Answer:
E_{k2}=2660 [J] kinetic energy.
Explanation:
The energy in the initial state i.e. when the rollercoaster is at the top is equal to the energy in the final state i.e. when it is at the bottom of the hill.
These states can be represented by means of the second equation.
[tex]E_{k1}+E_{p1}=E_{k2}\\160 + 2500 = E_{k2}\\E_{k2}=2660 [J][/tex]
Since the rollercoaster is located in the bottom of the hill where the potential energy level is zero, therefore there is only kinetic energy in the second state.
if the volume of a cube is 100cm3. what's the measurement of one of its length
Answer:
100 cm
Explanation:
Answer:
4.64
Explanation:
The cube root of 100 is 4.64.
Where are alkaline earth metals found on the periodic table?
Group 1
Group 2
Groups 3–12
Group 17
Answer:
B
Explanation:
Answer:
B
Explanation:
I had a feeling
When the 9-kg pendulum bob is swinging, it reaches its maximum speed at its lowest position at v = 7 m/s. calculate the pendulum bob's kinetic energy at the moment it passes the lowest position. (Round your answer to hundredth, keep two decimal digits. Fill the numerical value in the box without unit.)
A car travels 3500 m in 200 seconds what is the car speed
Answer:
17.5 m/s
Explanation:
We can calculate the meters per second by dividing the distance by time. 3500 divided by 200 is 17.5, therefore the speed is 17.5 meters per second.
Calculate the average speed of a runner who runs to for 500 meters in 40 second
Answer:
12.5
Explanation:
Suppose you are in a moving car and the motor stops running. You step on the brakes and slow the car to half speed. If you release your foot from the brakes, will the car speed up a bit, or will it continue at half speed and slow due to friction?
Answer:
See the answer below
Explanation:
If you step on the brake of a car while driving, the frictional force between the tires of the car and the surface of the road increases in opposition to the motion of the car. Consequently, the car slows down.
If you release your foot from the brake pedal when the car is still at half speed, the frictional force reduces and the car speeds up a bit even without pressing the throttle. Eventually, the frictional force will slow down and stop the car if the throttle is not pressed.
A fish is 4.7 cm from the front surface of a fish bowl of radius 21 cm. Where does the fish appear to be to someone in air viewing it from in front of the bowl? Do not forget the proper sign. (Give your answer in cm.)
______ cm
Where does the fish appear to be when it is 38.9 cm from the front surface of the bowl? (Give your answer in cm.)
______ cm
Answer:
Explanation:
From the information given:
We can properly determine the distance where the fish appear in the air viewing it from in front of the bowl by using the formula:
[tex]\dfrac{n_i}{d_o}+\dfrac{n_2}{d_1}= \dfrac{n_2-n_1}{r}[/tex]
where;
[tex]n_1[/tex] = refractive index in the air; = 1.33 &
[tex]n_2[/tex] = refractive index in water. = 1
[tex]\dfrac{n_2}{d_i}= \dfrac{n_2-n_1}{r}-\dfrac{n_1}{d_o}[/tex]
[tex]\dfrac{1}{d_i}= \dfrac{1-1.33}{-21 \ cm}-\dfrac{1.33}{4.7\ cm}[/tex]
[tex]\dfrac{1}{d_i}= - 0.26726 \ cm[/tex]
[tex]d_i =\dfrac{1}{ - 0.26726 \ cm}[/tex]
[tex]\mathbf{d_i }[/tex] = - 3.74 cm
2)
To determine where the fish appear to be when it is 38.9 cm from the front surface of the bowl by using the formula:
[tex]\dfrac{n_2}{d_i}= \dfrac{n_2-n_1}{r}-\dfrac{n_1}{d_o}[/tex]
[tex]\dfrac{1}{d_i}= \dfrac{1-1.33}{-21 \ cm}-\dfrac{1.33}{38.9\ cm}[/tex]
[tex]\dfrac{1}{d_i}=- 0.0184759 \ cm[/tex]
[tex]d_i = \dfrac{1}{- 0.0184759 \ cm}[/tex]
[tex]\mathbf{d_i = }[/tex] -54.12 cm
Integrated Science- 8th grade science
Please Help ASAP!
Its almost the end of semester And I need to fix my grade for science so PLEASE help!
its almost report cards time!
Answer:
I do believe it is A.
Explanation:
I hope this helps :)
Answer:I believe it is A
Explanation: B just doesn't seem like something an 8th grader would be learning about, and I'm not sure about the other ones.
an object with a mass of 6 kg accelerates 4 m/s2 when an unknown force is applied to it. what is the amount of the force?
Explanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question we have
force = 6 × 4
We have the final answer as
24 NHope this helps you
Answer:
24 n is the answer
In 1989 Carl Lewis established a world record when he ran the hundred meter dash in 9.92 seconds. What was his average speed (in M/S) for the race? Remember to include your data, equation, and work on solving the problem.
Answer:
10.08 m/s
Explanation:
The average speed of a body or an object can be calculated from the ratio of the total distance traveled by the body/object to that of the time taken to cover the distance.
Mathematically,
Average speed = total distance/total time
The total distance covered by Carl Lewis = 100 m
The total time taken = 9.92 s
Hence,
Average speed of Carl Lewis = 100/9.92
= 10.08 m/s
Electromagnetic radiation is emitted by accelerating charges. The rate at which energy is emitted from an accelerating charge that has charge q and acceleration a is given by dEdt=q2a26πϵ0c3 where c is the speed of light.Part AIf a proton with a kinetic energy of 5.0 MeV is traveling in a particle accelerator in a circular orbit with a radius of 0.530 m , what fraction of its energy does it radiate per second?(dE/dt)⋅1sE =
Answer:
P /K = 1,997 10⁻³⁶ s⁻¹
Explanation:
For this exercise let's start by finding the radiation emitted from the accelerator
[tex]\frac{dE}{dt}[/tex] = [tex]\frac{q^{2} a^{2} }{6\pi \epsilon_{o} c^{2} }[/tex]
the radius of the orbit is the radius of the accelerator a = r = 0.530 m
let's calculate
\frac{dE}{dt} = [(1.6 10⁻¹⁹)² 0.530²] / [6π 8.85 10⁻¹² (3 108)³]
P= \frac{dE}{dt}= 1.597 10⁻⁵⁴ W
Now let's reduce the kinetic energy to SI units
K = 5.0 10⁶ eV (1.6 10⁻¹⁹ J / 1 eV) = 8.0 10⁻¹⁹ J
the fraction of energy emitted is
P / K = 1.597 10⁻⁵⁴ / 8.0 10⁻¹⁹
P /K = 1,997 10⁻³⁶ s⁻¹
Which of the following charts correctly compares plant and animal cells?
Answer:
Wheres the charts??
Explanation:
An object starts at 16 m/s with an acceleration of 4.5 m/s? How far does it go in 9.0 seconds?
How do you compare the mass of proton, neutron, and
electron?
Answer:Explanation:
Protons and neutrons have very similar mass, while electrons are far lighter, approximately 11800 times the mass. Protons are positively charged, neutrons have no electric charge, electrons are negatively charged. The size of the charges is the same, the sign is opposite.
. If the kinetic energy is given in units of
g.cm/swhat units must the slope have?
A. g.cm/s
B. 8 cm/s?
C. s.cm/g
D. s? /(g.cm)
why is thouching the live wire of an appliane when it is connecfed to the mains dangerous
Answer: The live wire is the most dangerous one, since it is at 230 V. it should never touch the earth wire (unless the insulation is between them, of course!), because this would make a complete circuit from your mains supply to the ground (earth). A shock or fire would be highly likely.
Explanation:
How much heat in kcal is required to change 0.5 kg of ice, originally at - 10 0 * C into steam at 110 C?Constants needed in the problemLatent heat of fusion=79.7 kcal/kg Specific heat of ice=0.5 kcal/kg/K ; Latent heat of vaporization ation = 539 kcal/kg ; Specific heat of water 1.0 kcal/kg/K Specific heat of ieam=0.480 kcal/kg
Answer:
Q = 364.25 kcal
Explanation:
In this question, we will have to calculate the heat absorptions for different steps of temperature rise and phase change. And then we will ad them to calculate total heat absorbed.
1. RISE IN TEMPERATURE OF ICE:
First, the temperature of ice will be increased from - 10°C to 0 °C. Heat absorbed during this process will be given as:
Q₁ = mC₁ΔT₁
where,
Q₁ = Heat absorbed while increasing temperature of ice = ?
m = mass of ice = 0.5 kg
C₁ = specific heat of ice = 0.5 kcal/kg k
ΔT₁ = change in temperature of ice = 0 - (-10) = 10 k
Therefore,
Q₁ = (0.5 kg)(0.5 kcal/kg.k)(10)
Q₁ = 2.5 kcal
2. MELTING OF ICE:
Now, the melting of ice will occur at 0°C and the heat absorbed during this process will be:
Q₂ = m(Latent Heat of Fusion of Ice)
where,
Q₂ = heat Absorbed during melting of ice = ?
Therefore,
Q₂ = (0.5 kg)(79.7 kcal/kg)
Q₂ = 39.85 kcal
3. RISE IN TEMPERATURE OF WATER:
Now, the temperature of water will be increased from 0°C to 100 °C. Heat absorbed during this process will be given as:
Q₃ = mC₃ΔT₃
where,
Q₃ = Heat absorbed while increasing temperature of water = ?
m = mass of water = 0.5 kg
C₃ = specific heat of water = 1 kcal/kg k
ΔT₃ = change in temperature of ice = 100 - 0 = 100 k
Therefore,
Q₃ = (0.5 kg)(1 kcal/kg.k)(100 k)
Q₃ = 50 kcal
4. VAPORIZATION OF WATER:
Now, the vaporization of water will occur at 100°C and the heat absorbed during this process will be:
Q₄ = m(Latent Heat of Vaporization of Water)
where,
Q₄ = heat Absorbed during vaporization of water = ?
Therefore,
Q₄ = (0.5 kg)(539 kcal/kg)
Q₄ = 269.5 kcal
5. RISE IN TEMPERATURE OF STEAM:
Now, the temperature of steam will be increased from 100°C to 110 °C. Heat absorbed during this process will be given as:
Q₅ = mC₅ΔT₅
where,
Q₅ = Heat absorbed while increasing temperature of steam = ?
m = mass of steam = 0.5 kg
C₅ = specific heat of steam = 0.48 kcal/kg k
ΔT₅ = change in temperature of ice = 110 - 100 = 10 k
Therefore,
Q₅ = (0.5 kg)(0.48 kcal/kg.k)(10 k)
Q₅ = 2.4 kcal
Hence, the total heat absorbed to change 0.5 kg of ice at - 10°C into steam at 110°C will be:
Q = Q₁ + Q₂ + Q₃ + Q₄ + Q₅
Q = 2.5 kcal + 39.85 kcal + 50 kcal + 269.5 kcal + 2.4 kcal
Q = 364.25 kcal
Please help which one !!
Answer:
4th one
Explanation:
A 1.0 kg ball has a potential energy of 10 J and falls to the ground. What is the velocity right before it hits the ground?
a)20 m/s
b)10 m/s
c)4.5 m/s
d)15 m/s
Answer:
10m/s
Explanation:
Carbon is stored in leaves in various forms, such as sugar. When leaves decay, they lose mass. Which of the following sentences explains what happens to the carbon that is stored in leaves when they decay?
a. The carbon evaporates.
b. The carbon is destroyed as the leaves decompose.
c. The carbon is converted into nitrogen by bacteria in the soil.
d. The carbon is converted into carbon dioxide and released into the atmosphere.
Answer:either D or C
Explanation:
The carbon is converted into carbon dioxide and released into the atmosphere. therefore the correct answer is option D
What is a Chemical compound?A chemical compound is a combination of two or more either similar or dissimilar chemical elements, for example, H₂O is a chemical compound made up of two oxygen atoms and a single hydrogen atom.
These chemical compounds are formed because of different types of bonds between the constituent's elements, the chemical bonds are mainly ionic bonds, covalent bonds,s, and hydrogen bonds.
Carbon is stored in leaves in various forms, such as sugar. When leaves decay, they lose mass.
The carbon is converted into carbon dioxide and released into the atmosphere is the sentence that explains what happens to the carbon that is stored in leaves when they decay.
Thus, the carbon is converted into carbon dioxide and released into the atmosphere. the correct answer is option D.
Learn more about a chemical compound from here
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Which physical property is best measured using only a balance? A. Density B. Volume C. Color D. Mass
Answer:
D. Mass
hope it helps
Explanation:
Mass is commonly measured with a balance
Arrange Kepler's laws in order: a. The ratio of the squares of the periods of any two planets revolving around the sun is equal to the ratio of the cubes of their average distance from the sun. b. The path of each planet around the sun is an ellipse with the sun at one focus. c. As a planet moves in its orbit, a line from the sun to the planet sweeps out equal areas in equal times. a. 3, 2, 1 b. 2, 3, 1 c. 3, 1, 2 d. 1, 2, 3
Answer:
2,3,1
Explanation:
There are 3 laws of Kepler.
First law = The path of each planet around the sun is an ellipse with the sun at one focus.
Second law = As a planet moves in its orbit, a line from the sun to the planet sweeps out equal areas in equal times.
Third law = The ratio of the squares of the periods of any two planets revolving around the sun is equal to the ratio of the cubes of their average distance from the sun.
Hence, the correct order for Kepler's law is: 2,3,1
A rock has a mass of 3.1 kg. What is its weight on earth
Answer:
W = 30.38 N
Explanation:
Given that,
Mass of a rock, m = 3.1 kg
We need to find the weight of the rock on the surface of Earth. Weight of an object is given by :
W = mg
g is the acceleration due to gravity, g = 9.8 m/s²
W = 3.1 kg × 9.8 m/s²
= 30.38 N
So, the weight of the rock on the Earth is 30.38 N.
what is si unit?mention any give phisical quantities with their si unit.
The SI base units are the standard units of measurement defined by the International System held in France is called Si unit.
A football is kicked with a speed of 18 m/s at an angle of 65° to the horizontal. How far does the football travel horizontally before it hits the ground?
The horizontal distance traveled by the football is determined as 25.33 m.
Horizontal distance traveled by the football
The horizontal distance traveled by the football is calculated as follows;
X = u²sin(2θ)/g
where;
u is the initial speedg is acceleration due to gravityX = (18² x sin(2 x 65))/9.8
X = 25.33 m
Thus, the horizontal distance traveled by the football is determined as 25.33 m.
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Los muelles de un remolque están calibrados para soportar su peso, cuando se carga el remolque con 2100 kg, la fuerza ejercida es de 20580 N comprime los muelles de un remolque 5,5 cm a)Longitud que desciende el remolque si se carga con 28000 N b)Si ha descendido 4,2 cm la carga
Answer:
a) El remolque desciende 7.4 cm
b) La carga debe ser de 15715.6 N ó 1603.6 kg
Explanation:
Para los cálculos que involucren muelles, se aplica la Ley de Hooke, la cual relaciona el efecto de una Fuerza y el cambio de longitud que esta ejerce, en un resorte de elasticidad dada.
Escrito en fórmula:
[tex]F=-k \cdot \Delta L[/tex]
Donde:
F es la fuerza ejercida
k es la constante elástica del muelle
ΔL es la variación de longitud del muelle
El problema indica que al cargar 2100 kg se ejerce una fuerza de 20580 N
Esto se corrobora con la 2da ley de Newton y asumiendo una aceleración de gravedad de 9.8 [tex]\frac{m}{s^{2} }[/tex]
[tex]F_{1} =m \cdot a\\F_{1}=2100kg \cdot 9.8\frac{m}{s^2}\\F_{1}=20580N[/tex]
Esta fuerza comprime o reduce la longitud del muelle en 5.5 cm. Usando estos datos en la Ley de Hooke, podemos obtener la constante elástica k:
[tex]F=-k \cdot \Delta L\\20580N=-k \cdot (-0.055m)\\\\k=\frac{20580N}{0.055m}\\k= 374181\frac{N}{m}[/tex]
Ahora ya tenemos los datos para resolver las preguntas:
a) Longitud que desciende el remolque si se carga con 28000 NAplicando directamente la formula de la Ley de Hooke:
[tex]F=-k \cdot \Delta L\\\Delta L=\frac{F}{-k} \\\Delta L= \frac{28000N}{-374181\frac{N}{m}} \\\Delta L=-0.074 m = -7.4cm[/tex]
b) Si ha descendido 4,2 cm la cargaEn este caso debemos calcular la fuerza necesaria que haga descender el remolque 4.2cm. Nuevamente utilizando la Ley de Hooke con estos nuevos datos:
[tex]F=-k \cdot \Delta L\\F=-374181\frac{N}{m} \cdot (-0.042m)\\F=15715.6N[/tex]
Si queremos saber la carga en kilogramos:
[tex]F = m \cdot a\\m = \frac{F}{a} \\m = \frac{15715.6N}{9.8\frac{m}{s^2} }\\m= 1603.6 kg[/tex]
what makes up a atom
Answer:
They're typically made up of three main parts: protons, neutrons and electrons. Think of the protons and neutrons as together forming a “sun”, or nucleus, at the centre of the system. The electrons orbit this nucleus, like planets. If atoms are impossibly small, these subatomic particles are even more so.
Explanation:
hope i helped.
Answer:
Atoms consist of a nucleus made of protons and neutrons orbited by electrons. ... We now know that atoms are made up of three particles: protons, neutrons and electrons — which are composed of even smaller particles, such as quarks.
Explanation:
6th grade science I mark as brainliest.
Answer:
2m 13[tex]\frac{1}{3}[/tex]s
Explanation:
1.5m = 1s
200m = [tex]\frac{200}{1.5}[/tex] × 1s
= 133[tex]\frac{1}{3}[/tex]s
= 2m 13[tex]\frac{1}{3}[/tex]s
If a lever has a mechanical advantage of 5 and 50 N of force is used to lift a rock, what is the weight of the rock?
A horizontal pipe contains water at a pressure of 110 kPa flowing with a speed of 1.4 m/s. When the pipe narrows to one half its original diameter, what is (a) the speed and (b) the pressure of the water?
Answer:
a
[tex]v_2 = 5.6 \ m/s[/tex]
b
[tex]P_2 = 80600 \ Pa[/tex]
Explanation:
From the question we are told that
The pressure of the water in the pipe is [tex]P_1= 110 \ kPa = 110 *10^{3 } \ Pa[/tex]
The speed of the water is [tex]v_1 = 1.4 \ m/s[/tex]
The original area of the pipe is [tex]A_1 = \pi \frac{d^2 }{4}[/tex]
The new area of the pipe is [tex]A_2 = \pi * \frac{[\frac{d}{2} ]^2}{4} = \pi * \frac{\frac{d^2}{4} }{4} = \pi \frac{d^2}{16}[/tex]
Generally the continuity equation is mathematically represented as
[tex]A_1 * v_1 = A_2 * v_2[/tex]
Here [tex]v_2[/tex] is the new velocity
So
[tex]\pi * \frac{d^2}{4} * 1.4 = \pi * \frac{d^2}{16} * v_2[/tex]
=> [tex]\frac{d^2}{4} * 1.4 = \frac{d^2}{16} * v_2[/tex]
=> [tex]d^2 * 1.4 = \frac{d^2}{4} * v_2[/tex]
=> [tex]1.4 = 0.25 * v_2[/tex]
=> [tex]v_2 = 5.6 \ m/s[/tex]
Generally given that the height of the original pipe and the narrower pipe are the same , then we will b making use of the Bernoulli's equation for constant height to calculate the pressure
This is mathematically represented as
[tex]P_1 + \frac{1}{2} * \rho * v_1 ^2 = P_2 + \frac{1}{2} * \rho * v_2 ^2[/tex]
Here [tex]\rho[/tex] is the density of water with value [tex]\rho = 1000 \ kg /m^3[/tex]
[tex]P_2 = P_1 + \frac{1}{2} * \rho [ v_1^2 - v_2^2 ][/tex]
=> [tex]P_2 = 110 *10^{3} + \frac{1}{2} * 1000 * [ 1.4 ^2 - 5.6 ^2 ][/tex]
=> [tex]P_2 = 80600 \ Pa[/tex]