any two substances which are odourless​

Answer:

See explanation

Explanation:

Given that;

E = hc/λ

h = 6.63 * 10^-34 Js

c = 3 * 10^8 ms-1

λ = ?

E = 3.978 * 10^-19 J

λ = hc/E

λ = 6.63 * 10^-34 * 3 * 10^8 /3.978 * 10^-19

λ = 19.89 * 10^-26/3.978 * 10^-19

λ = 5 * 10^-7 m The colour is green

2. E = hc/λ

E=  6.63 * 10^-34 * 3 * 10^8 /1000 * 10^-9

E = 1.989 * 10^-19 J

But

E = hf

f = E/h

f =  1.989 * 10^-19/6.63 * 10^-34

f = 3 * 10^14 Hz The radiation is infrared

3. E = hc/λ

λ= hc/E

λ= 6.63 * 10^-34 *  3 * 10^8 /2.0 * 10^-14

λ= 995 * 10^-14 m This is gamma radiation

4. E = hc/λ

E=6.63 * 10^-34 *  3 * 10^8 /620 * 10^-9

E = 3.2 * 10^-19 J

5. E = hf

E= 6.63 * 10^-34 * 2 * 10^17

E = 1326 * 10^-19 J

E = hc/λ

λ= hc/E

λ= 6.63 * 10^-34 * 3 * 10^8 /1326 * 10^-19 = 15 * 10^-9

This is ultraviolet radiation

Answer:

Na sodium or Rb rubidium

Explanation:

Because Na is present in first group all members of group 1 have 1 electron in valence shell and show similar properties.

Answer:C. They can be produced easily in areas with geothermal activity.

D. The land can be used for other purposes while supplying energy.

Explanation:

Both c and d are correct

It is easier to switch to solar and wind energy as compared to other alternative energy sources because they can be produced easily in areas with geothermal activity and can be used for other purposes while supplying energy.

Solar energy is any type of energy generated by the sun. Solar energy can be harnessed directly or indirectly for human use.

Generating energy that produces no greenhouse gas emissions from fossil fuels and reduces some types of air pollution.

Diversifying energy supply and reducing dependence on imported fuels. Creating economic development and jobs in manufacturing, installation, and more.

Hence, options C and D are correct.

Learn more about the solar energy here:

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#SPJ2

Answer:

3

Explanation:

Answer:

Compound 1- ionic solid

Compound 2- can't really decide

Compound 3- molecular solid

Explanation:

An ionic solid has a very high melting point. It is hard but not brittle. It's solution or melt but not it's solid conducts electricity. Compound 1 is an ionic solid.

We can't really decide on compound 2 since it is brittle yet it's solution conducts electricity.

Lastly, compound 3 is a molecular solid since it has a low melting point.

Answer:

Compound 1- ionic solid

Compound 2- can't really decide

Compound 3- molecular solid

Explanation:

Answer:

true

.......................

Answer: You're Welcome!

Oh, It's False - Kinetic energy depends upon the speed of the object; potential energy depends upon the position of the object.

Answer:

C₃H₆ is an alkene

C₆H₁₂ is an alkene

C₈H₁₈ is an alkane

C₇H₁₂ is an alkyne

Explanation:

To determine which of the compound is alkane, alkene, or alkyne,we shall use the general formula of alkane, alkene, and alkyne. This is illustrated below:

General formula for alkane => CₙH₂ₙ₊₂

General formula for alkene => CₙH₂ₙ

General formula for alkyne => CₙH₂ₙ₋₂

For C₃H₆:

n = 3

Alkane => CₙH₂ₙ₊₂ => C₃H₂₍₃₎₊₂ => C₃H₈

Alkene => CₙH₂ₙ => C₃H₂₍₃₎ => C₃H₆

Alkyne => CₙH₂ₙ₋₂ => C₃H₂₍₃₎₋₂ => C₃H₄

Thus, C₃H₆ is an alkene

For C₆H₁₂:

n = 6

Alkane => CₙH₂ₙ₊₂ => C₆H₂₍₆₎₊₂ =>C₆H₁₄

Alkene => CₙH₂ₙ => C₆H₂₍₆₎ => C₆H₁₂

Alkyne => CₙH₂ₙ₋₂ => C₆H₂₍₆₎₋₂ => C₆H₁₀

Thus, C₆H₁₂ is an alkene

For C₈H₁₈:

n = 8

Alkane => CₙH₂ₙ₊₂ => C₈H₂₍₈₎₊₂ => C₈H₁₈

Alkene => CₙH₂ₙ => C₈H₂₍₈₎ => C₈H₁₆

Alkyne => CₙH₂ₙ₋₂ => C₈H₂₍₈₎₋₂ => C₈H₁₄

Thus, C₈H₁₈ is an alkane.

For C₇H₁₂:

n = 7

Alkane => CₙH₂ₙ₊₂ => C₇H₂₍₇₎₊₂ => C₇H₁₆

Alkene => CₙH₂ₙ => C₇H₂₍₇₎ => C₇H₁₄

Alkyne => CₙH₂ₙ₋₂ => C₇H₂₍₇₎₋₂ => C₇H₁₂

Thus, C₇H₁₂ is an alkyne.

SUMMARY:

C₃H₆ is an alkene

C₆H₁₂ is an alkene

C₈H₁₈ is an alkane

C₇H₁₂ is an alkyne

Answer:

Explanation:

H₃PO₄ + 3NaOH = Na₃PO₄ + 3 H₂O.

1 mole     3 mole

22.85 mL of the standardized 0.0995M NaOH solution will contain

.0995 x .02285 moles of NaOH

= 22.7357 x 10⁻⁴ moles of NaOH

3 moles of NaOH reacts with 1 mole of H₃PO₄

22.7357 x 10⁻⁴ moles of NaOH reacts with 1 x 22.7357 x 10⁻⁴  / 3 mole of H₃PO₄

= 7.5785 x 10⁻⁴ moles of H₃PO₄

7.5785 x 10⁻⁴ moles of H₃PO₄  is contained in 10 mL or 10⁻² L

molarity of H₃PO₄ solution = 7.5785 x 10⁻⁴ / 10⁻²

= 7.58 x 10⁻² M

= .0758 M .

The original concentration : 800%

Given

Diluted 1/40

Final concentration 20%

Required

The original concentration

Solution

Dilution is the process of adding solvent to get a more dilute solution.

The moles(n) before and after dilution are the same.

Can be formulated :

 n₁ = n₂

M₁.V₁ = M₂.V₂

diluted 1/40(dilution factor)⇒ V₁/V₂=1/40⇒V₂/V₁=40

M₂ = 0.2(20%)

Input the value for M₁ :

M₁=M₂ x (V₂/V₁)

M₁ = 0.2 x 40

M₂ = 8(800%)

=

Answer:

B) separation by boiling points

Explanation:

According to the diagram depicted, crude oil is separated into its different units using boiling points.

H2O as an oxidant only

Given

Reaction

2 Na + 2 H2O → 2 NaOH + H2

Required

The function of water in the equation

Solution

Water : oxidizing agent

Na : reducing agent

Na⁰ → Na⁺ (oxidation)

H⁺- → H⁰ (reduction)

Acids and bases according to Bronsted-Lowry

Acid = donor (donor) proton (H⁺ ion)

Base = proton (receiver) acceptor (H⁺ ion)

If water is acting as an acid it should only give 1 H +, so that becomes:

H₂O (l) ⇔ OH⁻ (aq) not H₂

Answer:

Comvection

Explanation:

The movement causes the density to rise and therefore transfer more heat

Answer:

Cu    +    2AgNO₃  →   2Ag    +    Cu(NO₃)₂

Explanation:

The reactants are:

         Copper metal  = Cu

         Silver nitrate  = AgNO₃

The products are:

          Silver metal  = Ag

           Copper (II) nitrate  = Cu(NO₃)₂

So, the reaction equation is given as;

      Cu    +    2AgNO₃  →   2Ag    +    Cu(NO₃)₂

This is a single displacement reaction

Answer:

Calcium

Explanation:

The symbol for the element with a mass number of 27 is actually Al for Aluminum instead of Co for Cobalt. Mass number refers to atomic mass, not atomic number.

Aluminum has an atomic mass of 26.982 or 27.

The letters to unscramble are I, M, C, Al, U, and C.

The mystery element is Calcium.

Hope that helps.

Answer:

One electron per single hydrogen atom.

Explanation:

Hello!

In this case, given the reaction:

[tex]H_2+O_2\rightarrow H_2O[/tex]

Whereas we can identify the following half-reaction for hydrogen:

[tex]H_2^0\rightarrow H_2^+[/tex]

Whereas we see that each single hydrogen atom gains one electron in order to go from 0 to +1, which is also related to an oxidation half-reaction.

Best regards!

Answer:

Therefore, the specific heat capacity of the iron is 0.567J/g.°C.

Note: The question is incomplete. The complete question is given as follows:

A 59.1 g sample of iron is put into a calorimeter (see sketch attached) that contains 100.0 g of water. The iron sample starts off at 85.0 °C and the temperature of the water starts off at 23.0 °C. When the temperature of the water stops changing it's 27.6 °C. The pressure remains constant at 1 atm.

Calculate the specific heat capacity of iron according to this experiment. Be sure your answer is rounded to the correct number of significant digits

Explanation:

Using the formula of heat, Q = mc∆T  

where Q = heat energy (Joules, J), m = mass of a substance (g)

c = specific heat capacity (J/g∙°C), ∆T = change in temperature (°C)

When the hot iron is placed in the water, the temperature of the iron and water attains equilibrium when the temperature stops changing at 27.6 °C. Since it is assumed that heat exchange occurs only between the iron metal and water; Heat lost by Iron = Heat gained by water

mass of iron  = 59.1 g, c = ?, Tinitial = 85.0 °C, Tfinal = 27.6 °C

∆T = 85.0 °C - 27.6 °C = 57.4 °C

mass of water = 100.0 g, c = 4.184 J/g∙°C, Tinitial = 23.0 °C, Tfinal = 27.6 °C

∆T = 27.6°C - 23.0°C = 4.6 °C

Substituting the values above in the equation; Heat lost by Iron = Heat gained by water

59.1 g * c * 57.4 °C  = 100.0 g * 4.184 J/g.°C * 4.6 °C

c = 0.567 J/g.°C

Therefore, the specific heat capacity of the iron is 0.567 J/g.°C.

Answer:

Incomplete combustion produces carbon monoxide (CO), a toxic gas.

Explanation:

Combustion is the rapid chemical reaction of oxygen in the air or direct oxygen, which is defined as oxidizer, with the different elements that make up the fuel (mainly carbon (C) and hydrogen (H)). These chemical reactions release energy producing local increases in temperature, which causes a flow of heat to the outside.

In other words, on the one hand you have the fuel, which is the substance that oxidizes and that you can find in a solid, liquid or gaseous state and which is made up mostly of carbon and hydrogen.

The oxidizer, for its part, is the substance that oxidizes the fuel, and it is generally the oxygen found in the air.

Certain amounts of oxidizer and fuel must come into contact for combustion to occur.

Incomplete combustion occurs when part of the fuel does not fully react. Incomplete combustion produces carbon monoxide (CO), a toxic gas.

Answer:

Pressure is often defined as a measure of force applied on an area, or over a unit area.

Explanation:

Answer:

The manner in which objects will move is determined by the answer to this question. Unbalanced forces will cause objects to change their state of motion

Explanation:

Since these two forces are of equal magnitude and in opposite directions, they balance each other.

Answer:

balance force are those force whose resultant force is zero and unbalanced force are those whose resultant are non zero

Answer:

a solution color becoming less intense  due to dilution- is not an evidence of a chemical reaction

bubbles (gas formation) - evidence of a chemical reaction

explosion or fire - evidence of a chemical reaction

changes in color- evidence of a chemical reaction

precipitation- evidence of a chemical reaction

changes in temperature - evidence of a chemical reaction

a solid liquifying - is not an evidence of a chemical reaction

solution colors mixing - is not an evidence of a chemical reaction

Explanation:

A chemical change is not easily reversible and yields new substances. It is often accompanied by a loss or gain of heat.

In the answer section, i have shown some evidences that lead us to conclude that a chemical reaction has taken place. The occurrence of a chemical change often goes with the formation of new substances as earlier stated and any of these signs may accompany the process.

For instance, when a metal is dropped in dilute acid solution, bubble of hydrogen gas indicates that a chemical reaction has taken place.

Answer:

Gravitational force between two objects depends on: a. The weight of the objects c. The mass of each object b. The distance between the objects d. Both b and c Please select the best answer from the choices provided A B C D

✓d

Which of the statements about liquids and gases are true?

The particles in liquids and gases can move past one another freely.

Which of the statements about liquids and gases are true?

Both liquids and gases have a definite volume.

The particles in liquids and gases can move past one another freely

Both liquids and gases have a definite shape.

Neither liquids nor gases have a definite shape.

The particles in liquids and gases can move past one another freely.

Answer:

Introduction

As a diligent student of chemistry, you will likely encounter tons of reactions that occur in aqueous solution (perhaps you are already drowning in them!). When ions are involved in a reaction, the equation for the reaction can be written with various levels of detail. Depending on which part of the reaction you are interested in, you might write a molecular, complete ionic, or net ionic equation.

Definitions of molecular, complete ionic, and net ionic equations

A molecular equation is sometimes simply called a balanced equation. In a molecular equation, any ionic compounds or acids are represented as neutral compounds using their chemical formulas. The state of each substance is indicated in parentheses after the formula. [Huh?]

Let's consider the reaction that occurs between \text{AgNO}_3AgNO

3

​

start text, A, g, N, O, end text, start subscript, 3, end subscript and \text{NaCl}NaClstart text, N, a, C, l, end text. When aqueous solutions of \text{AgNO}_3AgNO

3

​

start text, A, g, N, O, end text, start subscript, 3, end subscript and \text{NaCl}NaClstart text, N, a, C, l, end text are mixed, solid \text{AgCl}AgClstart text, A, g, C, l, end text and aqueous \text{NaNO}_3NaNO

3

​

start text, N, a, N, O, end text, start subscript, 3, end subscript are formed. Using this information, we can write a balanced molecular equation for the reaction:

\text{AgNO}_3(aq) + \text{NaCl}(aq) \rightarrow \text{AgCl}(s) + \text{NaNO}_3(aq)AgNO

3

​

(aq)+NaCl(aq)→AgCl(s)+NaNO

3

​

(aq)start text, A, g, N, O, end text, start subscript, 3, end subscript, left parenthesis, a, q, right parenthesis, plus, start text, N, a, C, l, end text, left parenthesis, a, q, right parenthesis, right arrow, start text, A, g, C, l, end text, left parenthesis, s, right parenthesis, plus, start text, N, a, N, O, end text, start subscript, 3, end subscript, left parenthesis, a, q, right parenthesis

[What kind of reaction is this?]

If we could zoom in on the contents of the reaction beaker, though, we wouldn't find actual molecules of \text{AgNO}_3AgNO

3

​

start text, A, g, N, O, end text, start subscript, 3, end subscript, \text{NaCl}NaClstart text, N, a, C, l, end text, or \text{NaNO}_3NaNO

3

​

start text, N, a, N, O, end text, start subscript, 3, end subscript. Since \text{AgNO}_3AgNO

3

​

start text, A, g, N, O, end text, start subscript, 3, end subscript, \text{NaCl}NaClstart text, N, a, C, l, end text, and \text{NaNO}_3NaNO

3

​

start text, N, a, N, O, end text, start subscript, 3, end subscript are soluble ionic compounds, they dissociate into their constituent ions in water. For example, \text{NaCl}NaClstart text, N, a, C, l, end text dissociates into one ion of \text{Na}^+Na

+

start text, N, a, end text, start superscript, plus, end superscript for every ion of \text{Cl}^-Cl

−

start text, C, l, end text, start superscript, minus, end superscript; these ions are stabilized by ion-dipole interactions with the surrounding water molecules. [I don't get it!]

Image of crystalline sodium chloride next to image of chloride and sodium ions dissociated in water. Each chloride ion is interacting with multiple water molecules through the positive dipole of the water, and each sodium ion is interacting with water molecules through the negative dipole of the water.

Image of crystalline sodium chloride next to image of chloride and sodium ions dissociated in water. Each chloride ion is interacting with multiple water molecules through the positive dipole of the water, and each sodium ion is interacting with water molecules through the negative dipole of the water.

Sodium chloride dissociates into sodium and chloride ions in water, and these ions become solvated by the highly polar water molecules. Image credit: "Salts: Figure 1" by OpenStax Anatomy and Physiology, CC-BY-NC-SA 4.0.

From the molecular formula, we can rewrite the soluble ionic compounds as dissociated ions to get the complete ionic equation:

\text{Ag}^+(aq) + \blueD{{\text{NO}_3}^-(aq)} + \maroonD{\text{Na}^+(aq)} + \text{Cl}^-(aq) \rightarrow \text{AgCl}(s) + \maroonD{\text{Na}^+(aq)} + \blueD{{\text{NO}_3}^- (aq)}Ag

+

(aq)+NO

3

​

−

(aq)+Na

+

(aq)+Cl

−

(aq)→AgCl(s)+Na

+

(aq)+NO

3

​

−

​

−

(aq)

​

+

Na

+

(aq)

​

+Cl

−

(aq)→AgCl(s)+

Na

+

(aq)

​

+

NO

3

​

−

(aq)

​

Answer: a) [tex]1.7\times 10^{-4}[/tex]

b) [tex]3.4\times 10^{-4}[/tex]

Explanation:

The reaction is :

[tex]2N_2O_5(g)\rightarrow 4NO_2(g)+O_2(g)[/tex]

Rate = Rate of disappearance of [tex]N_2O_5[/tex] = Rate of appearance of [tex]NO_2[/tex]

Rate =  [tex]-\frac{d[N_2O_5]}{2dt}[/tex] = [tex]\frac{d[NO_2]}{4dt}[/tex]

Rate of disappearance of [tex]N_2O_5[/tex] = [tex]\frac{\text {change in concentration}}{time}[/tex] = [tex]\frac{0.100-0.066}{200-0}=1.7\times 10^{-4}[/tex]

a) Rate of disappearance of [tex]N_2O_5[/tex] = [tex]-\frac{d[N_2O_5]}{2dt}[/tex]

Rate of appearance of [tex]NO_2[/tex] = [tex]\frac{d[NO_2]}{4dt}[/tex]

b) Rate of appearance of [tex]NO_2[/tex] =  [tex]\frac{d[NO_2]}{dt}=2\times 1.7\times 10^{-4}}=3.4\times 10^{-4}[/tex]

A) Find the rate of disappearance of [tex]N_2O_5[/tex] from t = 0 s to t = 200s

[tex]Rate = \frac{1}{2}(\frac{-\delta N_2O_5}{\delta t})\\\\Rate = -\frac{1}{2}(\frac{0.066 - 0.100}{200 - 0})\\\\Rate = 8.5*10^{-5}[/tex]

B) Find the rate of appearance of [tex]NO_2[/tex] from t = 0 s to t = 200s

According to rate law,

[tex]\frac{1}{2}(\frac{-\delta N_2O_5}{\delta t}) = \frac{1}{4}(\frac{\delta NO_2}{\delta t})\\\\8.5*10^{-5} = \frac{1}{4}(\frac{\delta NO_2}{\delta t})\\\\\frac{\delta NO_2}{\delta t} = 4 * 8.5*10^{-5}\\\\Rate = 3.4*10^{-4}[/tex]

For more information on rate of disappearance

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Answer:

1: false

2: B

Explanation:

I do not know the 3rd one

Answer:

yes because of fluorine has higher electronegativity