An old 0.500 L lecture bottle of triethylamine (N(CH₂CH₃)₃) was found in a lab and needed for a synthesis reaction. A pressure regulator indicated a pressure of 27.0 psi, and the lab was at room temperature (25.0°C). What mass of vaporized triethylamine in grams was left in the lecture bottle?

Answers

Answer 1

Answer:

About 3.81 grams.

Explanation:

We can use the ideal gas law. Recall that:

[tex]\displaystyle PV = nRT[/tex]

Note that the universal gas constant R has the value 0.08206 L-atm/mol-K.

Hence, convert the measured pressure to atms (1 atm = 14.7 psi):

[tex]\displaystyle 27.0\text{ psi} \cdot \frac{1\text{ atm}}{14.7\text{ psi}} = 1.84\text{ atm}[/tex]

Rearrange the equation to solve for n, the number of moles of vaporized triethylamine and evaluate. The temperature is (25.0 + 273.15 ) K = 298.2 K:

[tex]\displaystyle \begin{aligned} n& = \frac{PV}{RT} \\ \\ & = \frac{(1.84\text{ atm})(0.500\text{ L})}{\left(\dfrac{0.08206\text{ L - atm}}{\text{mol-K}}\right)(273.2\text{ K})} \\ \\ &= 0.0376\text{ mol N(CH$_2$CH$_3$)$_3$}\end{aligned}[/tex]

Convert from moles to grams:

[tex]\displaystyle 0.0376\text{ mol N(CH$_2$CH$_3$)$_3$} \cdot \frac{101.22\text{ g N(CH$_2$CH$_3$)$_3$}}{1\text{ mol N(CH$_2$CH$_3$)$_3$}} = 3.81\text{ g N(CH$_2$CH$_3$)$_3$}}[/tex]

In conclusion, there is about 3.81 grams of vaporized triethylamine in the lecture bottle.


Related Questions

Hello, do these calculations using table 1 look correct? Thank you

Table 1.
Sugar (Sucrose) Data
Mass of unchewed gum 3.7 (g)
Mass of chewed gum 2.0 (g)
Mass of sugar 1.7 (g)
Percent sugar
46%

Post-Lab Questions
1. What is the percent sugar? Show your calculations.
mass of sugar (1.7) ÷ mass of unchewed gum ( 3.7) × 100 = 45.94 (46%)
2. What is the molar mass of sugar (sucrose, C12H22O11)? Show your calculations.
C=12×12=144
H=1×22=22
O=16×11=176
To get the molar mass of the entire compound you, 144 + 22 + 176 = 342 g/mol
3. Convert the mass of dissolved sugar to moles. Show your calculations.
1.7 g ÷ 342 g/mol = 0.00497 moles
4. Convert the moles of sugar to molecules of sugar. Show your calculations.
0.00497 mole × 6.022 × 10^23 = 2.992934 × 10^21 molecules
5. Imagine that you used four pieces of gum instead of two. Calculate the number of moles. Show your calculations.
In theory, assuming the sticks of gum were exactly the same mass and sugar content, the moles would double.
2 ÷ 342 g/mol × 1.7 = 0.00994 moles
6. How does the mass of the saliva alter the experimental data?
It is impossible to blot off all the saliva with a paper towel because the gum sticks to the paper, so it adds more mass to the chewed gum and therefore alters the amount and percent of sugar calculations.

Answers

Answer:

yes it does look correct. good job.

Post- lab the percent sugar 46%, and the molar mass of sugar is 342 g/mol,  the mass of dissolved sugar to moles is 0.00497 moles of sugar to molecules of sugar is  2.992934 × 10^21 molecules, assuming the sticks of gum were exactly the same mass and sugar content, the moles would double  0.00994 moles.

What are moles?

moles is the unit of the molecule and it is defined as the number of molecules participating in a chemical reaction and value of one mole is equal to Avogadro constant that is 2.303 × 10²³

Sugar percentage = mass of sugar / mass of gum × 100  = 1.7 / 3.7 × 100 =  45.94 (46%)

Molar mass of sugar = C12H22O11 = C=12×12=144 + H=1×22=22  + O=16×11=176 = 342 g/mol  

Mass of dissolved sugar to moles = 1.7 g ÷ 342 g/mol = 0.00497 moles

The moles of sugar to molecules of sugar = 0.00497 mole × 6.022 × 10^23 = 2.992934 × 10^21 moleculesIn the given theory using four pieces of gum will exactly be the same to the mass of sugar.2 ÷ 342 g/mol × 1.7 = 0.00994 moles

The mass of the saliva alter the experimental data because it is not possible to remove all the saliva from the surface as it gets stick to the paper which changes the amount of sugar.

Therefore, the percent sugar 46%, and the molar mass of sugar is 342 g/mol, the mass of dissolved sugar to moles is 0.00497 moles of sugar to molecules of sugar is  2.992934 × 10^21 molecules, assuming the sticks of gum were exactly the same mass and sugar content, the moles would double  0.00994 moles.

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Which characteristic do all owl families share? A.) small eyes B.) large body size C.) nighttime hunting D.) heart-shaped faces

Need this answer in 5 MINUTES!
If any turtors are out there I need a Verified answer

Answers

Heart-shaped faces is the characteristic all owl families share and it is denoted as option D.

What is an Owl?

This is a type of bird which is known for its heart shaped face, big round eyes and reversible toe.

This animal has majority of its species as night time hunters which is why option D was chosen.

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dk how to do this :)

Answers

Answer:

2Mg, 2 02, MgO

find the molarity of 131 g Ba(NO3)2 dissolved in 750.0 water

Answers

Answer:

6.68 x 10^-4

Explanation:

131g ÷ 261.337g/mol = 0.5012685 moles

0.5012685 moles ÷ 750.0 liters =

0.5012685÷ 750.0=0.000668358

6.68 x 10^-4

Giving Brainliest

Which choice is an example of the use of sound energy in everyday life?

batteries powering toys

fireplaces keeping people warm

lights helping people see

car horns preventing accidents

Answers

Answer:

car horn preventing accidents

Answer:

d) car horns preventing accidents

Explanation:

the use of car horns represents sound energy in everyday life. batteries use chemical energy that is turned into electrical energy, fireplaces use thermal energy, and lights use electrical energy!

3. Arrange the following according to increasing acid strength
(i) Ka= 2.5 + 10-15
(ii) Ka= 9.0 + 10-9
(iii) pKa= 7.5
(iv) % dissociation =100
(a) iv, iii, ii, i
(b) ii, I, iii, iv
(c) i, iii, iv, ii
(d) i, ii, iii, iv
(e) iii, iv, ii, i

Answers

Answer:

3. Arrange the following according to increasing acid strength (i) Ka=2.5x 10-10 (ii) Ka=9.0x108 (iii)pKa= 7.5 (iv)% dissociation -100 (a) iv, iii, ii, i (b) ii, 1, iii, iv (c) i, iii, iv, ii (d)i, ii, iii, iv (e) iii, iv, ii, i

5. Consider the buffer NH/NH.Cl. If one wants to prepare 250.0mL of this buffer at pH 4.0. Is it possible to achieve one's sim? (a) yes (b) no 6. If the pH of the buffer in (5) above would be 9.0, the ratio of NH/NH.Cl required for the preparation, considering I Liter of buffer, is (a) 1.80 (b) 0.56 (c) 4.26 (d) 1.82 x 10: (e) K, (NH -1.8x109)

Explanation:

How many milliliters of a 1 M nitric acid solution are required to prepare 60 mL of 0.15 M solution?
Select the correct answer below:
400 mL
O 9 mL
O 0.25 mL
none of the above

Answers

9 mL
Explaination:
V1= m2*v2/m1 = 60 x 0.15 /1 = 9 mL

9 mL of a 1 M nitric acid solution are required to prepare 60 mL of 0.15 M solution. Therefore, the correct option is option A.

What is volume?

A measurement of three-dimensional space is volume. It is frequently expressed quantitatively using SI-derived units, as well as several imperial or US-standard units. Volume and the notion of length are connected. A container's capacity is typically thought of as being represented by its volume.

Rather considering how much space the container takes up, think about how much fluid it could hold. Volume was initially measured using naturally occurring vessels of a comparable shape and then with standardised containers. Arithmetic formulas can be used to quickly calculate the volume of several straightforward three-dimensional shapes.

V1= m2×v2/m1 = 60 x 0.15 /1 = 9 mL

Therefore, the correct option is option A.

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Use this equation: N2 + 3H2 → 2NH3, for the following problems:

1. If 2.5 moles of N2 react, how many grams of NH3 can be produced?




2. If 10.0 moles of NH3 are produced, how many grams of H2 would be required?




Use this equation: B2O3 + 3Mg → 3MgO + 2B, for the following problems:

3. How many grams of boron can be obtained from 8 moles of B2O3?




4. How many grams of magnesium are required to produce 4 moles of boron?




Use this equation: S8 + 12O2 → 8SO3, for the following problems:

5. How many grams of oxygen is needed to produce 7.5 moles of sulfur trioxide?




6. How many grams of sulfur trioxide can be produced from 2 moles of octasulfur?

Answers

Answer:hop this helps

Explanation:

describe the arrangement of the 118 elements in the periodic table how is it arrange?

Answers

The periodiC table is organized By molar mass

Which of the following is most likely to lose electrons in an ionic compound?

a. lead (Pb)

b. carbon (C)

C. oxygen (O)

d. hydrogen (H)

Answers

Answer:

a. Lead (Pb)

Am 100% sure

Hope it helps

please mark me as brainliest

Hydrogen has a melting point of -259 °C, and a boiling point of -253 °C. Its density at liquid state is 0.07 g/cm³. What is the physical state of Hydrogen at -250 °C? Explain your answer.

Answers

Answer:

Explanation:

Remark

-250, if you can believe it, is actually warmer than - 253. At -250 the hydrogen has gone through a phase change (a phase change means that it has gone  from a liquid to a gas).

From here on as far as you are concerned, the hydrogen will stay as a gas. Later on, if all other things remain constant, you will learn that hydrogen can do some very strange things.

Please help!

A molecule that is either cycloheptane or cycloheptene is treated with bromine and the sample immediately absorbs the red bromine color—which compound is present?

Answers

The compound that is most likely present when treated with bromine and the sample absorbs the red bromine color is ; Cycloheptene

What is cycloheptene

Cycloheptene is an unsaturated colorless oily liquid which is insoluble in water it absorbs Bromine when used in performing unsaturation test due it unsaturated nature.

The red bromine color will be absorbed when used to treat Cycloheptene but will not be absorbed when used to treat cycloheptane due to its saturated nature.  

Hence we can conclude that the compound that is present is Cycloheptene.

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An alkyne with the molecular formula C6H10 was reduced with H2 and Lindlar's catalyst. Ozonolysis of the resulting alkene afforded formaldehyde and an unbranched aldehyde. What is the IUPAC name of the alkyne that was reduced?

Answers

Given that the alkyne has a formula as C₆H₁₀, the IUPAC name of the alkyne is hexyne

What is an alkyne?

Alkynes are unsaturated hydcarbons with the general formula of CₙH₂ₙ₋₂. They contains triple bonds (C≡C) in the carbon chains. The simplest member of this family is ethyne (C₂H₂)

The first nine members of the Alkynes sre:

Ethyne, C₂H₂Propyne, C₃H₄ Butyne, C₄H₆ Pentyne, C₅H₈Hexyne, C₆H₁₀Heptyne, C₇H₁₂Octyne, C₈H₁₄Nonyne, C₉H₁₆Decyne, C₁₀H₁₈

Considering the question given above, the formula of the alkyne is C₆H₁₀.

Therefore, the name of the alkyne is hexyne

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What is the pressure exerted by a force of 14.7 N over an area of 0.00482 m²?

Answers

Answer:

[tex]p= \frac{F}{A} = \frac{ 14.7 }{0.00482} = 3050 \: Pa[/tex]

6. How many molecules of ammonia are present in 34 g of ammonia (Formula = NH3)?

Answers

12.044*10^23, because 1 mole is 6.022*10^23

Balance the equation for a half-reaction that occurs in acidic solution. Use e− as the symbol for an electron.

MnO_{4}^{-} -> MnO_{2}

Answers

The balanced half reaction equation is MnO4^- + 4H^+ ------>MnO2 + 2H2O + 3e

What is a redox reaction?

The term redox reaction has to do with a reaction in which there is a loss or  gain of electrons. In this reaction, one specie accepts electrons while another specie looses electrons.

The balanced half reaction equation in acid is; MnO4^- + 4H^+ ------>MnO2 + 2H2O + 3e

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20 L of nitrogen gas are collected at a temperature of 50°C and 2 atm. How many grams of nitrogen gas were collected? A.21.1 g B.29.6 C.42.3 g D.59.2

Answers

Taking into account the Ideal Gas Law, the mass of nitrogen gas collected is 21.1 grams.

Ideal Gas Law

Ideal gases are a simplification of real gases that is done to study them more easily. It is considered to be formed by point particles, do not interact with each other and move randomly. It is also considered that the molecules of an ideal gas, in themselves, do not occupy any volume.

An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of gases:

P×V = n×R×T

Mass of nitrogen

In this case, you know:

P= 2 atmV= 20 Ln= ?R= 0.082 [tex]\frac{atm L}{molK}[/tex]T= 50 °C= 323 K (being 0°C= 273 K)

Replacing in the ideal gas law:

2 atm ×20 L = n×0.082 [tex]\frac{atm L}{molK}[/tex] ×323 K

Solving:

n= (2 atm ×20 L) ÷(0.082 [tex]\frac{atm L}{molK}[/tex] ×323 K)

n= 1.51 moles

Being the molar mass of nitrogen 14 g/mole, that is the amount of mass that a substance contains in one mole, the mass of nitrogen gas collected is calculated as:

[tex]mass of nitrogen gas=1.51 molesx\frac{14 grams}{1 mole}[/tex]

mass of nitrogen gas= 21.1 grams

Finally, the correct answer is option A.: the mass of nitrogen gas collected is 21.1 grams.

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calculate the pressure in atmospheres of 1.92 moles of helium gas in a 10.0L container at 25C

Answers

The pressure in atmospheres of the given mole and volume of helium gas is 4.7atm.

Given the data in the question;

Amount of helium; [tex]n = 1.92mol[/tex]Volume of the gas; [tex]V = 10.0L[/tex]Temperature; [tex]T = 25^0C = 298.15K[/tex]

Pressure in atmosphere; [tex]P = \ ?[/tex]

Ideal Gas Law

The Ideal gas law emphasizes on the behavior of a hypothetical ideal gas. It states that pressure P multiply by volume V is equal to moles times temperature and the universal gas constant.

It is expressed;

[tex]PV = nRT[/tex]

Where P is pressure, V is volume, n is the amount of substance, T is temperature and R is the ideal gas constant.( [tex]R = 0.08206Latm/molK[/tex] ).

To determine the pressure in atmosphere, we substitute our values into the expression above.

[tex]PV = nRT\\\\P = \frac{nRT}{V} \\\\P = \frac{1.92mol\ *\ 0.08206Latm/molK\ *\ 298.15K}{10.0L} \\\\P = \frac{46.975Latm}{10.0L}\\\\P = 4.7atm[/tex]

Therefore, the pressure in atmospheres of the given mole and volume of helium gas is 4.7atm.

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what does SPDF Blocks represent on the periodic table?

Answers

Answer:

SPDF blocks represents the last electron of particular element entering into valance subshell.

example: oxygen is p block element because (1s2, 2s2 2p4) its last electron is in p block

A block of the periodic table is unified by the atomic orbitals in which valence electrons lie in.

What is the block in the periodic table?

A block can be described as a set of elements in which the valence electrons lie in atomic orbitals. Each block in the periodic table is named after its characteristic orbital: s-block, p-block, d-block, and f-block.

The block names (s, p, d, and f) are derived from the value of an electron's azimuthal quantum number: sharp (0), principal (1), diffuse (2), and fundamental (3).

The s-block, where 's' stands for "sharp" and azimuthal quantum number 0, is on the left side of the periodic table. The p-block, where 'p' stands for "principal" and azimuthal quantum number 1, is on the right side of the modern periodic table and elements in groups 13 to 18.

The d-block, where 'd' stands for "diffuse" and azimuthal quantum number 2, is in the middle of the periodic table and elements from groups 3 to 12.

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How moles of Cl' are in a 45 mL of 1,4 M solution of NaCl?

Answers

Answer:

.063 moles Cl-

Explanation:

To find moles multiply molarity by volume.

1.4*.045=.063 moles Cl-

When salt is added to water, what happens to the molecules?
The water molecules remain together. The salt molecules break apart.
Water and salt molecules remain together.
The water molecules break apart. The salt molecules remain together.
Water and salt molecules break apart.

Answers

Answer:

The the salt dissolves

Explanation:

The salt dissolves because the covalent bonds of water are stronger than the ionic bonds in the salt molecules.

What is the product of radioactive decay 0/-1 e called?
A. An alpha particle
B. A beta particle
C. Nuclear fission
D. A gamma wave

Answers

Answer:

it represents a beta particle so the answer is B a beta particle

Answer:

The product of radioactive decay ⁰-₁e called a beta particle

B. A beta particle

The release of aluminium ions as a result of acid rain is less significant in areas containing limestone rock - why?

Answers

Answer:

As it flows through the soil, acidic rain water can leach aluminum from soil clay particles and then flow into streams and lakes. The more acid that is introduced to the ecosystem, the more aluminum is released. Some types of plants and animals are able to tolerate acidic waters and moderate amounts of aluminum

Explanation:

Which action would shift this reaction away from solid silver chloride and toward the dissolved ions

Answers

removing chloride ion is the reaction away

an organisms particular role in its habitat,or when and how it survives, is called its

Answers

Answer:

Niche.

A niche is a place where an organism lives at a given time or how the organism lives there.

Based upon the chemical equation in #2 above, if 45.7g C2H4O2 are used in the reaction, how many grams of H2O will result

Answers

calcium chloride and carbon dioxide

What does an electrostatic force do?
A. An electrostatic force attracts oppositely charged particles.
B. An electrostatic force holds particles together by sharing
electrons.
C. An electrostatic force holds particles of the same charge together.
D. An electrostatic force attracts particles via gravitational pull.

Answers

Answer:

A.

Explanation:

Opposite charged particles attract.

Particles of same charge are repelled.

Answer:

attracts opposites (a)

Explanation:

The Molar mass of silicon is 28.09 grams/mole

Calculate the number of atoms in a 92.8 mg sample of silicon
Write your answer in scientific notation using three significant figures

Answers

1. Set up conversion factors.
92.8 mg x 1 g/10^3 mg x 1 mol/28.09 g x 6.022x10^23 atoms/1 mol

2. Cancel units.
1.99 x 10^21 Si atoms

use the kinetic theory to explain why a windy day is a good drying day?​

Answers

Explanation:

Wind helps to get out molecules of water from clothes.

In summer Ball is hard b because due to heat kinetic energy of molecules increases

Evaporation increases with increase in wind speed. With the increase in wind speed, the particles of water vapour move away with the wind, decreasing the amount of water vapour in the surrounding. Hence, clothes dry faster on a windy day.

About how many centimeters will make an inch?
A)5
B)2+
C) 200
D)10

Answers

Answer: B) 2+

Explanation:

   There are exactly 2.54 centimeters in an inch, the closest option is:

B) 2+

Answer:

2.54 centimetres

Explanation:

Ur options are wrong

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