A reservoir has a surface area of and an average depth of 40. 0 m. What mass of water is held behind the dam? (See
Figure 11. 5 for a view of a large reservoir—the Three Gorges Dam site on the Yangtze River in central China. )
Answers
The density of water ρ from Table 1 is [tex]1.000 * 10^{3} kg / m^{3}[/tex] . Subbing V and ρ into the expression for mass gives:m= [tex]V=Ah=(50.0km^{2} )(40.0m)\\=[(50km^{2} ) (\frac{10^{3}m }{1km} )^2] (40.0m) = 2.00 * 10^{9} m^{3}[/tex]
We can ascertain the volume V of the supply from its aspects, and track down the density of water ρ in Table 1. Then, at that point, the mass m can be tracked down in the meaning of density.
[tex]p =\frac{m}{v}[/tex]
Tackling condition ρ = m/V for m gives m=ρV.
The volume V of the supply is its surface region Multiple times its typical profundity h:
[tex]V=Ah=(50.0km^{2} )(40.0m)\\=[(50km^{2} ) (\frac{10^{3}m }{1km} )^2] (40.0m) = 2.00 * 10^{9} m^{3}[/tex]
The density of water ρ from Table 1 is [tex]1.000 * 10^{3} kg / m^{3}[/tex] .
Subbing V and ρ into the expression for mass gives:
[tex]m= (1.00 * 10^3kg / m^3) (2.00* 10^9m^3) \\ = 2.00 * 10^{12} kg[/tex]
An enormous supply contains an extremely huge mass of water. In this model, the heaviness of the water in the repository is mg=1.96× [tex]10^{13}[/tex] N, where g is the speed increase because of the Earth's gravity (around 9.80[tex]m/s^{2}[/tex] ). It is sensible to find out if the dam should supply a power equivalent to this colossal weight. The response is no. As we will find in the accompanying segments, the power the dam should supply can be a lot more modest than the heaviness of the water it keeps down.
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the complete question is:
A reservoir has a surface area of [tex]50.0 km^{2}[/tex] and an average depth of 40.0 m. What mass of water is held behind the dam? (See Figure 2 for a view of a large reservoir—the Three Gorges Dam site on the Yangtze River in central China.)
Related Questions
The energy (E) of photon depends upon its wavelngth 'λ' , Planck's constant ' h ' and velocity
' c'. Derive the formula for energy using dimensional analysis
Answers
The formula for energy of a photon in terms of its wavelength, Planck's constant, and the speed of light is:
E = (hc)/λ
We can use dimensional analysis to derive the formula for energy of a photon in terms of its wavelength, Planck's constant, and the speed of light.
A photon's energy can be written as:
E = f × h
where
f is the frequency of the photon and h is Planck's constant.
We know that the frequency of a photon is related to its wavelength and the speed of light by the following equation:
f = c/λ
where c is the speed of light and λ is the wavelength.
Substituting this expression for f into the equation for energy, we get:
E = (c/λ) × h
Now let's check the dimensions of each term in this expression using brackets [] to represent dimensions:
[c/λ] = [L/T] / [L] =[tex][T^{-1} ][/tex]
[h] = [[tex]M L^2 T^{-1}[/tex]]
Therefore, the dimensions of the product (c/λ) × h are:
[tex][T^{-1} ] \times [M L^2 T^{-1} ] = [M L^2 T^{-2} ][/tex]
This is the dimension of energy (which can be expressed as[tex][M L^2 T^{-2} ]).[/tex]
Therefore, we can conclude that the formula for energy of a photon in terms of its wavelength, Planck's constant, and the speed of light is:
E = (hc)/λ
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What is the electric field strength between two parallel charged plates that are 3.50 cm apart and have a potential difference of 18.0 V?
Answers
The electric field strength between the two parallel charged plates is 514.29 V/m.
How do you determine the electric field strength between two parallel charged plates?The electric field strength (E) between two parallel charged plates can be determined using the formula:
E = V / d
where V is the potential difference (in volts) between the plates, and d is the distance (in meters) separating them.
In this case, the potential difference V is 18.0 V and the distance d is 3.50 cm. First, we need to convert the distance from centimeters to meters:
d = 3.50 cm x (1 m / 100 cm) = 0.035 m
Now we can calculate the electric field strength:
E = 18.0 V / 0.035 m = 514.29 V/m
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Part (A) A light, rigid rod of length
ℓ = 1. 00 m
joins two particles, with masses
m1 = 4. 00 kg
m2 = 3. 00 kg
at its ends. The combination rotates in the xy-plane about a pivot through the center of the rod. Determine the angular momentum of the system about the origin when the speed of each particle is 6. 40 m/s.
I got the answer to be 22. 4 with a +z direction.
Part (B) What would be the new angular momentum of the system (in kg · m2/s) if each of the masses were instead a solid sphere 10. 5 cm in diameter?
I'm not sure how this changes the equation. All my attempts are incorrect so far
Answers
In Part A, the angular momentum of the system about the origin can be calculated using the formula:
L = r × p, where r is the position vector from the origin to the center of mass of the system, and p is the linear momentum of the system. In this case, since the system is rotating in the xy-plane about the origin, the angular momentum is in the +z direction. The position vector r is perpendicular to the plane of rotation and has a magnitude of ℓ/2. The linear momentum of each particle is mvi, where vi is the speed of the particle. Using this information, we can calculate the angular momentum of the system as: L = (ℓ/2) × (m1v1 - m2v2). Substituting the given values, we get: L = (1/2) × (4.00 kg × 6.40 m/s - 3.00 kg × 6.40 m/s) = 22.4 kg·m^2/s. In Part B, we need to find the new angular momentum of the system if each of the masses were instead a solid sphere 10.5 cm in diameter. In this case, we can assume that the spheres rotate about their own center of mass. The moment of inertia of each sphere can be calculated using the formula for the moment of inertia of a solid sphere: I = (2/5) × mr^2, where m is the mass of the sphere and r is the radius of the sphere. Substituting the given values, we get: I = (2/5) × (m/4π) × (10.5/200)^2, where m = 4.00 kg for one sphere and m = 3.00 kg for the other sphere. The total moment of inertia of the system can be found by adding the moments of inertia of the two spheres. We can then use the formula for the angular momentum of a rotating object: L = Iω, where ω is the angular velocity of the system. However, we do not have enough information to find the angular velocity ω. Therefore, we cannot find the new angular momentum of the system with the given information.
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A bowl is shaped like a hemisphere with diameter 76 cm. A heavy ball with diameter 8 cm is placed in the bowl and water is poured into the bowl to a depth of h centimeters. Find the volume v of water in the bowl. (consider two cases: one in which the ball is not completely submerged and the other in which it is. )
Answers
The volume of water in the bowl is then:
v = (2/3)π(38)^3 - (1/3)π(h - 4)^2(3h + 8) - 256π/3 Case 1: The ball is not completely submerged
The volume of water displaced by the ball is equal to the volume of the ball. The radius of the ball is 4 cm, so its volume is (4/3)π(4)^3 = 256π/3 cm^3. The height of the water in the bowl is h - 4 cm, where h is the total height of the water and the ball. The volume of water in the bowl is given by the formula for the volume of a hemisphere with radius 38 cm minus the volume of the spherical segment cut off by the water level: v = (2/3)π(38)^3 - (1/3)π(h - 4)^2(3h + 8). The volume of water in the bowl is then:
v = (2/3)π(38)^3 - (1/3)π(h - 4)^2(3h + 8) - 256π/3
Case 2: The ball is completely submerged
In this case, the volume of water displaced by the ball is equal to the volume of the ball. The height of the water in the bowl is h, so the radius of the water level is (38^2 - 4^2)^(1/2) = 37.83 cm (by the Pythagorean theorem). The volume of water in the bowl is then the volume of a spherical cap with radius 37.83 cm and height h, minus the volume of the ball:
v = (1/3)πh^2(3(37.83) - h) - (4/3)π(4)^3
Note that the volume of the ball is the same in both cases, but the volume of water in the bowl is different.
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A man is attempting to lift a crate using a two part pulley system as shown in the image. The crate has mass m2 = 53 kg, and the man has m1 = 75 kg. He pulls downward on the rope with a force of magnitude F = 659 N. The pulleys are massless and frictionless.1.) Using T to describe the magnitude of the tension force, write an expression for the sum of the forces in the y direction acting on the crate, in terms of gravity and the variables provided.2.) what is the blocks acceleration in m/s^2?
Answers
1.) The sum of the forces in the y direction acting on the crate is given by the equation: F_y = m2g - T, where m2 is the mass of the crate, g is the gravitational acceleration (9.81 m/s^2), and T is the tension force.
2.) The acceleration of the block is given by the equation: a = F/m2 = 659 N / 53 kg = 12.4 m/s^2.
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How far will the driver be behind the vehicle in front at 30mph ? Give your answer to 2 significant figures
Answers
The driver should be at least 39 meters behind the vehicle in front at 30mph. Rounded to 2 significant figures, this is 39 meters.
Meters are a unit of length used in the International System of Units (SI) to measure distance or displacement. A meter is defined as the length of the path traveled by light in a vacuum during a time interval of 1/299,792,458 of a second. This definition provides a precise and universal standard for the measurement of length, as the speed of light is constant and independent of the observer.
Meters are commonly used to measure the length or width of objects, as well as the distance between two points. They are also used in scientific fields such as physics, where they are used to measure quantities such as wavelength and amplitude.
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6. A student placed a cardboard box at the
bottom of a hill. The student then released a
ball from a point on the hill. The ball collided
with the box, and the box moved a distance
of 2 meters before both the box and the ball
came to rest. Which change to the initial
conditions would be most likfly to result in
the box moving a greater distance?
A. Decreasing the mass of both the ball and the
box
B. Decreasing the mass of the ball and
increasing the mass of the box
C. Increasing the mass of the ball and
releasing it from a lower point on the hill
D. Decreasing the mass of the box and
releasing the ball from a higher point on
the hill
Answers
The correct option for the given question is D. Decreasing the mass of the box and releasing the ball from a higher point on the hill.
A cardboard box was placed at the bottom of a hill, and a ball was released from a point on the hill. The box moved a distance of 2 meters before coming to rest, along with the ball. To move the box a greater distance, a change in the initial conditions is required. It can be achieved by decreasing the mass of the box and releasing the ball from a higher point on the hill.
According to the law of conservation of momentum, the total momentum before and after the collision is conserved. If the mass of the box is decreased, its momentum will be less after the collision. Therefore, the momentum of the ball will be greater than the momentum of the box, allowing it to move the box to a greater distance. Thus the correct option is Option D.
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The shock waves on a vehicle in supersonic flight cause a component of drag called supersonic wave drag D_w. Define the wave-drag coefficient as C_D, w = D_w/q_infinity S, where S is a suitable reference area for the body. In supersonic flight, the flow is governed in part by its thermodynamic properties, given by the specific heats at constant pressure C_p and at constant volume C_v. Define the ratio C_p/C_v identical to gamma. Using Buckingham's pi theorem, show that C_D, w = f(M_infinity, gamma). Neglect the influence of friction.
Answers
The wave drag coefficient, C_D,w, is a component of drag experienced by a vehicle during supersonic flight and is defined as the ratio of the wave drag D_w to the dynamic pressure q_infinity times the reference area S. This wave drag is a result of the shock waves created by the vehicle travelling at supersonic speeds, and is governed by thermodynamic properties such as specific heats at constant pressure (C_p) and constant volume (C_v).
The ratio of these two specific heats, C_p/C_v, is equal to gamma, and with the use of Buckingham's pi theorem, C_D,w can be expressed as a function of M_infinity and gamma. Friction can be ignored due to the supersonic speeds of the vehicle.
To express C_D,w as a function of M_infinity and gamma using Buckingham's pi theorem, the independent parameters of the problem must first be identified. The independent parameters of this problem are the Mach number M_infinity, the reference area S, and the ratio of the specific heats C_p/C_v, also known as gamma. With these identified, the dependent parameter of C_D,w can be expressed as a function of the independent parameters by constructing a dimensionless group or pi group.
The pi group for C_D,w is formed by the multiplication of the independent parameters. For example, the group can be expressed as (M_infinity * S * (C_p/C_v)). This group can then be rearranged to C_D,w = f(M_infinity * S * (C_p/C_v)). Since gamma is equal to the ratio of the specific heats, the pi group can be simplified to C_D,w = f(M_infinity, gamma). This shows that C_D,w is a function of the Mach number and gamma, and that friction can be neglected.
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how tall must a water-filled manometer be to measure blood pressure as high as 300 mm hg? density of blood is 1.05 x 103 kg/m3
Answers
The height of a water-filled manometer required to measure blood pressure as high as 300 mm Hg is 229.69 cm.
A manometer is a pressure measurement device that is utilized to measure the pressure of gases and liquids in a container.
The weight of the liquid in the manometer rises or falls depending on the pressure of the gases and liquids in the container.
In order to measure blood pressure, a water-filled manometer is used. The density of blood is 1.05 x 103 kg/m3. The height of the manometer is required to be found.
The pressure of blood is 300 mm Hg.
The following formula will be used to calculate the height of the manometer:
h = (P*d)/(g*H2O)
where, P = 300 mm Hg,
d = 1.05 × 103 kg/m^3,
g = 9.8 m/s2, and
H2O = 1000 kg/m^3
Substituting the values in the equation:
h = (300*1.05*103)/(9.8*1000)
h = 229.69 cm
The height of the manometer must be 229.69 cm to measure blood pressure as high as 300 mm Hg.
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WILL MARK BRAINLIEST!!!
From the choices below, select the one that best describes the difference between distance and displacement.
Distance includes direction,
Distance includes acceleration, displacement does not
Displacement includes direction, distance does not
Distance include speed, displacement, does not
Answers
Displacement includes direction, distance does not
is your answer. hope it helps!
Two cars are traveling towards one another. The VW Bug has a mass of 187 kg and its initial velocity is -38 m/s. The compact car has a mass of 702 kg and an initial velocity of 23 m/s. They collide and stick together. How fast does the wreckage move immediately after the collision
Answers
Answer:
10.17 m/s in the direction the compact car was going (+)
Explanation:
Law of conservation of momentum states that total P before the collision must equal total momentum after the collision.
P = mv
solve for v, velocity of the two cars stuck together after the collision:
(187kg)(-38 m/s) + (702kg)(23 m/s) = (187 + 702 kg)v
momentum before = momentum after
-7106 kg·m/s + 16146 kg·m/s = 889 kg(v)
9040 kg·m/s = 889 kg(v)
v = 9040 kg·m/s / 889 kg = 10.17 m/s
Problem 7.4 Two capacitors, each of capacitance 2 μF are connected in parallell. If the p.d. across them is 120V, calculate the charge on each capacitor.
Answers
Answer:
240 μC
Explanation:
When two capacitors are connected in parallel, the effective capacitance is the sum of the individual capacitances. In this case, the effective capacitance is:
C = C1 + C2 = 2 μF + 2 μF = 4 μF
The charge on a capacitor is related to the capacitance and the potential difference across it by the equation:
Q = C × V
where Q is the charge, C is the capacitance, and V is the potential difference.
Using this equation, the charge on each capacitor can be calculated as follows:
Q1 = C1 × V = 2 μF × 120 V = 240 μC
Q2 = C2 × V = 2 μF × 120 V = 240 μC
Therefore, the charge on each capacitor is 240 μC.
What are two reasons digital storage of data is more secure than analog
storage?
A. Digital data can be encoded by a computer program.
B. Digital data can be protected by a fingerprint or facial ID.
C. Access to digital data requires a stronger password.
D. Digital data are easy to change with a computer program.
SUBMIT
Answers
Digital data can be encoded by a computer program and are easy to change by a computer program. Therefore, options A and D are correct.
Why are the given two options correct?A and D are two reasons why digital storage of data is more secure than analogue storage.
A - Digital data can be encoded using various encryption techniques that make it more difficult for unauthorized individuals to access or interpret the data.
D - Digital data are easy to change or modify using a computer program, but this can also be a security advantage as it allows for quick updates and corrections to be made, and changes can be tracked and logged for security purposes.
B and C are not necessarily unique to digital storage, and may also be applicable to analogue storage. Fingerprint or facial ID can be used to protect physical storage devices, and a strong password can also be used to secure both digital and analogue storage.
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Answer:
A. Digital data can be encoded by a computer program.
B. Digital data can be protected by a fingerprint or facial ID.
Explanation:
did quiz
The diagram shows the cross-section of a progressive transverse wave travelling at 24 cm s−1 on
water. The amplitude of the wave is 2.0 cm and the frequency is 4.0 Hz.
Which statement is correct?
A The phase difference between particles at P and S is rad.
B The distance between P and R is 6.0 cm.
C The particle velocity at Q is a maximum.
D Particles at P and R are in phase.
Answers
The amplitude of wave is 2.0 cm and the frequency is 4.0 Hz, then the correct statements are : B) The distance between P and R is 6.0 cm ; D)Particles at P and R are in the phase.
What is meant by transverse wave?Moving wave whose oscillations are perpendicular to the direction of the wave is known as transverse wave.
As we know, v = fλ
v is the velocity of wave, f is frequency, and λ is wavelength.
λ = v/f
λ = 24 cm s−1 / 4.0 Hz = 6.0 cm
So the wavelength of the wave is 6.0 cm.
A.)The phase difference between particles at P and S is π/2 radians.
This statement cannot be determined from given information.
B.)Distance between P and R is 6.0 cm.
This statement is correct as the distance between two consecutive points on a wave with wavelength of 6.0 cm is also 6.0 cm.
C.)The particle velocity at Q is maximum.
This statement cannot be determined from given information.
D.)Particle at P and R are in phase.
This statement is correct as particles at two points on a wave with wavelength of 6.0 cm are in phase.
Therefore, correct statements are B and D.
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A crate is placed on the flatbed of truck and is free to move. Truck accelerates in the positive +x direction (to the right) too fast and crate slides and falls back of the truck. There is some friction between the truck bed and the crate.(a) When the crate falls off, in what direction is it moving relative to the ground?Choose the correct option:A. It is not moving with respect to the groundB. To the left (negative x direction)C. To the right (positive x direction)
Answers
Answer:
(C) it is moving to the right wrt to the ground
The crate is accelerated to the right (wrt the ground) because the frictional force between the truck bed and the crate is to the right and it is this force that provides movement to the crate
Answer : a) The crate will be moving in the negative x direction (to the left) when it falls off the truck. The force of the acceleration of the truck in the positive x direction will push the crate in the negative x direction. This will cause the crate to move away from the truck in the negative x direction. Correct answer is option B
This is because the truck is accelerating in the positive x direction (to the right), and the crate, being free to move, will have the same acceleration as the truck. This will cause the crate to slide backwards off the truck in the negative x direction.
Therefore, the crate will be moving in the negative x direction (to the left) when it falls off the truck.
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in the diagram, a conducting loop has a current running through it counter-clockwise. in which direction is the magnetic field inside of the loop going to be pointing?
Answers
Answer:
Place the thumb of your right hand in the direction of the current and the fingers will be pointing "upwards" - this is handy for long straight wires
State the function of the following electrical instrument. Rheostat
Answers
The function of a rheostat is to vary the resistance in an electrical circuit, thereby controlling the amount of current flowing through the circuit.
A rheostat is an electrical instrument that is used to vary the resistance in a circuit. It is a variable resistor that can be adjusted to control the amount of current flowing through the circuit. By increasing or decreasing the resistance, a rheostat can regulate the current flow, which can be useful in various applications.
For example, in a lighting circuit, a rheostat can be used to control the brightness of a bulb by adjusting the amount of current flowing through it. Similarly, in a motor control circuit, a rheostat can be used to adjust the speed of a motor by regulating the amount of current that flows through it. Overall, the function of a rheostat is to provide variable resistance in a circuit, allowing for the control of current flow and the regulation of various electrical devices.
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sarah attempts to do the popular physics trick of swinging a shallow pail of water around in a vertical circle with uniform circular motion so that the water doesn't spill out when the pail is upside down. if the distance from the bottom of the pail to her shoulder (the center of rotation) is 0.449 meters long, what is the minimum constant tangential speed that the pail bottom must have so that the water does not spill out at the top of the circular path
Answers
A pail of water is swung in a vertical circle using a uniform circular motion. In order to make sure that the water doesn't spill out when the pail is upside down, a minimum constant tangential speed of 2.1 m/s is required.
The minimum constant tangential speed required by the pail of water in order to ensure that the water doesn't spill out when the pail is upside down can be calculated using the formula:
[tex]v = \sqrt{gr}[/tex]
where v = minimum constant tangential speed g = acceleration due to gravity r = radius of the circle.
The distance from the bottom of the pail to Sarah's shoulder is 0.449 m long.
Since this distance is the radius of the circular path, we can substitute it in the formula.
Therefore,
[tex]v = \sqrt{9.8 m/s^2 \times 0.449 \ m} = \sqrt{4.4102 m^2/s^2} = 2.1 \ m/s[/tex]
Therefore, the minimum constant tangential speed required by the pail of water is approximately 2.1 m/s.
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Ms. Johnson points a laser pointer from a certain angle toward the bottom of an empty aquarium. Her students see the reflection of its rays at the bottom of the aquarium.
A hand holding a laser pointer toward the bottom of an aquarium and the end of the beam is reflected at the bottom of the aquarium.
She then partially fills the aquarium and points the laser pointer from the same height and angle as before.
A laser pointer pointing toward water in an aquarium.
Predict whether or not the reflected spot of light will be in the same place as it was when she pointed the laser pointer into the empty aquarium. Explain your reasoning.
Answers
Answer:
The reflected spot will appear to be closer than when the aquarium was empty.
N1 sin θ1 = N2 sin θ2 N1 is in air and equals 1, N2 is greater than one
θ2 is measured from the vertical and the ray is less than θ1
The distance to spot is less so it appears closer
(Consider a spot directly below the pointer L1 = N2 L2)
If N2 = 4/3 then L2 would be 3/4 L1
a pickup truck is moving at 25 m/s with a toolbox of mass m resting on the bed of the truck 3.5 m behind the cab. suddenly the brakes are applied, causing the toolbox to slide, and the truck comes to a stop in 6.0 s. the coefficient of kinetic friction between the toolbox and the bed of the truck is 0.3. after the brakes are applied, how much time elapses before the toolbox strikes the cab
Answers
After the brakes are applied it takes 8.47s time elapses before the toolbox strikes the cab.
The pickup truck is moving at 25 m/s with the toolbox of mass m resting on the bed of the truck 3.5 m behind the cab and the coefficient of kinetic friction between the toolbox and the bed of the truck is 0.3.
By using the equation a = (μk * g) / m
where a is the acceleration,
μk is the coefficient of kinetic friction,
g is the acceleration due to gravity (9.8 m/s2), and m is the mass of the toolbox.
By substituting the given values, we find the acceleration of the toolbox to be
a = (0.3 * 9.8) / m = 2.94 m/s2.
Since the toolbox is initially at rest, the velocity at which it strikes the cab is equal to the final velocity of the truck, 25 m/s. To find the time it takes for the toolbox to reach the cab, we can use the equation
t = vf / a where t is the time, vf is the final velocity, and a is the acceleration found above.
By substituting the given values, we find the time it takes for the toolbox to reach the cab to be
t = 25 / 2.94 = 8.47 seconds.
Therefore, the time it takes for the toolbox to strike the cab after the brakes are applied is 8.47 seconds.
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If old mountains are worn down over the course of millions of years, what is one of the primary reasons that mountains still exist?
Answers
Volcanic activity and the movement of lithospheric plates both result in the formation of new mountains.
Describe volcanic activity.Volcanic activity can include the release of gases, pro lava emissions, or extremely ferocious explosive bursts that can last for several hours. Volcano shapes and sizes are influenced by eruption type, which also affects the relative volumes & types of lava flows and volcaniclastic debris.
What would occur in the event that Yellowstone erupted?Worldwide repercussions would result from another big caldera-forming eruption at Yellowstone. The repercussions of such a large eruption would be felt locally and include ash fall and short-term (decades to years) changes to the global climate.
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1. The speed of a bobsled is increasing because it has an acceleration of 2.4 m/3. At a given instant in time, the forces resisting the motion, including kinetic friction and air resistance, total 450 N. The combined mass of the bobsled and its riders is 270 kg. (a) What is the magnitude of the force propelling the bobsled forward? (b) What is the magnitude of the net force that acts on the bobsled?
Answers
Answer:
Explanation:
Fnet = ma = (270 kg)(2.3 m/s²) = 621 N
Fnet = F-forward - F-resistance
a) F-forward = Fnet + F-resistance = 621 N + 450 N = 1,071 N
b) Fnet = F-forward - F-resistance = 1071 N - 450 N = 621 N
4.5.1 Explain how UV light can cause damage to one's eyes. 4.5.2 Explain the reason for using UV light in butcheries.
Answers
(1) UV (ultraviolet) light can cause damage to one's eyes because it is a type of radiation that is invisible to the human eye.
(2) In a butchery setting, UV-C disinfection can be used to sanitize surfaces such as meat slicers, cutting boards, and countertops.
How does ultraviolet light cause damage to eyes?When we are exposed to UV light, it can penetrate the outer layer of our eyes and reach the lens and the retina.
This UV light can cause a range of problems, such as:
Photokeratitis: Also known as "snow blindness"CataractsMacular degenerationUV light is used in butcheries for a process called "UV-C disinfection". UV-C light has a wavelength of between 200 and 280 nanometers, which is capable of killing bacteria, viruses, and other microorganisms.
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A main idea of the article is that the glowworm is a very unusual and beautiful insect. Give two details from the passage that support this statement
Answers
Two details from the passage to show that the glowworm is a very unusual and beautiful insect are:
Their light display is so beautiful that it looks like the sky at night They are able to use their light to capture their prey.What are glowworms?Glowworms are the larvae of certain species of insects that belong to the family Lampyridae, which includes fireflies. These larvae are bioluminescent, which means they can produce light through a chemical reaction in their bodies.
Glowworms are most often seen in dark environments, such as caves or forests at night. They use their light to attract prey, which includes small insects and other invertebrates. The beauty and unusual nature of glowworms has captured the imagination of people for centuries. They are often associated with magic and mystery, and their ability to produce light without heat has been the subject of scientific investigation for many years.
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A 0. 60 kg spike is hammered into a railroad
tie. The initial speed of the spike is equal to
1. 8 m/s.
If the tie and spike together absorb 57. 8
percent of the spike's initial kinetic energy
as internal energy, calculate the increase in
internal energy of the tie and spike.
Answer in units of J.
Answers
The increase in internal energy of the tie and spike is approximately 1.12 Joules.
The initial kinetic energy of the spike is:
K_i = (1/2) * m * v^2
K_i = (1/2) * 0.60 kg * (1.8 m/s)^2
K_i = 1.94 J
The amount of kinetic energy that is absorbed as internal energy is:
K_absorbed = 0.578 * K_i
K_absorbed = 0.578 * 1.94 J
K_absorbed = 1.12 J
Thus,the value is 1.12 Joules.
Kinetic energy is the energy an object has because of its motion. If we want to accelerate an object, then we must apply a force. Applying a force requires us to do work. After work has been done, energy has been transferred to the object, and the object will be moving with a new constant speed.
Kinetic energy is the energy of motion, observable as the movement of an object or subatomic particle. Every moving object and particle have kinetic energy. A person walking, a soaring baseball, a crumb falling from a table and a charged particle in an electric field are all examples of kinetic energy at work.
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as the heavier bucket moves downward to the ground, what will have been the change in mechanical energy of a system consisting of the lighter bucket and the earth, and what will have been the tension in the rope? give your answer as an ordered pair, with the change in mechanical energy first, followed by a comma, followed by the tension in the rope.
Answers
The change in mechanical energy of a system consisting of the heavier bucket and the earth is the sum of the potential energy of the bucket, minus the potential energy of the earth, which is the same as the weight of the heavier bucket multiplied by the distance the bucket fell.
The change in mechanical energy is the external work provided to the system. The potential energy of the bucket decreases. The work done by the earth is (weight of the heavier bucket x distance the bucket fell).
The tension in the rope is equal to the weight of the heavier bucket.
Therefore, the ordered pair of the change in mechanical energy and tension in the rope is (weight of the heavier bucket x distance the bucket fell, weight of the heavier bucket).
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onsider the two statements below. Which of the following best explains (I) and (II)? (I) the Ka of HXO2 is greater than the Ka of HYO2, but (II) the Ka of HX is less than the Ka of HY (A) (I) X is more electronegative than Y, and (II) the H-X bond is shorter than the H-Y bond (B) (I) X is less electronegative than Y, and (II) the H-X bond is longer than the H-Y bond (C) (I) the HX bond is weaker than the H-Y bond, and (II) X is more electronegative than Y (D) (I) the HX bond is stronger than the H-Y bond, and (II) X is less electronegative than Y
Answers
(I) The Ka of HXO2 is greater than the Ka of HYO2 because the HX bond is weaker than the H-Y bond. This is because X is more electronegative than Y, which means the electron density in the H-X bond is more attracted to X, making the bond weaker than the H-Y bond. The best explaination is option (C).
(II) The Ka of HX is less than the Ka of HY because the H-X bond is longer than the H-Y bond. This is because X is more electronegative than Y, which means that the electron density in the H-X bond is more attracted to X, causing it to be longer than the H-Y bond.
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9. A 1385-kg pickup truck hitched to a 453-kg
trailer accelerates along a level road from a
stoplight at 0. 75 m/s2 [forward]. Ignore friction
on the trailer and air resistance. Calculate
(a) the tension in the hitch a
(b) the force of static friction exerted by the road
on the pickup truck to propel it forward a
(c) the force the trailer exerts on the pickup
truck a
Answers
(a) The tension in the hitch is 339.75 N.
equal to the mass of the trailer times the acceleration (453 kg x 0.75 m/s2 = 339.75 N).
(b) The force of static friction exerted by the road on the pickup truck is 1038.75 N.
(c) The force the trailer exerts on the pickup truck is equal to 339.75 N.
(a) The tension in the hitch is equal to the mass of the trailer times the acceleration.
It is calculated by,
453 kg x 0.75 m/s2
= 339.75 N.
(b) The force of static friction exerted by the road on the pickup truck to propel it forward is equal to the mass of the pickup truck times the acceleration
It is calculated by
1385 kg x 0.75 m/s2
= 1038.75 N
(c) The force the trailer exerts on the pickup truck is equal to the mass of the trailer times the acceleration.
It is calculated by,
453 kg x 0.75 m/s2
= 339.75 N
Static friction is a force that keeps an object at rest. Static friction definition can be written as: The friction experienced when individuals try to move a stationary object on a surface, without actually triggering any relative motion between the body and the surface on which it is on.
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a small rope has a linear mass density of 8.00 g/m and is tied to two vertical walls that are separated by three fourths the length of the rope, as shown in the figure. a box of mass m is hanging from the rope halfway between its ends. (a) find an expression for the speed of a wave on the rope as a function of m. (b) what must the mass of the box be to have a wave speed of 65.0 m/s? (c) using the proportionality sensemaking technique, would you expect the mass of the box to increase or decrease if the wave speed needed to be 130 m/s? by what factor would the mass increase?
Answers
a. The speed of the wave in the ropes is [tex]30.43 \sqrt{m/s}[/tex]
b. 4.56 kg
What is Linear Mass Density?Linear mass density, also known as linear density, is a measure of the mass per unit length of a one-dimensional object such as a string, wire, or rod. It is defined as the mass of the object divided by its length, and has units of mass per unit length, such as kg/m or g/cm.
For example, if a wire has a mass of 10 grams and a length of 2 meters, its linear mass density would be 5 g/m. Linear mass density is an important concept in physics and engineering, as it is used to describe the properties of one-dimensional objects under tension, compression, and other forces.
The answer and solution are in the attached images.
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PLEASE HELP MEE
Two blocks of silver have a temperature of 175°C. One block has a mass of 33g, the other block has a mass of 300g. Do the blocks have the same amount of thermal energy? Why or why not?
Answers
Answer & Explanation FROM YOUR TEACHER:
The blocks does not have the same amount of thermal energy
The mass and temperature of an item are both inversely correlated with thermal energy. Thermal energy is expressed as follows:
Mass times Specific Heat Capacity times Temperature equals thermal energy.
where the material's specific heat capacity relates the amount of heat required to raise a unit mass of the material's temperature by one degree Celsius.
Even if the two blocks are at the same temperature, they will have different quantities of thermal energy since they have different masses. Assuming they are both composed of the same material and have the same specific heat capacity, the block with a mass of 300g will contain more thermal energy than the block with a mass of 33g.
33g × specific heat capacity x 175°C Equals 33g thermal energy of a 33g block.
Heat capacity of a 300g block is equal to 300g times 175°C in terms of thermal energy.
The thermal energy of the two blocks will vary since the masses are different.