A positive charge is 1 m to the left of a negative charge. The positive charge is then moved and placed 1 m to the right of the negative charge. What happens to the electrostatic force between the charges?
The electrostatic force remains attractive, and the magnitude does not change.
The electrostatic force remains repulsive, and the magnitude does not change.
The electrostatic force remains repulsive, but the magnitude changes.
The electrostatic force remains attractive, but the magnitude changes.

Answers

Answer 1

Answer:

Option (a) is correct.

Explanation:

Let the magnitude of the positive charge = [tex]q_1[/tex] and the magnitude of the negative charge = [tex]q_2[/tex]

Earlier, the distance between both the charge, d = 1m

By using Coulomb's law, the magnitude of the force between two charge

[tex]F=k\frac {q_1 q_2}{d^2}[/tex], where k is a constant.

So, the magnitude of the force in the initial configuration,

[tex]F_i = k\frac {q_1 q_2}{1^2}= k q_1q_2\cdots(i)[/tex]

The nature of the force is attractive, as both the charges are opposite in nature.

On replacing the positive charge from 1m left to 1 m right side of the negative charge, the distance between the charges remains the same, i.e d=1m.

Moreover, the magnitude, and nature of each charge, [tex]q_1[/tex] as well as [tex]q_2[/tex], are remain the same.

So, the magnitude of the force in the final configuration,

[tex]F_f = k\frac {q_1 q_2}{1^2}= k q_1q_2[/tex]

From equation (i), [tex]F_f=F_i[/tex]

The nature of the force is attractive, as both the charges are opposite in nature.

So, the electrostatic force remains attractive, and the magnitude does not change.

Hence, option (a) is correct.

Answer 2

When the electrostatic force lies between the charges so here the force should remain attractive, also the magnitude should remain the same.

Impact on the electrostatic force:

Here we assume the magnitude of the positive charge should be q1 and the magnitude of the negative charge should be q2

Also, the distance between the charge should be d = 1 m

So here we use the columb law

F = kq1q2/d2

here k should be constant

Here the nature of the force should be attractive since the both the charges should be opposite.

Hence, the first option is correct.

Learn more about force here: https://brainly.com/question/3398162


Related Questions

Finding volume using displacement and calculating density

Answers

Answer:

a) 0.1

b) density = mass/volume

                 = 0.5 /0.1

                 = 5 kg/[tex]m^{3}[/tex]

A space shuttle travels around the Earth at a constant speed of 28000 kilometers per hour. If it takes 90 minutes to complete one orbit, how far is its journey around Earth?​

Answers

42000 kilometers

Explanation:

distance is velocity × time

28000 ×1.5

42000

remember to match units

thats why i wrote 1.5 hours instead of 90minutes

A 10 gram ball is rolling at 3 m/s. What is the energy the ball has?

Answers

Answer:

K = 0.045 J

Explanation:

It is given that,

Mass of a ball, m = 10 g = 0.01 kg

Speed of the ball, v = 3 m/s

To find,

The energy of the ball.

Solution,

Due  to the motion of the ball, it will have kinetic energy. It can be given by the formula as follows :

[tex]K=\dfrac{1}{2}mv^2\\\\K=\dfrac{1}{2}\times 0.01\times 3^2\\\\K=0.045\ J[/tex]

So, the ball will have a kinetic energy of 0.045 J.

If the astronaut from question #9 collides with a satellite and comes to a complete stop, where did his momentum go? Explain this in terms of conservation of momentum.

Answers

Answer:

    m v ´- MV = (m + M) v ’

Explanation:

If the astronaut initially has a speed v the satellite has a speed V, we can define a system that is formed by the two bodies, therefore the forces during the collision are internal, so the momentum is conserved

initial instant. Before the crash

          p₀ = m v - MV

final instatne. After the crash, we have two cases

1) inelastic shock

          m_f = (m + M) v '

          p₀ = p_f

         m v ´- MV = (m + M) v ’

2) elastic collision with the astronaut's velocity, zero in this case the moment remains

        m v - MV = mv ’+ Mv’

also the kinetic energy is conserved

       mv'2 + M V2 = mv'2 + m v'2

with these two equations we can find the speed of the cars

The yoga term asanas are which of the following?
A.
The yoga breathing method.
B.
The yoga term for mediation.
C.
The yoga term for exercises or poses.
D.
The yoga term for spiritual enlightenment.

Answers

Answer:

i guss its A

Explanation:

The sum of two component vectors is referred to as the
vector.
Addition
Quantitative
Subtraction
Resultant

Answers

resultant is the correct answer!

brainlists please help

on the coner opposite of 8n is 5n​

Answers

Answer:

resultant force=16N→(TOWARDS THE DIRECTION OF 8N)

Explanation:

resultant force=8N+13N-5N

                        =16N→(TOWARDS THE DIRECTION OF 8N)

40 POINTS I WILL GIVE TO BRAINLYEST.
PLEASE HELP​

Answers

Just divide the d/t to get answer: 10.99

Explanation:

Just divide the distance you are traveling (100m) by the mps (9.1m) and that’s it

Put in your calculator 100 divide by 9.1 and you get the answer:

10.989011

Hope that helps :D

UWU plz help 50 points!!
A sprinter accelerates from the starting blocks with an acceleration of 2.5 m/s/s. They accelerate for a total of 8 seconds.
a. How far will they run while accelerating? Explain how you found your answer.
b. How fast are they moving after those 8 seconds? Explain how you found your answer

Answers

Answer:

i think its 20m for b

Explanation:

PLEASE HELP!! ITS URGENT!!!​

Answers

Answer:

F = 800 [N]

Explanation:

To be able to calculate this problem we must use the principle of momentum before and after the impact of the hammer.

We must summarize that after the impact the hammer does not move, therefore its speed is zero. In this way, we can propose the following equation.

ΣPbefore = ΣPafter

[tex](m_{1}*v_{1}) - F*t = (m_{1}*v_{2})[/tex]

where:

m₁ = mass of the hammer = 0.15 [m/s]

v₁ = velocity of the hammer = 8 [m/s]

F = force [N] (units of Newtons)

t = time = 0.0015 [s]

v₂ = velocity of the hammer after the impact = 0

[tex](0.15*8)-(F*0.0015) = (0.15*0)\\F*0.0015 = 0.15*8\\F = 1.2/(0.0015)\\F = 800 [N][/tex]

Note: The force is taken as negative since it is exerted by the nail on the hammer and this force is directed in the opposite direction to the movement of the hammer.

Please help. to find these














Answers

Answer:

Velocity ratio & input work

Explanation:

If u input velocity u can work the ratio...;D ;D ;D xD

Calculate Vector component in Y if the hypotenuse is 32 and angle is 45

Answers

Answer:

The correct option is;

c. 22.6

Explanation:

The given parameters are;

The hypotenuse of the vector = 32

The angle of the vector = 45°

Therefore, the vector component in the y-axis is given as follows;

[tex]v_y = v \times sin(\theta)[/tex]

Substituting the values from the question gives;

[tex]v_y = 32 \times sin(45^{\circ}) \approx 22.6[/tex]

The vector component in the y-axis, [tex]v_y[/tex], is approximately 22.6.

Need help solving this question.

Answers

Answer:

See the answers below.

Explanation:

to solve this problem we must make a free body diagram, with the forces acting on the metal rod.

i)

The center of gravity of the rod is concentrated in half the distance, that is, from the end of the bar to the center there is 40 [cm]. This can be seen in the attached free body diagram.

We have only two equilibrium equations, a summation of forces on the Y-axis equal to zero, and a summation of moments on any point equal to zero.

For the summation of forces we will take the forces upwards as positive and the negative forces downwards.

ΣF = 0

[tex]-15+T-W=0\\T-W=15[/tex]

Now we perform a sum of moments equal to zero around the point of attachment of the string with the metal bar. Let's take as a positive the moment of the force that rotates the metal bar counterclockwise.

ii) In the free body diagram we can see that the force acts at 18 [cm] of the string.

ΣM = 0

[tex](15*9) - (18*W) = 0\\135 = 18*W\\W = 7.5 [N][/tex]

Consider again the objects you ranked by distance. Suppose each object emitted a burst of light right now. Rank the objects from left to right based on the amount of time it would take this light to reach Earth, from longest time to shortest time.a. star on far side of Andromeda Galaxyb. star on near side of Andromeda Galaxyc. star on far side of Milky Way Galaxyd. star near center of Milky Way Galaxy1. Orion Nebula2. Alpha Centauri3. Pluto4. The Sun

Answers

Answer:

Following are the solution to this question:

Explanation:

That light takes a very long time to hit the planet, and the object is far off the earth. The light of such an item near to the planet takes less time to enter it. The star is 2,5 million light-years from the Planet on the far side of the Andromeda Galaxy. But on the other hand, the moon is 15 crore miles from the earth, so sunlight is quickly reached on the ground as the other thing.  

That milky way away from the earth is 66,500 light-years far, that distance between Earth and Orion nebula is 1,344 light-years, with such a distance of 4,367 light-years. The earth is 5.2261 trillion km apart from Pluto.

Which of the following best describes inertia?
A. Rowing a boat
B. Moving forward in your seat when the car suddenly stops
C. A rocket taking off from the launching pad
D. A bicycle requires less force to move than a car

Answers

I think B I’m not quite sure

How do you solving kinematic equations for horizontal projectiles?

Answers

See projectiles are very simple unless you understand its core concepts....projectile is nothing just mixture of upward motion and horizontal motion....
THE KEY IS FORGET THE NAME PROJECTILE...ITS JUST HORIZONTAL MOTION + VERTICAL MOTION

Please answer these three multiple choices!
Would appreciate a loooottttt today!!

Answers

Answer:

Q2 [ C ]

Q4 [ C]

Q5 [ C]

if u want the steps write a comment

What are the different forms of potential energy

Answers

Answer:

   Gravitational potential energy.

   Chemical energy.

   Nuclear energy.

   Elastic potential energy

   Electrical potential energy

    Hope this helps :)

Which of the following groups contain three elements with stable electron configurations?

A. xenon, neon, boron
B. helium, xenon, neon
C. argon, neon, barium
D. lithium, krypton, argon

Answers

Answer:

B. helium, xenon, neon

Explanation:

B is the correct answer because Helium, Xenon, and Neon are all Noble Gases at Group 18, which means they contain the full 8 electrons they need meaning they all have stable electron configurations.

PLEASE HELP IF YOU KNOW THE ANSWER QUICK PLEASE!!!

Answers

Answer:

d

Explanation:

An electric heater is rated 1000watts. If a current of 5A pass through the heater, find the value of its resistance.​

Answers

Answer: R=40 Ω

Explanation: [tex]P=I^{2} R[/tex]

R=1000/ (25)=40

Two bowling balls, each with a mass of 8.52 kg, are traveling toward each other. Find the total momentum of the system if both balls have a speed of 2.13 m/s, but are traveling opposite of one another.
a. 18.1
b. 36.3
c. 0.0

d. 17.4

Answers

b=36•3

momentum=mass×velocity

The total momentum of the given system is equal to zero. Therefore, option (C) is correct.

What is the law of conservation of momentum?

The linear momentum can be described as the product of the mass times the velocity of that object. Conservation of momentum is a property of an object as the total amount of momentum stays the same.

According to the law of conservation of momentum, the sum of the momentum before and after the collision of the objects must be equal.

m₁ u₁ + m₂ u₂ = m₁ v₁ + m₂v₂

where u₁ and u₂ are initial speed while v₁ & v₂ is final speed and m₁ and m₂ is the mass of the collided objects.

The first ball, m = 8.52 g and v = 2.13 m/s

The momentum of the first ball = 18.15 g.m/s

The second ball is moving in the opposite direction w.r.t. first ball,

The second ball, m = 8.52 g and v = - 2.13 m/s

The momentum of the first ball = - 18.15 g.m/s

The total momentum  of the system = 18.15 + (-18.15) = 0

Therefore, the total momentum of the given system is zero.

Learn more about the law of conservation of linear momentum, here:

brainly.com/question/17140635

#SPJ6

What is a transverse wave like?

Answers

Answer:

a transverse wave is a moving wave whose oscillations are perpendicular to the direction of the wave or path of propagation

Explanation:

wave oscillate along paths at right angles to the direction of the wave’s advance.

Explanation:

what is the direction of the sum of these two vectors? ​

Answers

Answer:

what is the direction of the sum of these two vectors?

Answer:

69.6

Explanation:

Ax= 0

Ay= 63.5

Bx= 101 cos 57= 55.009

By= 101 sin 57= 84.706

Tan-1 = (84.706/55.009)

         = 69.6

Please help me idk what dis

Answers

Answer:
1) Just draw a line with arrow pointing downward
2)Yes
3) Yes
4) draw a dotted line with a arrow pointing downward.

Explanation: Remember, that “acceleration” just simply means a change in velocity.


can somone pls help me??!! i’m very stuck

Answers

Answer:

R

Explanation:

Her distance from home and Time increase

the stops when she gets to the library

then her distance from home decreases while her time increases

Lily can run 100 m in 10s. How fast was her average speed?

Answers

Answer:

The answer is 10 m/s

Explanation:

The average speed can be found by using the formula

[tex]v = \frac{d}{t} \\ [/tex]

d is the distance

t is the time taken

From the question we have

[tex]v = \frac{100}{10} \\ [/tex]

We have the final answer as

10 m/s

Hope this helps you

In a perfectly insulated container of negligible mass, 4.00 × 10−2 kg of steam at 100◦C and atmospheric pressure is added to 0.200 kg of water at 50.0◦C.
A) If no heat is lost to the surroundings, what is the final temperature of the system? B) At the final temperature, how many kilograms are there of steam and how many of liquid water?

Answers

Answer:

Following are the solution to this question:

Explanation:

Given value:

[tex]m_s= 4.00 \times 10^{-2} \ kg \\\\L_v=2256 \times 10^{3} \ \frac{J}{kg}\\\\m_w= 0.2 \ kg\\\\\Delta T= 50^{\circ}[/tex]

In point A:

[tex]Q_{Steam}=m_s \ L_v[/tex]

            [tex]=0.04 \times 2256 \times 10^{3}\\\\=9.02 \times 10^4 \ J[/tex]

[tex]Q_{water}= m_w \ c_w \ \Delta T\\\\[/tex]

           [tex]=0.2 \times 4190 \times 50\\\\=4.19 \times 10^4 \ J[/tex]

[tex]Q_{steam}> Q_{water}[/tex], that's why the final temperature is [tex]= 100^{\circ}[/tex]

In point B:

[tex]\to \Delta m_s L_v=m_w\ c_w \Delta T\\\\\to \Delta m_s \times 2256\times 10^3= 0.2 \times 4190 \times 50\\\\\to \Delta m_s= 1.86 \times 10^{-2} \ kg\\\\\to m_s = 2.14 \times 10^{-2} \ kg\\\\\to liquid \ left = 0.2+ 2.14 \times 10^{-2} = 2.34 \times 10^{-2} \\[/tex]

Define acceleration. Give its mathematical formula and SI unit. When is acceleration of a body negative? Give two examples of situations in which acceleration of the body is negative.

Answers

Answer:

The rate of change of velocity of a moving body is called acceleration. mathematical formula of Acceleration = Final velocity-Initial velocity

________________________

Time taken

SI Unit of Acceleration is m/s2. If the Velocity of a moving body decreases, it's acceleration will be negative. Two examples of situations in which acceleration of the body is negative are ÷

* Applying brakes * When a ball is thrown upward it experiences a negative Acceleration

A cork floats on the surface of an incompressible liquid in a container exposed to atmospheric pressure. The container is then sealed and the air above the liquid is evacuated. The cork:

Answers

Question:

A cork floats on the surface of an incompressible liquid in a container exposed to atmospheric pressure. The container is then sealed and the air above the liquid is evacuated. The cork:

A. sinks slightly  

B. rises slightly  

C. floats at the same height  

D. bobs up and down about its old position

Answer:

The correct answer is C)  floats at the same height  

Explanation:

The liquid is incompressible because its density very high and leaves no room for further compaction whether or not there is atmospheric pressure. So when you put a cork on the liquid, pressure or no pressure, there is no displacement hence it floats on the same height regardless of the absence of air.

Cheers!

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