A small town has two local high schools. High School A currently has 900 studentsand is projected to grow by 50 students each year. High School B currently has 500students and is projected to grow by 100 students each year. Let A represent thenumber of students in High School A in t years, and let B represent the number ofstudents in High School B after t years. Graph each function and determine whichhigh school is projected to have more students in 4 years.

A Small Town Has Two Local High Schools. High School A Currently Has 900 Studentsand Is Projected To

Answers

Answer 1

High School A currently has 900 students and is projected to grow by 50 students each year.

We can write an equation using the above information

[tex]A=900+50t[/tex]

Where A represents the number of students in High School A in t years.

High School B currently has 500 students and is projected to grow by 100 students each year.

We can write an equation using the above information

[tex]B=500+100t[/tex]

Where B represents the number of students in High School B in t years.

Let us graph these two equations

Determine which high school is projected to have more students in 4 years.

Let us substitute t = 4 into both equations

[tex]\begin{gathered} A=900+50t \\ A=900+50(4) \\ A=900+200 \\ A=1100 \end{gathered}[/tex]

High school A is projected to have 1100 students in 4 years.

[tex]\begin{gathered} B=500+100t \\ B=500+100(4) \\ B=500+400 \\ B=900 \end{gathered}[/tex]

High school B is projected to have 900 students in 4 years.

Therefore, high school A is projected to have more students (1100) as compared to high school B (900) in 4 years.

A Small Town Has Two Local High Schools. High School A Currently Has 900 Studentsand Is Projected To

Related Questions

Im just needing a little bit more help with these type of problems ;/

Answers

Answer:

Expected value = 2.21

Explanation:

The formula to obtain the expected value is given by:

[tex]E\mleft(X\mright)=\mu=∑xP\mleft(x\mright)[/tex]

We will proceed to calculate the given scenario as given below:

[tex]\begin{gathered} E\mleft(X\mright)=\mu=∑xP\mleft(x\mright) \\ E(X)=(1\times0.31)+(2\times0.41)+(3\times0.07)+(4\times0.18)+(5\times0.03) \\ E(X)=0.31+0.82+0.21+0.72+0.15 \\ E(X)=2.21 \\ \\ \therefore E(X)=2.21 \end{gathered}[/tex]

Therefore, the expected value of this scenario is 2.21

Lin is paid $90 for 5 hours of work. She used the following table to calculate how much she would be paid at this rate for 8 Hours of work. 1. What is the meaning of the 18 that appears in the table? 2. Explain how Lin used this table to solve the problem. 3. At this rate, how much would Lin be paid for 3 hours of work? For 2.1 hours of work. AMOUNTS EARNED ($) | TIME WORKED(hours)

Answers

Let

y ------> the amount earned

x ----> the number of hours worked

In this problem we have a direct variation

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form y=kx

where

k is the constant of proportionality

k=y/x

In this problem the value of k is hourly rate

so

we have

For y=$90 -------> x=5 hours

substitute

k=90/5

k=$18 per hour

substitute in the linear equation

y=18x

so

Part 1) What is the meaning of the 18 that appears in the table?

18 is the hourly rate ( amount earned by a one hour of work)

Part 2) Explain how Lin used this table to solve the problem.

using the table

For x=8 hours

the value of y=$144

Verify with the equation

y=18x

y=18(8)=144 -----> is ok

Part 3) At this rate, how much would Lin be paid for 3 hours of work? For 2.1 hours of work.

For x=3 hours

substitute in the equation

y=18x

substitute the value of x

y=18(3)=$54

For x=2.1 hours

y=18(2.1)=$37.8

HELP ME PLEASE!!! Question 1Jim is planning his spring garden. He will construct a rectangular gardensurrounded by a chain link fence. The length of Jim's garden will be 8 feet morethan 3 times its width (w).(Drawing and labeling a diagram may be helpful)Part A: Write an expression in terms of w to represent the amount of chain linkfencing (the perimeter) Teeded to enclose Jim's garden.

Answers

We have a rectangular garden.

The length L is 8 feet more than 3 times its width.

3 times the width is 3w, so we will add 8 to it and equal it to the length L:

[tex]L=8+3w[/tex]

The perimeter will be 2 times the length plus 2 times the width. We can write it and transform it to an expression in terms only of w:

[tex]\begin{gathered} P=2L+2w \\ P=2(8+3w)+2w \\ P=16+6w+2w \\ P=16+8w \end{gathered}[/tex]

The perimeter has a value of P=16+8w.

We can draw the diagram as:

Part B: If the perimeter of Jims garden is 88 feet, what would be the width of the garden?

We will use the equation we derived in Part A, and we have to replace P=88, in order to find w.

[tex]\begin{gathered} P=16+8w \\ 88=16+8w \\ 88-16=8w \\ 72=8w \\ w=\frac{72}{8} \\ w=9.75 \end{gathered}[/tex]

The width is 9.75 feet.

I’m trying to make a study guide and need step by step explanation on how to solve this question please

Answers

Given:

The dimension of square shape floor is 200 feet by 200 feet.

The area of the square is calculated as,

[tex]\begin{gathered} A=side^2 \\ A=200^2=40000 \end{gathered}[/tex]

Now, given that the 1/2 bottle will cover approximately 2000 quare feet.

It gives,

[tex]\begin{gathered} \frac{1}{2}\text{ bottle=2000 square f}ee\text{t} \\ 1\text{ bottle=4000 square fe}et \end{gathered}[/tex]

So, the number of bottles required are,

[tex]\frac{A}{4000}=\frac{40000}{4000}=10\text{ bottles}[/tex]

Answer: option B)

Jane is attending physical therapy after knee surgery. She walked 9 3/4 miles over 3 days. How many miles is this per day? (Simplify the answer and write it as a mixed number.)

Answers

She walked 3 1/4 miles per day.

Given,

Jane walked 9 3/4 miles in the course of 3 days.

If we calculate this mixed number into a fraction,

We get:

9 3/4 miles = {(9×4)+3} / 4 miles

=39/4 miles.

So, Jane walks 39/4 miles in 3 days.

Therefore, in one day she walked:

(39/4 ÷ 3) miles

= 13/4 miles per day

Let's now convert this fraction into a mixed number:

when 13 is divided by 4 we get the remainder as 1 and the quotient as 3.

So, a mixed number is given by:

quotient remainder/divisor

Hence 13/4 = 3 1/4.

So, Jane walked 3 1/4 miles per day.

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What is the scale factor for AXYZ to AUVW?O A1/1O B. 1/1/20OC. 2OD. 4371620A A837-105353X 6 Z12

Answers

SOLUTION:

We want to know the scale factor of the transformation from;

[tex]\Delta XYZ\rightarrow\Delta UVW[/tex]

We do this by taking ratios of corresponding sides, they should be the same in either case;

Thus , the scale factor is;

[tex]\frac{20}{10}=\frac{12}{6}=\frac{16}{8}=2[/tex]

Thus, the scale factor is 2.

Evaluate 2(x - 4) + 3x - x^2 for x = 2.O A. -6O B. -2O C. 6O D. 2

Answers

C. 6

Explanation

To evaluate an algebraic expression means to find the value of the expression when the variable is replaced by a given number.so

Step 1

given

[tex]2(x-4)+3x-x^2[/tex]

a)let

[tex]x=2[/tex]

b) now, replace and calculate

[tex]\begin{gathered} 2(x-4)+3x-x^2 \\ 2(2-4)+3(2)-(2^2) \\ 2(-2)+6-4 \\ -4+6-4 \\ -4+6-4=6 \end{gathered}[/tex]

therefore, the answer is

C. 6

I hope this helps you

Blue whales can weigh as much as 150 tons. Convert the weight to pounds.

Answers

SOLUTION:

The conversion formula from tons to pounds is;

[tex]1\text{ }US\text{ }ton=2000\text{ }pounds[/tex]

Thus, converting this to pounds, the Blue whale would weigh;

[tex]150\times2000=300,000\text{ }pounds[/tex]

Thus, the whale weighs 300,000 pounds

Answer:

The answer is C: 150/y

Step-by-step explanation:

If Omar still needs 458How much does he need after saving for 5 weeks

Answers

(a) Setting A(w)=458, we get:

[tex]800-18w=458.[/tex]

Subtracting 800 from the above equation we get:

[tex]\begin{gathered} 800-18w-800=458-800, \\ -18w=-342. \end{gathered}[/tex]

Dividing the above equation by -18 we get:

[tex]\begin{gathered} \frac{-18w}{-18}=\frac{-342}{-18}, \\ w=19. \end{gathered}[/tex]

Therefore Omar has been saving for 19 weeks.

(b) Recall that to evaluate a function at a given value, we substitute the variable by the given value.

Evaluating A(w) at w=5 we get:

[tex]A(5)=800-18\cdot5.[/tex]

Simplifying the above result we get:

[tex]\begin{gathered} A(5)=800-90 \\ =710. \end{gathered}[/tex]

Answer:

(a) 19.

(b) $710.

Is this correct?
Or please provide an explanation.

Answers

Answer:

The answer selected is correct

Step-by-step explanation:

When talking about balance, having -X (being X in the negative) , means owing X.

Dylan owes $19.25

Elise owes $42.75

Francesca owes $23

Jamaal owes $35.50

So naturally, Dylan owes the least.

y + 7x= 11; x= -1,0, 4

Answers

We have an expression with 2 unknowns, and we have values for one unknown. We have to calculate then the other unknown value:

Expression:

[tex]\begin{gathered} y+7x=11 \\ y=11-7x \end{gathered}[/tex]

Then, when x=-1

[tex]y=11-7x=11-7(-1)=11+7=18[/tex]

When x=0

[tex]y=11-7(0)=11[/tex]

When x=4

[tex]y=11-7(4)=11-28=-17[/tex]

The graph represents a quadratic function. Write an equation of the function in standard form.

Answers

A quadratic function in standard form with the given characteristics is (1/4) x² - 3x + 5.

Given that, the graph is passing through (2, 0), (10, 0) and (6, -4).

What is a quadratic function in standard form?

The standard form of a quadratic equation is given as:

ax² + bx + c = 0 where a, b, c are real numbers and a ≠ 0.

Now, the equation passes through (2, 0)

y = ax² + bx + c

0 = 4a + 2b + c  ----------------(1)

The equation passes through (6, -4)

y = ax² + bx + c

-4= 36a + 6b + c ----------------(2)

The equation passes through (10, 0)

y = ax² + bx + c

0 = 100a + 10b + c ----------------(3)

Using the Gauss elimination method to solve the system of equations we get,

a = 1/4, b = -3, and c = 5

The quadratic equation will be:

y = ax² + bx + c

y = (1/4) x² - 3x + 5

Therefore, a quadratic function in standard form with the given characteristics is (1/4) x² - 3x + 5.

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The problem is below, we know the man weighs 60, the cat weighs 10 but we’re having a hard time explaining how

Answers

Given data:

The weight of man and daughter = 90

The weight of man and cat is = 70

The weight of cat and daughter = 40 .

The man weights 60 kg.

then daughter weight = 90-60 = 30.

Thus the daughter weight is 30kg.

therefore the cat weight iwith daughter, 40-30 = 10 .

also with father, 70-60 = 10 .

Thus, the father weight is 60 kg.

The daughter weight is 30 kg and

The cat weight is 10 kg.

How do I identify the horizontal and vertical asymptotes, find several points, and graph each function?Y=4/x+3 -2

Answers

Given:

[tex]y=\frac{4}{x+3}-2[/tex]

Required:

To identify the horizontal and vertical asymptotes, and to point the graph.

Explanation:

Now the graph of the given function is

To find the horizontal asymptotes apply the limit

Virginia is going to visit 5 cities this summer. She will choose from 8 different cities and the order in which she visits the cities does not matter. How many different city combinations are possible for the summer travelling?

Answers

[tex]\begin{gathered} To\text{ choose 5 cities from 8 cites can be reprsent this way,} \\ \Rightarrow8C_5=\frac{8!}{5!\times3!}=\frac{8\times7\times6\times5!}{5!\times3\times2} \\ =56 \end{gathered}[/tex]

[tex]\begin{gathered} To\text{ choose 5 cities from 8 cites can be reprsent this way,} \\ \Rightarrow8C_5=\frac{8!}{5!\times3!}=\frac{8\times7\times6\times5!}{5!\times3\times2} \\ =56 \end{gathered}[/tex]

State the domain of the function.{-2,0, 1, 2, 3, 4){-4,0, 1, 2, 6){0, 1,2,3)(-2,4)

Answers

D= {-2,0,1, 2,3,4}

1) Considering that the Domain is the set of entries of a function, on the x-axis, and examining that graph we can state

- The lowest value for that is given by x=-2

- The highest value for that is x= 4

- The points (-2,-4) (0,0), (1,1), (2,2), (3,1) and (4,6)

2) So, we can write the set, the Domain, after examining the options as:

D= {-2,0,1, 2,3,4}

Notice that we're considering the x-coordinates

3) So the answer is D= {-2,0,1, 2,3,4}

write the following basic forms in their single form
2√3

Answers

The expression which represents the written form of the basic form expression; 2√3 as a single form is; √12.

What is the single form expression which is equivalent to the basic form expression; 2√3?

It follows from the task content that the basic form expression be written as it's equivalent single form expression.

Since the given radical expression is; 2√3; it follows that the expression can be written as a single form expression as follows;

First, the square of 2, 2² is equal to 4;

Hence, by the converse;

2 = √4.

The given expression can therefore be written as; √4 • √3.

The expression above can therefore be written in its single form as; √(4 × 3) = √12.

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Select the expressions that are equivalent to 7(7f)1. 49f2. 7(f+6f)3. f+144. f+49

Answers

ANSWER :

49f and 7(f + 6f)

EXPLANATION :

From the problem, we have :

[tex]7(7f)[/tex]

When multiplied, it will be 49f

When breaking it down, 7f is equal to f + 6f. Then it will be 7(f + 6f)

The next options f + 14 and f + 49 has two terms, so it will not be equivalent to the given expression with one term.

So the only expressions that are equivalent to the given expression are 1 and 2

What is the equation of the circle with endpoints (5,7) and (1,3)

Answers

[tex]\text{Equation of circle: }(x-3)^2+(y-5)^2=\text{ 8}[/tex]

Explanation:

endpoints (5,7) and (1,3)

The equation of circle formula:

[tex]\begin{gathered} (x-a)^2+(y-b)^2=r^2 \\ radius\text{ =r and (a, b) are the coordinates of the centre} \end{gathered}[/tex]

To find the centre(a, b), we need to find the midpoint of the two given points:

[tex]\begin{gathered} \text{Midpoint = }\frac{1}{2}(x_1+x_2),\text{ }\frac{1}{2}(y_1+y_2) \\ \text{Midpoint = 1/2(5+1), 1/2(7+3)} \\ \text{Midpoint = 3, 5} \\ \text{centre = (a, b) =(3, 5)} \end{gathered}[/tex]

The radius is the distance between the centre of the circle and any of the two points.

We will apply the distance formula:

[tex]\begin{gathered} dis\tan ce\text{ = }\sqrt[]{(y_2-y_1)^2+(x_2-x_1)^2} \\ (3,5)\text{ and (1, 3)} \\ \text{Distance =}\sqrt[]{(3-5)^2+(1-3)^2} \\ \text{Distance =}\sqrt[]{4+4} \\ \text{Distance =}\sqrt[]{8}\text{ = 2}\sqrt[]{2} \\ \text{radius = distance = 2}\sqrt[]{2} \end{gathered}[/tex]

Using the equation of circle:

[tex]\begin{gathered} (x-3)^2+(y-5)^2=(2\sqrt[]{2)}^2 \\ (2\sqrt[]{2)}^2=\text{ }2\sqrt[]{2)}\times2\sqrt[]{2)}\text{ = 4(}\sqrt[]{2})^2\text{ = 4(2) = 8} \\ (x-3)^2+(y-5)^2=\text{ 8} \end{gathered}[/tex]

Find the exact area of a circle with a diameter of 12 in., expressed in terms of n.361 square inches61 square inches14471 square inches12 square inches241 square inches< Previous

Answers

The area of a circle is given by:

[tex]A=\pi r^2[/tex]

Since the radius is half the diameter we have that r=6. Then the area is:

[tex]A=\pi(6)^2=36\pi[/tex]

Therefore, the answer is the first one.

State the domain and range for each graph and then tell if the graph is a function(write yes or no)

Answers

For the point 1)

- The domain will be: (note that this is not an interval, it is a set of two points)

[tex]\mleft\lbrace-3,2\mright\rbrace[/tex]

-The range is the set R of all real numbers (since the line extends to infinite)

-The first graph is NOT a function

For the point 2)

-The domain will be the interval

[tex](-5,5\rbrack[/tex]

-The range is the interval:

[tex]\lbrack-2,2\rbrack[/tex]

-The second graph is a function.

...........................

Answers

Solution

We have the following:

5!= 5*4*3*2= 20*3*2= 60*2= 120

A local dairy has three machines to fill half-gallon milk cartons. The machines can fill the daily quota in 3 hrs, 14 hrs, and 10.5 hrs, respectively. Find how long it takes to fill the daily quota if all three machines are running.

Answers

Answer

It will take 2 hours to fill the daily quota if all the machines are running.

Explanation

To find how long it takes to fill the daily quota if all the machines are running, we use the relation below:

Rate of machine 1 + Rate of machine 2 + Rate of machine 3 = Total rate of the machines

[tex]\begin{gathered} \Rightarrow\frac{1}{3}+\frac{1}{14}+\frac{1}{10.5}=\frac{1}{x} \\ \text{Where x is the }time\text{ it takes to fill the daily quota} \\ \frac{1}{3}+\frac{1}{14}+\frac{2}{21}=\frac{1}{x} \\ \text{Multiply all through by 42x} \\ 42x(\frac{1}{3})+42x(\frac{1}{14})+42x(\frac{2}{21})=42x(\frac{1}{x}) \\ 14x+3x+4x=42 \\ 21x=42 \\ x=\frac{42}{21} \\ x=2 \\ \text{Therefore it will take 2 hours to fill the daily quota} \end{gathered}[/tex]

In a circle with radius 8, an angle measuring radians intercepts an arc. Find thelength of the arc in simplest form.

Answers

Answer:

s = 28π/3

Explanation:

The radius, r = 8

The angle, θ = 7π/6 radian

The length of the arc, s = rθ

s = 8 x 7π/6

s = 28π/3

This chart shows the cost per pound of different fruits.

Answers

From the given data, the cost per pound of apple, CP=$1.89≈$2.

We have to estimate the cost of n=3.2≈3 pounds(lb) of apple.

The cost of n=3 lb of apple can be calculated as,

[tex]\begin{gathered} T=CP\times n \\ =2\times3\text{ lb} \\ =6 \end{gathered}[/tex]

Therefore, the cost of 3. pounds of apples is about $6.048.

个 == CR Algebra 1 B (GP) 21-22 / 8:Radical Expressions and Equations 104 6 2 -10-8-6 -4 - 2 0 N 4 6 8 10 2 -4 6 -8 -10 Match the graph with its function by translating the graph of y = Vx. 3. O y = √x-1+7 O y = x-7+1 = 7 O O y=√x+1+7 O y = x+7+1 Search the web and Windows a

Answers

SOLUTION

The transformation of the function

[tex]y=\sqrt[]{x}[/tex]

To give the graph in the question is as follows.

The graph is move to the left from the origin by 1 unit on the x-axis, which is to add 1 to x, we have

[tex]y=\sqrt[]{x+1}[/tex]

Also,

The graph is the move upward along the y-axis by 7 unit, which is addition of 7 to the function

Then, the equations becomes

[tex]y=\sqrt[]{x+1}+7[/tex]

Therefore

The function that produce the graph in the image is

y = (√x+1) + 7

What types of solutions will a quadratic equation have when the discriminant b2 − 4ac in the quadratic formula is negative?

Answers

Explanation

When the discriminant is negative, this implies that

[tex]b^2-4ac<0[/tex]

Answer: In this case, the equation has no real solutions;

If you borrow $100 for 3 years at anannual interest rate of 9%, howmuch will you pay altogether?

Answers

We are to determine the amount that you have pay back after borrowing a principal amount ( P ) for ( t ) number of years which is compounded annualy at rate ( R ).

You borrowed a principal amount of:

[tex]P\text{ = \$100}[/tex]

The time duration for which we have borrowed the money for is:

[tex]t\text{ = 3 years}[/tex]

The annual interest rate coumpounded each year is:

[tex]R\text{ = 9\% / year}[/tex]

Step 1: Determine the simple interest that accumulated at the end of ( t ) years.

The folllowing formula is used to determine the simple interest that the borrower has to pay once the period of borrowing/lending is over i.e ( t ) years.

The simple interest is the proportional rate of interest ( R ) and the initial borrowed/loaned amount called principal amount ( P ).

[tex]\text{Simple Interest ( I ) = }\frac{P\cdot R\cdot t}{100}[/tex]

Use the above simple interest formula ( I ) by plugging in the respective values as follows:

[tex]\text{Simple Interest ( I ) = }\frac{100\cdot9\cdot3}{100}\text{ = \$27}[/tex]

Therefore, the total amount of interest that the borrower must pay as an extra ( over the borrowed amount ) is $27.

Step 2: Determine the total amount that is to be returned/paid to the lender

The total amoun that is to be paid by the borrower ( you ) to the lender is the principal amount borrowed ( P ) and the amount of interest accumulated for the contractual time period i.e ( I ).

[tex]\begin{gathered} \text{Total amount to be paid = P + I} \\ \text{Total amount to be paid = \$100 + \$27} \\ \text{Total amount to be paid = }127 \end{gathered}[/tex]

Therefore, the amount that you need to pay altogether is:

[tex]\textcolor{#FF7968}{127}\text{\textcolor{#FF7968}{ dollars}}[/tex]

Find the vertical and horizontal lines that passes through the point (3,6).

Answers

We have to find the vertical and horizontal lines that passes through the point (3,6).

A vertical line will be defined as x = constant. If it passes trough a point (x,1,y1), the line will be defined as a x=x1, so the point (x1,y1) belongs to the line.

The same goes for horizontal lines, but in this case the line is defined as y = constant.

For a point (x1,y1), the horizontal line that pass through the point will be y = y1.

Then, for point (x,y)=(3,6), the vertical and horizontal lines as:

x=3 and y=6.

Answer:

Vertical line: x = 3

Horizontal line: y = 6.

The shortest side of a right triangle measures 5, and the longest side measures 13. Determine the measurement of the unknown side.

Answers

The solution that we have that would have to do with the measurement of the unknown side would be 12.

How to solve for the unknown

The Pythagoras theorem says that the length of the suym of the square of a triangle is the same as the sum of the square of the other two sides.

From the definition that we have above.

We have the shortest side as 5.

The longest side as 13

Then we would have

13² - 5² = 25 - 169

= 144

Next we would have to take the square root of 144

= √144

= 12

Hence we would say that the length of the unknown is given as 12

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