A skydiver is falling through the air because his:____. question 7 options: a. weight is over 100 n b. weight force down is greater than the air drag c. drag force needs to be at least 50 n because nothing can stop gravity from making an object fall

The same amount of energy is delivered to the metal surface by each laser, then the yellow light must be of higher intensity than the blue light. The yellow light must generate more electrons. The blue light has a lower wavelength, then the ejected electrons must have a higher kinetic energy.

What is meant by electrons?

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The distance of the image, given that the focal length is 15 cm and the object has a distance of 10 cm is -30 cm

The relationship between focal length, object and image distance is given by the following mirror formula:

1/f = 1/v + 1/u

Where

Using the above formula, we can obtain the distance of the image as illustrated below:

1/f = 1/v + 1/u

Rearrange

1/v = 1/f - 1/u

v = (f × u) / (u - f)

v = (15 × 10) / (10 - 15)

v = 150 / -5

v = -30 cm

Thus, we can conclude that the distance of the image is -30 cm

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1.0 m above the earth, a ball is hurled. 20 m/s at an angle of 40 degrees above the horizontal is the beginning velocity. The ball may rise 9.4 metres above the earth.

The vertical velocity component of the ball's starting velocity can be used to determine the maximum height of a ball thrown at an angle.

v iy = v 0 * sin(),

here v = 0 , initial velocity

it may be used to get the vertical component of the initial velocity.

maximum height ,  H = v iy2 / (2 * g),

where g = 9.8m/s2

H = (20 sin 40°)²/ 2 X 9.8

H = 165.27/ 19.6

H = 8.4 m

therefore, the maximum height is = 1+ 8.4m = 9.4

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The time period is not depends on the mass. So even the mass is doubled its time period not changes. The period of a simple pendulum is given by the equation T = 2π√(L/g), where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity.

A. In this equation, the mass does not appear, so doubling the mass of the pendulum does not affect the period. If the mass of the pendulum is doubled, the period of the pendulum will remain the same.

B. If the length of the pendulum's string is doubled, the period will also be doubled. The period of a simple pendulum is given by the equation T = 2π√(L/g),

where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity. Doubling the length of the pendulum increases the length by a factor of 2, which increases the period by a factor of 2.

A pendulum is a weight suspended from a pivot so that it can swing freely. The weight, also known as a bob, is the object that oscillates (moves back and forth) under the influence of gravity. Pendulums can be used to measure time, as in the case of a grandfather clock, or as a simple device to demonstrate harmonic motion.

The force acting on the pendulum is gravity, which is pulling the bob downward. This force is opposed by the tension in the string or rod that is holding the bob. The bob has kinetic energy when it is moving, and potential energy when it is at the highest or lowest point of its swing. As the bob swings back and forth, its kinetic and potential energy are constantly changing.

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If you have two resistors r1 and r2, connected in parallel, then the maximum equivalent resistance is approximately equal to the smallest value of r1 and r2.

Suppose we have two resistors r1 and r2, connected in parallel, then its equivalent resistance is:

1/r = 1/r1 + 1/r2

Notice that since it is a reciprocal equality, the maximum possible r will occur when one of 1/r1 or 1/r2 is equal to zero.

Let's assume 1/r2 = 0, then r = r1.

1/r2 = 0 will never be achieved, but for very large r2, we can expect:

1/r2 ≈ 0

It means, the possible maximum equivalent resistance is approximately equal to the smallest value of r1 and r2.

Example:

r1 = 2 Ohm, r2 = 10000 Ohm  

1/r = 1/2 + 1/10000

1/r = 5001/10000

r = 10000/5001 = 1.999  ≈  2 Ohm  ( which is approximately equivalent to r1)

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A magnetic field is created between these two charged parallel plates. The field indicates a direction from the positive plate to the negative plate.

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The recoil speed of man and rifle are 0.05 m/s and 0.0021 m/s .

(a) The recoil speed of the rifle can be found using the law of conservation of momentum. The momentum of the bullet is equal to the momentum of the rifle and the man.

Momentum of the bullet = mv = (5.0 g)(300 m/s) = 1.5 kg·m/s

Momentum of the rifle = (30.0 n)(v)

Therefore, v = 1.5 kg·m/s ÷ 30.0 n = 0.05 m/s

The recoil speed of the rifle is 0.05 m/s.

(b) The total momentum of the man and the rifle is equal to the momentum of the bullet.

Momentum of the man and rifle = mv = (700 n)(v)

Therefore, v = 1.5 kg·m/s ÷ 700 n = 0.0021 m/s

The recoil speed of the man  is 0.0021 m/s.

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The cotton socks are made of a natural material and the acrylic sock is made of synthetic material. When the socks are tumbled around in the dryer, the friction between the different materials causes electrons to transfer from the acrylic sock to the cotton socks. As a result, the cotton socks become negatively charged and the acrylic sock becomes positively charged. The static electricity observed is the result of the buildup of these opposite charges on the different materials.

Electrons are subatomic particles that carry a negative electric charge. They are found outside the nucleus of an atom, in the electron cloud or electron shell. Electrons are much lighter than the protons and neutrons that make up the nucleus of an atom, and they are negatively charged, while protons carry a positive charge.

The behavior of electrons is described by quantum mechanics. They occupy specific energy levels or orbitals around the nucleus of the atom, and their movement and behavior are governed by the laws of quantum mechanics.

Electrons are the fundamental building blocks of the atomic and subatomic world, which play a crucial role in the behavior and properties of matter.

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Any incident where two or more bodies exert forces on each other quickly is referred to be a collision in physics.

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The repulsive electrical force between two protons is 3.6 × 10³⁹ N. The result is obtained by using the formula for electrostatic.

The formula for electrostatic force is

F = kq₁q₂/r²

Where

Two protons are apart from each other in an atomic nucleus. The distance between them is 5.0 × 10⁻¹⁵ m.

Find the repulsive electrical force!

Proton has a charge of +1. So, the electrostatic force would be

F = kq₁q₂/r²

F = 9 × 10⁹(1)(1)/(5.0 × 10⁻¹⁵)²

F = (9 × 10⁹)/(2.5 × 10⁻³⁰)

F = 3.6 × 10³⁹ N

Hence, the two protos has repulsive electrical force of 3.6 × 10³⁹ N.

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The closest star to the Sun is Proxima Centauri, which is about 4.24 light-years away from the Sun. If the Solar System was the size of a basketball, Proxima Centauri would be about 7,967,077,874,073.7 miles away.

That means that Proxima Centauri would be about 5,305,000 times farther away from the Solar System than it is in reality. To put this in perspective, light travels at 186,000 miles per second. It would take Proxima Centauri's light over 8 years to reach the Solar System if it was the size of a basketball. That's over 3 thousand times longer than it would take in reality!

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The correct option: a. Not eating enough protein to synthesize proteins needed to maintain fluid balance or transport fat from the liver.

Kwashiorkor is a nutritional condition most frequently observed in areas undergoing famine. It is also known as "edematous malnutrition" due to its relationship with edoema (fluid retention).

Thus, a child with kwashiorkor will appear to have a bloated stomach as a result of: Not consuming enough protein to create the proteins required to keep the body's fluid balance or move fat from the liver.

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The electric field due to the net charge of the atomic nucleus is found to be 5 x 10⁻¹⁸ C.

The formula for the electric field is,

E = Kq/r²

K is the constant,

q is the charge of the source,

r is the distance from the center of the nucleus.

The charge on the atomic nucleus is given to be 52e and the distance is given to be 3.87 m.

Now, putting values,

E = 9 x 10⁹ x 52 x 1.67 x 10⁻¹⁹/(3.87)²

E = 5 x 10⁻¹⁸ C.

So, the electric field is found to be 5 x 10⁻¹⁸ C.

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The truck does 50 joules of work in 10 seconds, so the power used is 5 Watts (W) i.e, 5J/s (Joules per second) .

The truck does 50 joules of work in 10 seconds, so the power used is:

                    Power = 50J/10s = 5J/s (Joules per second)

                               = 5 Watts (W)

It is important to note that the power is a scalar quantity and its unit is Joules per second (J/s) or watts (W).

Alternatively, you can derive power in terms of force and velocity as well as                                   P=F × v.

Power is a measure of the rate at which work is done. It is the amount of energy that is used over time. It is a scalar quantity and it has units of Joules per second (J/s) or Watts (W). Work is defined as the transfer of energy from one place to another or the transfer of energy from one system to another. Power is a measure of how fast that work is being done. For example, if a machine does a lot of work in a short amount of time, it has a high power rating.

Power can be calculated by using the formula:

                    Power = Work / Time

Where Work is the amount of energy that is transferred and Time is the amount of time over which the work is done.

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The police officer will take 38.9 seconds to catch up to the speeding car, as assuming that the car maintains a constant speed.

The pace at which an object's velocity with regard to time changes is referred to as acceleration in mechanics. They are endogenous variables, accelerations. The direction of the total force exerted on an object determines the direction of its acceleration.

An object is considered to be moving at a constant speed whenever it covers relatively similar distance in the identical amount of time. When moving at a constant pace, an object covers a certain distance in a fixed amount of time. S = d t is a formula that can be used to express the speed.

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A car speeds past a stationary police officer while traveling 140 km/h. The officer immediately begins pursuit at a constant acceleration of 10.9 km/h/s, just as the driver passes her. A. How much time, in seconds, will it take for the police officer to catch up to the speeding car, assuming that the car maintains a constant speed?

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The acceleration of the car is 146.3 m/s². The result is obtained by using the formula for acceleration.

Acceleration is the rate of change in velocity of an object with respect to time. It can be expressed as

[tex]\bar{a} = \frac{\Delta v}{\Delta t}[/tex]

Where

A car stopped and moves with a constant acceleration. It means that the car moves from rest. We have

The change in time is

Δt = Δv/x

Δt = (v₂ - v₁)/Δx

Δt = (23.7 - 0)/146

Δt = 0,162 s

The acceleration of the car would be

[tex]\bar{a} = \frac{\Delta v}{\Delta t}[/tex]

[tex]\bar{a} = \frac{23.7 - 0}{0.162}[/tex]

[tex]\bar{a} = 146.3 m/s^{2}[/tex]

Hence, the car has an acceleration of 146.3 m/s².

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When you are pushing a book across a desk with a constant velocity, there are two forces acting on the book: friction and the force of your push.

The force of friction acts in the opposite direction to the motion of the book and opposes the motion of the book. The force of friction is caused by the interaction between the bottom surface of the book and the surface of the desk.

The force of your push acts in the same direction as the motion of the book and causes the book to move.

The y-forces on the book are not equal in magnitude, as there is only one force acting in the y-direction, which is the force of friction. The x-forces are also not equal in magnitude, as there is one force acting in the x-direction, which is the force of your push.

According to Newton's Second Law, the force acting on an object is equal to the mass of the object multiplied by its acceleration. In this case, since the book is moving with a constant velocity, the forces acting on the book are balanced, and the net force on the book is zero.

According to Newton's Third Law of Motion, for every action, there is an equal and opposite reaction. So, when you push on the book, the equal and opposite force is the force exerted by the book on your hand.

Answer:

The book is being pushed from the side meaning there are horizontal forces at work. The first is an applied force, the second is a force of friction against the motion. Since the book is moving at a constant velocity, the book is not accelerating. This means that the forces must be balanced.

Have a Nice Day :  ) .

Answer:

In Explanation

Explanation:

The transition from ocean to cloud refers to the process by which water vapour in the ocean rises and condenses into clouds. This process is known as evaporation and is a key component of the water cycle.

Evaporation occurs when the sun's energy heats the surface of the ocean, causing water molecules to gain enough energy to escape into the atmosphere as water vapour. As the water vapour rises, it cools and condenses into tiny droplets, which form clouds. The clouds can be made of water droplets or ice crystals, and they can be observed in the sky in different forms, such as stratus clouds, cumulus clouds, and cirrus clouds.

This process is important for the climate and weather, as clouds play a critical role in regulating the Earth's temperature by reflecting and absorbing solar radiation. Clouds also affect precipitation, as the droplets or crystals in the clouds grow and fall as rain or snow. The transition from ocean to the cloud is also important for the water cycle as precipitation, either in form of rain or snow, replenishes the water in the oceans and rivers.

In summary, the transition from ocean to the cloud is the process by which water vapour in the ocean rises and condenses into clouds, known as evaporation, and is a key component of the water cycle. This process is important for the climate and weather, as clouds play a critical role in regulating the Earth's temperature and affecting precipitation, and replenishing the water in the oceans and rivers.

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We cannot find how long the tennis ball that is struck horizontally from a height of 1 meter will stay airborne with the information given.

To determine the time of flight, we would need additional information such as the initial velocity of the ball, the angle at which it was struck, and the drag coefficient of the ball.

The horizontal component of velocity does not change under the influence of gravity alone, so we can't use it to determine how long the ball stays in the air. Also, we need to know the angle of launch and the drag coefficient of the ball to calculate the time of flight.

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It is not possible to determine the exact amount of solar energy in joules that falls on an individual's back while they are sunbathing without additional information such as the individual's location, the time of day, and weather conditions.

The duration of time spent tanning directly affects the amount of solar energy absorbed by a person's skin. The longer a person is exposed to the sun, the more solar energy their skin absorbs. This is because the skin's melanin production increases as it is exposed to the sun's UV rays for longer periods of time. Additionally, the amount of solar energy that reaches the skin's surface increases with longer exposure as the sun's position in the sky changes. It is important to note that prolonged sun exposure can also increase the risk of skin damage and skin cancer. Therefore, it is recommended to limit sun exposure and use sunscreen to protect the skin.

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The velocity of cart 2 will be 2.5m/s

Explain collision

A collision is a brief interaction between two or more bodies that modifies their motion due to internal forces acting between them. the forces at work during collisions (there is a change in velocity).

Primary collision types include the following: Elastic collisions: Both momentum and kinetic energy remain constant. Only momentum is conserved during inelastic collisions. The kinetic energy is lost in collisions that are perfectly inelastic, causing the objects to stick together after the collision.

Before collision :

m1 = 6kg

v1 = 3m/s

p1 = m1v1 = 3*6 = 18kg*m/s

m2 = 4kg

v2 = 4m/s

p2 = m2v2 = 4*4 = 16kg*m/s

Δp1 = p1 + p2

After collision :

m1 = 6kg

v1 = 4m/s

p1 = m1v1 = 6*4 = 24kgm/s

m2 = 4kg

v2 =?

p2 = m2v2 = 4*v2 kgm/s

Δp2 = p1 + p2

We know Δp1 = Δp2

So, 18 + 16 = 24 + 4v2

4v2 = 34-24 = 10

v2 = 10/4 = 2.5m/s .

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a) The North Pole is equal to the Earth's radius (6.371 x 10⁶ m).

b) The period of rotation is 24 hours.

c) The puck moves in a circle with a radius of zero.

d) The circle's radius would be R cos(45).

The process by which an object spins around its own axis is referred to as "rotation." The process by which an object moves around another object is referred to as a "revolution." The Earth's rotation on its own axis, for instance, is what creates the 24-hour day.

a) In the non-inertial rotating frame of the Earth, This is because objects at the poles move in circles with a radius that is equal to the Earth's. This is caused by the Earth's rotation.

b) The puck's period of rotation, or the time it takes for the puck to complete one full revolution, is approximately the length of a day. This is due to the fact that the puck moves as a result of the Earth's rotation, which takes one day to complete.

c) When moving at a speed of v toward the south on frictionless ice at the equator, the puck moves in a circle with a radius of zero. The puck would not travel in a circular path because the Earth's rotation does not cause objects to move in circles at the equator.

d) Because it is the projection of the earth's radius onto the plane perpendicular to the axis of rotation, the circle's radius would be R cos(45). The radius projected at 45 degrees latitude is shorter than the radius projected at the equator.

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The complete question is:

A puck slides with speed v on a frictionless sheet of ice at the North Pole. In the non-inertial rotating frame of the Earth the puck moves in a circle.

a) What is the radius of the circle?

b) What is the period of rotation?

c) Now let the puck slides with speed v toward the south on a frictionless sheet of ice at the equator. What is the radius of the circle?

d) Now let the puck slide with speed v toward the south on a frictionless sheet of ice a ta latitude of 45o. What is the radius of the circle?

Linear expansion refers to the increase in length of a material as its temperature increases. It is typically measured as the change in length per unit length per degree of temperature change. the answer change in length of the rod is approximately 0.014 cm.

This effect is caused by the thermal motion of the atoms or molecules in a material, which increases as the temperature increases. Linear expansion is typically a small effect, but can be significant in certain applications, such as in the construction of bridges or buildings.The change in length of the rod can be calculated using the equation for linear expansion:

ΔL = L0 * α * ΔT

Where:

L0 = initial length (20.0 cm)

α = coefficient of linear expansion for aluminum (about 2.5 x 10^-5 /°C)

ΔT = change in temperature (can be calculated by using the heat added, mass, and specific heat capacity of aluminum)

First we need to calculate ΔT, we know that c(Aluminum)= 0.90 J/g °C

ΔT= Q / (m * c)where:

Q = heat added (10000 J)

m = mass of the rod (350 g)

c = specific heat capacity of aluminum (0.90 J/g °C)

Substituting the values we have,

ΔT = 10000 J / (350 g * 0.90 J/g °C) = 28.57142857142857 °C

Now we can find the change in length,

ΔL = L0 * α * ΔT = 20.0 cm * 2.5 x 10^-5 /°C * 28.57142857142857 °C = 0.014 cm

So the change in length of the rod is approximately 0.014 cm.

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No net force is experienced. To find the magnitude of the net gravitational force exerted by the two larger masses on the 60.6 kg mass, we can use the equation for gravitational force.

Gravitational force equation:

F = G * (m1 * m2) / r^2

Where F is the gravitational force, G is the universal gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between them.

In this case, m1 = 232 kg, m2 = 538 kg and r = 0.342 m.

So, F = G * (232 kg * 538 kg) / (0.342 m)^2

Plugging in the values, we get:

F = 6.672 x 10^-11 N*(m^2)/(kg^2) * (232 kg * 538 kg) / (0.342 m)^2

The magnitude of the net gravitational force exerted by the two larger masses on the 60.6 kg mass is 0.092 N.

To find the distance at which the 60.6 kg mass experiences a net force of zero, we can use the equation for the gravitational force between two masses. Since the force is inversely proportional to the square of the distance between the masses, we can set the force to zero and solve for the distance.

F = G * (232 kg * 60.6 kg) / (r)^2 = 0

r = √((232 kg * 60.6 kg) / (G))

r = √((232 * 60.6) / (6.672 * 10^-11))

r = 2.36*10^-5 m

At this distance, the 60.6 kg mass experiences no net force from the two larger masses, as the gravitational force exerted by the 232 kg mass balances out the gravitational force exerted by the 538 kg mass.

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The magnitude of the velocity of the of the chain when 5.58m of the chain is hanging vertically is 10.46m/s.

Given the length of chain (s) = 5.58m

We know that from Newtons second law of motion :

v^2 = u^2 + 2gs where v is the final velocity, u is the initial velocity and g is the acceleration due to gravity.

Here u = 0m/s as the chain is at rest initially.

So, v^2 = 0 + 2 x 9.8 x 5.58

v^2 = 109.368

v = √109.368 = 10.46m/s

Hence the magnitude of the velocity of the of the chain = 10.46m/s.

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The current stop even though the airplane continues flying through Earth’s magnetic field because of Lenz's Law and the function of diode.

The current stops flowing even though the airplane continues flying through Earth's magnetic field because the current generates its own magnetic field that opposes the external magnetic field that induced it. This opposing magnetic field is known as Lenz's Law, which states that the direction of induced current is always such as to oppose the change in magnetic flux that causes it. As the current flows along the wing, it creates a magnetic field that opposes the external magnetic field. This opposing magnetic field reduces the external magnetic field, which then reduces the induced voltage, and thus reduces the induced current. Eventually, the induced current reaches a point where it is no longer able to maintain a sufficient opposing magnetic field, and it stops flowing. Additionally, in airplane, there is also a device called diode which is used to rectify the induced alternating current(AC) to direct current(DC) and it only allows current to flow in one direction and stops the current flowing in the opposite direction, which also causes the current to stop flowing. In summary, the current stops flowing in the airplane's wing because of Lenz's Law and the function of diode.

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After 10 seconds, the final speed is 32 m/s.After 10 seconds, the displacement is 170 m.

After 10 seconds, the object's final velocity can be calculated as follows:

Initially traveling at 2 m/s

a = 3 m/s for acceleration

Time (t) equals ten seconds.

Final velocity (v) =

v = u + at

v = 2 + (3 × 10)

v = 2 + 30

v = 32 m/s

Consequently, the object's terminal velocity is 32 m/s.

2. Methods for calculating displacement

After 10 seconds, the object's displacement can be calculated as follows:

Initial speed (u) equals 2 m/s

Final speed (v) is 32 m/s.

The speed of sound is 3 m/s2.

Relocation (s) =

v² = u² + 2as

32² = 2² + (2 × 3 × s)

1024 = 4 + 6s

assemble similar terms

1024 - 4 = 6s

1020 = 6s

6 divided by both sides

s = 1020 / 6

s = 170 m

The displacement is 170 m as a result.

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Where lighting units, cord- and plug-connected utilization equipment not fastened in place, or both, are also supplied, the overall rating of fastened-in utilization equipment, excluding luminaires, shall not be greater than 50% of the branch-circuit ampere rating.

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With a=11.43 m/s2, option 4 is the proper response. The airplane accelerates to 160+ mph in less than two seconds during a catapult launch.

The speed about which velocity decreases is known termed accelerating. Acceleration typically indicates that the speed is changing, but not necessarily. An item that is moving in a circle while maintaining a constant speed is still accelerating because the direction of its motion is shifting.

An object's velocity may alter depending on whether it is moving faster, slower, or in a different direction. The moon orbiting the earth and an apple falling to the ground are two instances of acceleration.

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The normal force acting on the block is 4.11N/0.325 = 12.68N.

Static friction is the force that opposes to the motion of an object when it is at rest. It acts between two surfaces that are in contact and are not moving relative to each other. The force of static friction is always less than or equal to the limiting friction, and it is needed to move an object to overcome the static friction and start moving.

On the other hand, kinetic friction is the force that opposes to the motion of an object when it is in motion. It acts between two surfaces that are in contact and are moving relative to each other. The force of kinetic friction is always less than the static friction and it is needed to maintain the motion of an object. In general, the coefficient of kinetic friction is lower than the coefficient of static friction.

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The normal force acting on the block is 12.68N when block is on a surface with is = 0. 325. It takes 4. 11 N to break it free from static friction.

Surface = 0.325

force = 4.11 N

Static friction =      4.11N/0.325

                                  = 12.68N.

Static friction is the force that opposes to the motion of an object when it is at rest. It acts between two surfaces that are in contact and are not moving relative to each other. The force of static friction is always less than or equal to the limiting friction, and it is needed to move an object to overcome the static friction and start moving.

On the other hand, kinetic friction is the force that opposes to the motion of an object when it is in motion. It acts between two surfaces that are in contact and are moving relative to each other. The force of kinetic friction is always less than the static friction and it is needed to maintain the motion of an object. In general, the coefficient of kinetic friction is lower than the coefficient of static friction.

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