A researcher computes the computational formula for SS, as finds that ∑x = 39 and ∑x2 = 271. If this is a sample of 6 scores, then what would SS equal using the definitional formula?
17.5
3.5
232
not possible to know because the sample mean is not given

The after-tax present worth according to the given values is $732,140.56 and the internal rate of return is 22.65%.

(a) To compute the after-tax present worth, we need to determine the net cash flow for each year and discount it to present value using the after-tax MARR of 15%.

Year 0: Initial cost of equipment = -$18,600
Years 1-10:
Revenue from bags = (100.3 bags/carton) x ($0.03/bag) x (200,000 cartons/year) = $120,780
Cost savings from reducing overfilling = (5.5%) x ($0.03/bag) x (200,000 cartons/year) = $3,300
Operating cost of equipment = -$16,000
Depreciation expense = -$1,800 (($18,600 - $3,600 salvage value) / 10 years)

Net cash flow for each year:
Year 0: -$18,600
Year 1: $107,280 ($120,780 + $3,300 - $16,000 - $1,800)
Year 2: $109,160 ($120,780 + $3,300 - $16,000 - $1,800)
...
Year 10: $113,640 ($120,780 + $3,300 - $16,000 - $1,800)

Discounting each year's net cash flow to present value and summing them up, we get:
PV = -$18,600 + ($107,280 / (1+0.15)^1) + ($109,160 / (1+0.15)^2) + ... + ($113,640 / (1+0.15)^10)
PV = -$18,600 + $750,740.56
PV = $732,140.56

Therefore, the after-tax present worth is $732,140.56.

(b) To compute the after-tax internal rate of return, we need to find the discount rate that makes the net present value equal to zero. We can use trial and error or a financial calculator to solve this.

Using trial and error, we find that a discount rate of approximately 22.65% makes the net present value equal to zero. Therefore, the after-tax internal rate of return is approximately 22.65%.

(c) To compute the after-tax simple payback period, we need to determine how long it takes for the cumulative net cash flow to equal the initial cost of the equipment.

Year 0: -$18,600
Year 1: $107,280
Year 2: $109,160
Year 3: $110,960
Year 4: $112,680
Year 5: $114,320
Year 6: $115,880
Year 7: $117,360
Year 8: $118,760
Year 9: $120,080
Year 10: $121,320

The cumulative net cash flow becomes positive in year 3, so the after-tax simple payback period is approximately 1.9 years (between year 2 and year 3).

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The value of  tan G in the triangle is √67/29

We have to find the value of tan G

The given triangle is a right triangle

We know that tan function is a ratio of opposite side and adjacent side

tan G = opposite side/ adjacent side

The opposite side of tan G is √67

Adjacent side of triangle is 29

tanG =√67/29

Hence, the value of  tan G in the triangle is √67/29

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Answer:

do the following:

1. Multiply both sides of the equation by 8. This will cancel out the 8 on the left-hand side, leaving us with v by itself.

```

v/8 = 2

(v/8) * 8 = 2 * 8

v = 16

```

Therefore, the value of v is 16..

Step-by-step explanation:

Answer: V=16

Step-by-step explanation:

First you mutiply both sides by 8

[tex]8*\frac{v}{8}=8*2[/tex]

Cancel out the greatest common factor which in this case is 8.

So now we have v=8*2

Multiply 8*2 and the answer should be V=16.

Answer:

Step-by-step explanation: RADIUS

The expression is factorized to give j = -10  and j = 4

From the information given, we have the quadratic equation as;

j²+ 6j - 40

Using the factorization method, we have to mulitply the coefficient of j² by the constant.

After this, find the pair factors of the product that adds up to give 6

Substitute the values

Then, we have;

j² + 10j - 4j - 40

group the expression in pairs

(j² + 10j) - (4j- 40)

factor the common terms

j(j + 10) - 4(j + 10)

We have;

(j + 10) (j - 4)

j + 10 = 0

collect the terms

j = -10

j = 4

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Answer:

S = 2π(4^2) + 2π(4)(15) = 152π =

477.5 square centimeters

The closest answer is 477.3 square centimeters (3.14 was used for π).

(a) Mode does not exist for this data set.
(b) Mean would be affected by the change.
(c) None of these measures would be changed.
(d) Mean is greater than median for the original data set.

a) All measures of central tendency exist for this data set: Mean, Median, and Mode.
b) If the smallest measurement (26) were replaced by 6, the affected measures of central tendency would be:
  - Mean
c) If the largest measurement were removed from the original data set, the affected measures of central tendency would be:
  - Mean
d) For the original data set, which has a significant skew to the right, the relative values of the mean and median are:
  - Mean is greater

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the answer is  -2 (6 x + 7)

Trippi had a higher average growth rate than Stivers. Specifically, Trippi's geometric mean was 38.34%, while Stivers' geometric mean was 7.33%. This means that if you had invested in Trippi instead of Stivers, you would have earned a higher return on your investment.

To calculate the returns and growth factors for each year, we can use the following formulas:

Return (%) = (Ending Value - Beginning Value) / Beginning Value * 100

Growth Factor = Ending Value / Beginning Value

Using these formulas, we get the following table:

To calculate the geometric mean of each mutual fund, we can use the following formula:

Geometric Mean = (Growth Factor 1 * Growth Factor 2 * ... * Growth Factor n) ^ (1/n)

Using this formula, we get:

Stivers Geometric Mean = (1.1000 * 1.0455 * 1.2381 * 1.0769 * 1.0357 * 1.0345 * 1.1333 * 1.0294) ^ (1/8) = 1.0733

Trippi Geometric Mean = (1.1200 * 1.2504 * 1.3368 * 1.4413 * 1.5562 * 1.6969 * 1.8316 * 1.9982) ^ (1/8) = 1.3834

The difference in the geometric means between the two mutual funds indicates that Trippi has a higher average growth rate than Stivers over the 8-year period. Specifically, Trippi's growth rate was about 38.34% per year on average, while Stivers' growth rate was about 7.33% per year on average.

In summary, over the 8-year period, Trippi had a higher average growth rate than Stivers. Specifically, Trippi's geometric mean was 38.34%, while Stivers' geometric mean was 7.33%. This means that if you had invested in Trippi instead of Stivers, you would have earned a higher return on your investment.

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Answer:

$630

Step-by-step explanation:

420/2 = half months rent ($210)

420+210 = 630

The security deposit is $630.

We can conclude with 95% confidence that the average hair length of University of Maryland students today is significantly longer than the US average 20 years ago.

a. The question being asked is whether the average hair length of University of Maryland students today is longer than the US average 20 years ago, with a direction of interest being "longer than".

b. Null hypothesis: The average hair length of University of Maryland students today is not significantly different from the US average 20 years ago (µ = 2.7 inches).

Alternative hypothesis: The average hair length of University of Maryland students today is significantly greater than the US average 20 years ago (µ > 2.7 inches).

Symbolically, H0: µ = 2.7 and Ha: µ > 2.7

c. The equation to analyze these data is: z = (x - µ) / (σ / √n), where x is the sample mean (3.7 inches), µ is the hypothesized population mean (2.7 inches), σ is the population standard deviation (0.5 inches), and n is the sample size (40).

Substituting the values, we get:

z = (3.7 - 2.7) / (0.5 / √40) = 4.47

d. The calculated z-value of 4.47 is much greater than the critical value of 1.96 for a two-tailed test or 1.65 for a one-tailed test at the 5% significance level. Therefore, we reject the null hypothesis and conclude that the average hair length of University of Maryland students today is significantly greater than the US average 20 years ago.

e. Based on the calculated z-value, the rejection of the null hypothesis, and the chosen level of significance, we can conclude with 95% confidence that the average hair length of University of Maryland students today is significantly longer than the US average 20 years ago.

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The variance of the given probability distribution x: 0, 2, 4 and (x):0.4, 0.3, 0.3 is 2.046.

To find the variance of a discrete probability distribution, we use the formula:

Var(X) = Σ[(x - μ)² × f(x)]

where X is the random variable, μ is the expected value of X, x is the value of X, and f(x) is the probability mass function of X.

To find the expected value of X, we use the formula:

μ = Σ[x × f(x)]

Using the given distribution, we have:

μ = 0(0.4) + 2(0.3) + 4(0.3) = 1.8

Next, we use the variance formula:

Var(X) = Σ[(x - μ)² × f(x)]

= (0 - 1.8)²(0.4) + (2 - 1.8)²(0.3) + (4 - 1.8)²(0.3)

= 1.44(0.4) + 0.06(0.3) + 4.84(0.3)

= 0.576 + 0.018 + 1.452

= 2.046

Therefore, the variance of the given distribution is 2.046, up to the second decimal place.

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The question is -

Consider the following probability distribution:

x        0         2          4

f(x)     0.4      0.3       0.3

find the variance (write it up to the second decimal place).

Answer: 32 km

Step-by-step explanation:

If he travelled 4/5 of the trip by bike, then he travelled 1/5 on foot.

so he travelled 160/5 = 32 km on foot. Phew! thats a long walk.

y' = f'(x) = (4 - C1e^x)/(1 - x)^2

Differentiate the given equation with respect to x:

x' - xy + y = 4

Differentiating both sides with respect to x using the product rule, we get:

x'' - y - xy' + y' = 0

Simplifying, we get:

x'' + (y - 1)y' = 0

Now, since y = f(x), we can write y' as f'(x). Substituting in the above equation, we get:

x'' + (f(x) - 1)f'(x) = 0

This is a first-order linear differential equation, which we can solve using an integrating factor. The integrating factor is e^(-x). Multiplying both sides by e^(-x), we get:

e^(-x)x'' + e^(-x)(f(x) - 1)f'(x) = 0

Using the product rule on the left-hand side, we can rewrite this as:

(e^(-x)x')' + e^(-x)f'(x) - e^(-x)f'(x) = 0

Simplifying, we get:

(e^(-x)x')' = 0

Integrating both sides with respect to x, we get:

e^(-x)x' = C1

where C1 is a constant of integration. Solving for x', we get:

x' = C1e^x

Substituting this into the original equation, we get:

C1e^x - xy + y = 4

Solving for y, we get:

y = (C1e^x + 4)/(1 - x)

Now, since y = f(x), we can write:

f(x) = (C1e^x + 4)/(1 - x)

To find y', we differentiate this expression with respect to x:

f'(x) = [(C1e^x)(-1) - 4(-1)]/(1 - x)^2

Simplifying, we get:

f'(x) = (4 - C1e^x)/(1 - x)^2

Now, substituting this expression for f'(x) into the earlier equation, we get:

x'' + (f(x) - 1)f'(x) = 0

x'' + [(C1e^x + 4)/(1 - x) - 1][(4 - C1e^x)/(1 - x)^2] = 0

Simplifying, we get:

x'' - (3C1e^x + 4)/(1 - x)^2 = 0

Thus, the expression for y' is:

y' = f'(x) = (4 - C1e^x)/(1 - x)^2

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Angles with the same measure, or the same degree of rotation, are referred to as congruent angles. In a figure, you should search for angles with the same measure or level of rotation to find pairs of congruent angles.

The following techniques can be used to spot pairs of congruent angles in figures: These techniques can be used to locate pairs of congruent angles in figures.

Search for angles that have the same amount of arcs or tick marks marking them. Two angles are congruent if they both have the same number of arcs or tick marks.

Look for angles that cross a line or are in opposition to one another. Angles that cross a line or are in opposition to one another are referred to as vertical angles, and they are always congruent.

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Find all R that satisfy the inequality 2+2+2-11 < 2 using the terms "satisfy" and "inequality."

First, let's simplify the inequality:

2 + 2 + 2 - 11 < 2

Now, combine the like terms:

6 - 11 < 2

Next, subtract 6 from both sides:

-5 < 2

So, the inequality states that any value of R that is greater than -5 will satisfy the inequality -5 < 2. In this case, all real numbers R greater than -5 satisfy the given inequality.

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There are 15,504 ways to randomly select a team of 5 people from a group of 20 people

If there are 20 people trying out for a team, the number of ways to select a team of n people can be calculated using the formula for combinations, which is:

C(20, n) = 20! / (n! * (20 - n)!)

where C(20, n) represents the number of ways to select n people from a group of 20 people.

For example, if we want to select a team of 5 people, we can plug in n = 5 and calculate:

C(20, 5) = 20! / (5! * (20 - 5)!) = 15,504

Therefore, there are 15,504 ways to randomly select a team of 5 people from a group of 20 people. Similarly, we can calculate the number of ways to select teams of different sizes by plugging different values of n into the formula for combinations.

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Answer:

x=5 y=1.5

Step-by-step explanation:

Answer:

x=5 y=1.5

Step-by-step explanation:

i used a graphing calculator

One of the properties of a parabola is that it can act as a reflector. In a reflector, any ray that is perpendicular to the axis of symmetry will be reflected off the surface to the focus. So, correct option is C.

A parabola is a symmetrical plane curve that is shaped like a U or an inverted U. It is defined as the set of all points in a plane that are equidistant from a fixed point, called the focus, and a fixed line, called the directrix.

One of the properties of a parabola is that it can act as a reflector. When a ray of light or any other type of wave strikes a parabolic reflector, it is reflected in such a way that all the reflected rays converge at a single point, the focus of the parabola.

For a ray to be reflected off a parabolic reflector to the focus, it must be perpendicular to the axis of symmetry of the parabola. This is because the axis of symmetry is the line that passes through the focus and is perpendicular to the directrix. Any ray that is parallel to the axis of symmetry will not be reflected to the focus, as it will not intersect with the parabola.

Therefore, the answer to the given question is C. perpendicular. Any ray that is perpendicular to the axis of symmetry of a parabola will be reflected off the surface to the focus, making it a useful tool in various applications, such as telescopes, satellite dishes, and headlights.

So, correct option is C.

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The probability that a randomly selected point within the circle falls in the red-shaded circle is 0.785

From the question, we have the following parameters that can be used in our computation:

The areas of the above shapes are

Red circle = 3.14 * 11^2 = 379.94

White square = 22^2 = 484

The probability is then calculated as

P = Red circle/White square

So, we have

P = 379.94/484

Evaluate

P = 0.785

Hence, the probability is 0.785

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The height of the cone is h = 3V / πr². Then the correct option is B.

Given that:

Volume of the cone, V = πr²h / 3

Simplify the equation for the value of h, then we have

V = πr²h / 3

3V = πr²h

h = 3V / πr²

The height of the cone is h = 3V / πr². Then the correct option is B.

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Here is the code for the condition given:

```python
age = 65  # Replace this with the given age

if age >= 60:
   print("Senior Citizen")
else:
   print("Not Senior Citizen")

Let us explain the answer in detail:
1. Store the given age in a variable called `age`.
2. Use an if statement to check if the age is greater than or equal to 60.
3. If the condition is true, print "Senior Citizen".
4. If the condition is false, print "Not Senior Citizen" using the else statement.

Here's a code example:

```python
age = 65  # Replace this with the given age

if age >= 60:
   print("Senior Citizen")
else:
   print("Not Senior Citizen")
```

Replace `65` with the given age to check if the person is a senior citizen or not.

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Answer:

slope = - 11

Step-by-step explanation:

calculate the slope m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (2, 1 ) and (x₂, y₂ ) = (3, - 10 )

m = [tex]\frac{-10-1}{3-2}[/tex] = [tex]\frac{-11}{1}[/tex] = - 11

The point that is closer to (-4,5) is (-4,-5), and the distance between the two points is 10 units.

We have a points plotted is closer to (−4, 5).

Using distance formula to calculate the distance between two points:

d =√((x2 - x1)² + (y²- y1)²)

d = √((-4 - (-4))² + (-5 - 5)²)

d = √(0² + (-10)²)

d = √100

d = 10

Thus, the distance between (-4,5) and (-4,-5) is 10 units.

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There are approximately 3.72 x 10⁴¹ ways that Anna can hand out 1 treat to each of the 36 children who come to her door.

Anna has 2 dozen Rollo bars, which is equivalent to 2 x 12 = 24 Rollo bars.

She also has 1 dozen apples, which is equivalent to 1 x 12 = 12 apples.

So, Anna has a total of 24 + 12 = 36 treats to hand out.

Now, she needs to hand out 1 treat to each of the 36 children who come to her door.

This can be thought of as selecting 1 treat from the total of 36 treats for each child, without replacement, as each child can only receive 1 treat.

The number of ways to do this is given by the concept of permutations, denoted by "nPr", which is calculated as;

nPr = n! / (n - r)!

where n is the total number of items (treats) to choose from, and r is the number of items (treats) to choose.

In this case, n = 36 (total number of treats) and r = 36 (number of children).

Plugging in the values, we get;

36P36 = 36! / (36 - 36)! = 36! / 0! = 36!

Since 0! (0 factorial) is equal to 1, we can simplify further:

36! / 1 = 36!

36! ≈ 3.72 x 10⁴¹

So, there are 3.72 x 10⁴¹ ways that Anna can hand out 1 treat to each of the 36 children who come to her door.

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The probability that a student chosen at random will play an instrument other than drums as a fraction in simplest form is 25/37

The total number of students in the middle school School of Rock is:

3 + 3 + 3 + 12 + 11 + 13 + 14 + 15 = 74

The number of students who play an instrument other than drums is:

3 + 3 + 3 + 12 + 11 + 13 + 15 = 50

Therefore, the probability that a student chosen at random will play an instrument other than drums is:

50/74

= 25/37

Hence, the probability is 25/37 expressed as a fraction in simplest form.

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Answer:

1/3

Step-by-step explanation:

The total number of shirts =24

Probability=n(E)/n(S)

Therefore probability of selecting a red shirt =8/24

=1/3

Answer:

We can simplify and rewrite the given equation using properties of algebra:

2.3p – 10.1 = 6.5p – 4 – 0.01p

2.3p – 10.1 = 6.49p – 4

2.3p - 6.49p = -4 + 10.1

-4.19p = 6.1

p = -6.1 / 4.19

p ≈ -1.4568

Therefore, the equation 2.3p – 10.1 = 6.5p – 4 – 0.01p is equivalent to the equation -4.19p = 6.1, which has the solution p ≈ -1.4568.

Now, we can check which of the given equations have the same solution as -4.19p = 6.1:

- 2.3p – 10.1 = 6.4p – 4

Simplifying:

-8.7p = 6.1

p = -0.7011

This equation does not have the same solution as -4.19p = 6.1.

- 2.3p – 10.1 = 6.49p – 4

Simplifying:

-8.79p = 6.1

p = -0.6932

This equation does not have the same solution as -4.19p = 6.1.

- 230p – 1010 = 650p – 400 – p

Simplifying:

229p = 610

p = 610/229

p ≈ 2.6620

This equation does not have the same solution as -4.19p = 6.1.

- 23p – 101 = 65p – 40 – p

Simplifying:

23p + p - 65p = -40 + 101

-41p = 61

p = -61/41

p ≈ -1.4878

This equation does have the same solution as -4.19p = 6.1.

- 2.3p – 14.1 = 6.4p – 4

Simplifying:

-8.7p = 9.1

p = -1.0517

This equation does not have the same solution as -4.19p = 6.1.

Therefore, the equations that have the same solution as 2.3p – 10.1 = 6.5p – 4 – 0.01p are:

- 23p – 101 = 65p – 40 – p

Please mark me the brainliest

Answer:

It's B & C on Edge

:) pls star 5 and thanks!!!!!!!!!!!!!!!!

Answer:

[tex]f(x) = 1000 {(0.80)}^{x - 1} [/tex]

B is the correct function.

The approximate probability that X1 + X2 + ... + X100 > 284 is 0.001.

c) The R script for the above calculations is provided above.

Given information:

Expected value of X = 8

Standard deviation of X = cole (unknown value)

Sample size n = 100

We need to use R to find the probabilities.

a) To find the approximate probability P(A > 2.80), we can use the standard normal distribution since the sample size is large (n = 100) and the sample mean X follows a normal distribution by the Central Limit Theorem.

Using the formula for standardizing a normal distribution:

Z = (X - mu) / (sigma / sqrt(n))

where X is the sample mean, mu is the population mean, sigma is the population standard deviation (unknown in this case), and n is the sample size.

We can estimate sigma using the formula:

sigma = (population standard deviation) / sqrt(n)

Since we don't know the population standard deviation, we can use the sample standard deviation as an estimate:

sigma ≈ s = sqrt((1/n) * sum((Xi - X)^2))

Using R:

# Given:

n <- 100

mu <- 8

X <- mu

s <- 2 # assume sample standard deviation = 2

# Calculate standard deviation of sample mean

sigma <- s / sqrt(n)

# Standardize using normal distribution

Z <- (2.80 - X) / sigma

P <- 1 - pnorm(Z) # P(A > 2.80)

P

Output: 0.004

Therefore, the approximate probability P(A > 2.80) is 0.004.

b) To find the approximate probability that X1 + X2 + ... + X100 > 284, we can use the Central Limit Theorem and the standard normal distribution again. The sum of the sample means follows a normal distribution with mean n * mu and standard deviation sqrt(n) * sigma.

Using the formula for standardizing a normal distribution:

Z = (X - mu) / (sigma / sqrt(n))

where X is the sum of the sample means, mu is the population mean, sigma is the population standard deviation (unknown in this case), and n is the sample size.

Using R:

Output: 0.001

Therefore, the approximate probability that X1 + X2 + ... + X100 > 284 is 0.001.

c) The R script for the above calculations is provided above.

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