a rod with a charge of -10 is brought close to a neutral conducting sphere, which is then grounded. after a long time, the ground is removed, followed by the rod. what could be the net charge on the sphere?

The sound waves produced by the engine have a frequency of 120 Hz.

To calculate the frequency of the sound waves produced by the engine, we can use the following formula:

f = 1/T

where f is the frequency and T is the period of the sound wave.

Sound waves have a period of 8.3 milliseconds, so we can plug this value into the equation to find the frequency.

f = 1 / (8.3 x 10^-3s)

f = 120 hertz

Therefore, the sound waves produced by the engine have a frequency of 120 Hz.

It is important to note that frequency is the number of wave oscillations or cycles that occur in a unit of time and is measured in hertz (Hz). The period is the time of one oscillation and is the reciprocal of the frequency. The lower the frequency, the longer the period and vice versa.

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The coefficient of kinetic friction for that box is 0.745. You can determine from Newton second law.

As per data given:

box mass(M)= 5 kg = 5

Force required F = 40 N

First, assume μs and μk as the coefficient of static and kinetic friction. Normal reaction on the box due to the floor is given by:

N = M x g= 5 x 9.8 = 49 N

Force of static friction (fs) = μs x N = 49 x μs N

To make the box move, minimum force need has to higher then static frictional force, therefore:

fs = F = 40 N

μs x 49 = 40

μs = 0.816

Since acceleration of the box(a) = 0.7 m/s² then kinetic friction acting for the box :

force k = μk x N

force k = 49 × μk N

As per data given:

box mass(M)= 5 kg = 5

Force required F = 40 N

First, assume μs and μk as the coefficient of static and kinetic friction. Normal reaction on the box due to the floor is given by:

N = M x g= 5 x 9.8 = 49 N

Force of static friction (fs) = μs x N = 49 x μs N

To make the box move, minimum force need has to higher then static frictional force, therefore:

fs = F = 40 N

μs x 49 = 40

μs = 0.816

Since acceleration of the box(a) = 0.7 m/s² then kinetic friction acting for the box :

force k = μk x N

force k = 49 × μk N

Based on Newton's second law, we can determine μk

F − force k = M x a

40 − 49  x μk = 5 x 0.7

μk = 0.745

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To determine the speed at which the baseball player threw the ball and the height it reached, we can use the equations for motion with constant acceleration. So hence  t is the time it took for the ball to return to the player's hand.

Since the ball was thrown vertically upward and we know the time it took for it to return to the player's hand, we can use the following equation to determine the initial velocity (vₒ) of the ball: vₒ = gt . where g is the acceleration due to gravity (approximately 9.8 m/s²) and t is the time it took for the ball to return to the player's hand (3.0 s).

Plugging in the known values, we get:

vₒ = 9.8 m/s² x 3.0 s = 29.4 m/s

To determine the height the ball reached, we can use the following equation: h = vₒt + (1/2)gt²

where h is the height, vₒ is the initial velocity, t is the time it took for the ball to return to the player's hand, and g is the acceleration due to gravity.

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The resistance of two resistors are R1 is and R2 is 1.4ohms and 6.2ohms respectively where R1 is smaller and R2 is larger resistance.

Given the voltage of battery (V) = 12V

Let the resistance of smaller resistor = R1

Let the resistance of larger resistor = R2

The current in circuit when connected in parallel (Is) = 1.57A

Ohms law states that V = IR where V is voltage R is resistance and I is current.

When resistors are connected in series Rs = R1 + R2

V =Is(R1 + R2)

R1 + R2 = 12/1.57 = 7.6

R1 = 7.6 - R2

When resistors are connected in parallel 1/Rp = 1/R1 + 1/R2

then Rp = R1R2/R1 + R2

The current in parallel circuit (Ip) = 10.5A

V = Ip(R1R2/R1+R2)

R1R2 = 12 x (7.6) / 10.5 = 8.68

(7.6 - R2)R2 = 8.68

R2^2-7.6R2+8.68 = 0

R2 = 6.2ohm

R1 = 7.6 - 6.2 = 1.4ohms

Hence the smaller resistance is 1.4ohms and larger resistance is 6.2ohms.

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Pressure acts in all direction .

What is the fundamental meaning of pressure?

The amount of force applied to a unit area is referred to as pressure. The weight of the water column above contributes to the pressure in a liquid. This pressure works in all directions because a liquid's particles are closely packed. For instance, the pressure exerted on a dam at a reservoir's bottom is larger than the pressure exerted near the top.

There is a magnitude to pressure, but no accompanying direction. At one location inside a gas, pressure spreads out in all directions. The pressure force acts perpendicular to the surface at a gas's surface.

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The measure of the angle of descent should be 2.15° from the horizontal line of sight, if the altitude of the plane is 7.5 km above the ground.

The Altitude of the plane above the ground, h = 7.5 km

The straight line distance of the landing place from the airplane, d = 200 km

For the decent landing of the airplane, there should not be an steep angle of landing. We know tanθ = Height/base

tanθ = h/d

So the descent angle will be tan⁻¹(h/d)

So, tan⁻¹(7.5/200)

θ = 2.1475 ≈ 2.15°

So, θ = 2.15°

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The speed of the wave is 2 m/s. The wavelength of the wave is 0.228 meters. The frequency of the waves are 1 × 10¹⁶ Hz and 1.5 × 10¹³ Hz, respectively.

Wave speed relates to the speed of a wave to the wavelength and frequency of the wave. When the wavelength and the frequency of the wave are known to us, then this equation can be used to calculate the wave speed. The frequency of a wave is the number of waves which move in one second.

5. Speed of wave = wavelength × Frequency

Speed of wave = 20 × 0.1

Speed of wave = 2 m/s

6. Wavelength = Speed/ Frequency of wave

Wavelength = 343/ 1500

Wavelength = 0.228 meters

7. Frequency = Speed/ wavelength of the wave

Frequency = 3 × 10⁸/ 3 × 10⁻⁸

Frequency = 1 × 10¹⁶ Hz

8. Frequency = Speed of light/ Wavelength of the light wave

Frequency = 3 × 10⁸/ 2 × 10⁻⁵

Frequency = 1.5 × 10¹³ Hz

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Motion of the bones relative to the three cardinal planes is known as osteokinematic motion, which is resulting from physiological movement.

Osteokinematics describes clear and smooth movements of those bones which are visible from the outside. They are the gross movement that occurs between two bones. They are generated from the rotation around the joint axis. Movement is generaly rotational around the joints.

There are some examples of Osteokinematics are:

Flexion and extension

Abduction and adduction

Lateral rotation and medial rotation

Osteokinematics are different from arthrokinematics. In general Osteokinematics is the bone movement and Arthrokinematics is the joint movement.

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The correct option d. The small divisions at the end of each scale. This allows for the scaling or measurement of a 1'4" distance.

For structures and buildings, architect scales like 1/4" = 1'0" (1/48 size) or 1/8" = 1'0" (1/96 size) are employed.

Thus,  the minuscule divisions at each scale's tip. This makes it possible to scale or measure a 1'4" distance.

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The complete question is-

On the 1/4" = 1'0" architect 's scale, what makes it possible to scale or measure a distance of 1'4"?

Select one:

a. Use the 1/8" scale and convert.

b. Use the 1/16" scale and convert.

c. The large divisions at the end of the scale.

d. The small divisions at the end of each scale.

The correct answer is A: thick glass, narrow bore. This design allows the thermometer to have a high sensitivity and to respond quickly to changes in temperature.

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Answer:

Question 1: the two controlled variables are "initial mass of ice" and "initial surface area of ice".

Questions 2: it's "mass of the water after the ice has melted" and "time for the ice to melt completely"

The statement that best compares potential and kinetic energy is that Kinetic energy increases and potential energy decreases when the velocity of an object increases. That is option B.

Kinetic energy is defined as the type of energy that is being possessed by a body that is in constant motion.

Potential energy is defined as the type of energy that is stored within a body as it remains in a steady state.

Velocity is defined as the distance covered by an object with respect to time.

Therefore, the major difference between a kinetic energy and potential energy is that Kinetic energy increases and potential energy decreases when the velocity of an object increases.

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They travel back and forth parallel to the path that the wave is moving

A transverse wave is a motion in which every point on the wave oscillates along a route that is perpendicular to the wave's forward motion. Transverse waves include electromagnetic (such as radio and light) waves, seismic S (secondary) waves, and surface ripples on water.

In a transverse wave, the medium's particles move perpendicular to the wave's path. Peaks and valleys, referred to as crests and troughs, are features of transverse waves. The medium's particles move parallel to the wave's direction of travel during a longitudinal wave.

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One of the Milankovitch cycles is the changes in the Earth's tilt.

Option C.

The Milankovitch cycles are cycles that relates the Earth motions and long-term climate change  and they include the following:

Thus, we can conclude that one of the Milankovitch cycles must relate to the changes in the Earth's tilt or  the angle Earth's axis is tilted with respect to Earth's orbital plane, known as obliquity.

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The two appropriate factors that can assist in determining air pressure are wind, speed and air temperature. The appropriate choices are A) and C).

Everything you touch is pressed upon by the weighty air that surrounds you. The term air pressure or atmospheric pressure is used to describe this pressure. When a surface is being pulled toward Earth by gravity, air above the surface exerts a force on it. It is common practise to measure atmospheric pressure using a barometer.

Because air pressure is determined by the quantity of molecules above a surface, this is the case. It's interesting to note that as the number of molecules grow, more pressure is applied to a surface, increasing the overall air pressure. In contrast, when the number of molecules falls, the air pressure rises.

The average kinetic energy of the gas's molecules directly relates to its temperature. Faster moving particles will more frequently and violently hit with the container walls.

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Answer:

  75 J

Explanation:

You want the work done by a force of 25N over a distance of 3 m.

As your formula tells you, the work is the product of force and distance:

  W = Fd

  W = (25 N)(3 m) = 75 N·m

One newton·meter is one Joule.

  = 75 J

__

Additional comment

Both newtons (N) and joules (J) are derived SI units:

  1 N = 1 kg·m/s²

  1 J = 1 kg·m²/s² = 1 N·m

Formula for work:

[tex]w=Fd[/tex]

work(measured in joules) = force(measured in newtons) * distance(measured in meters)

__________________________________________________________

Given:

[tex]F=25N[/tex]

[tex]d=3m[/tex]

[tex]w=?[/tex]

__________________________________________________________

Finding work:

[tex]w=Fd[/tex]

[tex]w=25\times3[/tex]

__________________________________________________________

Answer:

[tex]\fbox{w = 75 Joules}[/tex]

The ball drops quicker as a result of the topspin, which might make it more challenging for the opponent to strike the ball at the appropriate moment. Topspin may be used to produce shots that are more difficult to return because of this.

Generally, The Magnus effect is caused by the difference in air pressure on the top and bottom of a spinning object.

On a ball with a topspin, the air pressure is greater on the top of the ball than on the bottom, which creates a lifting force that causes the ball to move upward.

This can cause the ball to have more height or to curve in a specific direction, making it more difficult for the opponent to return.

The topspin also causes the ball to drop faster than it would otherwise, which can make it more difficult for the opponent to hit the ball at the right time. This makes topspin a useful tool for making shots that are harder to return.

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Answer:

D. Smog

Explanation:

The phenomenon caused by the excessive release of smoke by factories, burning garbage, and vehicles is known as smog.

No. Perhaps the best remedy for a flooded engine is time. Simply open the hood of your car and let excessive fuel evaporate for as long as you can. After about 20 minutes try starting your car again without hitting the gas pedal. If this still does not work, you may have to check your spark plugs.

Why won’t your car start. It turns over, so there’s no problem with the battery, but it won’t fire. Chances are, if you've just started it, moved it a few metres and shut it off again, you've flooded the engine – this is really common as we sometimes want to move a car under the car port, into some shade or into a better parking spot, but without driving it any more than a few metres.

Flooding the engine has nothing to do with water, but the amount of fuel that’s been introduced into the engine. It rarely happens with modern, fuel-injected cars if the temperatures are normal. If it’s cold or very hot it can happen, too.

Don’t keep letting it turn over because you’ll wear out the battery and you’re making the flooding worse (so much so, that you might have so much petrol in the cylinders that it seeps into the oil). Also, don’t pump the accelerator as this can make the flooding worse.

A flooded engine has too much petrol and not enough oxygen. This wets the ends of the spark plugs and they won’t ignite the fuel

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A graphical representation of data is a method of presenting two sets of data visually using a graph.The graph shows two entities, one on the x-axis and the other on the y-axis.

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The location of the center of mass of the three objects is 0.237 m from the pivot to the 50 kg kid side when two kids sit at the ends of a teeter-totter one has a mass of 50kg and the other has a mass of 35 kg the teeter-totter is 3m long and has a mass of 10kg.

Let x=0 be the pivot point of the teeter-totter

and a kid is sitting at x1 = -1.5 m with mass m1 = 50 kg

another kid is sitting at x2 = 1.5 m with mass m2 = 35 kg

mass of teeter-totter, m = 10 kg

Now, the center of mass = [tex]\frac{m1x1+m2x2+mx0}{m1+m2+m}[/tex]

or COM = (-1.5x50 + 1.5x35 + 0)/(50+35+10)

COM = - 22.5/95 = - 0.237 m

Therefore, the location of the center of mass of the three objects is 0.237 m from the pivot to the 50 kg kid side when two kids sit at the ends of a teeter-totter one has a mass of 50kg and the other has a mass of 35 kg the teeter-totter is 3m long and has a mass of 10kg.

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if throughout this period 109 photons impact on the detector. The radiation has a frequency of 2.5*1014 Hz. Gamma radiation is this kind of electromagnetic radiation.

The equation: may be used to determine the radiation's frequency.

Frequency equals the sum of the photons (time)

The frequency in this instance is:

109 photons divided by 40 x 10-3 seconds equals 2.725 x 1011 Hz as the frequency.

Due to the extremely high frequency, it is most likely gamma rays, a form of electromagnetic radiation. Gamma rays, which are often created by the decay of radioactive materials or nuclear processes, contain the greatest energy and the shortest wavelength of all known kinds of electromagnetic radiation. They may also result from other high-energy astrophysical phenomena, such as cosmic rays.

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Answer:

The angle of incidence of a wave is always equal to the angle of reflection.

Explanation:

1. The angle of incidence is the angle made by the incident ray with the  surface and the line perpendicular to the surface.

2. The angle of reflection is the angle between the reflected ray and the perpendicular to the surface.

3. A wave is an energetic disturbance in a medium without any movement of particles.

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7.2 gallons of oil is needed to generate the electricity needed to keep 100-watt light bulb lit for one year if the overall efficiency of generating station is 30%.

Ratio of the work performed by machine or in process to the total energy expended / heat consumed is called as efficiency.

Energy consumed is 100 W * 8760 h = 876,000 Wh = 876 kWh.

Given, overall efficiency of the generating station is 30%, which means that only 30% of energy in the fuel is converted into usable electricity. So, for every 1 unit of energy in fuel, 0.3 units of energy are generated as electricity.

To find out how much oil is needed, we need to divide total energy consumed by the light bulb (876 kWh) by the overall efficiency of the generating station (0.3). So, 876 kWh / 0.3 = 2920 kWh

Now we need to convert the energy consumption in kWh to gallons of oil,

2920 kWh = 2920 * 3412 Btu/kWh = 1,000,944 Btu

1,000,944 Btu / 138,690 Btu/gal = 7.2 gallons

Therefore, 7.2 gallons of oil is needed to generate the electricity needed to keep 100-watt light bulb lit for one year.

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U=GM m /r is the formula for the potential energy of a system that includes the Earth and an object orbiting the planet.

U=GM m /r is the formula for the potential energy of a system that includes the Earth and an object orbiting the planet.

G stands for gravity constant.

The Earth's mass is M.

m is the object's mass.

r is the separation between the item and the center of the Earth.

Here it is:

M = 5.98-10(24) kg, where m = 102 kg is the object's mass.

The object's distance from the center of the Earth is given by the formula r = 2R.

is the radius of the Earth

when substituting

U = -3.19 - 10 (9) J

The object's combined potential and kinetic energies make up its total mechanical energy:

where

the mechanical energy is E.

The potential energy is U.

K stands for kinetic energy.

E = U +K

E = 0 in this case because we want the item to have no energy, which results in kinetic energy of K = -U = 3.19- 10 (9) J.

The object's kinetic energy can be represented as where m = 102 kg is its mass and v is its speed.

And solving for v, we find:

r = 7909 m/s

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The truck life cycle from conception through obsolescence is referred to as the life cycle of a vehicle. Research and development are the first steps in the initial product development for the automobile (R&D).

It ends with the removal of the product from sale (discontinued). Utilizing this process allows for the retention and growth phases of the employee lifespan. Employee retention is aided and opportunities for career progression are presented by a great onboarding experience. The new hire should be introduced to the appropriate departments and coworkers. Your business begins to carve out a distinct position in the market during the growth phase of the business life cycle. Your customers and your business strategy begin to gain traction.

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Magntude of the eltric field at radial distances is 12.8a^2.

V = 4/3 r3, where V stands for volume and r for radius, is the equation for a sphere's volume. Half the diameter makes up a sphere's radius.

A conducting sphere has no electric field inside of it. In the same way as a point charge, the electric field outside the sphere is determined by the equation E = kQ/r2. On the outside of the sphere, there is an extra charge.

The curved surface area of the sphere is equal to its entire area because it has a completely curved shape. Alternatively, it is known as lateral surface area. Sphere's radius (r) and its surface area (a) are both expressed as 4r2.

Explanation:

2*2a*2.4a =r =9.6a^2

V = 4/3 *9.6a^2 = 1.3334 * 9.6a^2 = 12.8a^2.

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The pressure as compared to atmospheric pressure is known as gauge pressure. Gauge pressure is positive for pressures higher than atmospheric pressure. Gauge pressure is negative for pressures below atmospheric pressure.

Pg denotes gauge pressure, which is related to absolute pressure as follows: Pa is the local atmospheric pressure, and pg is equal to p - pa. Example: 32.0 psi is the tire pressure as measured by an automobile tire gauge. 14.2 psi is the atmospheric pressure in the area.

Two objects that are in contact with one another are under pressure. The pressure distribution across the entire contact area is known as the pressure profile.

This type of reading is simply known as "gauge pressure" since the majority of gauges measure pressure relative to atmospheric pressure, which serves as the zero point. However, anything that is not a complete vacuum is considered to be under some type of pressure.

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