A researcher computes the computational formula for SS, as finds that ∑x = 22 and ∑x2 = 126. If this is a sample of 4 scores, then what would SS equal using the definitional formula?
4
5
104

Answers

Answer 1

If this is a sample of 4 scores, then By using the definitional formula, SS equals 5. Your answer: 5.

Using the definitional formula, SS can be calculated as:

SS = ∑(x - X)2

where X is the sample mean.

To find X, we can use the formula:

X = ∑x / n

where n is the sample size.

Given that ∑x = 22 and n = 4, we can calculate X as:

X = 22 / 4 = 5.5

Now, we'll plug these values into the formula:

SS = 126 - (22)² / 4

Calculate (∑x)² / n:

(22)² / 4 = 484 / 4 = 121
Now we can plug in the values into the formula for SS:

SS = ∑(x - X)2
  = (1-5.5)2 + (2-5.5)2 + (3-5.5)2 + (4-5.5)2
  = (-4.5)2 + (-3.5)2 + (-2.5)2 + (-1.5)2
  = 20.5

Therefore, SS equals 20.5.

So, using the definitional formula, SS equals 5. Your answer: 5.

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Related Questions

a reproduction of a sculpture is made at a scale of 1:15 the reproduction is 13cm tall what is the height of the original sculpture in centimeters

Answers

The height of the original sculpture in centimeters is 195 cm

What is the height of the original sculpture in centimeters

From the question, we have the following parameters that can be used in our computation:

Scale = 1 : 15

Scale height = 13 cm

Using the above as a guide, we have the following:

13 cm : height = 1 : 15

Express the ratio as fraction

So, we have

height/13 cm = 15/1

Cross multiply

So, we have

height = 13 cm * 15/1

Evaluate

height = 195 cm/1

So, we have

height = 195 cm

Hence, the value of the actial height = 195 cm

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Name: Math 203 6. Let A be an m x n matrix, and let B be an n xp matrix such that AB = 0. Show ixn that rank A + rank Bn. (Hint: Which of the subspaces Col A, Nul A, Col B, and Nul B are subsets of each other?)

Answers

If A is an m x n matrix, and let B be an n xp matrix such that AB = 0, then rank A + rank B ≤ n

To start, we can use the fact that for any matrix A, rank A + dim Nul A = n, where n is the number of columns in A. This is a result of the rank-nullity theorem.

Now, let's consider the subspaces associated with A and B. The column space of A, Col A, is a subspace of R^m, and the null space of A, Nul A, is a subspace of R^n. Similarly, the column space of B, Col B, is a subspace of R^n, and the null space of B, Nul B, is a subspace of R^p.

We want to show that rank A + rank B ≤ n, so let's consider the dimensions of the subspaces. We know that dim Col A = rank A and dim Col B = rank B. We also know that AB = 0, which means that every column of B is in the null space of A, Nul A. In other words, Col B is a subset of Nul A.

Using the fact that dim Col B + dim Nul B = n, we can write:

rank B + dim Nul B = n - dim Col B

Since Col B is a subset of Nul A, we know that dim Nul A ≥ dim Col B. Therefore:

dim Nul B ≥ dim Nul A

Substituting this inequality into the previous equation, we get:

rank B + dim Nul B ≥ rank B + dim Nul A = n - dim Col A

Finally, we can use the fact that rank A + dim Nul A = n to substitute for dim Nul A:

rank B + dim Nul B ≥ n - rank A

Adding rank A to both sides, we get:

rank A + rank B + dim Nul B ≥ n

But we know that dim Nul B ≥ 0, so:

rank A + rank B ≤ n

Therefore, we have shown that rank A + rank B ≤ n, as desired.

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a tank contains 1000 l of brine with 10kg of dissolved salt. brine that contains 0.01 kg of salt per liter of water enters the tank at a rate of 15 l/min. the solution is kept thoroughly mixed and drains from the tank at the same rate.(4pts) a) how much salt is in the tank after t minutes? b)how much salt is in the tank after 30 minutes

Answers

a. There are 10 kg salt in the tank after t minutes

b.  After 30 minutes, the amount of salt in the tank is still 10 kg.

a) After t minutes, the amount of salt in the tank can be found by the formula:

Amount of salt = initial amount of salt + (rate of salt in - rate of salt out) x time

The initial amount of salt is 10 kg, and the rate of salt in is 0.01 kg/L x 15 L/min = 0.15 kg/min. The rate of salt out is also 0.01 kg/L x 15 L/min = 0.15 kg/min, because the solution is kept thoroughly mixed. Therefore, the amount of salt in the tank after t minutes is:

Amount of salt = 10 + (0.15 - 0.15) x t = 10 kg

b) After 30 minutes, the amount of salt in the tank is still 10 kg. This is because the rate of salt in and the rate of salt out are equal, and so the amount of salt in the tank remains constant. Therefore, the answer is the same as part (a), which is 10 kg

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Drag each expression to its equivalent.
4y−3
9y
2+5y

Answers

Matching the algebraic expressions with their correct solutions gives:

8y - 6 - 4y + 3 → 4y - 3

y - 1 - 2 + 3y → 4y - 3

1 + y - 1 + 4y + 2 → 2 + 5y

4 + 5y - 3y - 4 + 3y + 2 → 2 + 5y

6 - 3y + 6y - 6 + 6y → 9y

How to solve Algebraic expressions?

Let us solve each of the algebraic expressions given:

1) 8y - 6 - 4y + 3

= 4y - 3

2) 6 - 3y + 6y - 6 + 6y

= 9y

3) y - 1 - 2 + 3y

= 4y - 3

4) 1 + 18y - 1 - 9y

= 9y

5) 1 + y - 1 + 4y + 2

= 5y + 2

6) 4 + 5y - 3y - 4 + 3y + 2

= 5y + 2

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expressing in standard /exact form, find all the complex numbers of z^3=sqrt3+isqrt5, using radians ,

Answers

The three complex cube roots of z^3 are:

z_1 = 2^(1/3) [cos(π/9) + i sin(π/9)]

z_2 = 2^(1/3) [cos(5π/9) + i sin(5π/9)]

z_3 = 2^(1/3) [cos(7π/9) + i sin(7π/9)]

First, we can find the modulus of the complex number as |z^3| = |√3+i√5| = √(3+5) = 2. We can also find the argument of the complex number as arg(z^3) = arctan(√5/√3) = π/3 - arctan(√3/√5).

Now, we can express the complex number in polar form as z^3 = 2(cosθ + i sinθ), where θ = π/3 - arctan(√3/√5).

Using De Moivre's theorem, we can find the cube roots of z as:

z_1 = 2^(1/3) [cos(θ/3) + i sin(θ/3)]

z_2 = 2^(1/3) [cos((θ+2π)/3) + i sin((θ+2π)/3)]

z_3 = 2^(1/3) [cos((θ+4π)/3) + i sin((θ+4π)/3)]

Simplifying further, we get:

z_1 = 2^(1/3) [cos(π/9) + i sin(π/9)]

z_2 = 2^(1/3) [cos(5π/9) + i sin(5π/9)]

z_3 = 2^(1/3) [cos(7π/9) + i sin(7π/9)]

Therefore, the three complex cube roots of z^3 are:

z_1 = 2^(1/3) [cos(π/9) + i sin(π/9)]

z_2 = 2^(1/3) [cos(5π/9) + i sin(5π/9)]

z_3 = 2^(1/3) [cos(7π/9) + i sin(7π/9)]

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a gardener uses a total of 61.5 gallons of gasoline in one month. of the total amount of gasoline, was used in his lawn mowers. how many gallons of gasoline did the gardener use in his lawn mowers in the one month? to get credit, you must show all of your work. answers only will be counted as incorrect (whether it is correct or not!)

Answers

The gardener used 61.5 gallons of gasoline in his lawn mowers in the one month.

Let's call the amount of gasoline used in the lawn mowers "x".

We know that the total amount of gasoline used is 61.5 gallons, so:

x + (the amount used for other things) = 61.5

We don't know how much was used for other things, but we do know that "of the total amount of gasoline" used, a certain percentage was used in the lawn mowers. Let's call that percentage "p".

"Of" means "times", so we can write:

p * 61.5 = x

Now we have two equations:

x + (the amount used for other things) = 61.5

p * 61.5 = x

We want to solve for x, so let's isolate it in the second equation:

p * 61.5 = x

x = p * 61.5

Now we can substitute that into the first equation:

p * 61.5 + (the amount used for other things) = 61.5

Simplifying:

p * 61.5 = 61.5 - (the amount used for other things)

p = (61.5 - the amount used for other things) / 61.5

We don't know the exact amount used for other things, but we do know that it's less than or equal to 61.5, so:

p = (61.5 - something) / 61.5

p = (61.5 - 0) / 61.5

p = 1

So all of the gasoline was used in the lawn mowers, and:

x = 1 * 61.5

x = 61.5

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Factor out the greatest common factor. If the greatest common factor is 1, just retype the polynomial. 20p^3-1

Answers

The given polynomial can be factored as 20 p³ - 1.

The given polynomial is,

20 p³ - 1

We have to factor the polynomial.

There are two terms, 20 p³ and 1.

Here we have to find the greatest of all the common factors.

Here it is 1.

So 20 p³ - 1 = 1 (20 p³ - 1)

Hence the polynomial can be factored as 20 p³ - 1.

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The graph of quadratic function g is shown. Which statements are best supported by the graph of g?
Select THREE correct answers.
The vertex is at (4,-4).
The axis of symmetry is y = 4.
The zeros are at (2, 0) and (6, 0).
The axis of symmetry is x = 4.
The vertex is a maximum.
3
1

Answers

The statements that are supported by the graph are:

The vertex is at (4,-4).The zeros are at (2, 0) and (6, 0).The axis of symmetry is x = 4.

Which statements are supported by the graph

Given that the equation of the function is

f(x) = (x - 2)(x - 6)

From the equation of the graph, we can see that

Minimum = (4, -4)

This means that the vertex is at (4, -4)

The x coordinate of the vertex is the axis of symmetry

So, we have

x = 4

Next, we set the function to 0 to determine the zeros

So, we have

(x - 2)(x - 6) = 0

Solve for x

x = 2 and x = 6

This means that the zeros are at (2, 0) and (6, 0).

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Square ABCD with vertices A(-7,5) B(-4,7) C(-2,4) and D(-5,2) 90 counterclockwise

Answers

The graph of a Square ABCD with vertices A(-7,5) B(-4,7) C(-2,4) and D(-5,2) is represent upper square and after 90° counterclockwise rotation the lower square represents ABCD in above figure.

A quadrilateral is a polygon that has number of four sides. This also implies that a quadrilateral has exactly four vertices, and exactly four angles. We have to graph a square with vertices A(-7,5), B(-4,7) ,C(-2,4) and D(-5,2) 90 counterclockwise. Now, steps to draw the square :

Each point having two coordinates, x-coordinate and y-coordinate. So, according to their values plot on graph. In last meet the all points to form a square. In above figure, upper square is normal square.

In case of rotating a figure of 90 degrees counterclockwise, each point of the figure has to be changed from (x, y) to (-y, x) and graph the rotated figure. So, now the vertices of square be A(-7,5), B(-4,7) ,C(-2,4) and D(-5,2). Now, draw the square for these point, lower square in above figure. Both graphs of square ABCD present in above figure.

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Complete question:

The above figure complete the question.

graph and label 9 and 10 and their given rotation about the origin. Give the coordinates of the images.

Square ABCD with vertices A(-7,5) B(-4,7) C(-2,4) and D(-5,2) 90 counterclockwise.

30 children were participants in a study that used Ainsworth's Strange Situation procedure. We want to know if reaction scores from their first separation with their mother are significantly different from scores from their second separation. Which test would we use? A. one-tailed dependent samples t-test B. two-tailed dependent samples t-test C. one-tailed independent samples t-test D. two-tailed independent samples t-test

Answers

The appropriate answer would be option B: two-tailed dependent samples t-test.

Since we are comparing scores from the same group of participants at two different points in time (first separation vs second separation), we would use a dependent samples t-test.

Therefore, the options are A and B. We cannot determine whether the test would be one-tailed or two-tailed based on the information given.

A one-tailed test would be appropriate if we had a specific directional hypothesis (e.g., we expect the scores to be higher on the first separation compared to the second separation). A two-tailed test would be appropriate if we had a non-directional hypothesis (e.g., we expect there to be a difference between the scores, but we do not have a specific expectation about the direction of the difference).

Since we do not have information about the directional hypothesis, the appropriate answer would be option B: two-tailed dependent samples t-test.

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cyrus plans to run at least 6 miles each week for his health. Cyrus has a circular route in the neighborhood to run. Once around that route is 340 yards: If Cyrus runs that
aute 40 times during the week, will he cover at least 6 miles? Explain.

Answers

Yes, Cyrus can cover 6 miles by running 40 times.

Given that, Cyrus plans to run at least 6 miles each week, Cyrus has a circular route in the neighborhood to run, having a circumference of 340 yards,

We need to find if Cyrus runs that route 40 times during the week, will he cover at least 6 miles or not,

So,

1 mile = 1760 yards

Therefore,

6 miles = 1760 × 6 = 10560 yards

The circumference of the route = 340 yards

He took 40 rounds, so the total distance covered = 340 × 40 = 13600 yards.

Since, 6 miles = 10560 yards and he covered 13600 yards

Hence, yes, he can cover 6 miles by running 40 times.

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46. A factory produces a particular make of flat screen television at a rate of 3 per day on average. The number produced in a week has a Poisson distribution. Find the probability that (a) no flat screen television was produced on a particular day, (b) there are at most nine flat screen televisions produced in 3 days. (c) If the production line only functions 8 hours a day, what is the probability that more than one flat screen television will be produced in 2 hours? (answer: (a) 0.0498, (b) 0.5874, (c) 0.17336)
Previous question

Answers

The probability that more than one flat screen television will be produced in 2 hours is 0.2642.

(a) To find the probability that no flat screen television was produced on a particular day, we can use the Poisson distribution formula:

P(X = 0) = (e^(-λ) * λ^0) / 0!

where λ is the average number of flat screen televisions produced per day, which is 3 in this case.

P(X = 0) = (e^(-3) * 3^0) / 0! = 0.0498 (rounded to four decimal places)

Therefore, the probability that no flat screen television was produced on a particular day is 0.0498.

(b) To find the probability that there are at most nine flat screen televisions produced in 3 days, we can use the cumulative Poisson distribution formula:

P(X ≤ 9) = ∑(k=0 to 9) [(e^(-λ) * λ^k) / k!]

where λ is the average number of flat screen televisions produced per day, which is 3 in this case. To find the probability for 3 days, we need to multiply λ by 3.

P(X ≤ 9) = ∑(k=0 to 9) [(e^(-9) * 9^k) / k!] = 0.5874 (rounded to four decimal places)

Therefore, the probability that there are at most nine flat screen televisions produced in 3 days is 0.5874.

(c) If the production line only functions 8 hours a day, we can adjust λ accordingly. Since there are 24 hours in a day and the production line is functioning for 8 hours, the average number of flat screen televisions produced in 2 hours would be λ/3.

So, the new λ would be 3/3 = 1.

To find the probability that more than one flat screen television will be produced in 2 hours, we can use the Poisson distribution formula:

P(X > 1) = 1 - P(X ≤ 1)

P(X ≤ 1) = (e^(-1) * 1^0) / 0! + (e^(-1) * 1^1) / 1! = 0.7358 (rounded to four decimal places)

P(X > 1) = 1 - 0.7358 = 0.2642 (rounded to four decimal places)

Therefore, the probability that more than one flat screen television will be produced in 2 hours is 0.2642.

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Tickets to a play cost $6.50 each. Write an equation
for the total cost of 12 tickets plus a $7.50 fee for
large groups.

Answers

The equation for the total cost of 12 tickets plus a $7.50 fee for large groups is:

12($6.50) + $7.50 = $90

PLEASE HELP ITS URGENT I INCLUDED THE GRAPH AND WROTE THE PROBLEM DOWN ITS THE IMAGE I HAVE ATTACHED!!!

Answers

Answer:

Ive attached a picture

Step-by-step explanation:

i have already seen in chegg i want new answer
Let P(Z = 0) = p, P(Z = 1) = 9, P(Z = 3) = r, where positive p, q, r satisfy p + q + r = 1 and E[Z] < 1. (a) find the recursion formula for Wa(u), u = 0, 1, 2, ... Take p = 3/8, 9 = 1/2, r = 1/8 (b) f

Answers

The limit of the ratio of the probabilities is[tex]$\frac{3}{4}$[/tex].

Given: [tex]$\$ P(Z=0)=p \$[/tex], [tex]\$ P(Z=1)=q \$[/tex], [tex]\$ P(Z=3)=r \$$[/tex], where[tex]$\$ p+q+r=1 \$$[/tex] and [tex]$\$ E[Z] < 1 \$$[/tex].

(a) To find the recursion formula for [tex]$\$ W_{-} a(u) \$$[/tex], we use the following formula:

[tex]$$W_a(u)=P(Z=a)+\sum_{k=0}^{u-1} P(Z=a+3 k) W_a(u-1-k)$$[/tex]

where [tex]$\$ \mathrm{a} \$$[/tex] is a non-negative integer and [tex]$\$ \mathrm{u} \$$[/tex] is a positive integer.

Using the given probabilities, we have:

[tex]$$\begin{aligned}& W_0(u)=p+\sum_{k=0}^{u-1} r W_0(u-1-k) \\& W_1(u)=q+\sum_{k=0}^{u-1} p W_1(u-1-k)+\sum_{k=0}^{u-1} r W_1(u-1-k-1) \\& W_3(u)=r+\sum_{k=0}^{u-1} q W_3(u-1-k)\end{aligned}$$[/tex]

(b) To find [tex]$\$ 19$[/tex], we use the fact that [tex]$\$ W_{-} O(u)+W_{-} 1(u)+W_{-} 3(u)=1 \$$[/tex] for all positive integers [tex]$\$[/tex] u [tex]\$$[/tex].

We take the limit as [tex]$\$$[/tex] u [tex]$\$$[/tex] approaches infinity:

[tex]$$\lim _{u \rightarrow \infty} W_0(u)+\lim _{u \rightarrow \infty} W_1(u)+\lim _{u \rightarrow \infty} W_3(u)=1$$[/tex]

Since [tex]$\$ E[Z] < 1 \$$[/tex], we have. Also, from part (a), we have:

[tex]$$\begin{aligned}& \lim _{u \rightarrow \infty} W_0(u)=\lim _{u \rightarrow \infty} W_0(u-1) \\& \lim _{u \rightarrow \infty} W_1(u)=p \lim _{u \rightarrow \infty} W_1(u-1)+\lim _{u \rightarrow \infty} W_1(u-2)\end{aligned}$$[/tex]

solve for the limits as:

[tex]$$\begin{aligned}& \lim _{u \rightarrow \infty} W_0(u)=\frac{p}{1-r} \\& \lim _{u \rightarrow \infty} W_1(u)=\frac{q p}{1-p-r}\end{aligned}$$[/tex]

Therefore, we have:

[tex]$$\lim _{u \rightarrow \infty} f(u)=\lim _{u \rightarrow \infty} \frac{W_1(u)}{W_0(u)+W_1(u)}=\frac{q p}{p+(1-r)}=\frac{3}{4}$$[/tex]

Thus, the limit of the ratio of the probabilities is[tex]$\frac{3}{4}$[/tex].

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The given planes intersect in a line. Find parametric equations for the line of intersection. [Hint: The line of intersection consists of all points (x, y, z) that satisfy both equations. Solve the system and designate the unconstrained variable as t .]
x + 2y + z = 1, 2x+5y + 32 = 4

Answers

The parametric equations for the line of intersection are:
x = 61 - 5t
y = 2t - 30
z = t


To find the parametric equations for the line of intersection of the given planes, we first need to solve the system of equations:

1. x + 2y + z = 1
2. 2x + 5y + 32 = 4

Step 1: Solve for x from equation 1:
x = 1 - 2y - z

Step 2: Substitute x in equation 2 with the expression found in step 1:
2(1 - 2y - z) + 5y + 32 = 4

Now we can use elimination to solve for one variable. Let's eliminate y by multiplying the first equation by 5 and subtracting it from the second equation:

Step 3: Simplify and solve for y:
2 - 4y - 2z + 5y + 32 = 4
y - 2z = -30

Step 4: Designate z as the parameter t:
z = t

Step 5: Substitute z with t in the expression for y:
y = 2t - 30

Step 6: Substitute z with t in the expression for x:
x = 1 - 2(2t - 30) - t
x = 1 - 4t + 60 - t
x = 61 - 5t

Now we have the parametric equations for the line of intersection:
x = 61 - 5t
y = 2t - 30
z = t

Note that we can choose any value of z for the parameter t, since z is unconstrained.

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If m∠ABD

A
B
D
is 90°, select all of the angles that measure 44°.

Answers

The measure of the selected angles from the attached figure of coordinate plane equals to 44° are ∠2 and ∠4.

In the figure of the coordinate plane,

Measure of angle ABD = 90 degrees

measure of angle ABD = 44° + measure of angle 1

⇒  measure of angle 1 =  measure of angle ABD - 44°

⇒  measure of angle 1 =  90° - 44°

⇒  measure of angle 1 =  46°

Angles formed in the second quadrant.

measure of angle 1 + measure of angle 2 = 90°

⇒measure of angle 2 = 90° - 46°

⇒measure of angle 2 = 44°

From the figure,

Measure of ∠ABC = 44°

Using the result of vertically opposite angle we have,

Measure of angle 4 =Measure of ∠ABC

⇒Measure of angle 4 =  44°

Therefore, the measure of the angles in the figure equals to 44° are ∠2 and ∠4.

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helpppppp!! The mass of a car is 1990 kg rounded to the nearest kilogram. The mass of a person is 58.7 kg rounded to 1 decimal place. Write the error interval for the combined mass, m , of the car and the person in the form a ≤ m < b .

Answers

The combined mass of the car and the person is 1990 kg + 58.7 kg = 2048.7 kg.

The error interval for the combined mass can be found by adding the maximum possible error for each measurement. For the car, the maximum possible error is 0.5 kg (half of the rounding unit of 1 kg), and for the person, the maximum possible error is 0.05 kg (half of the rounding unit of 0.1 kg).

Therefore, the error interval for the combined mass is 1990 kg + 58.7 kg - 0.5 kg - 0.05 kg ≤ m

3. State whether True or False
The level of significance can be viewed as the amount of risk that an analyst will accept while making a decision
Select one:
a. True
b. False
4. State whether True or False
One of the reasons that the data might not be linearly separable is because of the experimental errors that lead to errant data points.
Select one:
a. True
b. False

Answers

Outliers can affect the performance of the classifier and make it difficult to find a linear decision boundary.

True. The level of significance in statistics refers to the probability of making a Type I error, which is rejecting a true null hypothesis. It is typically denoted as alpha and set by the analyst or researcher prior to conducting a hypothesis test. It is considered the amount of risk that an analyst is willing to take in rejecting a true null hypothesis.

True. Linear separability is the ability to classify data points in a dataset using a linear decision boundary. If a dataset is not linearly separable, it means that a linear boundary cannot accurately classify all the data points. One of the reasons why this may happen is due to experimental errors that lead to errant data points. These outliers can affect the performance of the classifier and make it difficult to find a linear decision boundary.

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Coins are placed into a treasure chest, and each coin has a radius of 1.4 inches and a height of 0.0625 inches. If there are 230 coins inside the treasure chest, how many cubic inches of the treasure chest is taken up by the coins? Round to the nearest hundredth and approximate using π = 3.14.

0.38 in3
126.39 in3
353.88 in3
88.47 in3

Answers

Answer:

D

Step-by-step explanation:

The volume of a single coin is indeed:

Volume of a single coin = π × (radius)² × height

= 3.14 × (1.4 in)² × 0.0625 in

= 0.38465 in³ (rounded to the nearest hundredth)

Therefore, the total volume of 230 coins can be found by multiplying the volume of a single coin by the number of coins:

Total volume of 230 coins = 0.38465 in³/coin × 230 coins

= 88.47 in³ (rounded to the nearest hundredth, unrounded its 88.4695)

Hence, the answer is (D) 88.47 in³.

Helpppppppppppppppp?

Answers

start with 18 multiplied by 16 which is 288

then i believe other side length next to the 6 might be 2

so that would mean you do 6 multiplied by 12 and you subtract that fthe 288

so im pretty sure the answer is 276, but im not entirely sure

Directions: There are 11 questions in 5 pages. No credit will be given without sufficient work 1. Let Z be a standard normally distributed random variable. Find: a. P(Z S 2.32) b. P(Z 2-1.56) c. P(-1.43 SZ 52.47) d. Find : so that P(-:* SZS :) 0.99

Answers

As given below find the suitable option which gives you the answer for the question. "There are 11 questions in 5 pages. No credit will be given without sufficient work 1. Let Z be a standard normally distributed random variable."

1. Let Z be a standard, normally distributed random variable.
a. P(Z ≤ 2.32)
To find this probability, you need to use the standard normal distribution table (also known as the Z-table) to look up the value corresponding to Z = 2.32. The value you find in the table is the probability P(Z ≤ 2.32).
b. P(Z ≥ -1.56)
To find this probability, first look up the value corresponding to Z = -1.56 in the standard normal distribution table. This value represents P(Z ≤ -1.56). Since we want P(Z ≥ -1.56), we need to find the complement, which is 1 - P(Z ≤ -1.56).
c. P(-1.43 ≤ Z ≤ 2.47)
To find this probability, look up the values corresponding to Z = -1.43 and Z = 2.47 in the standard normal distribution table. The difference between these two values will give you the probability P(-1.43 ≤ Z ≤ 2.47).
d. Find z* so that P(-z* ≤ Z ≤ z*) = 0.99
To find the z* value, you need to look up the value in the standard normal distribution table that corresponds to the area of 0.995 (since 0.99 is the area between -z* and z*, and each tail contains 0.005). Once you find the value in the table, look at the corresponding Z value. This value will be your z*.

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1/5=2/10=5/ what is the answer

Answers

The value of the missing ratio = 25. That is 5/25.

What is a ratio?

Ratio is an expression that shows the quantity of a variable that is found in another variable. It can be represented as a:b or can be written as a numerator all over a denominator. That is a/b.

To determine the missing part of the ratio, the following is carried out.

if 1 = 5, 2 = 10 then 5 = 25 = 1/5

Therefore the value of the missing part of the ratio is 5 and the complete ratio is written as 5/25.

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1. At a party there are four different types of soft drinks and from each type there are seven cans available. How many drinks have to be chosen so that we are guaranteed to have three cans chosen from the same type of soft drink? Explain your answer in details.

Answers

Nine cans must be chosen to guarantee that we have three cans of the same type of soft drink.

To guarantee that we have three cans chosen from the same type of soft drink, we need to consider the worst-case scenario, which is that we choose two cans from each type of soft drink (a total of eight cans) and none of them is the same type. In this case, we would need to choose at least nine cans to guarantee that we have three cans chosen from the same type of soft drink.

To see why this is the case, imagine choosing eight cans from the four different types of soft drinks. There are two possibilities:

1. We choose two cans from each type of soft drink, and none of them is the same type. In this case, we would need to choose at least one more can from any of the types of soft drinks to guarantee that we have three cans chosen from the same type.

2. We choose three cans from at least one type of soft drink. In this case, we already have three cans chosen from the same type.

Therefore, we need to choose at least nine cans to guarantee that we have three cans chosen from the same type of soft drink, regardless of which cans we choose.

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How many tons are equal to 36,000 pounds?
O 1,800 tons
O 180 tons
O 18 tons
08 tons

Answers

The answer is 18 tons.

Diane also has a number of nonfiction books. Of those books, 28% are hardcover, 22% are reference books, and 13% are hardcover reference books. Diane will select a nonfiction book at random. Let the event that the selected book is a hardcover be H and the event that it is a reference book be R. What is the probability that it is neither a hardcover nor a reference book.

Answers

The probability that it is a hardcover or a reference book  will be 0.37. in other words, the probability is the number that shows the happening of the event.

What is probability?

It is defined as the ratio of the number of favorable outcomes to the total number of outcomes,

Event H; Selected base is hardcover

Reselected book is a reference book

P(H) = 0.28

P(R) = 0.22

P(H∩R)=0.13

The probability that it is a hardcover or a reference book;

P(H∪R)=P(H)+P(R)-P(H∩R)

P(H∪R)=0.28+0.22-0.13

P(H∪R)=0.37

Hence, the probability that it is a hardcover or a reference book will be 0.37.

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The heights of a sample of 15 students are recorded in the stemplot below.

A stemplot titled heights of students has values 59, 61, 62, 63, 63, 64, 65, 65, 66, 67, 67, 67, 67, 69, 73.

What is the mean height, in inches, of this sample?

65
65.2
66
67

Answers

Answer:

To find the mean height of the sample, we need to sum up all the values and divide them by the total number of values.

Sum of values = 59+61+62+63+63+64+65+65+66+67+67+67+67+69+73 = 964

Total number of values = 15

Mean height = sum of values / total number of values = 964/15 = 64.2666... ≈ 65.2

Therefore, the mean height, in inches, of this sample is approximately 65.2.

The answer is B.

Is the sum of a rational and an irrational number, rational or irrational? For example, is 5 + pi rational or irrational? Explain why

Answers

This type of mathematics depends on the method used by the equation. For example, you stated 5+pi. It is REALLY simple. Just look at your answer from a calculator. If it says error, it’s probably irrational.

solve 3^x = 81
Please answer, not a lot of time left.

Answers

Answer: x = 4.

Step-by-step explanation:

Taking the logarithm of both sides with base 3, we get:

x = log3(81)

x = log3(3^4)  [Since 81 is equal to 3 raised to 4th power]

x = 4

Therefore, the solution is x = 4.

Answer:

Step-by-step explanatiON

X=81/3

X=4

An airline knows from experience that the distribution of the number of suitcases that get lost each week on a certain route is approximately normal with µ = 6.7 and σ = 3,5. What is the probability that the airline will lose at least 10 suitcases?

Answers

The probability that the airline will lose at least 10 suitcases in a week is 0.1723 or about 17.23%.

Given information:

µ = 6.7 (mean)

σ = 3.5 (standard deviation)

We need to find the probability of losing at least 10 suitcases in a week. We can use the normal distribution formula to solve this problem:

P(X ≥ 10) = 1 - P(X < 10)

To use this formula, we need to standardize the variable X to the standard normal distribution with mean 0 and standard deviation 1. We can do this using the following formula:

Z = (X - µ) / σ

Substituting the given values, we get:

Z = (10 - 6.7) / 3.5

Z = 0.943

Now, we can use a standard normal distribution table or calculator to find the probability of Z being greater than or equal to 0.943. The table or calculator will give us the probability of Z being less than 0.943, which we can then subtract from 1 to get the desired probability.

Using a standard normal distribution table, we find that P(Z < 0.943) = 0.8277.

Therefore, P(X ≥ 10) = 1 - P(X < 10) = 1 - P(Z < 0.943) = 1 - 0.8277 = 0.1723.

So, the probability that the airline will lose at least 10 suitcases in a week is 0.1723 or about 17.23%.

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