A ray of light passes symmetrically through on equilateral prism of refractive index 1.5. determine
the angel of incidence for which the minimum deviation can occur
​

Answer:

Advantage: it could get rid of some unwanted waste. Disadvantage: it would emit pollution into the air.

For the magnitude in N.m of the torque exerted by the fish about an axis perpendicular to the page and passing through the angler's hand is mathematically given as

Z = 360.33Nm

Generally, the equation for the Torque is mathematically given as

Z = force x perpendicular distance

Z = Tcos30° x L

Z = 166(0.886) x 2.45

Z = 360.33Nm

In conclusion s the magnitude in N.m of the torque exerted by the fish about an axis perpendicular to the page and passing through the angler's hand

Z = 360.33Nm

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Explanation:

Newton’s second law is a quantitative description of the changes that a force can produce on the motion of a body. It states that the time rate of change of the momentum of a body is equal in both magnitude and direction to the force imposed on it.

Answer:

0.1111 W/m²

Explanation:

If all other parameters are constant, sound intensity is inversely proportional to the square of the distance of the sound. That is,

I ∝ (1/r²)

I = k/r²

Since k can be the constant of proportionality. k = Ir²

We can write this relation as

I₁ × r₁² = I₂ × r₂²

I₁ = 0.25 W/m²

r₁ = 16 m

I₂ = ?

r₂ = 24 m

0.25 × 16² = I₂ × 24²

I₂ = (0.25 × 16²)/24²

I₂ = 0.1111 W/m²

Hi there!

Recall that a charge that enters a magnetic field while moving experiences a magnetic force that causes it to enter a state of uniform circular motion.

We know the following (For a point charge):
[tex]F_B = qv B[/tex]

q = Charge (C)
v = velocity (m/s)
B = Magnetic field (T)

Fb= Magnetic force (N)

The equation for centripetal force:
[tex]F_c = \frac{mv^2}{r}[/tex]

m = mass (kg)

v = velocity (m/s)

r = radius (m)

Fc = Centripetal force (N)

Since we are given its period:
[tex]T = \frac{2\pi r}{v}\\\\v = \frac{2\pi r}{T}[/tex]

Plug this expression into the above equations. Since the magnetic force equals the centripetal force, set them equal to each other and simplify.

[tex]q\frac{2\pi r}{T} B = \frac{m}{r}(\frac{2\pi r}{T})^2[/tex]

Cancel out the expression.

[tex]qB = \frac{m}{r} (\frac{2\pi r}{T})[/tex]

Cancel out 'r'.

[tex]qB = \frac{2\pi m}{T}[/tex]

Now, we can simplify as necessary to find a value for 'q' over 'm':
[tex]\frac{q}{m} = \frac{2\pi }{TB} = \frac{2\pi }{(4.79 \times 10^{-6})(0.775)} = \boxed{1692554.464}[/tex]

Thus, the charge is 1.693 ×10⁶ times larger than its mass.

9.19 seconds (2dp)

Given:

v = 50m/s

u = 0 m/s

a = 5.44 m/s

t = ?

Substitute values into the equation v = u + at

v = u + at

50 = 0 + 5.44 x t

t = 50/5.44

t = 9.19 seconds

Time is in seconds as the velocity and acceleration are in metres per second instead of kilometres per hour

Answer:

speed of the friend that is 8m from the center:

0.8π m/s

the distance she will travel in one rotation is:

10

Her speed compared to you is faster because, she is farther away from the axis compared to you.

Explanation:

for the speed, it says the farther you are from the axis the greater your speed is, and for the person who was 4m from the axis of rotation their speed was 0.4 because they are closer to the axis so therefore their speed is slower. so for the friend that is 8m from the axis of rotation its most likely their speed would be 0.8 m/s.

in one revolution you travel 8m your original distance from the axis was 4m so, 8-4 = 4, which means one revolution is plus 4 to your original distance. since the question is asking for rotation and not revolution you can do 4 ÷ 2 which is 2, so for rotation you need to add 2 to your original distance, so 8 + 2 = 10

Answer:

After 1 decay it has .9375 of its value left  

.9375^n = 1/2

What is the value of n (number of decays)

n log .9375 = -.693

n =.693 / .0645 = 10.7

After 10.7 periods of 50 sec it will have 1/2 of its original nuclei left

1/2 life = 10.7 * 50 sec = 537 sec = 8.95 min

Answer:

Work is best defined as a force exerted on a body to cause it move over a certain distance.

work=force×displacement×cosθ

Explanation:

The speed of the wave with the given frequency and wavelength is 1.2m/s.

Given the data in the question;

Wavelength is  the distance over which the shapes of waves are repeated. It is the spatial period of a periodic wave.

It is expressed as;

[tex]\lambda = \frac{v}{f}[/tex]

Where v is velocity/speed and f is frequency.

Now, we can easily get the speed of the wave by substituting our given values into the expression above.

[tex]\lambda = \frac{v}{f} \\\\0.4m = \frac{v}{3s^{-1}}\\ \\v = 0.4m * 3s^{-1}\\\\v = 1.2ms^{-1}\\\\v = 1.2m/s[/tex]

Therefore, the speed of the wave with the given frequency and wavelength is 1.2m/s.

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Answer:

0.568

Explanation:

velocity = -9.8 (t) + Vo

Vo= 0 so v= 9.8(t)

Momentum = mass x velocity

v * 0.14 kg = 0.78 kg m/s

v = 5.571 m/sec

v= 9.8(t) , so substituting v we get , 5.571 = 9.8 * t

t = 5.571/9.8 = 0.568 seconds

Answer:

If the Sun was on the left side of the diagram it would be points A and C

Explanation:

Spring tides are when the Sun, Earth, and Moon are aligned together. Neap tides occur when when the Sun, Earth, and Moon are forming a right angle.

Answer:

C and d mark mwe braliest

Explanation:

The period (T) of the right pendulum for small displacements in s is equal to 1.49 seconds.

Mathematically, the time taken by this pendulum to undergo a small displacement is given by this formula:

[tex]T=2\pi \sqrt{\frac{L}{g} }[/tex]

Where:

Scientific data:

Acceleration due to gravity (g) = 9.8 m/s².

Assuming a randomized variable for the length of the rope to be 1.2 meter. Also, we know that the right pendulum has a radius of 1/2L.

1/2L = L/2

L/2 = 1.1/2

L/2 = 0.55 meter.

Substituting the parameters into the formula, we have;

[tex]T=2\times 3.142 \sqrt{\frac{0.55}{9.8} }\\\\T=6.284 \times \sqrt{0.0561} \\\\T=6.284 \times 0.2369[/tex]

T = 1.49 seconds.

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The vertical component of the net force that is moving the rocket away from Earth is determined as 171,010.1 N.

The vertical component of the net force that is moving the rocket away from Earth is determined as follows;

Fy = Fsinθ

where;

Fy = 500,000 x sin(20)

Fy = 171,010.1 N

Thus, the vertical component of the net force that is moving the rocket away from Earth is determined as 171,010.1 N.

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Answer:

250,000

Explanation:

Answer:

Explanation:

You can use that [tex]v = v_{o}+gt[/tex] or [tex]v^{2}=v_{o}^{2}+2gh=(25)^{2}+(2)(10)(381)=8245 \rightarrow v \approx 90.8[/tex] m/s.

Answer:

Explanation:

You can use [tex]\Delta E=\frac{\hbar c}{\lambda} \rightarrow \lambda =\frac{\hbar c}{E} = \frac{1240 eV.nm}{0.0141 eV} \approx 87943.26[/tex] in nm.

Here the hc = 1240 eV.nm in eV and nanometer unit.

Based on law of conservation of angular momentum, the rotational speed of the star is equal to 6,000 rev/s.

Given the following data:

First of all, we would determine the initial angular speed of the neutron star as follows:

[tex]\omega_i = \frac{1 \;Rev}{10 \;days} \\\\\omega_i = \frac{1 \;Rev}{10 \times 24 \times 60 \times 60}\\\\\omega_i = 1.157 \times 10^{-6}\;rev/s[/tex]

Mathematically, the moment of inertia of a uniform solid sphere is given by this formula:

[tex]I=\frac{2}{5} mr^2[/tex]

Where:

In order to determine the rotational speed of this neutron star, we would apply the law of conservation of angular momentum:

[tex]L_1 = L_2\\\\I_1\omega_1 = I_2\omega_2\\\\\frac{2}{5} m_1r_1^2 \omega_1 = \frac{2}{5} m_2r_2^2\omega_2\\\\m_1r_1^2 \omega_1 = m_2r_2^2\omega_2\\\\\omega_2 =\frac{r_1^2 \omega_1}{r_2^2}[/tex]

Substituting the given parameters into the formula, we have;

[tex]\omega_2 = \frac{ (7 \times 10^5 )^2 \times 1.157 \times 10^{-6}}{ (10 )^2}\\\\\\\omega_2 = \frac{ (7 \times 10^5 )^2 \times 1.157 \times 10^{-6}}{ 10 0}\\\\\omega_2 =\frac{566,930}{100}[/tex]

Final angular speed = 5,669 ≈ 6,000 rev/s.

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The relative velocity of the ball with respect to the truck is same as that of the truck with respect to the ball at equal time.

The relative velocity of an object is the velocity of the object observed with respect to rest frame of another object.

The distance traveled by each object is determined from the prouduct of velocity and time of motion.

d = vt

where;

Thus, if the ball moved the same distance when it was on the flat bed truck, then the relative velocity of the ball with respect to the truck is same as that of the truck with respect to the ball at equal time.

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Take action on climate change has a positive effect on health of organisms and environment.

Spread awareness and encourage friends, family and co-workers to reduce carbon pollution, reduce burning of fossil fuels by using electrical vehicle and devices. Always buy sustainable products and avoid the use of plastics.

We have to take action on climate change because it improved health,  maintain the population of organism, and reduced inequality. So we can conclude that take action on climate change has a positive effect on health of organisms and environment.

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Answer:

234 90 +energy

Explanation:

because alpha decrease by 4 2helium

Answer:

Explanation:

The position between point charge q to x = -8.0 m and y = 1.5 m is:

[tex]r=\sqrt{x^{2}+y^{2}}=\sqrt{(-8)^{2}+(1.5)^{2}}=\sqrt{66.25}\approx 8.13[/tex] meter

Then the magnitude of the electric field E is:

[tex]E=\frac{1}{4\pi\epsilon_{o}} \frac{q}{r^{2}}=(9\times 10^{9}) \frac{6.0\times 10^{-9}}{66.25}\approx 0.81 N/C[/tex]

For the vector of E:

[tex]\tan\theta=\frac{1.5}{-8}=-0.1875 \rightarrow \theta = -10.61^{0}[/tex]

[tex]E_{x}=E\cos (-10.16)=(0.81)(0.984)=0.79704 N/C[/tex]

[tex]E_{y}=E\sin\theta = -0.81(0.184)=-0.14904 N/C[/tex]

[tex]\vec{E}=0.79704\hat{i}-0.14904\hat{j}[/tex] in N/C

Answer:

our acceleration is 0 because there is a constant speed..

a = final speed - initial speed / time

final speed = initial speed ( since speed is constant)

therefore acceleration is 0

The net force acting on the wagon when it is pulled at a constant speed is zero (0).

The net force acting on an object is the sum of all the forces acting on the object. The net force on an object is determined by applying Newton's second law of motion as shown below;

F(net) = ma

where;

Constant speed is a situation where the speed of the object does not change with time.

At constant speed, the acceleration of the object is zero (0).

F(net) = m x 0

F(net) = 0

Thus, the net force acting on the wagon when it is pulled at a constant speed is zero (0).

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Question :-

Answer :-

Explanation :-

As per the provided information in the given question, The Force is given as 10 Newton . The Distance is given as 30 cm [ 0.3 m ] . And, we have been asked to calculate the Amount of Force .

For calculating the Force , we will use the Formula :-

[tex] \bigstar \: \: \: \boxed{ \: \sf {Moment \: of \: Force \: = \: Force \: \times \: Distance} \: } [/tex]

Therefore , by Substituting the given values in the above Formula :-

[tex] \dag \: \: \: \sf {Moment \: of \: Force \: = \: Force \: \times \: Distance} [/tex]

[tex] \longmapsto \: \: \: \sf {Moment \: of \: Force \: = \: 10 \: \times \: 0.3} [/tex]

[tex] \longmapsto \: \: \: \textbf {\textsf {Moment \: of \: Force \: = \: 3}} [/tex]

Hence :-

[tex] \underline {\rule {185pt}{4pt}} [/tex]

Answer:

4

Explanation:

We know that :

Solving

Answer:

False

Explanation:

A land breeze is when air flows from land to water. The question above is describing a sea breeze, which is when cool ocean air blows toward land.

Explanation:

Water is wet, in the sense of being a liquid which flows easily, because its viscosity is low, which is because its molecules are rather loosely joined together.

Answer:

Liquid water is not itself wet, but can make other solid materials wet.

Wetness is the ability of a liquid to adhere to the surface of a solid, so when we say that something is wet, we mean that the liquid is sticking to the surface of a material.

Whether an object is wet or dry depends on a balance between cohesive and adhesive forces. Cohesive forces are attractive forces within the liquid that cause the molecules in the liquid to prefer to stick together. Cohesive forces are also responsible for surface tension. If the cohesive forces are very strong, then the liquid molecules really like to stay close together and they won't spread out on the surface of an object very much. On the contrary, adhesive forces are the attractive forces between the liquid and the surface of the material. If the adhesive forces are strong, then the liquid will try and spread out onto the surface as much as possible. So how wet a surface is depends on the balance between these two forces. If the adhesive forces (liquid-solid) are bigger than the cohesive forces (liquid-liquid), we say the material becomes wet, and the liquid tends to spread out to maximize contact with the surface. On the other hand, if the adhesive forces (liquid-solid) are smaller than the cohesive forces (liquid-liquid), we say the material is dry, and the liquid tends to bead-up into a spherical drop and tries to minimize the contact with the surface.

Water actually has pretty high cohesive forces due to hydrogen bonding, and so is not as good at wetting surfaces as some liquids such as acetone or alcohols. However, water does wet certain surfaces like glass for example. Adding detergents can make water better at wetting by lowering the cohesive forces . Water resistant materials such as Gore-tex fabric is made of material that is hydrophobic (water repellent) and so the cohesive forces within the water (liquid-liquid) are much stronger than the adhesive force (liquid-solid) and water tends to bead-up on the outside of the material and you stay dry.