ac a, c, with, \overleftrightarrow, on top is tangent to circle ooo at point ccc. what is the measure of \angle oac∠oacangle, o, a, c?

Answer:

1/8

Step-by-step explanation:

5/4   divided by   10/1   is the same as  

    5/4   times  1/10

       5/4 *  1/10 =  5/40    = 1/8

Answer: 1/8

Step-by-step explanation:

[tex]\displaystyle\\\frac{\frac{5}{4} }{10} =\\\\\frac{5}{4}:10=\\\\\frac{5}{4} *\frac{1}{10}=\\\\ \frac{5*1}{4*10}=\\\\\frac{5}{4*5*2} =\\\\\frac{1}{4*2}=\\\\\frac{1}{8}[/tex]

The  unit rate in minutes per meter is 28.8 minutes per meter when  David fills an aquarium to a depth of 3/8 meters in 3 3/5 minutes

The given Depth of the aquarium  = 3/8 meters

Time taken to fill the aquarium  = 3 3/5 minutes

To find the  the unit rate in minutes per meter, we need to divide the time taken to fill the aquarium by the depth of the aquarium

So, Unit rate in minutes per meter = 3 3/5minutes ÷ 3/8 meters

                                                            = 18/5 ÷ 3/8

                                                              = 18/5 ×8/3

                                                             = 144/15

                                                             = 28.8 minutes per meter

Hence, the unit rate in minutes per meter is 28.8 minutes per meter when  David fills an aquarium to a depth of 3/8 meters in 3 3/5 minutes

The correct question is David fills an aquarium to a depth of 3/8 meters in 3 3/5 minutes. What is the unit rate in minutes per meter?

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Solving the equation s = zr - 6zc^4 for z would give you: [tex]z = \frac{s}{r - 6c^4}[/tex].

Given the equation, s = zr - 6zc^4, to solve the equation for z, follow the steps below:

We have to isolate the variable "z" to one side of the equation if we are to solve the equation for z.

s = zr - 6zc^4

Factor out variable z

s = z(r - 6c^4)

Divide both sides of the equation by (r - 6c^4)

s/(r - 6c^4) = z(r - 6c^4) / (r - 6c^4)

s/(r - 6c^4) = z

[tex]z = \frac{s}{r - 6c^4}[/tex]

Therefore, solving the equation s = zr - 6zc^4 for z would give you: [tex]z = \frac{s}{r - 6c^4}[/tex].

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The subtraction sentence where the difference is positive which uses a positive and negative integer are written as  5 - (-3) =8.

Integers are all real , rational numbers except the decimals and fractions. There are 3 types of integers : positive negative and zero integers.

Integers include zero, a positive natural number, and a negative integer represented by a minus sign. The negative numbers are the inverse additions of the comparable positive numbers.

There are two cases;

Case 1;

when modulus of positive integer ≥ modulus of negative integer;

Example; 5 - (-3) = 5 + 3 = 8  (Here, |5| > |-3|)

Case 2;

when modulus of positive integer ≤ modulus of negative integer;

Example; 5 - (-10) = 5 + 10 = 15  (Here, |5| < |-10|)

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Minimum number of meeting required is 5 meetings required

As mentioned, if there is an edge between two committees, both the committee has atleast one member in common.

So if we consider two committees with atleast one member in common, i.e. we select two different vertices with an edge in between, the common member(s) in the committee can discuss and exchange ideas between the committees and thus they don't require a meeting to be scheduled.

So looking at the graph we can say that we only need to schedule meetings between committee with no edge connecting them.

6C2 - |E| or 15 - 10

= 5 meetings

Committees keep an eye on ongoing government activities, spot problems that warrant legislative scrutiny, collect and assess data, and suggest courses of action to the Senate.

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Answer:

$227 = washing machine cost

$391 = dryer cost

Step-by-step explanation:

$618 divided by 2 = 309

309 - 82 = 227 = cost of washing machine

618 - 227 = 391 = cost of dryer

You can double-check by,

391 + 227

= 618

$227 = washing machine cost

$391 = dryer cost

Cheyenne can buy a maximum of 13 bags of Takis.

We have,

To find the maximum number of bags of Takis Cheyenne can buy with $20, we need to divide the total amount of money she has by the cost per bag of Takis.

Cost per bag of Takis = $1.50

Total money Cheyenne has = $20

Maximum number of bags of Takis = Total money / Cost per bag

Maximum number of bags of Takis = $20 / $1.50

Maximum number of bags of Takis = 13.33

Since Cheyenne cannot buy a fraction of a bag, the maximum number of bags of Takis she can buy is 13.

Thus,

Cheyenne can buy a maximum of 13 bags of Takis.

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Answer:

10.97 mm

Step-by-step explanation:

Hello!

First, let's construct an altitude, as shown in the picture below. An altitude is a height from one point to another side, forming a 90° angle at that intersection.

The length of the altitude is the same as the missing length, they are both parallel.

The length from the altitude to the slant line would be 6, as found by subtracting 8 from 14.

If you look closely, we can see a right triangle, and 12.5 mm is the hypotenuse. We know the measure for another side, and we can solve for the altitude using the Pythagorean Theorem: [tex]a^2 + b^2 = c^2[/tex], a and b are legs, and c is the hypotenuse.

In this case, 6 and the altitude are legs.

The altitude is around 10.97, so the missing length will also be 10.97 mm.

The height of the box is 12cm, having volume = 1200cm ³ .

A triangular prism's volume is the area that it takes up in all three dimensions. A prism is a solid object that has the same cross-section throughout its entire length, equal bases, and flat, rectangular side faces. Prisms can be divided into many categories and given different names depending on the form of their bases. A triangular prism has three rectangular lateral sides and two identical triangular bases.

The formula yields the volume of a triangular prism.

Volume of triangular prism  = 1/2lwh

Where,

w = width

h = height

l = length.

We may determine the height by filling in the specified measurements.

1200cm ³ = 1/2 × (20 cm) × (10 cm) × h

h = (1200 cm³) / (100 cm²))

h = 12 cm

The box has a 12 centimeter height.

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4ft = 48in or 4 feet is equivalent to 48 inches.

In mathematics, conversion is the process of changing the value of one form or unit to another. It can be changing ones unit of length, weight, volume or even currency to another.

A conversion factor is a number used to change one set of units to another, either by multiplying or dividing.

The sentence states an equality between units of length: feet and inches.

From there, we can say that we are asked how many inches are there in 4 feet

Converting feet to inches, we must use the conversion

1 foot = 12 inches

4ft = 4 (12 inches)

4ft = 48in

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Answer: 4,800,000 mg

32,000 dg

Step-by-step explanation:

1 kg=1000 g

1 g=1000 mg

1 kg * 1000 g/1 kg * 1000 mg/1 g=

1*1000*1000=1,000,000 mg

1 kg=1,000,000 mg

4.8 kg=

4.8*1000000=4,800,000 mg

1 g=10 dg

3.2 kg =

3.2 kg * 1000 g/1 kg * 10 dg/1 g=

3.2*1000*10=

3.2*10,000=32,000 dg

Answer:

◉ 70/9

Step-by-step explanation:

9(x - 9) = -11

9x - 81 = -11

9x = 70

x = 70/9

In the given statement is :

Of the three types of general survivorship curves, which can be most likely expected to live closest to its maximum life expectancy?

In this case, In Type I Curve, organisms tend to live up to maximum life expectancy. They survive their adulthood and die when they become elderly. Humans come under this category.

Survivorship Curve:

The Survivorship Curve is used to represent the number of population that are expected to live to a certain age. There are three types of survival curves they are Type I, Type II, Type III. Each curve will show the life expectancy of a particular group of organisms.

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Edna has visited 44 countries.

For given question,

Edna has spent her whole life traveling. she has been to 4 different continents and to 11 countries on each continent.

Here each continent  has 11 countries.

She visited 4 different continents.

So, the total number of countries she has visited would be given by an expression,

11 × 4

We solve above expression to  determine how many countries Edna has visited.

11 × 4 = 44

Therefore, approximately 44 countries Edna has visited.

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Answer:

Step-by-step explanation:

0

Answer:

a: 0.5 + 0.3 = 0.8

b: 2.7 + 28.2 = 30.9

c: 3.1 + 2.4 + 9.9 = 15.4

d: 15.2 + 1.4 + 0.8 = 17.4

e: 39.2 + 2.5 + 0.8 = 42.5

Step-by-step explanation:

I did the assignment and I got it right

Answer:

10√2

or in decimal form:

14.1

Hope this helps! <3

If the American Heart Association suggests a target heart rate of T=0.75(220-a),  Proving  that given a person's target heart rate, you can calculate his or her age using the formula a=220- /0.75. His/her age is 16 years.

a. Given:

T=0.75(220-a)

where

T =a person's target heart rate

a= his or her age

Prove:

Hence:

T=0.75(220-a)

T/0.75=220-a

T/0.75-220=a

-T/0.75+220=a

a=-T/0.75+220

a=220-T/0.75

b. How old is she:

a=220-T/0.75

where:

T=153

Substitution

a=220-153/0.75

a=220-204

a=16 years

Therefore proving  that given a person's target heart rate, you can calculate his or her age using the formula a=220- /0.75. His/her age is 16 years.

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The complete question is:

Mai-Lin measures her heart rate whenever she exercises and tries to make sure that she is staying in her target heart rate zone. The American Heart Association suggests a target heart rate of T=0.75(220-a), where T is a person's target heart rate and a is his or her age.

a. Prove that given a person's target heart rate, you can calculate his or her age using the formula a=220- T/0.75.

b. If Mai-Lin’s target heart rate is 153, then how old is she? What property justifies your calculation?

Answer:

44

Step-by-step explanation:

(5)(4)(2) + 4 Calculate the product

40 + 4 Add

= 44

Answer: its 44 :D

have a great day young boy

Answer:

(a)=∆PQU,∆QRV,∆RSW and ∆SPT are congruent.

Step-by-step explanation:

PQRS is square (given)

PQ=QR=RS=PS

Total number of students in a class is 50.

A class has 40% of women.

Total Number of women in a class = 20                              equation 1

Let total number of students in a class = x

According to the question a class has 40% of women. Mathematically we can write it as,

Total Number of women in a class = 40 % of x

Total Number of women in a class = ( (40x) / 100 )               equation 2

On equating equation 1 and equation 2, we get

20 = ( (40x) / 100 )

⇒ 40x = 2000

⇒ x = 50

Total number of students in a class is 50.

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Answer: [tex]|x| \leq 5[/tex] (the last option)

Step-by-step explanation: When you plug in values from the given solution set, the number is positive because of the absolute value symbol. This causes the range of possible values to be from 0 to 5, which are all less than or equal to 5.

THIS IS EASY?? OH HELL NO-

Answer: 68%

Step-by-step explanation:

170/250=

17/25=

0.68=

0.68 * 1=

0.68 * 100%=68%

The equation of the parabola that models the given situation is y = [tex]\frac{-1}{6}(x-3)^{2}[/tex] + 1.5.

A parabola is a roughly U-shaped mirror-symmetrical plane curve. It corresponds to a number of seemingly unrelated mathematical descriptions that all define the same curves.

To represent a parabola algebraically in the coordinate plane, the standard equation of a parabola is used. The general equation of the parabola is given by  y = [tex]a(x-h)^{2}[/tex]+ k or x = [tex]a(y-k)^2[/tex] +h, where (h,k) denotes the vertex. A regular parabola's standard equation is [tex]y^2[/tex] = 4ax.

Now, the equation of parabola for the given situation is calculated as:

y = [tex]a(x-3)^2[/tex]+ 1.5

Now, put the value of x = 0 and y = 0.

0 = [tex]a(0-3)^2[/tex]+ 1.5

0 = 9a + 1.5

-9a = 1.5

a = - 1.5/9

a = -1/6

Now, put the value of a in equation y = [tex]a(x-3)^2[/tex]+ 1.5 to obtain:

y = [tex]\frac{-1}{6}(x-3)^{2}[/tex] + 1.5.

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15m/s * 1km/1000m*60s/1 min*60 min/1hr=

You do the calculation.

Here are the conversions used in the conversion.

1km = 1000 m, 60 seconds = 1 minute, 60 minutes = 1 hour.

When you set up the problem the 15 meters is in the numerator and 1 second is in the denominator. To convert the 15 meters to km the next conversion factor needs to have 1km in the numerator and 1000 meters in the denominator. Now the 15 m will be divided by 1000 m which cancels the meters and leaves km.

The seconds in 15 m/s is in the denominator so to convert seconds to hours multiply by 60 seconds placing it in the numerator over 1 minutes. Use the same idea to set up the conversion from minutes to hours.

Practice this conversion. It is a fundamental conversion that any middle school student should know how to do.

The expression is x+2-2y

It is given to us that logp5=x and logp7=y

Now we are required to find logp(5p^2)/49 in terms of x and y

we know that in logarithmic formulas

loga^b=b loga

logab = log a+log b

log a/b= log a- log b

Now using these formulas to find the solution,

logp 5p^2/49

= logp5+ logp p^2 -log 49

=logp5+2 logpp-2log7

we know that logpp=1,hence

= logp5+2 -2 logp7

=x+2-2y

Hence the expression is x+2-2y

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The value of angle m< EBF  is determined as 56⁰.

The sum of angles in a straight line is 180 degrees. The value of angle EBF can be determine using the concept of sum of angles in a straight line as shown below.

m< EBC  + m< ABE = 180

3y + 10 + 2y - 20 = 180

5y - 10 = 180

5y = 180 + 10

5y = 190

y = 190/5

y = 38

The value of m< EBF is calculated as follows;

Assuming equal division, m< EBF = m< ABE

m< EBF = 2y - 20

m< EBF = 2(38) - 20

m< EBF = 56⁰

Thus, the value of angle m< EBF  is determined as 56⁰.

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The graph of the inequality y > x + 4 matches the description in Option(c)

a shaded region above a dashed boundary line.

Given function: y > x + 4

Let's plot the graph of the given function and then match it with the options to see which is the solution.

So we will Plot y = x + 4 (as a dashed line because y > )

the coordinates will be,

x = 0 , y = 4

x = -1 , y = 3

x = -2 , y = 2

x =  1 , y = 5

x = 2 , y = 6

The purple shaded region satisfies the inequality y > x + 4.

Hence the graph description is a shaded region above a dashed boundary line.

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The complete question is: "Which description matches the graph of the inequality y > x + 4?

a) a shaded region above a solid boundary line

b) a shaded region below a solid boundary line

c) a shaded region above a dashed boundary line

d) a shaded region below a dashed boundary line."