The marginal error is 0.0240
The 95% confidence interval for the proportion of all student athletes in this country have been subjected to some form of hazing is (0.576, 0.624).
Given,
The percentage of students surveyed = 60%
Number of athletes = 1600
Confidence interval = 95%
We have to find the marginal error and 95% confidence interval of the study;
The following results are obtained from a sample of n people that were surveyed, with a probability of success of π and a level of confidence of 1 - ∝
π ± z [tex]\sqrt{\frac{\pi (1-\pi )}{n} }[/tex]
Where,
z is the z score with a p value of 1 - ∝/2
Here we have,
n = 1600 and π = 0.6
95% confidence level
So ∝ = 0.05 , z is the value of Z that has a pvalue of 1 - 0.05/2 , so Z = 1.96.
Then, the margin of error is;
M = [tex]z\sqrt{\frac{\pi (1-\pi )}{n} }[/tex]
M = [tex]1.96\sqrt{\frac{0.6.0.4}{1600} }[/tex]
M = 0.0240
M = 2.40 percentage points.
Lower limit of the interval;
π - M = 0.6 - 0.0240 = 0.576
Upper limit of the interval;
π + M = 0.6 + 0.0240 = 0.624
The 95% confidence interval for the proportion of all student athletes in this country have been subjected to some form of hazing is (0.576, 0.624).
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Given points C(-3,-8) and D(-6.5,-4.5), find the coordinate of the point that is 2/3 of the way from C to D.
Answer:
(-16/3,-17/3)
Explanation:
Let the point which is 2/3 of the way from C to D = X
It means that point X divides the line segment CD internally in the ratio 2:1.
To determine the coordinate of point X, we use the section formula for internal division of a line segment:
[tex](x,y)=\left\{ \frac{mx_2+nx_1}{m+n},\frac{my_2+ny_1}{m+n}\right\} [/tex][tex]\begin{gathered} (x_{1,}y_1)=(-3,-8) \\ (x_2,y_2)=(-6.5,-4.5) \\ m\colon n=2\colon1 \end{gathered}[/tex]Substituting these values into the formula above, we have:
[tex]X(x,y)=\left\{ \frac{2(-6.5)+1(-3)}{2+1},\frac{2(-4.5)+1(-8)}{2+1}\right\} [/tex]We then simplify:
[tex]\begin{gathered} X(x,y)=\left\{ \frac{-13-3}{3},\frac{-9-8}{3}\right\} \\ =\left\{ \frac{-16}{3},\frac{-17}{3}\right\} \end{gathered}[/tex]Therefore, the exact coordinate of the point that is 2/3 of the way from C to D is (-16/3,-17/3).
find the value of X and y if l || m.
The Solution.
Step 1:
We shall find two equations from the given angles.
First, by vertically opposite angle property of angles between two lines, we have that:
[tex]\begin{gathered} 7y-23=23x-16 \\ \text{Collecting the like terms , we get} \\ 7y-23x=23-16 \\ 7y-23x=7\ldots.eqn(1) \end{gathered}[/tex]Similarly, by alternate property of angles between lines, we have that:
[tex]\begin{gathered} 23x-16+8x-21=180 \\ \text{Collecting like terms, we get} \\ 31x-37=180 \\ 31x=180+37 \\ 31x=217 \\ \text{Dividing both sides by 31, we get} \\ x=\frac{217}{31}=7 \end{gathered}[/tex]Step 2:
We shall find the values of y by substituting 7 for x in eqn(1), we get
[tex]\begin{gathered} 7y-23(7)=7 \\ 7y-161=7 \\ 7y=7+161 \\ 7y=168 \\ \text{Collecting the like terms, we get} \\ y=\frac{168}{7}=24 \end{gathered}[/tex]Step 3:
Presentation of the Answer.
The correct answers are; x = 7 , and y = 24
A company estimates that that sales will grow continuously at a rate given by the functions S’(t)=15e^t where S’(t) Is the rate at which cells are increasing, in dollars per day, on day t. find the sales from the 2nd day through the 6th day (this is the integral from one to six)
Given the function:
[tex]S^{\prime}(t)=15e^t[/tex]Where S’(t) Is the rate at which sales are increasing (in dollars per day). To find the sales from the second day through the 6th day, we need to integrate this function from t = 1 to t = 6:
[tex]\int_1^6S^{\prime}(t)dt=\int_1^615e^tdt=15\int_1^6e^tdt[/tex]We know that:
[tex]\int e^tdt=e^t+C[/tex]Then:
[tex]15\int_1^6e^tdt=15(e^6-e^1)\approx\text{\$}6010.66[/tex]The sales from the 2nd day through the 6th day are $6,010.66
pls help me i’ll give ty brainlist
[tex]\sqrt{25*7x^{4}*x^{1} } \\=\sqrt{25*x^{4}*7 *x^{1} } \\=\sqrt{25x^{4} } *\sqrt{7x}\\=5x^{2} \sqrt{7x}[/tex]
Option B is the answer.
Answer: C
i hope you can see my handwriting
What’s the answer?? Just a part of a homework practice
The functions are
[tex]h(x)=0.42x^2+0.3x+4\text{ and }r(x)=-0.005x^2-0.2x+7[/tex]Multiply both functions s follows.
[tex]h(x)\times r(x)=(0.42x^2+0.3x+4)\times(-0.005x^2-0.2x+7)[/tex][tex]=0.42x^2\times(-0.005x^2-0.2x+7)+0.3x\times(-0.005x^2-0.2x+7)+4\times(-0.005x^2-0.2x+7)[/tex][tex]=0.42x^2\times(-0.005x^2)+0.42x^2\times(-0.2x)+0.42x^2\times7+0.3x\times(-0.005x^2)+0.3x\times(-0.2x)+0.3x\times7+4\times(-0.005x^2)+4\times(-0.2x)+4\times7)[/tex][tex]=-0.0021x^4-0.084x^3+2.94x^2-0.0015x^3-0.06x^2+2.1x-0.02x^2-0.8x+28[/tex][tex]=-0.0021x^4-0.084x^3-0.0015x^3+2.94x^2-0.06x^2-0.02x^2+2.1x-0.8x+28[/tex][tex]=-0.0021x^4-0.0855x^3+2.86x^2+1.3x+28[/tex]Hence the required product is
[tex]q(x)=-0.0021x^4-0.0855x^3+2.86x^2+1.3x+28[/tex]Hence the first option is correct.
solve the inequality for h. h-8> 4h+5. write the answer in simplest form
Subtract '4h' from both RHS (Right-Hand side) and LHS of the inequality (Left-Hand side).
[tex]\begin{gathered} h-8-4h>4h+5-4h \\ (h-4h)-8>5+(4h-4h) \\ -3h>5 \end{gathered}[/tex]Add '8' on both LHS and RHS of the above expression.
[tex]undefined[/tex]Divide both RHS and LHS of the above expression with '-3'. Whenever an inequality is divide or multiple with a negative value, the sign of the inequality shifts. Here, the above expression is dividing with '-3'. Thus, the > symbol shifts to < symbol.
[tex]\begin{gathered} \frac{-3h}{-3}<\frac{5}{-3} \\ h<\frac{-5}{3} \end{gathered}[/tex]Thus, the iniequality for h is h<-(5/3).
An Integer is a number with a fractional part. True or False
An integer is a number with a fractional part is true statement.
A class has 21 children, 10 are girls and 11 are boys. what fraction of the class is made up of boys?
A class has 21 children, 10 are girls and 11 are boys. what fraction of the class is made up of boys?
Let
x -----> number of boys
y -----> total number of children
we have that
x=11 -----> given
y=21 ----> given
therefore
The fraction of the class that is made up of boys is equal to
x/y
substitute
11/21What is the sum of -15 + 182A. 33B. 3c. -3 D-33Your answer
-15 + 18 is the same as 18 - 15, which is equal to 3.
What is the product of 125 × 25
Answer:
Step-by-step explanation:
125 X 25
= 3,125
Use function composition to verify f(x)=-3x+5 and g(x)=5x-3 are inverses. Type your simplified answers in descending powers of x an do not include any spaces between your characters.Type your answer for this composition without simplifying. Use parentheses to indicate when a distribution is needed to simplify. g(f(x))=AnswerNow simplify the composition, are f(x) and g(x) inverses? Answer
Answer:
• (a)g[f(x)]=5(-3x+5)+5
,• (b)No
Explanation:
Given f(x) and g(x):
[tex]\begin{gathered} f(x)=-3x+5 \\ g(x)=5x-3 \end{gathered}[/tex](a)First, we find the composition, g[f(x)].
[tex]\begin{gathered} g(x)=5x-3 \\ \implies g\lbrack f(x)\rbrack=5f(x)-3 \\ g\lbrack f(x)\rbrack=5(-3x+5)+5 \end{gathered}[/tex](b)Next, we simplify g[f(x)] obtained from part (a) above.
[tex]\begin{gathered} g\mleft[f\mleft(x\mright)\mright]=5\mleft(-3x+5\mright)+5 \\ =-15x+25+5 \\ =-15x+30 \end{gathered}[/tex]Given two functions, f(x) and g(x), in order for the functions to be inverses of one another, the following must hold: f[g(x)]=g[f(x)]=x.
Since g[f(x)] is not equal to x, the functions are not inverses of one another.
A/ Question 8 (5 points) A recent Nielson rating poll contact a random sample of Americans to determine the amount of time their family watched television on a Tuesday night. Exactly 250 people were involved in the poll with 37 people watching no television. 51 people watching 30 minutes of television. 17 people watching 45 minutes of television. 20 people watching 60 minutes of television, 19 people watching 75 minutes of television. 11 people watching 90 minutes of television. 50 people watching 120 minutes of television, and 45 people watching 240 minutes of television. Determine the mode from the given Nielson rating poll.
Answer
The mode of the Nielsen rating poll is the group that watch 30 minutes of televison.
Explanation
The mode in a dataset is the variable with the highest frequency. That is, the variable that occurs the most in the dataset.
37 people watching no television.
51 people watching 30 minutes of television.
17 people watching 45 minutes of television.
20 people watching 60 minutes of television.
19 people watching 75 minutes of television.
11 people watching 90 minutes of television.
50 people watching 120 minutes of television.
45 people watching 240 minutes of television.
The group with the highest frequency (51) is the the group that watch 30 minutes of television.
Hope this Helps!!!
Explain how rays AB and AC form both a line and an angle.
Answer:
The point from C goes straight until it reaches A and stull continues till it gets ti B and stops. The angle is then given as 180°
What are the solutions to the equation ? e^1/4x = (4x) [tex]e^1/4x =abs( 4x)[/tex](Round to the nearest hundredth). The solutions are about x = and
The solution of the equation e^(x/4) = |4x| for the x by graphical approach is 0.27 and -0.24.
What is the equation?The definition of an equation in algebra is a mathematical statement that demonstrates the equality of 2 mathematical expressions.
A formula known as an equation uses the same sign to denote the equality of two expressions.
As per the given expression,
e^(x/4) = |4x|
The function e^(x/4) is an exponential function and the plot of this function has been plotted below.
The mode function |4x| has also been plotted below.
The point of intersection is the point where both will be the same or the solution meets.
The first point of intersection is (0.267,1.0691) so x = 0.267 ≈ 0.27
The second point of intersection (-0.2357,0.9428) so x = -0.2357 ≈ -0.24
Hence " The solution of the equation e^(x/4) = |4x| for the x by graphical approach is 0.27 and -0.24.".
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I need a tutor for algebra
Answer:
0.40
Explanation:
From the question, we're given that;
* 8% of the members run only long-distance, so the probability that a member of the team will run only long-distance, P(A) = 8/100 = 0.08
* 12% compete only in non-running events, so the probability that a member will compete only in non-running events, P(B) = 12/100 = 0.12
* 32% are sprinters only, so the probability that a member is a sprinter only P(C) = 32/100 = 0.32
We're asked in the question to determine the probability that a randomly chosen team member runs only long-distance or competes only in sprint events, since these events cannot occur at the same time, we can use the below formula to solve as shown below;
[tex]P(\text{A or C) = P(A) + P(C)}[/tex]P(A or C) = 0.08 + 0.32 = 0.40
a) Jayla says that the equation y=2*3 matches the graph Substitute the ordered pairs (from part() into the equation to prove that jayla is correct. Make sure to show ALL steps
From the graph let's take the points as the ordered pairs:
(3, 3), (4, 5), and (5, 7)
Given the equation:
y = 2x - 3
Let's verify for all points, if the equation matches the graph:
a) (x, y) ==> (3, 3)
Substitute 3 for x and 3 for y in the equation
y = 2x - 3
3 = 3(3) - 3
3 = 6 - 3
3 = 3
b) (x, y) ==> (4, 5)
Substitute 4 for x and 5 for y:
y = 2x - 3
5 = 2(4) - 3
5 = 8 - 3
5 = 5
c) (x, y) ==> (5, 7)
Substitute 5 for x and 7 for y:
y = 2x - 3
7 = 5(2) - 3
7 = 10 - 3
7 = 7
Since the left side equals the right side of the equation, the equation
y=2x-3 matches the graph.
Therefore, Jayla is correct.
the stock market lost 231 points on Tuesday then walks 128 more points on Wednesday find a change of points over the two days
the change of the points is:
[tex]-231-128=-359[/tex]so in the 2 days the stock market lost 359 points
Can someone help me with this geometry question? First box has 3 options: 60,96,48Second box has two options: 480 and 552Third box: 180 and 216
Surface area of a square prism is:
[tex]\begin{gathered} \text{4\lparen ah\rparen= SA square prism} \\ 4(20)(6)\text{= SA square prism} \\ 80(6)\text{= SA square prism} \\ 480=\text{SA square prism} \\ \\ \end{gathered}[/tex]The surface area of the square prism 480.
The surface area for the cube is:
[tex]\begin{gathered} 5a^2=\text{ SA cube} \\ 5(6)^2=\text{ SA cube} \\ 5(36)=\text{ SA cube} \\ 180=\text{ Surface area of the cube} \end{gathered}[/tex]The surface area of the cube is: 180.
The surface area of the pyramid is:
[tex]\begin{gathered} SurfaceAreaPyramid=4bh \\ SAPyramid=\text{4\lparen6\rparen\lparen4\rparen} \\ SAPyramid=\text{ 96} \\ \end{gathered}[/tex]The surface area of the pyramid i 96.
In each geometric figure, we have to remove the inner square faces, since they are not on the surface.
The total surface area is:
[tex]\begin{gathered} SA\text{ cube + SA square prism + SA pyramid= Total SA} \\ 180\text{ + 480 + 96= Total SA} \\ 756=\text{ Total surface area. } \end{gathered}[/tex]The total surface area is 756.
help meee pleaseeee pleasee
Answer:
f(x) = (-1/4)x - 5
Step-by-step explanation:
(-8, -3), (-12, -2)
(x₁, y₁) (x₂, y₂)
y₂ - y₁ -2 - (-3) -2 + 3 1 -1
m = ------------ = ------------- = ----------- = --------- = -------
x₂ - x₁ -12 - (-8) -12 + 8 -4 4
y - y₁ = m(x - x₁)
y - (-3) = (-1/4)(x - (-8)
y + 3 = (-1/4)(x + 8)
y + 3 = (-1/4)x - 2
-3 -3
-------------------------------
y = (-1/4)x - 5
I hope this helps!
4. At a shelter, 15% of the dogs are puppies. If there are 60 dogs at the shelter, how many are puppies? * O 400 O 25 O 9 O 42
4. At a shelter, 15% of the dogs are puppies. If there are 60 dogs at the shelter, how many are puppies? * O 400 O 25 O 9 O 42
_____________________________________________________
60* (0.15) = 9
_______________________________
Answer
There are 9 puppies
8in 8in 8in area of irregular figures
Given data:
The given figure.
The expression for the area is,
[tex]\begin{gathered} A=(8\text{ in)(8 in)+}\frac{1}{2}(8\text{ in)( 8 in)} \\ =96in^2 \end{gathered}[/tex]Thus, the area of the given ffigure is 96 square-inches.
If we use 3.14 for pi, describe the ratio between the circumference and the diameter of a circle.
Solution
The ratio of the circumference of any circle to the diameter of that circle.
[tex]\begin{gathered} \text{circumference of a circle=}\pi d \\ \text{where d is the diameter} \\ \\ \text{circumference of a circle=3.14}d \end{gathered}[/tex]The ratio of the circumference of any circle to the diameter of that circle. Regardless of the circle's size, this ratio will always equal pi.
Find percent change of 50 to 43
Answer:
-14.00%
Step-by-step explanation:
((43-50)/50)*100 = -14.00%
nction.
f(x) = -x² + 3x + 11
Find f(-1)
Answer:
f(-1) = 7
Step-by-step explanation:
Hello!
You can evaluate for f(-1) by substituting -1 for x in the equation.
Evaluate f(-1)f(x) = -x² + 3x + 11f(-1) = -(-1)² + 3(-1) + 11f(-1) = -1 -3 + 11f(-1) = -4 + 11f(-1) = 7f(-1) is 7.
Answer:
f(-1) = 7
Step-by-step explanation:
Hello!
You can evaluate for f(-1) by substituting -1 for x in the equation.
Evaluate f(-1)f(x) = -x² + 3x + 11f(-1) = -(-1)² + 3(-1) + 11f(-1) = -1 -3 + 11f(-1) = -4 + 11f(-1) = 7f(-1) is 7.
Help me to answer this question with vectors, thank you
To find:
The coordinates of a point P such that PA = PB.
Solution:
Given that A(4, 0) and B(0, 9) are the coordinates.
Let the point P is (x,0) because the point is on x-axis, and it is given that |PA| = |PB|.
So,
[tex]\sqrt{(4-x)^2+(0-0)^2}=\sqrt{(x-0)^2+(0-9)^2}[/tex]Now, squaring both the sides:
[tex]\begin{gathered} (4-x)^2=x^2+9^2 \\ 16+x^2-8x=x^2+81 \\ 8x=-65 \\ x=\frac{-65}{8} \end{gathered}[/tex]Thus, the coordinates of point P are (-65/8, 0).
in the figure shown MN is parallel to segment YZ what is the length of segment YZ
We will solve this question using the similar angle theorem
The shape consist of two triangles which i am going to draw out,
One is a big triangle while the other is a small triangle
Let NZ = a
To find NZ We will equate the ratio of the big triangle to that of the small triangle
[tex]\frac{7.5\operatorname{cm}}{3\operatorname{cm}}=\frac{(a+5)cm}{5\operatorname{cm}}[/tex]We then cross multiply to get,
[tex]\begin{gathered} 3(a+5)=7.5\times5 \\ 3a+15=37.5 \\ by\text{ collecting like terms we will have that} \\ 3a=37.5-15 \\ 3a=22.5 \\ \frac{3a}{3}=\frac{22.5}{3} \\ a=7.5\operatorname{cm} \end{gathered}[/tex]Therefore XZ=XN+NZ
[tex]XZ=5+7.5=12.5\operatorname{cm}[/tex]To calculate YZ ,
We will use the pythagorean theorem,
[tex]\begin{gathered} XZ^2=YZ^2+XY^2 \\ 12.5^2=YZ^2+7.5^2 \\ 156.25=YZ^2+56.25 \\ YZ^2=156.25-56.25 \\ YZ^2=100 \\ YZ=\sqrt[]{100} \\ \vec{YZ}=10.0cm \end{gathered}[/tex]Therefore ,
The value of YZ is
[tex]\vec{YZ}=10.0\operatorname{cm}[/tex]Hence ,
The correct answer is OPTION B
If 16 is increased to 23, the increase is what percent of the original number? (This is known as the percent of change.)
Step 1
Given data
Old value = 16
New value = 23
Step 2
Write the percentage increase formula
[tex]\text{Percentage increase = }\frac{I\text{ncrease}}{\text{Old}}\text{ }\times\text{ 100\%}[/tex]Step 3
Increase = 23 - 16 = 7
[tex]\begin{gathered} \text{Percentage increase = }\frac{7}{16}\text{ }\times\text{ 100\%} \\ =\text{ 43.75\%} \end{gathered}[/tex]Find the percent of change from 120 bananas to 40 bananas.
Answer:
67% decrease
Explanation:
From the given problem:
Initial number of bananas = 120
Final number of bananas = 40
[tex]\begin{gathered} \text{Percent Change=}\frac{Final\text{ Value-Initial Value}}{\text{Initial Value}}\times100 \\ =\frac{40-120}{120}\times100 \\ =-\frac{80}{120}\times100 \\ =-0.667\times100 \\ =-66.7\% \\ \approx-67\% \end{gathered}[/tex]Since we have a negative value, we have a 67% decrease.
Evaluate. 7⋅5+42−23÷4
The result that can be gotten from the evaluation here is 6.625
How to solve the problemWe would have to solve the problem following the order that the operations are. The reason why it would have to be solve this way is because the operations are not in a bracket.
If it was in brackets, the brackets would have to be solved first using the bodmas rule
so we would have
7⋅5+42 = 49.5
49.5 - 23 = 26.5
26.5 / 4 = 6.625
The value that we got from the evaluation is 6.625
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A farm raises cows and chickens. The farm has total of 43 animals. One day he counts the legs of all his animals and realizes he has a total of 122. How many cows and chickens does he have?
Assume that there are x cows and y chickens in the form
Since there are 43 animals, then
Add x and y, then equate the sum by 43
[tex]x+y=43\rightarrow(1)[/tex]Since a cow has 4 legs and a chicken has 2 legs
Since there are 122 legs, then
Multiply x by 4 and y by 3, then add the products and equate the sum by 122
[tex]4x+2y=122\rightarrow(2)[/tex]Now, we have a system of equations to solve it
Multiply equation (1) by -2 to make the coefficients of y equal in values and opposite in signs
[tex]\begin{gathered} -2(x)+-2(y)=-2(43) \\ -2x-2y=-86\rightarrow(3) \end{gathered}[/tex]Add equations (2) and (3) to eliminate y
[tex]\begin{gathered} (4x-2x)+(2y-2y)=(122-86) \\ 2x+0=36 \\ 2x=36 \end{gathered}[/tex]Divide both sides by 2
[tex]\begin{gathered} \frac{2x}{2}=\frac{36}{2} \\ x=18 \end{gathered}[/tex]Substitute x by 18 in equation (1)
[tex]18+y=43[/tex]Subtract 18 from each side
[tex]\begin{gathered} 18-18+y=43-18 \\ y=25 \end{gathered}[/tex]The answer is
There are 18 cows and 25 chickens on the farm