Answer:
W = F * S one does not know the work performed because one does not know what force produced the resulting work. Neither can one calculate the power required because P = W / t (work / time)
One only knows the distance and the time but not the force required.
What do we mean by the diffraction limit of a telescope?.
Answer:
Diffraction Limit. The angular resolution that a telescope could achieve if it were limited only by the interference of light waves; it is smaller (i.e., better angular resolution) for larger telescopes.
Explanation:
Searched it up
The downward motion of an elevator is controlled by a cable that unwinds from a cylinder of radius 0.20 m. what is he angular velocity of the cylinder when the downward speed of the elevator is 1.2 m/s
The angular velcoity of this cylinder when the downward speed of the elevator is 1.2 m/s would be 6 rad/s.
Given the following data:
Radius of cylinder = 0.20 meter.
Linear velocity = 1.2 m/s.
What is angular velocity?Angular velocity can be defined as the rate of change of angular displacement of an object with respect to time. Thus, it is a measure of how fast and quickly an object revolves or rotates relative to another point or how its angular position changes with respect to time.
The formula for angular velcoity.Mathematically, angular velcoity is given by this formula:
[tex]V =r\omega\\\\\omega =\frac{V}{r}[/tex]
Substituting the given parameters into the formula, we have;
[tex]\omega = \frac{1.2}{0.2}[/tex]
Angular velocity = 6 rad/s.
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Sally and Suzy are moving into their first college dorm together. They are loading all their furniture onto a truck with a ramp that is 8 feet long.
How far is the back of the truck off the ground if the mecanical advantage of this ramp is 2?
A) .25 ft
B) 4 ft
C) 8 ft
D) 16 ft
Answer:
B
Explanation:
Formula
Mechanical advantage = length of the ramp / height
Givens
Length of the ramp = 8
Mechanical advantage = 2
height = ?
Solution
2 = 8feet / height Multiply both sides by height
2* height = 8 feet * height / height Combine
2* height = 8 feet Divide by 2
2*height/2 = 8 feet/2
height = 4 feet.
A sound travels down a hallway that is 115 m long. Then it echoes and
returns back to the source. If the speed of sound is 350 m/s, how long
does it take in seconds) to hear the echo?
Answer:
0.66 s
Explanation:
∆x = v∆t → 2 × 115 = 350 ∆t → ∆t = 230/350 = 0.66 s
What will an atom do if it has 1 to 3 valence electrons?
move electrons to a lower shell
move electrons to a higher shell
accepts (gains) electrons
donates (loses) electrons
Answer:
donates (loses) electrons
Explanation:
Atoms are most stable when they have zero valence electrons (full octets) and have the same electron configuration as the Noble Gases.
Atoms that have 1-3 valence electrons are most likely to donate them to reach this stable configuration.
An example is Sodium (Na) has 1 valence electron, as it is group one of the periodic table, and it often forms as a positive cation (Na+1) by donating its valence electron.
While electric current is flowing through a wire, what surrounds the wire?.
A material that doesn't conduct electricity well - such as a plastic/rubber covering, acting as the electrical insulator.
Hope this helps!
An ideal single movable pulley requires an input force that is one-half the ouput force.
True False
When 20. joules of work are done in 4.0 seconds; what is the power developed?
A. 0.20 watt
B. 5.0 watts
C. 16 watts
D. 80. watts
the power developed when, 20 joules of work are done in 4.0 second.
solution:power= workdone/ time
here workdone= 20 joules
time taken= 4.0s
so putting these values in the above formula, we get:
power= 20/4.0
=5.0 watts
answer= option b) 5.0 watts
[tex]\bold\blue{Formula : }[/tex]
[tex]\bold{Power = \frac{energy}{time} }[/tex]
[tex]\bold\blue{Given : }[/tex]
Joules of work = 20 work are done = 4.0 seconds[tex]\bold\blue{ Solution : }[/tex]
[tex]\bold{Power = \frac{energy}{time} }[/tex]
[tex]\bold{Power = \frac{20}{4.0} }[/tex]
[tex] \bold{ Power = 5.0}[/tex]
So , B.) 5.0 watts is answer .
Which term is used to describe the highest point on a transverse wave?
A. frequency
B. crest
C. trough
D. amplitude
Answer:
B. Crest
Explanation:
The high point of a transverse wave is a called the crest.
While on the surface of the earth a student has a weight of 450n if she is moved twice as far from the center of the earth then how does the new weight compare to her old?
Based on the fact that the student is moved twice as far from the center of the earth, her new weight will be 112.5 N.
What is her new weight?When the student was moved by the same distance from the center of the earth, her weight was halved.
When she was then moved twice as far, her weight was halved again.
This means that her new weight is:
= 450 x 1/2 x 1/2
= 450 x 1/4
= 112.5 N.
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16. Pressure of a fluid depends upon:
a) Height of the object
b) Depth at which object moves
c) density of the medium
d) all of above
Answer:
b that is density at object moves
Which of these invertebrates have asymmetric bodies?
Answer:
Sponges
Explanation:
It would be either sponges or flatworms.
I apologize if it is incorrect-
I hope it helps! Have a great day!
Anygays-
The graph represents the relationship between the work done by a student running up a flight of stairs and the time of ascent.
I think the answer is B, I think im wrong.
Answer:
power
Explanation:
The slope would be y/x or work / time which is the definition of power
How are temperature and molecular motion related?
Answer:
temperature is essentially the speed of the molecules.
Explanation:
temperature is the kinetic energy of molecules, and kinetic energy is dependent on velocity.
As an ambulance siren passes and moves away from you, the sound waves'
frequency __________
and their amplitude ________
A. increases,
decreases
B. increases,
increases
C. decreases,
increases
D. decreases,
decreases
[tex]\qquad\qquad\huge\underline{{\sf Answer}}♨[/tex]
Amplitude and frequency are two properties of sound waves that decreases as distance from source decrease.
Therefore, as the ambulance moves away,
frequency - decreasesamplitude - decreasesSo, correct choice is D
What is the volume of one rubber ball? round to the nearest hundredth of a centimeter. cm3 if the price of the rubber needed to produce a ball is $0.0045/cm3, what is the cost of producing one ball? round to the nearest cent. $ if the company sells a ball for $0.50, how much profit will it make on each ball? $
The volume of one rubber ball and the cost of producing one ball and the profit will it make on each ball will be 20.58 cm³, $0.09261, and $0.40739 respectively.
What exactly is geometry?It is concerned with the geometry, region, and density of various 2D and 3D shapes.
The given data in the problem is;
r is the Rubber balls = 1.7 cm
V is the volume
C is the cost of production
P is the profit
The volume of the rubber ball is found as;
[tex]\rm v= \frac{4}{3} \pi r^3 \\\\ \rm v= \frac{4}{3} \times 3.14 (4.913)^3 \\\\ \rm v= 20.58 cm^3[/tex]
If the price of the rubber required to make a ball is $0.0045/cm3, the ball's production cost will be $0.0045/cm3.
The cost of a ball is the multiplication of the cost of one ball and the selling price of the ball;
C = 0.0045 x 20.58
C = $0.09261
P is the profit gained and profit is the subtraction of the selling price and cost price.
P = S.P.-C.P.
P=0.5 - 0.09261
P = $0.40739
Hence the volume of one rubber ball and the cost of producing one ball and the profit will it make on each ball will be 20.58 cm³, $0.09261, and $0.40739 respectively.
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Answer:
1: C
2: C
3: A
Explanation: just did it
What was the first car fitted with an alternator, rather than a direct current dynamo?.
Answer:
The first vehicles fitted with an alternator was vehicles during WWll.
Chrysler Corporation fitted an alternator on the Valiant 1960 as standard equipment
Explanation:
Answer:
The first car fitted with an alternator, rather than a direct current dynamo was the 1960 Plymouth Valiant.
in a railyard a train is being put together from freight cars.An empty freight car coasting 10 m/s strikes a loaded car that is stationary and the cars couple together. Each of the cars Haas a mass of 3000kg when empty and the loaded car contains 12000kg of canned soda . with what speed does the combination of the two cars start to move?
Answer:m1v1 + m2v2 = (m1f + m2f)vf. 3000kg(10.0m/s) + (15000kg)(0.0m/s) = (18000kg)(vf).
Explanation:
where are metamorphic rocks formed? And how are they formed
6th Grade Earth science
Answer:
Metamorphic rocks form when rocks are subjected to high heat, high pressure, hot mineral-rich fluids or, more commonly, some combination of these factors. Conditions like these are found deep within the Earth or where tectonic plates meet.
Question 2 (1 point)
This graph shows an object in free fall. Assume there is no air resistance. What is the only force acting on this object?
Answer:
Actually, there is no force (felt by the object) acting on the object.
It is similar to an object in orbit around the earth (weightlessness)
F = M a describes the motion of the particle where
M a = M g where the acceleration of the particle is equal to the force of gravity acting on the particle
From an external view the only force acting on the particle is M g and it produces an acceleration of M g
There is no force felt by the freely falling body. The cause of free fall is gravitational pull. Where Acceleration is equal to the gravitational acceleration. According to Newton's Law of Gravitation , two bodies attract each other due to their masses and separation , since earth is a very big body therefore the lit body falls towards the earth . Thus the graph plotted is a straight line.
What is Newton's law of Gravitation?
"The force acting between two bodies is directly proportional to product of masses and inversely proportional to the square of the separation ."
F= G.{m_{1} . m_{2} }/r^{2}.
Hence the only force by which the object is falling is gravitational pull.
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Explore the Sun-Earth-Moon option in the Model Simulation (second option). Explain the conditions necessary for an astronomical apocalypse.
The conditions necessary for an astronomical apocalypse are the shifting of earth from its orbit and collision of big star with earth.
Conditions necessary for happening of an astronomical apocalypseThe apocalypse event occurs due to climatic, nuclear war, plague or virus, zombie apocalypse or alien invasion but astronomical apocalypse occurs due to the shifting of earth from its orbit and collision of big star with earth.
So we can conclude that the conditions necessary for an astronomical apocalypse are the shifting of earth from its orbit and collision of big star with earth.
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A particle moves in the xy plane in a circle centered on the origin. at a certain instant the velocity and acceleration of the particle are 6. 0 m/s and (3. 0 + 4. 0) m/s2. what are the x and y coordinates of the particle at this moment?
The x and y coordinates of the particle at this moment is (6x + 4.5y) m.
Position of the particleThe position of the particle at any instant is determined from the velocity and acceleration of the particle as shown below.
v² = u² + 2as
where;
v is the final velocity of the particleu is the initial velocitya is the acceleration of the particles is the position of the particlev² = 0 + 2as
v² = 2as
s = v²/2a
X and y - coordinates of the particle[tex]s_x = \frac{v^2}{2a_x} = \frac{6^2}{2(3)} = 6\ m\\\\s_y = \frac{v^2}{2a_y} = \frac{6^2}{2(4)} = 4.5 \ m\\\\s = (6 x \ + 4.5y)m[/tex]
Thus, the x and y coordinates of the particle at this moment is (6x + 4.5y) m.
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Applying definitions Samantha ran 90 meters in 35 seconds to catch up with her dog. When she got to him, she played with him for 70 seconds before they walked back in 75 seconds. Did Saman tha travel at constant speed? What was Samantha's average speed?
No, Saman didn't travel at constant speed
v₁ = 90/35 = 2.57 m/s
v₂ = 0
v₃ = 90/75 = 1.2 m/s
Average speed = total distance/time
Average speed = (90+90)/(35+70+75) = 1 m/s
How much heat does it take to melt a 0.234 kg ice cube at its melting point?
Answer:
Q = M kg* 3.33E5 J / kg = .234 * 3.33E5 = 7.79E4 Joules
As a check (using 80 cal/gm as latent heat of fusion for water)
234 g * 80 cal/gm = 18720 cal
1 cal = 4.19 J
18720 cal * 4.19 J / cal = 7.7E4 J agrees with value found above
Cause and Effect Reasoning Quick Check
1. Cells can repair small amounts of damage. In what situation-
[Answer: A person is exposed to large amounts of gamma rays.]
2. If a certain amount of time in the sun is dangerous for adults, what could-
[Answer: The adult and child would get the same damage per]
3. An individual must receive quite a lot of sun exposure over time to develop a high risk of cell damage. [Answer: A shorter exposure time to X-rays gives the same risk]
4. Ultraviolet light can damage a cell. Which exposure would most likely-
[Answer: 5 minutes of exposure to UVB light]
5. New vaccine studies are sometimes tested on pigs.
[Answer: Humans have an immune system very similar to pigs.]
The principle of cause and effect is applied in every life as is seen in damage caused to cells by exposure to large amounts of ultravoilet rays.
What is cause and effect?Cause and effect refers to the principle in which for every effect received or observed, an underlying cause is present.
Based on cause and effect;
Cells can repair small amounts of damage caused when a person is exposed to large amounts of gamma rays.
If a certain amount of exposure time in the sun is dangerous for adults, would result in a similar damage to a child.
A lot of sun exposure over time will cause an individual to develop a high risk of cell damage just as a shorter exposure time to X-rays gives the same risk.
Ultraviolet light can damage a cell especially with over 5 minutes of exposure to UVB light.
New vaccine studies are sometimes tested on pigs because humans have an immune system very similar to pigs.
Therefore, cause and effect is applied in every activities.
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If our planet was twice as far away how would the Earth’s orbit change?
Answer:
One of the indirect proofs that orbits change is actually in the growth of our own teeth when we were children. our teeth are some of the most basic, and primitive
parts of our bodies. They grow on a 9 day cycle, which was an ancient full moon to full moon cycle when the Earth and the Moon were a lot smaller, and closer together, and the co-orbital period was only 9 days, not the 29.5 days that it is currently.
So Given any two " Planets " that co-orbit a common gravitational center, the larger planet will grow larger far faster than the smaller planet, and the larger planet will accelerate the smaller planet to a higher orbit with a longer period, and decelerate itself to a lower orbit with a longer period, and the absolute value of the center to center distance will increase, and the orbital period will increase. The two orbs and their common gravitational center will remain co-linear through out the gradual growing and changing process.
This is an important process for the enlargement of the solar system as time passes, and an important process for larger galaxies as they attract and merge with smaller galaxies.
All of the planets grow larger at an accelerating rate, and thus systems spiral outward concentrating mass into larger and fewer galaxies, solar systems, and planet - moon systems.
Tomas lives in Brazil. When he looks up to the night sky, he always sees the same side of the Moon. Why does this happen?
A
The Moon orbits the Earth in the same length of time that it takes to make one revolution on its axis.
B
The Moon is stationary on its axis as it orbits the Earth.
C
The Moon orbits the Earth in the same length of time that it takes for the Earth to orbit the Sun.
D
The Moon is stationary in the sky in relation to Earth.
Answer: The answer is C. Hope it helps!!, and if you get it wrong it's my fault
(HELP ASAP! WILL MARK BRAINLIEST) How would you paraphrase: A powerful practical and spiritual relationship between the people and their environment was forged by their dependence upon its resources.
Answer:
The people's reliance on the environment's resources generated a deep practical and spiritual link between them and it.
Explanation:
You catch a 219 g ball moving at 6.1 m/s. If you catch the ball in a time period of
0.138 s what is the magnitude of the average force you must supply to the ball to
stop the ball?
Answer in units of Newtons (N)
Answer:
The magnitude of the average force to supply to the ball in order to stop the ball is 9.68 N.
Explanation:
Let's think Newton's 2nd Law: F = ma.
We are given the mass of the ball: 219 g ⇒ .219 kg.
We are given the initial velocity, time, and final velocity of the ball ∴ we can solve for acceleration.
We are trying to find the force needed to stop the ball.
Let's find the acceleration of the ball first.
We have the initial velocity of the ball, 6.1 m/s.We have the time it would hypothetically take the ball to stop, .138 s.We have the final velocity of the ball, 0 m/s (since we are trying to stop the ball).Now, we can plug these known values into this kinematic equation and solve for acceleration, a.
v = v₀ + at 0 = 6.1 + a(.138) -6.1 = .138a a = 44.2029 m/s²Substitute acceleration and mass into F = ma and solve for the force.
F = (.219)(44.2029) F = 9.68 NThe magnitude of the average force to supply to the ball in order to stop the ball is 9.68 N.
A spaceship moves at a constant velocity of 0.400c relative to an Earth observer. The pilot of the spaceship is holding a rod, which he measures to be 1.00 m long. The rod is held perpendicular to the direction of motion of the spaceship. How long is the rod according to the Earth observer
Since the rod is held perpendicular to the direction of motion of the spaceship, the rod is 1.00 m long to an Earth observer.
To answer the question, we use the principle of length contraction in relativity.
What is Length contraction?The principle of length contraction states that the length of an object would only contraction when it is in the direction of motion.
So, since the 1.00 m long rod is in the spaceship is held perpendicular to the direction of motion of the spaceship, there is no length contraction and thus, an observer on the Earth measures the same length of 1.00 m.
So, Since the rod is held perpendicular to the direction of motion of the spaceship, the rod is 1.00 m long to an Earth observer.
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