After a warehouse fire, a straight 30 kg pipe fell from the ceiling and rests against a rough concrete floor at point A and a smooth metal wall at point C. There is one remaining cable attached to the center of the pipe and anchored to the corner of a 7 m high ceiling. Determine the reactions at A and C, and the tension in the cable BD.

Answer:

The two charged objects will exert equal and opposite forces on each other.

Explanation:

Coulomb's law states that the electrical force between two charged objects is directly proportional to the product of charges on the objects and inversely proportional to the square of the distance between the two objects.

This force of attraction or repulsion between the two charged objects is always equal and opposite.

Therefore, the two charged objects will exert equal and opposite forces on each other.

Answer:

B. 450 N

Explanation:

Use Hooke's law:

F = kx

150 N = k (1 m)

k = 150 N/m

F = kx

F = (150 N/m) (3 m)

F = 450 N

Answer:

The acceleration of the car is 10.16m/s²

Explanation:

Given parameters:

  Initial velocity = 8.77m/s

   Final velocity = 47.8m/s

   Time duration  = 3.84s

Unknown:

Acceleration of the car = ?

Solution:

To find the acceleration, we must bear in mind that this physical quantity is the change in velocity with time;

     Acceleration  = [tex]\frac{V - U}{T}[/tex]

V is the final velocity

U is the initial velocity

T is the time taken

  Input the parameters and solve for acceleration;

      Acceleration  = [tex]\frac{47.8 - 8.77}{3.84}[/tex]   = 10.16m/s²

The acceleration of the car is 10.16m/s²

Answer:

19.5 m/s

87.8 m

Explanation:

The acceleration of block one is:

∑F = ma

-m₁gμ = m₁a

a = -gμ

a = -(9.8 m/s²) (0.22)

a = -2.16 m/s²

The velocity of block one just before the collision is:

v² = v₀² + 2aΔx

v² = (8.25 m/s)² + 2 (-2.16 m/s²) (2.3 m)

v = 7.63 m/s

Momentum is conserved, so the velocity of block two just after the collision is:

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

m₁u₁ = m₂v₂

(18.5 kg) (7.63 m/s) = (7.25 kg) v

v = 19.5 m/s

The acceleration of block two is also -2.16 m/s², so the distance is:

v² = v₀² + 2aΔx

(0 m/s)² = (19.5 m/s)² + 2 (-2.16 m/s²) Δx

Δx = 87.8 m

The velocity of block 2 and the distance traveled by it prior to being at rest post-collision are 19.5 m/s and 87.8 m. Check the calculations below:

Given that,

[tex]m_{1}[/tex] = 18.5 kg

d = 2.3m

To find,

Acceleration of block 1:

∑[tex]F = ma[/tex]

⇒ -m₁gμ = m₁a

⇒ a = -gμ

⇒ a [tex]= -(9.8 m/s^2) (0.22)[/tex]

∵ a [tex]= -2.16 m/s^2[/tex]

Now,

To determine the velocity of block one prior to the collision:

We know,

The initial velocity of block 1 = 8.25 m/s

⇒ [tex]v^2 = v_{o}^2 + 2[/tex]aΔx

⇒ [tex]v^2 = (8.25 m/s)^2 + 2 (-2.16 m/s^2) (2.3 m)[/tex]

∵ [tex]v = 7.63 m/s[/tex]

We also know,

[tex]m_{2}[/tex] = 7.25 kg

Now,

The velocity of block 2 post collision:

⇒ [tex]m_{1} u_{1} + m_{1} u_{1} = m_{1} v_{1} + m_{2} v_{2}[/tex]post-collision

Through this,

⇒ [tex](18.5 kg) (7.63 m/s) = (7.25 kg) v[/tex]

∵[tex]v = 19.5 m/s[/tex]

The distance can be found through:

⇒ [tex]v^2 = v_{o} ^{2} + 2[/tex][tex]a[/tex]Δ[tex]x[/tex]

⇒ [tex](0 m/s)^2 = (19.5 m/s)^2 + 2 (-2.16 m/s^2)[/tex]Δ[tex]x[/tex]

∵ Δ[tex]x = 87.8 m[/tex]

Thus, 19.5 m/s and 87.8 m are the correct answers.

Learn more about "Friction" here:

brainly.com/question/13357196

Answer:

Covalent Bond

Explanation:

i took the test , mark me brainliest.

Answer: Electrical

Explanation: Atoms are tied together by electrical bonding forces.

Answer:

2nd option on edge2021

Explanation:

Answer:

1.25 g/cm^3

Explanation:

mass-30.0g

volume- 4cm×2cm×3cm=24cm^3

density?

*to find density

Density=Mass/Volume

=30÷24

=1.25g/cm^3

Answer:

(1,)

Explanation:

Answer:

magnitude: 21.6; direction: 33.7°

Explanation:

Answer:

Total energy = Kinetic Energy + Potential Energy = Constant

Since the potential energy is lowest at point D the kinetic energy will be greatest at point D and the velocity will be the greatest.

Answer:

                                                dasgfwe

Explanation:

Answer:

168

Explanation:

Answer: a 15 kg object would weigh the most on Neptune

168 N

Answer: D 160kg object moving 126 m/s

Explanation:

An object having a mass of 162 kg and moving with a velocity of 124 m/sec will require the greatest amount of force to change its motion. The correct option is D.

Force is defined as the push or pull applied to the body. Sometimes it is used to change the shape, size, and direction of the body.

If the object has to stop, the final velocity must be zero. If the time is constant, the amount of force only depends on the mass and the velocity at which the body is moving.

The amount of force on the object depends on the momentum of the body.

The momentum of the body is;

P = mv

Object D will require the greatest amount of force to change its motion. Because the momentum of the body for option D is the greatest.

Hence, the correct option is D.

Learn more about the Force, here;

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#SPJ2

Answer:

options C is correct

Explanation:

asking questions is super in this education life

Answer:

option c should be the answer

Answer:

1- t^3

2- t^2

3- t1

Explanation:

The acceleration produced in a body, while travelling in a circular motion, due to change in direction of motion is called centripetal acceleration. The formula of the centripetal acceleration is as follows:

ac = v²/r

where,

ac = centripetal acceleration

v = speed

r = radius

for a constant radius the centripetal acceleration will be directly proportional to the speed of object. The speed of pendulum will be lowest at t1 due to zero speed initially. Then the speed will increase gradually having greater speed at t^2 and the highest speed and centripetal acceleration at t^3. Therefore, the three instants in tie can be written in following order from greatest centripetal acceleration to lowest:

1- t^3

2- t^2

3- t1

Answer: f= M×A

1.75kg×24= 42N

Explanation:

Because to find force you do Mass times acceleration so I did 1.75 kg times 24 would equal 42 Newtons!

Answer:

35.35 m

Explanation:

The following data were obtained from the question:

Initial velocity (u) = 20 m/s

Angle of projection (θ) = 30°

Acceleration due to gravity (g) = 9.8 m/s²

Range (R) =.?

The range (i.e how far away) of the ball can be obtained as follow:

R = u² Sine 2θ /g

R = 20² Sine (2×30) / 9.8

R = 400 Sine 60 / 9.8

R = (400 × 0866) / 9.8

R = 346.4 / 9.8

R = 35.35 m

Therefore, the range (i.e how far away) of the ball is 35.35 m

Answer:

I think it will get colder

Explanation:

Answer:

The water molecules go faster as it gets colder they go slower

Explanation:

trust me thats the answer

Answer:

9 ft*lb

Explanation:

super simple but you just have to understand that the integral is going with the curve

work = integral a to b of f(x)dx = integral 0 to 9 of 10/(1+x)^2dx = 9ft*lb

Answer:

Correlational research can be used to see if two variables are related and to make predictions based on this relationship.

Answer:

1) x = 30 - 8 t

2) x = -10

3) x = -10 + 5 t

4) x = -10 - 4 t

Explanation:

Motion 1:  constant negative velocity calculated via the points (0, 30) and (5, -10) rendering the equation of motion  x = 30 - 8 t

Motion 2: constant position over time, so the object is not moving, and the equation of motion is x = -10

Motion 3: constant positive velocity estimated via the points (0, -10) and (2, 0), and the equation of motion is:  x = -10 + 5 t

Motion 4: constant negative velocity estimated via the points (0, -10) and (5, -30), and the equation of motion is:  x = -10 - 4 t

The starting position of motion 1 is 30 meters

the starting position for the other 3 motions is - 10 meters. And none of them is accelerated (acceleration = zero for all).

Answer:

Explanation:

graphing is helpful

helps visualize the line

of your equation

Answer:

Average speed

Explanation:

250/50=5

1000/20=5

Answer:

v = 66 m/s

Explanation:

Given that,

The initial velocity of a car, u = 0

Acceleration of the car, a = 11 m/s²

We need to find the final velocity of the toy after 6 seconds.

Let v is the final velocity. It can be calculated using first equation of motion. It is given by :

v = u +at

v = 0 + 11 m/s² × 6 s

v = 66 m/s

So, the final velocity of the car is 66 m/s.

Answer:

The one with the faster velocity is the one with a velocity of -10m/s

Answer:

The  value of the power is   [tex]P_c  =  38.55 \  W [/tex]

Explanation:

From the question we are told that

   The  power  rating [tex]P_{1000} =P_b=  52 \  W[/tex]

    The frequency is  [tex]f = 1000 \  Hz[/tex]

    The  frequency at which the sound intensity decreases  [tex]f_k  =  20 \  Hz[/tex]

     The decrease in intensity is by [tex]\beta  =  1.3 dB[/tex]

Generally the  initial intensity of the speaker  is mathematically represented as

     [tex]\beta_1 =  10 log_{10} [\frac{P_b}{P_a} ][/tex]

Generally the intensity of the speaker after it has been decreased is

       [tex]\beta_2 =  10 log_{10} [\frac{P_c}{P_a} ][/tex]

So

[tex]\beta_1-\beta_2 =  10 log_{10} [\frac{P_c}{P_a} ]- 10 log_{10} [\frac{P_b}{P_a} ][/tex]

=>  [tex]\beta =  10 log_{10} [\frac{P_c}{P_a} ]- 10 log_{10} [\frac{P_b}{P_a} ]= 1.3[/tex]

=>  [tex]\beta =10log_{10} [\frac{\frac{P_b}{P_a}}{\frac{P_c}{P_a}} ] = 1.3[/tex]

=>  [tex]\beta =10log_{10} [\frac{P_b}{P_c} ] = 1.3[/tex]

=> [tex]10log_{10} [\frac{P_b}{P_c} ] = 1.3[/tex]

=> [tex]log_{10} [\frac{P_b}{P_c} ] = 0.13[/tex]

taking atilog of both sides

[tex][\frac{P_b}{P_c} ] = 10^{0.13}[/tex]      

=>[tex][\frac{52}{P_c} ] = 10^{0.13}[/tex]      

=>  [tex]P_c  =  \frac{52}{1.34896}[/tex]

=>   [tex]P_c  =  38.55 \  W [/tex]

Answer:

Platelets

Explanation:

Platelets are tiny blood cells that help your body form clots to stop bleeding. If one of your blood vessels gets damaged, it sends out signals to the platelets. The platelets then rush to the site of damage and form a clot to stop the bleeding.

Answer:

[tex]\boxed {\tt Platelets}[/tex]

Explanation:

There are three main types of blood cells:

We are looking for which blood cell helps clot the blood. From the list above, we can see the best answer is platelets.

Answer:

Explanation:

The question is incomplete. Here is the complete question with attachment below.

In the above figure on the LEFT side, a block (mass = 2.8 kg) starts from rest at the top of a frictionless inline and slides to the bottom. The height of the incline is h=6.5 m, angle