Aluminum reacts with chlorine gas to form aluminum chloride. (a) If 35g of aluminum reacts with excess chlorine, how many grams of aluminum chloride will form. (b) How many grams of chlorine will react completely with 42.8 g of aluminum 2Al + 3Cl2 ==> 2AlCl3

Answers

Answer 1

Answer

(a) 172.848 grams

(b) 168.584 grams

Explanation

The balanced equation for the reaction of aluminum with chlorine gas is:

[tex]2Al+3Cl_2\rightarrow2AlCl_3[/tex]

(a) Mass of Al = 35 g

From the Periodic Table;

Molar mass of Al = 27 g/mol

Molar mass of AlCl₃ = 133.34 g/mol

From the balanced equation above; 2 moles Al produced 2 moles AlCl₃

So in grams, 2 mol x 27 g/mol = 54 g Al produced 2 mol x 133.34 g/mol = 266.68 g AlCl₃

Therefore, 35 g Al will form:

[tex]\frac{266.68\text{ g AlCl}_{3}\text{ }\times35\text{ g Al}}{54\text{ g Al}}=172.848\text{ g AlCl}_{3}[/tex]

172.848 grams of aluminum chloride will be formed.

(b) Mass of Al = 42.8 g

Also from the Periodic Table; the molar mass of Cl₂ = 70.90 g/mol

From the equation above; 2 mol of Al requires 3 mol Cl₂.

In grams, 2 mol x 27 g/mol = 54 g Al requires 3 mol x 70.90 g/mol = 212.7 g Cl₂

Hence, 42.8 g Al will react with:

[tex]\frac{42.8\text{ g Al }\times212.7\text{ g Cl}_{2}}{54\text{ g Al}}=168.584\text{ g Cl}_{2}[/tex]

168.584 grams of chlorine will react completely with 42.8 g of aluminum


Related Questions

How many moles of copper(l) oxide contain 1.20 x 10^23 copper atoms? Include units and name of atom/molecule.

Answers

ANSWER

Number of moles = 0.1993 mole

STEP-BY-STEP EXPLANATION:

Given particles

[tex]\begin{gathered} \text{Number of particles = 1.20 }\cdot10^{23} \\ \text{Avogadro's number = }6.022\cdot10^{23} \end{gathered}[/tex]

The formula for calculating moles is written below

[tex]\text{Number of moles = }\frac{Number\text{ of particles}}{\text{Avogadro's number}}[/tex]

The next thing is to substitute the above parameters into the above formula

[tex]\begin{gathered} \text{Number of moles = }\frac{1.20\cdot10^{23}}{6.022\cdot10^{23}} \\ \text{Number of mole = }\frac{1.20}{6.022} \\ Number\text{ of moles = 0.1993 mole} \end{gathered}[/tex]

What could be the third quantum number for one of the electrons in the 4penergy sublevel of bromine?A. m = -1B. m = 5C. m = +D. m = 4

Answers

Assuming the third quantum number is the question is the magnetic quantum number, it is limited by the angular momentum quantum number. This is inditaced in the quastion: since the orbital is 4p, the "p" indicates that the angular momentum quantum number is 1.

The magnetic quantum number can only be -1, 0 or +1.

The only alternative with one os these is alternative A.

Which of the following statements does not describe the structure of an atom?

The electron cloud is a small and compacted space around the nucleus.

Inside the nucleus of an atom are protons and neutrons.

Protons are positively charged sub-atomic particles.

Electrons are negatively charged sub-atomic particles.

Answers

Answer:

A. The electron cloud is a small and compacted space around the nucleus.

Explanation:

Hope this helps! :))

A patient turns in a sample of urine for specific gravity test. The lab results record a value of1.024. What is the density of this patient's urine?

Answers

Specific gravity is the same concept for relative density. This measure indicates the density with respect to the density of water at standard temperature. The formula is:

[tex]\text{Specific gravity = }\frac{density\text{ of substance}}{density\text{ of water}},[/tex]

If we are comparing pure water, the density of this would be 1.00 g/mL, so clearing the formula and replacing, we're going to have:

[tex]\begin{gathered} \text{density of substance (urine) = specific gravity }\cdot\text{ density of water,} \\ \text{density of urine = 1.024 }\cdot\text{ 1.00}\frac{g}{mL}, \\ \text{density of urine = 1.024 }\frac{g}{mL}. \end{gathered}[/tex]

The density of the patient's urine is 1.024 g/mL if the specific gravity is 1.024.

Tablet salt (sodium chloride) is an example of a(n): A) element B) compound C) mixture

Answers

Sodium chloride contains sodium and chlorine in its structure. Both are elemens, which means that sodium chloride is a compound.

It is not a mixture since it is not made of 2 different substance. It is a substance made of 2 elements, which means it is a compound.

The correct answer is B) compound.

39.When the polyatomic ion (SO4)-2 combines with the iron (III) ion, Fe+3, the formula for the compound is...Select one:a. FeSO4b. Fe2SO4c. Fe2(SO4)3d. Fe3(SO4)2

Answers

Answer

c. Fe2(SO4)3

Explanation

The polyatomic ion (SO₄)⁻² has a net charge of -2 and iron (III) ion, Fe⁺³ has an oxidation number of +3. For a compound to be formed between them, two of Fe⁺³ will need three of the polyatomic ion, (SO₄)⁻² and the formula of the compound will be Fe2(SO4)3.

Predict the products of the reaction described above (Information Section).Ca(NO3)2 + Li > _______ + _____

Answers

Answer:[tex]Ca(NO_3)_2+2L\imaginaryI\operatorname{\rightarrow}Ca+2L\imaginaryI NO_3[/tex]

Explanations

A chemical reaction is known to be balanced if the number of elements on the reactant side is equal to that of the product.

Given the reactant of a chemical reaction between calcium nitrate and Lithium, the balanced reaction is given as:

[tex]Ca(NO_3)_2+2Li\rightarrow Ca+2LiNO_3[/tex]

Hence the product of the balanced chemical reaction are Calcium and Lithium Nitrate.

CanvasX &Question 16Consider the reaction: 4Na(s) + O2(8) → 2Na2O(s)

Answers

ANSWER

The mass of Na2O in grams is 123.49 grams

EXPLANATION:

Given information

The mass of sodium is 91 grams

The mass of oxygen is 34.0 grams

To find the amount of Na2O produced, follow the steps below

Step 1: Write the balanced equation of the reaction

[tex]\text{ 4Na}_{(s)}\text{ + O}_{2(g)}\rightarrow\text{ 2Na}_2O_{(S)}[/tex]

Step 2: Find the number of moles of sodium and oxygen using the formula below

[tex]\text{ Mole = }\frac{\text{ mass}}{molar\text{ mass}}[/tex]

Recall, that the molar mass of Na is 22.989 g/mol, and the molar mass of oxygen atom is 32 g/mol

For Na

[tex]\begin{gathered} \text{ Mole = }\frac{mass}{molar\text{ mass}} \\ \text{ Mole = }\frac{91.6}{22.989} \\ \text{ Mole = 3.985 moles} \end{gathered}[/tex]

For O2

[tex]\begin{gathered} \text{ Mole = }\frac{mass}{molar\text{ mass}} \\ \text{ } \\ \text{ Mole = }\frac{34}{32} \\ \text{ Mole = 1.0625 moles} \end{gathered}[/tex]

Step 3: Find the limiting reactant of the reaction

The limiting reactant is the reactant that has the least number of moles after dividing it by the coefficient of the reactant

From the reaction above, you will see that 4 moles of sodium react with one mole of oxygen to give 2 moles of sodium oxide.

For Na

[tex]\begin{gathered} \text{ Na = }\frac{\text{ number of moles}}{\text{ coefficient}} \\ \text{ Na = }\frac{3.985}{4} \\ \text{ Na = 0.99625 mole/wt} \\ \\ \text{ For O}_2 \\ \text{ O}_2\text{ = }\frac{1.0625}{1} \\ \text{ O}_2\text{ = 1.0625 moles/wt} \end{gathered}[/tex]

From the above calculations, you will see that Na has the least number of moles, hence, Na is the limiting reactant

Step 4: Find the number of moles of Na2O

The Na2O can be determined using a stoichiometric ratio

Let x represents the number of moles

[tex]\begin{gathered} \text{ 4 moles of Na }\rightarrow\text{ 2 moles of Na}_2O \\ 3.985\text{ moles of Na }\rightarrow\text{ x moles of Na}_2O \\ \text{ cross multiply} \\ \text{ 4 moles of Na }\times\text{ x moles of Na}_2O\text{ = 2 moles of Na}_2O\times3.985\text{ moles of Na} \\ \text{ x moles of Na}_2O\text{ = }\frac{2\cancel{moles\text{ of Na}_2}O\times3.985\cancel{moles\text{ of Na}}}{4\cancel{moles\text{ of Na}}} \\ \text{ x moles of Na}_2O\text{ = }\frac{2\times\text{ 3.985}}{4} \\ \text{ X moles of Na}_2O\text{ = 1.9925 moles} \end{gathered}[/tex]

Hence, the number of moles of Na2O is 1.9925 moles

Step 5: Find the mass of Na2O

[tex]\begin{gathered} \text{ Mole = }\frac{\text{ mass}}{\text{ molar mass}} \\ \end{gathered}[/tex]

Recall, that the molar mass of Na2O is 61.9789 g/mol

[tex]\begin{gathered} \text{ 1.9925 = }\frac{\text{ mass}}{61.978} \\ \text{ Cross multiply} \\ \text{ Mass = 1.9925}\times61.978 \\ \text{ Mass = 123.49 grams} \end{gathered}[/tex]

Hence, the mass of Na2O in grams is 123.49 grams

How many moles are in 95 grams of aluminum (AI)?

Answers

ANSWER

3.52 moles are in 95 grams of aluminum

STEP-BY-STEP EXPLANATION:

As you can see from the question provided, you are asked to find the moles of aluminum

Given data

Mass of aluminum = 95 grams

To find the moles of aluminum, we will need to apply the below formula

[tex]\text{ Mole }=\text{ }\frac{\text{ reacting mass}}{\text{molar mass}}[/tex]

From the question provided, you can see that the molar mass of aluminum was given

From your periodic table, you will see that the molar mass of aluminum is 27 g/mol

Molar mass of aluminum = 27g/mol

The next thing is to substitute the data given in the above formula

[tex]\begin{gathered} \text{ Mole = }\frac{95}{27} \\ \text{mole = }3.52\text{ g/mol} \end{gathered}[/tex]

Therefore, we have 3.52 moles are in 95 grams of aluminum

Predict the products for each of the following reactions. Write the molecular equation, the complete ionic equation, and the net ionic equation. Classify the reactions in as many ways as you can.

Aqueous sodium carbonate is added to aqueous hydrochloric acid.

Answers

The equation that is the net description of the ions involved is;[tex]CO_{3} ^{2-} (aq) + 2H^{+} (aq)----- > H_{2} O(l) + CO_{2} (g)[/tex]

What is the net ionic equation?

The term net ionic equation has to do with the final ionic equation which does not include the spectator ions. What I mean by the spectator ions are those ions that do not undergo a change in a chemical reaction. The first step when we want to write the net ionic equation is first to write down the molecular equation and balance the equation accordingly.

We shall now show the balanced overall reaction equation of the process

Thus, the balanced molecular equation of this reaction is; [tex]Na_{2} CO_{3} (aq) +2 HCl(aq) ----- > NaCl(aq) +H_{2} O(l) + CO_{2} (g)[/tex]

The net ionic equation is;

[tex]CO_{3} ^{2-} (aq) + 2H^{+} (aq)----- > H_{2} O(l) + CO_{2} (g)[/tex]

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Use the concentrations given to determine whether each of the following is acidic, neutral, or basic.A. [H+] = 4.3 × 10-3 mol/LB. [H+] = 9.8 × 10-12 mol/LC. [OH-] = 4.8 × 10-2 mol/L

Answers

We have the concentration of H+ ions, from these concentrations we can find the pH values of the solutions with the following equation:

[tex]pH=-log\lbrack H^+\rbrack[/tex]

Where [H+] is the concentration of H+ ions.

Now, the acidity or basicity of a solution depends on the pH value. A solution above 7 will be basic, below 7 will be acidic, and equal to 7 will be neutral.

Let's determine the pH value for each solution:

[tex]\begin{gathered} pH=-log\lbrack4.3\times10^{-3}mol/L\rbrack \\ pH=2.4 \end{gathered}[/tex][tex]\begin{gathered} pH=-log\lbrack9.8\times10^{-12}mol/L\rbrack \\ pH=11.0 \end{gathered}[/tex][tex]\begin{gathered} pH=-log\lbrack4.8\times10^{-2}mol/L\rbrack \\ pH=1.3 \end{gathered}[/tex]

So, we have that:

A. [H+] = 4.3 × 10-3 mol/L. pH=2.4. Acidic

B. [H+] = 9.8 × 10-12 mol/L pH = 11.0 Basic

C. [OH-] = 4.8 × 10-2 mol/L pH=1.3 Acidic



2. Oxygen gas is collected at a pressure of 123 kPa in a container which has a volumeof 10.0 L. What temperature must be maintained on 0.654 moles of this gas in order tomaintain this pressure? Express the temperature in Kelvin.

Answers

Answer

T = 226.21 K

Explanation

Given:

Pressure = 123 kPa

Volume = 10.0 L

number of moles = 0.654 moles

We know R = 8.314 L kPa/mol k.

Required: Temperature

Solution:

Pv = nRT

T = PV/nR

T = (123 kPa x 10.0 L)/(0.654 mol x 8.314 L kPa/mol k)

T = 226.21 K

Sn +Cl————SnCl4what is the limiting reactant when 15.7 g of tin reacts with 17.4 of chlorine? what mass of tin chloride can be formed?

Answers

Cl is the limiting reactant and the mass of tin chloride that can be formed is 31.9g.

- First, we need to balance the equation:

[tex]Sn\text{ + 4 Cl }\rightarrow SnCl_4[/tex]

- Second, we need to know the molar weight of the compounds:

Sn: 118.7 g/mol

Cl: 35.5 g/mol

SnCl4: 260.7 g/mol

- Third, we need to know how much Sn can react with Cl according to the balanced equation:

[tex]\frac{15.7g\text{ . 142g}}{118.7g}=\text{ 18.8 g}[/tex]

If 118.7g of Sn needs 142g of Cl to react according to the balanced equation, we found that the 15.7g of Sn will need 18.8g of Cl to complete the reaction.

As we have 17.4g of Cl available, we can see that we are going to need more Cl and therefore Cl is the limiting reactant.

- Now, to find the mass of tin chloride that can be formed, we use the limiting reactant amount for the calculation:

[tex]\frac{17.4g\text{ . 260.7g}}{142g}=31.9\text{ g}[/tex]

According to the balanced equation we need 142g of Cl to produce 260.7g of tin chloride, so with 17.4g of chlorine we will obtain 260.7g of SnCl4.

So, the mass of tin chloride that can be formed is 31.9g.

9. Which of the following shows whose model?a. Bohrb. Daltonc. Rutherfordd. Thomson

Answers

Answer

d. Thomson

Explanation

The given model shown above is Thomson's model of an atom.

In 1898, J. J. Thomson proposed that an atom is shaped like a sphere with a radius of approximately 10⁻¹⁰m, where the positive charge is uniformly distributed as shown in the model given. The electrons are embedded in this sphere so as to give the most stable electrostatic arrangement.

Thus, Thomson's model of an atom is also referred to as the watermelon model, the plum pudding model or the raisin pudding model.

An important aspect of Thomson's model of an atom is that it assumes that the mass of the atom is uniformly distributed over the atom. The model was successful in explaining the overall neutrality of the atom.

i need help with chemistry

Answers

Answer:

2.04×10^25

Explanation:

multiply with 10^9

Fill in the Blanks
Type your answers in all of the blanks and submit
- current answer: When solid potassium chlorate is heated in the laboratory it decomposes to form potassium chloride and oxygen. Consider this reaction to answer the questions below: When properly balanced the sum of the coefficients for this reaction = - 7 -. When you decompose 71.7 grams of potassium chlorate you can form a maximum of - blank2 -grams of potassium chloride and - blank3 -grams of oxygen.



When solid potassium chlorate is heated in the laboratory it decomposes to form potassium chloride and oxygen.
Consider this reaction to answer the questions below:
When properly balanced the sum of the coefficients for this reaction =
blank1 - Word Answer
7
.
When you decompose 71.7 grams of potassium chlorate you can form a maximum of
blank2 - Word Answer

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grams of potassium chloride and
blank3 - Word Answer

grams of oxygen.
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Answers

Answer:

The correct answer is option C. Slavery is a degrading institution to all those involved. Explanation: As Douglass narrates, slavery not only degrades slaves, but slavers asWhich of the following sentences best describes Douglass’s opinion about slavery?

Add 43.8lbs and 56.8923lbs. What is the answer in the correct significant figures?

Answers

The answer in correct significant figures of the addition of the two numbers mentioned is 100.70.

What are significant figures?

Significant figures are used for establishment  of a number which is presented in the form of digits. These digits give a meaningful representation  to the numbers.

The significant figures are the significant digits which convey the meaning according to the accuracy. These provide precision to the numbers and hence are called as significant numbers.There are rules for counting significant figures which are as follows:

1)All non-zero digits are significant .

2)All zeroes which occur between non-zero digits are significant.

3)All zeroes to the left and right of  a non-zero digit are not significant.

4) All zeroes on right  of decimal are significant if a non-zero number follows them.

5)All zeroes on right side of non-zero digit are significant.

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PLEASE HELPPP! It’s due today! Will Mark Brainliest!
Usually scientists will a large isotope such as Uranium-235 with a ____.
The collision results in several more nuclear fissions, also known as a ____. This results in a HUGE release in energy!

Answers

Answer:

Fission and fusion

Explanation: Fission and fusion are two physical processes that produce massive amounts of energy from atoms.

Hope this helps!

Create a diagram of your electroplating apparatus (an electrolytic cell). Then submit your drawing with the following terms labeled correctly. Or, beginning with the positive terminal of the battery and ending with the negative terminal of the battery, describe the path that the electricity takes and where each of the following occurs: anodecathodecopper stripbatterypositive terminalnegative terminalplace where oxidation occursplace where reduction occurselectrolyte solutioncoin (or nail)direction of electron flow

Answers

Please, look at the next drawing:

Electrolytic cell: Electrical energy is used to drive nonspontaneous redox reactions.

Oxidation half-reaction: Z- => Z + e- (anode)

Reduction half-reaction: Y+ + e- => Y (cathode)

ic

Experiment 2: Copper(II) carbonate hydroxide produces one mole of water (=18.015 g/mol) for every two moles of solid product (=79.545 g/mol) produced. If 3.597 g of solid product were produced during the reaction, how many grams of water were realeased as water vapor?

Answers

The answer is 0.4073 and the explanation is in the picture.

Which of the following formulas represent valid ionic compounds that can be made from these six elements: Al, Be, F, Li, N, and S? Select all that apply. A. AlN B. BeS C. AlLi D. LiF

Answers

The compound AlN, BeS, and LiF represents valid ionic compounds.

Ionic bonding:-

When all of the electrons are successfully transferred from one element to another, this sort of bonding is created. One element in this bonding is always a metal, whereas the other is invariably a non-metal.Thus, Al, Be, Li are metals and F, N, S are nonmetals which can form ionic bonding with each other. So, AlLi (Option C) rules out.Considering option A: - AlNThe valency of aluminum is  3 and nitrogen is of 3. The valency of the cations and the anions must be switched and subscripted in order to identify the ionic compound. Thus,

                          Al         N

                           3          3

Simplest ratio : -  1            1

AlN is an ionic compound and thus it is a valid ionic compound.The valency of beryllium is 2 and sulfur of 2. The valency of the cations and the anions are switched and put in subscripts to create the ionic compound. Thus,

                          Be         S

                           2          2

Simplest ratio : -  1            1

The ionic compound created is (b) BeS, making it a legitimate ionic compound.Fluorine and lithium both have valencies of 1. The valency of the cations and the anions are switched and put in subscripts to determine the ionic compound. Thus,

                         Li           F

                          1            1

The ionic compound created is (d) LiF, making it a legitimate ionic compound.

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Calculate the shortest wavelength of light capable of dissociating the Cl–Cl bond in one molecule of chlorine if the bond energy, or bond dissociation energy, is 243 kJ/mol .

Answers

The shortest wavelength of light capable of dissociating the Cl–Cl bond in one molecule of chlorine is 493 nanometer.

The formula to calculate Energy is given as follows :

E = BE / Na

E = energy

BE = bond energy = 243 KJ / mol

Na = Avogadro number = 6.02 × 10²³

substituting the values in the formula:

E = 243 × 10³ / 6.02 × 10²³

E = 4.03 × 10⁻¹⁹ J

By using Einstein equation for photon , we can calculate the shortest wavelength :

E = (h c) / λ

E = energy

h = Planck constant = 6.626 × 10⁻³⁴ J.s

c = speed of light =  3 × 10⁸ m/s

λ = wavelength

therefore,

λ = (hc )/ E

λ =( 6.626 × 10⁻³⁴ J.s × 3 × 10⁸ m/s ) /  4.03 × 10⁻¹⁹ J

λ = 4.93 × 10⁻⁷ m

λ = 493 × 10 ⁻⁹ m

1 nm = 1 × 10 ⁻⁹ m

Shortest wavelength = 493 nanometer.

Thus, The shortest wavelength of light capable of dissociating the Cl–Cl bond in one molecule of chlorine if the bond energy, or bond dissociation energy, is 243 kJ/mol  is 493 nanometer.

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Balance the chemical equation below using the smallest possible whole number stoichiometric coefficients.
Na(s) + O₂(g) → Na₂O₂ (s)

Answers

Answer: 2Na(s)+O₂(g) → Na₂O₂ (s)

Explanation: Since there is only one sodium on the left side of the equation and 2 on the right all you have to do is put a 2 in front of the sodium on the left

can someone please help me with question 27 B please!

Answers

Answer:

Sodium carbonate + Nitric acid → sodium nitrate + water + carbon dioxide. - To write the balanced chemical reaction between sodium carbonate and nitric acid we should know the chemical formula of them. - The chemical formula of sodium carbonate is Na2CO3 and the chemical formula of nitric acid is HNO3

Explanation:

hope it help

- 47 Celsius to kelvin

Answers

Answer

226 K

Explanation

To change from C to K, you add 273

Therefore -47 C + 273 = 226 K

T

______ oil drop experiment measured the size of the ____ on the____ .

Answers

Millikan's oil drop experiment measured the size of the electric charge on the electron.

What is an Experiment?

This is referred to as a type of procedure which is carried out in other to accept or refute a hypothesis. Electron on the other hand, is the negatively charged subatomic particle which is present in an atom and are involved in the formation of new substances during a chemical reaction.

Millikan's oil drop experiment measured the size of the electric charge on the electron and used tiny drops of oil which helped in the calculation of the charge and the mass of an electron.

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explain the process of photosynthesis with these

Words:
Photosynthesis,
light,
water,
energy,
Carbon Dioxide,
Oxygen,
xylem,
stomata,
Sugar(Glucose),
phloem,
chloroplasts,
leaves,
roots

Be legible and neat please and thank you

Answers

Explanation:

PHOTOSYNTHESIS

This is a process in which green plants and other organisms such as bacteria and algae manufacture their own food from simple inorganic matters such as sunlight,CO2,water to produce O2,glucose and water .Plants gets water and minerals when the roots absorbs from the ground,Xylem transports water and mineral salts from the roots to all parts of the plant i.e leaves.Photosynthesis takes place in the leaves where Co2 diffuse to a leaf via the stomata and reach the chloroplast.The chloroplast maximize absorption of sunlight energy.At the end of the process,water,oxygen and glucose is produced.The manufactured food is transported to all parts of a plant from the leaves via the Phloem tissues.

Using the Mole: Empirical Formulas, Molecular Formulas, % Composition5. Potassium persulfate was used in photography to remove the last traces of hypo from photographic papers and plates, A 0,8162 g sample was found to contain 0,2361 g of potassium, 0.1936 g of sulfur, and the rest was oxygen. The formula weight of this compound was measured to be 270. What are the empirical and molecular formulas of this compound?

Answers

Answer:

Molecular formula = KSO4.

Empirical formula = K2S2O4.

Explanation:

What is given?

Mass of K (potassium) = 0.2361 g.

Mass of S (sulfur) = 0.1936 g.

Mass of O (oxygen) = 0.8162 g - 0.2361 g - 0.1936 g = 0.3865 g.

Molar mass of K = 39.1 g/mol.

Molar mass of S = 32 g/mol.

Molar mass of O = 16 g/mol.

Weight of compound = 270 g/mol.

Step-by-step solution:

Remember that empirical formulas show the simplest whole-number ratio of atoms in a compound, and molecular formulas show the number of each type of atom in a molecule. So first, let's see what would be the molecular formula:

Let's find the number of moles of each element using its molar mass:

[tex]\begin{gathered} 0.2361\text{ g K}\cdot\frac{1\text{ mol K}}{39.1\text{ g K}}=0.006038\text{ moles K,} \\ 0.1936\text{ g S}\cdot\frac{1\text{ mol S}}{32\text{g S}}=0.006050\text{ moles S,} \\ 0.3865\text{ g O}\cdot\frac{1\text{ mol O}}{16\text{ g O}}=0.02416\text{ moles O.} \end{gathered}[/tex]

The next step is to divide each number of moles obtained by the least number of moles, in this case, the least number is 0.006038:

[tex]\begin{gathered} 0.006038\text{ moles K/0.006038=1 mol K,} \\ 0.006050\text{ moles S/0.006038 =}1.001\text{ moles S}\approx1\text{ mol S,} \\ 0.02416\text{ moles O/0.006038=4.001 moles O}\approx\text{4 moles O.} \end{gathered}[/tex]

Our molecular formula would contain 1 mol of K, 1 mol of S, and 4 moles of O, so it would be KSO4.

But remember that we need to find the empirical formula too, based on the molecular weight. In the statement, they're telling us that the molecular weight is 270 g/mol, but the molecular weight of KSO4 is 135 g/mol (you can calculate it using the given molar masses and by doing an algebraic sum). So, to obtain the empirical formula with 270 g/mol as molecular weight, we have to multiply by two each number of moles of the compound (135 g/mol * 2 = 270 g/mol):

[tex]\begin{gathered} 1\text{ mol K}\cdot2=2\text{ moles K,} \\ 1\text{ mol S}\cdot2=2\text{ moles S,} \\ 4\text{ moles O }\cdot2=8\text{ moles O.} \end{gathered}[/tex]

So, you can realize that K2S2O4 would be the empirical formula because its molecular weight would be 270 g/mol.

Molecular formula = KSO4.

Empirical formula = K2S2O4.

When dealing with diatomic elements like oxygen, the atoms are not separate; they always come in pairs. Therefore, one mole of oxygen molecules would weigh _______ grams and not 16 grams

Answers

Answer:

32 grams

Explanations:What are diatomic elements?

Diatomic elements are elements that contain two atoms chemically bonded together.

When looking for the molar mass of a diatomic element, the number of atoms in the element is multiplied by the molar mass of the element.

For instance, oxygen is a diatomic element with the chemical symbol of O₂. This shows that the molar mass of oxygen will be given as:

[tex]\begin{gathered} molar\text{ mass of O}_₂=2\times16g\text{/mol} \\ molar\text{ mass of }O_2=32g\text{/}mol \end{gathered}[/tex]

This shows that one mole of oxygen molecules would weigh 32 grams and not 16 grams.

Hydrochloric acid is prepared by bubbling hydrogen chloride gas through water. What is the concentration of a solution prepared by dissolving 225 l of hcl g at 37

Answers

Answer:

149 M

Explanation:

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