its b welcome
Explanation:
Jenny puts a book on her desk. Jenny’s book has an area of 200 cm2.It exerts a pressure of 0.05 N/cm2 on the desk. What is the weight of the book? *
If you are trying to hit a baseball as far as possible, you would want to:
apply a small force over a short time
apply a small force over a long time
apply a large force over a short time
apply a large force over a long time
Question 4 of 10 Which three components define a person's overall health? A. Mental and emotional health B. Social health C. Physical health D. Public health
Answer:
physical, social, and mental
Explanation:
Answer:
A,B,C
Explanation:
These three maintain the overall health of the person being. Take for instance an example a cake, it has layers that make the overall cake. So it is with the persons health, it takes all three of these feilds to make the overall health.
A computational model predicts the maximum kinetic energy a roller coaster car can have given its mass, the speed at the highest point of its journey, and the height of the highest point. The mass is 250 kg, and the highest point of the journey is at 30m, where the cart is at rest. What is the maximum kinetic energy?
A. 113500 J
B. 468750 J
C. 0 J
D. 73500 J
Answer:
D
Explanation:
The decrease in potential energy is equal to the increase in kinetic energy.
mgh
250 x 9.8 x 30
=73, 500
Answer:
73,500 J
Explanation:
100% Correct
Assuming that the acceleration of an object due to gravity is ag = 10 m/s2, it is possible to find the distance an object falls when dropped by using the equation ay = \frac{1}{2} ag t2. Using this value for gravity, how far would an object drop after 5.0 s?
105 m
125 m
135 m
115 m
Answer:
125 m
Explanation:
i just did the edpuzzle
When momentum is conserved it is called _____. (multiple choice)
A.) Conservation of Momentum
B.) The Law of Momentum
C.) The Physics of Momentum
D.) The Rules of Momentum
Answer:
Based off the word "conserved" I would say
A. Conservation of Momentum.
Explanation:
Answer:
A.) Conservation of Momentum
After 4 half-lives, I ended up with 10 gram sample of
Carbon-14. What was the original amount of Carbon-14
that I started with?
Answer:
80g
Explanation:
The half - life is the time taken for half of radioactive substance to decay to half of its original composition.
After 4 half lives, the carbon - 14 sample is 10grams
Now let us trace the decay of this substance;
At the 3rd half life, it will have double the amount at the 4th half life;
2 x 10 = 20g
At the 2nd half life, there will be double the amount at the 3rd half life;
20 x 2 = 40g
Originally, we are going to have;
40 x 2 = 80g
What is the period of a rotating object if it spins 24 times in 13 seconds?
Answer:
The period is 0.54 seconds
Explanation:
Period (T)
Is the time required for a rotating object to make one complete revolution around a circular path.
If it takes a time t to complete n revolutions, the period is:
[tex]\displaystyle T=\frac{t}{n}[/tex]
The rotating object spins n=24 times in t=13 seconds, thus its period is:
[tex]\displaystyle T=\frac{13}{24}[/tex]
T = 0.54 sec
The period is 0.54 seconds
A spring has a spring constant of 120 N/m. How much energy is stored in the spring as it is stretched a distance of 0.20 meter?
Answer:
2.4J
Explanation:
Given parameters:
Spring constant = 120N/m
Extension = 0.2m
Unknown:
Amount of energy = ?
Solution:
The energy stored in this stretched spring is called the elastic potential energy.
It can be derived using the expression below:
Elastic Potential energy = [tex]\frac{1}{2}[/tex] ke²
k is the elastic constant
e is the extension
Insert the parameters;
Elastic potential energy = [tex]\frac{1}{2}[/tex] x 120 x 0.2² = 2.4J
A book that weighs 5 N sits on a table. What force does the table apply to the book?
Answer:
E =F.d =[1/2]mv^2
mad = [1/2]mv^2
d= v^2/2a ,v=u+at , v^2 = [at]^2 since u=0
So d = at^2/2
F = ma= 20a= 50 , a=5/2 and t=2
so d = [5/2][2^2]/2=5
Explanation:
Every action has an equal and opposite reaction. It is an action-reaction principle. Therefore the table exerts a force of 5 N on the book in order to be in stable condition.
What is Newton's third law of motion?Newton's third law of motion state that every action has an equal and opposite reaction. It is an action-reaction principle. It stated that the force always exists in a pair.
Therefore the table exerts a force of 5 N on the book in order to be in stable condition.
The given data in the problem is ;
W is the weight of the book sits on table = 5N
N is the normal force on the book
From the equilibrium equation ;
Weight -Normal force on the book =0
Weight =Normal force on the book
The normal force on the book =5N
Hence the table exerts a force of 5 N on the book in order to be in stable condition.
To learn more about Newton's third law of motion refer to the link;
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please help I’m struggling
Answer:
11025 J
183.75 W
Explanation:
[tex]W=mgh\\W=(75\ kg)*(9.8\ m/s^{2})*(15\ m)\\W=11025\ J\\\\P=work/time\\P=(11025\ J)/(60\ s)\\P=183.75\ W[/tex]
what is the KE of a 1.00 kg hammer swinging at 20.0 m/s? 200 Joules
I know the answer I just need help understanding it.
Answer:
Explanation:
From the question given above, the following data were obtained:
Mass (m) = 1250 kg
Velocity (v) = 20.0 m/s.
Kinetic energy (K.E) =?
Kinetic energy is simply defined as energy possed by a body in motion. Mathematically, it is expressed as:
K.E = ½mv²
Where:
K.E is the kinetic energy
m is the mass of the object
v is the velocity of the object.
Thus, we can obtain the kinetic energy of the automobile by using the above formula as illustrated below:
Mass (m) = 1250 kg
Velocity (v) = 20.0 m/s.
Kinetic energy (K.E) =?
K.E = ½mv²
K.E = ½ × 1250 × 20²
K.E = 625 × 400
K.E = 250000 J
Therefore, the kinetic energy of the automobile is 250000 J
Biker 1 is on a motorcycle facing West is initially at rest. The motorcycle speeds up from rest to 25 mph in three seconds.
Biker 2 is right by his side to start. He speeds up from rest to 85 mph in eight seconds.
Which biker has a greater acceleration?
Biker 1's acceleration:
(25 mph) / (3 s) = ((25 mi/h) • (1/3600 h/s)) / (3 s) ≈ 0.00231 mi/s²
Biker 2's acceleration:
(85 mph) / (8 s) = ((85 mi/h) • (1/3600 h/s)) / (8 s) ≈ 0.00295 mi/s²
Biker 2 has the greater acceleration.
A 8.0\,\text {kg}8.0kg8, point, 0, start text, k, g, end text box is released from rest at a height y_0 =0.25\,\text my 0 =0.25my, start subscript, 0, end subscript, equals, 0, point, 25, start text, m, end text on a frictionless ramp. The box slides from the ramp onto a rough horizontal surface. The box slides 2.0\,\text m2.0m2, point, 0, start text, m, end text horizontally until it stops.
Answer:
μ = 0.125
Explanation:
To solve this problem, which is generally asked for the coefficient of friction, we will use the conservation of energy.
Let's start working on the ramp
starting point. Highest point of the ramp
Em₀ = U = m h y
final point. Lower part of the ramp, before entering the rough surface
[tex]Em_{f}[/tex] = K = ½ m v²
as they indicate that there is no friction on the ramp
Em₀ = Em_{f}
m g y = ½ m v²
v = [tex]\sqrt{2gy}[/tex]
we calculate
v = √(2 9.8 0.25)
v = 2.21 m / s
in the rough part we use the relationship between work and kinetic energy
W = ΔK = K_{f} -K₀
as it stops the final kinetic energy is zero
W = -K₀
The work is done by the friction force, which opposes the movement
W = - fr x
friction force has the expression
fr = μ N
let's write Newton's second law for the vertical axis
N-W = 0
N = W = m g
we substitute
-μ m g x = - ½ m v²
μ = [tex]\frac{v^{2} }{2 g x}[/tex]
Let's calculate
μ = [tex]\frac{2.21^{2}}{2\ 9.8\ 2.0}[/tex]
μ = 0.125
A 8.0 kg box is released from rest at a height y0 = 0.25 m on a frictionless ramp. The box slides from the ramp onto a rough horizontal surface. The box slides 2.0 m horizontally until it stops.
What is the friction coefficient of the horizontal surface?
Answer: 0.125
The radius of the planet Mercury is 2.43 x 10^6m and its mass
is 3.2 x 10^23 kg. What is the speed of a satellite in orbit
265.000 m above the surface?
[tex]\huge\boxed{Option D}[/tex]
_____________________________________DATA:Radius of Mercury = [tex]R_m[/tex] = [tex]2.43x10^6m[/tex]
Mass of Mercury = [tex]M_m = 3.2x10^{23}m[/tex]
Distance Satellite above the surface of the Mercury = d = 265,000m
Gravitational Constant = [tex]G = 6.67x10^{-11} \frac{N.m^2}{kg^2}[/tex]
_____________________________________SOLUTION:Since the Satellite is orbiting around the Planet Mercury, due to the centripetal force, and Centripetal force is the force that acts towards the center of the circle, Whereas The gravitational force also acts towards the center of the circle thus we can say that Centripetal force is equal or same as centripetal force. So,
[tex]F_g =F_C[/tex]
Fg is Given by,
[tex]F_g = \frac{GM_MM_S}{r^2}[/tex]
Fc is Given by,
[tex]F_c=\frac{M_SV^2}{r}[/tex]
Where,
G is Gravitational Constant
[tex]M_e[/tex] is mass of Planet Mercury
[tex]M_S[/tex] is Mass of Satellite
r(small letter) is the distance between the center of the Planet Mercury and the satellite.
V is velocity of satellite
_____________________________________Now,
[tex]\frac{GM_MM_S}{r^2} =\frac{M_SV^2}{r}[/tex]
[tex]V = \sqrt\frac{GM_M}{r}[/tex]
r can also be written as,
[tex]V = \sqrt\frac{GM_M}{R_M +d}[/tex]
Substitute the variables,
[tex]V = \sqrt{\frac{(6.67x10^{-11})x(3.2x10^{23})}{2695000}[/tex]
Simplify the equation,
V = 2814 [tex]\frac{m}{s}[/tex]
Approximately,
V = 2800 [tex]\frac{m}{s}[/tex]
_____________________________________Best Regards,'Borz'What two things does force depend on
What energy transformations take place from the outlet charger to the ringing phone?
Explain how the Law of Conservation of Energy applies to the energy
transformations that occur from the outlet charger to the ringing phone.
Answer:
Chemical energy transformations take place from the outlet charger to the ringing phone.
Explanation:
chemical energy
While charging the mobile electrical energy gets transformed into chemical energy. Most of the contemporary mobile phone batteries are lithium-ion batteries where the power is saved by the chemical transformations in the ionic structure of the battery. When the power gets into the mobile phone it is transformed and collected as chemical energy inside of the battery and when we utilize the mobile the earlier saved chemical energy is again transformed into electrical energy.
The energy transformation that takes place from the outlet charger to the
ringing phone is electrical energy from the outlet is converted to chemical
energy and back to electrical energy and sound energy when the phone is
being used and ringing.
The charger provides a source of electrical energy which gets converted to
chemical energy stored in the battery. During use, the chemical energy gets
converted to electrical energy to power the phone and to sound energy
when it rings with heat energy being dissipated also.
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it takes 5100 N of force to accelerate a ford mustang 3 m/s2 what is the mass of the car
Answer:
1700 kg
Explanation:
The mass of the ford mustang car be 1700 kg.
What is mass?In physics, mass is a quantitative measurement of inertia, a basic characteristic of all matter. It essentially refers to a body of matter's resistance to changing its speed or location in response to the application of a force.
The change caused by an applied force is smaller the more mass a body has. The kilograms serves as the unit of mass in the International System of Units (SI).
Given parameters:
Force applied on the ford mustang car: F = 5100 N.
Acceleration of the ford mustang car: a = 3 m/s^2.
So, The mass of the ford mustang car be = force/acceleration
= 5100/3 kg.
= 1700 kg.
Hence, the mass of the ford mustang car be 1700 kg.
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plzzzz help me this is due today. only need help with these two questions and the element is oxygen.
How do protons, neutrons, and electrons differ in terms of their electrical charges and locations within the atom?
Describe the four fundamental forces. Which of these forces are involved in chemical bonding?
Answer: thanks for the point
Explanation:
The gravitational force between two objects is
proportional to the products of the masses and
proportional to the square of the distance between them.
The complete question is;
The gravitational force between two objects is ______ proportional to the products of the masses and _______ proportional to the square of the distance between them.
Answer:
First dash is directly
Second dash is inversely
Explanation:
From Newton's law of gravitation the gravitational force is given by the equation;
F = GMm/r²
Where:
F is gravitational force
M and m are two masses representing the two objects
r is the distance between them
G = universal gravitational constant
Thus, if we are to write it in proportion format, we will have;
F ∝ Mm/r²
From this proportion relationship, we can see that the Gravitational force is directly proportional to the products of the two masses and inversely proportional to the square of the distance between them.
Answer:
DirectlyInverselyExplanation:
The gravitational force between two objects is directly proportional to the products of the masses and inversely proportional to the square of the distance between them.
Diana hangs a lead cylinder with a force of 12 N from a model bridge.
Which vector(s) accurately illustrates the reaction force of the bridge on the lead cylinder?
The action and reaction law allows us to find that the reaction force, the weight of the cylinder, is:
12 N force directed upward
Newton's third law or action and reaction law, establishes that if two bodies interact with each other the force that one applies to the other, is equal in magnitude to the force of the second on the first but in the opposite direction, that is, all forces act in pairs one in each body that interact.
Forces with these characteristics are called action and reaction.
In this case we have a hanging cylinder, with the cylinder it has mass so the weight is 12 N it acts on the table in a downward direction, let's say this is the action force.
In response to this force, the table exerts a force on the cylinder of equal magnitude but in the opposite direction, which is why it is directed upwards.
let's analyze the force diagram
When analyzing the forces shown in the diagram, the forces of equal magnitude to the weight are the first twoThe weight is directed downward, the answer must be directed upward.
In conclusion using theaction and reaction law we find that the answer for reaction force is:
12 N force directed upward
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A car travels 14 km due west, then does a
U-turn, and travels 43 km due west.
I. What total distance has the car
traveled?
II.
What is the total displacement of the
car?
III. If the entire trip took 3.20 hours.
determine the average speed of the
car. Give
your answer in both
km hour, and m s. (show
conversion)
IV. If the entire trip took 2.50 hours.
determine the average velocity of
the car. Give your answer in both
km h, and mph (show conversion)
Explanation:
It is given that,
A car travels 14 km due west, then does a U-turn and travels 43 km due east (when it takes U-turn, it will change direction from west to east)
i. Total distance = total path covered
= 14 km + 43 km
= 57 km
ii. Let east is positive and west is negative.
Displacement = final position-initial position
= 43-14
= 29 km
iii. If time taken in the entire trip = 3.2 hours
Average speed = distance/time
[tex]s=\dfrac{57\ km}{3.2\ h}\\\\=17.81\ km/h[/tex]
1 km/h = 0.2777 m/s
17.81 km/h = 4.94 m/s
iv. If time taken in the entire trip = 2.5 hours
Average velocity = displacement/time
[tex]v=\dfrac{29\ km}{2.5\ h}\\\\=11.6\ km/h[/tex]
1 km/h = 0.621 mph
11.6 km/h = 7.2 mph
Henc, this is the required solution.
A teacher opens a window on a cold day. Which statement explains why the room starts to feel cooler? (1 point)
0 Air moves from the areas of higher temperature to areas of lower temperature
O Cold air is moving into the room from outside.
0 The density of the air is lower on the inside than on the outside
0 The kinetic energy of the air molecules outside is higher than the kinetic energy of the air molecules inside.
Answer:
Air moves from the areas of higher temperature to areas of lower temperature.
Explanation:
this is because hotter temperatures seek out colder temps.
hope this helped!
When a teacher opens a window on a cold day. the room starts to feel cooler because air moves from the areas of higher temperature to areas of lower temperature.
What is convection of heat transfer?The transfer of heat between two bodies by currents of moving gas or fluid is known as convective heat transfer. In free convection, air or water rises and is replaced by a cooler parcel of air or water as it moves away from the hot body.
As air moves from the areas of higher temperature to areas of lower temperature, when the teacher opens a window on a cold day, the air in the room moves out side and cold air takes the position inside the room. So, it feels cooler then.
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Students are asked to design an experiment about Newton’s 2nd Law. One student decides to roll a marble down a ramp into a pile of sand to measure the force impact.
Which variable should she manipulate to best exemplify the relationship explained by this law?
A.She should use a heavier marble, because the marbles will roll at the same rate of acceleration but more mass will produce a larger impact force.
B.She should increase the slope of the ramp by propping it up to higher height, because a steeper ramp will cause a greater rate of acceleration and a larger impact force.
C.She should use a heavier marble, because a bigger marble will accelerate more quickly down the ramp and cause a greater impact force.
D.She should decrease the slope of the ramp, because a ramp with a smaller slope will allow the ball more time to build up speed and cause a greater impact force.
Answer:
A
Explanation:
Trust me I just took it !
A box is sitting stationary on a long level ramp on level ground. The coefficient of static friction is (1.0). One end of the ramp is slowly lifted higher and higher. What is the angle of the ramp with respect to the ground when the box begins slidig?
Answer:
45 degrees
Explanation:
Given that the coefficient of friction, [tex]\mu=1.0[/tex]
Let the angle of the ramp be [tex]\theta[/tex].
The gravitational force acting downward [tex]=mg[/tex]
The normal reaction by the ramp on the box, [tex]N=mg\cos\theta[/tex]
So, the maximum frictional force that can act on the box, [tex]f= \mu N[/tex]
The force along with the plane in the direction of sliding, [tex]F = mg\sin\theta[/tex]
When the box begins sliding, the F must have to overcome the frictional force,f.
So, F=f
[tex]mg\sin\theta=\mu N \\\\mg\sin\theta=\mu mg\cos\theta \\\\\frac {\sin\theta}{\cos\theta}=\mu \\\\\tan\theta=\mu \\\\\theta=\tan^{-1}\mu \\\\[/tex]
Putting the value of \mu, we have
[tex]\theta=\tan^{-1}1[/tex]
[tex]\theta=45[/tex] degrees.
Hence, the angle of the ramp with respect to the ground when the box begins sliding is 45 degrees.
A car of mass 1500 kg starting from rest can reach a speed of 20
m/s within 10 seconds. Calculate the accelerating force of the car
engine.
Explanation:
F=MA
F=1500 * 2
F=3000N
Help please! I hope the given possibles help
Answer:
The answer is "[tex]5.184 \times 10^{23}[/tex] kg"
Explanation:
Given:
[tex]g= 6.003 \ \frac{m}{s^2}\\\\G= 6.67 \times 10^{-11} \ \frac{N - m^2}{kg^2}\\\\M=?\\\\radius= 2,400 \ km\\\\[/tex]
Calculating diameter:
[tex]Diameter =radius \times 2[/tex]
[tex]=24\times 10^5 \times 2\\\\=48 \times 10^5 \ m[/tex]
The formula for mass calculation:
[tex]\to g = G \times \frac{M}{(\frac{d^2}{4})}\\\\\to g=G\times \frac{4M}{d^2}\\\\\to 4M= \frac{g \times d^2}{G} \\\\\to M= \frac{g \times d^2}{4G} \\\\[/tex]
[tex]=\frac{6.003 \times (48 \times 10^{5})^2}{4 \times 6.67 \times 10^{-11}}\\\\=\frac{6.003 \times 2,304 \times 10^{10}}{26.68\times 10^{-11}}\\\\=\frac{13,830.912 \times 10^{10}}{26.68\times 10^{-11}}\\\\=518.4 \times 10^{21}\\\\= 5.184 \times 10^{23}\\\\[/tex]
An example of a poor coping mechanism is ?
Answer: A bad, maladaptive, unhealthy or destructive coping mechanism is one where the behavior does not resolve the problem in the long-term and may actually increase the harm. Unhealthy coping strategies may feel like they are having the desired effect in the short term.
Explanation: Yes, it was from google...
a car travels west at 40 km/h
a man on a bike travels at 10 km/h
what is the speed of the car relative to the speed of the bicycle ?
Answer:
The car is going 0 km/h more than the bike
Explanation:
Please help! Will mark brainliest!
Answer:
im pretty sure its d
Explanation: