Answer:
The answer is 20 JExplanation:
The work done by an object can be found by using the formula
workdone = force × distance
From the question we have
workdone = 10 × 2
We have the final answer as
20 JHope this helps you
Answer:
20 i think
Explanation:
A rock is dropped (from rest) off a bridge over the Merrimack River. The falling rock
accelerates at 10 m/s2 downward. If it takes 2.5 seconds before a splash is heard,
approximately how high is the bridge?
Answer:
31.25 meters or ~31 meters approximately
Explanation:
Let's see which of the 5 variables we are given since this is a constant acceleration problem.
[tex]v_i \ \ \ \ \ \ t \\ v_f \ \ \ \ \ \triangle x \\ a[/tex]We want to find the height of the bridge, aka the vertical displacement of the rock. Let's set the upwards direction to be positive and the downwards direction to be negative.
We are told that the acceleration is 10 m/s² downward, so we have a = -10 m/s².
We are also told that the time it takes the rock to hit the water is 2.5 seconds. Time is the same regardless of the x- or y- direction, so we can say that t = 2.5 seconds.
Now, we aren't told this directly, but we can figure out that the velocity in the y-direction is 0 m/s, since the rock is dropped from rest off the bridge. Therefore, [tex]v_i=0 \frac{m}{s}[/tex].
We want to find the vertical displacement, the height of the bridge, so we can say that [tex]\triangle x= \ ?[/tex]
We have 4 out of 5 variables:
[tex]v_i,\ a, \ t, \ \triangle x[/tex]Look through the constant acceleration equations to see which equation has all 4 of these variables. You should come up with this one (no final velocity):
[tex]x_f=x_i+v_it+\frac{1}{2}at^2[/tex]Subtract [tex]x_i[/tex] from both sides of the equation to get:
[tex]\triangle x=v_it+\frac{1}{2}at^2[/tex]Substitute in our known variables and solve for delta x.
[tex]\triangle x=(0\frac{m}{s})(2.5s) + \frac{1}{2} (-10\frac{m}{s^2})(2.5s)^2[/tex]0 m/s multiplied by 2.5 s is 0, so we have:
[tex]\triangle x =\frac{1}{2} (-10)(2.5)^2[/tex]Evaluate the exponent first and multiply the terms together.
[tex]\triangle x =(-5)(6.25)[/tex] [tex]\triangle x =-31.25[/tex]The vertical displacement is -31.25 meters from the rock's starting position, so we can say that the height of the bridge is 31.25 meters, which is approximately 31 meters tall.
Answer:
31 meters
hope it help you
thanks for free points.........
Two bowling balls, each with a mass of 8.52 kg, are traveling toward each other. Find the total momentum of the system if both balls have a speed of 2.13 m/s, but are traveling opposite of one another.
a. 18.1
b. 36.3
c. 0.0
d. 17.4
b=36•3
momentum=mass×velocity
The total momentum of the given system is equal to zero. Therefore, option (C) is correct.
What is the law of conservation of momentum?The linear momentum can be described as the product of the mass times the velocity of that object. Conservation of momentum is a property of an object as the total amount of momentum stays the same.
According to the law of conservation of momentum, the sum of the momentum before and after the collision of the objects must be equal.
m₁ u₁ + m₂ u₂ = m₁ v₁ + m₂v₂
where u₁ and u₂ are initial speed while v₁ & v₂ is final speed and m₁ and m₂ is the mass of the collided objects.
The first ball, m = 8.52 g and v = 2.13 m/s
The momentum of the first ball = 18.15 g.m/s
The second ball is moving in the opposite direction w.r.t. first ball,
The second ball, m = 8.52 g and v = - 2.13 m/s
The momentum of the first ball = - 18.15 g.m/s
The total momentum of the system = 18.15 + (-18.15) = 0
Therefore, the total momentum of the given system is zero.
Learn more about the law of conservation of linear momentum, here:
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PLEASE HELP IF YOU KNOW THE ANSWER QUICK PLEASE!!!
Answer:
d
Explanation:
8. An object has a force applied. The object has a mass of 36 Kg and accelerates at 3.4 m/sec2. What is the force acting on the object? *
a. 120.6 N
b. 126.9 N
c. 122.4 N
d. 118.3 N
Answer:
122.4
Explanation:
can somone pls help me??!! i’m very stuck
Answer:
R
Explanation:
Her distance from home and Time increase
the stops when she gets to the library
then her distance from home decreases while her time increases
A positive charge is 1 m to the left of a negative charge. The positive charge is then moved and placed 1 m to the right of the negative charge. What happens to the electrostatic force between the charges?
The electrostatic force remains attractive, and the magnitude does not change.
The electrostatic force remains repulsive, and the magnitude does not change.
The electrostatic force remains repulsive, but the magnitude changes.
The electrostatic force remains attractive, but the magnitude changes.
Answer:
Option (a) is correct.
Explanation:
Let the magnitude of the positive charge = [tex]q_1[/tex] and the magnitude of the negative charge = [tex]q_2[/tex]
Earlier, the distance between both the charge, d = 1m
By using Coulomb's law, the magnitude of the force between two charge
[tex]F=k\frac {q_1 q_2}{d^2}[/tex], where k is a constant.
So, the magnitude of the force in the initial configuration,
[tex]F_i = k\frac {q_1 q_2}{1^2}= k q_1q_2\cdots(i)[/tex]
The nature of the force is attractive, as both the charges are opposite in nature.
On replacing the positive charge from 1m left to 1 m right side of the negative charge, the distance between the charges remains the same, i.e d=1m.
Moreover, the magnitude, and nature of each charge, [tex]q_1[/tex] as well as [tex]q_2[/tex], are remain the same.
So, the magnitude of the force in the final configuration,
[tex]F_f = k\frac {q_1 q_2}{1^2}= k q_1q_2[/tex]
From equation (i), [tex]F_f=F_i[/tex]
The nature of the force is attractive, as both the charges are opposite in nature.
So, the electrostatic force remains attractive, and the magnitude does not change.
Hence, option (a) is correct.
When the electrostatic force lies between the charges so here the force should remain attractive, also the magnitude should remain the same.
Impact on the electrostatic force:Here we assume the magnitude of the positive charge should be q1 and the magnitude of the negative charge should be q2
Also, the distance between the charge should be d = 1 m
So here we use the columb law
F = kq1q2/d2
here k should be constant
Here the nature of the force should be attractive since the both the charges should be opposite.
Hence, the first option is correct.
Learn more about force here: https://brainly.com/question/3398162
What is the power of a crane that does 5.60 kJ of work in 2.80 s?
Answer:
I don't understand what is a power cane??
2. A 75 kg runner accelerates from 0.00 m/s to 10.0 m/s in 1.5 seconds.
a) What is the runner's acceleration?
b) How much Kinetic Energy does the runner have at 0.0m/s, 5.0m/s, 10.0 m/s?
c) graph his kinetic energy. Use velocity on the x-axis and KE on the y-axis
Given, Unknown: Equation, Substitute: Solution:
The yoga term asanas are which of the following?
A.
The yoga breathing method.
B.
The yoga term for mediation.
C.
The yoga term for exercises or poses.
D.
The yoga term for spiritual enlightenment.
Answer:
i guss its A
Explanation:
The kinetic energy of a roller coaster is 100 joules. The potential energy of the same coaster is 100 joules. What is the mechanical energy of the coaster?
Answer/Explanation:
The mechanical energy is 200 joules. Mechanical energy is determined by adding the total kinetic energy by the total potential energy.
M = kp
100 + 100 = 200
Which line represents a stationary object?
A. Line A
B. Line B
C. Line C
D. Line D
PLZ HELP
Line D represents a stationary object.
When an object is stationary, the line on the graph is horizontal.
When the object is stationary the gradient is?We know, that an object is stationary means the slope of its position-time graph is zero or its pt graph is a straight line parallel to the x-axis.
What is an example of a stationary object?The nest, or the resting place, is a stationary object, and one cannot put one's foot in front of it. A string is then tied from the head assembly to another stationary object.
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How much power is required to lift a 2.00-kg object 5.00 meters in 4.50 seconds? (If there is a formula for this please, tell me what it is also it is about pulleys one of the simple machines)
A swimmer jumps from a diving board into a pool. What would a graph of the swimmer's potential energy and total mechanical energy look like?(1 point)
Potential energy would increase, while total mechanical energy would remain constant.
Potential energy would remain constant, while total mechanical energy would increase.
Potential energy would decrease, while total mechanical energy would remain constant.
Potential energy would remain constant, while total mechanical energy would decrease.
Answer: Potential energy would decrease, while total mechanical energy would remain constant.
Explanation: I did the test and this was right.
The graph should represent the third option.
Potential energy & mechanical energy:The graph for the potential energy of the swimmer and the mechanical energy should be that there is a reduction of the potential energy and the mechanical energy should remain the same.
learn more about energy here; https://brainly.com/question/18640356
Two asteroids with masses 5.34 x 103 kg and 2.06 x 104 kg are separated by a distance of 5,000 m. What is the gravitational force between the asteroids? Newton's law of gravitation is F gravity Gmim. The gravitational constant Gis 6.67 x 10-11 N-m²/kg2. A. 400N B. 1.24 x 1032 N C. 1.47 x 10-6 N D. 2.93 x 10-10 N
Answer:
[tex]F=2.93\cdot 10^{-10}~N[/tex]
Explanation:
Newton’s Law of Universal Gravitation
Objects attract each other with a force that is proportional to their masses and inversely proportional to the square of the distance.
[tex]\displaystyle F=G{\frac {m_{1}m_{2}}{r^{2}}}[/tex]
Where:
m1 = mass of object 1
m2 = mass of object 2
r = distance between the objects' center of masses
G = gravitational constant: [tex]6.67\cdot 10^{-11}~Nw*m^2/Kg^2[/tex]
The asteroids have masses of [tex]m1=5.34\cdot 10^{3}~Kg[/tex] and [tex]m2=2.06\cdot 10^{4}~Kg[/tex] and are separated by r=5,000 m.
Calculating the gravitational force:
[tex]\displaystyle F=6.67\cdot 10^{-11}~Nw*m^2/Kg^2~{\frac {5.34\cdot 10^{3}~Kg \cdot2.06\cdot 10^{4}~Kg}{5,000^{2}}}[/tex]
Calculating:
[tex]\mathbf{F=2.93\cdot 10^{-10}~N}[/tex]
Answer:
D. 2.93 x 10-10 N
Explanation:
Answer got deleted? Dont delete my answer 'katie'
btw got it right
How does increasing the amount of charge on an object affect the electric force it exerts on another charged object?
The electric force increases because the amount of charge has an indirect relationship to the force.
The electric force increases because the amount of charge has a direct relationship to the force.
The electric force decreases because the amount of charge has an indirect relationship to the force.
The electric force decreases because the amount of charge has a direct relationship to the force.
Answer:
a
Explanation:
Answer:
A
Explanation:
brainlists please help
on the coner opposite of 8n is 5n
Answer:
resultant force=16N→(TOWARDS THE DIRECTION OF 8N)
Explanation:
resultant force=8N+13N-5N
=16N→(TOWARDS THE DIRECTION OF 8N)
If
you
increased one mass 2 times and another
mass by 4 times how would the force of gravity
between them change?
Answer:
A factor of 2*4 = 8
Explanation:
F_g = (G*m1*m2)/r^2
where m1 and m2 are the two masses, G is Newton's gravitational constant, and r is the distance between the center of mass of the two objects.
So, if you double m1 and quadruple m2:
m1' = 2*m1
m2' = 4*m2
Then F_g' = (G*m1'*m2')/r^2 = (G*2*m1*4*m2)/r^2 = 8*(G*m1*m2)/r^2 = 8*F_g
Un automóvil circula a una velocidad de 60 km/h durante 1 hora y 15 minutos, después se para durante 5 minutos y luego regresa hacia el punto de partida a una velocidad de 10 m/s durante 45 minutos. Halla: a) La posición final. b) La distancia recorrida. c) La velocidad media.
Answer:
(a) 48 km
(b) 102 km
(c) 48.96 km/h.
Explanation:
Assuming that at first, the car travels from point A to point B, then the cat returns from point B to point C.
As the car traveled from point A to point B in 1 hour 15 minutes with a speed of 60 km/h.
Using distance = speed x time, so
Distance traveled from A to B is
[tex]d_{AB}= 60 x 1.25=75[/tex] km [ as time = 1 h 15 min = 1.25 h]
Stop time at point B is 5 minutes.
For the return journey, from point B to C:
Speed = 10 m/s
Time = 45 minutes = 45 x 60 seconds = 2700 seconds
Distance traveled from point B to C is
[tex]d_{BC}=[/tex] 10 x 2700 = 27000 meters
as 1000 meters = 1 km, so
[tex]d_{BC}=[/tex] 27 km.
(a) The final position of the car from the starting point A is the distance between points A and C.
[tex]d_{AC}=[/tex]75 -27=48 km.
Hence, the car is 48 km away from point A.
(b) Total distance traveled,
[tex]d= d_{AB}+d_{BC}=[/tex]75+27=102 km.
(c) Total time taken
t= 1.25 hour + 5 minutes + 45 minutes
= 5/4 hour + 5/60 hour + 45/60 hour [ as 1 hour = 60 min]
=25/ 12 hours.
Total distance traveled, d= 102 km [ from part (b)]
Average speed = (Total distance traveled)/(Total time taken)
=102/ (25/12)= 48.96 km/h.
Hence, the average speed of the car is 48.96 km/h.
Define acceleration. Give its mathematical formula and SI unit. When is acceleration of a body negative? Give two examples of situations in which acceleration of the body is negative.
Answer:
The rate of change of velocity of a moving body is called acceleration. mathematical formula of Acceleration = Final velocity-Initial velocity
________________________
Time taken
SI Unit of Acceleration is m/s2. If the Velocity of a moving body decreases, it's acceleration will be negative. Two examples of situations in which acceleration of the body is negative are ÷
* Applying brakes * When a ball is thrown upward it experiences a negative Accelerationwhat is the direction of the sum of these two vectors?
Answer:
what is the direction of the sum of these two vectors?
Answer:
69.6
Explanation:
Ax= 0
Ay= 63.5
Bx= 101 cos 57= 55.009
By= 101 sin 57= 84.706
Tan-1 = (84.706/55.009)
= 69.6
A kangaroo hopped at 22 meters per second, saw a skunk and then
hopped at 52 meters per second. This is an example of which of the
following?
Acceleration
Velocity
Speed
motion graphs
Answer:
this is an example of acceleration
prove that:the unit of pressure is a derived units
What is a transverse wave like?
Answer:
a transverse wave is a moving wave whose oscillations are perpendicular to the direction of the wave or path of propagation
Explanation:
wave oscillate along paths at right angles to the direction of the wave’s advance.
Explanation:
An electric heater is rated 1000watts. If a current of 5A pass through the heater, find the value of its resistance.
Answer: R=40 Ω
Explanation: [tex]P=I^{2} R[/tex]
R=1000/ (25)=40
A soccer ball takes 30 seconds to roll 15 meters. calculate the average speed ot the ball using distance and tome measurements?
Answer:
average speed = 0.5 m/s
Explanation:
average speed = (distance) / (elapsed time)
Given time elapsed = 30 seconds and distance = 15 meters
average speed = 15 meters / 30 seconds = 0.5 meters/second = 0.5 m/s
If the astronaut from question #9 collides with a satellite and comes to a complete stop, where did his momentum go? Explain this in terms of conservation of momentum.
Answer:
m v ´- MV = (m + M) v ’
Explanation:
If the astronaut initially has a speed v the satellite has a speed V, we can define a system that is formed by the two bodies, therefore the forces during the collision are internal, so the momentum is conserved
initial instant. Before the crash
p₀ = m v - MV
final instatne. After the crash, we have two cases
1) inelastic shock
m_f = (m + M) v '
p₀ = p_f
m v ´- MV = (m + M) v ’
2) elastic collision with the astronaut's velocity, zero in this case the moment remains
m v - MV = mv ’+ Mv’
also the kinetic energy is conserved
mv'2 + M V2 = mv'2 + m v'2
with these two equations we can find the speed of the cars
a cyclist accelerates from a initial speed of 0 m/s to a final speed of 8 m/s in 3 second what is his acceleration?
Answer:
3 m/s ^2 rounded to one signifiicant figure.
Explanation:
Hope this helped!
What is the force needed to move a 300 kg object if you have an acceleration of 8 m/s2?
Answer: mass = 10 kg, acceleration = 3 m/s2.
Explanation: I hope that helped!!
1. When a car turns sharply to the right, objects in the back seat move to the left. Why?
2. What type of motion does an object have if it is falling with terminal velocity
Answer:
Explanation: It is inertia that causes the passengers to move toward the right side of the car. As the car swerves to left, passengers' body continues their motion as hitherto and as such it causes the passengers to move toward the right side of the car.
Please help me idk what dis