Answer:
Displacement=10 meters
Explanation:
The displacement is the direct path from the first contact with the ball and the last spot it was seen in. The ball was kicked north 8 meters, meaning it was kicked vertically upward, and then it was kicked east 6 meters, or to the right. If we were to draw the displacement we would see that this is a right triangle. That means we can use the Pythagorean Theorem:
[tex]a^2+b^2=c^2\\8^2+6^2=c^2\\64+36=c^2\\c^2=100\\\sqrt{c} =\sqrt{100} \\c=10[/tex]
Boom.
The displacement is 10 m toward the northeast. The first option is correct.
The displacement is a vector quantity having both magnitude and direction. It is equal to the path length between the initial and final positions.
Given:
North displacement, y=8 m
East displacement, x= 6 m
The net displacement is calculated using Pythagoras' theorem as the displacements are perpendicular to each other.
The displacement is given by:
d=√(x²+y²)
d=√(8²+6²)
d=10 m
So, the displacement is 10 m.
Therefore, the displacement is 10 m toward the northeast. The first option is correct.
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If the radio waves that are sent from the speed gun have a frequency of 400,000,002 Hz and the radio waves reflected off an approaching car have a frequency of 400, 000, 10 , what is the speed of the car? (Hz is the SI unit of frequency, equal to cycles per second).
Answer:
fL = fs(V/v-vs) 400000002= 40000010(331/331- vs). then find vs so easy
Pedro runs a total of 125 m in a straight line north in 11.5 s. What is his velocity.
the apparent shift of a nearby object against the background of more distant stars is called:
Answer:
Astronomers estimate the distance of nearby objects in space by using a method called stellar parallax, or trigonometric parallax. Simply put, they measure a star's apparent movement against the background of more distant stars as Earth revolves around the sun.
light waves are first transmitted through the ________ at the front of the eye and enter an opening called the ________ before shining onto the retina.
The transmission of light waves is usually done through cornea of the eyes, then move through another opening which is regarded as pupil before it will get to the retina.
Light waves can be regarded as moving energy which contains microscopic particles known as photons. The vision of the eye can be completed through the light wave passing through the components of the eyes and this process goes thus;Light will move through the (cornea) which is situated at the front area of the eyes into lens. Then both the cornea and the lens give room for the focusing of the light rays to the retina which is situated at the back of the eye .Then through the help of the cells in the retina, the light will be absorbed and then be converted to electrochemical impulses and then transfer it to the brain as well as optic nerve.Therefore, light wave are form of tiny microscopic particles.
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What is Newton's first law of motion?
A. For every force there is an equal and opposite reaction force.
B. If a net force is applied to an object, then the object will accelerate.
C. An object will remain at rest or continue moving in a straight line with a constant speed unless acted on by an unbalanced force.
D. The gravitational force between two objects is proportional to their masses and inversely proportional to the distance between them.
Answer:
C
Explanation:
Newton's first Law of Motion is also known as law of inertia, which states that "an object at rest remains at rest, and an object that is moving will continue to move straight and with constant velocity, if and only if there is no net force acting on that object". As such, the correct option should be C.
Option A is Newton's third Law of Motion.
Option B is Newton's second Law of Motion
Option D is Newton's Law of Universal Gravity
Differentiate the followingy= 14t^2-t^2/2+5t-3dy/dt=?
I'm going to assume you mean
[tex]y = 14t^2 - \dfrac{t^2}{2+5t} - 3[/tex]
Taking the derivative with respect to t on both sides gives
[tex]\dfrac{\mathrm dy}{\mathrm dt} = 2\cdot14t - \dfrac{(2+5t)(2t)-t^2(5)}{(2+5t)^2} - 0 \\\\ \dfrac{\mathrm dy}{\mathrm dt} = \boxed{28t - \dfrac{4t+5t^2}{(2+5t)^2}}[/tex]
You could go on to expand the rational expression into partial fractions. One way to do this:
[tex]\dfrac{5t^2 + 4t}{(2 + 5t)^2} = \dfrac{t(5t+2) + 2t}{(2+5t)^2} \\\\= \dfrac{t}{2+5t} + \dfrac{2t}{(2+5t)^2} \\\\= \dfrac15 \cdot \dfrac{t}{\frac25+t} + \dfrac{2t}{(2+5t)^2} \\\\ = \dfrac15 \cdot \dfrac{t+\frac25-\frac25}{\frac25+t} + \dfrac{2t}{(2+5t)^2} \\\\ = \dfrac15 \left(1 - \dfrac{2}{2+5t}\right) + \dfrac{2t}{(2+5t)^2} \\\\ = \dfrac15 - \dfrac{2}{10+25t}+ \dfrac{2t}{(2+5t)^2}[/tex]
and this would give
[tex]\dfrac{\mathrm dy}{\mathrm dt} = 28t - \dfrac15 + \dfrac2{10+25t} - \dfrac{2t}{(2+5t)^2}[/tex]
someone help me please
Answer:
The moon is being pulled to the earth by gravity, so the net force makes a circular pattern.
Explanation:
The force of gravity is a force that pulls objects toward the centre of the earth. The acceleration due to gravity of the moon is about 1.6 metre per second square which is comparatively smaller than the earth's 10metre per second. Therefore, the moon isn't completely pulled to the centre of the earth, but orbits around the earth
when two charged particles interact there is an ____how do the coils impact the strength of the magnetic field
when two charge particles interact
On a trip you travel at a constant speed of 50 kilometers per hour North for 1 hour. Then you turn West and travel at a constant speed of 40 kilometers per hour for 2 hours. Calculate your velocity for the trip.
43 km per hour
31 km per hour
27 km per hour West + 17 km per hour North
50 km per hour North + 40 km per hour West
Answer::27 km per hour West + 17 km per hour North
Explanation:
:27 km per hour West + 17 km per hour North
he or she is right good jod
The velocity for the trip would be 31 km per hour, therefore the correct answer is option B.
What is displacement?An object's position changes if it moves in relation to a reference frame, such as when a passenger moves to the back of an airplane or a professor moves to the right in relation to a whiteboard. Displacement describes this shift in location.
As given in the problem, on a trip you travel at a constant speed of 50 kilometers per hour North for 1 hour. Then you turn West and travel at a constant speed of 40 kilometers per hour for 2 hours.
The final displacement of the trip = √(50² + 80²)
= 94.34 kilometers
The velocity of the trip = total displacement of the trip / time period
=94.34 kilometers / 3
= 31 kilometers per hour
Thus, the velocity of the trip would be 31 kilometers per hour.
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A toy truck has a mass of 8kg. If it is moving at a velocity of 3m/s, what is it's
momentum?
Answer:
[tex]momentum =mv \\ = 8 \times 3 = 24kg.m. {s}^{ - 1} [/tex]
A train accelerates to a velocity of 500 m/s over time of 2s. The acceleration it experienced was 50m/s2. What was its initial velocity?
Explanation:
We know ,
v = u + at u = v - at u = 500 - 2*50u = 400 m/sa) The mass of a box is 250 kg. The lower surface area is 150 cm². What is the pressure exerted by the box on the surface?
[tex]\\ \sf\longmapsto Force=ma=250(10)=2500N[/tex]
Area=150cm^2=0.015m^2[tex]\\ \sf\longmapsto Pressure=\dfrac{Force}{Area}[/tex]
[tex]\\ \sf\longmapsto Pressure=\dfrac{2500}{0.015}=1.6666.6Pa[/tex]
a bus starts to move from rest . if its velocity becomes 90km/per hour after 8s. calculate its acceration .
its answers is : 3.13ms-2
Answer:
3.13m/s²
Explanation:
first convert from KM to M, 1km-1000m then convert from km/h to m/s (speed)90×1000/3600 note: 1h- 3600s
=25m/s
a=v/t
a= 25m/s ÷ 8s
a= 3.125 / 3.13m/s²
what is the instantaneous velocity at 1s.
Answer:
the average velocity between two points on the path in the limit that the time (and therefore the displacement) between the two points approaches zero.
Explanation:
Volcanic Island Arcs, such as Japan, form when a(n) __________ plate is subducted below a(n) _________________ and takes seawater with it. A rock and water mixture will break through the crust.
Volcanic Island arcs form when an oceanic tectonic plate is subducted below a tectonic plate taking seawater with it.
Volcanic island arcs occur offshore during volcanoes. They occur due to the subduction of an oceanic plate under another tectonic plate. Volcanic Island arcs occur mostly in ocean basins.
Due to the subduction of oceanic plates under tectonic plates, Island Arcs are found, mostly along the margins of continent.
Hence we can conclude that Volcanic Island arcs Form when an oceanic tectonic plate is subducted below a tectonic plate taking seawater with it.
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A wave has a speed of 150 m/s and a frequency of 60 Hz. What is the wavelength of this wave in metres?
Answer:
wavelength = 2.5 m
Explanation:
λ=. v/f
= [tex]\frac{150m/s}{60Hz} = 2.5m[/tex]
what is the force of a punch if it accelerates at 0.2m/s2 and has a mass of 2kg?
Answer:
0.4 N
Explanation:
We know ,
F = maF = 0.2 * 2 NF = 0.4NWhat science projects should I do? Please just choose something basic!
I NEED HELP I AM SO CONFUSED, WILL GIVE BRAIN.
1. What is the acceleration of a spaceship that can accelerate from 10,000 m/s to 17,500 m/s in 20 seconds?
2. How long does it take the principal to run to our classroom, if the distance is 125 meters, and he accelerates, from rest, at a rate of 4 m/s^2?
3. A pen falls off my desk. It took 1.5 seconds to fall. What was the velocity of the pen just before it hit the ground?
4. You are standing at the edge of a cliff that is 40m tall. You throw an apple down with a speed of 15 m/s. How long does it take to fall to the bottom of the cliff?
5. A stone is dropped from the roof of a building. It took 5 s for the stone to reach the ground. What is the height of the building?
6. A man is on a 30m cliff and throws a ball down with a speed of 7 m/s.
A) With what velocity does the ball hit the ground? B) How high above the ground is the ball after the ball has fallen for 1 second?
7. A watermelon is dropped from rest from the top of a 20m cliff. A) How long does the watermelon be in the air?
B) What was the watermelon’s final velocity?
The kinematic relations allow finding the results for the different questions are:
1. The acceleraations is a = 375 m/s²
2. The time is t = 62.5 s
3. The velocity at the ground is v = -14.7 m / s
4. The time to the bottoncliff is 1.7 s
5. The height isy₀ = 122.5 m
6.
A) The velocity is v = 25.2 m / s
B) The height for t=1 s is y = 18.1 m
7.
A) Time in the air is t = 2 s
B) The final veloicty is v = - 19.6 m / s
Kinematics analyzes the movement of bodies, finding relationships between the position, velocity and acceleration of bodies.
Let's look for the answers to a series of questions:
1. They indicate the initial and final velocities of the body and the time to reach it is 20 s, ask how much the acceleration is worth
Let's use the relationship
v = v₀ + a t
a = [tex]\frac{v-v_o}{t}[/tex]
a = [tex]\frac{17500-10000}{20}[/tex]
a = 375 m/s²
2. What is the time it takes to travel a distance of 125 m with an acceleration of 4 m / s²
x = v₀ t + ½ a t²
As it leaves the direction its initial velocity is zero
x = ½ to t²
t = [tex]\sqrt{\frac{2x}{a} }[/tex]
t = [tex]\sqrt{\frac{2 \ 125}{4} }[/tex]
t = 62.5 s
3. A pencil falls from a height and reaches the floor in a time of 1.5 s what is the speed when reaching the floor
v = v₀ - g t
As it is released its initial velocity is zero
v = -g t
v = - 9.8 1.5
v = -14.7 m / s
The negative sign indicates that the velocity is directed downwards.
4. From the edge of a cliff 40 m high, an apple is thrown downward with an initial velocity of 15 m / s. How long does it take to get to the bottom?
y = y₀ + v₀ t - ½ g t²
In this case the initial velocity is negative because it is directed downwards and when it reaches the floor its height is zero, let us substitute
Suppose the acceleration is g = 10 m / s²
0 = 40 - 15 t - ½ 10 t²
0 = 40 - 15 t - 5 t²
let's solve the quadratic equation
t² + 3 t - 8 = 0
t = -3 + Ts 9 + 4 8/2
t = -3 + 6. 4/2
t₁ = - 4.9 s
t₂ = 1.7 s
The time must be a positive quantity, so the correct answer is 1.7 s
5. A stone is dropped from the ceiling and it takes a time 5 s to reach the floor, which is the height of the ceiling
y = y₀ +v₀ t - ½ g t²
as it is released from the ceiling its initial velocity is zero and the height upon reaching the floor is zero
0 = y₀ + 0 - ½ g t²
y₀ = ½ g t²
y₀ = ½ 9.8 5²
y₀ = 122.5 m
6. A man at a height of 30 m throws a ball downward at 7 m / s
A) The speed when reaching the ground
B) The height of the ball when a time of 1 s has fallen.
A) Let's use the kinematics relation
v² = v₀² - 2 g (y -y₀)
v = 7² - 2 9.8 (0 -30)
v = 25.2 m / s
B) y = y₀ + v₀ t - ½ g t²
y = 30 7 1 - ½ 9.8 1²
y = 18.1 m
7. A watermelon is dropped from rest from the top of a 20m cliff.
A) time in the air
B) ground speed
A) Let's use the relation
y = y₀ + v₀ t - ½ g t²
It is released its initial velocity is zero and when it reaches the ground its height is zero (y = 0)
0 = y₀ + 0 - ½ g t²
t = [tex]\sqrt{\frac{2y_o}{g} }[/tex]
t = [tex]\sqrt{\frac{2 \ 20}{9.8} }[/tex]
t = 2 s
B) the speed when reaching the ground
v = v₀ - g t
v = 0 - 9.8 2
v = - 19.6 m / s
The negative sign indicates that the speed is down
In conclusion using the kinematic relations we can find the results for the different questions are:
1. The acceleraations is a = 375 m/s²
2. The time is t = 62.5 s
3. The velocity at the ground is v = -14.7 m / s
4. The time to the bottoncliff is 1.7 s
5. The height isy₀ = 122.5 m
6.
A) The velocity is v = 25.2 m / s
B) The height for t=1 s is y = 18.1 m
7)
A) Time in the air is t = 2 s
B) Te final veloicty is v = - 19.6 m / s
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when the speed of a moving car is doubled, how much more kinetic energy does it have?
Answer: 4 times
Explanation:
KE1 = (1/2)mv^2
KE2 = (1/2)m(2v)^2 or (1/2)m*4v^2
KE2/KE1 = ((1/2)m*4v^2)/((1/2)mv^2) = 4 times
Latitude is measured from the equator in a and a direction and what's it known as
Answer:hey can you help me answer my question please.
Explanation:
On a pirate map, “X” marks the spot. Does that “X” reference the position or the
displacement of the treasure?
Answer:
it References the position
Explanation:
Displacement is defined to be the change in position of an object.
And the treasure can't move by itself because its an object (and objects don't move).
How do I find force?
Answer:
The force formula is defined by Newton's second law of motion: Force exerted by an object equals mass times acceleration of that object: F = m×a( force = mass×area)
QUESTION 14
The sides of a small rectangular box are measured to be 1.75 +/- 0.01 cm, 7.25 +/- 0.02 cm, and 8.5 +/- 0.1 cm long. Calculate the uncertainty in its volume in cubic centimeters
A) 1.2x10^-3 cm^3
B) 0.13 cm^3
C) 2 cm^3
D)0.02 cm^3
Answer:
firts divide then multiply divide again and your and your answer should d
If y = ab, then find the maximum percentage error in the measurement of y.
Answer:
(Δa/a +Δb/b) × 100
Explanation:
Y= a/b
So, maximum percentage error
Δy/y = ( Δa/a + Δ b/b) × 100
Plz, Mark me as the brainlest
Please help with number 24
Answer:
I think its false cause with a slope you have acceleration
Aristotle supported which of these views?
A. The Sun and all the planets revolve around Earth.
B. The speed of a free-falling object is independent of its weight.
C. Earth and other planets revolve around the Sun.
D. Every action has an equal and opposite reaction.
E. The fifth element, ether, does not exist in heavenly bodies.
(PLEASE HELP ME)
Answer:
I am pretty sure that it is A. The Sun and all the planets revolve around Earth. Hope this helps!!!!!
Explanation:
How does a pedometer help people reach their fitness goals?
Answer:
Pedometers are designed to detect vertical movement at the hip and so measure the number of steps and provide an estimate of distance walked. They cannot provide information on the temporal pattern of physical activity or the time spent in different activity at different intensity.
A child throws a ball up with an initial velocity of 4
m/s. If the starting height of the ball was 2.5 meters,
what will be the height of the ball after 0.5 seconds?
Use a = -9.8 m/s/s.
The height of the ball after the given time of motion is 3.275 m.
The given parameters;
initial velocity of the ball, u = 4 m/sheight of fall of the ball, h = 2.5 mtime of motion, t = 0.5 sThe distance traveled by the ball is calculated as follows;
[tex]h =h_0 + ut - \frac{1}{2}gt^2 \\\\h = 2.5 + 4(0.5) - (0.5\times 9.8\times 0.5^2)\\\\h = 3.275 \ m[/tex]
Thus, the height of the ball after the given time of motion is 3.275 m.
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EXPLAIN: Why must you reduce friction
order to move certain objects?
Friction is one of the forces working against a moving object, it makes it harder to move the more friction is exerted on the object. So, by reducing friction, you are making it easier for you to be able to move objects.