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Answer:

Shrink-wrap, Box-top, and Click-wrap Agreements

a) The best practices to assure that shrink-wrap, box-top, and click-wrap agreements are legal include  

1) having e-commerce terms and conditions separate from the normal trade terms and conditions,  

2) ensuring that customers agree to the terms before entering into a transaction, and  

3) laying the code of conduct for all visitors interacting with your site or doing any business transaction on your site.

b) The best ethical practices that the e-commerce industry should adopt are:

1) Put additional layers of protection like a web application firewall to their websites.  

2) Ensure they always adhere to PCI (Payment Card Industry) compliance guidelines.

3) They should not store customers' data which they do not need.

4) Ensure privacy and security of customers' data.

5) Establish trust by safeguarding intellectual property rights.

6) Consider some environmental issues (customers care about them).

Explanation:

a) Websites' Terms and Conditions (T&C) establish some form of legal contract between the organization and its clients.  

b)To ensure that organizations that process, store, or transmit credit card information maintain secure online environment, they are required to comply with PCI DSS.  It is a set of Payment Card Industry requirements for all organizations involved in the use of online cards for payment for their goods and services.

Answer:

some advantages of top down is that you can start off from what you know and figure out what you need to complete it, advantages to bottom up is that you can make something new . if you are starting something from scratch and you dont know what the end goal might be you would use bottom up but if you already have an idea or the final product of what you want you would go the top down approach.

Explanation: just saying you shouldnt just copy and paste my response but rather pick out what you want to say and use this to complete what ever your working on. hope i helped :)

Answer:

the guy on top of me is super right follow him

Explanation:

Answer:

ring

Explanation:

import java.util.Scanner;

import java.util.Arrays;

public class JavaApplication30 {

   public static int max(int x, int y, int z){

       int[] arr = {x, y, z};

       Arrays.sort(arr);

       return arr[2];

   }

   public static int min(int x, int y, int z){

       int[] arr = {x, y, z};

       Arrays.sort(arr);

       return arr[0];

   }

   public static double average(int x, int y, int z){

       return  (double) (x + y + z) / 3;

   }

   public static void main(String[] args) {

       Scanner scan = new Scanner(System.in);

       System.out.println("Enter your first number");

       int x = scan.nextInt();

       System.out.println("Enter your second number");

       int y = scan.nextInt();

       System.out.println("Enter your third number");

       int z = scan.nextInt();

       System.out.println("Min is "+min(x,y,z));

       System.out.println("Max is "+max(x,y,z));

       System.out.println("Average is "+average(x,y,z));

   }

}

I hope this helps! If you have any more questions, I'll try my best to answer them.

Answer: It’s Letter (B) the other ones just don’t fit.

Explanation:

Mark me as brainlest please?!!

Answer:

b

Explanation:

Answer:

a) "Quit"  

c) "Q only

Explanation:

Given

String s = "Go";

while ((!s.equals("q"))&& (!s.equals("")))  {

System.out.println("In loop");

s = scnr.next();

}

Required

What input causes another execution

Analyzing the while condition

while ((!s.equals("q"))&& (!s.equals("")))  

This can be split into:

!s.equals("q")) && (!s.equals(""))

Meaning

When s is not equal to "q" and when s is not an empty string

In other words,

the loop will be executed when user input is not "q" and user input is not empty.

So, from the list of given options: The loop both will be executed when:

a) Input is "Quit"

c) Input is Q only

Input of q will terminate the loop, hence b and d are incorrect

I wrote my code in python 3.8:

def print_total_inches(num_feet, num_inches):

   return ((num_feet)*12) + num_inches

print("There are a total of {} inches".format(print_total_inches(5,8)))

I hope this helps!

Answer:

#include <iostream>

#include <cstring>

using namespace std;

struct Data {

   int userId;

   char name[80];

}

void newData(string data char[]){

   int counts= 0;

   struct Data name;

   data.userId = ++counts;

   data.name = char[];

   cout<< data.userId << "\n"<< data.name ;

}

int main( ) {

   char myName;

   string mydata;

   cin>> myName;

   cin>> mydata;

   newData( myName, mydata);

}

Explanation:

The c++ source code above stores its data in a struct called "Data". The function newData dynamically creates new data from the struct defined.

Answer:

length = 12 cm

breadth = 9 cm.

perimeter of rectangle = 2( l+b)

= 2(12+9) = 2(21) = 42cm.

New length = (12+x) cm

New breath = (9+x) cm

2(12+x+9+x) = 42×2

2(21+x) = 84

21+ x = 84/2

21+x = 42

x= 42-21= 21

x= 21.

Therefore, length = (12+x)cm

=( 12+21) cm = 33cm.

Explanation:

Firstly we have written the length and breadth of the rectangle.

And the perimeter of rectangle i.e. 2(l+b)

Then, as it is in question we have doubled the perimeter

And at last, we have got the value of x.

and by putting the value in the new length we will get our answer.

hope you have got your answer dear.

Question:

Vector testGrades contains NUM_VALS test scores. Write a for loop that sets sumExtra to the total extra credit received. Full credit is 100, so anything over 100 is extra credit. Ex: If testGrades = {101, 83, 107, 90}, then sumExtra = 8, because 1 + 0 + 7 + 0 is 8.

#include <iostream>

#include <vector>

using namespace std;  

int main() {

  const int NUM_VALS = 4;

  vector<int> testGrades(NUM_VALS);

  int i = 0;

  int sumExtra = -9999; // Assign sumExtra with 0 before your for loop  

  testGrades.at(0) = 101;

  testGrades.at(1) = 83;

  testGrades.at(2) = 107;

  testGrades.at(3) = 90;

   /* Your solution goes here  */

  cout << "sumExtra: " << sumExtra << endl;

  return 0;

}

Answer:

Replace /* Your solution goes here  */  with the following lines of code

sumExtra = 0;

do{

if(testGrades.at(i) > 100){

sumExtra = sumExtra + (testGrades.at(i) - 100);

}

i++;

}

while(i<NUM_VALS);

Explanation:

In the complete question posted,  the variables sumExtra and i have already been declared an initialized.

So, the first thing we do in the solution is:

set  sumExtra to 0 using sumExtra = 0;

Then iterate through vector testGrades using i as the iterating variable

Here, I made used of a do while loop and the explanation is as follows:

do{

This line checks if current element of the vector is greater than 100

if(testGrades.at(i) > 100){

If yes, the extra digits above 100 is added to the sumExtra

sumExtra = sumExtra + (testGrades.at(i) - 100);

}

The counter is increased, here

i++;

}

The loop is continued while the iterating variable i is less than NUM_VALS which is 4

while(i<NUM_VALS);

Answer:

a block of data inside the packet

Answer:

def encrypt_text(text,value):

   encoded = ""

   for i in range(len(text)):

       char = text[i]

       if (char.isupper()):

           encoded += chr"po"ord'po'char'pc' + value -65'pc' % 26 + 65'pc'

       else:

           encoded += chr'po'ord'po'char'pc' + value -97'pc' % 26 + 97'pc'

   return encoded

plaintext = input("Enter sentence of encrypt: ")

dist_value = int(input("Enter number: "))

encrypted = encrypt_text(plaintext, dist_value)

print(encrypted)

Explanation:

The python program above is a Ceasar cipher implementation. The encrypt_text function is defined to accept text input and a distance value, which is used to encrypt the plaintext.

The user can directly input text and the distance value from the prompt and get the encrypted text printed on the screen.

public class JavaApplication78 {

   public boolean findChar(String string, String key){

       if (string.contains(key)){

           return true;

       }

      return false;

   }

   public static void main(String[] args) {

       JavaApplication78 java = new JavaApplication78();

       System.out.println(java.findChar("hello", "h"));

   }

}

First I created the findChar method using the contains method. It checks to see if a certain sequence of characters is in another string. We returned the result. In our main method, we had to create a new instance of our main class so we could call our findChar method.

B will cause an error.

Allison needs to declare a type for variable i and use semi-colons.

The for statement should be for(int i = 0; i <=13; i++){