Answer:
The net force acting on the wagon is 63 N
Explanation:
Net Force
According to the second Newton's law, the net force exerted by an external agent on an object of mass (m) is:
F = m.a
Where (a) is the acceleration of the object.
The wagon has a mass of m=42 Kg is accelerated at [tex]a=1.5\ m/s^2[/tex]. The net force is:
F = 42*1.5
F = 63 N
The net force acting on the wagon is 63 N
A child pushes a 100 kg refrigerator with a force of 50 N, but the refrigerator does not move. Suppose the coefficient of static friction between the floor and the refrigerator is 0.4. What is the force due to friction in this scenario
Answer:
50 N
Explanation:
Since the refrigerator doesn’t move, that means the force of friction equals the amount of force the child exerts on the fridge. If the friction force were greater than the force by the child, the fridge would start accelerating towards the child. If it were less than the force the child exerted, the fridge would start accelerating away from the child. Therefore, the net force must be 0, in this case, the friction force is equal to the force the child exerted, for it to stay at rest (as Newton’s First Law stated).
I hope this helps! :)
What would the mechanical advantage of a ramp be if the length is 25 feet and the height is 5 feet?
10
125
5
30
Answer:
5.
Explanation:
From the question given above, the following data were obtained:
Length (L) of ramp = 25 feet
Height (H) of ramp = 5 feet
Mechanical advantage (MA) of ramp =?
Mechanical advantage of an inclined plane is simply defined as the ratio of the length of the ramp to the height of the ramp. Mathematically, it is expressed as:
Mechanical advantage = length /height
MA = L/H
With the above formula, we can simply calculate the mechanical advantage of the ramp as follow:
Length (L) of ramp = 25 feet
Height (H) of ramp = 5 feet
Mechanical advantage (MA) of ramp =.?
MA = 25 / 5
MA = 5
The, the mechanical advantage of the ramp is 5.
Answer:
5.
Explanation:
From the question given above, the following data were obtained:
Length (L) of ramp = 25 feet
Height (H) of ramp = 5 feet
Mechanical advantage (MA) of ramp =?
Mechanical advantage of an inclined plane is simply defined as the ratio of the length of the ramp to the height of the ramp. Mathematically, it is expressed as:
Mechanical advantage = length /height
MA = L/H
With the above formula, we can simply calculate the mechanical advantage of the ramp as follow:
Length (L) of ramp = 25 feet
Height (H) of ramp = 5 feet
Mechanical advantage (MA) of ramp =.?
MA = 25 / 5
MA = 5
The, the mechanical advantage of the ramp is 5.
A teacher pushes a cart, while a student pushes a second, heavier cart
with the same amount of force. If the student's cart has three times the
mass as the teacher's, which of the following is true? *
Answer:
frictional force acting on the cart 450 N.
Given:
mass of cart = 50 kg
acceleration = 3
To find:
Frictional force = ?
Formula used:
F - = 600 N
F = ma
= frictional force
Solution:
Force on the block is given by,
F - = 600 N
F = ma
= frictional force
= 600 - m a
= 600 - (50 × 3)
= 600- 150
= 450 N
According to the given data the frictional force acting on the cart 450 N.
Explain why different types of musical instruments sound different, even though they play the same notes.
Draw a picture showing the possible phases of the moon in this binary star
system, do they look the same or different from those we see in the sky in
reality? (You might want to think about scale and how far the suns would be
when considering your answer.)
(Help ASAP)
A merry go round exerts a force of 1000 N on a rider on the
outer ring of animals when it takes 15 seconds to make a
complete revolution. If the person weighs 750 N, the radius
of the circle he is making is m. Round your answer to
the nearest tenth.
Answer:
The radius of the circle made by the person on the merry go round is 74.55 meters
Explanation:
The given parameters are;
The force the merry go round exerts on the rider = 1000 N
The time it takes the merry go round to make one complete revolution = 15 seconds
The weight of the person = 750 N
The radius of the circle made by the person on the merry go round = r
We have;
[tex]F_c = \dfrac{m \cdot v^2}{r} = m \cdot \omega ^2 \cdot r[/tex]
Where;
m = The mass of the person
v = The velocity of the person
[tex]F_c[/tex] = The centrifugal force acting on the person = 1,000 N
r = The radius of the circle made by the person on the merry go round
ω = Angular velocity = 2·π/15 rad/s
We have;
The mass of the person = The weight/(The acceleration due to gravity, g)
∴ The mass of the person = 750/9.81 ≈ 76.45 kg
By substituting the calculated and known values into the equation for the centripetal force, we have;
[tex]F_c[/tex] = m × ω² × r
1000 = 76.45 × (2·π/15)² × r
r = 1000/(76.45 × (2·π/15)²) = 74.55 m
The radius of the circle made by the person on the merry go round = r = 74.55 m.
question in the photo
A 10 kg object experiences an acceleration of 2 m/s squared. What net force was applied to the object?
F = ma
= 10kg × 2m/s
= 20N
Answer : 20N
Explanation :
F = Force (N)
m = mass (kg)
a = acceleration (m/s)
A sound wave passes from air into water and then into steel. With each change in medium, the velocity of this wave will a(increase,then decrease b(decrease c(increase d( decrease,then increase ?
Answer:
a
Explanation:
because it can increase anything
I need help in Physics pls help me!
20 points for CORRECT ANSWER!!!
Answer:
V = 3.65 m/s
Explanation:
If 200 ml of a gas at 27 degrees celsius is cooled to -33 degrees Celsius at a constant pressure , the volume will be
A 250ml
B 204ml
C 196ml
D 160ml
Given that,
Volume of gas, V₁ = 200 mL
Initial temperature, T₁ = 27°C
Final temperature, T₂ = -33°C
To find,
New volume of the gas.
Solution,
Initial temperature, T₁ = 27°C = 300 K
Final temperature, T₂ = -33°C = 240 K
Let V₂ is the new volume.
The relation between volume and temperature is given by :
[tex]\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}\\\\V_2=\dfrac{V_1T_2}{T_1}\\\\=\dfrac{200\times 240}{300}\\\\=160\ mL[/tex]
Hence, the volume will be 160 mL.
WILL MARK BRAINLY!! QUICK HELP PLEASE!
A 40.0 kg rocket produces a
764 N upwards force ("thrust").
What is the net force acting on
the rocket?
Answer:
372Explanation:(40.0)×(9.8)=392
764N-392=372
a beaker weighs 0.4N when empty and1.4N when filled with water what does ot weigh when filled with brine of density 1.2 g/cm3
Answer: 1.6 N
Explanation:
The weight of an object is calculated as:
W = g*m
where:
g = gravitational acceleration = 9.8m/s^2
m = mass of the object.
We also know that:
mass = density*volume.
or:
m = d*v
Let's start:
The weight of the beaker is 0.4N
And the weight of the beaker filled with water is 1.4N
Then the weight of the water alone will be:
1.4N - 0.4N = 1N = (d*v)*9.8m/s^2
And we know that the density of the water is:
1 g/cm^3
But we are working with Newtons, then we need to rewrite this with kilograms as the mass unit, we can use that:
1000g = 1kg
Now we can rewrite the density as:
d = 1 g/cm^3 = 1*(1/1000) kg/cm^3 = 0.001 kg/cm^3
Replacing that in the above equation, we get:
With this, we can find the volume that the water occupies.
W = 1 N = v* 0.001 kg/cm^3*9.8m/s^2
1 N /( 0.001 kg/cm^3*9.8m/s^2 ) = 102.04 cm^3.
Now, when we fill it with a brine with a density of 1.2 g/cm^3, the mass of this brine in a volume of 102.04 cm^3 be:
M = (1.2 g/cm^3)*( 102.04 cm^3) = 122.448 g
Rewriting this in kg we get:
M = 122.448 g = (122.448/1000) kg = 0.122448 kg
Then the weight of this brine is:
M = 0.122448 kg*9.8m/s^2 = 1.2 N
And the beaker weighs 0.4N, then the beaker filled with this brine will weight:
1.2 N + 0.4N = 1.6 N
Alex wants to learn how to surf, but he is not a strong swimmer. He knows he needs to increase his ability to paddle out in order to catch the best waves. Which piece of advice would you give to help him get started on reaching his goal? He should swim at least three times a week at the community pool to build stamina. He should tread water every day to get more comfortable in the water. He should purchase the best surfboard he can afford because it will help him paddle faster. He should watch your friend who is a competitive surfer practice to learn her technique.
Answer:
He should swim at least three times a week at the community pool to build stamina.
Explanation:
A loudspeaker produces a sound wave of frequency 50hz.
The amplitude of sound wave is increased.
What is heard?
A) a louder sound of higher pitch.
B) a louder sound of the same pitch.
C) a sound of higher pitch but the same loudness.
D) a sound of the same pitch and loudness as before.
Using Velocity vs Time Graphs to Find Acceleration
A graph titled velocity versus time has horizontal axis time (seconds) and vertical axis velocity (meters per second). A line has 4 straight segments. Line segment A runs from 0 seconds 0 meters per second to 1 seconds 15 meters per second. Then segment B runs to 2 seconds 20 meters per second. Then segment C runs to 4 seconds 20 meters per second. Then segment D runs to 5 seconds 0 meters per second.
The acceleration of segment D is m/s2.
Rank segments A, B, and C from least acceleration to greatest acceleration.
Least:
Greatest:
The acceleration at segment D is -20m/s²
The rank of the acceleration from the least to the greatest is -20m/s² < 0m/s² < 5m/s² < 10m/s² (D<C<B<A)
Acceleration is the change in velocity with respect to time.
a = v-u/t
Acceleration at segment A:
Aa = 15-0/1-0
Aa = 15m/s²
Acceleration at segment B:
Ab = 20-15/2-1
Ab = 5m/s²
Acceleration at segment C:
Aa = 0-0/4-2
Aa = 0m/s²
Acceleration at segment D:
Ac = 0-20/5-4
Ac = -20m/s²
Hence the acceleration at segment D is -20m/s²
The rank of the acceleration from the least to the greatest is -20m/s² < 0m/s² < 5m/s² < 10m/s² (D<C<B<A)
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Four measurements of the file card's width are made. Of the measurements given below, the LEAST precise.
O 7.62
O 7.63
O 7.34
O 7.6
Describe the last three years of your life. Include positive and negative experiences.
For a middle school girl
Answer:
my middle school life was horrible and still is sadly ); could you please do my recent brainless <333
Explanation:
My middle school life was eh.i allways got assumed that i was a elementry kid when i was and 6 and 7 grade.until 8th when i hit my grow spurt.my voice end up getting really deep in 8th grade too.tho in 8th i got sent to a certain type of scholl for kids who did bad because of some dum teacher who lied that i hit her when i actually just went to her desk to get my phone sence she saw it in my pocket and took it away.i got sent there for 3 months and was worst thing ever.the treated us like prisoners in that school and made us tacky uniforms that i refused to where.i believe it was a school for 7th-12th.after my expierence at that school my expierence in 8th grade was almost done.i end up being popular at school for being that kid who hit the teacher.ofc that was like 2 years ago im 10th now.i dont really remember my 6th and 7th grade year.only thing i rember is i was a trouble maker and still am a trouble maker.
hope that helped you:)
please make my answer brainiest as im trying get 4 brainiest answers
A car with a mass of 900 kg is traveling at a
speed of 25 m/s. What is the kinetic energy
from the car's motion?
Explanation:
Kinetic Energy
= 0.5mv²
= 0.5(900kg)(25m/s)²
= 281,250J.
Which frequency would be the third harmonic in a series for an open-pipe resonator if the fundamental is 440 Hz
Answer:
1320 Hz
Explanation:
The third harmonic is given as 3fo, where fo is the fundamental frequency.
The fundamental frequency is the lowest frequency that can occur in a pipe. In an open pipe, both even and odd harmonics occur which are multiples of the fundamental frequency fo. Hence the harmonics in an open pipe are; 2fo, 3fo,4fo..... etc.
For the third harmonic; 3fo = 3 (440 Hz) = 1320 Hz
Which of the following is NOT one of the essential components of an exercise program?
Answer:
i dont know dude but ask someone who is in your grade lol
Explanation:
The fall of a body on the earth surface cannot be a complete free fall ? why
How long will it take an object traveling at 7 m/s to reach a distance of 26 meters
Answer:
3 hours 71 minutes
Explanation:
As because Speed= distance/time taken
so time taken= 3.71
n Olympic diver is on a diving platform 3.60 m above the water. To start her dive, she runs off of the platform with a speed of 1.3 m/s in the horizontal direction. What is the diver's speed, in m/s, just before she enters the water
Answer:
8.5m/s
Explanation:
Using the equation of motion
v² = u² + 2gH
v is the final speed of the diver
u is the initial speed of the diver
g is the acceleration due to gravity
H is the height of the object
Given the following
V = 1.3m/s
H = 3.60m
g = 9.8m/s²
Required
Initial speed of the diver u
Substitute the given values into the formula:
v² = u² -2gH
1.3² = u² - 2(9.8)(3.60)
1.69 = u²-70.56
u² = 1.69+70.56
u² = 72.25
u = √72.25
u = 8.5m/s
Hence the diver's speed, in m/s, just before she enters the water is 8.5m/s
True or false Adding salt to a pot of water will decrease the temperature that water boils at.
Answer:water gets hot at 212 so incress
Explanation:
Answer:
False
Explanation:
It will increase
an object weighs 150N on earth. what is the mass of the object?
Answer:
450 g =0.9921 lb
Explanation:
pls help me w this, I've been doing this since 5 minutes ago
Answer:
t=0.0625s
Explanation:
F=number of swings/time taken
DATA
Frequency=4.0Hz
number of swings from Q to R
=1/4
time taken=?
Frequency=number of swings/time taken
make t the subject of the formula
t=n/f
substitute the given date
t=0.25/4.0
t=0.0625s
option A is collect
The temperature of rock located 1,000 kilometers below the Earth's surface is about a. 200 C b.2,100 C c.2,800 C d.3,200 C
The temperature of the rock located at 1,000 km below the earth' surface has been 3200 degree Celsius. Thus, option D is correct.
The temperature at the earth's surface has been found to be nearly 0 degree Celsius. According to the geology of the earth, the temperature has been increased to 1500 degree Celsius by digging 100 km below the earth surface.
Thus, the temperature at 100 km from earth surface has been 1500 degree Celsius.
On moving down from 100 km, there has been a rise in temperature, and at the mouth of the mantle at 1000 km, the temperature has been approximately 3500 degree Celsius.
Thus the temperature that has been near about 3500 degree Celsius is 3200 degree Celsius. Thus, the temperature of the rock at 1000 km below the earth surface has been 3200 degree Celsius. Thus, option D is correct.
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26. For this table of data, which column is the independent variable?
radius of circle (m) area of circle (m2)
3.4
36.317
4.5
63.617
4.6
66.476
6.2
120.763
7.6
181.458
7.7
186.265
8.6
232.352
9.7
295.592
area of circle
o
radius of circle
O
None of these is correct.
Answer:
radius of a circle is measured by an instrument, so it is the independent variable
Explanation:
The independent variable corresponds to the magnitude controlled by the experimenter and in general can be measured by an instrument.
The dependent variable is the variable used to perform the calculations, obtained from a mathematical transformation of the independent variable.
The radius of a circle is measured by an instrument, so it is the independent variable and the area is calculated by
A = π r²
Therefore the area corresponds to the dependent variable
Explain why the total positive charge in every atom of an element is always the
same.
Answer:
When an atom has an equal number of electrons and protons, it has an equal number of negative electric charges (the electrons) and positive electric charges (the protons). The total electric charge of the atom is therefore zero and the atom is said to be neutral.
Explanation:
An atom has an equal quantity of positive and negative electric charges (the protons and electrons) when its electron and proton counts are equal (the protons). Since the atom has a total electric charge of zero, it is referred regarded as being neutral.
What is an atom?The atom is the smallest unit of matter that may be divided without resulting in electrically charged particles. Additionally, it is the tiniest substance with features like chemical elements. The atom is therefore the basic building block of chemistry.
Examine different electron arrangements in the electron shells that surround an atom's nucleus.
Examine different electron arrangements in the electron shells that surround an atom's nucleus. The rest is made up of a cloud of negatively charged electrons surrounding a positively charged nucleus made up of protons and neutrons. Compared to electrons, which are the lightest charged particles in nature, the nucleus is small and dense.
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