A stone is thrown horizontally at 15 m/s from the top of a cliff 44 meters high. How far from the base does the stone hit the ground?

Your answer would be Device A.

Answer:

Device A because it would use more voltage :D

Explanation:

V = I · R

I = V / R

R = V / I

R = V / I

Resistance of the living room light = (12V) / (15A)

Resistance of the light = 0.8 ohm

V = I · R

Voltage of the bedroom circuit = (15 A) · (12 ohms)

Voltage of the bedroom circuit = 180 volts

I = V / R

Current through the dryer = (240V) / (28 ohms)

Current through the dryer = 8.57 A

Answer

D

Explanation:

Potential energy is related to an object's position, and kinetic

energy is related to its motion.

The work needed to stop the car is

W = ∆K = 0 - 1/2 (1242 kg) (22.5 m/s)² ≈ -314 kJ

A stopping force that does this amount of work, pointing in the opposite direction with magnitude 7210 N, would be exerted over a distance x such that

W = (-7210 N) x   ==>   x ≈ 43.6 m

Answer:

the last answer is correct.

Explanation:

If one team pulls with more force than the middle flag or marker will move

Answer:

The coefficient of friction between the block and the slope is 0.16.

Explanation:

We can find the coefficient of friction between the block and the slope by using Newton's second law:        

[tex] \Sigma F = ma [/tex]

[tex]P_{x} -\mu N = ma[/tex]

[tex] mgsin(\theta) - \mu mgcos(\theta) = ma [/tex]    (1)              

Where:

m: is the mass of the block = 5.0 kg

a: is the acceleration = 4.2 m/s²

θ: is the angle = 34°

μ: is the coefficient of friction =?

g: is the gravity = 9.81 m/s²

By entering the above values into equation (1) we have:

[tex] gsin(\theta) - \mu gcos(\theta) = a [/tex]                  

[tex] \mu = \frac{gsin(\theta) - a}{gcos(\theta)} = \frac{9.81 m/s^{2}*sin(34) - 4.2 m/s^{2}}{9.81 m/s^{2}*cos(34)} = 0.16 [/tex]

Therefore, the coefficient of friction between the block and the slope is 0.16.

I hope it helps you!        

Answer:

It is a product, so it is released by the plant.

Explanation:

[tex]6CO2 + 6H2O[/tex] → [tex]C6H12O6 + 6O2[/tex]

The plant uses water and carbon dioxide to create glucose and oxygen. Glucose is plant food, and Oxygen is given off as a byproduct.

Answer:

It is a product, so it is released by the plant.

Explanation:

Answer:

Condensation

Explanation:

Answer:

Condensation! Hope this helps!!!

Explanation:

Answer:

Speed is acceleration or a high rate of motion

Answer:

the rate at which something or someone moves or operates or is able to move or operate .

Answer:

A. chemical

Explanation:

the type of energy our body contain is chemical energy and that chemical energy is the one used while pushing the swing.. so I guess it's chemical energy.. based on my knowledge hope this helps.

Answer:

98

Explanation:

Answer:

A mirror is an image reflecting an object.

Explanation:

yes a mirror is reflective

Answer:

Explanation:

Yes, a mirror is reflective to light. But there are electro magnetic waves of different frequency like radio wave that a mirror is not reflective.

Answer:

Force / mass

Explanation:

Divide mass on both sides to get acceleration by itself leaving you with mass below force hence divide force by mass

Answer:

F, = 12N. F, = 2 N. Block. 4) a 20.0-kg mass moving at 1.00 m/s.

Explanation:

The mass of the block on the frictionless horizontal surface is 5 kg.

The given parameters;

The mass of the block is determined by applying Newton's second law of motion;

F = ma

[tex]\Sigma F = ma\\\\F_1 - F_2 = ma\\\\12 - 2 = 2m\\\\10 = 2m\\\\m = 5 \ kg[/tex]

Thus, the mass of the block on the frictionless horizontal surface is 5 kg.

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Answer:

p = 50 kg·m/s

Explanation:

attached is a good way to remember the formula!

Answer: it’s 1,470 N

Explanation:

Since F=m*a then 150*9.8=1,470.

Weight of given cart is 1,470 N

Given that:

Mass of cart = 150 kg

Acceleration due to gravity = 9.8 m/s²

Find:

Weight of cart

Computation:

Weight = m × g

Weight of cart = Mass of cart × Acceleration due to gravity

Weight of cart = 150 × 9.8

Weight of cart = 1,470 N

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Answer:

F - fr = ma ,    N - W = 0

Explanation:

In this exercise we are asked to identify the forces that act on the jack, for this we will use Newton's second law

On the x axis

We have two forces: the friction and the force of the girl who pulls the cat

           F - fr = ma

On the y axis

There are two forces: normal and weight

         N - W = 0

A diagram of these forces can be seen in the attachment

Answer:

The earth is 4 billion years old.

Explanation:

Answer:

you need to capitalize

Explanation:

When Grandpa Joe comes to visit, he tells us stories about when he was in the army with Colonel Jack S. Anderson.

Answer: 5m

(10m) sin 30

=5m

The vertical displacement of the circus performer in m is 5m.

The displacement is the shortest distance travelled by the particle. It is the vector quantity which represents both the magnitude and direction.

A circus performer walked up and to the right for a total displacement of 10 m along a diagonal tightrope angled 30° above the ground.

We know the hypotenuse is 10m (diagonal) and the angle above the ground is 30°

The displacement will be sin (30) of hypotenuse.

Displacement = 10 sin (30)

                      d = 5m

Thus, the vertical displacement of the circus performer is 5 m.

Learn more about displacement.

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#SPJ2

Answer:

(a) 5.62 m/s²

(b) 5.46 m/s²

Explanation:

The given values are:

mass,

m = 50 kg

angle

= 35°

(a)

If friction neglected,

⇒ [tex]F_x=mgSin \theta=ma[/tex]

⇒ [tex]a_x=gSin \theta[/tex]

       [tex]=9.8 \ Sin35^{\circ}[/tex]

       [tex]=5.62 \ m/s^2[/tex]

(b)

If friction present,

⇒ [tex]F_x=mgCos \theta[/tex]

⇒ [tex]F_x=mgSin \theta-\mu_r mgCos \theta[/tex]

⇒ [tex]a=gSin \theta-\mu_rgCos \theta[/tex]

      [tex]=9.8 \ Sin35^{\circ}-0.02\times 9.8 \ Cos30^{\circ}[/tex]

      [tex]=5.46 \ m/s^2[/tex]

Answer:

less force

Explanation:

less force because they is increase in area and not enough energy to balance the whole equation

Answer:

the same

Explanation:

Answer:

The angular velocity of the propeller is 2.22 rad/s.

Explanation:

The angular velocity (ω) of the propeller is:  

[tex] \omega = \frac{\Delta \theta}{\Delta t} [/tex]                              

Where:

θ: is the angular displacement = 10.6 revolutions

t: is the time = 30 s

[tex] \omega = \frac{\Delta \theta}{\Delta t} = \frac{10.6 rev*\frac{2\pi rad}{1 rev}}{30 s} = 2.22 rad/s [/tex]

Therefore, the angular velocity of the propeller is 2.22 rad/s.

I hope it helps you!

Given:

Angular displacement,

Diameter,

Time,

Now,

The angular velocity will be:

→ [tex]\omega = \frac{\Delta \Theta}{\Delta t}[/tex]

By putting the values, we get

       [tex]= \frac{10.6\times \frac{2 \pi rad}{1 \ rev} }{30 \ s}[/tex]

       [tex]= 2.22 \ rad/s[/tex]

Thus the response above is right.

Learn more about velocity here:

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Answer:

Time = 11.60 seconds.

Explanation:

Speed can be defined as distance covered per unit time. Speed is a scalar quantity and as such it has magnitude but no direction.

Mathematically, speed is given by the equation;

[tex]Speed = \frac{distance}{time}[/tex]

Given the following data;

Speed = 0.711m/s

Distance = 8.25m

To find the time;

Making time the subject of formula, we have;

[tex]Time = \frac{distance}{speed}[/tex]

Substituting into the equation, we have;

[tex]Time = \frac{8.25}{0.711}[/tex]

Time = 11.60 secs.

Answer:it’s a

Explanation:

Answer:

A electrons

Explanation:

bcs

Answer:

All forms of energy are either kinetic or potential. The energy associated with motion is called kinetic energy . The energy associated with position is called potential energy . Potential energy is not "stored energy".

Explanation:

Explanation:

W=F×s

=> W= [MLT^-2] [L]

W= [ML2T-2]