From the first floor to the fourth floor, the elevator's net work during the entire trip is -3mgh.
Given,
On the first floor of a building, an elevator with mass m is initially at rest. It ascends at a constant speed, passing second and third floors before coming to a stop at the fourth floor.
the separation between the floors is h
The distance from the first floor to the fourth floor Equals 3 hours of work = -mg(3 hours)
= -3mgh
Work Done = -3mgh
Learn more about Work done here:
https://brainly.com/question/13662169
#SPJ4
a baseball player exerts a force of 100n on a ball for a distance of 0.5m as he throws it. if the ball has a mass of 0.15kg, what is its velocity as it leaves his hand?
the magnetic field of a long, straight wire has a value b0 at a distance of r0 when the current is i0. at a distance of 3.00 r0. what current is necessary to produce a field having the same strength b0 at this position?
The magnetic field of a long straight wire has a board b0 at a distance r0 when the cutting edge is i0. at a distance of 3.00 r0: B'=2B0.
A magnetic field is a vector domain that describes the magnetic effect on moving electricity costs, currents, and magnetic materials. Transfer fees in magnetic fields are under pressure perpendicular to personal speed and magnetic fields.
The magnetic field is the place around the magnet where the effect of the magnetism is felt. We use magnetic fields as tools to explain how magnetic forces are directed into circular space and are essentially magnetic. This force attracts or repels magnets to each other. Examples of magnetic forces include compasses, motors, magnets that keep things in refrigerators, learning tracks, and new roller coasters. All the carrying charges create a magnetic field, and the charges flowing through that area enjoy the force.
Learn more about the magnetic field here:
https://brainly.com/question/14411049
#SPJ4
Kinetic theory told us that gas particles are moving constantly and bumping into anything in their path. The collisions of these particles in the gas result in ___________ .
a
Energy conversion
b
Pressure
c
Creation of new forms of matter
d
Potential energy
Answer:
a
Explanation:
because if gas particles move they move with speed and that is because they are free,so when they bump into something,they bump into it with force so it converts the energy
10 N of force is applied to a spring and its length increases by 4 cm. If the spring is obeying Hooke's law, what will its extension be if 30 N of force is applied?
I think Twelve is the answer
a car is traveling at 100 mph down the highway. at some time the driver sees an obstruction in the road and slams on the brakes skidding to a halt reducing its kinetic energy to zero. what happened to the kinetic energy of the car?
The kinetic energy is changed to thermal energy by brake friction and turns to zero.
We need to know about kinetic energy to solve this problem. Kinetic energy is the energy from a moving object. It can be determined as
KE = 1/2 . m . v²
where KE is kinetic energy, m is mass and v is speed.
From the question above, we know that
v1 = 100 mph
KE2 = 0 joule
When the car moves at 100 mph, the car has kinetic energy. But on the way when the driver brakes the car, the kinetic energy is changed to thermal energy by brake friction. Hence, the kinetic energy is reduced every time and finally turns to zero.
Find more on kinetic energy at: https://brainly.com/question/25959744
#SPJ4
A child boards a bus for summer camp. His mom is waiting next to the bus. The bus begins
moving 3 m/s east with respect to the ground. The child is walking 0.5 m/s west towards the back
of the bus with respect to the bus. The mother begins running 1 m/s east with respect to the
ground, chasing after the bus and thoroughly humiliating her child. What is the child's velocity
a) relative to the ground?
b) relative to the mother?
Answer:
a) relative to the ground
Explanation:
after driving a portion of the route, the taptap is fully loaded with a total of 23 people including the driver, with an average mass of 65 kg per person. in addition, there are three 15- kg goats, five 3- kg chickens, and a total of 25 kg of bananas on their way to the market. assume that the springs have somehow not yet compressed to their maximum amount. how much are the springs compressed?
The compression of the spring at the given weight is 61 cm.
Given,
The spring constant is k =2.4 × 10⁴ N/m
mass of each of the 23 persons, = 65 kg
mass of each of the 3 goats, = 15 kg
mass of each of the 5 chickens, = 3 kg
mass of the bananas, = 25 kg
The total mass of all the passengers contained in the laptop is calculated as;
total mass of the persons = 23 x 65 = 1495 kg
total mass of the goats = 3 x 15 = 45 kg
total mass of the chickens = 5 x 3 = 15 kg
the total mass of the bananas = 25 kg
The total mass = (1495 + 45 + 15 + 25)kg
1The total mass = 580 kg
The calculation for the lengthy of spring:-
F = kx
x = F/k = mg/k
x = (1495*9.8)/2.4*10^4
x = 0.610 m
x = 61 cm
Hence, the compression of the spring at the given weight is 61 cm.
Learn more about spring here:-https://brainly.com/question/13771495
#SPJ4
What is the acceleration of a car that goes from
rest to 25 m/s in 5.0 s?
Answer:
5 m/s^2
Explanation:
Acceleration is change in velocity / change in time
Accel = 25 m/s / 5 s = 5 m/s^2
It takes 10 seconds to accelerate from rest to rate of 8 m/s. If the mass of the car is 1,200kg. Calculate the net force acting on the car .
Answer:
960 N
Explanation:
Find acceleration
Change in velocity / change in time
8 /10 = .8 m/s^2
Then F = ma
= 1200 kg * .8 m/s^2 = 960 N
A cart is set up as shown below, with three fans directed to the left and two of the fans running. The motion of the cart is represented by the v vs t graph shown. If the experiment were repeated with all three fans running, what might the resulting v vs t graph look like?
A. Graph A
B. Graph B
C. Graph C
D. Graph D
a cliff diver steps off a cliff and hits the water 2.2 seconds later. How high was the cliff?
The height of the cliff is 24.2 m.
Let:
'h' be the height of the cliff'u' be the initial velocity of diver; u = 0m/s'+'ve been the annotation for the Downward directiona = 10m/s^2 be the approximation of acceleration due to gravityUsing the Second Equation of Motion:
[tex]h = ut + 1/2 at^{2} \\h = 0 + 1/2 (10)(2.2)^{2} \\h = 0 + 5(2.2)^{2} \\h = 5(4.84)\\h = 24.2m[/tex]
The Second Equation of Motion establishes a relationship between displacement and time. It can be used to calculate the displacement and time, in different conditions.
The cliff was 24.2m high above the water surface, into which the cliff diver dived.
Learn more about the Second Equation of Motion:
https://brainly.com/question/25951773
If centripetal force is towards the center and gravitational force is also towards the center how can we be lighter at the equator?
ANSWER and EXPLANATION
We want to determine why a person weighs lighter at the equator.
At the equator, an object will weigh slightly less as a result of the slightly greater centripetal force and the slight increase in distance from the center of gravity of the earth due to the equatorial bulge. This would imply a decrease in the gravitational force that an object experiences.
In other words, the earth is not a perfect sphere, and so, at the equator, an object will be slightly farther from the center.
That is the answer.
There is a ball of fresh fruit at the top of a small cliff that is 45 m high. The fresh fruit baskets mass is 10kg's. Identify the energy (PE or KE) and calculate the it.
Given,
The mass of the fruit basket, m=10 kg
The height of the cliff, h=45 m
Kinetic energy is the energy possessed by an object due to its motion. Kinetic energy is directly proportional to the square of the velocity of the object.
Potential energy is the energy possessed by an object due to its position. The gravitational potential energy is directly proportional to the height at which the object is situated.
As the basket is at rest, its velocity is zero and hence it does not have kinetic energy.
Thus the energy possessed by the fruit basket is the potential energy.
The potential energy is given by,
[tex]E_P=\text{mgh}[/tex]Where g is the acceleration due to gravity.
On substituting the known values,
[tex]\begin{gathered} E_P=10\times9.8\times45 \\ =4410\text{ J} \end{gathered}[/tex]The potential energy of the fruit basket is 4410 J
suppose we want to place a weather satellite into a circular orbit 300 kmkm above the earth's surface. what speed, period, and radial acceleration must it have? the earth's radius is 6380km
a. The speed of the satellite is 244 m/s
b. The period of the satellite is 1.72 × 10⁷ s
c. The radial acceleration of the satellite is 8913 rad/s
What is the speed of the satellite?The speed of the satellite is given by v = √(GM/R) where
G = universal gravitational constant = 6.67 × 10⁻¹¹ Nm²/kg², M = mass of earth = 5.972 × 10²⁴ kg and R = radius of orbit = r + r' where r = radius of earth = 6380 km and r' = radius of orbit = 300 kmSo, substituting the values of the variables into the equation, we have that
v = √(GM/R)
v = √(6.67 × 10⁻¹¹ Nm²/kg² × 5.972 × 10²⁴ kg /6380 km + 300 km)
v = √(6.67 × 10⁻¹¹ Nm²/kg² × 5.972 × 10²⁴ kg /6680 km)
v = √(39.83324 × 10¹³ Nm²/kg ÷ 6.680 × 10⁶ m)
v = √(5.963 × 10⁻³ × 10⁷ Nm²/kg)
v = √(5.963 × 10⁴ Nm/kg)
v = 2.44 × 10² m/s
V = 244 m/s
So, the speed of the satellite is 244 m/s
b. What is the period of the orbit?The period of the orbit is given by T = 2πR/v where
R = radius of orbit = 6680 km and v = speed of orbit = 244 m/sSo, substituting the values of the variables into the equation, we have
T = 2πR/v
T = 2π × 6680 km/244 m/s
T = 2π × 6680 × 10³ m/244 × 10⁵ m/s
T = 13660π × 10³ m/244 × 10⁵ m/s
T = 41971.68 × 10³ m/244 × 10⁵ m/s
T = 17201.5 × 10³ s
T = 1.72015 × 10⁷ s
T ≅ 1.72 × 10⁷ s
So, the period of the satellite is 1.72 × 10⁷ s
What is the radial acceleration of the satellite?The radial acceleration of the satellite is given by a = v²/R where
v = speed of satellite = 244 m/s and R = radius of orbit = 6680 kmSubstituting the values of the variables into the equation, we have
a = v²/R
a = (244 m/s)²/6680 km
a = 59536 m²/s²/6680 × 10³ m
a = 8.913 × 10³ rad/s
a = 8913 rad/s
So, the radial acceleration of the satellite is 8913 rad/s
Learn more about speed of satellite here:
https://brainly.com/question/7260440
#SPJ1
an electron accelerated from rest through a voltage of 790 v enters a region of constant magnetic field. part a if the electron follows a circular path with a radius of 21 cm , what is the magnitude of the magnetic field? express your answer using two significant figures. b
The electron is accelerated through a potential difference of , so the kinetic energy gained by the electron is equal to its variation of electrical potential energy:
1/2mv²=eΔV
where
m is the electron mass
v is the final speed of the electron
e is the electron charge
is the potential difference
Re-arranging this equation, we can find the speed of the electron before entering the magnetic field:
v=√2eΔv/m=√2(1.6-10-19c)(790v)/9.1-10-31=1.66.10 m/s
Now the electron enters the magnetic field. The Lorentz force provides the centripetal force that keeps the electron in circular orbit:
evb=mv²/r
where B is the intensity of the magnetic field and r is the orbital radius. Since the radius is r=25 cm=0.25 m, we can re-arrange this equation to find B:
b=m/er =3.8.10 t
To learn more about voltage refer to:
https://brainly.com/question/1176850
#SPJ4
the barrel of a shotgun: group of answer choices is generally shorter than that of a rifle. is wider at the end to concentrate shot. is smooth without the grooves and lands found in rifles. is indistinguishable from that of a rifle.
Measures the diameter of a shotgun's barrel in terms of the quantity of lead balls needed to make the bore weigh one pound (12 gauge is the diameter of a lead ball weighing one-twelfth of a pound).
What differentiates a shotgun from a rifle?A shotgun has many projectile properties while a rifle only comes with one. Shotguns are helpful at close ranges when rifles are useful at a distance. Shotguns only have a front sight, whereas rifles have both front and rear sights.
Rifles are typically a little noisier than shotguns. Analyzing test results reveals that shotguns and rifles have decibel levels that are comparable. The typical decibel range
To learn more about differentiates a shotgun from a rifle refer to:
https://brainly.com/question/2988517
#SPJ1
two objects with equal masses are in motion. which object will have more kinetic energy? (1 point) responses the object with the greater speed the object with the greater speed the object with the greater density the object with the greater density the object with the greater acceleration the object with the greater acceleration the object with the greater volume the object with the greater volume
Answer:
I rephrased your question:
Two objects with equal masses are in motion. which object will have more kinetic energy?
A) the object with the greater speed
B) the object with the greater density
C) the object with the greater acceleration
D) the object with the greater acceleration
E) the object with the greater volume
F) the object with the greater volume
Explanation:
Kinetic Energy is equal to (1/2)mv^2, where m is the mass and v is the velocity.
-----
A) the object with the greater speed YES
B) the object with the greater density NO
C) the object with the greater density NO
D) the object with the greater acceleration MAYBE. Acceleration means energy is being added, so it depends on how much and the masses of each object.
E) the object with the greater volume NO
Answer:
Explanation: Two objects with equal masses are in motion. Which object will have more kinetic energy?
Responses
the object with the greater density
the object with the greater volume
the object with the greater acceleration
the object with the greater speed
Answer: The object with the greater speed
Calculator A dog has a kinetic energy of 111J and is running at a speed of 10m/s. What is the mass of the dog? Give your answer to 2 decimal places.
Explanation:
MASS=2.22
VELOCITY=10m/s
KINETIC ENERGY=111
PLEASE MARK ME AS BRILLIANT
You want to lift a heavy box with a mass L = 64.0 kg using the two-ideal pulley system as shown. With what minimum force do you have to pull down on the rope in order to lift the box at a constant velocity? One pulley is attached to the ceiling and one to the box.
The given problem can be solved using the following free-body diagram:
The diagram is the free-body diagram for the pulley that is holding the weight. Where:
[tex]\begin{gathered} T=\text{ tension} \\ m=\text{ mass} \\ g=\text{ acceleration of gravity} \end{gathered}[/tex]Now we add the forces in the vertical direction:
[tex]\Sigma F_v=T+T-mg[/tex]Adding like terms:
[tex]\Sigma F_v=2T-mg[/tex]Now, since the velocity is constant this means that the acceleration is zero and therefore the sum of forces is zero:
[tex]2T-mg=0[/tex]Now we solve for "T" by adding "mg" from both sides:
[tex]2T=mg[/tex]Now we divide both sides by 2:
[tex]T=\frac{mg}{2}[/tex]Now we substitute the values and we get:
[tex]T=\frac{(64\operatorname{kg})(9.8\frac{m}{s^2})}{2}[/tex]Solving the operations:
[tex]T=313.6N[/tex]Now we use the free body diagram for the second pulley:
Now we add the forces in the vertical direction:
[tex]\Sigma F_v=T-F[/tex]The forces add up to zero because the velocity is constant and the acceleration is zero:
[tex]T-F=0[/tex]Solving for the force:
[tex]T=F[/tex]Therefore, the pulling force is equal to the tension we determined previously and therefore is:
[tex]F=313.6N[/tex]
a powerful motorcycle can produce an acceleration of while traveling at 90.0 km/h. at that speed, the forces resisting motion, including friction and air resistance, total 400.0 n. (air resistance is analogous to air friction. it always opposes the motion of an object.) what is the magnitude of the force that motorcycle exerts backward on the ground to produce its acceleration if the mass of the motorcycle with rider is 245 kg? 34. a car with a mass o
1257.5 N is the magnitude of the force that motorcycle exerts backward on the ground to produce its acceleration.
What is a magnitude in physics?The definition of magnitude is simply "distance or quantity." It displays an object's size, direction, or speed, whether relative or absolute. It's used to indicate that something has a certain size or scope.
Briefing:A = 3.50 m/s² is the motorcycle's acceleration.
f = 400.0 N, the force of resistance to motion
M = 245 kg for the motorcycle's mass
F is the amount of force a motorcycle exerts when moving rearward.
The amount of force a motorcycle exerts when moving rearward is described as
F = f + ma
Inserting the values
F = 400.0 + (245) (3.50)
F = 1257.5 N
To know more about Magnitude visit:
https://brainly.com/question/1313542
#SPJ4
The complete question is -
A powerful motorcycle can produce an acceleration of 3.50 m/s² while traveling at 90.0 km/h. At that speed, the forces resisting motion, including friction and air resistance, total 400.0 N. (Air resistance is analogous to air friction. It always opposes the motion of an object.) What is the magnitude of the force that motorcycle exerts backward on the ground to produce its acceleration if the mass of the motorcycle with rider is 245 kg?
A piece of rock weighs 5 Newtons. A force F is applied to it and it produces an acceleration of a. Now, if there is a second piece of rock, what force needs to be applied to the second piece of rock to produce an acceleration of 8a?
Given,
weight of a piece of rock, W = mg = 5N
So, mass of a piece of rock is m = W ÷ g = 5N ÷ 9.8 m/[tex]s^{2}[/tex] = 0.51 kg.
When a force F is applied, it produces an acceleration 'a'. From Newton's second law of motion, F = ma = 0.51 a.
⇒a = F / 0.51.
Acceleration produced by 2nd piece of the rock is a' = 8a.
Assuming the mass of 2nd piece of rock to be same as the 1st piece, force to be applied on 2nd piece is F' = m'a'.
⇒ F' = m' × 8a = 8m'a
If the mass of both pieces of rock are equal, then m' = m = 0.51 kg.
⇒ F' = 0.51kg × 8a
⇒ F' = 0.51kg × 8 (F / 0.51)
⇒ F' = 8F.
Thus, a force equal to 8 times the force applied on 1st piece should be applied on the 2nd piece of the rock to produce an acceleration of 8a (if their masses are equal.
Learn more about Newton's Second law here, https://brainly.com/question/10673278.
#SPJ1
An apple is resting on a table. Claire says that there are no forces acting on the apple because it is not moving. Is she right?
Answer:
no
Explanation:
there are forces , even when the apple isnt moving , for example gravity which is keeping the apple on the table
a 7.50-nc point charge is located 1.80 m from a 4.20-nc point charge. (a) find the magnitude of the electric force that one particle exerts on the other. (b) is the force attractive or repulsive?
The electric force is 8.370 x 10^9N.
We need to know about the electric force to solve this problem. The electric force produced by charges interacting each other, whose strength is given by the equation
F = k.Q1 . Q2/r²
where F is the electric force, Q1 and Q2 is the charge and r is the radius.
From the question above, we know that
k = 9 x 10⁹ Nm²/C²
Q1 =e = 7.50 x 10^-9 C
Q2 = e = 4.02 x 10^-9 C
r = 1.80 m
The electric force will attract each other when the charges are different and will repel each other when the charges are same.
F = k.Q1 . Q2/r²
F = 9 x 10⁹ . 7.50 x 10^-9 . 4.02 x 10^-9/(1.80)²
F = 8.37 x 10^9 N
Find more on electric force at: brainly.com/question/17692887
#SPJ1
points :)
don't mind this just getting to 20 words :)
Answer:
20 20 20 20 25 points 20 20 20 25 points
Explanation:
assume that you weight yourself on a bathroom scale. would the springs inside a bathroom scale be more compressed or less compressed if you weighed yourself in an elevator that was accelerating upward?
The springs inside a bathroom scale will be more compressed.
What is acceleration due to gravity?
In physics, gravitational acceleration is the acceleration of an object in free fall in a vacuum (hence no resistance). This is a steady increase in velocity caused solely by the gravitational pull. All objects accelerate at the same speed in a vacuum, regardless of their mass or composition . The measurement and analysis of these velocities is known as gravimetry.
At a fixed point on the surface, the magnitude of the Earth's gravity is the combined effect of gravity and the centrifugal force due to the rotation of the Earth. Free-fall acceleration at various points on the Earth's surface ranges from 9.764 to 9.834 m/s2 (32.03 to 32.26 ft /s2) depending on altitude, latitude and longitude . The old standard is precisely defined as 9.80665 m/s2 (32.1740 ft/s2). Locations that deviate significantly from this value are called gravity anomalies. Other effects such as lift and air resistance are not taken into account.
When the elevator accelerates and shows a higher weight reading. As the lift accelerates and descends, the springs in the bathroom scale are compressed less and the displayed weight value is reduced.
To learn more about acceleration due to gravity from the link;
https://brainly.in/question/2073284
#SPJ4
Two ice skaters stand facing each other at rest on a frozen pond. They push off against one another and the 49 kg skater acquires a speed of 2. 10 m/s. If the other skater acquires a speed of 3. 81 m/s, what is her mass in kilograms?
Her mass is approximately equal to 27 kilograms.
How do you prove that?First of all, you need to understand that momentum is a conserved quantity and the solution to this problem involves elastic collision.
Momentum can be defined as p = mv where p is momentum, m is mass, and v is velocity. Just like energy, momentum is a physical quantity that is conserved in an isolated system. Momentum is conserved as a result of Newton's third law, which states that [tex]F_A=-F_B[/tex].
You are given that the ice skaters bounce off each other, meaning the collision is elastic. Remember that in an elastic collision, m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂ where
m₁ is the mass of the first body, m₂ is the mass of the second body,u₁ is the initial velocity of m₁,u₂ is the initial velocity of m₂,v₁ is the final velocity of m₁, andv₂ is the final velocity of m₂.Suppose that m₁ = 49 kg, m₂ = x, u₁ and u₂ = 0 m/s, v₁ = 2.1 m/s, and v₂ = 3.81 m/s. Then the mass of the other ice skater is as follows:
49 · 0 + x · 0 = 49 · 2.1 + x · 3.81
0 = 102.9 + 3.81x
3.81x + 102.9 = 0
3.81x = -102.9
x ≈ -27
Since a mass value can't be negative, the absolute value of x is 27. Therefore, it's her actual mass in kilograms.
Learn more about collisions in physics here: https://brainly.com/question/12644900
#SPJ4
If you wanted to visit a area with very little wind whear might you go
Answer:Ohio
Explanation:
A 14 kg boulder is pushed off a cliff with velocity v = ( 14.0 m/s ) + ( 2.0m/s ) y . Will the object experience a larger vertical or horizontal acceleration?
The object will eventually experience a large vertical acceleration since the vertical velocity increases as the object moves downwards.
What is horizontal motion of a projectile?The horizontal motion of a projectile is the motion of the projectile along a horizontal path.
The horizontal distance of a projectile is not affected by gravity and hence the horizontal speed of a projectile remains constant. That is the initial horizontal velocity is equal to the final horizontal velocity of the projectile.
However, the during the vertical motion an object, the vertical velocity decreases as the object moves upwards and eventual becomes zero when the object reaches the maximum height.
As the object begins to move downwards the vertical velocity increase and eventually become maximum before the object hits the ground.
Learn more about vertical acceleration here: https://brainly.com/question/8564131
#SPJ1
in february 1955, a paratrooper fell 370 m from an air- plane without being able to open his chute but happened to land in snow, suffering only minor injuries. assume that his speed at im- pact was 56 m/s (terminal speed), that his mass (including gear) was 85 kg, and that the magnitude of the force on him from the www.engineeringbookspdf problems 249 12.0 m/s and angle u1 35.0. just after, it is traveling directly upward with velocity of magnitude 10.0 m/s. the duration of the collision is 2.00 ms. what are the (a) magni- v : 2 snow was at the survivable limit of 1.2 105 n. what are (a) the minimum depth of snow that would have stopped him safely and (b) the magnitude of the impulse on him from the snow?
(a)1.1 m is the minimum depth of snow that would have stopped him safely. (b)The magnitude of the impulse on him from the snow[tex]|\Delta \overrightarrow{\mathrm{p}}|[/tex] -4.8 * 10³ kg. m/s.
What is magnitude ?A key concept in science is magnitude, which is employed in physics. Magnitude describes a general amount or a distance. We can relate magnitude to size and speed of the object is motion while considering the aspects of movement. The magnitude of the an object is defined by it's own size or quantity.
Briefing:We choose +y upward, which implies a>0 (the acceleration is upward since it represents a deceleration of his downward motion through the snow).
a) The maximum deceleration a[tex]_m_a_x[/tex] of the paratrooper (of mass m and initial speed ν=56m/s ) is found from Newton’s second law
F[tex]_s_n_o_w[/tex]−mg=ma[tex]_m_a_x[/tex]
where we require F[tex]_s_n_o_w[/tex] =1.2×10⁵N . Using Eq. 2 −15ν² =2a max d , we find the minimum depth of snow for the man to survive :
[tex]\mathrm{d}=\frac{v^2}{2 \mathrm{a}_{\text {max }}}=\frac{\mathrm{m} v^2}{2\left(\mathrm{~F}_{\text {snow }}-\mathrm{mg}\right)} \approx \frac{(85 \mathrm{~kg})(56 \mathrm{~m} / \mathrm{s})^2}{2\left(1.2 \times 10^5 \mathrm{~N}\right)}=[/tex]1.1 m.
(a) He experiences a change in momentum during his brief journey through the snow.
[tex]\Delta \overrightarrow{\mathrm{p}}=\overrightarrow{\mathrm{p}}_{\mathrm{f}}-\overrightarrow{\mathrm{p}}_{\mathrm{i}}[/tex] = 0 - (85 kg)(-56m/s)= -4.8 * 10³ kg. m/s.
or[tex]|\Delta \overrightarrow{\mathrm{p}}|[/tex] = -4.8 * 10³ kg. m/s.
Because downward is the negative direction, the starting velocity has a negative value. This equals the impulse caused by the net force F[tex]_s_n_o_w[/tex]−mg according to the impulse-momentum theorem, but since F[tex]_s_n_o_w[/tex] ≫mg we can approximate this as the impulse on him just from the snow.
To know more about Magnitude visit:
https://brainly.com/question/1313542
#SPJ4
The complete question is -
In February 1955, a paratrooper fell 370m from an airplane without being able to open his chute but happened to land in snow, suffering only minor injuries. Assume that his speed at impact was 56m/s (terminal speed), that his mass (including gear) was 85kg, and that the magnitude of the force on him from the snow was at the survivable limit of 1.2×10⁵ N. What are (a) the minimum depth of snow that would have stopped him safely and (b) the magnitude of the impulse on him from the snow?
a wheel has a constant angular acceleration of 4 rad/s2. starting from rest, it turns through 300 rad. what is its final angular velocity? how much time elapses while it turns through the 300 radians?
If a wheel has a constant angular acceleration of 4 rad/s2. starting from rest, it turns through 300 rad , then the final angular velocity would be 48.96 rad /s and 12.24 seconds elapse while it turns through the 300 radians.
What are the three equations of motion?There are three equations of motion given by Newton,
v = u + at
S = ut + 1/2×a×t²
v² - u² = 2×a×s
By using the second equation of motion given by Newton,
S = ut + 1/2at²
300 = 0 + 0.5 × 4 × t²
t² =300 /2
t = 12.24 seconds
The final angular velocity = 0+ 12.24 × 4
= 48.96 rad /s
Thus, 12.24 seconds elapse while it turns through the 300 radians.
To learn more about equations of motion here,
brainly.com/question/5955789
#SPJ1