a trucker is driving on the highway traveling 65 miles per hour write an equation that shows the relationship between the number of hours of highway travel x and the number of miles traveled 7 answer quickly for 20 points!!

Answer:

∠ DFG = 48°

Step-by-step explanation:

the central angle is equal to the measure of the arc that subtends it.

since EOG is the diameter of the circle with central angle of 180° , then

arc EG = 180°

the inscribed angle EGD is half the measure of the arc ED that subtends it, so

arc ED = 2 × ∠ EGD = 2 × 42° = 84° , then

ED + DG = EG , that is

84° + DG = 180° ( subtract 84° from both sides )

DG = 96°

Then

∠ DFG = [tex]\frac{1}{2}[/tex] × EG = [tex]\frac{1}{2}[/tex] × 96° = 48°

Based on the information, A. There is a 99% chance that the proportion of students who eat cauliflower on Jane's campus is between 5.03% and 17.83%.

Calculate the sample proportion:

= x / n = 4 / 35

= 0.1143

Calculate the Agresti and Coull's adjustment factor:

zα/2 = z(1 - α/2) = z(1 - 0.99/2)

= 2.576

Calculate the margin of error:

= 2.576 √(0.1143(1 - 0.1143) / 35)

= 0.064

Calculate the confidence interval:

= 0.1143 ± 0.064

= (0.0503, 0.1783)

We are 99% confident that the true proportion of students who eat cauliflower on Jane's campus is between 5.03% and 17.83%.

In other words, if we were to repeat this study many times, we would expect to obtain a confidence interval that includes the true proportion of students who eat cauliflower on Jane's campus 99% of the time.

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The product of (7x - 5)(6x - 4) is 42x^2 - 58x + 20.

First, distribute the first term of the first polynomial (7x) to each term in the second polynomial (6x - 4):

7x × 6x = 42x²

7x × (-4) = -28x

Next, distribute the second term of the first polynomial (-5) to each term in the second polynomial (6x - 4):

-5 × 6x = -30x

-5 × (-4) = 20

Now, combine the like terms:

42x² - 28x - 30x + 20

Simplify the expression:

42x² - 58x + 20

Therefore, the product of (7x - 5)(6x - 4) is 42x^2 - 58x + 20.

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Answer:

The remaining is 75%, the length of the stick would be 1.2

Step-by-step explanation:

According to the information given,

We know that Brian cut off 25% of a stick which was 1.6 meters long

and 1.6 is the 100% of the stick:

It is fairly easy to calculate this, subtract 25 from 100 ( 100 - 25 ), which is equal to 75.

Hence, the answer is 75% and 1.2 for the remaining length of the stick

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The vertices of triangle image are L'(1, -4), M'(6, 4) and N'(7, -2).

Given that, triangle LMIN with vertices L(2, -8), M(12, 8) and N(14,-4).

Here, scale factor k=1/2

Now, by applying scale factor to the vertices, we get

L(2, -8)→1/2 (2, -8)→L'(1, -4)

M(12, 8)→1/2 (12, 8)→M'(6, 4)

N(14,-4)→1/2 (14, -4)→N'(7, -2)

Therefore, the vertices of triangle image are L'(1, -4), M'(6, 4) and N'(7, -2).

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"Your question is incomplete, probably the complete question/missing part is:"

Triangle LMIN with vertices L(2, -8), M(12, 8), and N(14,-4): k = ½.

"The set of all functions from X to Y" refers to the collection of all possible functions that can be defined from a set X to a set Y. This set is denoted as Y^X or X→Y.

Each element of the set Y^X is a function that maps each element of set X to a unique element of set Y. The notation for such a function f is f: X → Y.

Given,

f is a function from X to Y .

Note:

The cardinality (size) of the set Y^X is given by |Y^X| = |Y|^|X|. In other words, if the set X has m elements and the set Y has n elements, then the set of all functions from X to Y has n^m elements.

It is often used to describe the space of all possible solutions to a given problem or equation.

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The measure of length of the triangle is solved and

a) x = 4.9 units

b) x = 14 units

c) x = 4.8 cm

d) b = 68.5 units

Given data ,

Let the triangle be represented as ΔABC

where the measure of the lengths of the sides are given as

a)

The measure of hypotenuse AC = 12

The measure of angle ∠BAC = 66°

So , from the trigonometric relations , we get

cos θ = adjacent / hypotenuse

cos 66° = x / 12

So , x = 12 cos ( 66 )°

x = 4.9 units

b)

The measure of base of triangle BC = 20 units

And , the angle ∠BAC = 55°

So , from the trigonometric relations , we get

tan θ = opposite / adjacent

tan 55° = 20/x

x = 20 / tan55°

x = 14 units

c)

The measure of base of triangle BC = 4 cm

And , the angle ∠BAC = 57°

So , from the trigonometric relations , we get

sin θ = opposite / hypotenuse

sin 57° = 4/x

x = 4 / sin 57°

x = 4.8 cm

d)

The measure of base of triangle BC = 38 units

And , the angle ∠BAC = 61°

So , from the trigonometric relations , we get

tan θ = opposite / adjacent

tan 61° = b/38

b = 38 x tan 61°

b = 68.5 units

Hence , the trigonometric relations are solved.

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The road trip will take approximately 5 hours.

Two one-step equations:

a) 2x + 5 = 13

In this equation, the variable 'x' represents an unknown number. By performing one step of subtraction, we can find the value of 'x' that makes the equation true.

The solution is x = 4.  

b) 3y - 7 = 16

Similar to the first equation, 'y' represents an unknown number.

By adding 7 to both sides of the equation, we can isolate the variable and solve for 'y.'  

The solution is y = 7.

Two equations with fractions:

a) (1/3)x + 2 = 5

Here, the variable 'x' is multiplied by a fraction.

To isolate 'x,' we can subtract 2 from both sides and then multiply both sides by the reciprocal of 1/3, which is 3/1.

The solution is x = 9.

b) (2/5)y - 3 = 1

In this equation, 'y' is multiplied by a fraction.

We can isolate 'y' by adding 3 to both sides and then multiplying both sides by the reciprocal of 2/5, which is 5/2.

The solution is y = 4.

One equation with the distributive property:

a) 2(x + 3) = 10

This equation demonstrates the distributive property.

By applying it, we multiply 2 by both x and 3, resulting in 2x + 6 = 10.

We can then solve for 'x' by subtracting 6 from both sides.

The solution is x = 2.

One equation with decimals:

a) 0.4x + 0.8 = 1.6

In this equation, 'x' is multiplied by a decimal.

To isolate 'x,' we subtract 0.8 from both sides and then divide both sides by 0.4.

The solution is x = 2.

Real-world problem:

Imagine you're planning a road trip.

The distance you'll be traveling is 250 miles, and your car's average speed is 50 miles per hour.

You want to determine how long the trip will take.

Let 't' represent the time in hours it will take to complete the trip.

The equation that represents this situation is:

50t = 250

By dividing both sides of the equation by 50, we find that t = 5.

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The value of x would be,

⇒ x = 15

We have to given that;

A figure with QC is parallel to BR

Now, We can formulate that,

Triangle BDR and triangle CDQ are similar.

Hence, By using proportionality we get;

⇒ BD / DR = QD / CD

Substitute all the values we get;

⇒ (24 + 40) / (15 + x) = 40 / x

Solve for x,

⇒ 64 / (15 + x) = 40 / x

⇒ 64x = 40 (15 + x)

⇒ 8x = 5 (15 + x)

⇒ 8x = 45 + 5x

⇒ 8x - 5x = 45

⇒ 3x = 45

⇒ x = 15

Thus, The value of x would be,

⇒ x = 15

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Answer:

n this question, you are asked how much the maximum revenue. Since candy Y sold for a higher price than candy X, that means you have to sell candy Y as much as possible.The number of candy Y must be >= 3 times candy X. Since this won't limit candy Y selling, then you can convert all 36 candy into candy Y and 0 candy X36 candy (Y) >= 0 candy(X) ----> the requirement is met.The revenue would be 36 candy Y * $3/candy Y= $108

Step-by-step explanation:

Answer: i'm kind of just guessing, but i think x = 13

Step-by-step explanation:

please don't ask me how i don't know

Answer:

Decrease in temp.

Step-by-step explanation:

Here is the reason:

Initially, at an altitude of 3,000 meters above sea level, the temperature was 12 degrees Celsius. As the altitude increased, the temperature dropped to 4 degrees Celsius. Since the temperature decreased from 12 degrees Celsius to 4 degrees Celsius, there was a decrease in the temperature

The true statements about the graph of h(x) = ∛(x-4) are:

The domain of h(x) is the set of all real numbers.

For all points (x, h(x)), h(x) exists if and only if x - 4≥0

The graph of h(x) intercepts the x-axis at (4, 0).

The domain of h(x) is the set of all real numbers since there are no restrictions on the input variable x.

For all points (x, h(x)), h(x) exists if and only if x - 4 ≥ 0. This is because the cube root function is only defined for non-negative values, and the expression inside the cube root, x - 4, must be non-negative for h(x) to exist.

The graph of h(x) intercepts the x-axis at (4, 0) since plugging in x = 4 into the equation gives h(4) = ∛(4-4) = ∛0 = 0. This means that the point (4, 0) lies on the graph.

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Answer:

-8 and 4

Step-by-step explanation:

P= -2

-2+6 = 4

-2-8= -8

The other options provided, -3x - 1, -x - 12, and -x - 3, do not match the simplified form of the given expression. Only -3x - 4 corresponds to the original expression after simplification. It is important to carefully distribute and combine like terms to simplify expressions correctly.

The expression shown is 2 + 2(x – 3) – 5x. To find an equivalent expression, we need to distribute the 2 to both terms inside the parentheses, resulting in 2x - 6. Now we can simplify the expression further:

2 + 2x - 6 - 5x

Combining like terms, we have:

(2x - 5x) + (2 - 6)

This simplifies to:

-3x - 4

Hence, the expression -3x - 4 is equivalent to 2 + 2(x – 3) – 5x.

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The statement indicates that in practical applications, it is common to extend the basic logical language with additional symbols and allow for some degree of informality in the representation of formulas, as long as it is clear that these additional symbols and formulas can be formalized in terms of the basic logical language.

The statement means that when working with formulas in a particular context or domain, it is common to introduce additional symbols beyond the basic logical symbols such as "E" (for existential quantification) and "∧" (for conjunction). These additional symbols can include defined predicates, operations, and constants.

Defined predicates refer to predicates or relations that are defined in terms of other predicates or relations. They can be used to express complex concepts or conditions in a concise manner. For example, in mathematics, one may define a predicate "Prime(x)" to represent the concept of a number being prime.

Operations refer to functions or operations that can be applied to terms or formulas. They allow for combining or manipulating expressions in a meaningful way. For instance, addition, multiplication, and exponentiation are common operations in mathematics.

Constants are symbols that represent specific, fixed values. They can be used to denote specific objects or elements within the domain of discourse. For example, in logic, "0" and "1" can be used as constants to represent the truth values "false" and "true," respectively.

Furthermore, the statement suggests that formulas may be used informally, meaning that they can be expressed or written in a less strict or precise manner. While the informal representation of formulas may be easier to understand or work with, it is understood that each of these formulas can be translated or reformulated in a way that only involves the basic logical symbols (such as "E" and "∧") and the specified nonlogical symbols (such as defined predicates, operations, and constants).

Overall, the statement acknowledges that in practical applications, it is common to extend the basic logical language with additional symbols and allow for some degree of informality in the representation of formulas, as long as it is clear that these additional symbols and formulas can be formalized in terms of the basic logical language.

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The solutions of the quadratic equation are: x = 1

The x-intercept is x = 1

The formula for the equation of a line in slope intercept form is:

y = mx + c

where:

m is slope

c is y-intercept

The y-intercept is the point at which the graph crosses the y-axis and in this case it is: y = 1

The x-intercepts are where the graph touches the x-axis and in this case, it is x = 1

The zeros of the quadratic equation are the x-intercepts and since the curve does not cross, then we can say that the zeros are x = 1 and x = 1 which signifies double root and as such the solution is x = 1

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Answer:

 [(5 ± √(29)) ÷ 2]

Step-by-step explanation:

x = [(-b ± √(b² - 4ac)) ÷ 2a]

=  [(-(-5) ± √((-5)² - 4(1)(-1))) ÷ 2(1)]

=  [(5 ± √(25 + 4)) ÷ 2]

=  [(5 ± √(29)) ÷ 2]

1. There is no relationship

2. Two cities have an average snowfall of nearly 100 inches.

A scatter plot, also known as a scatter diagram or scatter graph, displays the relationship between two variables. It is particularly beneficial for identifying any patterns or trends in the data and showing how one variable might be related to another.

In a scatter plot, each data point is represented on the graph by a dot or marker. The horizontal axis (x-axis) is frequently used to represent the independent variable or predictor, while the vertical axis (y-axis) is frequently used to represent the dependent variable or reaction. Each dot's locations on the graph correspond to the values of the two variables for that particular data point.

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The required answer are :

6. The transformation from the graph of f to the graph of r in equation (6) involves compressing the graph horizontally by a factor of 5/2.

7. The transformation from the graph of f to the graph of r in equation (7) involves stretching the graph vertically by a factor of 6.

8.  The transformation from the graph of f to the graph of r in equation (8) involves shifting the graph horizontally to the right by 3 units.

9. The transformation from the graph of f to the graph of r in equation (9) involves compressing the graph horizontally by a factor of 4/3.

10.  The transformation from the graph of f to the graph of r in equation (10) involves shrinking the graph vertically by a factor of 1/2.

11.  The transformation from the graph of f to the graph of r in equation (11) involves shifting the graph vertically upward by 3 units.

In formula form: r(x) = f(2/5x)

This transformation causes the graph of r to become narrower compared to the graph of f, as it is compressed horizontally. The rate at which x-values change is increased, resulting in a steeper slope. The overall shape and direction of the graph remain the same, but it is narrower and more compact.

Therefore, the transformation from the graph of f to the graph of r in equation (6) involves compressing the graph horizontally by a factor of 5/2. This means that every x-coordinate in the graph of f is multiplied by 2/5 to obtain the corresponding x-coordinate in the graph of r. The vertical positioning of the graph remains unchanged.

In formula form: r(x) = 6f(x)

This transformation causes the graph of r to become taller compared to the graph of f, as it is stretched vertically. The rate at which y-values change is increased, resulting in a steeper slope. The overall shape and direction of the graph remain the same, but it is taller and more elongated.

Therefore, the transformation from the graph of f to the graph of r in equation (7) involves stretching the graph vertically by a factor of 6. This means that every y-coordinate in the graph of f is multiplied by 6 to obtain the corresponding y-coordinate in the graph of r. The horizontal positioning of the graph remains unchanged.

In formula form: g(x) = f(x - 3)

This transformation causes the entire graph of f to shift to the right by 3 units. Every point on the graph of f moves horizontally to the right, maintaining the same vertical position. The overall shape and slope of the graph remain the same, but it is shifted to the right.

Therefore, the transformation from the graph of f to the graph of r in equation (8) involves shifting the graph horizontally to the right by 3 units. This means that each x-coordinate in the graph of f is increased by 3 to obtain the corresponding x-coordinate in the graph of r. The vertical positioning of the graph remains unchanged.

In formula form: g(x) = f(4/3x)

This transformation causes the graph of r to become narrower compared to the graph of f, as it is compressed horizontally. The rate at which x-values change is increased, resulting in a steeper slope. The overall shape and direction of the graph remain the same, but it is narrower and more compact.

Therefore, the transformation from the graph of f to the graph of r in equation (9) involves compressing the graph horizontally by a factor of 4/3. This means that every x-coordinate in the graph of f is multiplied by 4/3 to obtain the corresponding x-coordinate in the graph of r. The vertical positioning of the graph remains unchanged.

In formula form: g(x) = 1/2 f(x)

This transformation causes the graph of r to become shorter compared to the graph of f, as it is vertically shrunk. The rate at which y-values change is decreased, resulting in a flatter slope. The overall shape and direction of the graph remain the same, but it is shorter and more compact.

The transformation from the graph of f to the graph of r in equation (10) involves shrinking the graph vertically by a factor of 1/2. This means that every y-coordinate in the graph of f is multiplied by 1/2 to obtain the corresponding y-coordinate in the graph of r. The horizontal positioning of the graph remains unchanged.

In formula form: g(x) = f(x) + 3

This transformation causes the entire graph of f to shift upward by 3 units. Every point on the graph of f moves vertically upward, maintaining the same horizontal position. The overall shape and slope of the graph remain the same, but it is shifted upward.

The transformation from the graph of f to the graph of r in equation (11) involves shifting the graph vertically upward by 3 units. This means that every y-coordinate in the graph of f is increased by 3 to obtain the corresponding y-coordinate in the graph of r. The horizontal positioning of the graph remains unchanged.

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Answer:

Center ( -8, 1 )

Radius ( 13 )

Let's solve the inequality to determine the number of outfits Tariq can purchase while staying within his budget.

Given:

Amount Tariq has to spend: $640

Cost of a new bicycle: $291.24

Cost of 4 bicycle reflectors: $19.56 each

Cost of bike gloves: $16.52

Cost of each biking outfit: $50.80

Let's assume the number of outfits Tariq can purchase is represented by x.

The total cost of the items he has already purchased is:

Cost of bicycle = $291.24

Cost of 4 bicycle reflectors = $19.56 * 4 = $78.24

Cost of bike gloves = $16.52

The remaining amount Tariq has to spend can be calculated as:

Remaining amount = Total amount - (Cost of bicycle + Cost of reflectors + Cost of gloves)

Remaining amount = $640 - ($291.24 + $78.24 + $16.52)

Now, we need to determine the maximum number of outfits Tariq can purchase with the remaining amount. Each outfit costs $50.80.

Inequality: x * $50.80 ≤ Remaining amount

Substituting the values:

x * $50.80 ≤ $640 - ($291.24 + $78.24 + $16.52)

Simplifying further:

x * $50.80 ≤ $640 - $385

x * $50.80 ≤ $255

To solve for x, we divide both sides of the inequality by $50.80:

x ≤ $255 / $50.80

x ≤ 5

Therefore, the maximum number of outfits Tariq can purchase while staying within his budget is 5.

The correct option is the second one, the order is:

g(x), f(x), h(x).

To find the rate of change for a function f(x) on an interval [a, b] we need to get:

R = (f(b) - f(a))/(b - a)

Here the interval is [-1, 3]

The first function is:

f(x)=  (x + 3)² - 2

Evaluating we get:

f(-1) = (-1 + 3)² - 2

f(-1) = 2² - 2 = 4 -2 = 2

and f(3) = (3 + 3)² - 2 = 34

Then the rate is:

R = (34 - 2)/(3 + 1) = 8

For g(x) we can use the graph, we have:

R = (0 + 2)/4 = 1/2

For the last function we need to use the table, then we will get:

R = (62 - 14)/(3 + 1) = 12

Then the order, from least to greatest is:

g(x), f(x), h(x).

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The amount of juice served this year is given as follows:

513 gallons.

The amount of juice served this year is obtained applying the proportions in the context of the problem.

The amount last year was given as follows:

540 gallons.

The percentage of this year's amount relative to last year's amount is given as follows:

95%, due to the decay of 5%, 100 - 5 = 95%.

Hence the amount of juice served this year is given as follows:

0.95 x 540 = 513 gallons.

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At a price of $3, the total revenue will be the greatest, and the company will sell 3 units at that price.

To find the total revenue at each price, we can multiply the price by the corresponding quantity.

Price        Quantity          Total Revenue

$6                0                      $0

$5                 1                       $5

$4                 2                       $8

$3                 3                        $9

$2                 4                         $8

$1                  5                          $5

To find the price at which total revenue is the greatest, we look for the highest value in the Total Revenue column.

In this case, the highest total revenue is $9, which occurs when the price is $3.

At a price of $3, the company will sell 3 units (as indicated in the Quantity column).

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The length of the cement post's statue is 6.25 feet.

We shall use Mathematical operators to compute the length of the cement post's statue.

(Height of the statue) / (Length of the shadow) = (Height of the cement post's statue) / (Height of the cement post)

Given:

Height of the statue = 25 feet

Length of the shadow = 16 feet

Height of the cement post = 4 feet

Let x =  length of the cement post's statue

25 feet / 16 feet = x / 4 feet

To find x, we cross-multiply:

25 * 4 = 16 * x

100 = 16 * x

To isolate x, we divide both sides of the equation by 16 feet:

100 / 16 = x

x ≈ 6.25 feet

Therefore, the length of the cement post's statue is 6.25 feet.

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The required reverse Euclidean algorithm is the solution to the modular equation (5x) mod 91 is

x = 6(mod 91).

Given that (5*x) mod 91 =32.

To solve the modular equation (5*x) mod 91 =32 using reverse Euclidean algorithm is to find the modular inverse of 5 modulo 91.

Consider  (5*x) mod 91 =32.

5x = 32(mod 91)

Apply the Euclidean algorithm to find GCD of 5 and 91 is

91 = 18 * 5 + 1.

Rewrite it in congruence form,

1 = 91 - 18 *5

On simplifying the equation,

1 = 91 (mod 5)

The modular inverse of 5 modulo 91 is 18.

Multiply equation by 18 on both sides,

90x = 576 (mod91)

To obtain the smallest positive  solution,

91:576 = 6 (mod 91)

Divide both sides by the coefficient of x:

x = 6 * 90^(-1).

Apply the Euclidean algorithm,

91 = 1*90 + 1.

Simplify the equation,

1 + 1 mod (90)

The modular inverse of 90 modulo 91 is 1.

Substitute the modular inverse in the given question gives,

x = 6*1(mod 91)

x= 6 (mod91)

Therefore, the solution to the modular equation (5x) mod 91 is

x = 6(mod 91).

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