An apple is resting on a table. Claire says that there are no forces acting on the apple because it is not moving. Is she right?

The magnetic field of a long straight wire has a board b0 at a distance r0 when the cutting edge is i0. at a distance of 3.00 r0: B'=2B0.

A magnetic field is a vector domain that describes the magnetic effect on moving electricity costs, currents, and magnetic materials. Transfer fees in magnetic fields are under pressure perpendicular to personal speed and magnetic fields.

The magnetic field is the place around the magnet where the effect of the magnetism is felt. We use magnetic fields as tools to explain how magnetic forces are directed into circular space and are essentially magnetic. This force attracts or repels magnets to each other. Examples of magnetic forces include compasses, motors, magnets that keep things in refrigerators, learning tracks, and new roller coasters. All the carrying charges create a magnetic field, and the charges flowing through that area enjoy the force.

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Explanation:

MASS=2.22

VELOCITY=10m/s

KINETIC ENERGY=111

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The pressure exerted by both on the trampoline is 25,480 N/m².

The pressure exerted by both on the trampoline is the force per unit area which is calculated as follows;

P = F/A

where;

Substitute the given parameters and solve for the pressure exerted.

P = (mg)/A

A = 0.25 m x 0.1 m

A = 0.025 m²

P = (65 x 9.8) / (0.025)

P = 25,480 N/m²

Thus, the pressure exerted at any given surface depends on the applied force and the area of the given surface.

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The springs inside a bathroom scale will be more compressed.

What is acceleration due to gravity?

In physics, gravitational acceleration is the acceleration of an object in free fall in a vacuum (hence no resistance). This is a steady increase in velocity caused solely by the gravitational pull. All objects accelerate at the same speed in a vacuum, regardless of their mass or composition . The measurement and analysis of these velocities is known as gravimetry.

At a fixed point on the surface, the magnitude of the Earth's gravity is the combined effect of gravity and the centrifugal force due to the rotation of the Earth. Free-fall acceleration at various points on the Earth's surface ranges from 9.764 to 9.834 m/s2 (32.03 to 32.26 ft /s2) depending on altitude, latitude and longitude . The old standard is precisely defined as 9.80665 m/s2 (32.1740 ft/s2). Locations that deviate significantly from this value are called gravity anomalies. Other effects such as lift and air resistance are not taken into account.

When the elevator accelerates and shows a higher weight reading. As the lift accelerates and descends, the springs in the bathroom scale are compressed less and the displayed weight value is reduced.

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The compression of the spring at the given weight is 61 cm.

Given,

The spring constant is k =2.4 × 10⁴ N/m

mass of each of the 23 persons, = 65 kg

mass of each of the 3 goats, = 15 kg

mass of each of the 5 chickens, = 3 kg

mass of the bananas, = 25 kg

The total mass of all the passengers contained in the laptop is calculated as;

total mass of the persons = 23 x 65 = 1495 kg

total mass of the goats = 3 x 15 = 45 kg

total mass of the chickens = 5 x 3 = 15 kg

the total mass of the bananas = 25 kg

The total mass = (1495 + 45 + 15 + 25)kg

1The total mass = 580 kg

The calculation for the lengthy of spring:-

F = kx

x = F/k = mg/k

x = (1495*9.8)/2.4*10^4

x = 0.610 m

x = 61 cm

Hence, the compression of the spring at the given weight is 61 cm.

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The given problem can be solved using the following free-body diagram:

The diagram is the free-body diagram for the pulley that is holding the weight. Where:

Now we add the forces in the vertical direction:

Adding like terms:

Now, since the velocity is constant this means that the acceleration is zero and therefore the sum of forces is zero:

Now we solve for "T" by adding "mg" from both sides:

Now we divide both sides by 2:

Now we substitute the values and we get:

Solving the operations:

Now we use the free body diagram for the second pulley:

Now we add the forces in the vertical direction:

The forces add up to zero because the velocity is constant and the acceleration is zero:

Solving for the force:

Therefore, the pulling force is equal to the tension we determined previously and therefore is:

        When acceleration is constant, we may connect displacement to time and velocity, two of the other three parameters that describe motion, using the following three equations: d = ( 1 2 ) ( 1 2 ) (v f + v I (t) (Equation 1) D = v I t + a t + 1 2 (Equation 2) V I 2 + 2 a d = v f 2 (Equation 3).

         Displacement is directly proportional to the square of the length of the linear motion when acceleration is constant and beginning velocity is zero.

Solution:-

vi =+245km/h

aavg = -3.0m/s2

vf =vi -(0.200)vi

vi =(245km/h)(1h/3600s)(103m/1km)= +68.1m/s

vf =(1.000-0.200)vi =(0.800)(68.1m/s)=+54.5m/s

Δt=vf -vi /aavg

 = 54.5m/s - 68.1m/s / -3.0m/s2

 =-13.6m/s /-3.0 m/s2

 =  4.5s

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With 1 scoop of flour, Olivia can bake 15 biscuits if the the equation that shows the relation between number of biscuits and amount of flour is c = 15f.

c = 15 f

c = Number of biscuits

f = Number of scoops of flour

f = 1

c = 15 * 1

c = 15

This equation shows that number of biscuits that can be made is 15 times the number of scoops of flour. So if the number of scoops of flour is 1, the number of biscuits that can be made is 15.

Therefore, with 1 scoop of flour, Olivia can bake 15 biscuits

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a. The speed of the satellite is  244 m/s

b. The period of the satellite is 1.72 × 10⁷ s

c. The radial acceleration of the satellite is 8913 rad/s

The speed of the satellite is given by v = √(GM/R) where

So, substituting the values of the variables into the equation, we have that

v = √(GM/R)

v = √(6.67 × 10⁻¹¹ Nm²/kg² × 5.972 × 10²⁴ kg /6380 km + 300 km)

v = √(6.67 × 10⁻¹¹ Nm²/kg² × 5.972 × 10²⁴ kg /6680 km)

v = √(39.83324 × 10¹³ Nm²/kg ÷ 6.680 × 10⁶ m)

v = √(5.963 × 10⁻³ × 10⁷ Nm²/kg)

v = √(5.963 × 10⁴ Nm/kg)

v = 2.44 × 10² m/s

V = 244 m/s

So, the speed of the satellite is  244 m/s

The period of the orbit is given by T = 2πR/v where

So, substituting the values of the variables into the equation, we have

T = 2πR/v

T = 2π × 6680 km/244 m/s

T = 2π × 6680 × 10³ m/244 × 10⁵ m/s

T = 13660π × 10³ m/244 × 10⁵ m/s

T = 41971.68 × 10³ m/244 × 10⁵ m/s

T = 17201.5 × 10³ s

T = 1.72015 × 10⁷ s

T ≅  1.72 × 10⁷ s

So, the period of the satellite is 1.72 × 10⁷ s

The radial acceleration of the satellite is given by a = v²/R where

Substituting the values of the variables into the equation, we have

a = v²/R

a = (244 m/s)²/6680 km

a = 59536 m²/s²/6680 × 10³ m

a = 8.913 × 10³ rad/s

a = 8913 rad/s

So, the radial acceleration of the satellite is 8913 rad/s

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If a wheel has a constant angular acceleration of 4 rad/s2. starting from rest, it turns through 300 rad , then the final angular velocity would be 48.96 rad /s  and 12.24  seconds elapse while it turns through the 300 radians.

There are three equations of motion given by  Newton,

v = u + at

S = ut + 1/2×a×t²

v² - u² = 2×a×s

By using the second equation of motion given by Newton,

S = ut + 1/2at²

300 = 0 + 0.5 × 4 × t²

t² =300 /2

t = 12.24  seconds

The final angular velocity = 0+ 12.24 × 4

                                          = 48.96 rad /s  

Thus,  12.24  seconds elapse while it turns through the 300 radians.

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The height of the cliff is 24.2 m.

Let:

Using the Second Equation of Motion:

                               [tex]h = ut + 1/2 at^{2} \\h = 0 + 1/2 (10)(2.2)^{2} \\h = 0 + 5(2.2)^{2} \\h = 5(4.84)\\h = 24.2m[/tex]

The Second Equation of Motion establishes a relationship between displacement and time. It can be used to calculate the displacement and time, in different conditions.

The cliff was 24.2m high above the water surface, into which the cliff diver dived.

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The wavelength, the speed of sound and the water level of the next resonant length (the fifth harmonics) are as follows;

An harmonics are waves with a frequency that is an integer multiple of the fundamental frequency.

The given frequency of the sound wave, f = 330 hz

The first water level that gives the first loud sound, l₁ = 17.8 cm

The water level from the open end at the second loud sound, l₂ = 57.3 cm

First part;

The first harmonics that gives the fundamental frequency for the pipe is expressed as follows;

[tex]\dfrac{\lambda}{4} = l_1+e[/tex]
Where;

e = The distance to the antinode of the wave above the top of the pipe

The third harmonics is given by the formula

[tex]\dfrac{3\cdot \lambda}{4} = l_2+e[/tex]

[tex]\dfrac{3\cdot \lambda}{4}- \dfrac{\lambda}{4} = \dfrac{\lambda}{2} = (l_2+e) - (l_1+e) = l_2 - l_1[/tex]

[tex]\dfrac{\lambda}{2} = l_2 - l_1[/tex]

λ = 2 × (l₂ - l₁)

λ = 2 × (57.3 - 17.8) = 79

The wavelength of the wave, λ = 79 centimeters = 0.79 meters

Second part;

Speed of sound, v = f × λ

Therefore; v = 330 Hz × 0.79 m = 260.7 m/s

Third part;

[tex]\dfrac{\lambda}{4} = l_1+e[/tex]

[tex]\dfrac{3\cdot \lambda}{4} = l_2+e[/tex]

Which gives; 3·(l₁ + e) = l₂ + e

3·l₁ + 3·e = l₂ + e

3·e - e = l₂ - 3·l₁

2·e = l₂ - 3·l₁

Therefore, 2·e = 57.3 - 3 × 17.8 = 2.9

The water level for the next resonant length, which is the fifth harmonics, is given by the formula;

[tex]\dfrac{5\cdot \lambda}{4} = l_3+e[/tex]

Which gives;

[tex]l_3 = \dfrac{5\cdot \lambda}{4} - e[/tex]

Therefore;

[tex]l_3 = \dfrac{5\times 79 }{4} - 1.95 = 96.8[/tex]

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The electric force is 8.370 x 10^9N.

We need to know about the electric force to solve this problem. The electric force produced by charges interacting each other, whose strength is given by the equation

F = k.Q1 . Q2/r²

where F is the electric force, Q1 and Q2 is the charge and r is the radius.

From the question above, we know that

k = 9 x 10⁹ Nm²/C²

Q1 =e = 7.50 x 10^-9 C

Q2 = e = 4.02 x 10^-9 C

r = 1.80 m

The electric force will attract each other when the charges are different and will repel each other when the charges are same.

F = k.Q1 . Q2/r²

F = 9 x 10⁹ . 7.50 x 10^-9 . 4.02 x 10^-9/(1.80)²

F = 8.37 x 10^9 N

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The kinetic energy is changed to thermal energy by brake friction and turns to zero.

We need to know about kinetic energy to solve this problem. Kinetic energy is the energy from a moving object. It can be determined as

KE = 1/2 . m . v²

where KE is kinetic energy, m is mass and v is speed.

From the question above, we know that

v1 = 100 mph

KE2 = 0 joule

When the car moves at 100 mph, the car has kinetic energy. But on the way when the driver brakes the car, the kinetic energy is changed to thermal energy by brake friction. Hence, the kinetic energy is reduced every time and finally turns to zero.

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Given,  

weight of a piece of rock, W = mg = 5N

So, mass of a piece of rock is m = W ÷ g = 5N ÷ 9.8 m/[tex]s^{2}[/tex] = 0.51 kg.

When a force F is applied, it produces an acceleration 'a'. From Newton's second law of motion, F = ma = 0.51 a.

⇒a = F / 0.51.

Acceleration produced by 2nd piece of the rock is a' = 8a.

Assuming the mass of 2nd piece of rock to be same as the 1st piece, force to be applied on 2nd piece is F' = m'a'.

⇒ F' = m' × 8a = 8m'a

If the mass of both pieces of rock are equal, then m' = m = 0.51 kg.

⇒ F' = 0.51kg × 8a

⇒  F' = 0.51kg × 8 (F / 0.51)

⇒  F' = 8F.

Thus, a force equal to 8 times the force applied on 1st piece should be applied on the 2nd piece of the rock to produce an acceleration of 8a (if their masses are equal.

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I think Twelve is the answer

The electron is accelerated through a potential difference of , so the kinetic energy gained by the electron is equal to its variation of electrical potential energy:

1/2mv²=eΔV

where

m is the electron mass

v is the final speed of the electron

e is the electron charge

is the potential difference

Re-arranging this equation, we can find the speed of the electron before entering the magnetic field:

v=√2eΔv/m=√2(1.6-10-19c)(790v)/9.1-10-31=1.66.10 m/s

Now the electron enters the magnetic field. The Lorentz force provides the centripetal force that keeps the electron in circular orbit:

evb=mv²/r

where B is the intensity of the magnetic field and r is the orbital radius. Since the radius is r=25 cm=0.25 m, we can re-arrange this equation to find B:

b=m/er =3.8.10 t

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Answer:

960 N

Explanation:

Find acceleration

  Change in velocity / change in time

      8 /10 = .8 m/s^2

Then F = ma

            = 1200 kg  * .8 m/s^2 = 960 N

Answer:

a) relative to the ground

Explanation:

Measures the diameter of a shotgun's barrel in terms of the quantity of lead balls needed to make the bore weigh one pound (12 gauge is the diameter of a lead ball weighing one-twelfth of a pound).

A shotgun has many projectile properties while a rifle only comes with one. Shotguns are helpful at close ranges when rifles are useful at a distance. Shotguns only have a front sight, whereas rifles have both front and rear sights.

Rifles are typically a little noisier than shotguns. Analyzing test results reveals that shotguns and rifles have decibel levels that are comparable. The typical decibel range

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Answer:Ohio

Explanation:

Answer:

20 20 20 20 25 points 20 20 20 25 points

Explanation:

Answer:

I rephrased your question:

Two objects with equal masses are in motion. which object will have more kinetic energy?

A) the object with the greater speed

B) the object with the greater density  

C) the object with the greater acceleration

D) the object with the greater acceleration

E) the object with the greater volume

F) the object with the greater volume

Explanation:

Kinetic Energy is equal to (1/2)mv^2, where m is the mass and v is the velocity.

-----

A) the object with the greater speed   YES

B) the object with the greater density  NO

C) the object with the greater density  NO

D) the object with the greater acceleration MAYBE.  Acceleration means energy is being added, so it depends on how much and the masses of each object.

E) the object with the greater volume  NO

Answer:

Explanation: Two objects with equal masses are in motion. Which object will have more kinetic energy?

Responses

the object with the greater density

the object with the greater volume

the object with the greater acceleration

the object with the greater speed

Answer: The object with the greater speed

1257.5 N is the magnitude of the force that motorcycle exerts backward on the ground to produce its acceleration.

The definition of magnitude is simply "distance or quantity." It displays an object's size, direction, or speed, whether relative or absolute. It's used to indicate that something has a certain size or scope.

A = 3.50 m/s² is the motorcycle's acceleration.

f = 400.0 N, the force of resistance to motion

M = 245 kg for the motorcycle's mass

F is the amount of force a motorcycle exerts when moving rearward.

The amount of force a motorcycle exerts when moving rearward is described as

F = f + ma

Inserting the values

F = 400.0 + (245) (3.50)

F = 1257.5 N

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The complete question is -

A powerful motorcycle can produce an acceleration of 3.50 m/s² while traveling at 90.0 km/h. At that speed, the forces resisting motion, including friction and air resistance, total 400.0 N. (Air resistance is analogous to air friction. It always opposes the motion of an object.) What is the magnitude of the force that motorcycle exerts backward on the ground to produce its acceleration if the mass of the motorcycle with rider is 245 kg?

Her mass is approximately equal to 27 kilograms.

First of all, you need to understand that momentum is a conserved quantity and the solution to this problem involves elastic collision.

Momentum can be defined as p = mv where p is momentum, m is mass, and v is velocity. Just like energy, momentum is a physical quantity that is conserved in an isolated system. Momentum is conserved as a result of Newton's third law, which states that [tex]F_A=-F_B[/tex].

You are given that the ice skaters bounce off each other, meaning the collision is elastic. Remember that in an elastic collision, m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂ where

Suppose that m₁ = 49 kg, m₂ = x, u₁ and u₂ = 0 m/s, v₁ = 2.1 m/s, and v₂ = 3.81 m/s. Then the mass of the other ice skater is as follows:

49 · 0 + x · 0 = 49 · 2.1 + x · 3.81

0 = 102.9 + 3.81x

3.81x + 102.9 = 0

3.81x = -102.9

x ≈ -27

Since a mass value can't be negative, the absolute value of x is 27. Therefore, it's her actual mass in kilograms.

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The displacement of the team is 2.74 miles due east and 7.52 miles due north from where they started.

The eastward displacement of Ida Haitarun and his team during the cross country race is calculated by forming a right triangle from the displacement of the team.

The angle of inclination of the displacement is calculated as follows;

θ = 90⁰ - 20⁰ = 70⁰ (above the horizontal)

The eastward displacement is the base of the triangle and it is calculated as follows;

cos θ = base / hypotenuse side

cos 70 = base / 8 miles

base = (8 miles) x (cos 70)

base = 2.74 miles

The northward displacement is calculated as follows;

sin θ = height / hypotenuse side

sin 70 = height / 8 miles

height = (8 miles) x (sin 70)

height = 7.52 miles

Thus, the team is 2.74 miles due east and 7.52 miles due north from where they started.

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magnitude of the momentum of the combined mass immediately after the collision  p = 0. 478 (kg. m/sec)

Mass of bullet : m = 5. 25 (g) = 0. 00525 (kg)

Mass of block : M = 360 (g) = 0. 360 (kg)

Height : h = 8. 75 (m) = 0. 0875 (m)

Here we need to find the momentum :

Now,

As we know that,

The conservation of energy :

Now,

Kinetic energy = Potential energy

= 1/2( m + M)v² = (m+M)gh (m,M is mass of bullet and block)

Now,

v = [tex]\sqrt{2gh}[/tex]

Now,

Momentum can be defined as :

Here,

p = (m+ M) [tex]\sqrt{2gh}[/tex]. . . eqn 1

Putting the values in eqn 1 :

We get,

p = 0.478 (kg. m/sec)

Hence, the momentum : p = 0. 478 (kg. m/sec)

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