According to the law of multiple proportions, if 12 g of carbon combine with 16 g of oxygen to form co, the number of grams of carbon that combine with 16 g of oxygen in the formation of co2 is ________.

The apparent weight of the egg is found to be 0.852 N.

Given here, the mass of the egg is m=0.06kg, acceleration due to gravity g =9.8m/s², acceleration of rocket a = 4.4m/s².

Now, we calculate apparent weight by the formula,

We = m (a + g)

= 0.06( 4.4+ 9.8)

= 0.8528 newton.

Thus, the apparent weight of the egg is found to be 0.8528N.

An object’s perceived weight, which reflects how heavy it is, is a quality. When the force of gravity acting on an object is not counter balanced by a force of equal but opposite normality, the apparent weight of the object will differ from the actual weight of the thing.

The buoyant force pushing up on the object is subtracted from the apparent weight, which is equal to the actual weight (w=mg). The apparent weight of the object at its lowest point would be equal to its normal force.

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Answer:

Q1: C

Q2: C

Q3: D

Q4: D

Code: Left, Down, Up, Right

Your welcome.

Answer: ctrl+U

ctrl+G

Explanation:

I don't know how else to help

The FitnessGram PACER Test is a multistage aerobic capacity test that progressively gets more difficult as it continues.

The test is used to measure a student's aerobic capacity as part of the FitnessGram assessment. Students run back and forth as many times as they can, each lap signaled by a beep sound. The test get progressively faster as it continues until the student reaches their max lap score.

The PACER Test score is combined in the FitnessGram software with scores for muscular strength, endurance, flexibility and body composition to determine whether a student is in the Healthy Fitness Zone™ or the Needs Improvement Zone™.

The apparent weight of the egg = 0.264N

Here the rocket is accelerating upward from the surface of the earth. The egg is on the rocket.

The acceleration due to gravity is 4.4m/[tex]s^{2}[/tex].

The mass of a chicken egg is 0.060 kg.

Form Newton's second law, the net force acting on a body is equal to the product of mass and acceleration due to gravity.

So form Newton's second law we know the formula i.e.,

                         F = m×a

                            = 0.06 × 4.4

                            = 0.264N

Therefore the apparent weight of the egg is 0.264N.

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An automobile traveling in the left lane at 60.1 km/h to overtake (become even with) another car that is traveling in the right lane at 38.1 km/h, when the cars' front bumpers are initially 105.2 m apart and the time taken is t = 17.21 seconds.

To find the time, the given values are,

Distance in,

Left lane = 60.1 km/hr

Right lane = 38.1 km/hr

Initial length d₀ = 105.2 m

The distance covered can be derived using the equation of motion with no acceleration.

distance d = speed v × time t

d = vt

For the first automobile,

v = 60.1 km/h

d₁ = 60.1

For the second automobile,

v = 38.1 km/h

Initial distance d = 105.2 m = 0.1052 km

d = vt + d₀.

d₂ = 38.1 t  + 0.1052

For them to meet/overtake each other,

Their distance at that time must be equal.

d₁ = d₂

60.1 t = 38.1 t + 0.1052

60.1 t - 38.1 t = 0.1052

22 t = 0.1052

t = 0.1052 / 22 hr

Converting to seconds

t = 0.1052 / 22 × 3600s

t = 17.21 seconds.

The time taken for an automobile to travel is 17.21 seconds.

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Answer: The Big Bang!

The unknown material is glass because the refractive index is found out to be 1.5

[tex]u_{water\\}[/tex]= 1.33

[tex]u_{x}[/tex]=?

[tex]u_{1}[/tex]sini=[tex]u_{2}[/tex]sin27°

[tex]u_{2}[/tex] = 1.33 x [tex]\frac{sin31}{sin27}[/tex]

= 1.33 x (0.51/0.45)

= 1.50

so, deducing from it, we have refractive index = 1.50

Hence the unknown material is glass.

What is index of refraction?

The refractive index (or refraction index) of an optical media in optics is a dimensionless quantity that indicates the capacity of that medium to bend light. The refractive index controls how much light is refracted or twisted when it enters a substance.

The angle of incidence and angle of refraction of a ray as it crosses the interface between two media with refractive indices of n1 and n2 are, respectively, n1 sin 1 and n2 sin 2, which describes this.

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If the mirror is immersed in water whose index of refraction is 1.33 , No change in its focal distance . focal distance of mirrors does not depend on the external medium in which the mirror is immersed.

As the focal length of the convex mirror does not depend on the factor such as the refractive index of any medium. Hence even after the convex mirror is immersed in water, the focal distance remains unchanged. Hence the facility of the convex mirror also remains same.

Since from lens makers formula we will observe that focal length of lens is inversely proportional to refractive index of medium of lens . Hence net index of refraction of lens decreases when it is dipped in a denser medium than air, hence focal distance increases.

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The formula that we will apply to get to the answer would be:

2as = v² - u²

Using this we will get the answer as 82.35425 m.

Here,

U= initial velocity

V= final velocity

S= displacement of the body

A= acceleration of the body/ acceleration due to gravity (as per the question)

Something that has not been mentioned here but is present in the original question is that the acceleration due to gravity has been given as 0.170g.

While throwing the wrench on earth,

v² - u² = 2as

⇒[tex]u = \sqrt{v^2 - 2as}[/tex]

⇒ u = [tex]\sqrt{0-2 * -9.81 * 14}[/tex]

⇒ u= 16.57347 m/s

Since the astronaut gives the same starting speed in both the places so the u on moon would be 16.57347 m/s

While throwing the wrench on moon,

v² - u² = 2as

s = [tex]\frac{v^2 - u^2}{2a}[/tex]

⇒ s =  [tex]\frac{0^2 - 16.57347^2}{2 * (-9.81) * 0.17}[/tex]

⇒s = 82.35425 m

so, on moon, the wrench could be thrown a distance of 82.35425 m

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Answer:

B. one kind of matter changes into a different kind of matter with different properties

the mass of the astronaut will be 70KG, the mass stays the same everywhere.

The infinite three-dimensional expanse of space is where things and events have relative positions and directions. While modern physicists typically consider it to be a portion of an unbounded four-dimensional continuum known as spacetime, physical space is frequently conceptualized in classical physics as having three linear dimensions. It is believed that grasping the idea of space is essential to comprehending the physical cosmos. Philosophers dispute on whether it is a thing in and of itself, a connection between entities, or a component of a conceptual framework. Mathematicians started looking at non-Euclidean geometries in the 19th and 20th centuries, when space is thought of as curved rather than flat. Space around gravitational fields deviates from Euclidean space, according to Albert Einstein's theory of general relativity.

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With the concept of Coulomb's Law, the net force acting on the 2μC charge is 2.06 × 10⁻² newton.

Coulomb's Law states that the force of attraction or repulsion exerted by a charged particle on another charged particle is given by,

F=kq₁q₂ / r²

Here q₁ and q₂ are the charges on the particles,

r is the separation between them

k is a constant known as Coulomb's constant, whose value is, k = 9 × 10⁹ N m²/C²

So here in the question, we have been given an equilateral triangle of side 2 meters with three-point charges at its vertices

q₁ = 1μC ,

q₂ = 2μC ,

q₃ = 3μC ,

r=2 m

From Coulomb's law,

F₂₁ = kq₁q₂/r²

F₂₁ = (9 × 10⁹ × 1 × 2 × 10⁻¹²) / 2²

F₂₁ =4.5 × 10⁻³ N

This is the force on charge q₂ because of q₁.

Similarly,

F₂₃ = kq₂q₃ / r²

F₂₃ = (9 × 10⁹ × 2 × 3 × 10⁻¹²) / 2²

F₂₃ = 18 × 10⁻³ N

Now, the resultant of the two forces will be,

F(net) = [tex]\sqrt{F_{21} ^2 + F_{23}^2 +2F_{21}F_{23}cos60}[/tex]

On substituting all the values the net force will be

F(net) = 2.06 × 10⁻² N

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 r(t)=ti+5t²j+(4t²+50t⁴)k, For t∈ (-∞, ∞)

First plug the equation of y into the equation of z, so that we get their intersection:

We plug  

y=5x²

Into:

z=4x²+4y²

So, we get:

z=4x²+2(5x²)²

z=4x²+2(25x⁴)

z=4x²+50x⁴

Then we set  

x=t

And plug that in the equation [tex]y=5x^{2}[/tex] and z.

So that we get:

[tex]y=[/tex]5t², [tex]z=[/tex]4t²+50t⁴

Hence, the vector function r(t) that represents the curve of intersection is:

r(t)=ti+5t²j+(4t²+50t⁴)k, For t∈ (-∞, ∞)

A curve of intersection is made up of the common points of two transversally intersecting surfaces, which means that the surface normals are not parallel at any common point. This restriction applies only when the surfaces are touching or share surface sections.

The intersection of two non-parallel planes in Euclidean 3-space is a line in the simplest situation.

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Transformers may change the voltage in two different ways which are

This is further explained below.

Generally, Electric transformers are devices that can change the direction and speed of the flow of current in an electrical circuit. They do this by adjusting the voltage of the existing flow of current through the use of electromagnetic induction.

In conclusion,  There are two distinct methods by which transformers may alter the voltage, and they are

The step-up transformer is usually used for the transmitting of electric charge through a lengthy distance where power drop might be experienced, while the step-down is used to moderate said transmitted charge to a consumer.

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Yes, the statement is correct that keeping the flies in constant dark conditions abolish the light-emission oscillations

The electromagnetic radiation spectrum produced when an electron changes from a high energy state to a lower energy state is known as the emission spectrum of a chemical element or chemical compound. The energy difference between the two states is equal to the photon energy of the emitted photon. Each atom contains a large number of potential electron transitions, and each transition has a distinct energy difference. An emission spectrum is made up of a variety of transitions that result in various radiated wavelengths. The emission spectra of each element is distinct. Therefore, components in materials with an unknown composition can be identified via spectroscopy. Similar to this, chemical examination of substances may make use of the emission spectra of molecules.

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The Angular momentum of mass m moving with a constant velocity about origin is constant.

L= momentum × perpendicular distance of line of action of the momentum from origin.

L=mv×y

Here it is seen that mvy is a constant, therefore the angular momentum is constant.

The rotational equivalent of linear momentum in physics is called angular momentum, also known as moment of momentum or rotational momentum.

Because it is a conserved quantity, while calculating the total angular momentum of a closed system, it stays constant—it is significant in physics.

The direction and the amplitude of angular momentum are all conserved. The functional characteristics of bicycles and motorbikes, frisbees, rifled bullets, and gyroscopes are due to the conservation of angular momentum.

The conservation of angular momentum also explains why neutron stars rotate rapidly and hurricanes, build spiral structures. In general, conservation restricts a system’s potential motion but does not completely define it.

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Answer:

[tex]{ \tt{mass \: number = protons + neutrons}} \\ { \tt{7 = p + 3}} \\ { \tt{p = 4}}[/tex]

The athlete who jumps a vertical distance of 0.8 m has a initial speed of: 3.959 m/s and his total time in the air is: 0.8078 s

The formulas for the vertical launch upward and the procedures we will use are:

Where:

Information about the problem:

Applying the maximum height formula and clearing the initial velocity we get:

y max = v₀²/(2*g)

v₀ = √(y max * (2*g))

v₀ = √( 0.8 m * (2 * 9.8 m/s²))

v₀ = √( 0.8 m * 19.6 m/s²)

v₀ = √15.68 m²/s²

v₀ = 3.959 m/s

Applying  the maximum time formula we get::

t max = v₀ / g

t max =(3.959 m/s)/(9.8 m/s²)

t max = 0.4039 s

Applying  the time of flight formula we get::

t(of) =2 * t max

t(of) =2 * 0.4039 s

t(of) = 0.8078 s

In physics vertical launch upwards is the motion described by an object that has been launched vertically upwards in which the height and the effect of the earth's gravitational force on the launched object are taken into account.

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When a gas undergoes a quasi-static isobaric change in volume from 10.0 to 2.0 l, 15 j of work from an external source are required then the pressure of the gas is

Work done is given as

W=PdV

15 = P ×( 20-10)

P = 1.5 bar

The force delivered perpendicularly to an object's surface per unit area across which that force is dispersed is known as pressure (symbol: p or P). The pressure relative to the surrounding air is known as gauge pressure, also written gage pressure[a].

Pressure is expressed using a variety of units. Some of these result from dividing a unit of force by a unit of area; the pound-force per square inch (psi), which is equivalent to one newton per square meter (N/m2) in the SI, is the standard unit of pressure in the imperial and U.S.

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Answer:

you are very most correct

Explanation:

it does have something to do with terminal velocity and because the weight is so light of it any tiny gust of wind can push it back and forth and because wind is never stable thats why it moves side to side

Answer: Acceleration=Change in speed/time

=(20–8)/10

=1.2m/s²

We can find the distance travelled by using the kinematic equation

S=ut+½at²

S=8*10+½*1.2*100

S=80+0.6*100

S=80+60

S=140m

Explanation: hope this helps and good lucky!!

Galileo disproved Aristotle’s idea that heavy objects fall faster than lighter objects through his findings as specified in his books.

The story goes that Galileo used this experiment to find that the objects fell with the same acceleration, disproving Aristotle’s theory of gravity (which states that objects fall at a speed proportional to their mass) and proving his prediction.

Before Galileo, Aristotle’s writings had been accepted as true for over a thousand years. He claimed that heavier objects fall faster than lighter ones and that an object that weighs twice as much as another will fall twice as fast.

In his book Two New Sciences, Galileo outlined his theories regarding falling objects and projectiles in general (1638).

The two disciplines were the study of motion, which helped establish physics as a discipline, and the science of materials and construction, which made significant contributions to engineering.

This theory of Galileo’s was totally based on a well-known thought experiment that he described in his book.

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The height of the utility pole she has climbed is 60 m

When an object is dropped under gravity, the initial velocity is zero. While at the maximum height reached by an object when thrown up, the final velocity will be zero.

Given that a utility line worker drops a screwdriver which takes 3.5 seconds to hit the ground. The height of the utility pole can be calculated by using the formula below

h = ut + 1/2gt²

but u = 0

h = 1/2gt²

Substitute all the parameters into the equation

h = 1/2 × 9.8 × 3.5²

h = 4.9 × 12.25

h = 60.025 m

Therefore, the height of the utility pole she has climbed is 60 m approximately.

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By using vector

a. the distance traveled is 2.6 miles

b. the resultant displacement is s = ( 0.6 i - 0.8 j ) miles
the magnitude is |s| = 0.6 miles

We need to know about vectors to solve this problem. Vector has magnitude and also direction. Displacement is included in vector. It can be written as

s = sx i + sy j + sz k

where s is displacement, sx is displacement on x-axis, sy is displacement on y-axis and sz us displacement on z-axis.

From the question above, we know that

east = positive x

south = negative y

west = negative x

north = positive y

s1 = 0.8 i

s2 = -1.2 j

s3 = -0.2 i

s3 = 0.4 j

The distance traveled is

s = s1 + s2 + s3 + s4

s = 0.8 + 1.2 + 0.2 + 0.4

s = 2.6 miles

The resultant displacement is

s = s1 + s2 + s3 + s4

s = 0.8 i -1.2 j -0.2 i + 0.4 j

s = ( 0.6 i - 0.8 j ) miles

The magnitude is

|s| = √sx²

|s| = √0.6²

|s| = 0.6 miles

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The frequency of light emitted is 24.63 x [tex]10^1^5[/tex] Hz when an electron jumps from the 2nd to the 1st orbit in a hydrogen atom.

According to Bohr, the electrons in the atom's structure are situated around the nucleus at particular energy levels. An electron must either acquire or lose energy as it transitions from one of these energy levels to another. It is known as an absorption when an electron obtains energy and as an emittance when it loses energy. Both processes involve the absorption or emission of a PHOTON energy particle, which in turn causes the absorption or emission of light. Because various elements have varying energies, they each emit or absorb light in varying quantities (wavelengths).

The wavelength or wave number is used to compute the frequency of light emitted. 

The frequency of light emitted is inversely proportional to its wavelength.

Given:

Jump from 2nd orbit to 1st orbit

Planck’s constant, h = 6.626 x [tex]10^-^3^4[/tex]

To find:

Frequency of light emitted, υ = ?

Formula:

E = hυ

Calculations:

[tex]E = 13.6 * Z^2( \frac{1}{n_1^2} - \frac{1}{n_2^2} )[/tex]

E = hυ = 13.6 x 1 x [tex](1 - \frac{1}{4})[/tex]

υ x 6.626 x [tex]10^-^3^4[/tex] = 10.2 x 1.6 x [tex]10^-^1^9[/tex]

υ = 24.63 x [tex]10^1^5[/tex] Hz

Result:

The frequency of light emitted is 24.63 x [tex]10^1^5[/tex] Hz.

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In here E = 5.3 x 10^3 N/C, the potential difference (V) between the two plates is 116.6 V and if d is doubled, electric field E won't change but V gets doubled.

a) The electric field of infinite parallel plates can be formulated as

E= σ/2ε0 → eq1

Surface charge density is given as 47.0 nc/m2

So, the electric field is independent on d.

Hence the, so the net field is

E = E1 + E2 = σ/2ε0 + σ/2ε0 = σ/ε0

Substituting in eq 1,

E = [47 x 10^(-9) ] / 8.85 x 10^-12 = 5.3 x 10^3 N/C

b) Since the electric potential between them at any point and is given by.

V=Ed → eq 2

So, Substituting in eq 2 yields

V= 2.2 x 10^-2 x 5.3 x 10^3 = 116.6 V

c) If the distance between plates is doubled it will make no changes on the field because the field is independent on d.

For the voltage, according to equation 2 the voltage depends on d so if d is doubled then the potential between plates must be doubled.

Thus, magnitude of e in the region is 5.3 x 10^3 N/C.

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Answer:

Explanation:

Given that

To find

So, according the question

We have,

The formula for the ball's height as a function of time is

         [tex]y_f = y_i - u_it - \frac{1}{2} gt^2[/tex]------------------(1)

where,

         [tex]y_f = final \;height=0\\y_i = initial \;height=29.6m\\u_i = initial \;velocity=8.35m/s\\\;\; g = acceleration \;due\; to\; gravity= 9.81m/s^2[/tex]

Now, putting the all given values ,

         [tex]y_f = y_i - u_it - \frac{1}{2} gt^2[/tex]------------------(1)

         [tex]0 = 29.6 - 8.35t - \frac{1}{2} \times9.81t^2[/tex]

or,

         [tex]9.81t^2 + 16.7t -59.2 = 0\\\\t = \frac{-16.7 \pm \sqrt{(16.7)^2-4\times 9.81\times (-59.2)}}{2}}\\t = \frac{-16.7 \pm \sqrt{278.89+4\times 9.81\times 59.2}}{2}}\\t = \frac{-16.7 \pm \sqrt{278.89+2087.57}}{2}}\\t = \frac{-16.7 \pm \sqrt{2366.46}}{2}}\\t = \frac{-16.7 \pm 48.65}{2}}\\now \; we \; know \; that\; time\;always \; in\;only\;positive\\so,\\t = \frac{-16.7 + 48.65}{2}\\t = \frac{31.95}{2}\\t = 15.98s[/tex]

Answer:

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Answer:

the process of solving a mystery.

Explanation:

Answer:

neutron and proton are the answer

The speed of Olivia when she made it to the bottom of the hill is 14m/s.

Kinematics is the study of mechanical points, bodies, and systems in motion without taking into account the forces acting on them or the corresponding physical qualities.

Kinematics equations of motion define the fundamentals of an object's motion, such as its position, velocity, or acceleration over time. These three equations of motion control how an item moves in one, two, and three dimensions.

Kinetics considers physical forces as well as material characteristics such as mass stiffness and tensile or compressive strength. These characteristics can be used to take a theoretical model from kinematics and use physics and thermodynamics to determine how to construct a workable, dependable, and functional real-world system.

Given,

Initial velocity, u = 4m/s

Acceleration, a = 2m/s-2

Displacement, s= 45m

we know that,

[tex]v^{2}= u^{2} + 2as[/tex], where v= final velocity

substituting the value in the above equation, we got

[tex]v^{2}[/tex] = [tex]4^{2} + 2(2)(45)[/tex]

v = [tex]\sqrt{196}[/tex]

v = 14 m/s

Thus, the speed of Olivia going down the hill is 14m/s.

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