =\sqrt{(100)^2)+(50)^2}}[/tex]

[tex] :\implies\qquad \sf{ h=\sqrt{10000+2500}}[/tex]

[tex] :\implies\qquad \sf{ h =\sqrt{12500}}[/tex]

[tex] :\implies\qquad \underline{\underline{\pmb{\sf{h = 111.80mm}}} }[/tex]

Answers:

Hypotenuse of triangle ( a ) = 21.63 mm

Hypotenuse of triangle ( b ) = 150 mm

Hypotenuse of triangle ( c ) = 111.80 mm

Explanation :

find the length of hypotenuse in the given 3 triangles, which can be done by using Pythagoras theorem.

[tex]h^2 = b^2 + p^2[/tex]

And we have to convert the answer to the units indicated in red i.e, in mm.

Since 1cm = 10 mm, we will convert the given values of length of side in mm before putting the values in the formula

[tex]For \: \: triangle ( a )

\qquad \sf{ h^2 = b^2 + p^2}[/tex]

[tex]\qquad \sf{ h =\sqrt{b^2 + p^2}}[/tex][tex]\qquad \sf{h=\sqrt{ (12)^2 + (18)^2 }}[/tex][tex]\qquad\sf{h=\sqrt{ (12)^2 + (18)^2 }} \\ \\ \qquad \sf{ h= \sqrt{144 + 324}} \\ \\ \qquad \sf{ h = \sqrt{468}}

\\ \\\qquad\underline{\underline{\pmb{ \sf{ h = 21.63 mm}}}} \\ \\ For \: \: triangle ( b ) \qquad \sf{ h^2 = b^2 + p^2} \\ \\ \qquad \sf{h =\sqrt{b^2 + p^2} } \\ \\ \qquad \sf{ h = \sqrt{(90)^2+(120)^2}} \\ \\ \qquad \sf{ h=\sqrt{8100+14400}} \\ \\

\qquad \sf{ h =\sqrt{22500}} \\ \\\qquad\underline{\underline{\pmb{ \sf{h = 150mm}}} } \\ \\ For \: \: triangle ( c ) \qquad \sf{h^2 = b^2 + p^2 } \\ \\ \qquad \sf{ h=\sqrt{b^2 + p^2}} \\ \\\qquad\sf{ h=\sqrt{(100)^2)+(50)^2}} \\ \\\qquad\sf{ h=\sqrt{10000+2500}} \\ \\ \qquad \sf{ h =\sqrt{12500}} \\ \\

\qquad\underline{\underline{\pmb{\sf{h = 111.80mm}}} } [/tex]

please help with angle addition

Answers

Answer:

m∠1 = 89°

Step-by-step explanation:

Since m∠2 is a part of ∠GFH, he can do the following.

∠GFH - m∠2 = m∠1

133° - 44° = 89°

The photo is shown below, please help!

Answers

Answer/Explanation:

The formula for a rectangular prism is Length x Width x Height

With this information we can multiply 6x8x2 and get 96 ft³.

This is the volume of the original prism.

Doubling the dimensions means multiplying each side by 2.

The new dimensions would be a.16 b.4 c.12

Use the formula to find volume. 12x16x4=768

The volume of the enlarged prism is 768 feet³

For bonus question, divide 768 by 96.

The scale factor is 8.

Solve for m.
m/9 + 2/3 =7/3

Answers

Answer:

m= 15

Step-by-step explanation:

[tex] \frac{m}{9} + \frac{2}{3} = \frac{7}{3} [/tex]

To solve for m, start by moving the constants (numbers that are not attached to any variable) to the other side of the equation.

[tex] \frac{m}{9} = \frac{7}{3} - \frac{2}{3} [/tex]

Simplify:

[tex] \frac{m}{9} = \frac{5}{3} [/tex]

Multiply both sides by 9:

[tex]m = \frac{5}{3} \times 9[/tex]

Crossing out 3 from the denominator and from 9:

m= 5(3)

m= 15

Help!!! 8. Determine whether each pair of functions f and g are inverses. Explain your reasoning.

Answers

Answer:

I would say that a is NOT an inverse, however b is.

Step-by-step explanation:

If you look at the two tables for a, you can tell that every pair has swapped places (as they should) except 0 and 9. In which in the second table, what should be the 9 in the x row, is just another 0 in its place.

While if you look at the two tables for b, every single pair has been swapped like it should, meaning the second table is the inverse of the first table.

Hope this helps you btw. I'm sorry if it doesn't though.

Please Help!
In the diagram, secant AP intersects the circle at points A and B, and secant CP intersects the circle at points C and D. The lines intersect outside the circle at point P.
What is the length of AP?
(There are no answer options you must enter the correct value)

Answers

Answer AP might be 12

Step-by-step explanation:

The length of AP when secant AP intersects the circle at points A and B, and secant CP intersects the circle at points C and D. is 12 units.

The length of AP can be found using the following steps:

Draw a radius from the center of the circle to point P.

Let the radius intersect secant AP at point E.

Since AP and PE are secant segments, they share a common external tangent at point P.

Therefore, the two triangles, APE and BPF, are similar triangles.

The ratio of corresponding sides in similar triangles is equal, so:

AP/PB = PE/PF

We know that PB = 5 and PF = 20, so:

AP/5 = PE/20

Solving for AP, we get:

AP = 5 * 20/5 = 20

The diagram shows the two similar triangles, APE and BPF. The two triangles are similar because they share a common external tangent at point P. The ratio of corresponding sides in similar triangles is equal, so we can use the ratio of AP to PB to find the length of AP.

To learn more about length here:

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If you know the diameter of a circle,
how do you find the following. Explain
the steps clearly
a. the area of that circle?
b. the circumference of the circle?

Answers

Step-by-step explanation:

a. Area of a circle = πr², where r means radius.

Step 1: converted diameter to radius.

diameter = 2 radius

In other way of writing, radius = [tex]\frac{1}{2}[/tex] diameter.

Step 2: substitute radius into the formula.

Area of a circle = π([tex]\frac{1}{2}[/tex]d)²

Step 3: substitute π into the formula.

some question is given the value of π), if not substitute 3.14 for π.

Area of a circle = 3.14([tex]\frac{1}{2}[/tex]d)²

Step 4: substitute d into the formula, then we can solve its area.

b. a. Circumference of a circle = 2πr, where r means radius.

Step 1: converted diameter to radius.

diameter = 2 radius

In other way of writing, radius = [tex]\frac{1}{2}[/tex] diameter.

Step 2: substitute radius into the formula.

C = 2π([tex]\frac{1}{2}[/tex]d)

Step 3: substitute π into the formula.

some question is given the value of π), if not substitute 3.14 for π.

C = 2(3.14)([tex]\frac{1}{2}[/tex]d)

Step 4: substitute d into the formula, then we can solve its circumference.

In creating a new scale for the mercury thermometer, Anders Celsius initially set the boiling point of water at _____. A. 0° b. 32° c. 100° d. 273°.

Answers

The thermometer is a device that is used to measure the temperature gradient. Anders needs to set the boiling point of water at 100° C.

What is a thermometer?

The thermometer is a device that is used to measure the temperature gradient or the temperature of a body/object.

The boiling point of water is 100°C, therefore, Anders needs to set the boiling point of water at 100° C.

Thus, Anders needs to set the boiling point of water at 100° C.

Learn more about Thermometers:

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What is the simplified form of the following expression? 2 startroot 18 endroot 3 startroot 2 endroot startroot 162 endroot

Answers

The simplified form of the provided expression of 2 startroot 18 endroot +3 startroot 2 endroot startroot +162 endroot is 18√2.

What is the simplified form of an equation?

The simplified form of an equation is the simplest way of expressing the equation, by applying the required operations of mathematics.

The equation provided in the problem is,

[tex]2\sqrt{18}+3\sqrt{2}+\sqrt{162}[/tex]

Let the simplified form of the above expression is n. Thus,

[tex]n=2\sqrt{18}+3\sqrt{2}+\sqrt{162}[/tex]

Rewrite the equation to solve it further as,

[tex]n=2\sqrt{3\times3\times2}+3\sqrt{2}+\sqrt{9\times9\times2}\\n=2\sqrt{3^2\times2}+3\sqrt{2}+\sqrt{9^2\times2}[/tex]

The square of the term cancel out the square root of it. Thus,

[tex]n=2\times3\sqrt{2}+3\sqrt{2}+9\sqrt{2}\\n=6\sqrt{2}+3\sqrt{2}+9\sqrt{2}\\n=(6+3+9)\sqrt{2}\\n=18\sqrt{2}[/tex]

Thus, the simplified form of the provided expression of 2 startroot 18 endroot +3 startroot 2 endroot startroot +162 endroot is 18√2.