Al sumar su doble, su mitad y 15 se obtiene 99.
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Answer:

x^4n^4

Step-by-step explanation:

Answer:

[tex]n^{4} x^{4}[/tex]  

I really hope this helps!

Answer:

10%

Step-by-step explanation:

10% i think

Answer:

24units

Step-by-step explanation:

2(4y + 3) + 2(5y - 1) = 94

18y + 4 = 94

y = 5

WX = 5y - 1 = 5(5) - 1 = 24units

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First we need to find the value of y .

[tex]Perimeter = 2 \times ( \: (4y + 3) + (5y - 1) \: ) \\ [/tex]

[tex]Perimeter = 2 \times (9y + 2)[/tex]

[tex]Perimeter = 18y + 4[/tex]

Question told us that perimeter is 94 ,

Thus :

[tex]94 = 18y + 4[/tex]

[tex]18y + 4 = 94[/tex]

Subtract sides 4

[tex]18y + 4 - 4 = 94 - 4[/tex]

[tex]18y = 90[/tex]

Divide sides by 18

[tex] \frac{18y}{18} = \frac{90}{18} \\ [/tex]

[tex]y = 5[/tex]

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The face sides in the rectangular are same.

Thus :

[tex]VY = WX[/tex]

So ;

[tex] WX = 5y - 1[/tex]

[tex]WX = 5(5) - 1[/tex]

[tex]WX = 25 - 1[/tex]

[tex]WX = 24[/tex]

Done...

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Answer:

D

Step-by-step explanation:

Answer:

The cannonball lands at approximately 5.093 unit distance from the point of fire

Step-by-step explanation:

The given parameters are;

The arc denoting the equation of motion of the cannon is y₁ = -0.5·x² + 2.5·x + 1

The slope of the field where in the direction the cannon is fired is y₂ = 1.5·x

The points where the cannonball land on the slopping field is given as rightly pointed by equating the two equations, the cannonball path path and the field path as follows;

At the point of contact of the cannonball and the field, the y-values of both equation will be equal

y₁ = y₂

∴ -0.5·x² + 2.5·x + 1 = 0.15·x

Which gives;

-0.5·x² + 2.5·x - 0.15·x + 1 = 0

-0.5·x² + 2.35·x + 1 = 0

-(-0.5·x² + 2.35·x + 1) = 0.5·x² - 2.35·x - 1 = 0

0.5·x² - 2.35·x - 1 = 0

The above equation is in the general form of a quadratic equation, which is given as follows;

a·x² + b·x + c = 0

By the quadratic equation, we have;

[tex]x = \dfrac{-b\pm \sqrt{b^{2}-4\cdot a\cdot c}}{2\cdot a}[/tex]

Plugging in the values, gives;

[tex]x = \dfrac{2.35\pm \sqrt{(2.35)^{2}-4\cdot (0.5)\times (-1)}}{2\cdot (0.5)} = \dfrac{2.35\pm \sqrt{7.5225}}{1} =2.35 \pm \sqrt{7.5225}[/tex]

∴ x ≈ 5.093 or x ≈ -0.393

Therefore, the cannonball will takeoff at x ≈ -0.393 and land at x ≈ 5.093

The height from which they fire the cannon is given by the substituting the value of x ≈ -0.393 into the equation for the path of the cannonball, to give;

[tex]y_{(initial)}[/tex] = -0.5·(-0.393)² + 2.5·(-0.393) + 1 = -0.0597

[tex]y_{(initial)}[/tex] ≈ -0.0597.

However, the actual initial height from which the cannonball is fired given by placing x = 0, which gives y = 1, which is the reason for the other (negative) value for x. Please see the attached graph created with Microsoft Excel.

Answer:

A defensive way is use all your might to jump when the ball is coming at you, because as you might know is it takes a lot of effert to jump in a pool, the gravity is very strong in the pool! Or if you get the ball you can throw and swing your arm as strong as you can a HIT that ball! You wanna hit it hard so the players on the other side of the pool don’t get the ball,instead it will go over them and you WIN!

Step-by-step explanation:

Hope this helped :)✨

Answer:

71 miles in 1 hour

Step-by-step explanation:

divide the total amount of miles by the total amount of hours: 335/5

you get 71 mph

Answer:

71 miles per hour

Step-by-step explanation:

355 divided by 5 is 71

71 x 5 = 355

355 divided by 71 is 5

Answer:

a= -5/8

b= -4/7

c= -2/5

Step-by-step explanation:

8a + 5 = 7b + 4 =5c + 2

I'm not sure what you want with this incomplete question, but I assume it's to find the values of a, b, and c.

Therefore, to find the value of a,

8a+5=0

8a= - 5

a= -5/8

7b + 4=0

7b = - 4

b= -4/7

5c + 2=0

5c= - 2

c= -2/5

Therefore, the values of a, b, and c are -5/8, -4/7 and -2/5

Answer: the answers are the second one and the last one

Step-by-step explanation:

Answer:

probably A

Step-by-step explanation:

Answer:

because AC and BD bis => AX = XC; BX = XD

ΔAXD ≅ ΔCXB (SAS) because: AX = CX

                                                    DX = BX

                                                    m∠AXD = m∠BXC ( 2 opposing angles)

because ΔAXD ≅ ΔCXB (SAS)

=> AD = BC and m∠DAX = m∠BCX

because m∠DAX = m∠BCX => AD//BC

ABCD has AD = BC and AD//BC => ABCD is a parallelogram

Step-by-step explanation:

Answer:

[tex]-\frac{2}{3}[/tex]

Step-by-step explanation:

Answer:

measure of angle 2 and angle 3 are both 97

Step-by-step explanation:

angle 2 and angle 3 are vertical angles

Answer:

Just use a calcultor...

Step-by-step explanation:

Answer:

Step-by-step explanation:

4x + 6x + y = 180

6x + y = x + 5y

10x + y = 180 ........... (1)

5x - 4y = 0 .............. (2)

(1) - 2 × (2)

y + 8y = 180 ⇒ y = 20

6x + 20 = x + 100 ⇔ 5x = 80 ⇒ x = 16

64° , 116°

Answer:

are you missing a option because for me one option that has the same exact numbers that you mentioned is the cost of 8 hats is 60

Step-by-step explanation:

Answer:

The answer is A

Step-by-step explanation:

Camie: $5x + $50 = $55 ( for now/i think)

Jorge: $7x

The  equation to represent  Jorge has saved at least the same amount as Camie is 7w = 5W + 50.

The correct option is (A)

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side. It demonstrates the equality of the relationship between the expressions printed on the left and right sides. We have LHS = RHS (left hand side = right hand side) in every mathematical equation.

To determine the value of an unknown variable that represents an unknown quantity, equations can be solved. A statement is not an equation if it has no "equal to" sign.

Given:

Camie saves $5 per week plus $50 she receives for her birthday.

Jorge saves $7 per week.

Now, Jorge have to achieve the same amount as Camie.

let w be the number of weeks.

Then equation can be represented as

7w = 5W + 50

Here 7w is amount by Jorge and 5W + 50 is amount of Camie.

Hence, the equation to represent  Jorge has saved at least the same amount as Camie is 7w = 5W + 50.

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Answer:

Can confirm, it’s a=16.23 and b=17.99

Answer:

90.6

Step-by-step explanation:

that what i think and thanks

Answer:

its c i took the test trust me

Step-by-step explanation:

Answer:

PQ=30

Step-by-step explanation:

Knowing that the segment has 3 parts that are 3:1:1 and sum up to 50, you could find how much 1 would equal by finding the total in relation to the ratio (doing 3+1+1) which gets you 5 parts. Then you can divide the total (50) by 5 to figure out how much one part would equal (10). Now, since you know that 1 part is equal to 10 and that PQ is 3 parts, you can find that PQ is equal to 3x10, or 30.

Answer:

vertical line

Step-by-step explanation:

If it is possible to draw any vertical line (a line of constant x) which crosses the graph of the relation more than once, then the relation is not a function.

Answer:

the answer is b

Step-by-step explanation

Answer:

C. There is one solution, because the coefficients of the variables on both sides of the equation are different.

Step-by-step explanation:

The solution is m = 1

~theLocoCoco

Answer: There are four and one-fourth cups of dry ingredients are in the cake mix.

Step-by-step explanation:

Given: Quantities of dry ingredients for cake:

2 cups of flour, [tex]\dfrac32[/tex] cups of sugar, and [tex]\dfrac34[/tex] cup of cocoa.

Total cups of ingredients used = [tex]2+\dfrac32+\dfrac34[/tex]

[tex]\dfrac{2\times4+3\times2+3}{4}\\\\=\dfrac{8+6+3}{4}\\\\=\dfrac{17}{4}\\\\=\dfrac{16+1}{4}\\\\=4\dfrac14\text{ cups}[/tex]

Hence, there are four and one-fourth cups of dry ingredients are in the cake mix.

(i) The coordinates of the point Q is [tex](x, y) = (21, 0)[/tex].

(ii) The equation of the curve is [tex]y = 6\cdot \ln (2\cdot x + 1)-1.592[/tex].

(iii) The rate of increase of the y-coordinate is 1.2 units per second.

(i) By analytical geometry, we know that the slope of a line normal of a curve ([tex]m_{\perp}[/tex]) by the following expression:

[tex]m_{\perp} = - \frac{1}{\frac{dy}{dx} }[/tex] (1)

Where [tex]\frac{dy}{dx}[/tex] is the slope of the line tangent to the curve.

If we know that [tex]x = 1[/tex], then the slope of the normal to the curve is:

[tex]\frac{dy}{dx} = \frac{12}{2\cdot (1)+1}[/tex]

[tex]\frac{dy}{dx} = 4[/tex]

And the slope of a line normal of a curve is:

[tex]m_{\perp} = -\frac{1}{4}[/tex]

By definition of secant curve we calculate the remaining coordinate of the point Q:

[tex]m_{\perp} = \frac{y_{Q}-y_{P}}{x_{Q}-x_{P}}[/tex] (2)

Where:

If we know that [tex](x_{P}, y_{P}) = (1, 5)[/tex], [tex](x_{Q}, y_{Q}) = (x, 0)[/tex] and [tex]m_{\perp} = -\frac{1}{4}[/tex], then the remaining coordinate of point Q is:

[tex]-\frac{1}{4} = \frac{0-5}{x-1}[/tex]

[tex]-\frac{1}{4}\cdot (x-1) = -5[/tex]

[tex]-\frac{1}{4}\cdot x +\frac{1}{4} = -5[/tex]

[tex]\frac{1}{4}\cdot x = \frac{21}{4}[/tex]

[tex]x = 21[/tex]

The coordinates of the point Q is [tex](x, y) = (21, 0)[/tex].

(ii) The equation of the curve is derived by separating the variables and integrating the resulting expression:

[tex]dy = \frac{12}{2\cdot x + 1}\,dx[/tex]

[tex]\int\, dy = 6\int {\frac{2\,dx}{2\cdot x + 1} }[/tex]

[tex]\int \, dy = 6\int {\frac{du}{u} }[/tex]

[tex]y = 6\cdot \ln u[/tex]

[tex]y = 6\cdot \ln (2\cdot x + 1)+C[/tex]

And the integration constant is found for [tex](x,y) = (1, 5)[/tex]:

[tex]5 = 6\cdot \ln(2\cdot 1 + 1) + C[/tex]

[tex]C = -1.592[/tex]

The equation of the curve is [tex]y = 6\cdot \ln (2\cdot x + 1)-1.592[/tex].

(iii) The rate of increase of the y-coordinate by using the differential equation presented in statement and the definition of rate of change:

[tex]\frac{dy}{dt} = \left(\frac{12}{2\cdot x +1}\right)\cdot \frac{dx}{dt}[/tex] (3)

If we know that [tex]\frac{dx}{dt} = 0.3[/tex] and [tex]x = 1[/tex], then the rate of increase of the y-coordinate is:

[tex]\frac{dy}{dt} = \left[\frac{12}{2\cdot (1)+1} \right]\cdot (0.3)[/tex]

[tex]\frac{dy}{dt} = 1.2[/tex]

The rate of increase of the y-coordinate is 1.2 units per second.

To learn more on differential equations, we kindly invite to check this verified question: https://brainly.com/question/25731911

i). The coordinates of Q is equal to:

[tex](x,y) = (21, 0)[/tex]

ii). The equation of the curve is:

[tex]y = 6. In(2.x + 1) - 1.592[/tex]

iii). The rate of increase for y-coordinate when x = 1:

[tex]1.2 units[/tex] per second

i). Using analytical geometry,

[tex]xp[/tex] and [tex]xq[/tex] are the P and Q's x-coordinates.

[tex]yp[/tex] and [tex]yq[/tex] are the P and Q's y-coordinates.

Since ([tex]xp[/tex], [tex]yp[/tex]) = (1,5) and ( [tex]xq[/tex], [tex]yq[/tex]) = [tex](x, 0)[/tex] and m⊥ = - 1/4, the left coordinate of Q's point:-

-1/4 = (0-5)/(x - 1)

∵[tex]x = 21[/tex]

Thus, the coordinates of y = (21, 0)

ii). Through isolating the variables and employing integration:-

[tex]dy = \frac{12}{(2.x + 1)} dx[/tex]

by integration and integration constant (1,5), the equation is:

[tex]y = 6. In(2.x + 1) - 1.592[/tex]

iii). The rate of increase for y-coordinate:

[tex]dy/dt[/tex] = [tex]\frac{(12)}{(2.1 + 1)} .0.3[/tex]

∵ [tex]dy/dt[/tex] [tex]= 1.2[/tex]

Thus, the rate of increase for y-coordinate when x = 1 is 1.2 units per second.

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