A sports car reaches a speed of 50 m/sec in 12 seconds after staring from rest. The acceleration of the car is

Answers

Answer 1

Acceleration = (change in speed) / time for the change)

Acceleration = (50 m/s) / (12 s)

Acceleration = (4 and 1/6) m/s²


Related Questions

Which stament describes Newton’s law of universal gravitation

Mass has little effect on gravity between objects

Gravity pushes objects away from earths center

Gravity does not act between earth and the moon

Every object in the universe attracts every other object
I’ll give brainliest

Answers

every object in the universe attracts every other object

A rock is held steady over a cliff and dropped. 1 seconds later, another rock is thrown straight down at a speed of 11.3 m/s, and hits the first rock. How far have the rocks dropped before they collide? How long is the first rock in the air before it gets hit by the second rock?

What is the displacement of the rocks when they collide? __________ (Hint: be careful of sign -- the rocks drop.)
The first rock is in the air for __________ before it is hit.

Answers

Answer:  

4.27s

Explanation:

If "t" represents the time traveled from the time rock 2 is dropped until the collision, then the time traveled for rock 1 = t + 1. And, since rock #1 is dropped making its initial velocity = 0, then:

The distance rock 1 travels is  

x = (0)(t + 1) + 1/2(-9.8)(t + 1)2 = -4.9(t2 + 2t + 1) = -4.9t2 - 9.8t - 4.9

The distance rock 2 travels  

x = -11.3t + 1/2(-9.8)t2 = -11.3t - 4.9t2

For the distances must be equal when the rocks collide:  

-4.9t2 - 9.8t - 4.9 = -11.3t - 4.9t2  

-9.8t - 4.9 = -11.3t  

-4.9 = -1.5t  

t = 3.267 s

Now, the distance they traveled can be found by plugging the 3.267 s back into either equation:

x = -11.3(3.267) - 4.9(3.267)2 = -89.2 m or 89.2 m below where they began

The time the first rock was in the air is t + 1 = 3.267 + 1 = 4.267 s = 4.27 s

Let

First rocks time be x

Second rocks time be x+1

initial velocity=u=11.3m/s

Distance of both rocks be s1 and s2

[tex]\\ \sf\longmapsto s=ut+\dfrac{1}{2}at^2[/tex]

Now

[tex]\\ \sf\longmapsto s1=11.3x+5x^2[/tex]

[tex]\\ \sf\longmapsto s2=11.3(x+1)+5(x+1)^2[/tex]

As both collide then

[tex]\\ \sf\longmapsto s1=s2[/tex]

[tex]\\ \sf\longmapsto 11.3x+5x^2=11.3x+11.3+5(x+1)^2[/tex]

[tex]\\ \sf\longmapsto 5x^2=11.3+5x^2+10x+1[/tex]

[tex]\\ \sf\longmapsto 10x+12.3=0[/tex]

[tex]\\ \sf\longmapsto x=1.23s[/tex]

Displacement

[tex]\\ \sf\longmapsto 11.3(1.23)=13.8m[/tex]

Done

2. Starting from rest, a racecar has a displacement of 201 m south while accelerating at

16 m/s?. Calculate the time it takes the car to travel the 201 m.


Help solve please!

Answers

Answer:

Explanation:

Assuming you mean a = 16 m/s²

s = ½at²

t = √(2s/a)

t = √(2(201)/16)

t = 5.012484...

t = 5.0 s

PLEASEEEEEE HELPPPPPPP MEEEEEEEE!!!!!!!!!!!!!

Answers

Answer:

[tex]2 \\ because \\ 2 - 2 = 0 \\ 5 - 5 = 0[/tex]

plz help owo

What characteristic is shared by sunspots, solar flares, and coronal mass ejections? Select the two correct responses.


They are caused by outward fluctuations of the sun's magnetic field.

They appear as dark spots on the sun's surface.

They tend to occur during active periods of the solar cycle.

They appear as bright spots on the sun's surface.

Answers

Answer:

They are caused by outward fluctuations of the sun's magnetic field.

They tend to occur during active periods of the solar cycle.

Explanation:

While sun spots will appear darker than the surrounding surface, flares will tend to appear brighter. CME's are associated with massive flares.

The two correct responses are as follows:

They are caused by outward fluctuations of the sun's magnetic field.They tend to occur during active periods of the solar cycle.

The following information should be considered:

At the time when sunspots should appear darker as compared to the surrounding surface, so flares should be appear brighter. CME's are along with massive flares.Due to this, the above answers are considered.

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While you push a box you begin to decrease the force you are exerting on the box. When will the box reach equilibrium?

A. When the force you are exerting on the box is equal to 0.

B. When Fyou on box = -Fbox on you.

C. When the force of the box becomes Fyou on box < Fbox on you

D. The box will never reach equilibrium.

Answers

The application of a force on the box overcomes the friction and causes the box to accelerate

While the force is decreasing, the box will stabilize;

B. When [tex]\underline{F_{you \, on \, box} = -F_{box \, on \, you}}[/tex]

Reason:

Newton's third Law of Motion states that action and reaction are equal in magnitude and opposite in direction

When the box is pushed with a force, [tex]F_{you \, on \, box}[/tex], the reaction of the box of mass, m,  is as follows;

[tex]F_{you \, on \, box}[/tex] = [tex]F_{friction}[/tex] + m × acceleration

Where;

[tex]F_{friction}[/tex] = [tex]-F_{box}[/tex] for example

The negative sign is due to the direction of the friction force, or [tex]F_{box}[/tex] is opposite to the direction of the applied force

When the force is decreased to F₂ = [tex]F_{you \, on \, box}[/tex], such that we have;

[tex]F_{you \, on \, box}[/tex] = [tex]-F_{box \, on \, you}[/tex] , which is the condition for equilibrium, and the net

force is zero and according to Newton's first law of motion,  the box moves

at constant speed no acceleration

Therefore the box will reach equilibrium when;

[tex]\mathbf{\underline{F_{you \, on \, box} = -F_{box \, on \, you}}}[/tex]

Learn more about equilibrium here;

https://brainly.com/question/16679851

Answer:

When the force you are exerting on the box is equal to 0

Explanation:

Once again expert verifiers are sabotaging people here is the actual answer.

What four processes allow for the change of thermodynamics properties according to the first law

Answers

Answer:

The four types of thermodynamic process are isobaric, isochoric, isothermal and adiabatic.

You are driving to grandma's house, and you are traveling at an average of 70 mph. How long will it take you to travel 70 miles?
O 1 hour
O 1 second
70 hours
O 70 seconds

Answers

Answer: 1 hour

Explanation: Focus on the units; 70 miles per hour means that each hour, you will travel 70 miles

or you can use the equation time = distance/speed. You have 70miles/ 70mph = 1hour

Helppppppppppppppp please and explain!

Answers

An EM with a short energy has more energy than a longer wavelength. the higher the frequency, the shorter the wavelength and the higher the energy of the wave. yw

the atmosphere of mercury and mars are very thin.what effects does the thin atmosphere on the temperature on the surface of this planet?

Answers

Answer:

The effects of the thin atmosphere are that the surface of the planet is going to be much hotter and not only that but also more radioactive than a planet with a thicker atmosphere. The thick atmosphere on other planets prevents a lot of radiation from going straight to the surface of the planet.

Explanation:

Say hi :P...................................................................

Answers

HELLOOOOOOOOOOOOOOOOOOOOO

Everytime a train passes Ms. Lindsey's house, one specific item on her dresser rattles. Use physics to explain why this occurs.

Answers

Answer: gravity

Explanation: the moving and sifting around in the train

What is the magnitude of the momentum of a 1000 kg car traveling
at 5 m/s?

Answers

Answer:

5000 kg.m/s

Explanation:

The momentum of an object can be found by using the formula

momentum = mass × velocity

From the question

mass = 1000 kg

velocity = 5 m/s

We have

momentum = 1000 × 5 = 5000

We have the final answer as

5000 kg.m/s

Hope this helps you

What is the pulling force of this train, if its engine provides 4200 kW power and 90 km/h speed?

Answers

Answer:

yes by 30

Explanation:

uhnhuh

What is the smallest part of a compound called?
element
O
molecule
O
atom
O
mixture
o

Answers

Answer:

Here is your answer,thanks for using brainly!

Explanation:

B:Molecule

Molecules usually consist of 2 atoms linked together,however some molecules  consist of thousands of atoms!

Here is a list of smalles to largest with the answers provided

Molecules

Atoms

Elements

Mixtures

Hope this helped

Plz mark brainliest

Dont forget to smash that heart at the bottom <3

Have a great day!


A block of mass 2.52 kg is kept at rest
as it compresses a horizontal massless spring
(k 116 N/m) by 9.73 cm. As the block
is released, it travels 0.537 m on a rough
horizontal surface before stopping.
The acceleration of gravity is 9.8 m/s.
Calculate the coefficient of kinetic friction
between surface and block.

Answers

By Newton's second law, the net vertical force on the block is

F = N - mg = 0

so that the normal force exerted by the surface has magnitude

N = mg = (2.52 kg) (9.80 m/s²) = 24.7 N

Then as the block slides over the surface, it feels a frictional force of

f = µ (24.7 N)

where µ is the coefficient of kinetic friction.

As the block is pushed by the spring to its equilibrium position, friction performs

µ (-24.7 N) (0.0973 m) = -2.40µ J

of work (which is negative because it opposes the block's motion).

In compressing the spring by 9.73 cm = 0.0973 m, we store

1/2 (116 N/m) (0.0973 m)² = 0.549 J

of energy. This energy is released and partially converted to kinetic energy, while the rest is lost to friction.

By the work-energy theorem, the total work performed on the block as the spring pushes it towards the equilibrium position is equal to the change in its kinetic energy:

W = ∆K

0.549 J - 2.40µ J = 1/2 (2.52 kg) v ² - 0

where v is the speed of the block at the equilibrium position. Solving for v, we get

v = 0.891 √(0.549 - 2.40µ) m/s

After the block is released, the only force acting on it as it slides freely is friction. It comes to a stop after 0.537 m, so that friction performs

µ (-24.7 N) (0.537 m) = -13.3µ J

of work.

Using the work-energy theorem again, we have

W = ∆K

-13.3µ J = 0 - 1/2 (2.52 kg) v ²

Substitute the velocity we found in terms of µ, and solve for µ :

-13.3µ J = -1/2 (2.52 kg) (0.891 √(0.549 - 2.40µ) m/s)²

===>   µ = 0.0350

If a material were being designed to demonstrate no thermal expansions, how would the energy plot look like?

Answers

The characteristics of thermal expansion allow finding that the response for a material without thermal expansion is

The length variation is zero In the graph the line is horizontal so there is no change in length with temperature

Thermal expansion is the macroscopic sum of the changes in the length of the bonds when the energy (temperature) changes, it can be written

              ΔL = α L₀ ΔT

Where ΔL is the change in length, α the coefficient of linear expansion, L₀ the initial length and ΔT the change in body temperature

In this case, a material is being designed that the thermal expansion is very small, for this the material must be made up of several compounds where some of them present a contraction with temperature, some examples: water at low temperature, liquefied gases , ceramic tile, quartz, etc.

The thermal expansion measurement processes control the body temperature and measure the change in length, in this case the change in length must be zero, in the attachment we can see a graph of a composite material with these characteristics, an example of this type of material is Invar an alloy of nickel and iron α = 3.7 10⁻⁶ ºC⁻¹

In conclusion, using the characteristics of thermal expansion we can find that the response of material without thermal expansion is

The length variation is zero In the graph the line is horizontal so there is no change in length with temperature

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A dog is running at an initial speed of 10 m/s. He covers 50 m in 4 seconds. What is the acceleration of the dog?

a.
1.25 m/s2

b.
1.04 m/s2

c.
5 m/s2

d.
3.2 m/s2

Answers

D i hope this helps
:))

For question 51, do you use a=d/t

Answers

No. That won't help. It's not even true.

When a car's acceleration is negative, what is happening to the car's motion?
the car slows down
the car speeds up
the car travels at a constant speed
the car remains at rest

Answers

Answer:

the car slows down

Explanation:

two balls are dropped from rest and allowed to fall for 1 s and the other for 3 s, compare the distances they have fallen​

Answers

Answer:
distance traveled by 3 second ball ≈ 45m
distance traveled by 1 second ball ≈ 5m

Explanation:

Since the 2 balls started at rest, their v initial = 0, and since no other force is acting on them except for the gravitational force, they accelerate downwards at 10m/s2.

To calculate the distance traveled by both balls, we apply the second formula of UARM motion:

• Δx = 1/2(a)(t^2) + (v0)(t)

Applying both 1s and 3s in this formula will yield you 5m and 45m respectively.


Hope this helps, brainliest would be appreciated :)

Which of the following is the best hypothesis

Answers

Answer:

Melting and frezzing are physical changes

In two paragraph of lines each, describe how you
would simplify, for your
grade 10 learners the
following topics
1.1 Electricity and magnetism.

Answers

The question above wants to assess your ability to simplify complex matters. In that case, I can't answer this question for you, but I'll show you how to answer it.

First, you should research electricity and magnetism. This research will make you understand the subject and all its elements. You can do this research in textbooks and digital platforms aimed at children and teenagers since these media usually present subjects in a more simplified way.

After doing this research, you will be able to write a text about electricity and magnetism as follows:

Present the main focus of this subject.Present the elements that make up this subject.Present how this subject applies in the real world.Present the importance of this subject in human life and society.

Remember that you must use simple language, without the use of technical terms, but with common terms.

More information:

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A rocket traveling through space with a constant velocity of 10 m/s fires up a booster. The booster accelerates the rocket at a rate of 5 m/s. What distance in meters has the rocket traveled within 12 seconds after the booster is turned on?​

Answers

The distance traveled by the rocket after the given time period is 480 m.

The given parameters;

velocity of the rocket, v = 10 m/sacceleration of the rocket, a = 5 m/s²time of motion of the rocket, t = 12 s

The distance traveled by the rocket after the given time period is calculated from the second kinematic equation of as shown below;

s = ut + ¹/₂at²

s = (10 x 12) + (0.5 x 5 x 12²)

s = 120 + 360

s = 480 m

Thus, the distance traveled by the rocket after the given time period is 480 m.

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PLEASE HELP!!
What process is illustrated in the figure?

Answers

Answer: A

Explanation:

When the propeller were turning at 25 rad/s , what is the period (in seconds) of this propeller?

Answers

Answer:

Explanation:

T = (2π rad / rev) / (25 rad/s) = 0.251327... = 0.25 s

The propeller was turning at 25 rad/s then the period of the propeller will be equal to 0.25 seconds.

What is Velocity?

In terms of physics, velocity is a vector assessment of the motion's direction and speed. The rate of change in an object's position relative to a reference frame and time is the more precise definition of velocity. Simply put, the concept of velocity informs us of the rate at which an object is travelling in a given direction.

It indicates the rate of motion of objects. Take two moving things like our illustration. If both items are travelling in the same vague direction, it is simple to determine which is moving more quickly.

From the given data in the question,

T = 2π (rad/rev) / 25 (rad/s)

T = 0.25 seconds.

Therefore, the period of this propeller is 0.25 seconds.

To know more about Velocity:

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Michael stands upright and allows his right arm to swing back and forth, naturally and without forcing, like a pendulum. He measures the time for 21 oscillations (complete cycles) to be 28.1 s. Assume his arm (length L) behaves as a simple pendulum, with an effective length of 2/3 L. Find the length of his arm, L.

Answers

Answer:

ytdgnrjjksmzjj3hfgbdhehkj jfjbcjbwbjrhrhb jdhbbjhhrhrhhjrjjr jfjnekrj

The length of his arm, L = 0.67 m.

What is time period?

A basic pendulum consists of a point mass hung by a tightly supported, weightless, and inextensible string.

T = 2π√ L/g, where L is the pendulum's length and g is the acceleration brought on by gravity, is the formula for a pendulum's period.

Given in the question  the time for 21 oscillations (complete cycles) to be 28.1 s. Assume his arm (length L) behaves as a simple pendulum, with an effective length of 2/3 L.

T = 2π√ L/g

T = 2π√2l/3g

T = 28.1/21

T = 1.33

2π√2l/3g =  1.33

l = .67 m

The length of his arm, L = 0.67 m.

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help please this is due in an hour!!!

Answers

[tex]▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ { \huge \mathfrak{Answer}}▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ [/tex]

Charge on one electron :

[tex]1.602 \times 10 {}^{ - 19} \: \: coulombs[/tex]

So, charge on ball having 97 electrons is equal to :

[tex]97 \times 1.602 \times 10 {}^{ - 19} [/tex]

[tex]155.394 \times 10 {}^{ - 19} [/tex]

[tex]1.554 \times 10 {}^{ - 17} \: \: coulombs[/tex]

A train travels meters in the first second of travel, 6 meters again during the second second of travel, and 6 meters again during the third second. Its
acceleration is
O 0 m/s
6 m/s
O 12 m/s/s
18 m/s
O None of the above

Answers

Answer:

0 m/s

Explanation:

there is no acceleration, it's velocity is always 6m/s

so your answer is 0m/s

What force prevents a machine from having 100% efficiency? A. Magnetic B. Electric O C. Friction O D. Gravity ​

Answers

Answer:

I believe it would be C ? my apologies if I'm wrong.

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