A truck with a mass of 5000 kg and transfers 800,000 newtons(N) of force when it hits a wall. What was the acceleration of the truck?

a. 160 m/s
b. 160 km/hr
c. 160 m/s2
d. 160 miles/hr

Explanation:

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Answer:

Explanation:

The velocity can be found by using the formula

[tex]v = \sqrt{ \frac{2k}{m} } \\ [/tex]

k is the kinetic energy

m is the mass

From the question we have

[tex]v = \sqrt{ \frac{2 \times 4116}{4200} } \\ = 1.4[/tex]

We have the final answer as

Hope this helps you

Answer:

The speed of the lift is 1.4 m/s

Explanation:

Kinetic Energy

Is the type of energy of an object due to its motion. It's proportional to the square of the speed and the mass.

The equation for the kinetic energy is:

[tex]\displaystyle K=\frac{1}{2}mv^2[/tex]

Where:

m = mass of the object

v = speed at which the object moves

The kinetic energy is expressed in Joules (J)

It's given the mass of the lift as m=4,200 kg and its kinetic energy K=4,116 J. To calculate the speed (magnitude of velocity), we solve the formula for v as follows:

[tex]\displaystyle v=\sqrt{\frac{2k}{m}}[/tex]

[tex]\displaystyle v=\sqrt{\frac{2*4,116}{4,200}}[/tex]

[tex]\displaystyle v=\sqrt{1.96}[/tex]

v = 1.4 m/s

The speed of the lift is 1.4 m/s

Answer:

3rd law beacuse there a flies

Answer:

gases.

Explanation:

gases have the highest volume. if you compress (increase pressure) a gas, the volume decreases and it will take up less space as a liquid, and if you compress more, the liquid will become a solid.

additionally info: this is generally true, but as you get into more difficult subjects, this rule does not hold. for example, some substances cannot obtain a certain phase of matter when they are a certain temperature and or pressure. but that could be way more out of this questions league.

Answer:

1. where the skater turns and goes back in the opposite direction- point w

2. gravitational force of the object

3. point a

4. the bar representing sphere 4 should be twice as tall as the bar representing sphere 2

5. B; its mass is smaller (?)

yolo

Answer:

ABCDEFGHIJKLMNOPQRSTUVWXYZ

Explanation:

The given question is incomplete. The complete question is:

Estimate the volume of each ball. Use the formula [tex]v=\frac{4\pi\times r^3}{3}[/tex] where v is the volume and r is the radius. record the volume in table A of your student guide. The radius of the tennis ball is 2.1 cm and the radius of thr golf ball is 2.0 cm. What is the estimated volume of the table tennis ball in [tex]cm^3 [/tex] What is the estimated volume of the golf ball in

Answer: Volume of the tennis ball is [tex]38.8cm^3[/tex] and  Volume of the golf ball is [tex]33.5cm^3[/tex]

Explanation:

We have to find the Volume of tennis ball and golf ball by using the formula [tex]v=\frac{4\pi\times r^3}{3}[/tex]

Radius of the tennis ball = 2.1 cm

Radius  of the golf ball =2.0 cm.

Putting the value of radius in the formula , we get:

Volume of the tennis ball =  [tex]\frac{4\times 3.14\times (2.1cm)^3}{3} =38.8cm^3[/tex]

Volume of the golf ball =   [tex]\frac{4\times 3.14\times (2.0cm)^3}{3} =33.5cm^3[/tex]

Volume of the tennis ball is [tex]38.8cm^3[/tex] and  Volume of the golf ball is [tex]33.5cm^3[/tex]

it's  38.8 and 33.5 hope this helps

The correctly lists the three features shown in the photo is folds, strike-slip faults, and anticlines.

Modern folds are those that emerged recently (on the scale of geological periods), that is, in the Tertiary Period (between 65 million and 2.5 million years ago). Faults are geological structures that originate from vertical (top-down) or inclined internal forces.

The transcurrent fault – also called horizontal fault – occurs when there is displacement in the horizontal plane between the two blocks, being more common in zones where two tectonic plates meet, when these also move horizontally.

See more about transcurrent fault at brainly.com/question/2387953

#SPJ2

Answer: folds, strike-slip faults, and anticlines. (A)

Explanation: Got it right on my exam on Edge.

Answer:

A magnet has a field having lines of force around it that moves through the air which is a nonpermeable medium that allows the passage of magnetic field lines of force. The cardboard is a similar nonpermeable medium and the magnetic lines of force pass through to induce magnetism in the iron nail which is a ferromagnetic material that becomes magnetized by the magnetic field from the magnet

The induced magnetism in the iron nails causes the reverse poles to form in the iron with the iron domain's induced north pole pointing in the direction of the south pole of the magnet and vice versa

The iron nail is then attracted to the magnet as like poles attract, thereby holding the iron nail in place with the cardboard in between, without direct contact between the nail and the magnet as the cardboard prevents the magnet from touching the iron nail held in place

Explanation:

Answer:

[tex]\mathrm{(a)\:}32,000,000\:\mathrm{Ns},\\\mathrm{(b)\:}390,000\:\mathrm{N}[/tex]

Explanation:

The impulse-momentum theorem states the impulse on an object is equal to the change in momentum of that object. Momentum is given by [tex]p=mv[/tex]. Since mass is constant, the train's change in momentum is:

[tex]\Delta p=m\Delta v=750,000\cdot42=31,500,000=\fbox{$32,000,000\:\mathrm{Ns}$}[/tex](two significant figures).

Impulse is also given as [tex]\Delta p = F\Delta t[/tex], where [tex]F[/tex] is the average force applied and [tex]\Delta t[/tex] is change in time. Since [tex]t[/tex] is given as [tex]80\mathrm{s}[/tex], we have the following equation:

[tex]F\Delta t=\Delta p\\\\F=\frac{\Delta p}{\Delta t},\\\\F=\frac{31,500,000}{80},\\\\F=393,750=\fbox{$390,000\:\mathrm{N}$}[/tex](two significant figures).

Answer:

1.5m/s²

Explanation:

Given parameters:

Mass of the wheelbarrow = 50kg

Net force applied  = 75N

Unknown:

Acceleration of the barrow = ?

Solution:

From Newton's second law of motion, we know that:

       Force  = mass x acceleration

 Now insert the parameters and find the acceleration

       75  = 50 x acceleration

      Acceleration  = 1.5m/s²

Answer:

30,000kgm/s

Explanation:

Change in momentum is expressed as;

Change in momentum = mass × change in velocity

∆M = m∆v

Mass m = 1.5×10³kg = 1500kg

∆v = 30-10 =20m/s

Substitute into the formula

Change in momentum = 1500(20)

Change in momentum = 30,000kgm/s

Answer: B. Mechanical Waves

Explanation:

Answer:

the work function of the metal is 4.167 x 10⁻¹⁹ J .

Explanation:

Given;

wavelength of the incident light, λ = 450 nm = 450 x 10⁻⁹ m

kinetic energy, K.E = 2.5 x 10⁻²⁰ J

The energy of the incident light is calculated as;

[tex]E = hf = \frac{h c}{\lambda} \\\\where;\\\\c \ is \ speed \ of \ light = 3 \times 10^8 \ m/s\\\\ h \ is \ Planck's constant = 6.626 \times 10^{-34} Js \\\\E = \frac{(6.626 \times 10^{-34})(3\times 10^8)}{450 \times 10^{-9}} \\\\E = 4.417 \times 10^{-19} \ J[/tex]

Apply Einstein photoelectric equation to determine the work function of the metal;

E = W + K.E

where;

W is the work function of the metal

W = E - K.E

W = 4.417 x 10⁻¹⁹ J - 2.5 x 10⁻²⁰ J

W = 44.17 x 10⁻²⁰ J -  2.5 x 10⁻²⁰ J

W = 41.67 x 10⁻²⁰ J

W = 4.167 x 10⁻¹⁹ J

Therefore, the work function of the metal is 4.167 x 10⁻¹⁹ J .

The work function of the photon is 4.167*10^19J

The energy of this photon can be calculated as

E = hc/λ

Data given;

substituting the values into the equation;

[tex]E = hc / y\\E = \frac{6.626*10^-^3^4*3.0*10^8}{450*10^-^9} \\E = 4.42*10^-^1^9J[/tex]

The work function of the photon can be calculated as;

E = K.E + Ф

4.42*10^-19 = 2.5*10^-20 + Ф

Ф = [tex]4.42*10^-^1^9 - 2.5*10^-^2^0=4.167*10^-^1^9J[/tex]

The work function of the photon is 4.167*10^-19 J

Learn more on work function  of a photon here;

https://brainly.com/question/11683155

Answer:

The last option.

Explanation:

Since you are going down, the gravitational potential energy would go down too. Thus, the gravitational potential energy decreases.

Since the gravitational potential energy is converted to kinetic energy when you move down, there is an increase in kinetic energy.

Answer:

The fourth option

Explanation:

Answer:

2.71 m/s

Explanation:

Apply the formula for cosine of an angle where;

The hypotenuse is the speed the hawk dives towards the ground : 3.31 m/s

The angle of direction of motion from the horizontal is : 35°

Speed of the shadow along the ground will be, A ;

Cosine 35° = A / 3.31

A= 3.31 cosine 35°

A= 2.71 m/s

Answer:

option 2

Explanation:

you are very welcom

Answer:

The semi truck travels at an initial speed of 69.545 meters per second downwards.

Explanation:

In this exercise we see a case of an entirely inellastic collision between the semi truck and the car, which can be described by the following equation derived from Principle of Linear Momentum Conservation: (We assume that velocity oriented northwards is positive)

[tex]m_{S}\cdot v_{S}+m_{C}\cdot v_{C} = (m_{S}+m_{C})\cdot v[/tex] (1)

Where:

[tex]m_{S}[/tex], [tex]m_{C}[/tex] - Masses of the semi truck and the car, measured in kilograms.

[tex]v_{S}[/tex], [tex]v_{C}[/tex] - Initial velocities of the semi truck and the car, measured in meters per second.

[tex]v[/tex] - Final speed of the system after collision, measured in meters per second.

If we know that [tex]m_{S} = 2200\,kg[/tex], [tex]m_{C} = 2000\,kg[/tex], [tex]v_{C} = 45\,\frac{m}{s}[/tex] and [tex]v = -15\,\frac{m}{s}[/tex], then the initial velocity of the semi truck is:

[tex]m_{S}\cdot v_{S} = (m_{S}+m_{C})\cdot v -m_{C}\cdot v_{C}[/tex]

[tex]v_{S} = \frac{(m_{S}+m_{C})\cdot v - m_{C}\cdot v_{C}}{m_{S}}[/tex]

[tex]v_{S} = \left(1+\frac{m_{C}}{m_{S}} \right)\cdot v - \frac{m_{C}}{m_{S}} \cdot v_{C}[/tex]

[tex]v_{S} = v +\frac{m_{C}}{m_{S}}\cdot (v-v_{C})[/tex]

[tex]v_{S} = -15\,\frac{m}{s}+\left(\frac{2000\,kg}{2200\,kg} \right) \cdot \left(-15\,\frac{m}{s}-45\,\frac{m}{s} \right)[/tex]

[tex]v_{S} = -69.545\,\frac{m}{s}[/tex]  

The semi truck travels at an initial speed of 69.545 meters per second downwards.

Answer:

a) 1.55 m/s

b) 2.3 m/s

Explanation:

We know that the boat travels across the river, if we define the river as the x-axis, then the velocity of the boat is only on the y-axis.

Then we can write the velocity of the boat in still water as:

S = (0, B)

Now, when the boat is on the river, the velocity of the boat will be equal to the velocity of the boat in still water plus the velocity of the river.

The velocity of the river is:

v = (R, 0).

Then the velocity of the boat in that river is:

V' = (0, B) + (R, 0) = (R, B)

Now, we know that the velocity of the boat is 10km/h, and it travels at an angle of 34° with respect to the shore.

We can use the Pythagoreans theorem to write the components of this velocity as:

x-axis component = 10km/h*cos(34°) = 8.29 km/h

y-axis component = 10km/h*sin(34°) =  5.59 km/h

Then the velocity of the boat can be written in components as:

velocity = ( 8.29 km/h,  5.59 km/h)

And we knew that the velocity of the boat was written as  (R, B)

Then we must have:

R = 8.29 km/h

B = 5.59 km/h

a) The speed of the boat in m/s:

We know that the speed of the boat is 5.59 km/h.

First, we know that:

1km = 1000m, then:

5.59 km/h = 5.59*(1000m)h = 5,590 m/h

And we know that:

1h = 3600s

Then we can write:

5,590 m/h = 5,590 m/(3600s) = 1.55 m/s

b) The speed of the river in m/s:

We know that the speed of the river is 8.29 km/h

Using the same reasoning as above, we can do the change of units as follows:

8.29 km/h = 8.29 (1000m)/(3600s) = 2.3 m/s

Answer:

T try d add b CD c

Explanation:

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Answer:

They have the highest melting point so that mean that the temperature and the are a conductive to electricity.

Explanation:

Answer:

its digital technology

Answer:

The energy that will go will for thermal store of the surroundings is 20 J.

Explanation:

Given;

kinetic of the thrown ball, K.E₁ = 50 J

kinetic energy used to move the target, K.E₂ = 30 J

The excess energy that will go will for thermal store of the surroundings;

ΔK.E = K.E₁ - K.E₂

ΔK.E = 50J - 30J

ΔK.E = 20 J

Therefore, the energy that will go will for thermal store of the surroundings is 20 J.

Answer:

1m/s²

Explanation:

Given parameters:

Initial velocity  = 2m/s

Final velocity  = 4m/s

Time of chase  = 2s

Unknown:

Acceleration = ?

Solution:

Acceleration is the rate of change of velocity with time;

 A = [tex]\frac{v - u }{t}[/tex]  

A is the acceleration

v is the final velocity

u is the initial velocity

t is the time taken

      A  = [tex]\frac{4 - 2}{2}[/tex]   = 1m/s²

The question is incomplete. The compete question is :

Margaret Mary, Doug , and Kako are at a local amusement park. They see an attraction called the Giant Slide, which is simply a very long and high inclined plane. Visitors at the amusement park climb a long flight of stairs to the top of the 27inclined plane and are given canvas sacks. They sit on the sacks and slide down the plane 70m long. At the time when the three friends walked past the slide, a 135-kg man and a 20-kg boy are each at the top preparing to slide down. "I wonder how much less time it will take the man to slide down than it will take the boy," said Margaret Mary. "I think the boy will take less time," said Doug. "You're both wrong,"said Kako. "They will reach the bottom at the same time."

If the man and the boy do not take the same amount of time to reach the bottom of the slide, calculate how many seconds of difference there will between the two times.

Solution :

From body sliding down an incline plane, the acceleration is given by, [tex]$a = g \sin \theta$[/tex]

Since the body slides from rest, the initial velocity is, u = 0

Now the equation of motion, we have

        v= u + at

or     v = 0 +at

or      v = at

or     [tex]$t=\frac{v}{a}$[/tex] ............(1)

again we have, [tex]$v^2 -u^2 =2as $[/tex]

                         or [tex]$v = \sqrt{2s g \sin \theta} $[/tex]

Then from equation (1), we have

[tex]$t=\frac{\sqrt{2sg \sin \theta}}{g \sin \theta}$[/tex]

Thus this means that the time of sliding down an inclined plane does not depend on the mass of the body that slides.

Therefore, Kako is correct.

Since the time taken to slide an inclined plane is same for both the man and the boy, there is no difference between their time of sliding.

Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 2000 × 3

We have the final answer as

Hope this helps you

Answer:

12 m

Explanation:

From the question given above, the following data were obtained:

Mass (m) of bag = 25 kg

Potential energy (PE) = 2940 J

Height (h) =?

Objects carried to a particular height will always experience an acceleration due to gravity of 9.8 m/s².

With the above in mind, we can obtain the height to which the load is lifted to as shown below:

Mass (m) of bag = 25 kg

Potential energy (PE) = 2940 J

Acceleration due to gravity (g) = 9.8 m/s².

Height (h) =?

PE = mgh

2940 = 25 × 9.8 × h

2940 = 245 × h

Divide both side by 245

h = 2940 / 245

h = 12 m

Therefore, the worker lifts the load to a height of 12 m.

Answer:

[tex]P=203.3819375kg.m/s\\P\approx203.4kg.m/s[/tex]

[tex]\theta=6.4541\textdegree North East\\\theta\approx6.5\textdegree North East[/tex]

Explanation:

From the question we are told that

Mass of first jogger [tex]M=69kg[/tex]

Speed[tex]v_1=1.6m/s[/tex]

Direction [tex]d= East[/tex]

Mass of 2nd jogger [tex]M=63kg[/tex]

Speed [tex]v_2=1.5m/s[/tex]

Direction [tex]d= 14\textdegree north[/tex]

Generally equation for momentum along the the horizontal is mathematically given as

[tex]P_x=m_1v_1 +m_2v_2cos\theta[/tex]

[tex]P_x=(69)*(1.6) +(63)*(1.5)cos14[/tex]

[tex]P_x=202.0929461kg.m/s[/tex]

Generally equation for momentum along the the vertical is mathematically given as

[tex]P_y=m_2v_2cos\theta[/tex]

[tex]P_x=22.86161913kgm/s[/tex]

a)Generally the magnitude of momentum is mathematically given by

[tex]P=\sqrt{(P_x)^2+(P_y)^2}[/tex]

[tex]P=\sqrt{(202.0929461)^2+(22.86161913)^2}[/tex]

[tex]P=\sqrt{41364.21249}[/tex]

[tex]P=203.3819375kg.m/s[/tex]

[tex]P\approx203.4kg.m/s[/tex]

b) Generally the angle [tex]\theta[/tex] is mathematically given by

[tex]\theta=tan^-^1\frac{py}{px} \\[/tex]

[tex]\theta=tan^-^1\frac{22.86161913}{202.0929461}[/tex]

[tex]\theta=tan^-^1(0.1131242805)[/tex]

[tex]\theta=6.4541\textdegree North East[/tex]

Answer: B

"Ball 1 at 0.21 m/s left, Ball 2 at 0.22 m/s left"