Answer:
3a^2b - 2ab^2 + 8ab
Step-by-step explanation:
just add the like terms
a^b + 2a^2b - ab^2 -ab^2 + 8ab
3a^2b - 2ab^2 + 8ab
The addition of the expressions a²b - ab² + 8ab and 2a²b - ab² will be 3a²b - 2ab² + 8ab.
What is Algebra?Algebra is the study of abstract symbols, while logic is the manipulation of all those ideas.
The acronym PEMDAS stands for Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction. This approach is used to answer the problem correctly and completely.
The expressions are given below.
a²b - ab² + 8ab and 2a²b - ab²
The addition of the expressions a²b - ab² + 8ab and 2a²b - ab² will be given as,
⇒ a²b - ab² + 8ab + 2a²b - ab²
⇒ 3a²b - 2ab² + 8ab
The addition of the expressions a²b - ab² + 8ab and 2a²b - ab² will be 3a²b - 2ab² + 8ab.
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What is the square root of 169
Answer:13
Step-by-step explanation:
13^2
Plz help I’ve been doing this for 6 days
Hi there! :)
t ≥ -22t + 8 ≥ -4(t + 1)
Distribute the coefficient outside of the parenthesis:
2t + 8 ≥ -4(t) -4(1)
2t + 8 ≥ -4t - 4
Add 4t to both sides:
6t + 8 ≥ -4
Subtract 8 from both sides:
6t ≥ -12
Divide both sides by 6:
t ≥ -2.
Answer: t ≥ -2/3
Step-by-step explanation:
Distribute the -4 into (t + 1). 2t + 8 ≥ - 4t - 4Add 4t on both sides. 6t + 8 ≥ -4Subtract 8 on both sides. 6t ≥ -4Divide by 6 on both side. Then , simplify -4/6 by 2 on both the numerator and denominator. t ≥ -2/3Two stores sell CDs in packages, as shown in the table below. CD Prices at Store A Number of CDs in Package 1 12 20 45 Cost $0.70 $8.40 ? $31.50 CD Prices at Store B Number of CDs in Package 1 20 30 65 Cost $0.60 ? $18.00 $39.00 If the rate at each store is constant, which statement correctly compares the cost of a package containing 20 CDs?
Answer:
IT'S A BELIEVE PLZZZZZZZz
Step-by-step explanation:
Answer:
The cost at Store A is $2.00 greater than at Store B.
Step-by-step explanation:
i had the same quiz this was correct
FIRST PERSON TO ANSWER CORRECTLY GETS BRAINLIEST AND 10 POINTS!!!!!!! Click an item in the list or group of pictures at the bottom of the problem and holding the button down drag it into the correct position in the answer box. Release your mouse button when the item is placed if you change your mind drag the item to the trashcan. Click the trashcan to clear all your answers.
Evaluate the following expression. 7^0
Answer:
The answer is 1
Step-by-step explanation:
Which ratios are equivalent to 8 : 12? Select all that apply. A 4 : 6 B 12 : 8 C 16 : 20 D 24 : 36 E 56 : 84
Answer:
A, D, E
Step-by-step explanation:
like with division if you multiply the same thing on both sides it is still equal
The ratios are equivalent to 8 : 12 are A 4 : 6 , D 24 : 36 and E 56 : 84.
Those expressions who might look different but their simplified forms are same expressions are called equivalent expressions.
What is the ratio of two quantities?Suppose that we've got two quantities with measurements as 'a' and 'b'
Then, their ratio(ratio of a to b) a:b
We usually cancel out the common factors from both the numerator and the denominator of the fraction we obtained. Numerator is the upper quantity in the fraction and denominator is the lower quantity in the fraction).
Suppose that we've got a = 8, and b= 12,
[tex]a:b = 8 : 12\\\\ = \dfrac{8}{12} = \dfrac{2 \times 4}{2 \times 6} \\= \dfrac{2}{3} \\\\a : b = 2 : 3[/tex]
So, the ratios are equivalent to 8 : 12
A 4 : 6
D 24 : 36
E 56 : 84
Remember that the ratio should always be taken of quantities with same unit of measurement. Also, ratio is a unitless(no units) quantity.
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Graph [tex]g(x)=\frac{1}{2}|x+2|-3[/tex] as a transformation of [tex]f(x)=|x|[/tex]. Then identify the transformation.
Answer:
see below
Step-by-step explanation:
g(x) = 1/2 | x+2| -3
y = Cf(x) 0 < C < 1 compresses it in the y-direction
y = f(x + C) C > 0 moves it left
y = f(x) + C C < 0 moves it down
1/2 compression in the y direction moved to the left 2 units and down 3 units
Given: g(x) = 1/2|x + 2| - 3
0 < c < 1 means at the y-axis and makes it smaller
y = cf(x)
1/2 compression
c > 0 means that you move it to the left
y = f(x + c)
2 units to the left
c < 0 means that you move it down
y = f(x) + c
3 units down
Best of Luck!
For questions 1 - 6, solve each quadratic equation.
1. (x + 5)(x - 2) = 0
2. (3x - 1)(2x + 5) = 0
3. x^2-3x -4 = 0
4.2x^2 -5x - 3 = 0
5. x^2 - 16 = 0
6.9x^2 - 25 = 0
Answer:
1. -5
2. 1/3 (1 third)
3. -3
4. -1\2 (negative one and a half)
5.-4
6. 1.66666
Step-by-step explanation:
1. Let's solve your equation step-by-step. ( x + 5 ) ( x − 2 ) = 0 Step 1: Simplify both sides of the equation. x 2 + 3 x − 10 = 0 Step 2: Factor left side of equation. ( x − 2 ) ( x + 5 ) = 0 Step 3: Set factors equal to 0. x − 2 = 0 or x + 5 = 0 x = 2 or x = − 5. <—— this is for the first explanation
2. Step 1: Simplify both sides of the equation. 6 x 2 + 13 x − 5 = 0 Step 2: Factor left side of equation. ( 3 x − 1 ) ( 2 x + 5 ) = 0 Step 3: Set factors equal to 0. 3 x − 1 = 0 or 2 x + 5 = 0 x = 1 3 or x = − 5 2 Answer: x = 1 3 or x = − 5 2
<———— this is for the second explanation
3.Step 1: Factor left side of equation. ( x + 1 ) ( x − 4 ) = 0 Step 2: Set factors equal to 0. x + 1 = 0 or x − 4 = 0 x = − 1 or x
<———- this is for the third explanation
4.Step 1: Factor left side of equation. ( 2 x + 1 ) ( x − 3 ) = 0 Step 2: Set factors equal to 0. 2 x + 1 = 0 or x − 3 = 0 x = − 1 2 or x = 3
<—————- this is for the fourth explanation
5. Step 1: Add 16 to both sides. x 2 − 16 + 16 = 0 + 16 x 2 = 16 Step 2: Take square root. x = ± 16 x = 4 or x = − 4
<—————- this is for the fith explanation
6. Step 1: Add 25 to both sides. 9 x 2 − 25 + 25 = 0 + 25 9 x 2 = 25 Step 2: Divide both sides by 9. 9 x 2 9 = 25 9 x 2 = 25 9 Step 3: Take square root. x = ± 25 9 x = 1.666667 , − 1.666667
<—————- this is for the sixth explanation
Hope this helps :)
Dave is driving to Dallas, TX for the weekend from Austin, TX for the weekend. He is traveling along the tollway 130. The speed limit is 80 mph. There are approximately 1.6 kilometers in 1 mile. What is this limit in kilometers per hour?
We need to multiply the 80mph by the 1.6 to make it KPH
When done correctly we get the answer of 128KPH
The limit is 128kph
HOPE THIS HELPED. DONT FORGET TO MARK THIS AS THE BRAINLIEST ANSWER AND GIVE IT A 5 STAR SO OTHER PEOPLE CAN BE HELPED BY THIS ANSWER!! HAVE A NICE DAY!
I didn't understand how C wasn't a correct answer to this problem alongside A, as the only correct answer is A/
Answer: It is A
Step-by-step explanation:
In the given figure D) DC/BC has the same ratio as AB/BC.
What is the interior angle bisector theorem?The interior angle bisector theorem states that in a triangle the angle bisector of an angle divides the opposite side to the angle in the ratio of the remaining two sides.
In ΔABC m∠A = 28° and the ratio is taken for the sides which is opposite to the given angle BC and the side which not base AB.
Given the ratio AB/BC.
∴ In ΔBCD in which m∠B is also 28° we have to take the same sides opposite side is DC and the side which is not the base BC.
So, in the triangles ABC and ABD The ratio which has the same value as AB/BC is BC/DC.
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Help pls i need help !!
Answer:
Ray, Line, Transversal?, Plane, Segment
Step-by-step explanation:
Chase watched a movie about aliens who never stop growing. Every alien is 10 centimeters tall at birth and grows exactly 8 centimeters each year.
Let y represent the number of years since birth and h represent the alien's height in centimeters.
Complete the equation that represents the relationship between y and h.
y h
5 50
6 58
7 66
8 74
h=y+
Answer:
Step-by-step explanation:
Let the height (the dependent variable) be h.
Let the independent variable (x) be y
h = 8y + 10
So at birth, these creatures are 10 cm long. At each birthday, they are another 8 cm.
Take the fifth year which is where the table begins.
y= 8*5 + 10
y = 40 + 10
y = 50 cm which is exactly what you got.
-96 divided by (-12)
Answer:
8
Step-by-step explanation:
The two triangles in the sketch below are congruent. Which sequence could transform triangle ABC to triangle DEF? A translation 7 units down followed by a rotation 180° clockwise about the origin A translation 7 units left followed by a rotation 90° clockwise about the origin A translation 7 units right followed by a rotation 180° clockwise about the origin A translation 7 units left followed by a rotation 180° clockwise about the origin
Answer:
Its A
Step-by-step explanation:
do two lines meet in more than one point
Answer:
It depends.
Step-by-step explanation:
If it is two straight lines, then no, there is no way for the lines to intersect in more than one place. If the line is a parabola, then the lines would intersect in 2 places. It depends on what type of line you have.
The value of the expression is
Steps to solve:
4 + (m - n)^4 when m = 7 and n = 5
~Substitute
4 + (7 - 5)^4
~Simplify
4 + 2^4
~Simplify
4 + 16
~Add
20
Best of Luck!
What’s the answer too this problem?
Think about the rule when multiplying powers together.
When multiplying two powers that have the
same base, simply add their exponents.
In this problem, each power has a base
of a and our exponents are m and n.
So adding these exponents together, we have a^m + n.
Find the measure of angle XAZ in the figure below.
Answer:
m∠XAZ = 40°
Step-by-step explanation:
Since ∠YAU, ∠YAZ and ∠XAZ are the angles based at a point on a straight line, and the sum of the all angles on a line is 180°.
Therefore, m∠YAU + m∠YAZ + m∠XAZ = 180°
50° + 90° + m∠XAZ = 180°
m∠XAZ = 180° - 140°
= 40°
Therefore, measure of angle XAZ is 40°.
3x – 1 > 4x + 7
What’s the answer
Answer:
[tex]x<-8[/tex]
Step-by-step explanation:
So we have the inequality:
[tex]3x-1>4x+7[/tex]
Add 1 to both sides. The left side cancels:
[tex]3x>4x+8[/tex]
Subtract 4x from both sides. The right side cancels:
[tex]-x>8[/tex]
Divide both sides by -1. Since we're dividing by a negative, we flip the sign:
[tex]x<-8[/tex]
And we're done!
Our solution is all numbers less than -8.
Answer:
x = -8
Step-by-step explanation:
I will be the brainliest, its hard to explain on a document, i could make you avideo how to do these problems, im a math teacher.
pls answer this qeustion as soon as possible
The dimensions of this rectangle are 4 units by 3 units
4 units * 3 units = 12 sq units
Write 9.1 as a mixed number and as an improper fraction.
Do not try to simplify your answers.
Answer: 9 1/10 91/10
Step-by-step explanation:
Answer:
9 1/10 and 91/10
Step-by-step explanation:
hope it helps :)
brainliest pls? have a good day/night
Three to the 4th power
4^3x4^7=? HURRYYYYYYYYYYY
Answer:
4¹⁰
Step-by-step explanation:
4³ × 4⁷ = 4³⁺⁷ = 4¹⁰
8. What is the solution to 0,3(12x16)=0.4(12-3x)?
Answer: False
Step-by-step explanation: First, you are going to multiply the numbers in the first set of parenthesis, getting 72. Now, have 72 take the place of 12x6 in the equation. Your new equation looks like this: 0.3 x 72 = 0.4(12-3).
Going off of step one, you will be doing the same thing with the second set, but you will be subtracting instead. You will get 9, and plug it place of the parenthesis. Your equation now looks like o.3 x 72 = 0.4 x 9.
Next, you will multiply the set of numbers on the left side of the equal sign, getting 21.6. You now have an equation of 21.6 = 0.4 x 9.
Going off of step 3, you are going to do the exact same thing we did in step 3. Multiply 0.4 and 9, and you will get 3.6. The equation now looks like 21.6 = 3.6.
Now, the inequality is false because the left-hand side and right-hand side are two completely different numbers. A bigger number cannot be equal to a smaller number.
Hope this helps!
Please help me to prove this!
Answer: see proof below
Step-by-step explanation:
Given: A + B + C = π → A + B = π - C
→ B + C = π - A
→ C + A = π - B
→ C = π - (B + C)
Use Sum to Product Identity: cos A + cos B = 2 cos [(A + B)/2] · cos [(A - B)/2]
Use the Sum/Difference Identity: cos (A - B) = cos A · cos B + sin A · sin B
Use the Double Angle Identity: sin 2A = 2 sin A · cos A
Use the Cofunction Identity: cos (π/2 - A) = sin A
Proof LHS → Middle:
[tex]\text{LHS:}\qquad \qquad \cos \bigg(\dfrac{A}{2}\bigg)+\cos \bigg(\dfrac{B}{2}\bigg)+\cos \bigg(\dfrac{C}{2}\bigg)[/tex]
[tex]\text{Sum to Product:}\qquad 2\cos \bigg(\dfrac{\frac{A}{2}+\frac{B}{2}}{2}\bigg)\cdot \cos \bigg(\dfrac{\frac{A}{2}-\frac{B}{2}}{2}\bigg)+\cos \bigg(\dfrac{C}{2}\bigg)\\\\\\.\qquad \qquad \qquad \qquad =2\cos \bigg(\dfrac{A+B}{4}\bigg)\cdot \cos \bigg(\dfrac{A-B}{4}\bigg)+\cos \bigg(\dfrac{C}{2}\bigg)[/tex]
[tex]\text{Given:}\qquad \quad =2\cos \bigg(\dfrac{A+B}{4}\bigg)\cdot \cos \bigg(\dfrac{A-B}{4}\bigg)+\cos \bigg(\dfrac{\pi -(A+B)}{2}\bigg)[/tex]
[tex]\text{Sum/Difference:}\quad =2\cos \bigg(\dfrac{A+B}{4}\bigg)\cdot \cos \bigg(\dfrac{A-B}{4}\bigg)+\sin \bigg(\dfrac{A+B}{2}\bigg)[/tex]
[tex]\text{Double Angle:}\quad =2\cos \bigg(\dfrac{A+B}{4}\bigg)\cdot \cos \bigg(\dfrac{A-B}{4}\bigg)+\sin \bigg(\dfrac{2(A+B)}{2(2)}\bigg)\\\\\\.\qquad \qquad \qquad =2\cos \bigg(\dfrac{A+B}{4}\bigg)\cdot \cos \bigg(\dfrac{A-B}{4}\bigg)+2\sin \bigg(\dfrac{A+B}{4}\bigg)\cdot \cos \bigg(\dfrac{A+B}{4}\bigg)[/tex]
[tex]\text{Factor:}\quad =2\cos \bigg(\dfrac{A+B}{4}\bigg)\bigg[ \cos \bigg(\dfrac{A-B}{4}\bigg)+\sin \bigg(\dfrac{A+B}{4}\bigg)\bigg][/tex]
[tex]\text{Cofunction:}\quad =2\cos \bigg(\dfrac{A+B}{4}\bigg)\bigg[ \cos \bigg(\dfrac{A-B}{4}\bigg)+\cos \bigg(\dfrac{\pi}{2}-\dfrac{A+B}{4}\bigg)\bigg]\\\\\\.\qquad \qquad \qquad =2\cos \bigg(\dfrac{A+B}{4}\bigg)\cdot \cos \bigg(\dfrac{A-B}{4}\bigg)+\cos \bigg(\dfrac{2\pi-(A+B)}{4}\bigg)\bigg][/tex]
[tex]\text{Sum to Product:}\ 2\cos \bigg(\dfrac{A+B}{4}\bigg)\bigg[2 \cos \bigg(\dfrac{2\pi-2B}{2\cdot 4}\bigg)\cdot \cos \bigg(\dfrac{2A-2\pi}{2\cdot 4}\bigg)\bigg]\\\\\\.\qquad \qquad \qquad =4\cos \bigg(\dfrac{A+B}{4}\bigg)\cdot \cos \bigg(\dfrac{\pi-B}{4}\bigg)\cdot \cos \bigg(\dfrac{\pi -A}{4}\bigg)[/tex]
[tex]\text{Given:}\qquad \qquad 4\cos \bigg(\dfrac{\pi -C}{4}\bigg)\cdot \cos \bigg(\dfrac{\pi-B}{4}\bigg)\cdot \cos \bigg(\dfrac{\pi -A}{4}\bigg)\\\\\\.\qquad \qquad \qquad =4\cos \bigg(\dfrac{\pi -A}{4}\bigg)\cdot \cos \bigg(\dfrac{\pi-B}{4}\bigg)\cdot \cos \bigg(\dfrac{\pi -C}{4}\bigg)[/tex]
LHS = Middle [tex]\checkmark[/tex]
Proof Middle → RHS:
[tex]\text{Middle:}\qquad 4\cos \bigg(\dfrac{\pi -A}{4}\bigg)\cdot \cos \bigg(\dfrac{\pi-B}{4}\bigg)\cdot \cos \bigg(\dfrac{\pi -C}{4}\bigg)\\\\\\\text{Given:}\qquad \qquad 4\cos \bigg(\dfrac{B+C}{4}\bigg)\cdot \cos \bigg(\dfrac{C+A}{4}\bigg)\cdot \cos \bigg(\dfrac{A+B}{4}\bigg)\\\\\\.\qquad \qquad \qquad =4\cos \bigg(\dfrac{A+B}{4}\bigg)\cdot \cos \bigg(\dfrac{B+C}{4}\bigg)\cdot \cos \bigg(\dfrac{C+A}{4}\bigg)[/tex]
Middle = RHS [tex]\checkmark[/tex]
The temperature at 3:00 pm is 27 degrees. The temperature drops 4 degrees every hour for 8 hours. What is the temperature at 11:00 pm?
Lcm of 4 , 8 , 12???
Answer:
It is 4
Step-by-step explanation:
4
4 8
4 8 12
as you can tell 4 is your answer.
On a coordinate plane the vertices of a triangle are A(-1, 4), B(-3,2), and C(0, -1). Find the coordinates of the
midpoint of side AB.
A)
(3,-2)
B)
(-2,3)
(2, -3)
D)
(2, 1)
Answer:
B) (-2,3)
Step-by-step explanation:
Graph all your points. No count the distance from point A to B. divide in half .
You have a handful of dimes and quarters that totals 26 coins and is worth $5.15. How many of each do you have?
Answer:
9 dimes and 17 quarters
Step-by-step explanation:
9+17=26 coins
9 dimes = 90 cents
17 = 425 cents
90+425= 515 cents or $5.15
Hope this helps! :)
A car can travel 210 miles on 8 gallons of gas. Which equation best represents the linear relationship between x, the number of gallons of gas, and y, the total distance the car can travel?
A. x = 30y
B. x = 3y
C. y = 26.25x
D. y = 22.65x
Answer:
D
Step-by-step explanation:
Solve the following equations, show all work. Leave your answers in reduced improper fraction form .
X+7/6=2x-7/6
[tex] \huge \purple {\tt {x + \frac{7}{6} = 2x - \frac{7}{6}}} [/tex]
To Find:[tex] \large {\tt {The \: answer \: in \: reduced}} [/tex]
[tex] \large {\tt { improper \: fraction \: form.}} [/tex]
Solution:[tex] \huge \pink {\tt {x + \frac{7}{6} = 2x - \frac{7}{6}}} [/tex]
[tex] \huge \blue {\tt {or, \: x - 2x = - \frac{7}{6} - \frac{7}{6}}} [/tex]
[tex] \huge \red {\tt {or, \: - x = \frac{ - 14}{6} = \frac{ - 7}{3}}} [/tex]
[tex] \huge \green {\tt {or, \: x = \frac{7}{3}}} [/tex]
Answer:[tex] \huge \orange {\tt {x = \frac{7}{3}}} [/tex]