Answer:
What is the normal force on the object (draw a diagram if needed)
784 N
How much force is required to get the object to start to move from rest (max static friction)?
470.4 N
When the object starts moving, what is the force of kinetic friction?
274.4 N
If the moving object has a tension force of 300N to the right pulling it, what is the net force on the object in the horizontal direction? 784 N
What is the acceleration (with direction) of the object based on your answer for part d? Remember that a = net force/m.
Explanation:
We have that for the Question "" it can be said that the normal force and How much force is required to get the object to start to move from rest is
F_N=784NF_{max}480N
From the question we are told
An 80 kg object has a µk = 0.35 and a µs = 0.60. Assuming it is on a flat surface
What is the normal force on the object (draw a diagram if needed) How much force is required to get the object to start to move from rest?
a)
Generally the equation for the Normal Force is mathematically given as
[tex]F_N=mg\\\\F_N=80*9.8\\\\F_N=784N\\\\[/tex]
b)
[tex]F_{max}=0.60*800\\\\\F_{max}480N\\\\[/tex]
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Complete Question
An 80 kg object has a µk = 0.35 and a µs = 0.60. Assuming it is on a flat surface
What is the normal force on the object (draw a diagram if needed) How much force is required to get the object to start to move from rest?
An automobile traveling 88.0 km/h has tires of 72.0 cm diameter. (a) What is the angular speed of the tires about their axles
Answer:
angular speed = 67.91 rad/s
Explanation:
Given that,
The diameter of a tire, d = 72 cm
The radius of a tire, r = 36 cm = 0.36 m
Linear speed of an automobile, v = 88 km/h = 24.45 m/s
We need to find the angular speed of the tires about their axles. The relation between angular speed and angular speed is given by :
[tex]v=r\omega\\\\\omega=\dfrac{v}{r}\\\\\omega=\dfrac{24.45 }{0.36}\\\\\omega=67.91\ rad/s[/tex]
So, the angular speed of the tire is 67.91 rad/s.
A 1400 kg car traveling in the positive direction takes 11.0 seconds to slow from 25.0 meters per second to 12.0 meters per second. What is the average force on the car during this time?
Answer:
–1652 N. The negative sign indicate that the force is in opposite direction to car.
Explanation:
The following data were obtained from the question:
Mass (m) of car = 1400 kg
Time (t) = 11 s
Initial velocity (u) = 25 m/s
Final velocity (v) = 12 m/s
Force (F) applied on the car =?
Next, we shall determine the acceleration of the car. This can be obtained as follow:
Time (t) = 11 s
Initial velocity (u) = 25 m/s
Final velocity (v) = 12 m/s
Acceleration (a) =?
a = (v – u) /t
a = (12 – 25) /11
a = –13/11
a = –1.18 m/s²
Finally, we shall determine the force on the car as follow:
Acceleration (a) = –1.18 m/s²
Mass (m) of car = 1400 kg
Force (F) applied on the car =?
F = ma
F = 1400 × –1.18
F = –1652 N
Thus, the force on the car is –1652 N. The negative sign indicate that the force is in opposite direction to car.
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Which statement best explains why two flowers of the same species have different colored petals?:
A. exposure to sunlight
B. expression of an inherited trait
C. expression of an acquired trait
D. photosynthesis
You will get brainliest just for trying because i could use the help.
Answer:
B
Explanation:
it could be because they have a difference in genes
NEED HELP ASP
WILL GIVE POINTS OR WHATEVER
Answer:
you need to multiply the momentum and the mass
a steel is 40cm long at 20c.the coefficient of linear expansivity for steel is 0.000012.find the increase in length at 70C
Answer:
janakajnakanabjjiaj yav good day for you to everyone else to do with my family is it just doesn't want me and I am
One atomic mass unit is defined as 1.66 x 10^-27 kg. If a proton has a mass of one atomic mass unit and a density of approximately 5.8 x 10^27 kg/m3^ . What is the diameter of a proton if we assume it is a sphere?
Answer:
The diameter is [tex]d = 8.18*10^{-19} \ m[/tex]
Explanation:
From the question we are told that
The value of one atomic mass unit is [tex]u = 1.66 *10^{-27} \ kg[/tex]
The density of the proton is [tex]\rho = 5.8 *10^{27} \ kg/m^3[/tex]
Generally the volume of the proton (sphere)is mathematically represented as
[tex]V = \frac{4}{3} * \pi * r^3[/tex]
Generally this volume can also be evaluated as
[tex]V = \frac{u}{\rho}[/tex]
=> [tex]V = \frac{1.66 *10^{-27}}{5.8*10^{27}}[/tex]
=> [tex]V = 2.862 *10^{-55} \ m^3[/tex]
So
[tex]2.862 *10^{-55} = \frac{4}{3} * 3.142 * r^3[/tex]
=> [tex]r^3 = 6.832 *10^{-56}[/tex]
=> [tex]r = 4.088 *10^{-19} \ m[/tex]
Now the diameter is mathematically represented as
[tex]d = 2 * r[/tex]
=> [tex]d = 2 * 4.088 *10^{-19}[/tex]
=> [tex]d = 8.18*10^{-19} \ m[/tex]
If you can answer my last post ill give you 75 points pls its very important and please make sure it correct!!!!!!!
Answer:
I can't see the post :/
Explanation:
Answer:
ok
Explanation:
ok how many points is this?????
Doing specific exercises to improve a particular skill or type of health fitness is called training? True or false
who plays adopt me on rob.lox!! plz answer people only if you play though tell me your best pet and your user name so we can play!!
Answer: I don't do adopt me but I do have a Ro.blox username its Nvm i cant but my user name
Explanation:
Answer:
adopt me sucks but my best pet was an albino monkey I think or a king monkey
Explanation:
MULTIPLE CHOICE
Newton’s first law of motion is also known as the law of ______ while the Newton’s 2nd law of motion is known as the law of _____ and Newton’s third law is also known as the law of ______
Answer:
1st law known as low of inertial
2nd law of acelaration and force relationship
3rd law of action and reaction
A student made a model of an onion skin cell she viewed using a microscope. The scale is 500:1. The student's cell model has a length of 15 cm. How many centimeters is the cells length
I feel like I'm in a city
Answer:
0.03 cm
Explanation: If the scale is 500:1, you have to divide 500 by 15 to get 0.03. You do not multiply 500 times 15 because the cells are smaller than the scale representation so you divide.
You perform an experiment to test how far a cannon will shoot a performer at
different angles. The data are shown below.
Angle
Distance (feet)
30°
110
34°
120
38°
128
42°
133
46°
127
50°
119
54°
109
At which angle will the performer travel the shortest distance?
A. 44°
B. 54
Ο Ο Ο Ο
C. 32
D. 50°
Answer:
128
Explanation:
Answer:
54 degrees
Explanation:
PLEASE PROVIDE AN EXPLANATION.
THANKS!!!
Answer:
(a) A = 0.0800 m, λ = 20.9 m, f = 11.9 Hz
(b) 250 m/s
(c) 1250 N
(d) Positive x-direction
(e) 6.00 m/s
(f) 0.0365 m
Explanation:
(a) The standard form of the wave is:
y = A cos ((2πf) t ± (2π/λ) x)
where A is the amplitude, f is the frequency, and λ is the wavelength.
If the x term has a positive coefficient, the wave moves to the left.
If the x term has a negative coefficient, the wave moves to the right.
Therefore:
A = 0.0800 m
2π/λ = 0.300 m⁻¹
λ = 20.9 m
2πf = 75.0 rad/s
f = 11.9 Hz
(b) Velocity is wavelength times frequency.
v = λf
v = (20.9 m) (11.9 Hz)
v = 250 m/s
(c) The tension is:
T = v²ρ
where ρ is the mass per unit length.
T = (250 m/s)² (0.0200 kg/m)
T = 1250 N
(d) The x term has a negative coefficient, so the wave moves to the right (positive x-direction).
(e) The maximum transverse speed is Aω.
(0.0800 m) (75.0 rad/s)
6.00 m/s
(f) Plug in the values and find y.
y = (0.0800 m) cos((75.0 rad/s) (2.00 s) − (0.300 m⁻¹) (1.00 m))
y = 0.0365 m
Which kind of wave interaction is shown?
Answer:
where?
Explanation:
ill edit my answer when see it
Describe the difference between simply taking measurements and doing a scientific experiment.
In 2-3 sentences
A 30kg boxed is pushed with a force of 20N. What is the boxes acceleration. Please show work
Answer:
The answer is 0.67 m/s²Explanation:
The acceleration of an object given it's mass and the force acting on it can be found by using the formula
[tex]a = \frac{f}{m} \\ [/tex]
f is the force
m is the mass
From the question we have
[tex]a = \frac{20}{30} = \frac{2}{3} \\ = 0.6666666...[/tex]
We have the final answer as
0.67 m/s²Hope this helps you
Two balls collide in a head-on elastic collision and rebound in opposite directions. One ball has velocity 1.2 m/s before the collision, and −2.3 m/s after. The other ball has a mass of 1.1 kg and a velocity of −4.2 m/s before the collision. (a) What is the mass of the first ball? (b) What is the velocity of the second ball after the collision?
Answer:
If two particles are involved in an elastic collision, the velocity of the second particle after collision can be expressed as: v2f=2⋅m1(m2+m1)v1i+(m2−m1)(m2+m1)v2i v 2 f = 2 ⋅ m 1 ( m 2 + m 1 ) v 1 i + ( m 2 − m 1 ) ( m 2 + m 1 ) v 2 i .
Explanation:
Mark me as brainliest and follow me
Bru challenge with the physics.
Answer:
WHATATATATTAT
Explanation:
What is the main function of an earthworm organ
Answer:
brain
Explanation:
brain and blood
Why are continental rocks much older than oceanic crust?
A. Oceanic crust is continually recycled through convection in the earth's mantle
B. Oceanic crust is made out of much less dense material than continental crust
C. Continental crust is continually renewed through convection in the earth's mantle
D. Continental crust eats oceanic crust for breakfast
Answer:
A. Oceanic crust is continually recycled through convection in the earth's mantle
Explanation:
The oceanic plate is constantly being recycled through the forces of convection within the earth's mantle.
New oceanic plate are formed mid-oceanic ridge for example. As the magma cools and solidifies, they are moved away continually.
This is not the case for the continental curst.
Suppose that the space shuttle Columbia accelerates at 14.0 m/s2 for 8.50 minutes after takeoff.
A. What will be the speed of the shuttle at the end of 8.50 minutes?
B. How far will the shuttle have traveled during this time?
Answer:
A. speed = 7.14 Km/s
B. distance = 1820.7 Km
Explanation:
Given that: a = 14.0 m/[tex]s^{2}[/tex], t = 8.50 minutes.
But,
t = 8.50 = 8.50 x 60
= 510 seconds
A. By applying the first equation of motion, the speed of the shuttle at the end of 8.50 minutes can be determined by;
v = u + at
where: v is the final velocity, u is the initial velocity, a is the acceleration and t is the time.
u = 0
So that,
v = 14 x 510
= 7140 m/s
The speed of the shuttle at the end of 8.50 minute is 7.14 Km/s.
B. the distance traveled can be determined by applying second equation of motion.
s = ut + [tex]\frac{1}{2}[/tex]a[tex]t^{2}[/tex]
where: s is the distance, u is the initial velocity, a is the acceleration and t is the time.
u = 0
s = [tex]\frac{1}{2}[/tex]a[tex]t^{2}[/tex]
= [tex]\frac{1}{2}[/tex] x 14 x [tex](510)^{2}[/tex]
= 7 x 260100
= 1820700 m
The distance that the shuttle has traveled during the given time is 1820.7 Km.
The rotational inertia of a thin rod about one end is 1/3 ML2. What is the rotational inertia of the same rod about a point located 0.40 L from the end
Answer:
The value is [tex]I = 0.0932 ML ^2[/tex]
Explanation:
From the question we are told that
The rotational inertia about one end is [tex]I_R = \frac{1}{3} ML^2[/tex]
The location of the axis of rotation considered is [tex]d = 0.4 L[/tex]
Generally the mass of the portion of the rod from the axis of rotation considered to the end of the rod is [tex]0.4 M[/tex]
Generally the length of the rod from the its beginning to the axis of rotation consider is
[tex]k = 1 - 0.4 L = 0.6L[/tex]
Generally the mass of the portion of the rod from the its beginning to the axis of rotation consider is
[tex]m = 1- 0.4 M = 0.6 M[/tex]
Generally the rotational inertia about the axis of rotation consider for the first portion of the rod is
[tex]I_{R1} = \frac{1}{3} (0.6 M )(0.6L)^2[/tex]
[tex]I_{R1} = \frac{1}{3} (0.6 M )L^2 0.6^2[/tex]
Generally the rotational inertia about the axis of rotation consider for the second portion of the rod is
[tex]I_{R2} = \frac{1}{3} (0.6 M )(0.6L)^2[/tex]
=> [tex]I_{R2} = \frac{1}{3} (0.4 M )(0.4L)^2[/tex]
=> [tex]I_{R2} = \frac{1}{3} (0.4 M )L^2 0.4^2[/tex]
Generally by the principle of superposition that rotational inertia of the rod at the considered axis of rotation is
[tex]I = \frac{1}{3} (0.6 M )L^2 0.6^2 + \frac{1}{3} (0.4 M )L^2 0.4^2[/tex]
=> [tex]I = \frac{1}{3} ML ^2 [0.6 * (0.6)^2 + 0.4 * (0.4)^2 ][/tex]
=> [tex]I = 0.0932 ML ^2[/tex]
Which state of matter does this model represent?
Image of particles tightly packed
Solid
Liquid
Gas
Plasma
Answer:
gas
Explanation:
it is gas because the particles are floating up none of the above would be floating up.
Answer:
Solid
Explanation:
A: Solid- Solids have the particles tightly packed. They have a definite shape and volume
B: Liquid- Liquids have particles not to tightly packed but kind of loose. They have an indefinite shape but a definite volume
C: Gas- Gas has particles freely all around. Indefinite shape and volume
D: Plasma- Plasma is different and should be explained with an example; think of lighting....
Since the image shows tightly packed particles, it is clear the answer is a solid.
An arrow in a bow has 357 J of elastic potential energy How much Winette enere
Will the arrow have after it has been shot assuming there is no sir restoran
Answer:
357 J
Explanation:
The elastic potential energy of arrow in the stretched bow is 357 J.
The kinetic energy of the arrow after it has been shot is given by half of the product of the arrow's mass and velocity of the arrow.
Here there are no other forms of energy at play here. Only potential and kinetic energy.
As we know that in any system the energy is conserved accordingly the elastic potential energy of the arrow will be equal to the kinetic energy of the bow after it is released i.e., 357 J.
What famous equation describes the energy of stars?
Answer:
E=mc2
Explanation:
It explains that in their interiors, atoms fuse together, creating energy.
To solve this we must be knowing each and every concept related to energy and its different types. Therefore, the famous equation that describes the energy of stars is E=mc².
What is energy?In physics, energy is the capacity to accomplish work. It can be potential, kinetic, thermal, electric, chemical, radioactive, or in other forms.
There is also heat and work—energy inside the process of being transferred by one body to the other. Energy is always classified according to its type once it has been transmitted. As a result, heat transported could become thermal energy, whereas labor done may emerge as mechanical energy. The famous equation that describes the energy of stars is E=mc²
Therefore, the famous equation that describes the energy of stars is E=mc².
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If a 25 kg lawnmower produces 347 w and does 9514 J of work, for
how much time did the lawnmower run?
Steps 1 and 2)
The variables are W = work, P = power, and t = time. In this case, W = 9514 joules and P = 347 watts.
The goal is to solve for the unknown time t.
-----------------------
Step 3)
Since we want to solve for the time, and we have known W and P values, we use the equation t = W/P
-----------------------
Step 4)
t = W/P
t = 9514/347
t = 27.4178674351586
t = 27.4 seconds
-----------------------
Step 5)
The lawn mower ran for about 27.4 seconds. I rounded to three sig figs because this was the lower amount of sig figs when comparing 9514 and 347.
-----------------------
Note: we don't use the mass at all
What must happen to an atom of magnesium in order to become a magnesium ion Mg+2?
It must lose two neutrons and become a different isotope.
It must gain two neutrons and become a different isotope.
It must lose two electrons and become an ion.
It must gain two electrons and become an ion.
Answer:
Answer is: c. It must lose two electrons and become an ion.
Magnesium (Mg) is metal from 2. group of Periodic table of elements and has low ionisation energy and electronegativity, which means it easily lose valence electons (two valence electrons).
Magnesium has atomic number 12, which means it has 12 protons and 12 electrons. It lost two electrons to form magnesium cation (Mg²⁺) with stable electron configuration like closest noble gas neon (Ne) with 10 electrons.
Electron configuration of magnesium ion: ₁₂Mg²⁺ 1s² 2s² 2p⁶.
Explanation:
Answer:
the third option
Explanation:
What kind of food would you expect a turtle with a hard, sharp beak and short neck to eat?
A 3.0 kg object moving 8.0 m/s in the positive x-direction has a one-dimensional elastic collision with an object of mass, M, initially at rest. After the collision the object of unknown mass has a velocity of 6.0 m/s in the positive x direction. What is M
Answer:
1kgExplanation:
According to law of conservation of momentum
m1u1+ m2u2 = (m1+m2)v
m1 and m2 are the masses of the object
u1 and u2 are their initial velocities
v is their common velocity
Given
m1 = 3kg
m2 = M
u1 = 8m/s
u2 = 0m/s (object at rest)
v = 6.0m/s
Substitute and get M
3(8) + M(0) = (3+M)6
24 = 18+6M
24-18 = 6M
6 = 6M
M = 1kg
Hence the mass M is 1kg
What do you do abt onion eyes (MY EYES ARE BURNING BADDD)
Answer:
Leave onions in cold water for about 15 minutes! Takes out the chemical reaction in the onion's defense system.
Explanation:
This is what people NEED to know for cooking... Lol :)