A steel beam is rotated in a horizontal plane to provide the centripetal acceleration for training pilots. If the pilot sits 2.19 m from the center of rotation, at what speed must he rotate in order to experience a horizontal centripetal acceleration of 65.8 m/s/s?

Answer:

2.4J

Explanation:

Given parameters:

Spring constant  = 120N/m

Extension  = 0.2m

Unknown:

Amount of energy  = ?

Solution:

The energy stored in this stretched spring is called the elastic potential energy.

It can be derived using the expression below:

 Elastic Potential energy  = [tex]\frac{1}{2}[/tex] ke²  

k is the elastic constant

e is the extension

  Insert the parameters;

        Elastic potential energy  =  [tex]\frac{1}{2}[/tex]  x 120 x 0.2²  = 2.4J

Explanation:

F=MA

F=1500 * 2

F=3000N

Answer:

D

Explanation:

The decrease in potential energy is equal to the increase in kinetic energy.

mgh

250 x 9.8 x 30

=73, 500

Answer:

73,500 J

Explanation:

100% Correct

Answer:

μ = 0.125

Explanation:

To solve this problem, which is generally asked for the coefficient of friction, we will use the conservation of energy.

Let's start working on the ramp

starting point. Highest point of the ramp

         Em₀ = U = m h y

final point. Lower part of the ramp, before entering the rough surface

        [tex]Em_{f}[/tex] = K = ½ m v²

as they indicate that there is no friction on the ramp

          Em₀ = Em_{f}

          m g y = ½ m v²

          v = [tex]\sqrt{2gy}[/tex]

we calculate

          v = √(2 9.8 0.25)

           v = 2.21 m / s

in the rough part we use the relationship between work and kinetic energy

          W = ΔK = K_{f} -K₀

as it stops the final kinetic energy is zero

          W = -K₀

The work is done by the friction force, which opposes the movement

          W = - fr x

friction force has the expression

          fr = μ N

let's write Newton's second law for the vertical axis

         N-W = 0

         N = W = m g

we substitute

            -μ m g x = - ½ m v²

           μ = [tex]\frac{v^{2} }{2 g x}[/tex]

Let's calculate

           μ = [tex]\frac{2.21^{2}}{2\ 9.8\ 2.0}[/tex]

           μ = 0.125

A 8.0 kg box is released from rest at a height y0 = 0.25 m on a frictionless ramp. The box slides from the ramp onto a rough horizontal surface. The box slides 2.0 m horizontally until it stops.

What is the friction coefficient of the horizontal surface?

Answer: 0.125

Answer:

45 degrees

Explanation:

Given that the coefficient of friction, [tex]\mu=1.0[/tex]

Let the angle of the ramp be [tex]\theta[/tex].

The gravitational force acting downward [tex]=mg[/tex]

The normal reaction by the ramp on the box, [tex]N=mg\cos\theta[/tex]

So, the maximum frictional force that can act on the box, [tex]f= \mu N[/tex]

The force along with the plane in the direction of sliding, [tex]F = mg\sin\theta[/tex]

When the box begins sliding, the F must have to overcome the frictional force,f.

So, F=f

[tex]mg\sin\theta=\mu N \\\\mg\sin\theta=\mu mg\cos\theta \\\\\frac {\sin\theta}{\cos\theta}=\mu \\\\\tan\theta=\mu \\\\\theta=\tan^{-1}\mu \\\\[/tex]

Putting the value of \mu, we have

[tex]\theta=\tan^{-1}1[/tex]

[tex]\theta=45[/tex] degrees.

Hence, the angle of the ramp with respect to the ground when the box begins sliding is 45 degrees.

Answer:

Explanation:

From the question given above, the following data were obtained:

Mass (m) = 1250 kg

Velocity (v) = 20.0 m/s.

Kinetic energy (K.E) =?

Kinetic energy is simply defined as energy possed by a body in motion. Mathematically, it is expressed as:

K.E = ½mv²

Where:

K.E is the kinetic energy

m is the mass of the object

v is the velocity of the object.

Thus, we can obtain the kinetic energy of the automobile by using the above formula as illustrated below:

Mass (m) = 1250 kg

Velocity (v) = 20.0 m/s.

Kinetic energy (K.E) =?

K.E = ½mv²

K.E = ½ × 1250 × 20²

K.E = 625 × 400

K.E = 250000 J

Therefore, the kinetic energy of the automobile is 250000 J

The action and reaction law allows us to find that the reaction force, the weight of the cylinder, is:

Newton's third law or action and reaction law, establishes that if two bodies interact with each other the force that one applies to the other, is equal in magnitude to the force of the second on the first but in the opposite direction, that is, all forces act in pairs one in each body that interact.

Forces with these characteristics are called action and reaction.

In this case we have a hanging cylinder, with the cylinder it has mass so the weight is 12 N it acts on the table in a downward direction, let's say this is the action force.

In response to this force, the table exerts a force on the cylinder of equal magnitude but in the opposite direction, which is why it is directed upwards.

let's analyze the force diagram

In conclusion using theaction and reaction law we find that the answer for reaction force is:

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Answer: A bad, maladaptive, unhealthy or destructive coping mechanism is one where the behavior does not resolve the problem in the long-term and may actually increase the harm. Unhealthy coping strategies may feel like they are having the desired effect in the short term.

Explanation: Yes, it was from google...

Answer:

truck 1 has the most velocity

Explanation:

Because it weights less which means it faster and yea

[tex]\huge\boxed{Option D}[/tex]

Radius of Mercury = [tex]R_m[/tex] = [tex]2.43x10^6m[/tex]

Mass of Mercury = [tex]M_m = 3.2x10^{23}m[/tex]

Distance Satellite above the surface of the Mercury = d = 265,000m

Gravitational Constant =  [tex]G = 6.67x10^{-11} \frac{N.m^2}{kg^2}[/tex]

Since the Satellite is orbiting around the Planet Mercury, due to the centripetal force, and Centripetal force is the force that acts towards the center of the circle, Whereas The gravitational force also acts towards the center of the circle thus we can say that Centripetal force is equal or same as centripetal force.  So,

                                             [tex]F_g =F_C[/tex]

Fg is Given by,

                                           [tex]F_g = \frac{GM_MM_S}{r^2}[/tex]

Fc is Given by,

                                           [tex]F_c=\frac{M_SV^2}{r}[/tex]

Where,

            G is Gravitational Constant

            [tex]M_e[/tex] is mass of Planet Mercury

            [tex]M_S[/tex] is Mass of Satellite

             r(small letter) is the distance between the center of the Planet Mercury and the satellite.

             V is velocity of satellite

Now,

                                 [tex]\frac{GM_MM_S}{r^2} =\frac{M_SV^2}{r}[/tex]

                                 [tex]V = \sqrt\frac{GM_M}{r}[/tex]

 r can also be written as,

                                  [tex]V = \sqrt\frac{GM_M}{R_M +d}[/tex]

Substitute the variables,

                                  [tex]V = \sqrt{\frac{(6.67x10^{-11})x(3.2x10^{23})}{2695000}[/tex]

Simplify the equation,

                                  V = 2814 [tex]\frac{m}{s}[/tex]

Approximately,

                                  V = 2800 [tex]\frac{m}{s}[/tex]

Explanation:

It is given that,

A car travels 14 km due west, then does a U-turn and travels 43 km due east (when it takes U-turn, it will change direction from west to east)

i. Total distance = total path covered

= 14 km + 43 km

= 57 km

ii. Let east is positive and west is negative.

Displacement = final position-initial position

= 43-14

= 29 km

iii. If time taken in the entire trip = 3.2 hours

Average speed = distance/time

[tex]s=\dfrac{57\ km}{3.2\ h}\\\\=17.81\ km/h[/tex]

1 km/h = 0.2777 m/s

17.81 km/h = 4.94 m/s

iv. If time taken in the entire trip = 2.5 hours

Average velocity = displacement/time

[tex]v=\dfrac{29\ km}{2.5\ h}\\\\=11.6\ km/h[/tex]

1 km/h = 0.621 mph

11.6 km/h = 7.2 mph

Henc, this is the required solution.

Answer:

The answer is "[tex]5.184 \times 10^{23}[/tex] kg"

Explanation:

Given:

[tex]g= 6.003 \ \frac{m}{s^2}\\\\G= 6.67 \times 10^{-11} \ \frac{N - m^2}{kg^2}\\\\M=?\\\\radius= 2,400 \ km\\\\[/tex]

Calculating diameter:

[tex]Diameter =radius \times 2[/tex]

                [tex]=24\times 10^5 \times 2\\\\=48 \times 10^5 \ m[/tex]

The formula for mass calculation:

[tex]\to g = G \times \frac{M}{(\frac{d^2}{4})}\\\\\to g=G\times \frac{4M}{d^2}\\\\\to 4M= \frac{g \times d^2}{G} \\\\\to M= \frac{g \times d^2}{4G} \\\\[/tex]

         [tex]=\frac{6.003 \times (48 \times 10^{5})^2}{4 \times 6.67 \times 10^{-11}}\\\\=\frac{6.003 \times 2,304 \times 10^{10}}{26.68\times 10^{-11}}\\\\=\frac{13,830.912 \times 10^{10}}{26.68\times 10^{-11}}\\\\=518.4 \times 10^{21}\\\\= 5.184 \times 10^{23}\\\\[/tex]

Answer:

True

Explanation:

Understanding the relationship between change in velocity with time will explain to you how the object is accelerating or decelerating. This means acceleration is a ratio calculated from the change in velocity of an object and change in time. In a velocity time graph, the y-axis represents the velocity and the x-axis represents the time.

The slope of the graph m = Δ y-axis values/Δ x-axis values

m= Δvelocity / Δ time

m= Δ v / Δ t ------this the definition of acceleration so;

a= Δ v / Δ t

Conclusion : The slope/gradient of a velocity -time graph is acceleration.

The complete question is;

The gravitational force between two objects is ______ proportional to the products of the masses and _______ proportional to the square of the distance between them.

Answer:

First dash is directly

Second dash is inversely

Explanation:

From Newton's law of gravitation the gravitational force is given by the equation;

F = GMm/r²

Where:

F is gravitational force

M and m are two masses representing the two objects

r is the distance between them

G = universal gravitational constant

Thus, if we are to write it in proportion format, we will have;

F ∝ Mm/r²

From this proportion relationship, we can see that the Gravitational force is directly proportional to the products of the two masses and inversely proportional to the square of the distance between them.

Answer:

Explanation:

The gravitational force between two objects is directly  proportional to the products of the masses and  inversely proportional to the square of the distance between them.

Answer:

a

Explanation:

Answer:

A or each parent had at least one allele for white pedals

Explanation:

Answer:

E =F.d =[1/2]mv^2

mad = [1/2]mv^2

d= v^2/2a ,v=u+at , v^2 = [at]^2 since u=0

So d = at^2/2

F = ma= 20a= 50 , a=5/2 and t=2

so d = [5/2][2^2]/2=5

Explanation:

Every action has an equal and opposite reaction. It is an action-reaction principle. Therefore the table exerts a force of 5 N on the book in order to be in stable condition.

Newton's third law of motion state that every action has an equal and opposite reaction. It is an action-reaction principle. It stated that the force always exists in a pair.

Therefore the table exerts a force of 5 N on the book in order to be in stable condition.

The given data in the problem is ;

W is the weight of the book sits on table = 5N

N is the normal force on the book

From the equilibrium equation ;

Weight -Normal force on the book  =0

Weight =Normal force on the book

The normal force on the book =5N

Hence the table exerts a force of 5 N on the book in order to be in stable condition.

To learn more about Newton's third law of motion refer to the link;

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Answer:

physical, social, and mental

Explanation:

Answer:

A,B,C

Explanation:

These three maintain the overall health of the person being. Take for instance an example a cake, it has layers that make the overall cake. So it is with the persons health, it takes all three of these feilds to make the overall health.

Answer:

The car is going 0 km/h more than the bike

Explanation:

Answer:

A

Explanation:

Trust me I just took it !

Answer:

between a ball and a car

Explanation:

lol i am just as baffled as you luv

Answer:

im pretty sure its d

Explanation:

Answer:

1700 kg

Explanation:

The mass of the ford mustang car be 1700 kg.

In physics, mass is a quantitative measurement of inertia, a basic characteristic of all matter. It essentially refers to a body of matter's resistance to changing its speed or location in response to the application of a force.

The change caused by an applied force is smaller the more mass a body has. The kilograms serves as the unit of mass in the International System of Units (SI).

Given parameters:

Force applied on the ford mustang car: F = 5100 N.

Acceleration of the ford mustang car: a = 3 m/s^2.

So, The mass of the ford mustang car be = force/acceleration

= 5100/3 kg.

= 1700 kg.

Hence, the mass of the ford mustang car be  1700 kg.

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#SPJ2

Answer:

Based off the word "conserved" I would say

A. Conservation of Momentum.

Explanation:

Answer:

A.) Conservation of Momentum

The first question's answer depends on what you mean by "sponge". If you're talking about sea sponges, then all but plastic are made up of cells. Some sponges used for cleaning are also made of plant material but also other, non-organic materials like dyes.

Cell walls are only present in plant cells, so they would be found in cork (derived from a certain tree bark), wood, and trees. Synthetic sponges made with plant material might also contain them, but they wouldn't be made entirely of cells with walls.

From given options or choices all are made up of cells except plastic and among the other four Cork, Sponge, Wood, and tree all show cell walls except Sponge.

A cell is the basic structural unit of all living organisms and contains various cell organelles. On the base of different cell organelles or presence or absence of the certain organelles help in distinct and divide the cell type.

The major types of cells are:

Plastic is not a living organism as there are no cells and is made up of polymers of hydrocarbon.

The cell wall is one of the major cellular structures that helps in identifying the type of cell organism and protects the organism from the external environment. It classifies the organism on its constituent of the cell wall.

In eukaryotic cells, animal cells have no cell wall, however, fungi cells, plant cells have a cell wall. A sponge is an animal and other cork wood, and trees are plants or plant-based products.

Thus, the sponge does not show the cell wall.

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Answer: thanks for the point

Explanation:

Answer:

[tex]T_2=\frac{T}{2}[/tex]

Explanation:

Given that engine 1 produces twice the power of engine 2.

Let [tex]P_1[/tex] and [tex]P_2[/tex] be the power of engine 1 and engine2.

So, the power of the engine 2,

[tex]P_2 = 2P_1\cdots(i)[/tex]

As, Work = Power x time,

So, the work, W, done by an engine 1:

[tex]W=P_1\timesT\cdots(ii)[/tex]

The work, W, done by an engine 2:

[tex]W_2=P_2\times T_2\cdots(iii)[/tex]

If the work done by both the engines are the same, then

[tex]W_2=W[/tex]

[tex]\Rightarrow P_2\times T_2=P_1\timesT[/tex] [from (ii) nd (iii)]

[tex]\Rightarrow 2P_1\times T_2=P_1\timesT[/tex] [by using (i)]

[tex]\Rightarrow 2 T_2=T \\\\\Rightarrow T_2=\frac{T}{2}[/tex]

Hence, [tex]T_2=\frac{T}{2}.[/tex]

The time taken for engine 2 to do the same amount of work is given by:

Let the power of the 1st engine be P₁

Let the power of the 2nd engine be P₂

From the question given above,

Engine 1 produces twice the power of engine 2.

Thus,

P₁ = 2P₂

P₂ = ½P₁

Work = W

Time (T₁) = T

Power = Work / time

Work = W

Power of engine 1 (P₁) = [tex]\frac{W}{T}\\\\[/tex]

Power of engine 2 (P₂) = ½P₁

Power of engine 2 (P₂) = [tex]\frac{1}{2} (\frac{W}{T}) = \frac{W}{2T}[/tex]

[tex]Power = \frac{Work}{time} \\\\ P_{2} = \frac{W}{T_{2}} \\\\\frac{W}{2T} = \frac{W}{T_{2}} \\\\\frac{1}{2T} = \frac{1}{T_{2}}\\\\[/tex]

Invert

Therefore, the time taken for engine 2 to do the same amount of work is: T₂ = 2T

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