A pharmaceutical manufacturer is concerned that the impurity concentration in pills should not exceed 3%. It is known that from a particular production run impurity concentrations follow a normal distribution with a standard deviation of 0.4%. A random sample of 64 pills from a production run was checked, and the sample mean impurity concentration was found to be 3.07%. Testing at the 5% level the null hypothesis that the population mean impurity concentration is 3% against the alternative that it is more than 3%.
a. Calculate the p-value for this test.
b. Find the p-value for this test and draw your conclusion.
c. Suppose that the alternative hypothesis in part b had been two-sided rather than one-sided. Conduct your test using either the critical value or the p-value approach.

Answer:

c

Step-by-step explanation:

Marl me as brainliest answer c

The p-value for the given test is 0.0901.

Given that, a pharmaceutical manufacturer is concerned that the impurity concentration in pills should not exceed 3%.

Standard deviation is the degree of dispersion or the scatter of the data points relative to its mean, in descriptive statistics.

Given, Mean = 3.07, μ=3%, σ =0.4% and n=64.

Hypothesis test [tex]H_{0}[/tex];μ=3 and [tex]H_{1}[/tex];μ>3

We need to test the null hypothesis against the alternative hypothesis, we reject the null hypothesis and accept the alternative hypothesis.

When x>x critical

x critical = μ+Z+σ

Z = (x-μ)/(σ/√n)

= (3.07-3)/(0.4/√64)

= (0.07)/0.05

= 1.4

α = 5 and [tex]z_{0.05[/tex]= 1.645

If Z>[tex]Z_{0.05[/tex]

1.4 > 1.645

Therefore, we do not reject null hypothesis at 5% significant level.

There is sufficient evidence that the mean impurity in concentration pills is 3% or less than 3%.

p-value

p−value=P(Z>1.4)

=1−P(Z<1.4)

=1−0.90988

=0.0901

Therefore, the p-value for the given test is 0.0901.

To learn more about the standard deviation visit:

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