θ = 0.0090 degree is the angle does the water surface make with the horizontal
At a radius of 12.5 cm from the center, or r = 13.5 cm, a tiny container of water is positioned on a rotating carousel within a microwave oven.
Time for every rotation is 7.15 seconds.
Fc=mrω^2
Fc=mr(2 π/T^2)^2
Fc=m12.5x10^-2(2 π/7.45)^2.....(1)
Gravitational force is caused by:
Fg=mg
Fg=mx9.8........(2)
Letθ is the angle between the water's surface and the horizontal be. Equations (1) and (2) can be used to compute it as follows:
tanθ=Fc/Fg
tanθ=m12.5x10^-2(2 π/7.45)^2/mx9.8
tanθ=0.0090
θ=0.0090 degree
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Answer: The angle between the water's surface and the horizontal is = 0.0090 degrees.
Explanation: The angle between the water's surface and the horizontal is = 0.0090 degrees.
A little container of water is placed on a revolving carousel within a microwave oven at a radius of 12.5 cm from the center, or r = 13.5 cm.
7.15 seconds pass throughout each revolution.
Fc=mrω^2
Fc=mr(2 π/T^2)^2
Fc=m12.5x10^-2(2 π/7.45)^2....(1) (1)
There is a gravitational force because of:
Fg=mg
Fg=mx9.8........(2)
Take as an example the angle formed by the water's surface and the horizontal. It can be calculated using Equations (1) and (2) as follows:
tanθ=Fc/Fg
tan = (m12.5x10-2(2 /7.45)/mx9.8)
tanθ=0.0090
0.09 degrees.
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An object took 15.3 seconds to strike the ground after it was released from a certain
height. Find the height of the object just prior to being released. Round to nearest hundredths
The object took 15.3 seconds to reach the ground when released.Then the height of the object just prior to being released will be 1147 m.
What is gravity?Gravity, g of is a downward force acting on a body which is moving or at rest at positioned at a height h from the surface.
Gravity is the downward acceleration of a moving body and it have value equal to 9.8 m/s². If the time taken to hit the ground when released from a height is t, then thee equation connecting this time, height h and g is written as follows;
h = 1/2 gt².
Hence, the height of the object prior to the point of releasing is calculated as follows:
h = 1/2 9.8 m/s² × (15.3 s )²
= 1147 m.
Therefore, height of the object just prior to being released will be 1147 m.
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what fluid property is responsible for the development of the velocity boundary layer? for what kinds of fluids will there be no velocity boundary layer in a pipe?
Fluid viscosity is the property of the fluid that is responsible for the development of the velocity boundary layer. Non-viscous fluids do not exhibit the property of velocity boundary layer in a pipe.
What is fluid viscosity?
Thickness of a fluid is called its viscosity. In liquids, velocity boundary layer is formed due to viscosity.
Viscosity is also termed as the flow rate of a liquid. If a liquid has a high flow rate then its viscosity is low and vice versa.
The fluid viscosity can be measured by using viscometer. The formula to measure viscosity is F = μA. u/y
Here F is force, μ is fluid viscosity, A is the area and u/y sheer deformation rate.
On the contrary, a non-viscous fluid is one that has less thickness and can flow easily.
For example, water is a non-viscous fluid.
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a wire having mass per unit length of 0.460 g/cm carries a 2.12 a current horizontally to the south. what are the direction and magnitude of the minimum magnetic field needed to lift this wire vertically upward? magnitude
The direction and magnitude of the minimum magnetic field needed to lift this wire vertically upward is clock wise direction and 0.245T.
What is a magnetic field?The magnetic field is the area that is affected by magnetism and is located around a magnet. The magnetic field is a valuable tool for explaining the distribution of the magnetic force within and around a magnetic object in nature.
The mass per unit length of the wire = 0.460 g/cm = 0.046 kg/m
Current in the wire, A = 2.12 A (due south)
To find,
The minimal magnetic field's magnitude as well as its direction.
F = ILB = mg
B = mg/IL
B = 0.046 × 9.8 /2
B = 0.225T
B = 0.245T.
The right hand rule specifies the magnetic field's direction, which is clockwise around the wire.
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You're driving home from the grocery store at 18 m/s with a 7. 0 kg bag of groceries on the front seat when the light ahead turns red. What is the shortest distance in which you can stop, after the brakes are applied, without the groceries sliding off the seat? the static and kinetic coefficients of friction are, respectively, 0. 65 and 0. 45. Assume that the surface of the seat is horizontal
The minimum distance such that the grocery bag does not slide off when the brake force applied is 25.43 m
The grocery bag will start to slide off if the force exerted by the brake is equal to the maximum static friction force.
Let:
Fs = static friction force
F = force exerted by the brake
m = mass of the grocery bag
v = velocity
μs = static coefficients of friction
g = gravitational acceleration = 9.8 m/s²
Then,
Fs = - μs . m. g
F = m . a
Fs = F
- μs . m. g = m . a
a = μs . g = 0.65 . 9.8 = - 6.37 m/s²
With this deceleration, the distance (s) will be:
v² = u² + 2 . a. s
Where v = 0 (since vehicle stops), u = 18 m/s
0 = 18² + 2 . (- 6.37 ) . s
s = 25.43 m
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A school bus moves 200 meters in 20 seconds, and another 100 meters in the next 10 seconds.
Calculate its average speed in m/s.
Answer: 300 m/s
Explanation:
So If it moves 200 metres in 20 seconds and then another 100 metres this is changing the total distance travelled to 300 metres. Also, it moves this distance extra distance in 10 seconds therefore the total time is 30 seconds.
speed = distance / time
speed = 300 / 30
speed = 10 m/s
After travelling a total of 300 metres and spending a total of 30 seconds in motion, the school bus travels at an average speed of 10 metres per second (m/s).
To figure out how fast the school bus was going on average, we need to know how far it went and how long it took to get there.
First, we add up the two lengths the school bus travelled: 200 metres plus 100 metres equals 300 metres.
Next, we add up how long it took to go both distances: 20 seconds plus 10 seconds equals 30 seconds.
Here's how to figure out the average speed:
Average Speed = Total Distance Travelled / Total Time Spent
Putting the numbers in:
Average Speed = 300 metres in 30 seconds
10 metres per second (m/s) is the average speed.
So, the school bus's usual speed is 10 m/s.
Average speed is the general rate of movement over a certain amount of time, no matter how it changes during the trip. In this case, the bus went 300 metres in 30 seconds, which means it went 10 m/s on average.
It's important to know that instantaneous speed is not the same as usual speed. Instantaneous speed is the speed of the bus at any given time during its trip. This speed could change as the bus speeds up, slows down, or stays at the same speed.
Calculating the average speed is helpful for figuring out how well something works generally, figuring out how efficient it is, and comparing different trips or types of transportation. But it might not take into account all the details of a given trip, such as different speeds or stops along the way. For a full picture of how the bus moves, it may be necessary to think about other things.
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if you drop a baseball and let it fall, gravity from Earth pulls down on the baseball with 1.4 N of force. What is the reaction force in this situation?
A)Gravity from the ball pulls up on the Earth with 1.4 N of force.
B)Your fingers exerted an upward force of 1.4 N before they released the ball.
C)Once it hits the ground, normal force from Earth's surface will push up on the ball with 1.4 N
D)Air resistance pushes up on the ball with 1.4 N.
The reaction force in this situation occur once it hits the ground, and normal force from Earth's surface will push up on the ball with 1.4 N.
The correct answer is option (C)
What is Newton's third law of motion?Newton's third law of motion states that for every action there is equal and opposite reaction.
Mathematically, this law is given as;
Fa = Fb
where;
Fa is the force applied by object AFb is the reaction experienced by object BThe force applied by object is equal and opposite the reaction experienced by object B.
When an object placed on the floor, the weight of the object acts downward while the normal reaction of the object acts upwards.
Thus, if you drop a baseball and let it fall, gravity from Earth pulls down on the baseball with 1.4 N of force, the reaction force will occur once it hits the ground, as the normal force from Earth's surface will push up on the ball with 1.4 N.
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an object is launched from ground level with an initial speed of 24.6 meters/second at an upward angle of 0.595 radians above the horizontal (90 degrees is about 1.57 radians). how far will it travel horizontally before hitting the ground?
The object will travel 55.67 meters horizontally before hitting the ground.
The object is launched with speed 24.6 meters/second.
The angle at which the object is launched is 0.595 radians.
We know,
90° = 1.57 radians
1 radian = 90°/1.57
So,
0.595 radians = 90°(0.595)/1.57
0.595 radians = 34°
The horizontally distance R travelled by the projectile can be given by,
R = U²sin2A/g
Where, U is the initial speed,
A is the angle at which object is launched,
g is acceleration due to gravity,
Putting all the values,
R = (24.6)²sin(68°)/10
R = 55.67 meters.
The horizontal range is 55.67 meters.
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a first piece of rock which weiahs 5N, force F is applied to this first piece of rock and it produces an acceleration of a. now if there is a second rock. what force needs to be applied to the second piece of rock to produce an acceleration of 8a. mass of both rock is the same
The force that needs to be applied to the second piece of rock to produce an acceleration of 8a is 8F.
What is the relationship between the force, mass, and acceleration of an object?The relationship between the force, mass, and acceleration of an object is given in the formula below:
Force = mass * accelerationThe force on an object is directly proportional to its mass and acceleration.
However, the acceleration of an object when a constant force is applied is inversely proportional to the mass of the object.
Given two rocks that weigh 5 N each.
Force applied on the first rock, F produces an acceleration = a
F = ma
mass = constant
hence, F = a
For the second rock to have an acceleration 8a, the force applied will be:
F / a = Fx / 8a
Fx = 8 F
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a soccer ball is kicked from the ground with an initial speed of 19.5 m/s at an upward angle of 45o. a player 55m away in the direction of the kick starts running to meet the ball at that instant. what must be his average speed if he is to meet the ball just before it hits the ground?
Answer:
R = V^2 sin 2θ / g range formula
R = 19.5^2 * 1 / 9.80 = 38.8 m
Vx = 19.5 cos 45 = 13.8 m/s horizontal speed
t = R / Vx = 38.8 / 13.8 = 2.81 sec
v = (55 - 38.8) / 2.81 = 5.76 m/s (about 12.9 mph)
An elevator uses 100 000J of electrical energy to raise a load of 800 N through a height of 40m in a time of 20s. What is the rate of conversion of the electrical energy to other forms?
Therefore:
[tex]P_{out}:P_{in}=\frac{P_{out}}{P_{in}}=\frac{1600W}{5000W}=0.32[/tex]Answer:
1600W
a certain amount of work w is required to accelerate a motorcycle from rest to a speed v. how much work is required to accelerate the same motorcycle from rest up to a speed v/4?
The work required to move the motorcycle from rest to a speed of v/4 is 1/16 times of the initial work w.
As we already know, from the work energy theorem,
That work done by all the conservative forces and all the none conservative forces on the body is equal to the change in kinetic energy of that body.
So, in formula form, it can be written as,
W = ∆K
Where w is work done on the body and ∆K is the change in kinetic energy of the body.
So, if now we assume, that the work done to increase the velocity of the body from zero to V is w, then we can write,
w = 1/2mv² ..... Equation 1
m is the mass of the body.
Now, as per the question,
Let us say the work done needed to increase the speed of the body from rest to v/4 is w', then we can write,
w' = 1/2m(v/4)² ..... Equation 2
Now,
Dividing equation 2 by 1,
We get,
w'/w = 1/16
So, the value of w' is w/16.
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A 33-N force is applied to a 7-kg object to move it with a constant velocity of 6.3 m/s across a level surface. The coefficient of friction between the object and the surface is approximately ____. Round your answer to the hundredths place.(Use the approximation g ≈ 10 m/s2.)
Given:
The applied force is,
[tex]F=33\text{ N}[/tex]The mass of the object is,
[tex]m=7\text{ kg}[/tex]The constant velocity of the object is,
[tex]v=6.3\text{ m/s}[/tex]To find:
The coefficient of friction between the object and the surface
Explanation:
The object is moving with a constant velocity which means the object is under equilibrium. So, the applied force is equal to the frictional force on the object.
If the coefficient of friction between the object and the surface is
[tex]\mu[/tex]we can write the frictional force as,
[tex]f=\mu mg[/tex]For equilibrium condition,
[tex]\begin{gathered} \mu mg=F \\ \mu=\frac{F}{mg} \\ \mu=\frac{33}{7\times10} \\ \mu=0.47 \end{gathered}[/tex]Hence, the coefficient of friction between the object and the surface is 0.47.
A crate is at rest on an inclined plane. As the slope increases the crate remains at rest until the incline reaches an angle of 32.7° from the horizontal. At this angle the crate begins to slidedown the ramp.Draw a free body diagram of the crate just before it slides
The free body diagram of the crate can be shown as,
Here, N is the normal force acting on crate, mg is the weight of crate, f is the frictional force and theta is the angle of inclination of plane.
a 28 kg child is coasting at 2.0 m/s over flat ground in a 5.0 kg wagon. the child drops a 1.1 kg ball from the side of the wagon. what is the final speed (in m/s) of the child and wagon?
The final speed of the child and wagon is 2.1 m/s.
Momentum in a simple manner is an amount of motion. here amount is measurable due to the fact if an item is transferring and has mass, then it has momentum. If an object does not pass then it has no momentum. however, in normal lifestyles, it has a significance that many human beings failed to recognize it.
mass of child = 20 kg
mass of wagon = 5 kg
total mass m₁ = 25 kg
mass of ball dropped = 1.1 kg
new mass m₂ = 23.9
the initial speed of the child and wagon u₁ = 2 m/s
the final speed of the wagon = v₂
using conservation of momentum
m₁u₁ = m₂v₂
25×2 = 23.9 × v₂
final speed v₂ = 50/23.9
= 2.092 m/s
= 2.1 m/s
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which body has more internal energy - a piece of ice at a temperature of 0 degrees or from the melting of this ice at the same temperature?
The melting ice at the same temperature will have greater internal energy as compared to the ice at 0° C.
What is internal energy?
In thermodynamics, the internal energy is a quantity or state function that characterizes a substance's energy when capillary effects and other external fields, such as electric and magnetic forces, are absent. The value of the energy depends on the substance's state, not the nature of the processes that brought it to that condition, just like any other state function.
The melting ice at the same temperature will have more internal energy as compared to the ice at 0° C because during the melting of ice the intermolecular particles will absorb energy while breaking their bond and because of this, the melting ice has greater kinetic energy as well.
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Use the velocity vs time graph below for objects A and B to answer the given question.If A has the greater value pick answer choice AIf B has the greater value pick answer choice Bif A = B pick answer choice =.Which object has the greater Instantaneous Velocity at t = 5s?
Given the velocity versus time graph of an object.
From the graph, the velocity of object A is constant as the line representing its velocity is horizontal. The velocity of object a is decreasing with time. That is, object B is decelerating.
From the graph, at t=5 s the value of the instantaneous velocity of object A is 0 m/s.
And the value of the instantaneous velocity of object B is the same throughout the graph. And the value is 4 m/s.
Thus the value of the instantaneous velocity of object B is greater than that of object A.
Thus the correct answer is B has the greater value
Free-body diagrams for four situations are shown below. For each situation, determine the net force acting upon the object. Your answer must include both the magnitude and the direction of the net force vector. You should have four (4) total responses to this question (labeled A, B, C, and D).
The magnitude and direction of the net force are:
A: the net force is 3N in the downward direction,
B: the net force is zero,
C: The net force is 5N in the downward direction,
D: The net force is 4N in the right direction.
What is the net force?The net force of an object can be described as the vector sum of all the forces acting on an object. The net force is a single force that shows the same effect as the original forces on the particle's motion.
The net force becomes the resultant force. The net force has the same effect on the rotational motion as all original forces together by the object.
The mathematical expression can be written for the net force as:
[tex]\vec F_{net} = \vec F_{x} + \vec F_{y}[/tex]
For figure (A), the net force is equal to :
F = (2N - 2N) + (2N - 5N) = - 3N
So the magnitude of the force is 3N in the downward direction.
For figure (B), the net force is equal to :
F = (2N - 2N) + (5N - 5N) = 0
So the magnitude of the net force is equal to zero.
For figure (C), the net force is equal to :
F = (5N - 5N) + (5 N) = 5 N
So the magnitude of the net force is 5N in the downward direction.
For figure (D), the net force is equal to :
F = (2N - 2N) + (7N - 3N) = 4N
So the magnitude of the net force is 4N towards the right direction.
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A runner is initially going 5 m/s to the right when she slows down at to 2 m/s over 10
seconds.
a) What is her acceleration?
b) How far does she travel in these 10 seconds?
Answer:
acceleration =-0.3
distance =0.16m
Explanation:
the runner was initially moving with a velocity of 5mls and attained a final velocity of 2mls because it decelerated. therefore to find its acceleration you can go by the formula a=v-u÷t
the distance can be found by the formula v²=u²+2as
Just before Sarah started her laboratory work, she made a hot cup of tea. She left the tea on her desk while she worked because she never takes food or drink into the lab area. When she finished collecting data, Sarah's cup of tea was cool. What energy transfer caused her tea to cool?
The energy transfer between cup tea and surrounding caused her tea to cool according to newtons law of cooling.
The pace at which a body is exposed to radiation alters its temperature is roughly proportional to the temperature difference between the item and its surroundings, and the provided difference is small. The cooling law of Newton is this.
Heat is transported more quickly and a person's body temperature changes more quickly the higher the temperature difference between a system and its surroundings. When the temperature difference between the body and its surroundings is small, the rate of cooling of a body is directly related to the temperature difference and the surface area exposed.
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a woman stands near the edge of a cliff and drops a stone over the edge. exactly one second later she drops another stone. one second after that, how fast is the distance between the two stones changing?
The two stones will fall at the different time. But the difference between the time is just of one second.
The distance of the cliff is also considered. Here, the speed or velocity is asked. To calculate this we have to use the equation of motion.
There are three equations of motion.
We have;
The kinematic equation of motion that can be used is s = ut - (1/2)·gt²
For the first stone, we have, s₁ = ut₁ - (1/2)·gt₁²
For the second stone, we get; s₂ = ut₂ - (1/2)·gt₂²
g = The acceleration due to gravity ≈ 9.81 m/s²
s = The distance below the cliff top
The initial velocity of the stones, u = 0
To calculate the change of distance between the two stones,
we will subtract the two equation of motions are
s₁-s₂
With all the values kept together in the equation of motion, we can easily find the change of distance between the two stones.
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If the force of gravity acting on an object is 40N and the object has a mass of 2.8k, what is the acceleration due to gravity?
Answer:
0.07
Explanation:
2.8/40 = 0.07
1. A bike takes 9.0 seconds to decelerate to a stop over a distance of 30 meters. How fast was the bike traveling before the biker started to decelerate?
Answer:
Starting speed Vo = 6.7 m/s
Explanation:
Given:
t = 9.0 s
S = 30 m
___________
V₀ - ?
The path is numerically equal to the area of the figure lying under the velocity graph:
S = V₀* t / 2
Starting speed:
V₀ = 2*S / t = 2*30 / 9 ≈ 6.7 m/s
Two electromagnetic waves are traveling through a material. Wave 1 has a maximum electric field strength that is three times the maximum field strength of wave 2. How do the average intensities of the waves compare?.
The average intensities of the waves compare I1 = 9 x I2.
The electric field of an electromagnetic wave points in the positive y direction. At the same time, the magnetic field of this wave points in the positive z direction. In the electromagnetic field, electric and magnetic fields exist in the form of waves in horizontal and vertical patterns. To exist in this pattern requires maximum amplitude. Charged particles create electric fields.
This electric field exerts forces on other charged particles. A positive charge accelerates in the direction of the electric field, and a negative charge accelerates in the direction of the electric field. Magnetic fields are generated when charged particles move. In electromagnetic waves, the electric and magnetic fields are perpendicular to each other and both are also perpendicular to the direction of wave propagation.
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jim leaves his house and begins walking to his car in a straight line. he goes 2.0 m then returns to his house to get his keys. next, he leaves his house and travels 6.0 m to his car. what is jim's displacement?
Jim's displacement if Jim leaves his house and begins walking to his car in a straight line and he goes 2.0 m then returns to his house to get his keys, next, he leaves his house and travels 6.0 m to his car is 6 m
Δx = x2 - x1
Δx = Displacement
x2 = Final position
x1 = Initial position
Considering the house as origin,
Final position = 6 m
Initial position = 0
Δx = 6 - 0
Δx = 6 m
Displacement is the vector quantity that describes position change in a motion. Its scalar quantity distance describes the overall distance travelled during the entire motion.
Therefore, Jim's displacement is 6 m
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gravity always tries to collapse the mass of a star toward its center. what mechanism can oppose this gravitational collapse for a star? question 5 options: solar wind pressure convective movement of gases magnetic field pressure radiation pressure
Answer: The correct option is D radiation pressure.
Explanation: When gravitational force tries to collapse the star in itself, the radiation pressure coming from the gamma rays creates a force in the outward direction. This outward force hence creates equilibrium and as a result, the star remains in a stable condition.
The radiation pressure is due to the gamma rays. These rays are produced through the fusion reaction, taking place in the core of the star.
Hypothetically considering, if this radiation pressure is not present the star will eventually collapse due to its own gravity. This phenomenon is termed Gravitational Collapse.
Explain one recent idea that scientists have proposed for how the universe began. Consider the big bounce theory or the multiverse theory.
The most widely accepted theory about the universe is the big bang theory.
What is big bounce theory?The Big Bounce theory refers to the universe that is expanding and contracting, move back and forth in a big-picture timeline. The Big Bang theory was happened about 13.8 billion years ago when the universe began as a tiny, dense, ball that exploded. Many astronomers use the Big Bang theory to show how the universe began. But what caused this explosion in the first thing that is still a mystery. It has passed through many stages, which can be considered cosmological theories. The flat Earth, the geocentric model, heliocentricity, galactic centricity, the Big Bang, and the Inflationary Big Bang. In the Big Bounce theory, the universe is expanding and contracting, seesawing back and forth in a massively big-picture timeline more specific theory called "Big Bounce" theory proposes that the universe could collapse to the state where it is first started and then initiate another Big Bang.
So we can conclude that The Big Bang theory says that the universe came into being from a single more than 13 billion years ago.
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While traveling, an airplane passenger placed a bag of potato chips in his checked luggage that was placed in the baggage compartment where the air was not regulated. When he opened the luggage after landing, the bag had exploded and potato chips were everywhere in his luggage. Which gas law does this describe?.
While traveling, an airplane passenger placed a bag of potato chips in his checked luggage that was placed in the baggage compartment where the air was not regulated. When he opened the luggage after landing, the bag exploded and potato chips were everywhere in his luggage. Boyle's law explains this phenomenon.
According to Boyle's law, the volume of a gas and its pressure are inversely proportional to each other.
In a bag of potato chips, nitrogen gas is filled to prevent breakage and keep the flavor intact.
At Earth, the pressure of the gas inside the package is less than the surrounding pressure and it prevents the potato pouch from bloating up. However, at higher altitudes, pressure decreases, and the volume of the gases inside the bag expands under lower pressure and ultimately the bag explodes.
In general, when the pressure of the potato bag becomes greater than the surrounding pressure, then it explodes.
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how does heat move from the inside to the outside in the outer 30% of the sun? through neutrinos released by nuclear fusion by convection: hot gas rises and cool gas sinks by radiation: photons bounce around heating up the gas by sound waves
Heat moves from the inside to the outside in the outer 30% of the sun by hot gas rises and cool gas sinks by radiation.
Radiation is the exchange of heat vitality through space by electromagnetic radiation. Most of the electromagnetic radiation that comes to the soil from the sun is imperceptible. As it were a little parcel comes as obvious light.
Energy from the sun is exchanged through space and the earth's climate to the earth's surface. Since this vitality warms the earth's surface and environment, a few of it is or gets to be heat vitality.
Even though you're encompassed by discussion, the discussion has nothing to do with this exchange of heat.
Heat lights, that keep food warm, work in the same way. Radiation is the exchange of warm vitality through space by electromagnetic radiation. Most of the electromagnetic radiation that comes to the soil from the sun is undetectable.
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what is the tension in a tow rope that is used to accelerate a 1700-kg car at 0.5 m/s2? (ignore the effects of friction.) a) assuming the tow rope is completely horizontal? b) assuming the tow rope is 400 above the horizontal?
The tension in a tow rope,
a ) If it is completely horizontal = 850 N
b ) If it is 40° above the horizontal = 1103.9 N
F = m a
F = Net force
m = Mass
a = Acceleration
m = 1700 kg
a = 0.5 m / s²
∑ [tex]F_{x}[/tex] = m a
T = m a
T = 1700 * 0.5
T = 850 N
b ) Assuming the tow rope is 40° above the horizontal,
θ = 40°
Resolving the tension force into its horizontal component,
Tx = T cos θ
∑ [tex]F_{x}[/tex] = m [tex]a_{x}[/tex]
Tx = 1700 * 0.5
T cos 40° = 850
T = 1103.9 N
Therefore, the tension in a tow rope,
a ) If it is completely horizontal = 850 N
b ) If it is 40° above the horizontal = 1103.9 N
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145-g baseball is dropped from a tree 12.0 m above the ground. (a) with what speed would it hit the ground if air resistance could be ignored? (b) if it actually hits the ground with a speed of what is the average force of air resistance exerted on it?
The required speed is 15.35 m/s, if air resistance is ignored.
The magnitude of average force of air resistance is 1.0341N.
a) V = √2gh
The required speed is
V = √2(9.8)(12)
V = 15.35m/s
b) W = 1/2m([tex]v^{2}[/tex]-[tex]u^{2}[/tex])
W = (mg - f)h
( (0.145)(9.8) - f)12 = 1/2(0.145)(([tex]8^{2}[/tex]))
(1.421 - f)12 = 4.64
Force of an air resistance = 1.0341N
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